Police radar guns measure the speed of moving vehicles by transmitting electromagnetic waves at a vehicle and detecting a Doppler shift in the reflected wave. Suppose police radar transmits at a frequency of 24.0 GHz and receives a wave reflected from a car moving toward the radar at 65.0 mph. Find the frequency shift Df 5 fO 2 fS between the observed (received) and source (transmitted) frequencies.

Answers

Answer 1

Answer:

[tex]4649.20\ \text{Hz}[/tex]

Explanation:

u = Speed of car = 65 mph

[tex]f_s[/tex] = Frequency of source = 24 GHz

c = Speed of light = [tex]3\times 10^8\ \text{m/s}[/tex]

Beat frequency or frequency shift between the observed (received) and source (transmitted) frequencies is given by

[tex]f_o-f_s=\dfrac{2uf_s}{c}\\\Rightarrow \Delta f=\dfrac{2\times 65\times \dfrac{1609.34}{3600}\times 24\times 10^9}{3\times 10^8}\\\Rightarrow \Delta f=4649.20\ \text{Hz}[/tex]

The difference between te required frequencies is [tex]4649.20\ \text{Hz}[/tex].


Related Questions

A running Marites launched the egg she
stole as she was about to be caught with
a velocity of 25 m/s in a direction making
an angle of 20° upward with the
horizontal
a) What is the maximum height reached by
the egg?
b) What is the total flight time (between
launch and touching the ground) of the
egg?
c) What is the horizontal range (maximum
* above ground) of the egg?
d) What is the magnitude of the velocity
of the egg just before it hits the ground?

Answers

Answer:

a)   y = 3.73 m,  b)  t = 1.74 s,  c)  R = 40.99 m,

d) vₓ  = 23.49  m/s,   v_y = -8.5 m / s

Explanation:

This is a projectile launching exercise, we start by breaking down the initial velocity

          sin θ = v_{oy} / v₀

          cos θ = v₀ₓ / v₀

          v_{oy} = v₀ sin θ

          v₀ₓ = v₀ cos θ

          v_{oy} = 25 sin 20 = 8.55 m / s

          v₀ₓ = 25 cos 20 = 23.49 m / s

a) when the egg reaches the maximum height its vertical speed is zero

          v_y² = v_{oy}² - 2 g y

          0 = v_[oy}² - 2g y

           y = v_{oy}² / 2g

          y = [tex]\frac{8.55^2}{2 \ 9.8 }[/tex]

          y = 3.73 m

b) flight time

          y = v_{oy} t - ½ g t²

the time of flight occurs when the body reaches the ground y = 0

          0 = (v_{oy} - ½ g t) t

         

The results are

          t₁ = 0s        this time is for using the body star

          v_{oy} - ½ g t = 0

           t = [tex]\frac{2v_{oy}^2}{g}[/tex]

           t = 2 8.55 / 9.8

           t = 1.74 s

c) the range

           R = v₀² sin 2θ / g

           R = 25² sin (2 20) / 9.8

           R = 40.99 m

d) speed at the point of arrival

horizontal speed is constant

           vₓ = v₀ₓ = 23.49  m/s

vertical speed is

           v_y = Iv_{oy} - g t

           v_y = 8.55 - 9.8  1.74

           v_y = -8.5 m / s

What is the term that describes waves that require a medium through which to travel?

Answers

Answer:

Mechanical waves are waves that require a medium. This means that they have to have some sort of matter to travel through. These waves travel when molecules in the medium collide with each other passing on energy. One example of a mechanical wave is sound.

Earth's neighboring galaxy, the Andromeda Galaxy, is a distance of 2.54×107 light-years from Earth. If the lifetime of a human is taken to be 90.0 years, a spaceship would need to achieve some minimum speed vmin to deliver a living human being to this galaxy. How close to the speed of light would this minimum speed be? Express your answer as the difference between vmin and the speed of light c.

Answers

Answer:

[tex]0.0018833\ \text{m/s}[/tex]

Explanation:

[tex]d[/tex] = Distance of Andromeda Galaxy from Earth = [tex]2.54\times 10^7\ \text{ly}[/tex]

[tex]t[/tex] = Time taken = [tex]90\ \text{years}[/tex]

[tex]c[/tex] = Speed of light = [tex]3\times 10^8\ \text{m/s}[/tex]

We have the relation

[tex]t=t_o\sqrt{1-\dfrac{v^2}{c^2}}\\\Rightarrow 90=2.54\times 10^7\sqrt{1-\dfrac{v^2}{c^2}}\\\Rightarrow \dfrac{90^2}{(2.54\times 10^7)^2}=1-\dfrac{v^2}{c^2}\\\Rightarrow 1-\dfrac{90^2}{(2.54\times 10^7)^2}=\dfrac{v^2}{c^2}\\\Rightarrow v=c\sqrt{1-\dfrac{90^2}{(2.54\times 10^7)^2}}[/tex]

[tex]c-v=c(1-\sqrt{1-\dfrac{90^2}{(2.54\times 10^7)^2}})\\\Rightarrow c-v=3\times 10^8(1-\sqrt{1-\dfrac{90^2}{(2.54\times 10^7)^2}})\\\Rightarrow c-v=0.0018833\ \text{m/s}[/tex]

The required answer is [tex]0.0018833\ \text{m/s}[/tex].

The diagram shows a charge moving into an electric field. The charge will most likely leave the electric field near which letter? OW OX OY OZ ​

Answers

you haven't attached the diagram, but i assume that this diagram is what you were talking about

Answer:

near Y

Explanation:

the electric field lines goes from a positive charge to a negative charge. This means that a positive charge would move in the same direction of the field lines, while a negative charge would move in the opposite direction of the field lines. the field lines are created from +vely charged plate to -vely charged plate so the negative charged particles moves towards the lower plate which is positively charged, and opposite to the direction of field lines.

The charge will most likely leave the electric field near Y letter. Hence option C is correct.

What is electric charge ?

Electric charge is the physical property of matter that experiences force when it is placed in electric field. F = qE where q is amount of charge, E = electric field and F = is force experienced by the charge. there are two types of charges, positive charge and negative charge which are generally carried by proton and electron resp. like charges repel each other and unlike charges attract each other. the flow charges is called as current. Elementary charge is amount of charge a electron is having, whose value is 1.602 x 10⁻¹⁹ C

The charge on the electron is negative, and the force is directed in the opposite direction as the electric field. When an electron is projected perpendicular to a uniform electric field, it experiences an electric force in the opposite direction of the field.

the trajectory of the charged particle in the electric filed is parabolic and in magnetic field it is circular. when this electron moves perpendicular to the electric field, electron experience force in opposite direction to the electric field and due to parabolic nature, it will leave at Y.

Hence option C is correct.

To know more about Electric field :

https://brainly.com/question/8971780

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19. What is shape of BF3​

Answers

Explanation:

The geometry of the BF 3 molecule is called trigonal planar (see Figure 5). The fluorine atoms are positioned at the vertices of an equilateral triangle. The F-B-F angle is 120° and all four atoms lie in the same plane.

A 4 kg box is at rest on a table. The static friction coefficient u, between the box and table is 0.30, and
the kinetic friction coefficient Hi is 0.10. Then, a 10 N horizontal force is applied to the box.

Answers

Answer:

The box will not move from its position.

Explanation:

First, we will calculate the static frictional force that is stopping the box to move from its position:

[tex]f = \mu R = \mu W=\mu mg[/tex]

where,

f = static frictional force = ?

μ = coefficient of static friction = 0.3

m = mass of box = 4 kg

g = acceleration due to gravity = 9.81 m/s²

Therefore,

[tex]f = (0.3)(4\ kg)(9.81\ m/s^2)\\f=11.77\ N[/tex]

Since the frictional force (11.77 N) is greater than the applied force (10 N).

Therefore, the box will not move from its position.

What happens when Molecules collide?

Answers

Answer:

Collision theory is used to predict the rates of chemical reactions, particularly for gases. It is based on the assumption that for a reaction to occur for the reacting species (atoms or molecules) must come together or collide with one another. Not all collisions, however, bring about chemical change.

If two molecules collide with sufficient activation energy, there is no guarantee that the collision will be successful. In fact, the collision theory says that not every collision is successful, even if molecules are moving with enough energy. The reason for this is because molecules also need to collide with the right orientation so that the proper atoms line up with one another, and bonds can break and re-form necessarily.

what is the relationship between Force, area and mass​

Answers

Answer:

F=ma

Explanation:

Force is equal to mass multiplied by area

Force= mass × area

In turn the formula can be twisted so

Force/mass= area

Force/area= mass

Answer:

It states that the rate of change of velocity of an object is directly proportional to the force applied and takes place in the direction of the force. It is summarized by the equation: Force (N) = mass (kg) × acceleration (m/s²). Thus, an object of constant mass accelerates in proportion to the force applied.

what is friction and the types withe examples.​

Answers

Explanation:

The answer is In the picture. Thanks.

Suppose a 65 kg person stands at the edge of a 6.5 m diameter merry-go-round turntable that is mounted on frictionless bearings and has a moment of inertia of 1850 kgm2. The turntable is at rest initially, but when the person begins running at a speed of 3.8 m/s (with respect to the turntable) around its edge, the turntable begins to rotate in the opposite direction. Calculate the angular velocity of the turntable. (Hint: use what you know about relative velocity to help solve the problem

Answers

Answer:

[tex]0.3165\ \text{rad/s}[/tex]

Explanation:

m = Mass of person = 65 kg

d = Diameter of round table = 6.5 m

r = Radius = [tex]\dfrac{d}{2}=3.25\ \text{m}[/tex]

v = Velocity of person running = 3.8 m/s

[tex]I_t[/tex] = Moment of inertia of turntable = [tex]1850\ \text{kg m}^2[/tex]

Moment of inertia of the system is

[tex]I=I_t+mr^2\\\Rightarrow I=1850+65\times 3.25^2\\\Rightarrow I=2536.5625\ \text{kg m}^2[/tex]

As the angular momentum of the system is conserved we have

[tex]L_i=L_f\\\Rightarrow mvr=I\omega_f\\\Rightarrow \omega_f=\dfrac{mvr}{I}\\\Rightarrow \omega_f=\dfrac{65\times 3.8\times 3.25}{2536.5625}\\\Rightarrow \omega_f=0.3165\ \text{rad/s}[/tex]

The angular velocity of the turntable is [tex]0.3165\ \text{rad/s}[/tex].

A long time ago on top of a mountain, the rocks were jagged and pointy. Over thousands of years, the rocks have become smooth.

What process explains this change?


pulling

weathering

depositing

eroding

Answers

Answer:

Eroding

Explanation:

A long time ago on top of a mountain, the rocks were jagged and pointy. Over thousands of years, the rocks have become smooth. The process explains this change is Eroding. Hence, Option D is the correct answer.

What is Erosion?

Erosion is  a  process  of  eroding some solids by wind, water and other  natural  agent  while  weathering  is  breaking  down  of  rocks, soil  and  minerals.

 

The  different types of Erosion includes,

Gully erosionsheet  erosionRill  erosionsheet  erosion

These factors that will contribute to the rate of water erosion includes the climatic factor (rainfall amount, intensity and frequency).

TopographySoil coverSoil properties

Mass wasting erosion if it is a type of erosion but not by water. It is a type of erosion that is generated mainly by the effect of gravity. It is also called mass movement, in which the material detaches from an inclined surface and falls as a result of gravity.

Here, A long time ago on top of a mountain, the rocks were jagged and pointy. Over thousands of years, the rocks have become smooth. The process explains this change is Eroding. Hence, Option D is the correct answer.

Learn more about Erosion,

https://brainly.com/question/7567484

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9. Mr. Smith went skiing in Maine last weekend. He traveled 523 kilometers to Sugarloaf from
Leominster. His average speed was 109 km/hr. How long did it take Mr. Smith to hit the slopes?

Answers

Answer:

Time taken by Mr. smith = 4.80 hour (Approx.)

Explanation:

Given:

Distance travel by Mr. smith = 523 kilometer

Average speed of Mr. smith = 109 km/hr

Find;

Time taken by Mr. smith

Computation:

Time taken = Distance cover / Speed

Time taken by Mr. smith = Distance travel by Mr. smith / Average speed of Mr.

smith

Time taken by Mr. smith = 523 / 109

Time taken by Mr. smith = 4.798 hr

Time taken by Mr. smith = 4.80 hour (Approx.)

A coil of resistance 100ohm is placed in a magnetic field of 1mWb the coil has 100 turns and a galvanometer of 400ohm resistance is connected in series with it. find the average emf and the current if the coil is moved in one tenth of a second from the given field to a field of 2.0mWb​

Answers

Answer:

C

Explanation:

C

A ray diagram is shown. A tree acts as the object further than 2 F away from a biconvex lens. The distance between 2 F and the object is labeled W. The distance between F and 2 F is labeled X. There I a light ray parallel to the principal axis is bent through F on the image side of the lens. There is a ray straight through the center of the lens. The rays intersect a point below the principle axis between F and 2 F on the image side of the lens and is closer to the principal axis than the object is tall. The intersect point is labeled Z and the distance between F and 2 F on the image side of the lens is labeled Y. Which letter represents the location of the image produced by the lens? W X Y Z

Answers

Answer:

Z

Explanation:

correct on edge

Answer: Z

good luck!

You are locked inside the train car and want to get it moving to draw attention to your plight. There is effectively no friction between the axle and the car, and the train is on horizontal tracks. To try and get the car moving with respect to the ground, you run and slam with all your force against the wall at the front. What happens with the car after you slammed against the wall of the car

Answers

Answer:

the car movves briefly as you ran, however, it stops again after you ran in to the wall

Explanation:

Our net total linear momentum was zero at the time both the train and the boy was at rest. As there is no pressure, the train and boy system's linear momentum can be conserved provided no external forces are working on it that might shift its momentum.

If the boy runs inside of the train with a velocity V1 in the forward direction, the train would have a velocity V2 in the reverse direction to V1 to conserve the system's momentum, resulting in Final momentum.

i.e

[tex]m \times V_1 + M \times V_2 = 0[/tex]  --- (1)

here;

m = mass of the boy

M = mass of the train

Thus;

[tex]m \times V_1 =- M \times V_2[/tex] --- (2)

As the boy crashes into the train's wall, a pair of equal and opposing force F intervene on both the train and the boy. This force F causes the boy traveling with momentum m× V1 to come to a halt; its momentum remains zero. As the train moves with about the same momentum as the boy as seen in (2) and is subjected to the same force F, its momentum will be diminished to zero, and it will come to a halt.

PLZ help 10 points!!! space question!

Answers

Answer:

3 i think

Explanation:

The answer is the bottom one all planets can not really all be compared

The half-life for a 400-gram sample of radioactive element X is 3 days. How much of element X remains after 15 days have passed?

A.
12.5 g

B.
25 g

C.
50 g

D.
100 g

Answers

The answer to your question is B!!

How many times a minute does a boat bob up and down on ocean waves that have a wavelength of 35.6 m and a propagation speed of 4.68 m/s? (the answer may not be a whole number)

Answers

Answer:

It will bob 7.887640449 times a minute

Explanation:

I hope this is correct!!

physics grade9 teacher guide​

Answers

Answer:

huh

Explanation:

(a) Neil A. Armstrong was the first person to walk on the moon. The distance between the earth and the moon is 3.85 x 108 m. Find the time it took for his voice to reach earth via radio waves. (b) Someday a person will walk on Mars, which is 5.6 x 1010 m from earth at the point of closest approach. Determine the minimum time that will be required for that person's voice to reach earth.

Answers

Answer:

a). 1.28333 seconds

b). 186.66 seconds

Explanation:

a). Given :

Distance between the earth and the moon, d = [tex]$3.85 \times 10^8$[/tex] m

Speed of the radio waves, c = [tex]$3 \times 10^8$[/tex] m/s

Therefore the time required for the voice of Neil Armstrong to reach the earth via radio waves is given by :

[tex]$t=\frac{d}{c}$[/tex]

 [tex]$=\frac{3.85 \times 10^8}{3 \times 10^8}$[/tex]

 = 1.28333 seconds

b). Distance between Mars and the earth, d = [tex]$5.6 \times 10^{10}$[/tex] m

   Speed of the radio waves, c = [tex]$3 \times 10^8$[/tex] m/s

So, the time required for his voice to reach earth is :

[tex]$t=\frac{d}{c}$[/tex]

 [tex]$=\frac{5.6 \times 10^{10}}{3 \times 10^8}$[/tex]

 = 186.66 seconds

A candle is placed 50 cm from a diverging lens with a focal length of 28. What is the image distance in cm.

Answers

Answer:

v = -17.94 cm

Explanation:

Given that,

The candle is placed at a distance of 50 cm, u = -50 cm

The focal length of the diverging lens, f = -28 cm (negative in case of a concave lens)

We need to find the image distance. We know that the lens formula is as follows:

[tex]\dfrac{1}{v}-\dfrac{1}{u}=\dfrac{1}{f}\\\\\dfrac{1}{v}=\dfrac{1}{f}+\dfrac{1}{u}\\\\\dfrac{1}{v}=\dfrac{1}{(-28)}+\dfrac{1}{(-50)}\\\\v=-17.94\ cm[/tex]

So, the image distance is equal to 17.94 cm.

Identical satellites X and Y of mass m are in circular orbits around a planet of mass M. The radius of the planet is R. Satellite X has an orbital radius of 3R, and satellite Y has an orbital radius of 4R. The kinetic energy of satellite X is Kx . Satellite X is moved to the same orbit as satellite Y by a force doing work on the satellite. In terms of Kx , the work done on satellite X by the force is

Answers

Answer:

The work down on satellite X by the force in terms of Kx is [tex]\dfrac{-K_x}{4}[/tex].

Explanation:

The work done is given as in terms of

[tex]W=\Delta TE[/tex]

Where ΔTE is the change in total energy.

This is given as

[tex]W=\Delta TE\\W=TE_y-TE_x\\W=\dfrac{-GMm}{2(4R)}-\dfrac{-GMm}{2(3R)}\\W=\dfrac{-GMm}{8R}+\dfrac{GMm}{6R}\\W=\dfrac{-6GMm+8GMm}{48R}\\W=\dfrac{2GMm}{48R}\\W=\dfrac{GMm}{24R}[/tex]

Rearranging it in  terms of K_x gives

[tex]W=\dfrac{GMm}{24R}\\W=\dfrac{GMm}{-4\times -6R}\\W=\dfrac{1}{-4}\dfrac{-GMm}{6R}\\W=\dfrac{1}{-4}\dfrac{-GMm}{2(3R)}\\W=\dfrac{1}{-4}K_x\\W=\dfrac{-K_x}{4}[/tex]

A block and tackle of 6 pulleys is used to raise a load of 300 newton steadily through a height of 30 meters. If the work done against friction is 2000j calculate the work done by effort?

Answers

Answer:

W = F * S = 300 N * 30 m = 9000 Joules

This is the work out of the system regardless of how the pulleys are arranged

Conservation of energy tells that

Work Out = Work In - Work done by friction

So Work In = 9000 J + 2000 J = 11000 J      The work input to the system

has been proposed to use an array of infrared telescopes spread over thousands of kilometers of spaceto observe planets orbiting other stars. Consider such an array with an effective diameter of 6000 km, whichobserves infrared radiation at a wavelength of 10m. If it is used to observe a planet orbiting the star 70Virginis, which is 59 light years from our solar system, what is the size of the smallest details that the arraymight resolve on the planet

Answers

Answer:

[tex]\triangle x=1.135 *10^9km[/tex]

Explanation:

From the question we are told that:

Diameter of array[tex]d=6000km \approx 6000*10^3[/tex]

Infrared wavelength [tex]\lambda =10m[/tex]

Distance of planet [tex]d=59 light\ years \approx 55.82*10^{16}m[/tex]

 

Generally the equation for Diffraction is mathematically given by

 [tex]sin\theta =1.22\frac{\lambda}{D}[/tex]

Given that

 [tex]sin\theta=\frac{\triangle x}{R}[/tex]

Therefore

 [tex]\frac{\triangle x}{R}=1.22\frac{\lambda}{D}[/tex]

 [tex]\triangle x=1.22\frac{R \lambda}{D}[/tex]

 [tex]\triangle x=1.22\frac{10 *55.82*10^{16}}{6000*10^3}[/tex]

 [tex]\triangle x=1.135 *!0^1^2m[/tex]

 [tex]\triangle x=1.135 *10^9km[/tex]

Think of a hydropower dam . How is electrical energy produced from potential and kinetic energy ?

Answers

hydroelectric dam converts the potential energy stored in a water reservoir behind a dam to mechanical energy—mechanical energy is also known as kinetic energy. ... The generator converts the turbine's mechanical energy into electricity.

Hope this helps!

Answer:

Potential energy and kinetic energy are constituents of mechanical energy.

When a turbine is switched on, it rotates with mechanical energy.

Since a motor runs the turbine, it converts this mechanical energy to electrical energy.

HURRY IM TIMED

How can you make people feel inspired?

By leading them on an emotional journey through various states to inspiration
By talking about something that interests you
By proving yourself to be a trustworthy speaker
By making them laugh and feel comfortable

Answers

Answer:

By talking about something that interesto you’

sorry if wrong

Explanation:

Describing a Wave
What does a wave carry?

Answers

Answer:

Waves carry energy from one place to another.

Explanation:

Because waves carry energy, some waves are used for communication, eg radio and television waves and mobile telephone signals.

It carries energy from one area to another

Philosophy: The Big Picture Unit 8

How does pragmatism differ from the utilitarianism of the previous era?

A. Utilitarianism did not consider rights and pragmatism did.
B. Pragmatism is concerned with function, utilitarianism with happiness.
C. Utilitarianism was created in England and pragmatism came from Germany.
D. Pragmatism applies to everyone, but utilitarianism is concerned with the upper class.

Answers


D. Pragmatism applies to everyone, but utilitarianism is concerned with the upper class.

How long will it take you to drive, at 80km/h a distance of 275km?

Answers

Answer:

3.44 s

Explanation:

speed=distance/time

=>t = s/v

=> t = 275/80

= 3.437.. s

Select the correct answer.
Each square dance begins with what?
A. Handshake
B. Dosado
C. Bow or curtsy
D. Promenade

Answers

Answer:

C

Explanation:

The men bow to the women and the women curtsy to the men.

(took on test and got it right)

Other Questions
People please help me.Use the correct form of the adjectives.1.The Europa Hotel is (expensive) than the Grand Hotel.2.Yesterday it was as (rainy) as it is today.3.That is the (old) building in the town.4.My room isn't as (big) as yours.5.It was (hot) day of the year.6.You are a (good) cook than I am.7.This is (bad) football match I ever seen.8.Kate is as (clever) as her (old) sister.9.John came home (early) than usual.10.Money is not (important) thing in life.11.This tomato ketchup is (tasty) than the other one.12.Sydney is (large) city in Australia. Which survey is biased? A. Going to the mall and asking people what their favorite color is. B. Going to the mall and asking people what their favorite place to shop is. C. Going to the mall and asking people what television channel they watch most. D. Going to the mall and asking people what radio station they listen to most often. From the set {7, 15, 18), which of the values can be substituted for c to make theequation true.90 - 2c = 60A. 7B. 18C. none of theseD. 15 Use the law of sines to find the value of a.B95D40a4.7 cmsin(A)asin(B)Law of sines:sin(C)C How do people use checking accounts differently from the way they use savings accounts? People use checking accounts to deposit money earned from their primary jobs, while people use savings accounts to deposit money earned from second or third jobs and gifts. I put in 100 points People write checks or use debit cards to pay for goods and services with the money in checking accounts, while the money in savings accounts is not generally accessed as frequently. People use checking accounts to build up funds over long periods of time in the hopes of making large purchases, while people use the funds in savings accounts to meet their regular expenses. People open checking accounts if they will not need to access the money deposited in them for several months or years, while people open savings accounts if they will need to access the money deposited in them much sooner. A pool company needs to make a cover for an in-ground pool. The pool cover is made up of the triangle PQT and the parallelogram MNPR. How many square feet of fabric will the company need to cover the pool? 5 tons of fertilizer cost $14,100.00. What is the price per pound? Directions: Select all the correct answers.Yvette needs 5/8 of a teaspoon of salt, 2/3 of a tablespoon of baking soda, and 3/4 of a cup of sugar to bake a cake.The order of the measurements from least to greatest are 5/8 < 3/4 < 2/3.The order of the measurements from least to greatest are 5/8 < 2/3 < 3/4.The numbers 5/8 and 3/4 are terminating decimals while 2/3 is a non-terminating decimal.The numbers 5/8 and 2/3 are terminating decimals.The number 5/8 is a terminating decimal while 3/4 and 2/3 are non-terminating decimals.The number expands to 0.75 while expands to 0.6.The number 5/8 expands to 0.625 while 3/4 expands to 0.75.The order of the measurements from least to greatest are 2/3 < 5/8 < 3/4 The shareholders equity for the Fiesta Foods, Inc. on December 31, 2010 follows: 12% Preference share capital, P100 par, 20,000 shares P2,000,000 Ordinary share capital, P25 par, 200,000 shares 5,000,000 Share premium 500,000 Retained earnings 750,000 Total shareholders equity P8,250,000 Preference shares have a liquidation value of P110; shares are cumulative, with dividends in arrears for 3 years including the current year and fully payable in the event of liquidation. The book value of an ordinary share is Group of answer choices 26.65 25.35 28.95 22.90 In 2019, Vaughn sold 3000 units at $500 each. Variable expenses were $250 per unit, and fixed expenses were $550000. The same selling price is expected for 2020. Vaughn is tentatively planning to invest in equipment that would increase fixed costs by 20%, while decreasing variable costs per unit by 20%. What is Vaughns break-even point in units for 2020? 2200. 3300. 2750. 2640. Explain why reflecting on work activities is an important develop your knowledge and skills With example What is a precipitation reaction? What strategies can help promote healthy relationships with parents or guardians and siblings? A student conducted an experiment to test the strength differences between an orb spider's web and a black widow spider's web. The student calculated the strength of the wob by using the number of seconds each web held a 4 gram weight What type of results did the student calculate in this experiment? A) Qualitative resultsB) Problem-solving resultsC) Hypothetical resultsD)Quantitative results The amount of interest accrued ona $7,000 loan with 6% interest after t years. Elias combined his own background knowledge with details from a text. Then, he drew a conclusion that the lead character was brave. This is an example ofa)a physical trait of a character.b)direct characterization of a character.c)an inference about a character.d)indirect characterization of a character. The expectation of a future devaluation of a fixed exchange rate will lead to Select an answer and submit. For keyboard navigation, use the up/down arrow keys to select an answer. a a sharp rise in reserves and a rise in the domestic interest rate above the world interest rate. b a sharp fall in reserves and an unchanged domestic interest rate. c a sharp fall in reserves and a rise in the domestic interest rate above the world interest rate. d a sharp rise in reserves and a fall in the domestic interest rate below the world interest rate. please help it's the last question Select the equation of a straight line that is parallel to the line 4y = 3x + 5. Y=-2x find Oder pairs