PLEASE PLEASE HELP PICTURE INCLUDED

PLEASE PLEASE HELP PICTURE INCLUDED

Answers

Answer 1

Answer:

a is the answer

Explanation:


Related Questions

define density with a suitable formula​

Answers

Answer:

ratio between m/v

or d= m/v

m= mass

v= volume

Why is it important to warm up your muscles?
Warming up the muscles increases lactic acid build up
Warming up the muscles increases temperature and flexibility of your muscles Warming up the muscles increases your risk of injury
All of the above

Answers

Answer: Warming up the muscles increases temperature and flexibility of your muscles
Hey :)

The answer would be

B. Warming up the muscles increase temperature and flexibility of your muscles.

Because, lactic acid buildup is from overexerting yourself when working out, and warming up muscles does not increase your risk in injury, rather, it decreases your risk of injury

Hope this helps!

Describe two similarities and two differences between electric and magnetic field lines. (Consider such things as where they originate and terminate, how they are related to the direction and strength of the field, whether they are closed curves or lines, and whether there's anything you can say about their flux through a closed surface.). Others

Answers

Answer:

Please see below as the answer is self- explanatory.

Explanation:

Similarities:The field vector is tangent to the field lines at any point of the trajectory.The density of field lines is proportional to the strength of the field.Differences:Electrostatic Field lines originate in charge distributions of positive charges and end in charge distributions of negative charges.Magnetic Field lines are closed lines, due to there are no isolated magnetic charges discovered yet.Electrostatic Field lines have the direction of the trajectory taken by a positive test charge.Magnetic Field lines have the direction defined by right-hand rule.Vector net flux of electrostatic field lines through a closed surface is equal to the net charge enclosed by the surface.Vector net flux of magnetic field lines through a closed surface is always zero.

Similarities

Field vectorDensity of field lines

Differences

Dispersions of positive charges .No separated attractive charges.

Electric and Magnetic field lines.

Similarities:

The field vector is tangent to the field lines at any point of the trajectory. The density of field lines is relative to the quality of the field.

Differences:

Electrostatic Field lines begin in charge dispersions of positive charges and conclusion in charge dispersions of negative charges.

Magnetic Field lines are closed lines, due to there are no separated attractive charges found yet.

Learn more about "Magnetic Lines":

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need help ASAP. please and thank you ​

Answers

I believe the correct answer is 9

2
A crane has an arm to which is attached a frictionless pulley. A cable passes over the pulley and
supports a load of 10 kN as shown.
frictionless pulley
104N
30
30°
crane arm
load
10 KN
The crane arm exerts a force F on the pulley.
What is the value of F?
C
8.7 KN
10 KN
D
A
17 kN
B
5.0 KN

Answers

Answer:

17kN

Explanation:

The force of 10 kN in the cable and the load of 10 kN both have a component along the crane arm.

The force F exerted by the crane arm on the pulley is the sum of these 2 components.

Component of force in cable along the crane arm = 10 cos 30°

Component of load along the crane arm = 10 cos 30°

Considering the forces on the pulley,

F = 10 cos 30° + 10 cos 30°

Force F = 17.32 kN = 17 kN

A rubber cord catapult has cross-sectional area
25mmand initial length of rubber cord is 10c.
Its is stretched to 5cm and then released to
project a missile of mass 5gm. Taking
Yubber = 5x108N/m² velocity of projected
missile is :
(1) 20ms -
(2) 100ms
(3) 250ms
(4) 200ms)​

Answers

Potential energy stored in the rubber cord catault will be converted into kinetic energy of mass
2
1

mv
2
=
2
1


L
YAl
2



where l=5×10
−2
m, A=25×10
−6
m
2
, L=10×10
−2
m, m=5×10
−3
kg
⇒v=
mL
YAl
2





v=
5×10
−3
×10×10
−2

5×10
8
×25×10
−6
×(5×10
−2
)
2





v=250ms
−1

A sled of mass m is coasting at a constant velocity on the ice covered surface of a lake. Three birds, with a combined mass 0.5m, gently land at the same time on the sled. The sled and birds continue sliding along the original direction of motion. How does the kinetic energy of the sled and birds compare with the initial kinetic energy of the sled before the birds landed

Answers

Complete Question

A sled of mass m is coasting at a constant velocity on the ice covered surface of a lake. Three birds, with a combined mass 0.5m, gently land at the same time on the sled. The sled and birds continue sliding along the original direction of motion. How does the kinetic energy of the sled and birds compare with the initial kinetic energy of the sled before the birds landed?

a) The final kinetic energy is one half of the initial kinetic energy.

b) The final kinetic energy is one third of the initial kinetic energy.

c) The final kinetic energy is one quarter of the initial kinetic energy.

d) The final kinetic energy is one ninth of the initial kinetic energy.

e) The final kinetic energy is equal to the initial kinetic energy

Answer:

The correct option is b

Explanation:

From the question we are told that

   The mass of the sled is  m  

   The  mass of the three birds is  [tex]m_b = 0.5 m[/tex]

Generally from the law of momentum conservation,

  The initial momentum of the boat  =  final  momentum of the boat

Hence

     [tex]m * v = (m_b+ m) * v_2[/tex]

=>  [tex]m v = (0.5m+ m) * v_2[/tex]

=>  [tex]m v = 1.5m* v_2[/tex]

Here v is the velocity of the boat before the birds landed and [tex]v_2[/tex] is the velocity after the birds landed

So

       [tex]v_2 = \frac{2}{3} v[/tex]

Generally the initial  velocity of the boat before the birds landed is mathematically represented as

      [tex]K_i = \frac{1}{2} * m * v ^2[/tex]

Generally the final  velocity of the boat when the birds have landed is mathematically represented as

      [tex]K_f = \frac{1}{2} * (m_b + m ) * v_2^2[/tex]

=>   [tex]K_f = \frac{1}{2} * (0.5m + m ) * (\frac{2}{3} v)^2[/tex]

=>  [tex]K_f = \frac{1}{2} * 1.5m * (\frac{2}{3} v)^2[/tex]

=>  [tex]K_f = \frac{1}{2} * 1.5m * \frac{4}{9} v^2[/tex]

=>  [tex]K_f = \frac{1}{2}m v^2 * \frac{1}{3}[/tex]

Comparing this equation with that of the initial  kinetic energy

=>  [tex]K_f = \frac{1}{3} K_i[/tex]      

The kinetic energy of the sled and birds is one-third the initial kinetic energy of the sled before the birds landed.

What is kinetic energy?

When an object is in motion, then the energy possessed by the object at the state of motion is known as its kinetic energy.

Given data -

The combined mass of three birds is, M = 0.5m.

Let m be the mass of the sled. Then applying the conservation of linear momentum as,

The initial momentum of the boat  =  final  momentum of the boat

mv = (M + m)v'

v is the velocity of the boat before the birds landed and v' is the velocity after the birds landed.

mv = (0.5m + m)v'

mv = 1.5mv'

v = 3/2 v'

or

v' =2/3v

The initial kinetic energy of the boat before the birds landed is mathematically represented as

[tex]K_{1}= \dfrac{1}{2}mv^{2}[/tex]

And the final kinetic energy of the boat when the birds have landed is mathematically represented as,

[tex]K_{2}=\dfrac{1}{2}(M+m)v'^{2}\\\\K_{2}=\dfrac{1}{2}(1.5m) \times 4/9v^{2}\\\\K_{2}=\dfrac{1}{3} \times \dfrac{1}{2}mv^{2}\\\\K_{2}=\dfrac{1}{3} \times K_{1}[/tex]

Thus, we can conclude that the kinetic energy of the sled and birds is one-third the initial kinetic energy of the sled before the birds landed.

Learn more about kinetic energy here:

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What is called mass per unit

volume of a substances? | ककसी पदाथष के

द्रव्यमान प्रतत इकाई आयतन को क्या कहते हैं?

A : Mass | द्रव्यमान

B : Weight | भार

C : Density | घनत्व

D : Volume | आयतन

Ans:
C : Density | घनत्व​

Answers

Answer:

Density

Explanation:

The definition of density of a substance is the quotient between its mass and its volume. Such results in the mass per unit of volume.

When a 600 g mass is suspended from a spring, the spring stretches 1.2 cm. What is the spring constant of the spring? ​

Answers

Well first you need to know the formula for the spring force. It’s -1/2k*d

K being the constant

D being the displacement

We can actually find the force on the spring by calculating the weight of the block. It would be mass multiplied by gravity, convert the grams to kilograms first tho.

600/1000 = 0.6kg

0.6kg * 9.8 m/s^2 = 5.88N

Now plug everything into the equation, also convert the centimeters to meters:

1.2/100 = 0.012 meters

5.88 = -1/2k*(0.012)

5.88 = k*(0.006)

We could drop the negative sign because we really just want the magnitude of the spring constant.

K = 980N

Emmy kicks a soccer ball up at an angle of 45° over a level field. She watches the ball's trajectory and notices that it lands, two seconds after being kicked, about 20 m away to the north. Assume that air resistance is negligible, and plot the horizontal and vertical components of the ball's velocity as a function of time. Consider only the time that the ball is in the air, after being kicked but before landing. Take "north" and "up" as the positive x ‑ and y ‑directions, respectively, and use g≈10 m/s2 for the downward acceleration due to gravity.

Answers

Answer:

v_y = 10 - 10t

v_x = 10 m/s

Explanation:

This is a projectile launch where the x axis and y axis will be treated independently.

Now, towards the north on the x-axis, there will be no acceleration and so the speed is constant

So, vₓ = v₀ₓ

Whereas, on the vertical y - axis, the acceleration due to gravity with be negative since it's in a downward direction.

Thus, the equation is;

v_y  =  v_oy - gt

Now, the initial velocity component will be;

cos 45 = v₀ₓ/v₀

And sin 45 = v_₀y/v₀

Thus, we have;

v₀ₓ = v₀(cos 45)

Also, v_oy = v₀(sin 45)

Now, the initial velocity would be gotten from the equation of range which is;

R = (v₀² × sin 2θ)/g

Making v₀ the subject, we have;

v₀ = √(Rg/sin 2θ)

We are given;

R = 20 m

g = 10 m/s²

θ = 45°

Thus;

v₀ = √[20 × 10/(sin (2 × 45))]

v₀ = √200

v₀ = 14.14 m/s

Thus;

v₀ₓ = 14.14(cos 45) = 10 m/s

v_oy = 14.14(sin 45) = 10 m/s

Earlier we saw that;

v_y  =  v_oy - gt

Thus;

v_y = 10 - 10t

Also,we saw that;

vₓ = v₀ₓ

Thus;

v_x = 10 m/s

For the graph, we will use times of  t = 0, 0.2, 0.4, 0.6, 0.8, 1.0, 1.2

Thus, for each of those values of t, we will have the following values of v_oy

t (s)       v_oy (m / s)

0           10

0.2         8

0.4          6

0.6         4

0.8          2

1.0         0

1.2          -2

Graph is attached

Add the following vectors:

(a) (12, 5) + (6, 3)
(b) (−3, 8) + (6, −2)
(c) (3, 8, −7) + (7, 2, 17)
(d) (a, b, c) + (d, e, f)

Answers

Answer:

a. (18,8)

b. (3, 6)

c. (10, 10, 10)

d. (a+d, b+e, c+f)

Give me brainliest for this... Thanks

which produces wave particles that move and displace one another

Answers

Answer:

a guitar?

Explanation:

A bus rolls to a stop along a horizontal road without the driver applying the brakes,
What answer choice BEST explains why this occurred?
A. The natural state of the bus is not to be in motion.
B. The bus ran out of momentum.
C. The force of gravity slowed the bus until it stopped.
D. The opposing force of friction stopped the train.

Answers

Answer:

should be d because friction allows things to go faster or slower

It’s opinion a I’m a 100%

the graph below represents the relationship between velocity and time for an object moving along a straight line.

What is the magnitude of the object's acceleration?

1. 5.0 m/s^2

2. 8.0 m/s^2

3. 10. m/s^2

4. 20. m/s^2​

Answers

Answer:

10. m/s^2

Explanation:

40-(-10)= 50

50/5 =10

This question can simply be answered by using the slope of the velocity-time graph.

The correct answer for the magnitude of the acceleration is "3. 10 m/s²".

Since the graph between the velocity and the time is in the form of a straight line. Hence, the acceleration can be calculated as the slope of this line. We will use the first and last point of the line to calculate the slope (acceleration):

[tex]Acceleration = Slope = \frac{v_2 - v_1}{t_2-t_1}[/tex]

where,

v₁ = initial velocity from the graph = - 10 m/s

v₂ = final velocity from the graph = 40 m/s

t₁ = initial time from the graph = 0 s

t₂ = final time from the graph = 5 s

Therefore,

[tex]Acceleration = \frac{40\ m/s\ -\ (-\ 10\ m/s)}{5\ s\ -\ 0\ s}[/tex]

Acceleration = 10 m/s²

The attached picture shows the types of a velocity-time graph.

Learn more about the velocity-time graph here:

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PLEASE HLEP ME ASAP

Tom, a 13 year old boy, wants to train for a 5k Fun Run that his school is organizing. What area of fitness should Tom focus on? What activities should he do to improve this area?

Answers

Answer:

cardiovascular endurance

Explanation:

In order for Tom to successfully complete the marathon, he should focus on being able to maintain a constant pace without tiring easily.

which graph best demonstrates the general relationship between mass and temperature similar to the trend of thermal energy absorbed by your sand and water samples

Answers

Answer: the first one

Explanation: got it right on edg

Answer:

The first graph

Explanation:

Correct on Edge 2022! :]

what are Newton's 3 laws

Answers

Answer:

Newton 3 laws

Explanation:

1.object will not change its motion unless a force acts on it . 2.the force on an object is equal to it's time mass on acceleration. 3. When 2 o jecys interact they apply forces to each other of equal.

Answer- In the first law, an object will not change its motion unless a force acts on it. In the second law, the force on an object is equal to its mass times its acceleration. In the third law, when two objects interact, they apply forces to each other of equal magnitude and opposite direction.
Hope this helps:)

Select the correct answer.
Which scientist discovered the relationship between electricity and magnetism?
OA.
Nikola Tesla
OB
Alessandro Volta
OC.
Hans Christian Oersted
OD
Isaac Newton

Answers

Answer:

Hans Christian Oersted

Explanation:

a leaky faucet is dripping at a rate of 1 pint per hour how many hours to fill 10 gallons

Answers

Answer:

80 hours :)))))))))))))

Which of the following choices is not part of the scientific method

Answers

Answer:

What are the choices?

Explanation:


A ball is thrown upward in the air with an initial velocity of 40 m/s. How long does it take to
reach back to the point it was thrown from?

Answers

Answer:

You need the definition of acceleration (a=Vf-Vi/t) and 1 equation of linear motion (deltaX = Vi×t + 1/2×a×t^2). Since you know a is constant (gravity) and you know your initial Vi to be 40 m/s and your final velocity Vf to be zero (maximum height), then you can use thhe definition of acceleration to find time.

-9.81m/s^2 = (0-40m/s)/t

t = (-40)/(-9.81) s

t = 4.077s

Now that you have time, you should know all but deltaX in the equation of linear motion.

dX = (40m/s)(4.077s) + (1/2)(-9.81m/s^2)(4.077s)^2

dX = (163.099m) — (81.549m)

dX = 81.55m

1) A rigid tank contains 2 kg of 134a refrigerant at 800 kPa and 120°C. Determine tank volume and total internal energy.

Answers

Answer:

V = 0.07525 [m³]

U  = 655.74 [kJ]

Explanation:

To solve this problem we must use the superheated refrigerant table for refrigerant 134a. The attached image shows the specific volume and specific internal energy values for a pressure of 800 [kPa] and a temperature of 120 [°C].

m = mass =2 [kg]

the specific volume = v = 0.037625 [m³/kg]

The volume of the tank can be found using the following expression:

V = v*m

V = 0.037625*2 = 0.07525 [m³]

The Specific internal energy = u = 327.87 [kJ/kg]

U = u*m

U = 327.87*2 = 655.74 [kJ]

Can you help me please! Love you​

Answers

Answer:

I think its B. wait...U love ME?????

Erica is working in the lab. She wants to remove the fine dust particles suspended in a sample of oil. Which method is she most likely to u

Answers

Answer:  Option A is your answer

Explanation:

8. In explosives, potential energy is generally
stored in the form of
a thermal energy
b. electromagnetic energy
c. nuclear energy
d. chemical energy

Answers

Answer:

In explosives,potential energy is in the stored form of chemical energy.

A race car driver travelling at 15m*s^-1 accelerates at a constant value for 10.0s. She is now driving at a speed of 35 m*s^-1 What was her acceleration? Give your answer in m*s^-2 to one significant figure . Do not include units with your answer.

Answers

The driver speeds up with acceleration a so that

35 m/s = 15 m/s + a (10.0 s)

Solve for a :

20 m/s = a (10.0 s)

a = (20 m/s) / (10.0 s)

a = 2 m/s²

Glucose is a carbohydrate.
True
0r False

Answers

Answer: True

Explanation: Glucose is a carbohydrate.

Which statement describes S waves? A. They move side to side.B.They arrive betore P waves. C. They travel through liquids D. They occur at Earth's surtace.​

Answers

Answer: they move side to side

Explanation:

i took the test

(DUE IN FIVE MINUTES, QUICK)

Explain why your weight would change if you went to the moon, but your mass wouldn’t.

Answers

The moon's gravitation force is determined by the mass and the size of the moon. Since the moon has significantly less mass than the Earth, it will not pull objects toward itself at the strength that Earth will.

A 10 [kg] object is dropped from rest. a. How far will it drop in 2 [s]?

Answers

Answer:

y=0.5 g t^2

=0.5*10*2^2

=20 m

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