Please some one help with this question

Answer:

= -6

Step-by-step explanation:

-12/2

= -6

Step-by-step explanation:

No. If you distribute the 'x', you get:

[tex]y = {x}^{2} + 3x[/tex]

The function is quadratic due to the exponetial term of x^2

Answer:

3,600

Explanation:

There's nine thousand numbers here, 4,500 of which are even, you will need to subtract mutiples of five from this number, making it even smaller.

subtract the non-even five's (exactly half of the 1800 hundred fives that fit in our little original number, (900!) ) 4,500-900= 3,600. Which should be your answer. :D

Step-by-step explanation:

The smallest possible number that is divisible by 45 when the blanked place of the number is filled is 345285.

The divisible rule of 9 and 5 are:

Two digits of the 6-digit number are missing.

[tex]X = 345 * 8*[/tex]

The smallest possible number from this is divisible by 45. The factors of 45 are 9 and 5.

[tex]45=9\times5[/tex]

Thus, the 6-digit number which is divisible by 45, must be divisible by 9 and 5.  

To be divisible with 5, the number has 0 or 5 in last. So the numbers can be,

[tex]X = 345 * 85\\X=345 * 80[/tex]

For first number, when the blank is filled with number 2 to make sum 9 and for second the blank number should be 7. Thus, the numbers,

[tex]X = 345 285\\X=3457 80[/tex]

Thus, the smallest possible number that is divisible by 45 when the blanked place of the number is filled is 345285.

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Answer:

(-1, -5)

(0, -2)

(-3, -11)

Step-by-step explanation:

y = 3x - 2.

→ 3×(-2)-2=-8 ≠0 ⇒(-2, 0) doesn’t correspond to input-output pairs for the function

→ 3×(-1)-2=-5 ⇒(-1, -5) corresponds to input-output pairs for the function

→ 3×(0)-2=-2 ⇒(0, -2) corresponds to input-output pairs for the function

→ 3×(2)-2=4≠3 ⇒(2, 3) doesn’t correspond to input-output pairs for the function

→ 3×(-3)-2=-11 ⇒(-3, -11) corresponds to input-output pairs for the function

The value of the function at the right endpoint of the rectangle is 5 +6k/n.

In the question above;

Th width of the interval is said to be  (5 -2) = 3.

So, the width of one of n parts of it = 3/n

To solve for the differences that exist between the left end point of the interval and the value of  x at the right end of the k-th rectangle, one can say that:

 k·(3/n) = 3k/n

Note that the value of x at shows the point of  difference added to the interval's left end and thus it will be:  2 + 3k/n

Therefore, the value of the function for the value of x will be:

 f(2 +3k/n) = 2(2 +3k/n) +1  = (4 +6k/n) +1

 = 5 +6k/n

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The experimental probability that the next train to pull in will be full is [tex]\rm \frac{4}{5}[/tex]. Probability is the ratio of the favorable event to the total number of events.

Probability means possibility. It deals with the occurrence of a random event. The value of probability can only be from 0 to 1. Its basic meaning is something is likely to happen.

The experimental probability that the next train to pull in will be full is found as;

[tex]\rm P= \frac{Favourable}{Total \ outcomes } \\\\\ P(full)= \frac{16}{16+4} \\\\\ P(full)=\frac{16}{20} \\\\ P(full)= \frac{4}{5}[/tex]

Hence, the  experimental probability that the next train to pull in will be full is [tex]\rm \frac{4}{5}[/tex].

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Answer:

It will always be 0 because the rule is anything times 0 is 0

Answer:

0

Step-by-step explanation:

Hey there!

The product of any number and 0 is zero

To explain why this is, just think of it visually

So lets say we are visually explaining 7 x 3

Here is a visual explanation

There are 7 strawberries

You take 7 more strawberries

You take 7 more strawberries again

This means that you are taking 7 strawberries 3 times thereby forming the equation, 7 x 3

Now lets say a numeber [tex]x[/tex] times zero is equal to what

Well we can visualize this again

There are [tex]x[/tex] strawberries in a group

You are taking zero of those groups

Meaning there are no groups

So if there are no groups

There are no strawberries

Meaning [tex]x[/tex] times zero is zero

Since [tex]x[/tex] is any number, the statement, the product of 0 and any number is 0 is true

This is why the product of 0 and any number is 0

Answer:22

Step-by-step explanation: since f(8) so x=8

substitiuting x in 2x+6

                                      f(8)= 2x8+6=22

so f(8)=22

Hope this helps! :)

Answer:

0 pars

Step-by-step explanation:

3-3=0

Answer:

m = [tex]\frac{1}{2}[/tex] , c = [tex]\frac{5}{2}[/tex]

Step-by-step explanation:

the equation of a line in slope- intercept form is

y = mx + c ( m is the slope and c the y- intercept )

given

y + 2x = 4 ( subtract 2x from both sides )

y = - 2x + 4 ← in slope- intercept form

with slope m = - 2

given a line with slope m then the slope of a line perpendicular to it is

[tex]m_{perpendicular}[/tex] = - [tex]\frac{1}{m}[/tex] = - [tex]\frac{1}{-2}[/tex] = [tex]\frac{1}{2}[/tex] , then

y = [tex]\frac{1}{2}[/tex] x + c ← is the partial equation

to find c substitute (3, 4 ) into the partial equation

4 = [tex]\frac{3}{2}[/tex] + c ⇒ c = 4 - [tex]\frac{3}{2}[/tex] = [tex]\frac{5}{2}[/tex]

y = [tex]\frac{1}{2}[/tex] x + [tex]\frac{5}{2}[/tex] ← equation of line

with m = [tex]\frac{1}{2}[/tex] and c = [tex]\frac{5}{2}[/tex]

The equivalent expression of [tex]\frac{(2mn)^4}{6m^{-3}n^{-2}}[/tex] is [tex]\frac{(2mn)^4}{6m^{-3}n^{-2}}[/tex]

The expression is given as:

[tex]\frac{(2mn)^4}{6m^{-3}n^{-2}}[/tex]

Evaluate the expression on the numerator

[tex]\frac{16m^4n^4}{6m^{-3}n^{-2}}[/tex]

Divide 16 by 6

[tex]\frac{8m^4n^4}{3m^{-3}n^{-2}}[/tex]

Apply the law of indices

[tex]\frac{8m^7n^6}{3}[/tex]

Hence, the equivalent expression of [tex]\frac{(2mn)^4}{6m^{-3}n^{-2}}[/tex] is [tex]\frac{(2mn)^4}{6m^{-3}n^{-2}}[/tex]

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Answer:

1.7

Step-by-step explanation: Combine multiplied terms into a single fraction

Answer: Heyaa! ~

Your Answer for X = 7

Step-by-step explanation:

             How to solve:

Hopefully this helps you! ^

Answer:

6x+8

Step-by-step explanation:

2(3x+4)= 2(3x) + 2(4) = 6x+8

Answer:

(4,5)

Step-by-step explanation:

-2x + 4y = 12

5x - 2y = 10

make them both set to y

4y = 2x + 12 -> y = 1/2x + 3

2y = 5x - 10 -> y = 5/2x - 5

since they're both equal to y, they are equal to each other

1/2x + 3 = 5/2x - 5

2x = 8

x = 4

plug it back in to get y

y = 1/2 (4) + 3

y = 5

Answer:

bottom left

Step-by-step explanation:

when divideing/mult by neg number, sign flips.

Answer:

37.2mm

Step-by-step explanation:

A = ½bh

h = (2A)/b

h = (2(39.06))/2.1

h = 78.12/2.1

h = 37.2mm

[tex]\\ \rm\Rrightarrow \sqrt{x²-10x+25}[/tex]

[tex]\\ \rm\Rrightarrow \sqrt{x²-5x-5x+25}[/tex]

[tex]\\ \rm\Rrightarrow \sqrt{x(x-5)-5(x-5)}[/tex]

[tex]\\ \rm\Rrightarrow \sqrt{(x-5)(x-5)}[/tex]

[tex]\\ \rm\Rrightarrow \sqrt{(x-5)^2}[/tex]

[tex]\\ \rm\Rrightarrow\pm (x-5)[/tex]

Solution set(for x-5)

for 5-x

Answer:

First, simplify the expression under the square root sign by factoring:

[tex]\implies x^2-10x+25[/tex]

[tex]\implies x^2-5x-5x+25[/tex]

[tex]\implies x(x-5)-5(x-5)[/tex]

[tex]\implies (x-5)(x-5)[/tex]

[tex]\implies (x-5)^2[/tex]

Therefore:

[tex]\implies \sqrt{x^2-10x+25}=\sqrt{(x-5)^2}[/tex]

[tex]\implies \sqrt{x^2-10x+25}=\pm(x-5)[/tex]

[tex]\implies \sqrt{x^2-10x+25}=|x-5|[/tex]

As the domain is -5 ≤ x < 5, then:

[tex]\implies y=-x+5[/tex]

and the range is 0 < y ≤ 10

Answer:

she could buy 5 outfits

Step-by-step explanation:

you multiply 7.17 by 3 = 21.51

700 - 21.51 = 678.49

678.49 - 242.33 = 436.16

436.16 - 33.68  = 402.48

402.48 divided by 77.40 = 5

1inch = 2.5cm

∆ 30cm

5cm =2inch

Answer:

it 288

Step-by-step explanation:

if u multiply 24x12 it gives you 288 hope this help you

Answer:

1.7.

Step-by-step explanation:

2x^3 + 9x^2 - 2x + 8 = 40

Substituting values for x in the range 1 to 2:

when x = (1.1):

f(1.1) = 2(1.1)^3 + 9(1.1)^2 - 2(1.1) + 8 = 19.32.

x = 1.3:

f(1.3) = 25.004

F(1.5) = 32

F(1.6) = 36.032

F(1.7) = 40.436   which is just greater than 40.

So the root is between 1.6 and 1.7.

f(1.65) = 38.19

Therefore the root is > 1.65 and < 1.7

and to  1 DP it is 1.7.

Answer:

Step-by-step explanation:

17.4-17.3=.1

that would be 1 moth

Answer:

  6.1 km

Step-by-step explanation:

The Pythagorean theorem tells you the relationship between the lengths of the sides of a right triangle.

  c² = a² +b² . . . . a, b are the short sides; c is the hypotenuse

__

The geometry of this problem can be modeled by a right triangle with legs 3.7 km and 4.9 km. The distance of interest is the hypotenuse of the triangle.

  c² = 3.7² +4.9² = 13.69 +24.01 = 37.70

  c = √37.70 ≈ 6.1

The straight-line distance is about 6.1 km.

Answer:

See below

Step-by-step explanation:

each term is the sum of the two before it

2 3 5 8 13 21 34

Answer:

[tex]x = 12[/tex]

Step-by-step explanation:

[tex]3x + 9 = 5x - 15[/tex]

[tex]2x = 24[/tex]

[tex]x = 12[/tex]

Answer:

-3125

Hope this helps!!

Answer:

If we square both sides then we get

x2-8x+16 = (x-4)2

Now if we expand the right side of the equation we get

x2-8x+16 = (x-4)(x-4)

x2-8x+16 = x2-8x+16

So no matter what x is, the right side will be equal to the left side.

However, if we look at the original equation on the left side, √(x2-8x+16) , the value under the square root symbol has to be greater than or equal to zero (otherwise we get an imaginary number and you might not be working with those yet)

Step-by-step explanation:

So in order for √(x2-8x+16) to be greater than or equal to zero, x has to be greater than or equal to 4. If x is less than 4 you get a negative number. If x is greater than 4, you'll get the same answer on both sides no matter what x is

[tex]\qquad\qquad\huge\underline{{\sf Answer}}[/tex]

Let's solve ~

[tex]\qquad \sf  \dashrightarrow \: \sqrt{ {x}^{2} - 8x + 16} [/tex]

[tex]\qquad \sf  \dashrightarrow \: \sqrt{ {x}^{2} - 4x - 4x + 16} [/tex]

[tex]\qquad \sf  \dashrightarrow \: \sqrt{ {x}^{} (x - 4) - 4(x - 4)} [/tex]

[tex]\qquad \sf  \dashrightarrow \: \sqrt{ (x - 4)(x - 4)} [/tex]

[tex]\qquad \sf  \dashrightarrow \: \sqrt{ (x - 4) {}^{2} } [/tex]

[tex]\qquad \sf  \dashrightarrow \: x - 4[/tex]

Now, it's given that ~

[tex]\qquad \sf  \dashrightarrow \:x \geqslant 4[/tex]

plug the value of x as 4 :

[tex]\qquad \sf  \dashrightarrow \:4 - 4[/tex]

[tex]\qquad \sf  \dashrightarrow \:0[/tex]

So, we can infer that :

Value of the required expression lies in :

[tex]\qquad \sf  \dashrightarrow \: \sqrt{ {x}^{2} - 8x + 16} \geqslant 0[/tex]

it's value is always greater than pr equal to 0, satisfying the given condition ~

Answer: 38 dollars

Step-by-step explanation: