Answer:
asd
Explanation:
How do I graph distance ,speed ,velocity, and acceleration?
Answer:
distance is how much space is between, speed is how fast they are going, velocity is money and acceleration is going
Explanation:
brainliest please help
show the resultant force
8n downwards
since downwards force is greater than upwards just minus
is it true or false that chemical change like baking a cake normally has a color change?
If a chicken has a weight of 300 N on Earth, what would be its weight on Mercury if the gravity is 0.38.
Answer:
114N
Explanation:
gravity on earth: 10m/s (exact: 9.82)
mass if chicken = 300/10 = 30Kg
weight of chicken on mercury = 3.8 x 30 = 114N (you wrote 0.38 but Mercury's gravity is about 3.7)
Answer:
113.15 g
Explanation:
That's because the planets weigh different amounts, and therefore the force of gravity is different from planet to planet. For example, if you weigh 100 pounds on Earth, you would weigh only 38 pounds on Mercury. That's because Mercury weighs less than Earth, and therefore its gravity would pull less on your body.
HELP ASAP I WILL GIVE YOU 40 POINT AND BRAINIEST
Answer:
first page answer is B
second page answer is D
Explanation:
What is the density of 15 cm3 and 3 g?
Answer:
0.2
Explanation:
3/15
Charlie's father built a tree house in their backyard. He constructed a spiral staircase around the tree trunk and installed a ladder. Which will involve more work in climbing up the tree house from the ground?
Answer:
The spiral staircase will require more work
Explanation:
This is because, work can be calculated as force (which is mass of the individual climbing the stairs in this case) multiplied by distance (or length) of the stairs. The only variable that changes in the work done while climbing any of the two (ladder or spiral staircase) is the distance and it is obvious the length of the spiral staircase will be longer; thus the spiral staircase will involve more work.
A horse gallops for 3.5 minutes around the raceing track. During this time it changes velocity from 543 min to 628 min. Calculate the acceleration of the horse during this 3.5min interval
Answer:
The acceleration of the horse during this time interval is 24.286 m/min²
Explanation:
Given;
initial velocity of the horse during the gallop, u = 543 m /min
final velocity of the horse during the gallop, v = 628 m /min
time of motion, t = 3.5 minutes
The acceleration of the horse is given by the change in velocity per change in time;
[tex]a = \frac{v-u}{t}\\\\a = \frac{628-543}{3.5}\\\\a = 24.286 \ m/min^2[/tex]
Therefore, the acceleration of the horse during this time interval is 24.286 m/min²
HELP ASAP ILL DO ANYTHING.!!!!!!
Why does ice cream melt when you are holding it in a cone but not when it is sitting
in the freezer? Answer in terms of particles.
Answer: the heat from the environment melts the ice cream. When it’s in the freezer it doesn’t melt because both the freezer and ice cream are the same temperature
Explanation:
Answer:
the freezer and the ice cream is at the same temp while your hand and the cone is warmer so he heat from the cone transfers to the ice cream and heat it up and its particles move faster as it changes from a solid to a liquid.
You can add an easy question and give me some points if you would like!
How long will it take to travel 200.000 m [N] traveling 10 m/s [N]?
Answer: here are 1,000m in a km, so 200km is 200,000m
200,000m/10m/s = 20,000s
Explanation:
Answer:
15.9k
Explanation:
PLS HELP DUE AT 10 PM
A bowling ball weighing 71.2 N is swinging like a pendulum at the end of a 3.8 m rope.
As the ball swings through its lowest point, its speed is measured at 4.2 m/s. What is
the magnitude and direction of the acceleration of the ball at this point?
A. 4.64 m/s, upward
B. 4.64 m/s, downward
C. 5.16 m/s, upward
D. 5.46 m/s, downward
Answer:
A
Explanation:
PLS HELP THIS IS DUE IN TWO HOURS
Answer:
C
Explanation:
A 5 kg ball rolling at 1.0 m/s hits a 15 kg ball at rest. The balls stick together after the collision What is the
velocity of the two balls after the collision?
Answer:
0.25m/s
Explanation:
Given parameters
m₁ = 5kg
v₁ = 1.0m/s
m₂ = 15kg
v₂ = 0m/s
Unknown:
velocity after collision = ?
Solution:
Momentum before collision and after collision will be the same. For inelastic collision;
m₁v₁ + m₂v₂ = v(m₁ + m₂)
Insert parameters and solve for v;
5 x 1 + 15 x 0 = v (5 + 15 )
5 = 20v
v = [tex]\frac{5}{20}[/tex] = 0.25m/s
Motion of a potter's wheel is an example of
motion
Answer:
bus , running boy etc
Explanation:
moving body is called motion .
e.g. running boy , bus, birds flying etc
A juggler throws a beanbag into the air with a speed of 1.0 m/s.
How long does it take for the beanbag to reach its maximum height?
Cody’s car accelerates from 0m/s to 65 m/s northward in 25 seconds. What is the acceleration of the car?
Answer:
v=v(initial)+at
45=0+15a
a= 3m/sec²
Explanation:
edge 2020
Do atomic bombs and nuclear reactors function in the same manner?
Answer:
No, they do not function in the same manner.
Explanation:
I actually don't know why.
does anyone know the answer to this ?????
Answer:
as fuel is combusted,the rocket pushes the gas is backward and the gas is pushed the rocket forward
Explanation:
hope this helps :]
Which of these is an example of a longitudinal wave?
Answer:
D. Sound waves
Explanation:
The following options are missing:
A. radio wave
B. X-rays
C. Light waves
D. Sound waves
There are two kinds of waves: longitudinal and transverse.
In longitudinal waves, the vibrations are parallel to the direction of wave travel. Examples of longitudinal waves include: sound waves and ultrasound waves.
In transverse waves, the vibrations are at right angles to the direction of wave travel. All electromagnetic waves (e.g. light waves, microwaves, radio waves and X-rays) are transverse waves.
Which two fundamental forces are only attractive?
O A. Gravitational and strong nuclear
O B. Electromagnetic and weak nuclear
O C. Electromagnetic and strong nuclear
O D. Gravitational and weak nuclear
The two fundamental forces that are only attractive is A. Gravitational and strong nuclear.
What connection exists between the strong nuclear force and gravity?The "strong" nuclear force outperforms gravity by a factor of 10 to the 38th. While gravitational and electromagnetic forces have relatively large ranges of action, the strong and weak nuclear forces operate at close ranges. All objects are affected by the strong and weak nuclear forces, whereas smaller objects are affected by gravitational and electromagnetic forces.
Nuclear forces are the most enticing of the four fundamental forces. There was no explanation provided as to how the nucleus in the atom is kept together by electromagnetism, which maintains matter together.
Therefore, option A is correct.
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You are helping your friend move a new refrigerator into his kitchen. You apply a horizontal force of 280 N in the positive x direction to try and move the 63 kg refrigerator. The coefficient of static friction is 0.55.
Complete Question
You are helping your friend move a new refrigerator into his kitchen. You apply a horizontal force of 280 N in the positive x direction to try and move the 63 kg refrigerator. The coefficient of static friction is 0.55.
(a) How much static frictional force does the floor exert on the refrigerator? Give both magnitude and direction.
magnitude N
direction
(b) What maximum force do you need to apply before the refrigerator starts to move?
Answer:
a
The magnitude is [tex]F_f = 339.57 \ N[/tex]
The direction is [negative x - axis ]
b
The maximum force to be applied for the refrigerator to start moving is
[tex]F_{max} = 339.57 \ N[/tex]
Explanation:
From the question we are told that
The horizontal force applied is [tex]F_a = 280 \ N[/tex] the direction is +ve x-axis
The mass of the refrigerator is [tex]m = 63 \ kg[/tex]
The coefficient of static friction is [tex]\mu_s = 0.55[/tex]
Generally the frictional force exerted on the refrigerator is mathematically represented as
[tex]F_f = \mu * m * g[/tex]
=> [tex]F_f = 0.55 * 63 * 9.8[/tex]
=> [tex]F_f = 339.57 \ N[/tex]
From the value obtained we see that the static force exerted by the floor on the refrigerator is greater than the force (280 N ) exerted by the person and the direction is -ve x-axis
Generally the maximum force that is to be applied by the person is mathematically equal to the force exerted by the floor on the refrigerator but the direction is in the positive x-axis i.e
[tex]F_{max} = F_f = 339.57 \ N[/tex]
In 1900, a German physicist discovered an equation that matched experimental data about the emission of light by a hot surface. *
a. Max Planck
b. Sir Isaac Newton
c. James Clerk Maxwell
d. Christian Huygens
1) An object is dropped from the top of tower of hight 156.8m and at the same time another object is thrown vertically upward with the velocity of 77.1 m/s from the feetof tower,when and where the object meet
Answer:
The objects meet after 2.033722438s, at a height 136.5334679m from the ground.
Explanation:
Call the object being dropped A and the object being thrown B.
When the objects meet, the time ('t') for both objects will be equal, and the sum of their distances will be equal to 156.8m.
Figure out the distance for A in terms of time, t:
s = ut + (1/2)at²
= 0t +(1/2)(9.8)t²
=4.9t²
Figure out the distance for B in terms of time, t:
s = ut + (1/2)at²
=(77.1)t + (1/2)(-9.8)t²
=77.1t - 4.9t²
We now adding the distances gives us 156.8, so can write:
(4.9t²) + (77.1t - 4.9t²) = 156.8
77.1t = 156.8
∴ t = 2.033722438s
To find the distances, plug in this value for t:
For A: 4.9t² → 20.26653209m
For B: 77.1t - 4.9t² → 136.5334679m
The objects will meet 155.2 meters below the top of the tower after 15.7 seconds.
What is the height?The formula to calculate the time it takes for the object thrown upwards to return to the ground:
Time = 2 * Initial velocity / gravitational acceleration
Plugging in the values given in the question, you can calculate the time as follows:
Time = 2 * 77.1 m/s / 9.8 m/s^2 = 15.7 seconds
To determine when and where the objects meet, you can use the following formula to calculate the height of the object thrown upwards at any given time:
[tex]Height = Initial velocity * time - (1/2) * gravitational acceleration * time^2[/tex]
Plugging in the time calculated above and the initial velocity and gravitational acceleration given in the question, you can calculate the height of the object at the time it returns to the ground as follows:
Height = 77.1 m/s * 15.7 s - (1/2) * 9.8 m/s^2 * (15.7 s)^2 = -1.6 meters
This means that the object thrown upwards returns to the ground 1.6 meters below the point where it was launched. The object dropped from the top of the tower will also have fallen a distance of 156.8 meters in the same amount of time, so the two objects will meet at a point 156.8 meters - 1.6 meters = 155.2 meters below the top of the tower
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PLS HELP ITS WORTH SO MANY POINTS AHH
LONGITUDINAL
SURFACE
TRANSVERSE
HEAT
Answer:
C. transverse
Why are bubbles round?
(A serious physics question)
Answer:
The Science of Round Bubbles
But once a bubble is sealed and removed from the wand, the tension in the bubble shrinks it to the smallest possible shape for the volume of air inside of it. That's a sphere, which is the familiar round shape we see when bubbles float through the air.
Explanation:
A ball is thrown horizontally at a speed of 16 m/s from the top of a cliff. If the ball hits the ground 6.0 s later, approximately how high is the cliff? 360m 240m 180m 150m
Answer:
Y = 176.4 m
Explanation:
For the height of cliff we will analyze the vertical motion. We will apply the 2nd equation of motion:
Y = V₀y*t + (0.5)gt²
where,
Y = Height = ?
V₀y = Initial Vertical Velocity = 0 m/s (since, ball is thrown horizontally)
t = time = 6 s
g = 9.8 m/s²
Therefore,
Y = (0 m/s)(6 s) + (0.5)(9.8 m/s²)(6 s)²
Y = 176.4 m
Which best compares kinetic energy and temperature?
Answer:
^ correct
Explanation:
Option A on edge 2020
PLEASE HELP!!!!! thx
Answer:
I thick it's ccc not for sure
Un montañero de 65kg de masa ha ascendido a la cima del Everest, la montaña más alta del mundo de 8848m de altura sobre el nivel del mar. Calcula el trabajo que ha realizado para subir los últimos 500m
Answer:
El trabajo realizado para subir los últimos 500 metros es 318727,5 joules.
Explanation:
Por la definición de trabajo sabemos que el montañero debió contrarrestar trabajo causado por la gravedad terrestre. Si asumimos que el cambio de la altura es muy pequeño en comparación con el radio del planeta (6371 kilómetros vs. 0,5 kilómetros), entonces podemos considerar que la aceleración gravitacional es constante y la ecuación de trabajo ([tex]\Delta W[/tex]), medido en joules, que reducida a:
[tex]\Delta W = m\cdot g\cdot \Delta z[/tex] (1)
Donde:
[tex]m[/tex] - Masa del montañero, medido en kilogramos.
[tex]g[/tex] - Aceleración gravitacional, medida en metros por segundo al cuadrado.
[tex]\Delta z[/tex] - Distancia vertical de ascenso del montañero, medida en metros.
Si tenemos que [tex]m = 65\,kg[/tex], [tex]g = 9,807\,\frac{m}{s^{2}}[/tex] y [tex]\Delta z = 500\,m[/tex], entonces el trabajo realizado por el montañero para subir es:
[tex]\Delta W = (65\,kg)\cdot \left(9,807\,\frac{m}{s^{2}} \right)\cdot (500\,m)[/tex]
[tex]\Delta W = 318727,5\,J[/tex]
El trabajo realizado para subir los últimos 500 metros es 318727,5 joules.