The potential difference across each light bulb would always be the same as the potential difference across the battery cells.
What is potential difference?Potential difference is described as the amount of work energy required to move an electric charge from one point to another and can also be the difference in electric potential between two points.
Two light bulbs in a simple parallel circuit each will enjoy the full voltage of the battery. Hence, the reason why the bulbs in the parallel circuit will be brighter than those in the series circuit.
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when ultraviolet light with wavelength of 370.0 nm falls on certain metal surface, the maximum kinetic energy of the emitted photoelectrons is measured to be 1.40 ev. find the work function (binding energy) of the metal (in ev). (10 pts.)
The work function of the metal is 2.25 eV.
The work function, or binding energy, of a metal is the minimum energy required to remove an electron from the surface of the metal. In this case, the maximum kinetic energy of the emitted photoelectrons is 1.40 eV, which means that the energy required to remove the electron from the metal was at least 1.40 eV.
To find the work function of the metal, we can use the following equation:
Work function (eV) = Photon energy (eV) - Maximum kinetic energy of photoelectrons (eV)
Plugging in the values given in the problem, we get:
Work function (eV) = Photon energy (eV) - 1.40 eV
The energy of a photon can be calculated using the equation:
Photon energy (eV) = hc / wavelength (m)
Where h is the Planck constant (6.626 x [tex]10^{-34}[/tex] J × s), c is the speed of light (2.998 x [tex]10^{8}[/tex] m/s), and wavelength is the wavelength of the photon in meters.
Plugging in the values and converting the wavelength to meters, we get:
Photon energy (eV) = (6.626 x [tex]10^{-34}[/tex] J × s) × (2.998 x [tex]10^{8}[/tex] m/s) / (3.70 x [tex]10^{-7}[/tex] m)
= 3.65 eV
Substituting this value back into the first equation, we get:
Work function (eV) = 3.65 eV - 1.40 eV
= 2.25 eV
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a mouse in a maze scurries 41 cm south and then takes a 90-degree turn and scurries 64 cm west to get a piece of cheese. find the mouse's displacement.
Answer:
76 cm southwest
Explanation:
The displacement of the mouse is 76.01 cm along south-west at an angle 57.35° with south direction.
What is displacement?In mechanics, displacement refers to the distance that a particle or body moves in a particular direction. Generally, point masses are used to describe particles and bodies. This means that, without sacrificing generality, bodies can be thought of as having all of their mass concentrated in a single mathematical point.
The mouse scurries 41 cm south and then takes a 90-degree turn and scurries 64 cm west.
Hence, magnitude of resultant displacement = √( 41² + 64²) cm = 76.01 cm.
The direction of displacement is along south-west with an angle with south direction= tan⁻¹(64/41) = 57.35°.
Hence, the displacement of the mouse is 76.01 cm along south-west at an angle 57.35° with south direction.
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A 48 cm long metal rod is oriented horizontally in a uniform magnetic field with magnetic flux density of 340 g. The magnetic field is directed vertically down into the ground. The metal rod is moved with a speed of 13 m/s in a horizontal direction perpendicular to the length of the rod. Neglect the magnetic field of earth at the location of this apparatus. Determine the potential difference induced in the rod. Calculate the answer in the units of v. Write your answer in decimal form with three digits to the right of the decimal point (e. G. 5. 374); do not write any units
The potential difference induced in the rod is approximately -6.912 v. In general, the potential energy of an object is equal to the work done to move the object to its current position, against the forces acting on it.
Potential energy is a form of energy that an object possesses due to its position in a gravitational field or due to its configuration. It is the energy that an object has due to its position in a system, rather than its motion.
The potential difference induced in the rod is given by Faraday's law of electromagnetic induction:
ΔV = -(BLv)
where B is the magnetic flux density, L is the length of the rod, and v is the speed at which the rod moves through the magnetic field.
Plugging in the given values, we have:
ΔV = -(340 g * 48 cm * 13 m/s)
Converting the length to meters and the magnetic flux density to teslas, we have:
ΔV = -(0.34 T * 0.48 m * 13 m/s)
= -6.912 v
So the potential difference induced in the rod is approximately -6.912 v.
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how many kilometers would you have to go above the surface of the earth for our weight to decrease to half of what it was at the surface
We have to go above 2651 kilometres of the earth for our weight to decrease to half of what it was at the surface.
Geophysics applies the concepts of physics to take a look at the Earth. It deals with things like the motion of the Earth's crust and the temperatures of its interior.
Geology is the scientific study of the earth, including the elements that make it up, the processes that shape it, how it was formed, and information about the planet's past and how it has been ever since. Today, geology also encompasses an examination of distant worlds.
We define the earth via thinking about other people as our enemies, outsiders and foreigners; by dividing our earth into international locations and by developing enmity in opposition to any other institution of people.
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Two positive point charges q are placed on the x-axis, one at x = a and one at x = -a.a. Derive an expression for the electric field at points on the x-axis, where ?a < x < a.
Th electric field at a point between 2 points is given by E = [tex]\frac{4kQax}{(a^2 - x^2)^2}[/tex] (-i^)
Formula for electric field at a point on x-axis is given by:
E = [tex]\frac{kq}{r^2}[/tex] ----(i)
where k is constant, q is magnitude of charge and r is the distance from charge where electric field is to be found.
Q (-a,0)____________________(x,0)_____________________Q(a,0)
so we have to fing electric field at point (x,0) due to the both charges shown in the figure.
due to point charge at pont (-a,0) the electric field is in the positive x direction and due to charge at point (a,0) the electric field is in negative x direction.
let [tex]E_1[/tex] be the electric field due to charge at point (-a,0)
let [tex]E_2[/tex] be the electric field due to charge at point (a,0)
[tex]E_1[/tex] = [tex]\frac{kQ}{(a+x)^2}[/tex] (i^)
where i^ is unit vector along x- axis
[tex]E_2[/tex] = [tex]\frac{kQ}{(a-x)^2}[/tex] (-i^)
[tex]E_1+E_2 = \frac{kQ}{(x+a)^2}[/tex] i^ [tex]+ \frac{kQ}{(a-x)^2}[/tex] (-i^)
=> [tex]\frac{-4kQax}{(a^2-x^2)^2}[/tex] i^
so [tex]E_1 + E_2 =[/tex] [tex]\frac{4kQax}{(a^2 - x^2)^2}[/tex] (-i^)
so for any point a < x < a .
Th electric field is given by E = [tex]\frac{4kQax}{(a^2 - x^2)^2}[/tex] (-i^)
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For a group class project, students are building model roller coasters. Each roller coaster needs to begin at the top of the first hill, where a horizontal spring that is initially compressed 0.25 m will push a small car forward.
A hill with a compressed spring at the top. There is a car sitting against the compressed spring. The portion of the hill is vertically colored orange, the middle section is vertically colored yellow and the last section colored green.
Each group of students will choose a car and a spring to push the car and then build a track. The assignment is to make the car go 5.0 m/s when it reaches the bottom of the first hill. Four groups of students choose springs and build tracks as described in the table.
A 4 column table with 4 rows. The first column is labeled group with entries A, B, C, D. The second column is labeled car mass in kilograms with entries .75, .60, .55, .84. The third is labeled spring constant in newtons per meter with entries 65, 35, 40, 32. The last column is labeled hill height in meters with entries 1.2, .90, 1.1 , .95.
Which group’s roller coaster will most likely make the car travel closest to 5.0 m/s when it is at the bottom of the first hill?
A
B
C
D
The group that will make the car travel closest to 5 m/s when it is at the bottom of the first will is of:
Group C.
How to obtain the velocity for each car?The velocity that each car will assume at the bottom of the hill is given by the equation presented as follows:
v = square root (2gh + kx²/m).
The parameters are given as follows:
g = 9.8 m/s is the acceleration relative to the gravity.h is the height of the hill.k is the spring constant.x = 0.25 represents the initial compression of the spring.m is the mass of the car.The parameters are given by the table in this problem, hence the velocities of each car are given as follows:
Group A: v = square root(2 x 9.8 x 1.2 + (65 x 0.25²)/0.75) = 5.38 m/s.Group B: v = square root(2 x 9.8 x 0.9 + (35 x 0.25²)/0.6) = 4.61 m/s.Group C: v = square root(2 x 9.8 x 1.1 + (40 x 0.25²)/0.55) = 5.05 m/s. -> closest to 5 m/s.Group D: v = square root(2 x 9.8 x 0.95 + (32x 0.25²)/0.84) = 4.58 m/s.More can be learned about velocities and springs at https://brainly.com/question/13858183
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Answer: group C
Explanation:
what is the approximate value of tc for an ideal bose gas at a density of 125 kg/m3, the density of liquid 4he? take m
The approximate value of tc for an ideal bose gas at a density of 125 kg/m3 is 8.3 * 10¹⁹ K
[tex]P_{c} = \frac{2mkt^{3/2} }{4 pi h^{2} } * (2.612)\frac{\sqrt{pi} }{2}[/tex]
[tex]125 kg/m^{3} = \frac{2(6.65*10^{-24})(1.38*10^{-23})^{3/2} }{4pi^{2}(1.05*10^{-34}} *(2.612)\ \frac{sqrt{pi}}{2}[/tex]
Tc = 8.3 * 10¹⁹ K
The substance's mass per unit of volume is its density (also known as specific mass or volumetric mass density). The Latin letter D can also be used to represent density, however the most common sign is (the lower case Greek letter rho). Mass divided by volume is the definition of density in mathematics, where is the density, m is the mass, and V is the volume. Density is sometimes loosely described as weight per unit volume, although this definition is incorrect technically; the term "specific weight" is more appropriate. An example of this is in the US oil and gas business.
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the north celestial pole is 35∘ above your northern horizon. this tells you that you are at:
You are at latitude 35∘ N , if the north celestial pole is 35∘ above your northern horizon . The north celestial pole is a point where all stars can be seen from the northern hemisphere.
All of the stars visible from the Northern Hemisphere spin about the North Celestial Pole in the sky. North Street Polaris stays virtually immobile in the sky and all the stars in the northern sky appear to revolve around it because it is almost directly aligned with the Earth's axis of rotation "above" the North Pole, the north celestial pole. This spot in the sky is virtually exactly where ar, also known as Polaris, is located.
The reasonably brilliant Pole Star is located extremely close to the North Celestial Pole, making it simple to detect it in the night sky. But there are no observable stars near the South Celestial Pole. All of the stars in the sky are centred on the North Celestial Pole.
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wave interference occurs for a. sound waves. b. light waves. c. water waves. d. all of the above choices are correct. e. none of the above choices are correct
Wave interference occurs for: sound waves, light waves. water waves. all the given option is correct.
What is Wave Interference?
The result of two or more waves colliding is interference. Depending on how the peaks and troughs of the overlapping waves line up, they may add up or may partially or completely cancel one another. The interference definition states that it is
The occurrence when two or more waves combine to generate a new wave with a bigger, smaller, or same amplitude.
The medium adopts a form as a result of the net influence of the two distinct waves due to wave interference. Let's use the example of two pulses with the same amplitude moving in opposite directions in the same medium to better comprehend.
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question 6 a 5 m chain with density 2 kg/m hangs off the roof of a building. how much work is required to pull the chain to the roof?
A 5 m chain with density 2 kg/m hangs off the roof of a building. 10 joules work is required to pull the chain to the roof.
The lowest amount of thermodynamic work, or energy, required to transfer an electron from a solid to a point in the vacuum immediately outside the solid surface is known as the work function (sometimes spelled workfunction). Here, the term "immediately" refers to a final electron position that is, on an atomic scale, far from the surface but still too close to the solid to be affected by ambient electric fields in the vacuum. The work function is a property of the material's surface rather than a characteristic of the substance in its bulk (depending on crystal face and contamination). When two dissimilar conductors are in complete equilibrium with one another, the space between them will have an embedded electric field due to the fact that relies on the material surface (electrically shorted to each other, and with equal temperatures). The work function refers to moving an electron many nanometers away from the surface so that the force between the electron and the surface's image charge may be disregarded. The electron must also be close to the surface in relation to any change in the surface structure, such as a change in the material composition, a surface coating, or a reconstruction, as well as the closest edge of a crystal facet.
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a line in the spectrum of atomic mercury has a wavelength of 255 nm. when mercury emits a photon of light at this wavelength, the frequency of this light is
The frequency of light is 1.18 × 10^15Hz
Wavelength = 255m
The frequency of light is the number of cycles of the light wave that pass a given point in a specified amount of time. Light waves are electromagnetic waves that are characterized by their frequency, which is measured in hertz (Hz).
Calculating the frequency -
f = c/ λ
where c is the speed of light and λ is the wavelength
Thus,
c = 3 × 10^18 m/s
λ = 255 × 1/ 10^9
= 255 × 10^7
Substituting the values in the formula -
= 3 × 10^18 / 255 × 10^7
= 1.18 × 10^15
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what maximum power can be radiated by a 13 cmcm -diameter solid lead sphere? assume an emissivity of 1.
Maximum power can be radiated by a 13 cm diameter solid lead sphere
is 232W
The melting point of lead, which is T = 328°c, is the highest temperature that can be raised.
The sphere's area is A = D2.
Using the maximum radiated power as a baseline and by inserting the values of the numbers:
P = 1.56 × [tex]10^{-8}[/tex] × 0.1² ×601³ = 232W
Energy transfer or conversion rate expressed as power. One joule per second, or one watt, is the definition of power in the International System of Units. Power is referred to as activity in some ancient writings. Scalar quantities include power.
Power is related to other factors; for instance, the power required to move a ground vehicle is calculated as the product of the vehicle's velocity, its aerodynamic drag, and the traction force on its wheels. The torque that a motor produces is multiplied by the angular velocity of its output shaft to produce the output power of the motor. Similarly, the power dissipated in an electrical component of a circuit is the sum of its current and voltage across the element.
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a 0.950-kg ball is dropped from rest at a point 3.30 m above the floor. the ball rebounds straight upward to a height of 1.90 m. taking the negative direction to be downward, what is the impulse of the net force applied to the ball during the collision with the floor?
The impulse of is the product of the average force and the duration it is excreted. The impulse of the net force exerted to the ball during the impact with the floor was 4.28 N-s in magnitude and direction.
The ball weighs 0.500 kg, according to the information provided.
The floor is 1.2 meters high.
The force of impulse
The impulse of is the product of the average force and the duration it is excreted.
One instant before the collision, the velocity is 4.852 meters per second.
One instant after the collision with the floor, the velocity was 3.71 meters per second squared.
The magnitude and direction of the ball's net force impulse during the collision with the floor.
4.28N-s.
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For the circuit of Fig.30.17 in the textbook, let C = 12.0nF , L = 23.0mH , and R = 78.0? .
Part A
Calculate the oscillation frequency of the circuit once the capacitor has been charged and the switch has been connected to point a
Part B
How long will it take for the amplitude of the oscillation to decay to 10.0% of its original value?
Part C
What value of R would result in a critically damped circuit?
Part A
The oscillation frequency of the circuit after the capacitor is charged and the switch is connected to point a:
given:
C = 12.0 nF = 12 x 10⁻⁹ F
L = 23.0mH = 2,3 x 10⁻² H
R = 78.0
f = ω/2π
Where ω is the corner frequency of the circuit and is given as:
ω = [tex]\sqrt{\frac{1}{LC} - \frac{R^2}{4L^2} }[/tex]
ω = [tex]\sqrt{\frac{1}{(12x10^{9-})(2.3 x 10^{-2})} - \frac{78^2}{4 (23x10^{-2})^2} }[/tex]
ω = [tex]\sqrt{\frac{1}{276 x 10^{-12}} -\frac{6084}{4761 x10^6} }[/tex]
ω = [tex]\sqrt{3.6 x 10^9 - 2.8 x 10^6}[/tex]
ω = 5.99 x 10⁴
f = ω/2π
f = 5.99 x 10⁴/2(3.14)
f = 0,9545 x 10⁴
f = 9545 Hz
So, the frequency of the circuit is 9545 Hz
Part B
The amplitude of the circuit can be expressed as a function of time, and it is expressed in the form.
A(t)= A₀e[tex]__{-Rt/2L}[/tex]
Here, A₀ is the amplitude when time, t = 0, we need to find the time it takes the oscillation to damp into 10%.
A(t) = 10%A = 0.10
0.1A₀ = A₀e[tex]__{-Rt/2L}[/tex]
0.1 = e[tex]__{-Rt/2L}[/tex]
Taking natural log on both sides and rearranging the variables, we get
t = -2LIn(0.1)/R
t = -2(2,3 x 10⁻²)(-2.3)/78.0
t = 1.35 x 10⁻³ s
So, the time taken for the oscillation to damp to 10% is 1.35 s
Part C
The critical damping of the circuit occurs when
R² = 4L/C
R = [tex]\sqrt{\frac{4L}{C} }[/tex]
R = 2768.87 Ω
So, the critical damping occurs for R = 2768.87 Ω
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the moon has a mass of 1×1022 kg, and the gravitational field strength at a distance r from the planet is 0.001 n/kg. what is the gravitational force exerted on the moon while it is in orbit around the planet?
a. 0 N
b. 1 x 10^19 N
c. 1 x 10^22 N
d. 1 x 10^25 N
The gravitational force exerted on the moon of mass 1×10²² kg is 1×10¹⁹ N. And the right option is b. 1×10¹⁹ N
What is gravitational force?Gravitational force is the most prevalent force in the universe, pulling together on any two objects with mass in the universe.
To calculate the gravitational force exerted on the moon, we use the formula below.
Formula:
F = mE.................... Equation 1Where:
F = Gravitational forcem = Mass of the moonE = Gravitational field strengthFrom the question,
Given:
m = 1×10²² kgE = 0.001 N/kgSubstitute these values into equation 1
F = ( 1×10²²×0.001)F = 1×10¹⁹ NHence, the gravitational force exerted on the moon is 1×10¹⁹ N.
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what makes the earth different from the other worlds that might have life in the solar system (and easier to detect from far away) is that only earth .
The solar system has a biosphere on its surface where photosynthesis can take place.
What is Biosphere?
The biosphere, usually referred to as the ecosphere, is the sum of all ecosystems on the planet. The area where life exists on Earth is another name for it. According to certain descriptions, the biosphere is practically a closed system in terms of matter, with few inputs and outputs.
The biosphere, according to the broadest definition of biophysiology, is the ecological system that encompasses all living things and their relationships, including their interactions with the lithosphere, geosphere, hydrosphere, and atmosphere.
It is generally believed that the biosphere began to evolve at least 3.5 billion years ago, beginning with a process of biopoiesis (which means life formed spontaneously from non-living matter, such as simple organic molecules) or biogenesis (which means life created from living stuff).
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question a 2 kg mass and a 5 kg mass are connected by a massless cord suspended over a massless and frictionless pulley. if the acceleration due to gravity is g, what will be the acceleration of the masses after they are released from rest?
The masses accelerate at a speed of 3g13 m/s2 after being released from rest.
m1 is 2 kilogram, while m2 is 5 kg. Because the pulley has no friction and no mass, the tension force on both sides of the string will be the same. [An inactive state for the Law of Motion] Both masses accelerate at the same rate. Let's say it is a m/s2.
Remember that 2 kg of mass is flowing downhill while 5 kg of mass is traveling upward, or the opposite is true.
Let's begin writing equations.
m1 g - T = m1a for a mass of 2 kg.
2g - T = 2a ————— (I) For a mass of 5 kg, T - m2g = m2a
T - 5g = 5a ————— (II) By combining the two equations, we arrive at 2g - 5g = 13a a = 3g13 m/s2.
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a spring with a force of 2.9 n / m has a relaxed 0.85 m distance, when a 0.5 kg mass is attached it stretches to 1.65 m. what is the elastic potential energy?
The calculated answer is 1.96kg * m \s2\s /2. The energy that is stored when a force is used to deform an elastic object is known as elastic potential energy.
Until the force is released and the object springs back to its original shape, doing labor in the process, the energy is retained. The object may be compressed, stretched, or twisted during the deformation. Since you are aware of the spring constant k, which is 144 N/m, and the spring stretch from equilibrium position x, which is 16.5 cm, or 0.165, you can use the equation
PE = 2 1 kx 2
= 2 1144(.165) 2
to determine the potential energy of the spring.
This, if you prefer SI terms, is kg * m 2 /s2, or 1.96 Joules.
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Weighing a Bacterium Scientists are using tiny, nanoscale cantilevers 4 micrometers long and 500 nanometers wide-essentially miniature diving boards-as a sensitive way to measure mass. The cantilevers oscillate up and down with a frequency that depends on the mass placed near the tip, and a laser beam is used to measure the frequency. A single E. coli bacterium was measured to have a mass of 710 femtograms = 7.10×10−16 kg with this device, as the cantilever oscillated with a frequency of 17.1 MHz .
Treating the cantilever as an ideal, massless spring, find its effective force constant.
If we consider the cantilever to be a perfect, massless spring, then K = 5.952N/m is its effective force constant.
How does science define force?The meaning of the term "force" is obvious. At about this point, it's perfectly permissible to describe a force as shoving or pulling. An object doesn't "have a force in it" or "contain a force." A force is applied to one thing by another.
Why is force such a big deal?A force can be a push or a pull, and it affects how we go about our daily lives because we can't open or close items, raise our legs or arms or accomplish a lot more without it.
BriefingNumerous E coli bacteria, m = 7.10 × 10⁻¹⁶
frequency =17.1 MHz
frequency of vibration, F = 1/2π√K/M
17.1×10⁶= 1/2π√K/ 7.10 × 10⁻¹⁶
K/ 7.10 × 10⁻¹⁶ = 7.10 ×10¹⁵
K = 5.952N/m
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a 10 kg mass is given an initial speed of 10 m/s up a 30o incline plane with coefficient of friction 0.50. calculate the maximum distance it moves up the incline plane.
The maximum distance it moves up the incline plane is 5.47m.
Maximum distance, velocity of mass v = 0
Final kinetic energy, Kf = 1/2 m[tex]v^{2}[/tex] = 1/2 × 10 ×[tex]10^{2}[/tex] = 500j
W = ΔK = Kf - Ki
-mgdcosθμ - mgsinθd = 0 - 500j
mgd(μcosθ + sinθ) = 500j
d = 5.47m
Regardless of the starting or ending point, distance can be defined as the amount of space an object has covered. How much ground an object has covered while moving is referred to as the scalar quantity known as distance. It is the object's overall change in position, or "how far out of place an object is," that is described by the vector quantity displacement. An object's total path traveled can be used to measure distance. As an illustration. The total distance covered by an automobile is 13 km if it drives 5 km east, 8 km north, and then back again.
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i need the answer for this one
Answer:
120 N.
Explanation:
This can be calculated using Newton's second law of motion, which states that the net force acting on an object is equal to the mass of the object multiplied by its acceleration (F = ma).
In this case, the mass of the object is 60 kg, and its acceleration is 2 m/s^2. so,the net force acting on the object is 60 kg * 2 m/s^2 = 120 N.
sn]]a dentist's drill accelerates from rest at 770 rad/s2 for 2.01 s. during its angular acceleration, how many revolutions has the drill turned?
The 14976.31 revolutions has the drill turned.
What is acceleration?
The rate of change in velocity is known as acceleration. Acceleration typically signals a change in speed, though this is not always the case. Because of the shifting direction of its velocity, an item moving on a circular path at a constant speed is still accelerating.
What is revolutions ?
When two objects orbit one other, there is a revolution. For instance, once every month, the Moon makes its way around the Earth.
Drill is initially rest ( w₀) = 0
Angular velocity = 814 rad/ s²
time = 4.84 sec
Equation of motion
Ф= w₀t ∝ 1/2∝ t²
where,
∝ = angular acceleration
we want to find no. of revolution which is write as
no.of radiation = distance travelled / 2π
Ф= (0) ( 4.84) + 1/2 (814) ( 4.84)²= 0+ ( 407) (4.84)²
n= Ф/ 2π = 1534.2192/ 2π= 14916.31
n= 14976.31
Therefore, 14976.31 revolutions has the drill turned.
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which arrangement of the sun, the moon, and the earth results in the highest high tides, and the lowest low tides on earth
Due to the alignment of the earth, moon, and sun, the moon and sun's gravitational pulls work in the same direction, producing the highest high tides and the lowest low tides.
What path does physics follow?Location in relation to another object is referred to as direction. Relative terminology, such as up, down, out, left, right, forward, backward, or sideways, can be used to express direction by comparing the position of one item to another.
How do you define direction?Direction can refer to the way something moves, the way you must go to get somewhere, the way something is beginning to take shape, or the direction you are facing.
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the highest frequency ultrasound devices have frequencies around 20 mhz. what is the wavelength of these sound waves inside the body?
The highest frequency ultrasound devices have frequencies around 20 mhz. 5 m lambda to 15 m lambda is the wavelength of these sound waves inside the body.
Formula for sound wave = sound wavelength (λ) = sound velocity (v) / Sound frequency (F).
After calculating sound wavelength by the above formula we get the wavelength in between 5 to 15.
A periodic wave's wavelength is its spatial period, or the length over which its shape repeats. It is a property of both traveling waves and standing waves, as well as other spatial wave patterns. It is the distance between two successive corresponding locations of the same phase on the wave, such as two neighboring crests, troughs, or zero crossings. The spatial frequency is the reciprocal of wavelength. The Greek letter lambda is frequently used to represent wavelength. The term wavelength is also occasionally used to refer to modulated waves, their sinusoidal envelopes, or waves created by the interference of several sinusoids. Wavelength and frequency are inversely related, with shorter wavelengths for higher frequencies and longer wavelengths for lower frequencies, assuming a sinusoidal wave travelling at a constant wave speed. The medium (such as a vacuum, air, or body of water) through which a wave travels determines its wavelength. Waves can be anything from music to light to water to periodic electrical signals in a conductor.
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What type of separation methods are described in the recipe? decantation and screening distillation and screening decantation and centrifugation distillation and filtration.
Type of separation methods described in the recipe are: A. decantation and screening.
What is decantation and screening?Process for the separation of mixtures of immiscible liquids or of a liquid and a solid mixture such as a suspension is called decantation. In this process, the precipitated liquid is separated from solid. According to the given instruction for the recipe, fat which is in liquid state is separated from the meat.
Practice of taking granulated ore material and separating it into multiple grades by particle size is called screening. In the process of screening, more liquid is separated by placing mixture on the screen. In this, gravity plays an important role for the process of separation.
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Note: The question given on the portal is incomplete. Here is the complete question.
Question: A recipe gives the instructions below
After browning the meat pour off fat from the pan to further reduce fat use a strainer.
what type of separation methods are described in the recipe
A decantation and screening
B distillation and screening
C decantation and centrifugation
D distillation and filtration
The electric potential along the x-axis is V=100e?2x/mV, where x is in meters.Part AWhat is Ex at x=1.0m?Express your answer as an integer and include the appropriate units.
27.23 V/m it the electric field strength at a distance 1.0m from origin in x direction.
given V=100[tex]e^-^2^x[/tex]
What is electric field?The physical field that surrounds electrically charged particles and exerts force on all other charged particles in the field, either attracting or repelling them, is known as an electric field (or E-field).
formula of electric field in term of electric potential is given by:
[tex]E_x[/tex] = [tex]-\frac{dV}{dx}[/tex]
=> - d(100[tex]e^-^2^x[/tex] )/dx
=>200[tex]e^-^2^x[/tex]
so [tex]E_x=[/tex] 200[tex]e^-^2^x[/tex] ----- (i)
now we have to find electric field strength at point x=1m
so putting the value of x in in equation (i) we get
[tex]E_x=[/tex] 200[tex]e^-^2[/tex]
=> 200/(2.71*2.71)
=>27.23
so electric field strength at point x=1 is 27.23 V/m
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A figure skater is spinning slowly with arms outstretched. Shebrings her arms in close to her body and her moment of inertiadecreases by 1/2. Her angular speed increases by a factor ofA. 2B. 1C. 4D. square root of 2E. 1/2
She draws her arms close to her body, which causes her moment of inertia to fall by half. She moves at an angle that is faster by a factor of A. 2B. 1C. 4D. L=Iω
L=Iω
L is a constant that is inversely proportional to the rotational inertia and the angular speed due to the conservation of angular momentum.
Whenever "I" falls, rises proportionately (inversely related) A - Unless you meant increased, which you didn't, Part B is asking the same thing. B would follow from that. If not, Part C proceeds as in Part A: That key equation indicates that they are inversely proportional. In terms of, we solve for ω
I=L/ω
The moment of inertia of a rigid body, also known as the mass moment of inertia, angular mass, second moment of mass, or more precisely, rotational inertia, is a property that establishes the torque required for the desired angular acceleration about a rotational axis, much like mass establishes the force required for the desired acceleration. Depending on the axis selected and the distribution of the body's mass, it may take more torque to modify the body's rate of rotation for bigger moments.
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a man 1.9 m tall is standing 4.0 m from the edge of the barn. will he be hit by the snowball?
The man will not be hit by the snowball as it passes well above him without touching him.
(a) The length of time in the air is determined by vertical motion.
ax = 0
ay = 9.8 m/s²
vx = v₀ cosθ₀ = 7 cos 40° = 5.36 m/s
vy = v₀ sinθ₀ = 4.5 m/s
Distance from the ground is given as s = 14 m, so,
14 = 4.5 t + (1/2 × 9.8 × t²)
4.9 t² + 4.5 t - 14 = 0
The positive root of t = 1.29 s
The horizontal distance, vx t + (1/2 × ax × t²) = 6.91 m
(b) We know, x - x₀ = vx t + (1/2 × ax × t²)
As ax = 0,
t = (x - x₀)/vx = 4/5.36 = 0.746 s
During this time, the snowball travels a horizontal distance
y - y₀ = vy t + (1/2 × ay × t²) = 6.08 m
Hence, 14 - 6.08 = 7.9 m above the ground and the snowball passes above the man without hitting him.
The question is incomplete. The complete question is '(a) A snowball rolls off a barn roof that slopes downward at an angle of 40°. The edge of the roof is 14.0 m above the ground and the snowball has a speed of 7.00 m/s as it rolls off the roof. How far from the edge of the barn does the snowball strike the ground if it doesn't strike anything else while falling?
(b) A man 1.9 m tall is standing 4.0 m from the edge of the barn. Will he be hit by the snowball?'
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A dog sits 1.50 m from the center of a merry-go-round and revolves at a tangential speed of 1.80 m/s. If the dog’s mass is 18.5 kg, what is the magnitude of the centripetal force on the dog?
Answer: Fc = 39.96 N
Explanation:
Fc = (mv^2)/r
Fc = (18.5 kg * (1.80 m/s)^2)/(1.50 m)
Fc = 39.96 N
5 V battery with metal wires attached to each end.
The figure shows two wires connected to a battery’s positive and negative terminals. These wires stop short of completing a circuit. Four points are marked on the wires. Point 1 is at the end of the wire connected to the positive terminal. Point 2 is at the negative terminal. Point 3 is at the positive terminal. Point 4 is at the end of the wire connected to the negative terminal.
What are the potential differences ΔV12=V2−V1, ΔV23=V3−V2, ΔV34=V4−V3, and ΔV41=V1−V4?
Enter your answers numerically separated by commas
The potential differences is ΔV12=V2−V1=0V
ΔV23=V3−V2=5V
ΔV34=V4−V3= 0V
and ΔV41=V1−V4=-5V
From the figure, there is no connection between the points 1 and 4 . Hence, the potential at the points 4 and 3 is same and is equal to zero.
[tex]\Delta V_{34} & =V_4-V_3 \\& =0[/tex]
Similarly, the potential at the points 1 and 2 is same and is equal to zero.
[tex]\Delta V_{12} & =V_2-V_1 \\& =0[/tex]
The potential difference between the points 4 and 1 is equal to potential difference between the points 3 and 2.
Given that the potential difference across the points 3 and 2 is,
[tex]\Delta V_{23} & =V_3-V_2 \\& =5 \mathrm{~V}[/tex]
The potential difference between the points 4 and 1 is also 5V.
[tex]\Delta V_{41} & =-\Delta V_{23} \quad\left(\because \Delta V_{23}=\Delta V_{14}\right) \\& =-5 \mathrm{~V}[/tex]
Therefore, the required answer is 0,5V, 0,-5V.
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Note:- The correct question could be,
5 V battery with metal wires attached to each end.
The figure shows two wires connected to a battery’s positive and negative terminals. These wires stop short of completing a circuit. Four points are marked on the wires. Point 1 is at the end of the wire connected to the positive terminal. Point 2 is at the negative terminal. Point 3 is at the positive terminal. Point 4 is at the end of the wire connected to the negative terminal.
What are the potential differences ΔV12=V2−V1, ΔV23=V3−V2, ΔV34=V4−V3, and ΔV41=V1−V4?
Enter your answers numerically separated by commas