PLS HELP WITH STEPS I'LL MARK U BRAINLISTT

Answer:

A

Explanation:

because the water carRies but also compacts

Explanation:

Given : S=400Jkg

−1

C

−1

and L

f

=3.5×10

5

Jkg

−1

Mass of copper block m=2kg

Heat released by the copper block is equal to the heat gained by the ice to melt.

Let the mass of the ice melted be M.

Change in temperature of copper block ΔT=500−0=500

o

C

∴ mS(ΔT)=ML

f

Or 2×400×500=M×3.5×10

5

⟹ M=1.14kg

hope it help u

We have that If a 2kg block of copper is heated and a temperature increase of 50C is measured,the energy has been provided is

E=418KJ

From the question we are told

If a 2kg block of copper is heated and a temperature increase of 50C is measured, how much energy has been provided?

Generally the equation for the Energy  is mathematically given as

[tex]E=mC(T_1-T_2)\\\\E=2*4180(50)\\\\E=418000J\\\\E=418KJ[/tex]

Therefore

If a 2kg block of copper is heated and a temperature increase of 50C is measured,the energy has been provided is

E=418KJ

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Answer:En general, los semiconductores son materiales, inorgánicos u orgánicos, que tienen la capacidad de controlar su conducción dependiendo de ...

Explanation:

The velocity of the watermelon as it hits the ground is 14.715 m/s.

Given the data in the question;

Since the Watermelon was dropped from rest,

Now, we determine the velocity of the watermelon as it hits the ground which is the final velocity.

From the First Equation of Motion:

[tex]v = u + at[/tex]

Now, under gravity, acceleration ''a" will Acceleration due to gravity;[tex]g = 9.81m/s^2[/tex], "v" is the final velocity, "u" is the initial velocity and "t" is the time taken.

So, we substitute our values into the equation

[tex]v = 0m/s\ +\ ( 9.81m/s^2\ * 1.5s )\\\\v = ( 9.81m/s^2\ * 1.5s )\\\\v = 14.715 m/s[/tex]

Therefore, the velocity of the watermelon as it hits the ground is 14.715 m/s

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The first one!

Hope this helps pls mark as brainliest :)

Answer:

Models change to accommodate new discoveries.

Explanation:

Scientific models are based on current scientific knowledge. This means that when new discoveries are made they are subject to change.

Answer:

your answer is 12.3

Explanation:

hope it helps : )

Answer:b

Explanation:

Answer:

Michelson reasoned that, if the speed of light were constant with respect to the proposed ether through which Earth was moving, that motion could be detected by comparing the speed of light in the direction of Earth's motion and the speed of light at right angles to Earth's motion.

Answer:

B. 5Ω

Explanation:

Equivalent resistance between point P and Q

= 3Ω + Tp

Total Parallel resistance, Tp

[tex] \frac{1}{Tp} = \frac{1}{12Ω} + \frac{1}{6Ω} + \frac{1}{4Ω} [/tex]

[tex]\frac{1}{Tp} = \frac{1}{12Ω} + \frac{2}{12Ω} + \frac{3}{12Ω} [/tex]

[tex]\frac{1}{Tp} = \frac{6}{12Ω}[/tex]

[tex]6(Tp) = 12Ω[/tex]

[tex]Tp = \frac{12Ω}{6} [/tex]

[tex]Tp = 2Ω[/tex]

Equivalent resistance between point P and Q

= 3Ω + 2Ω

= 5Ω

Answer:

respuesta d)

Explanation:

Answer:

b) 72 F°

Explanation:

In Fahrenheit, the difference between freezing and boiling is 180 F° (that’s 212 °F minus 32 °F). In Celsius, the difference is 100 C° (by definition of 0 °C and 100 °C for those two points). So 100 C° = 180 F°; dividing by 100 gives us 1 C° = 1.8 F°.

So a difference of 40 C° is equal to 40 times (1.8 F°) = 72 F°.

Notice I am using °F and °C for actual temperatures, and F° and C° for temperature DIFFERENCES.

Answer:

the radioactivity of carbon-14 DECAYS BY HALF.

Explanation:

Hi there!

We can solve this in two ways, using the Work-Energy theorem or kinematics.

Work-Energy:

We know that:

Ei = Ef, as long as there are no external forces working on the system.

Thus:

Ei = PE = mgh

Ef = KE = 1/2mv²

Therefore:

mgh = 1/2mv²

We can cancel out the mass:

gh = 1/2v²

9.8(10) = 1/2v²

√196 = v = 14 m/s

We can also solve using kinematics, using the equation:

vf² = vi² + 2ad

From rest (vi = 0 m/s) and a = g, so:

vf² = 2gd

vf = √2gh

vf = √(2 × 9.8 × 10) = 14 m/s

Answer:

the answer its time

v = d/t

Answer:distance

Explanation:

Answer: see below

Explanation:

The intial speed is u=0[tex]\frac{m}{s}[/tex]

The acceleration is a= 3.3[tex]\frac{m}{s}^2[/tex]

The distance is s=60m

Apply the equation of motion

[tex]v^{2}[/tex]=[tex]u^{2}[/tex]+2as

So,

[tex]v^{2}[/tex]=0+2*3.3*60=396

v=[tex]\sqrt{396}[/tex] = 19.89 m/s ≈20 m/s

Applying the equation of motion

v=u+at

t= [tex]\frac{v-u}{a}[/tex] =[tex]\frac{19.89-0}{3.3}[/tex] = 6.02seconds

HOPE IT HELPS YOU

CAN YOU BRAINLEST ME

Answer:

w

Explanation:

w

Answer:

A) B) and E)

Explanation:

Answer:

I can suggest them by making different program about it and I will tell them the importance of less and productive population . Also tell them bad consensus of over population. I also give the technique of stopping over population.

[tex]▪▪▪▪▪▪▪▪▪▪▪▪▪  {\huge\mathfrak{Answer}}▪▪▪▪▪▪▪▪▪▪▪▪▪▪[/tex]

The given statements are :

Q1) Distance formula is displacement/time T/F?

- False

Q2)velocity formula is = displacement/time T/F?

- True

The net vertical force on the trailer is 0, while the net horizontal force on the trailer is 20,000 N to the right.

The net vertical force on the truck is 0, while the net horizontal force on the truck is 6,400 N to the right.

The given parameters;

the trailer:

the truck:

The net force on each vehicle is calculated as follows;

for the trailer:

Net vertical force is calculated as;

[tex]\Sigma F_y = 250, 000 \ N - 250,000 \ N = 0[/tex]

Net horizontal force is calculated as;

[tex]\Sigma F_x = 20,000 \ N[/tex]

for the truck;

Net vertical force is calculated as;

[tex]\Sigma F_y =80,000 \ N - \ 80,000 \ N = 0[/tex]

Net horizontal force is calculated as;

[tex]\Sigma F_x = 26,400 \ N - \ 20,000 \ N = 6,400 \ N \ to \ the \ right[/tex]

"Your question is not complete, it seems to be missing the following information;"

find the net force on each vehicle.

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Answer:

k=1/2mv²

Explanation:

k is the kinetic energy

m is mass

and v is velocity/speed

Answer:

0.12kg / 0.19

Explanation:

Becase the volcity reuded

The final velocity of the 0.18 kg object after the collision is 0.19 m/s in the same direction as the object which strikes it, then the initial velocity of the 0.12 kg object would be 0.237 m / s .

It can be defined as the product of the mass and the speed of the particle, it represents the combined effect of mass and the speed of any particle, and the momentum of any particle is expressed in Kg m/s unit.

As given in the problem, a 0.12 kg object makes an elastic head-on collision with a 0.18 kg stationary object. The final velocity of the 0.12 kg object after the collision is 0.048 m/s in the direction opposite its initial movement. The final velocity of the 0.18 kg object after the collision is 0.19 m/s in the same direction as the object which strikes it.

By using the conservation of the momentum,

v × 0.12 + 0 × 0.18 = ( - 0.048)× 0.12 + 0.19 × 0.18

v = 0.237 m / s

Thus, the initial velocity of the 0.12 kg object would be 0.237 m / s .

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Answer:

That depends on your average speed and the number of stops you make. However, assuming you could average 55 miles per hour for the entire distance, your total driving time would be about 3 hours and 45 minutes.

Explanation:

Correct Answer: Option D

Explanation

X L=V/I=24/1.5=16Ω

L = XL/2πf=16/2π50

= 0.05H

hope this helps you.

Answer:

Hello There!!

Explanation:

I believe the answer is=>5.1 x 10-2H

Here's the explanation:↬

•XL= V/I= 24/1.5= 16Ω

•L= XL/2πf= 16/2π50

So the answer is 0.05H.

hope this helps,have a great day!!

~Pinky~

Answer:

How do X rays use electromagnetic waves to function?

X-rays are very high-frequency waves and carry a lot of energy. They will pass through most substances, making them useful in medicine and industry to see inside things. An X-ray machine works by firing a beam of electrons at a "target." If we fire the electrons with enough energy, X-rays will be produced.

Explanation:

An uncharged body is a body that has equal magnitude of positive as well as negative charge on it. So as soon as some charged body is placed near it, the charged body induces negative charges on the uncharged body.