Pls help if u cannnnnnnnnn

Pls Help If U Cannnnnnnnnn

Answers

Answer 1

Answer:

V≈2144.66m³

Step-by-step explanation:

V=4 /3πr^3

d=2r

Solving for V

V=1/ 6πd^3=1/ 6·π·16^3≈2144.66058m³

Hope this helped!!!

Answer 2

Answer:

2143.57 m³

Step-by-step explanation:

Formula of volume of sphere

[tex] = \frac{4}{3} \times π \times {r}^{3} [/tex]

The volume of the sphere

[tex] = \frac{4}{3} \times 3.14 \times {(16 \div 2)}^{3} [/tex]

[tex] = \frac{4}{3} \times 3.14 \times {8}^{3} [/tex]

[tex] = \frac{6430.72}{3} [/tex]

[tex] = 2143.573333...[/tex]

= 2143.57 m³ (rounded to the nearest hundredth)


Related Questions

Find the Perimeter of this figure. I do y get it

Answers

Answer:

56m

Step-by-step explanation:

5+7+5+11+7+16+5

= 56

Well to find the perimeter of any shape all you have to do is add the lengths of all the sides. In this problem the lengths of the sides are 5 + 5 + 5 + 11 + 7 + 16 + 7 which equals 56. So the perimeter of this shape is 56 m. Hope this helps!

Nettlefield primary school have you heard​

Answers

Answer:

No, I have not heard. Give me brainliest plz, I neeeeeeeeeeed it to level up

Step-by-step explanation:

I NEED HELPPP
PLEASEEEEEEEEEEEEEE

Answers

59 I have done this before

A 1/17th scale model of a new hybrid car is tested in a wind tunnel at the same Reynolds number as that of the full-scale prototype. The drag coefficient of the model is the same as that of the prototype. Assuming the model and prototype are both tested in air, find the ratio of the drag on the scale model (Fm) to the drag on the prototype (Fp), i.e., Fm/Fp. Since the size of the model is 1/17th of the size of the prototype, the projected area of the model is (1/17)2 of the projected area of the prototype. Round your answer to the nearest tenth.

Answers

Answer:

The ratio of the drag coefficients [tex]\dfrac{F_m}{F_p}[/tex] is approximately 0.0002

Step-by-step explanation:

The given Reynolds number of the model = The Reynolds number of the prototype

The drag coefficient of the model, [tex]c_{m}[/tex] = The drag coefficient of the prototype, [tex]c_{p}[/tex]

The medium of the test for the model, [tex]\rho_m[/tex] = The medium of the test for the prototype, [tex]\rho_p[/tex]

The drag force is given as follows;

[tex]F_D = C_D \times A \times \dfrac{\rho \cdot V^2}{2}[/tex]

We have;

[tex]L_p = \dfrac{\rho _p}{\rho _m} \times \left(\dfrac{V_p}{V_m} \right)^2 \times \left(\dfrac{c_p}{c_m} \right)^2 \times L_m[/tex]

Therefore;

[tex]\dfrac{L_p}{L_m} = \dfrac{\rho _p}{\rho _m} \times \left(\dfrac{V_p}{V_m} \right)^2 \times \left(\dfrac{c_p}{c_m} \right)^2[/tex]

[tex]\dfrac{L_p}{L_m} =\dfrac{17}{1}[/tex]

[tex]\therefore \dfrac{L_p}{L_m} = \dfrac{17}{1} =\dfrac{\rho _p}{\rho _p} \times \left(\dfrac{V_p}{V_m} \right)^2 \times \left(\dfrac{c_p}{c_p} \right)^2 = \left(\dfrac{V_p}{V_m} \right)^2[/tex]

[tex]\dfrac{17}{1} = \left(\dfrac{V_p}{V_m} \right)^2[/tex]

[tex]\dfrac{F_p}{F_m} = \dfrac{c_p \times A_p \times \dfrac{\rho_p \cdot V_p^2}{2}}{c_m \times A_m \times \dfrac{\rho_m \cdot V_m^2}{2}} = \dfrac{A_p}{A_m} \times \dfrac{V_p^2}{V_m^2}[/tex]

[tex]\dfrac{A_m}{A_p} = \left( \dfrac{1}{17} \right)^2[/tex]

[tex]\dfrac{F_p}{F_m} = \dfrac{A_p}{A_m} \times \dfrac{V_p^2}{V_m^2}= \left (\dfrac{17}{1} \right)^2 \times \left( \left\dfrac{17}{1} \right) = 17^3[/tex]

[tex]\dfrac{F_m}{F_p} = \left( \left\dfrac{1}{17} \right)^3[/tex]= (1/17)^3 ≈ 0.0002

The ratio of the drag coefficients [tex]\dfrac{F_m}{F_p}[/tex] ≈ 0.0002.

What are the solutions to 2(x+1^2)=18

Answers

Answer:

2( x + 1) = 18

2x + 2 = 18

2x = 16

x = 16/2 = 8

Brand A and brand B of frozen green beans both list a weight of 32 ounces on their bags. Because of variability in the manufacturing process, the bags often contain slightly more, or less, than 32 ounces of green beans. An inspector takes a random sample of 25 bags of green beans of each type and records their weights. The weights and their relative frequencies are summarized in the histograms. 2 histograms comparing brand A and brand B of green beans. The median weight for brand B is less than the median weight of brand A. Which of the following is a true statement when comparing the bags of green beans? The median weight for both types is between 32.1 and 32.2 ounces. The median weight for both types is between 32.0 and 32.1 ounces. The median weight for brand B is less than the median weight of brand A. The median weight for brand B is greater than the median weight of brand A.

Answers

Answer:

The answer is: B.)32.0–32.1 ounces

Step-by-step explanation:

Got it right on my test

The true statement is The median weight for both types is between 32.0 and 32.1 ounces.

What is data?

Data is referred to as a collection of information gathered by observations, measurements, research, or analysis. It may comprise facts, figures, numbers, names, or even general descriptions of things. Data can be organized in the form of graphs, charts, or tables for ease in our study.

Given:

Brand A and brand B of frozen green beans both list a weight of 32 ounces on their bags.

The median weight for brand B is less than the median weight of brand A.

So, if both brands weigh 32 ounces then the median weight for both types is between 32.0 and 32.1 ounces.

Learn more about data here:

https://brainly.com/question/10980404

#SPJ6

Use the remainder theorem to determine which of the following is not a factor of x^3-5x^2-x+5

Answers

Answer:

The answer is A

Step-by-step explanation:

x to the power of 1 is the lowest x and when you multiply -5 and -5 you get 5 so the answer is A.

3.294e6 standard form

Answers

Answer:

3.294

Step-by-step explanation:

Joe wants his overall test average to be 85%. What score would he need on his next test if the test scores he has so far are: 70%, 105%, 75%, 90%, 90%?

Answers

Answer:

He would need a score of 0.8 = 80%.

Step-by-step explanation:

Average score:

The average score is the sum of all scores divided by the number of tests.

What score would he need on his next test if the test scores he has so far are: 70%, 105%, 75%, 90%, 90%?

Combining with the next text, there will be 6, and the sum will be: 0.7 + 1.05 + 0.75 + 0.9 + 0.9 + x = 4.3 + x.

Joe wants his overall test average to be 85%.

So

[tex]\frac{4.3 + x}{6} = 0.85[/tex]

[tex]4.3 + x = 5.1[/tex]

[tex]x = 5.1 - 4.3 = 0.8[/tex]

He would need a score of 0.8 = 80%.

Help pleaseeeeeeeeeeee

Answers

Answer:

3

Step-by-step explanation:

When looking at a graph, the greatest speed will be the steepest part. Even though one line is further than another, does not mean it is faster.

A bag contains 10 blue marbles, 7 white marbles, 6 red marbles, and 2 Green marbles. what is the probability of randomly selecting the blue marble?

Answers

Answer:

Step-by-step explanation:

Number of blue marbles = 10

Number of white marbles = 7

Number of Red marbles = 6

Number of Green marbles = 2

Total marbles = 10 + 7 + 6 + 2 = 25

Probability of selecting the blue marble = 10/25 = 2/5

measure of each exterior angle of a regular 30-gon?
7. An exterior angle of a regular polygon measures 22.5°. How many sides does it have?
8. An interior

Answers

Answer:

I'm not sure would love to help but dont know the answer

Solve the equation below.

Answers

Answer:

D

Step-by-step explanation:

Just divide by 2/3

High point question. SAT prep

Answers

Answer:

[tex] log_{a}(a) \ + log_{a}( {10}^{ - 4} ) = 1 + \frac{ - 4}{ log_{10}(a) } = 1 + \frac{ - 4}{b} = \frac{b - 4}{b} [/tex]

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what's the distance between (-9,-6) and (-2,-2)

Answers

Answer:

the distance formula is square root (x2-x1)^2 + (y2-y1)^2

7^2 + 4^2 = 49+16 = 65

squarroot of 65 = 8.06

Step-by-step explanation:

Step-by-step explanation:

The distance formula is [tex]\sqrt{(x_{2} -x_{1} )^{2} +(y_{2} -y_{1} )^{2} }[/tex]. I don't provide answers for problems like these but will give the equations.

The management of KSmall Industries is considering a new method of assembling a computer. The current assembling method requires a mean time of 66 minutes with a standard deviation of 3.0 minutes. Using the new method, the mean assembly time for a random sample of 24 computers was 61 minutes.
a. Using the 0.10 level of significance, can we conclude that the assembly time using the new method is faster?
b. What is the probability of a Type II error? (Round "Critical values" to 2 decimal places and round your final answer to 4 decimal places.)

Answers

Answer:

Part a:

Since the calculated z= 8.1649 falls in the critical region  z < ± 1.28 we reject H0 and conclude that the assembly time using the new method is faster.

Part b:

P (Type II Error)=  0.6628

Step-by-step explanation:

The null and alternate hypothesis are

H0: μ1 ≥ μ2   against the claim Ha: μ1 < μ2

This is left tailed test

The critical region for this test at 0.10 ∝ is z < ± 1.28

The test statistic

z= x1-x2/ s/√n

z= 66-61/ 3/√24

z= 5/0.61238

z= 8.16486

Since the calculated z= 8.1649 falls in the critical region  z < ± 1.28 we reject H0 and conclude that the assembly time using the new method is faster.

Part b:

P (Type II Error)  = P ( accept H0/ H0 is false)

z ( ∝)= X-u/s/√n

1.28= X-61/0.61238

X= 61.7838

So I will incorrectly fail to reject the null as long as a draw a sample mean that greater than 61.7838

 The probability of a Type II error is given by

P (z> 61.7838-66/24)

P (z>- 0.42161)

From the tables

P (z>- 0.42161)=  0.6628

How many odd numbers are between 10 and 50?

Answers

Answer: 19 odd numbers: 11 , 13,  15,  17 , 19,  23,  25,  27,  29,  31,  33 , 35,  37, 39,  41,  43,  45, 47,  49

Hope that helped! :)

The dot plots show the numbers of children’s books purchased by customers at two different bookstores on one day.

Which statement is supported by the information in the dot plots?


A) The mean of the data for Store 1 is greater than the mean of the data for Store2
B) The mode of the data for Store 2 is greater than the mode of the data for Store1
C) The median of the data for Store 2 is greater than the median of the data for Store1
D) The range of the data for Store 1 is greater than the range of the data for Store2

Answers

Answer:

A

Step-by-step explanation:

since mean is the most annoying to calculate I went through and did everything else, the range is the same as both charts go 0-6. The median is is the middle number which means store 1 has a higher number of 3' s but our option says store 2 is greater and B is the mode, the number that shows up the most.

AB = 5, AP = 4, and DP = 12, then find the length of PC

Answers

Answer:

[tex]PC = 0.333[/tex]

Step-by-step explanation:

Given

[tex]AB = 5[/tex]

[tex]AP = 4[/tex]

[tex]DP =12\\[/tex]

See attachment

Required

Find PC

When two chords intersect, the product of the segments are always equal.

In chord DC, the segments are DP and PC

In chord AB, the segments are AP and PB

So:

[tex]DP * PC = AP * PB[/tex]

This gives:

[tex]12 * PC = 4 * PB[/tex] --- (1)

In chord AB, we have:

[tex]AB = AP + PB[/tex]

Make PB the subject

[tex]PB = AB - AP[/tex]

This becomes

[tex]PB = 5 - 4[/tex]

[tex]PB = 1[/tex]

[tex]12 * PC = 4 * PB[/tex] --- (1) becomes

[tex]12 * PC = 4 * 1[/tex]

[tex]12 * PC = 4[/tex]

Make PC the subject

[tex]PC = \frac{4}{12}[/tex]

[tex]PC = 0.333[/tex]

Find all the missing elements : C=120degrees
b= 5
c=11

Answers

Answer:

A = 36.8°

B = 23.2°

a = 7.6

Step-by-step explanation:

Given:

C = 120°

b = 5

c = 11

Required:

Find A, B, and a.

Solution:

✔️To find B, apply the Law of Sines

[tex] \frac{sin(B)}{b} = \frac{sin(C)}{c} [/tex]

Plug in the values

[tex] \frac{sin(B)}{5} = \frac{sin(120)}{11} [/tex]

Cross multiply

Sin(B)*11 = sin(120)*5

Divide both sides by 11

[tex] sin(B) = \frac{sin(120)*5}{11} [/tex]

[tex] sin(B) = \frac{sin(120)*5}{11} [/tex]

Sin(B) = 0.3936

B = [tex] sin^{-1}(0.3936) [/tex]

B = 23.1786882° ≈ 23.2° (nearest tenth)

✔️Find A:

A = 180° - (B + C) (sum of triangle)

A = 180° - (23.2° + 120°)

A = 36.8°

✔️To find a, apply the Law of sines:

[tex] \frac{sin(A)}{a} = \frac{sin(B)}{b} [/tex]

Plug in the values

[tex] \frac{sin(36.8)}{a} = \frac{sin(23.2)}{5} [/tex]

Cross multiply

a*sin(23.2) = 5*sin(36.8)

Divide both sides by sin(23.2)

[tex] a = \frac{5*sin(36.8)}{sin(23.2) [/tex]

a = 7.60294329 ≈ 7.6 (nearest tenth)

NASA is conducting an experiment to find out the fraction of people who black out at G forces greater than 6. In an earlier study, the population proportion was estimated to be 0.3 . How large a sample would be required in order to estimate the fraction of people who black out at 6 or more Gs at the 80% confidence level with an error of at most 0.03

Answers

Answer:

A sample of 383 would be required.

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of [tex]\pi[/tex], and a confidence level of [tex]1-\alpha[/tex], we have the following confidence interval of proportions.

[tex]\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}[/tex]

In which

z is the zscore that has a pvalue of [tex]1 - \frac{\alpha}{2}[/tex].

The margin of error is:

[tex]M = z\sqrt{\frac{\pi(1-\pi)}{n}}[/tex]

In an earlier study, the population proportion was estimated to be 0.3.

This means that [tex]\pi = 0.3[/tex]

80% confidence level

So [tex]\alpha = 0.2[/tex], z is the value of Z that has a pvalue of [tex]1 - \frac{0.2}{2} = 0.9[/tex], so [tex]Z = 1.28[/tex].

How large a sample would be required in order to estimate the fraction of people who black out at 6 or more Gs at the 80% confidence level with an error of at most 0.03?

A sample of n is needed.

n is found when M = 0.03. So

[tex]M = z\sqrt{\frac{\pi(1-\pi)}{n}}[/tex]

[tex]0.03 = 1.28\sqrt{\frac{0.3*0.7}{n}}[/tex]

[tex]0.03\sqrt{n} = 1.28\sqrt{0.3*0.7}[/tex]

[tex]\sqrt{n} = \frac{1.28\sqrt{0.3*0.7}}{0.03}[/tex]

[tex](\sqrt{n})^2 = (\frac{1.28\sqrt{0.3*0.7}}{0.03})^2[/tex]

[tex]n = 382.3[/tex]

Rounding up:

A sample of 383 would be required.

Will give the brainliest answer and 20 points to anyone who can give a complete answer and not a scam link or a joke answer or begging for points (those 3 types of answers will be reported)

Courtney and Christy both leave the coffee shop at the same time, but in opposite directions. If Christy travels 9 mph faster than Courtney and after 7 hours they are 189 miles apart, how fast is each traveling?

Courtney is traveling ___________ mph.

Christy is traveling _____________ mph.

Answers

Answer:

Courtney is travelling at 9mph

Christy is travelling at 18mph

Step-by-step explanation:

Courtney's speed = x

Christy's speed = y

Christy travels 9 mph faster than Courtney: x+9=y

Distance = speed * time

Courtney's distance after 7 hours = 7x

Christy's distance after 7 hours = 7y

After 7 hours, they're 189 miles apart:

7x+7y=189

x+y=27

x+y=27

x+x+9=27

2x=18

x=9

y=x+9

y=9+9

y=18


What is the area of the parallelogram?

Answers

Answer:

im not 100 percent sure but i think its

140 inches squared

Step-by-step explanation:

Find mean & margin of error if 28.4 < µ < 38.8

Answers

Answer:

The mean is of 33.6

The margin of error is of 5.2.

Step-by-step explanation:

Confidence interval concepts:

A confidence interval has two bounds, a lower bound and an upper bound.

A confidence interval is symmetric, which means that the point estimate used is the mid point between these two bounds, that is, the mean of the two bounds.

In this question:

Lower bound: 28.4

Upper bound: 38.8

Mean

(28.4+38.8)/2 = 33.6.

The mean is of 33.6

Margin of error:

(38.8 - 28.4)/2 = 5.2

The margin of error is of 5.2.

ted is twice his sister's age and three years younger than joe. ted's sister is half of a century plus ten. how old is ted how old is ted's sister​

Answers

Answer:

120, 60

Step-by-step explanation:

half a century = 60 + 10 x 2 = ted.

she is 60.

Solve for x:
2x + 9 = 3

Answers

Answer:

x = -3

Step-by-step explanation:

2x + 9 = 3

2x = 3 - 9

2x = -6

x = -3

Answer:

- 3

Step-by-step explanation:

given

2x + 9 = 3

2x = 3 - 9

2x = - 6

x = - 6/2

x = - 3

hope it helps :)

The groundhog population of​ Punxsutawny, Pennsylvania is closely monitored each year. Two years ago the population decreased by​ 12%. Last year the number of groundhogs increased by​ 6%. This year the population also increased by​ 9%. What was the percentage​ increase/decrease of groundhogs over these three​ years? Round your answer to the nearest tenth of a percentage poin

Answers

Answer:

There was a increase of 1.7% over these three​ years

Step-by-step explanation:

Multipliers:

For a decrease of a%, we multiply by: [tex]\frac{100-a}{100}[/tex]

For a increase of a%, we multiply by: [tex]\frac{100+a}{100}[/tex]

What was the percentage​ increase/decrease of groundhogs over these three​ years?

Decrease of 12%(multiplication by 0.88).

Increase of 6%(multiplication by 1.06).

Increase of 9%(multiplication by 1.09).

After these three years:

0.88*1.06*1.09 = 1.017

1.017 - 1 = 0.017

0.017*100% = 1.7%

There was a increase of 1.7% over these three​ years

Please explain step by step I dont get it.

Answers

Answer: B

Step-by-step explanation:

108 divide by 54 = 2

That equation means she paid 2 dollars per ticket, not 1 dollar for 2 tickets

(There is no 1 in the equation also)

The dot plot below shows the number of movies rented last month by students in Ms. Underwood's class.



What is the median number of movies rented?
A.
4
B.
6
C.
3
D.
2

Answers

Answer:

the answer gonna be 3

Answer: I the answer is 3 100%

Step-by-step explanation: I took the test

What is the equation of the following line?

Answers

The the the the the the the answer is of course 3

Answer:

Answer is F. y = 6x

Step-by-step explanation:

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