Answer:
B, A, E, D, C
Explanation:
If the arrow points to the right, then the force is positive.
If the arrow points to the left, then the force is negative.
Also, remember that the force does not relate (necessarily) to the mass, so the different blocks having different masses is not an important factor in this problem.
Let's find the force in each block.
A)
Here we have a positive force of 3N and a negative force of 1N
Then the net force (the sum of all the forces) is:
F = 3N - 1N = 2N
B)
Here we have two positive forces, one of 1N and other that I cant see, I guess that it is 3N
Then the net force is:
F = 1N + 3N = 4N
C)
Here we have two negative forces of 2N
Then the net force is:
F = - 2N + ( - 2N) = -4N
D)
Here we have a single force of 2N that is negative, then the net force is:
F = -2N
E)
Here we have a negative force of 3N and a positive force of 2N
then the net force is:
F = -3N + 2N = -1N
Then, the order of greatest to least (from positive to negative) is:
B, A, E, D, C
what is the power of a student that has done a work of 10 joules in 10 seconds
Answer:
1 Watt
Explanation:
P=W/t
P=10/10
P=1 Watt
La resistividad de cierto alambre es 1.72x10 -8 Ωm a 20 oC .Una batería de 6v se conecta a una bobina de 20 m de este alambre, con un diámetro de 0.8 mm. ¿Cuál es la corriente en el alambre?
Answer:
i = 1.09 10⁴ A
Explanation:
For this exercise we will look for the resistance of the wire
R = ρ L / a
the area of the wire is
a =ππ r² = π πd² / 4
we substitute
R = ρ L 4 / π d²
R = 1.72 10⁻⁸ 20 4/π 8 10⁻⁴
R = 5.47 10⁻⁴ Ω
to calculate the current we use ohm's law
V = R i
i = V / R
i = 6 / 5.47 10⁻⁴
i = 1.09 10⁴ A
Pop up spring Lab
Describe the energy conversion that took place. What energy was present just before the jump? What energy is present at its maximum height? What happens in between?
Draw bar charts of energy before the jump, while the spring toy is compressed and after the jump at the maximum height of its jump. Be sure to label each type of energy.
Answer:
I honestly don't know but that thing looks cool lol
Follow-up Questions
1.
How much stress do you think?
Warm air is less dense than cold air. The same is true of water. You decide to take a bath and turn on both the hot and cold faucets. When the tub is one-third full, you dip your hand in and discover the water is too cold. You turn the cold water faucet off and keep the hot water turned on. You leave the hot water running for ten minutes. When you return and dip your hand in, you discover that the water in the tub is different temperatures in different places. It is too hot close to the faucet and in a top layer across the entire tub. When you sit down, however, the water in the bottom of the tub is cold. Explain how this happens and why: • how the hot water ended up in a layer on the top and near the faucet. • why this is or is not a transfer of heat. • how the temperature of the water in the tub will change over time. • why you will eventually want to get out of the tub, considering the air and your porcelain enameled steel tub.
Answer:
Given that the warm water is less dense than the cold water, we have;
The cold water which is more dense than the warm water will remain settled in the lower part of the tub while particles of the less dense warm water will move above the cold water not being able to penetrate lower due of difference in their gravitational potential energiesThis is a case of (lack of) heat transfer due to inability of heat to penetrate into the lower layers and transfer the heat by conduction, from particle to particle, and therefore, one layer, the top remains warm while the other layer, the lower layer, remains coldWith time (over an hour) more and more warm water units will be able to penetrate deeper and make the lower layer warmer while the warm water at the top loses heat by evaporation to the atmosphere, until the entire water reaches equilibriumHeat will continue to be lost by evaporation to the air and by conduction through the porcelain to the steel tub until the water in the tub becomes coldExplanation:
One pot has a water height of 8cm. Calculate the water pressure at the bottom of the pot. They give g = 10N / kg p = 1000kg / m3
Answer:
P = 800 Pa
Explanation:
The pressure of water at the bottom of the pot can be given by the following formula:
[tex]P = \rho g h[/tex]
where,
P = Pressure at the bottom of the pot = ?
ρ = density = 1000 kg/m³
h = height of water = 8 cm = 0.08 m
Therefore,
[tex]P = (1000\ kg/m^3)(10\ m/s^2)(0.08\ m)[/tex]
P = 800 Pa
A car travels from A to B and from B back to A.If the distance between A and B is 12 km and it took 20 minutes to travel full , then the average speed and average velocity of the car is
Answer:
Average speed = 0, Average velocity = 0.02 m/s
Explanation:
Given that,
A car travels from A to B and from B back to A.
The distance between A and B is 12 km
It took 20 minutes to travel full.
We need to find the average speed and the average velocity of the car.
As the car reaches the point from where it was started, the displacement of the car is equal to 0. As a result, the average velocity is equal to 0.
For average speed,
[tex]s=\dfrac{12+12}{60\times 20}\\\\s=0.02\ m/s[/tex]
Hence, this is the required solution.
Is there any difference between antimatter, dark matter, dark energy, and degenerate matter?
pakisagutan po need ko na yan ngayon
*answer this please*
Explanation:
antimatter - counterpart of ordinary matter; identical in every way except for charge. Examples are positrons (counter to electrons) and antiprotons (counter to protons). Direct contact between matter and antimatter results in total annihilation accompanied by huge radiation output.
dark matter - hypothesized as the non-visible or not directly observable kind of matter that could explain some of the unusual behavior of stars and galaxies.
dark energy - hypothesized to be some kind of a repulsive force like anti-gravity that could explain the apparent accelerated rate of expansion of the universe.
degenerate matter - a very dense form of matter made up of fermions (like protons and neutrons) only. Some stars are believed to be made of degenerate matter.
Answer:
Yes. Although the names sound vague and almost fictional, the types of matter called antimatter, dark matter, dark energy, and degenerate matter are all different, specific entities that really exist in our universe. ... Antimatter is just regular matter with a few properties flipped, such as the electric charge.
#Captainpower
ik its a lot but can u help
Answer:
your correct ans is D.
object float in liquid when its density is less than liquid and sinks when its density is more than liquid..
stay safe healthy and happy.Global average temperature increases when energy absorbed by the surface ___?
Answer:
se elevator a maas eneergia mas alta
Which change would decrease the total current, I, flowing through this circuit?
A. Increasing the voltage of the battery
B. Decreasing the length of the wires
C. Rewiring the two resistors in a series
D. Adding a third resistor in parallel
Answer:
A. Increasing the voltage of the battery
Explanation:
The relationship between voltage, V, current, I and resistance, R, is given as follows;
V = I × R
∴ I = V/R
From the above relationship, the current flowing in the circuit is directly proportional to the voltage of the battery, and inversely proportional to the resistance, 'R', of the circuit
Therefore, increasing the voltage, 'V', of the battery, increases the total current, 'I', flowing in the circuit.
Moving along the elevtromagnetic spectrum from low frequency to high frequency, what , if anything, happens to the wavelength?
wavelength get longer
wavelength remains constant
the wavelengths get shorter
wavelength eventually disappear altogether
Explanation:
the wavelengths get shorter
Jorge tightens a bolt on his bicycle with a wrench that is 0.20 m long. If he pulls perpendicularly on the end of the wrench with a force of 140 N, how much torque does he apply ?
Answer:
28Nm
Explanation:
Torque is expressed as the prduct of force and radius
Given
Force = 140N
radius = 0.20m
Torque = 140 * 0.2
Torque = 140 * 1/5
Torque = 28Nm
Hence the amouunt of torque applied is 28Nm
the magnetic field 0.100 m from a wire is 4.20x10^-5 T. what is the field 0.200 m from the wire
Answer:
Your answer is given below:
Explanation:
Can you guys please like my spotify playlist
Answer:
sure
Explanation:
Answer:
uhm ok
Explanation:
When will you say a body is in (i) uniform acceleration? (ii) non-uniform
acceleration?
Answer:
Explanation:
A body is said to be in uniform acceleration if change in velocity with respect to time is the same in equal time interval .
A body is said to be in non uniform acceleration if change in velocity with respect to time is not the same in equal time interval.
If two charged balloons are 10cm apart and they feel a force of electrical repulsion of 20N, what would the force of electrical repulsion become if the balloons were moved apart to a distance of 100cm?
Answer:
200N
Explanation:
its basic.................
When red light and green light are mixed, the color created is
Answer:
blue lighp
Explanation:
Two astronauts push off each other in space. The 90 kg astronaut ends up with a speed of 5 ms. What is the mass of the other astronaut it he ended up with
a speed of 7 m/s?
Answer:
jsjshs
Explanation:
nsnajsajsnzbzbzbaba
Between which two points did they travel fastest?
How can you tell this from the graph that they travelled fastest during that section?
plzzz helppp mee
Answer:
During the section CD , the speed is fastest.
Explanation:
The rate of change of distance is called speed.
Speed = distance / time
Its SI unit ism/s. It is a scalar quantity.
The slope of the distance time graph is given by the speed of the object.
Here, the speed of AB is 30/3= 10 m/s .
The speed of BC is = 0 m/s
The speed of CD is (50 - 30)/(6 - 5) = 20 m/s
So, the speed is maximum during the section CD.
According to the Hertzsprung-Russell diagram, a star with a very high luminosity and a temperature of around 9000 K is most likely which type of star?
A. Main Sequence Star
B. Giant
C. Supergiant
D. White Dwarf
Answer:
supergiant
Explanation:
Answer:
the picture
Explanation:
you can see i got it right :)
An argon gas occupies 56.2 L at 760 torr. If the volume of gas dereases to 1/4 of the original volume ,calculate its final pressure
Answer:
3040 torr
Explanation:
Applying,
PV = P'V'..................... Equation 1
Where P = Initial Pressure, V = Initial volume, P' = Final pressure, V' = Final volume.
Make P' the subject of the equation
P' = PV/V'................. Equation 2
From the question,
Given: P = 760 torr, V = 56.2 L, V' = 56.2/4 = 14.05 L
Substitute these values into equation 2
P' = (56.2×760)/14.05
P' = 3040 torr
I WILL MARK YOU THE BRAINLIEST NO LINKS
What will happen if you heat a liquid to high temperatures?
It will become a solid.
It will become a plasma.
It will become a gas.
It will become a colloid.
Answer:
it becomes a gas
Explanation:
the matter expands, turning into steam, a gas.
I need help in this small question:
(make sure to answer them ALL)
passage: Uranium is a nuclear fuel, it is mined from under the ground.
1- what is nuclear energy
2- is uranium renewable, and why?
Answer:
1) The energy released during nuclear fission or fusion, especially when used to generate electricity is called nuclear energy.
2) It is not renewable because it is an element that has no way whatsoever to regenerate or replicate itself, nor gets created by any natural terrestrial means, neither makes itself available by arriving from outer space (like sunlight). There is a limited amount of it available on the Earth, and every bit you use is a bit you’ll never have available again (as Uranium atoms get destroyed by the fission process).
Hope this helps You
Please mark as brainliest
Thank You
The citizens of Paris were terrified during World War I when they were suddenly bombarded with shells fired from a long-range gun known as Big Bertha. The barrel of the gun was 36.6 m long, and it had a muzzle speed of 2.20 km/s. When the gun’s angle of elevation was set to 55.0°, what would be the range? For the purposes of solving this problem, ignore air resistance. (The actual range at this elevation was 121 km; air resistance cannot be ignored for the high muzzle speed of the shells.)
Answer:
464.1 km
Explanation:
Using R = u²sin2Ф/g where R = range of projectile, u = muzzle speed = 2.20 km/s = 2.20 × 10³ m/s, Ф = angle of elevation or projection angle = 55° and g = acceleration du° to gravity = 9.8 m/s²
Substituting the values of the variables into the equation, we have
R = u²sin2Ф/g
R = (2.20 × 10³ m/s)²sin2(55°)/9.8 m/s²
R = 4.84 × 10⁶ m²/s²sin110°/9.8 m/s²
R = 4.84 × 10⁶ m²/s² × 0.9397/9.8 m/s²
R = 4.548 × 10⁶ m²/s²/9.8 m/s²
R = 0.4641 × 10⁶ m
R = 464.1 × 10³ m
R = 464.1 km
A 46.0 g golf ball is travelling with a velocity of 5.10 m/s. What is the kinetic energy of the golf ball
Answer:
[tex]0.598\:\mathrm{J}}[/tex]
Explanation:
The kinetic energy of a golf ball is given by [tex]KE=\frac{1}{2}mv^2[/tex].
Since the golf ball is given in grams, we must convert to kilograms, as the SI unit of mass is kilograms.
[tex]46.0\:\mathrm{g}=0.046\:\mathrm{kg}[/tex]
Substituting given values, we have:
[tex]KE=\frac{1}{2}\cdot 0.046\cdot 5.10^2=\boxed{0.598\:\mathrm{J}}[/tex]
Answer: not sure
Explanation:I'm not sure
Which of the following statements explains how total time spent in the air is affected as a projectile's angle of launch is increased from 25 degrees to 50 degrees?
Answer:
Therefore letter C is the correct answer.
Explanation:
In a projectile motion the total time in the air can be calculated using the following equation:
We analyze the y-component motion.
[tex]v_{fy}=v_{iy}-gt[/tex]
When the final velocity (v(f)) is equal to zero we calculate the upward time and multiplying it by 2 we find the total time in the air. So we will have:
[tex]t_{tot}=2\frac{v_{iy}}{g}[/tex]
[tex]t_{tot}=2\frac{v_{i}sin(\theta)}{g}[/tex]
We can see that the total time is directly proportional to the angle, then when θ increase t increase.
Therefore letter C is the correct answer.
I hope it helps you!
Usain bolt ran the 200m race within 19.19 seconds. Calculate the speed of Usain bolt during the race
Answer: [tex]10.42\ m/s[/tex]
Explanation:
Given
Usain Bolt ran the race with a length [tex]200\ m[/tex]
Time is taken to complete it [tex]t=19.19\ s[/tex]
We know, [tex]\text{Distance}=\text{speed}\times \text{time}[/tex]
Insert the values
[tex]\Rightarrow 200=v\times 19.19\\\\\Rightarrow v=\dfrac{200}{19.19}\\\\\Rightarrow v=10.42\ m/s[/tex]
So, the speed of Usain Bolt is [tex]10.42\ m/s[/tex]
A beam of light shines on a plane mirror with an angle of incidence of 40°. The reflected light then hits another parallel plane mirror. What is the angle of reflection from the second mirror? A. 40° B. 50° C. 80° D. 90° E. 140°
Answer:
40degrees
Explanation:
Since the mirrors are parallel, the angle of incidence on the first mirror will be the same as the angle of incidence on the second mirror.
Angle of incidence on the second mirror = 40degrees
According to the second law of reflection, the angle of incidence is equal to the angle of reflection. Hence;
angle of incidence = angle of reflection = 40degrees
This shows that the angle of reflection from the second mirror is 40degrees
During a Buckeye football game, the quarterback throws a ‘long bomb' to a wide receiver. During it's flight, the ball reached a maximum height of 15 m [U] before it started falling back down, and during this time flew 30m [E], where it was caught. The receiver then ran it another 15 m [E] for a touchdown. A) Determine the distance and displacement experienced in the up-down dimension by the ball b) Determine the distance and displacement experienced by the ball in the east-west dimension.
Answer:
A) The distance traveled by the ball in the Up-down dimension is 30 m
The displacement of the ball in the up-down direction is 0 m
B) The distance the ball travels in the east west direction is 45 m [East]
The displacement of the ball is the east-west direction is 45 m [East]
Explanation:
The long measures of the ball motion are;
The maximum height reached = 15 m Up
The horizontal distance traveled by the ball during flight = 30 m East
The distance the receiver ran with the ball after the ball was caught = 15 m East
A) The distance traveled by the ball in the Up-down dimension = 15 m up + 15 m backdown = 30 m in the up-down direction
The displacement of the ball in the up-down direction, d = 15 m + (-15 m) = 0 m
B) The distance the ball travels in the east west direction = 30 m [E] + 15 m [E] = 45 [E]
The displacement of the ball is the east-west direction, d = 30 m + 15 m = 45 m [E].