PLZ HURRY! Kaylie wants to see how metals can be combined. She found a problem to solve. Help her solve it! How many pounds of a metal containing 20% nickel must be combined with 6 pounds of a metal containing 80% nickel to form an alloy containing 60% nickel?

Kaylie needs 3 pounds of the 20% nickel metal to combine with 6 pounds of the 80% nickel metal to form an alloy containing 60% nickel.

To solve the problem, we can use the concept of weighted averages. The first step is to determine the amount of nickel in each metal before they are combined.

For the 20% nickel metal, 20% of the metal is nickel. Therefore, the amount of nickel in x pounds of this metal is 0.2x.

For the 80% nickel metal, 80% of the metal is nickel. Therefore, the amount of nickel in 6 pounds of this metal is 0.8(6) = 4.8 pounds.

Next, we can use the weighted average formula to determine the amount of nickel in the alloy:

0.2x + 4.8 = 0.6(x + 6)

Simplifying the equation:

0.2x + 4.8 = 0.6x + 3.6

0.4x = 1.2

x = 3

Therefore, Kaylie needs 3 pounds of the 20% nickel metal to combine with 6 pounds of the 80% nickel metal to form an alloy containing 60% nickel.

In summary, to determine the amount of metal-containing 20% nickel needed to combine with 6 pounds of metal containing 80% nickel to form an alloy containing 60% nickel, we used the concept of weighted averages and found that Kaylie needs 3 pounds of the 20% nickel metal.

To know more about nickel refer here:

https://brainly.com/question/14221416#

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The scatterplot shown below represents data for each of the years from 2006
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37°, 40°, 103°

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