Pls help I need a good grade

r should be 4/7. You're comparing the given series to a geometric series that converges. By the limit comparison test, you have

[tex]\displaystyle\lim_{n\to\infty}\frac{\frac{4^n+7}{7^n}}{\frac{4^n}{7^n}}=\lim_{n\to\infty}\frac{4^n+7}{4^n}=\lim_{n\to\infty}\left(1+\frac7{4^n}\right)=1[/tex]

and since this limit is positive and finite, and the series you're comparing to is convergent, then the first series must also be convergent.

Answer:

Area of given figure = 60.8 mm² (Approx.)

Step-by-step explanation:

Given:

Length of figure = 9.3 mm

Width of figure = 7.8 mm

Height of triangular cut = 3 mm

Find:

Area of given figure

Computation:

Area of given figure = [(Length)(Width)] - Area of triangle

Area of given figure = [(9.3)(7.8)] - [(1/2)(b)(h)]

Area of given figure = [(9.3)(7.8)] - [(1/2)(7.8)(3)]

Area of given figure = [(9.3)(7.8)] - [(1/2)(7.8)(3)]

Area of given figure = [72.54] - [(1/2)(7.8)(3)]

Area of given figure = [72.54] - [11.7]

Area of given figure = 60.8 mm² (Approx.)

Answer:

[tex]\sigma_x = 2000[/tex]

Step-by-step explanation:

Given

[tex]\sigma = 4000[/tex]

[tex]n = 4[/tex]

Required

The sample standard deviation

The sample standard deviation cannot be calculated directly. However, we can use the value of standard error because standard error approximates to sample standard deviation.

So, we have:

[tex]\sigma_x = \frac{\sigma}{\sqrt n}[/tex]

[tex]\sigma_x = \frac{4000}{\sqrt 4}[/tex]

[tex]\sigma_x = \frac{4000}{2}[/tex]

[tex]\sigma_x = 2000[/tex]

Hence, the sample standard deviation is 2000

Step-by-step explanation:

what is your question please

Answer:

berg river

Step-by-step explanation:

it has good environmental health

Answer:

the slope is 8/7 and the y-intercept is 300

Step-by-step explanation:

The y-intercept is 300 because that is where the estimated line of bets fit (the red line) crosses the y-intercept.

Answer:

0.12

Step-by-step explanation:

Total number of questions in the book = 10

Number of questions answered correctly by Alice = 6

Number of questions answered correctly by Bob = 8

Probability of Alice answering a question correctly = 0.6

Probability of Alice answering a question incorrectly = 1- 0.6 = 0.4

Probability of Bob answering a question correctly = 0.8

Probability of Bob answering a question incorrectly = 1- 0.8 = 0.2

Probability that there exists at least one question on the test which is answered correctly by Alice but not by Bob = 0.6 *0.2 = 0.12

Answer:

[tex]{ \tt{3 \frac{4}{9} \div (5 \frac{1}{3} - 2 \frac{3}{4}) + 5 \frac{9}{10} }} \\ \\ = { \tt{ \frac{31}{9} \div ( \frac{16}{3} - \frac{11}{4} ) + \frac{59}{10} }} \\ \\ = { \tt{ \frac{31}{9} \div ( \frac{31}{12} ) + \frac{59}{10} }} \\ \\ { \tt{ = \frac{4}{3} + \frac{59}{10} }} \\ \\ { \bf{ = \frac{217}{30} }} \\ \\ { \boxed{ \tt{answer : 7 \frac{7}{30} }}} \\ \\ { \underline{ \blue{ \tt{becker ⚜jnr}}}}[/tex]

Answer:

[tex]7 \frac{7}{30}[/tex]

Step-by-step explanation:

[tex]3 \frac{4}{9} \div ( 5\frac{1}{3} - 2 \frac{3}{4}) + 5 \frac{9}{10}\\\\\frac{31}{9} \div (\frac{16}{3} - \frac{11}{4} ) + \frac{59}{10} \\\\\\Solving \ using \ BODMAS\\\\First \ Solve \ expression \ inside \ Bracket \\\\\frac{31}{9} \div (\frac{(16 \times 4) - ( 11 \times 3)}{12}) + \frac{59}{10} \\\\\frac{31}{9} \div (\frac{64- 33)}{12}) + \frac{59}{10} \\\\\frac{31}{9} \div \frac{31}{12} + \frac{59}{10} \\\\\\ \\\\\\Next \ solve \ Dvision \\\\\frac{\frac{31}{9}}{\frac{31}{12}} + \frac{59}{10}\\\\[/tex]

[tex](\frac{31}{9}} \times {\frac{12}{31}) + \frac{59}{10}[/tex]

[tex]\frac{4}{3} + \frac{59}{10}\\\\ Now \ solve \ final \ expression \\\\\\\frac{(4 \times 10) + ( 59 \times 3)}{30}\\\\\frac{40 + 177}{30}\\\\\frac{217}{30}\\\\7 \frac{7}{30}[/tex]

Answer:

.216165788

.582225057

.417774943

Step-by-step explanation:

We need to use a binomial distribution here

A.

10C5*.58⁵*(1-.58)⁵= .216165788

B.

I honestly think the fastest way to solve this is adding the probabiblity of exactly 6,7,8,9,10

which means we write

10C6*.58⁶*(1-.58)⁴+10C7*.58⁷*(1-.58)³+10C8*.58⁸*(1-.58)²+10C9*.58⁹*(1-.58)+10C10*.58¹⁰= .582225057

C.

To solve this just take the compliment of answer B

1-.582225057= .417774943

Answer:

A = [tex]\frac{3}{4}[/tex] [tex]\sqrt[3]{B}[/tex]

Step-by-step explanation:

Given A varies directly as [tex]\sqrt[3]{B}[/tex] then the equation relating them is

A = k [tex]\sqrt[3]{B}[/tex] ← k is the constant of variation

To find k use the condition A = 3 when B = 64 , then

3 = k [tex]\sqrt[3]{64}[/tex] = 4k ( divide both sides by 4 )

[tex]\frac{3}{4}[/tex] = k

A = [tex]\frac{3}{4}[/tex] [tex]\sqrt[3]{B}[/tex] ← equation of variation

9514 1404 393

Answer:

  C = 9x +2280

Step-by-step explanation:

The 2-point form of the equation for a line can be a place to start.

  y = (y2 -y1)/(x2 -x1)(x -x1) +y1

  C = (4800 -3000)/(280 -80)(x -80) +3000 . . . . . use given values

  C = 1800/200(x -80) +3000 . . . . simplify some

  C = 9x -720 +3000 . . . . eliminate parentheses

  C = 9x +2280

Answer:

The three sides are 27 feet, 15 feet, 13 feet

Step-by-step explanation:

Let second side of a triangle be = a

Let one side be 12 feet shorter than the second side = (a - 12)

Let the third side be 2 feet shorter than the second side= (a - 12) - 2 =(a - 14)

Perimeter of triangle = Sum of length of all 3 sides

55 = a + (a - 12) + (a - 14)

55 = a + a + a - 12 - 14

55 = 3a - 26

55 + 26 = 3a

81 = 3a

a = 27

Length of one side, a - 12 = 27 - 12 = 15 feet

Length of second side, a = 27 feet

Length of third side, a - 14 = 27 - 14 = 13 feet

The answer is attached. I hope this helps answer your question!

Answer:

V=480m^2

Step-by-step explanation:

dogs alpha an 125789 SMS Skoda Eloisa 124579 harm Occam

Answer:

48

Step-by-step explanation:

correct on Edge 2021

Answer:

B

Step-by-step explanation:

Find the area of the circle with r = 36/2     Area1 =  π r²

divide Area1 by two since the upper part of the figure is a semi-circle

then finally add and area of the rectangle   Area2 = (18)(36)

Total area = Area 1 + Area 2

Answer:

1156.7 cm^2

Step-by-step explanation:

for finding area of semi circle

diameter=36 cm

radius=diameter/2

=36/2

=18 cm

area of semi circle=πr^2/2

=3.14*(18)^2/2

=3.14*324/2

=1017.36/2

=508.68 cm^2

area of rectangle=length*breadth

=18 cm *36 cm

=648 cm^2

area of the figure=area of semi circle + area of rectangle

=508.68 + 648

=1156.68

=1156.7 cm^2

Answer:

x = -4, y = 6.

x = 0, y = 7.

x = 4, y = 8.

x = 8, y = 9.

Step-by-step explanation:

We are given the following rule:

[tex]y = \frac{x}{4} + 7[/tex]

To solve this question, we replace x by the asked values.

When x = -4

[tex]y = \frac{-4}{4} + 7 = -1 + 7 = 6[/tex]

So x = -4, y = 6.

When x = 0

[tex]y = \frac{0}{4} + 7 = 0 + 7 = 7[/tex]

So x = 0, y = 7.

When x = 4

[tex]y = \frac{4}{4} + 7 = 1 + 7 = 8[/tex]

So x = 4, y = 8.

When x = 8

[tex]y = \frac{8}{4} + 7 = 2 + 7 = 9[/tex]

So x = 8, y = 9.

This question is incomplete, the complete question is;

If n is a positive integer, how many 5-tuples of integers from 1 through n can be formed in which the elements of the 5-tuple are written in increasing order but are not necessarily distinct.

In other words, how many 5-tuples of integers  ( h, i , j , m ), are there with  n ≥ h ≥ i ≥ j ≥ k ≥ m ≥ 1 ?

Answer:

the number of 5-tuples of integers from 1 through n that can be formed is [ n( n+1 ) ( n+2 ) ( n+3 ) ( n+4 ) ] / 120

Step-by-step explanation:

Given the data in the question;

Any quintuple ( h, i , j , m ), with n ≥ h ≥ i ≥ j ≥ k ≥ m ≥ 1

this can be represented as a string of ( n-1 ) vertical bars and 5 crosses.

So the positions of the crosses will indicate which 5 integers from 1 to n are indicated in the n-tuple'

Hence, the number of such quintuple is the same as the number of strings of ( n-1 ) vertical bars and 5 crosses such as;

[tex]\left[\begin{array}{ccccc}5&+&n&-&1\\&&5\\\end{array}\right] = \left[\begin{array}{ccc}n&+&4\\&5&\\\end{array}\right][/tex]

= [( n + 4 )! ] / [ 5!( n + 4 - 5 )! ]

= [( n + 4 )!] / [ 5!( n-1 )! ]

= [ n( n+1 ) ( n+2 ) ( n+3 ) ( n+4 ) ] / 120

Therefore, the number of 5-tuples of integers from 1 through n that can be formed is [ n( n+1 ) ( n+2 ) ( n+3 ) ( n+4 ) ] / 120

Answer:

160 m²

Step-by-step explanation:

Given :

A parallelogram shaped lot :

Base of lot = 20 m

Distance between parallel sides, = height of lot = 8 m

The area of the lot can be obtained using the area formula of a parallelogram :

Area = base * height

Area = 20 m * 8 m

Area = 160 m²

Answer:

D. a line that shows only one solution to the equation

Step-by-step explanation:

I hope this helps uwu.

Answer: D.There is no answer.

Step-by-step explanation:

Answer:

Irony

Explanation:

I just took the test

Answer:

x = 5 is a vertical line at x = 5

Answer:

35 ft^2

Step-by-step explanation:

A = wl

A = 7 * 5

A = 35

Answer:

it takne 23 days to complete it I hope it is clear add all the no