If a car travels 10 km north and then 10 km west, what is the MAGNITUDE of
displacement?
Answer:
The magnitude of the displacement is [tex]H = 14.14 \ km[/tex]
Explanation:
From the question we are told that
The distance of the car to north is d = 10 km
The distance of car to the west is w = - 10 \ km
The negative sign is because the direction is west
Generally applying Pythagoras theorem , the displacement is
[tex]H = \sqrt{d^2 + w^2}[/tex]
=> [tex]H = \sqrt{(10)^2 + (-10)^2}[/tex]
=> [tex]H = 14.14 \ km[/tex]
Which two factors are used to calculate kinetic energy?
A The chemical formula for the object
B. The velocity of an object
c. The mass of an object
D. The height of an object
E . The density of an object
Answer:
B. The velocity of an object
c. The mass of an object
Explanation:
A school bus moves slower and slower. Using what you have learned about forces, explain why the bus moves slower and slower.
Explanation:
the weight of the people inside the bus
During a game of marbles, a player is trying to win a 2 g marble that is at rest. The player flicks a 1.25 g marble at a velocity of 8 at the larger marble that is sitting still. After the collision, the smaller marble has a velocity of 1 . What is the velocity of the 2 g marble after the collision? Round your answer to the nearest whole number.
Answer:
4 m/s
Explanation:jus did on edgu 2020
When you are standing in a subway train and the train suddenly stops but your body continues to move forward. Which one of Newton's laws is this?
1st law
2nd law
3rd law
4th law
Answer:
A. 1st law.
Explanation:
Newton's first law of motion states that, an object or body will continue to be at rest or experience a uniform motion in a straight line at constant speed provided there's no action of an external force. Thus, unless compelled to change its state by an external force, a body will continue to be at rest or experience a uniform motion in a straight line.
The Newton's first law of motion is also known as the law of inertia; which is the tendency of a body to be at rest unless acted upon by an external force.
In this scenario, you are standing in a subway train and the train suddenly stops but your body continues to move forward. This is in accordance with Newton's first law of motion.
Hence, the sudden stoppage of the train generates a force which acts on the body thereby causing the passenger to tip or move forward.
Make a motion chart for a cannonball launched with an initial speed of 20m/s. Neglect drag and the initial height of the cannonball. After the ball lands on the ground enter zero for all speeds and heights if necessary. Use regular metric units (ie. Meters).
Answer:
The speed and height at 0 sec are 20 m/s and 0 m.
The speed and height at 1 sec are 10.2 m/s and 15.1 m.
The speed and height at 2 sec are 0.4 m/s and 20.4 m.
The speed and height at 3 sec are 9.4 m/s and 15.9 m.
The speed and height at 4 sec are 19.2 m/s and 1.6 m.
Explanation:
Given that,
Initial speed = 20 m/s
Suppose, given time in charge are t= 0, 1, 2, 3, 4 sec
At t=0 sec,
We need to calculate the velocity and height
Using equation of motion
[tex]v=u-gt[/tex]
Put the value into the formula
[tex]v=20-9.8\times0[/tex]
[tex]v=20\ m/s[/tex]
Now, using second equation of motion
[tex]h=ut-\dfrac{1}{2}gt^2[/tex]
Put the value into the formula
[tex]h=20\times 0-\dfrac{1}{2}\times9.8\times0[/tex]
[tex]h=0\ m[/tex]
At t=1 sec,
We need to calculate the velocity and height
Using equation of motion
[tex]v=u-gt[/tex]
Put the value into the formula
[tex]v=20-9.8\times1[/tex]
[tex]v=10.2\ m/s[/tex]
Now, using second equation of motion
[tex]h=ut-\dfrac{1}{2}gt^2[/tex]
Put the value into the formula
[tex]h=20\times1-\dfrac{1}{2}\times9.8\times1^2[/tex]
[tex]h=15.1\ m[/tex]
At t=2 sec,
We need to calculate the velocity and height
Using equation of motion
[tex]v=u-gt[/tex]
Put the value into the formula
[tex]v=20-9.8\times2[/tex]
[tex]v=0.4\ m/s[/tex]
Now, using second equation of motion
[tex]h=ut-\dfrac{1}{2}gt^2[/tex]
Put the value into the formula
[tex]h=20\times2-\dfrac{1}{2}\times9.8\times2^2[/tex]
[tex]h=20.4\ m[/tex]
At t=3 sec,
We need to calculate the velocity and height
Using equation of motion
[tex]v=u-gt[/tex]
Put the value into the formula
[tex]v=20-9.8\times3[/tex]
[tex]v=-9.4\ m/s[/tex]
Negative sign shows the opposite direction of motion
Now, using second equation of motion
[tex]h=ut-\dfrac{1}{2}gt^2[/tex]
Put the value into the formula
[tex]h=20\times3-\dfrac{1}{2}\times9.8\times3^2[/tex]
[tex]h=15.9\ m[/tex]
At t=4 sec
We need to calculate the velocity and height
Using equation of motion
[tex]v=u-gt[/tex]
Put the value into th formula
[tex]v=20-9.8\times4[/tex]
[tex]v=-19.2\ m/s[/tex]
Negative sign shows the opposite direction of motion
Now, using second equation of motion
[tex]h=ut-\dfrac{1}{2}gt^2[/tex]
Put the value into the formula
[tex]h=20\times4-\dfrac{1}{2}\times9.8\times4^2[/tex]
[tex]h=1.6\ m[/tex]
So, The ball has hit the ground at 5 sec.
Hence, The speed and height at 0 sec are 20 m/s and 0 m.
The speed and height at 1 sec are 10.2 m/s and 15.1 m.
The speed and height at 2 sec are 0.4 m/s and 20.4 m.
The speed and height at 3 sec are 9.4 m/s and 15.9 m.
The speed and height at 4 sec are 19.2 m/s and 1.6 m.
Whats the difference between a solar eclipse and a lunar eclipse?
Answer:
A solar eclipse results when the moon passes in between the earth and the sun hiding the sun fully or partly for some time. A lunar eclipse occurs when the earth passes in between the moon and the sun casting its shadow on the moon and thus hiding it fully or partly for some time.
Explanation:
your welcome
Calculate the image position of an object located 25 cm from a concave lens with a focal length 5.0 cm
A man jumps from a 45 m cliff into a large body of water. How long will he fall before he enters the wate
Answer:
about 2.5 seconds depending on if he jumps up and out or if he jumps out.
Explanation:
Determine how far a vehicle moved if it started at 12 m/s and accelerated up to 47 m/s in a time of 34s.
Answer:
[tex] s = 1,003 \: m[/tex]
Explanation:
[tex]s = \frac{1}{2} (u + v)t = \frac{1}{2} (12 + 47)34 \\ s = 1,003 \: m[/tex]
A ninja applies a force of 1250-N to a piece of 4-inch solid oak with his fist. What is the size of
the force applied to the fist by the piece of oak?
Answer:
The force is 1250-N
Explanation:
Generally according to Newtons third law , which states that for every action there is an equal and opposite reaction
Now considering the question, the action here is the force applied by the ninja while the reaction is the force applied by the oak and from Newton law both of these action are equal but opposite to each other.
Hence the force applied by the the piece of oak on the fist is 1250 N
An oil drop (m = 1.6 x 10-16 kg) is suspended between plates separated by 1.8 cm. The voltage
across the plates is 125 V. Is this possible?
Answer:
E = V / d 125 V / .018 m = 6940 V/m electric field
F = E Q force on Q due to E
F = E n e where n is the number of electrons in Q
m g = E n e
n = m g / E e where n is the number of electrons e needed to support drop
n = 1.6 * 10E-16 * 9.8 / (6940 * 1.6 * 10E-19)
n = 1.41
Since n needs to be an integral number of charges, the drop would
not be suspended (motionless under these conditions).
Ahmet hits a baseball that has a mass of 0.14 kg and accelerates it to 600 m/s2. What is the force that was applied?
Answer:
F = 600N
Explanation:
F = m x a
F = Force
m = mass
a = acceleration
F = 0.14 x 600 = 84N
What is the measure of how much a material resists the formation of an electric field?
A. Permittivity
B. Dielectric
C. Capacitance
D. Resistance
Answer:
C. Capacitance
Explanation:
right on EDGE2021
What are five atomic models that have been proposed over time ?
why would it motivate Hollywood to use more realism in special effects?
Answer:
Explanation:
the search for authenticity in films, motivated Hollywood to use more realism in special effects.
HELP PLEASE
A cyclist and his bicycle have a combined mass of 88 kg and
a combined weight of 862.4 N. The cyclist accelerates at 1.2
m/s2. After 2 seconds he reaches a speed of 2.4 m/s. What is
his momentum at this point?
A. 359.3 kg.m/s
B. 105.6 kg.m/s
C. 211.2 kg-m/s
O D. 36.7 kg-m/s
The momentum of the cyclist and bicycle at this point is 211.2 kg·m/s, calculated by multiplying their combined mass (88 kg) by their velocity (2.4 m/s). The correct answer is C.
The momentum of an object is defined as the product of its mass and velocity. To find the momentum of the cyclist at this point, we can use the equation: momentum = mass × velocityFirst, let's find the mass of the cyclist and his bicycle. We are given that their combined mass is 88 kg. Next, we need to find the velocity of the cyclist. We are given that he reaches a speed of 2.4 m/s after 2 seconds, and that he accelerates at a rate of 1.2 m/s². We can use the equation of motion: velocity = initial velocity + acceleration × timeThe initial velocity is 0 m/s (since the cyclist starts from rest), the acceleration is 1.2 m/s², and the time is 2 seconds. Substituting these values into the equation, we get:For more questions on momentum
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Two conducting loops of the same diameter, #1 made of copper and #2 made of aluminum wires of the same length and cross-sections are placed on the horizontal surface in uniform magnetic field directed vertically up. Magnetic field vanishes suddenly. The magnitude of emf in loop #1 is
Answer:
Same as loop #2
Explanation:
The magnitude of emf in loop #1 is the same as that of loop #2
A delivery truck driver's round-trip route from the warehouse takes her 5 km east, then 2 km north, then 5 km west, and then 2 km south. Which of the following statements is FALSE?
they're all right, because he just took a lap and went back to the same starting point,
In the heart, what separates the oxygenated and deoxygenated blood?
A. Ventricle
B. Vessel
C.septum
D.atrium
Answer:
C. septum
Explanation:
The septum is the partition separating the right ventricle from the left ventricle. The right ventricle pumps deoxygenated blood to the lungs, and the left ventricle pumps oxygenated blood to the rest of the body.
Using the graphs on your notes, how are wavelength and frequency related to sound waves? Make sure to use proper terminology in your response.
Why does frost bite occur in mountain climbers ?
Answer:
Because they are in places that may be extremely cold
Explanation:
For example take Mount Everest. This place is a very high mountain, and is very cold. Usually hikers would get a frost bite from how cold it is in there. According to google, "Frostbite is an injury caused by freezing of the skin and underlying tissues."
Which three factors are used to calculate gravitational potential energy?
A. The mass of an object
B. The acceleration of an object due to gravity
C. The density of an object
D. The velocity of an object
E. The chemical formula for an object
F. The height of an object
Answer: height, mass, and acceleration.
Explanation:
Answer:
height, mass, and acceleration.
or a,b,f
Explanation:
A marble accelerates from rest at a constant rate .it travels 36 m in 12.0 sec what’s is it’s final velocity and what was the acceleration
Answer:
a = 0.50 m/s²
v = 6.0 m/s
Explanation:
Step 1: Given data
Initial velocity (u): 0 m/s (rest)Displacement of the marble (s): 36 mTime elapsed (t): 12.0 sFinal velocity (v): ?Acceleration (a): ?Step 2: Calculate the acceleration
We will use the following suvat equation.
s = u × t + 1/2 × a × t²
s = 0 × 12.0 s + 1/2 × a × (12.0 s)²
36 m = a × 72.0 s²
a = 0.50 m/s²
Step 3: Calculate the final velocity
We will use the following suvat equation.
v = u + a × t
v = 0 + 0.50 m/s² × 12.0 s
v = 6.0 m/s
Which of these consumers is an herbivore? *
1. lion
2. deer
3. spider
4. snake
Answer:
2. deer
Explanation:
The lion, spider, and snake eat meat or to an extent.
Deer don't eat meat
Answer:
deer :)
Explanation:
The rest are basically carnivores
Which of the following scenarios is possible for the resultant velocity of an airplane in a strong wind to be 150 m/s?
A. The wind is blowing at 10 m/s. The airplane is flying against the wind at 140 m/s.
B. The wind is blowing at 20 m/s. The airplane is flying with the wind at 130 m/s.
C. The wind is blowing at 200 m/s. The airplane is flying with the wind at 50 m/s.
D. The wind is blowing at 50 m/s. The airplane is flying against the wind at 100 m/s.
Answer:
B. The wind is blowing at 20 m/s. The airplane is flying with the wind at 130 m/s.
Explanation:
From Physics we get that resultant velocity of an airplane is the sum of an absolute velocity and a relative velocity, that is:
[tex]\vec v_{A} = \vec v_{W}+\vec v_{A/W}[/tex] (Eq. 1)
Where:
[tex]\vec v_{W}[/tex] - Wind velocity, measured in meters per second.
[tex]\vec v_{A/W}[/tex] - Airplance velocity relative to wind, measured in meters per second.
[tex]\vec v_{A}[/tex] - Airplane velocity, measured in meters per second.
If we assume that [tex]\vec v_{W} = 20\,\hat{i}\,\,\,\left[\frac{m}{s} \right][/tex] (The airplane flies with the wind), [tex]\vec v_{A/W} = 130\,\hat{i}\,\,\,\left[\frac{m}{s} \right][/tex], then the resultant velocity of the airplane is:
[tex]\vec v_{A} = 20\,\hat{i}+130\,\hat{i}\,\,\,\left[\frac{m}{s} \right][/tex]
[tex]\vec v_{A} = 150\,\hat{i}\,\,\,\left[\frac{m}{s} \right][/tex]
Therefore, correct answer is B.
Answer:
B. The wind is blowing at 20 m/s. The airplane is flying with the wind at 130 m/s.
Explanation:
Holden is trying to determine the velocity of his race car. He went 20 meters east, turned around, and went 40 meters west. He turned the car one more time and went 35 meters east. His car was 15 meters from the starting line. This took 5 seconds.
What is the car’s velocity?
Answer:
3 m/s east
Explanation:
I took a test a got it right
Answer:
3 m/s east
Explanation:
Click The Pros and Cons of Plastics and use the information to answer the question.
Which scenario shows an indirect environmental impact of using plastics?
Answer:
Plastics being consumed by fish and passing toxic compounds to the humans eat the fish.
Explanation:
I did that answer and got it right.
Answer:
Plastics being consumed by fish and passing toxic compounds to the humans that eat the fish.
Explanation:
4. Vector A is 7.00 units in length and points along the positive x-axis. Vector B is 5.00 units in length and points along the negative x-axis. find the magnitude and direction of A+2B 1 point
Answer:
Since the two vectors form a right angle, no components need to be found for the resultant vector - we already have them!
Vector R's x-component = 3.00 units
Vector R's y-component = 4.00 units
To solve for the magnitude of the displacement, use the distance formula: Square Root of [(3)^2 + (4)^2], which equals 5 units.
To solve for the direction of the displacement, plug in -4 (remember where it was pointing) for y and 3 for x. Tan-1(-4/3) = -53.13°, or 53.13° south of east.Please Mark as Brilliant
The magnitude of vector C is |C| = 3 and It is directed along the negative x - axis.
What is vector quantity?
A vector quantity is a quantity with both magnitude and direction.
Given is vector A is 7.00 units in length and points along the positive x-axis. and vector B is 5.00 units in length and points along the negative x-axis.
Vector A = 7 a[x]
Vector B = - 5 a[x]
Therefore, the given expression to be evaluated is -
C = A + 2B
C = 7 a[x] + 2(- 5 a[x])
C = 7 a[x] - 10 a[x]
C = - 3 a[x]
So, the magnitude of vector C is -
|C| = 3
It is directed along the negative x - axis.
Therefore, the magnitude of vector C is |C| = 3 and It is directed along the negative x - axis.
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The distance between a scalar and a vector is that a vector quantity includes what
Answer:
magnitude and direction e.g acceleration,displacement