Please help with this question​

Answer:

Power = ML²T⁻³

Pressure = ML⁻¹T⁻²

Explanation:

Applying,

Power(P) = Work(W)/Time(t)

P = W/t..................... Equation 1

But

W = Fd............. Equation 2

Where F = force, d = distance

Also,

F = ma.............. Equation 3

Where m = mass, a = acceleration.

Also,

a = v/t................  Equation 4

Where v = velocity

Also,

v = d/t............... Equation 5

Where d = distance

Substitute equation 5 into equation 4

a = d/t²................. Equation 6

Substitute equation 6 into equation 3

F = m(d/t²)........... Equation 7

Susbtitute equation 7 into equation 2

W = m(d/t²)×d

W = md²/t²........... Equation 8

Substitute equation 8 into equation 1

P = (md²/t²)/t

P = md²/t³............ Equation 9

In dimension,

mass(m) = M, distance(d) = L, time(t) = T

Substitute into equation 9

P = ML²/T³

P = ML²T⁻³

And

Pressure(R) = Force(F)/Area(A)

R = F/A................ Equation 10

F = md/t²,

A = d²

Susbtitute into equation 10

R = (md/t²)/d²

R = m/t²d

Therefore,

R = ML⁻¹T⁻²

Answer:

Explanation:

The frictionless surface implies that the speed of the spring is at a max. When the speed of the spring is at its max, the potential energy in the spring is 0. Use the equation for the Total Energy in a Spring/Mass System:

KE + PE = [tex]\frac{1}{2}kA^2[/tex] where KE is the Kinetic Energy available to the spring, PE is the potential energy available to the spring, and the sum of those is equal to one-half times the spring constant, k, times the amplitude of the spring's movement away from the equilibrium position. Sometimes this amplitude is the same as the displacement of the spring. This can be tricky. But since we are only given one value for the distance, we are going to use it as an amplitude. Keeping in mind that the PE is 0 when KE is at its max, then the equation becomes

KE + 0 = [tex]\frac{1}{2}kA^2[/tex] or to put it simpler terms:

KE = [tex]\frac{1}{2}kA^2[/tex] We need to find the value for KE before we can fully solve the problem we are being tasked with.

Filling in using the info given:

[tex]KE=\frac{1}{2}(2.0)(.06)^2[/tex] Notice I added another place of significance to the 2 because 1 simply isn't enough and the physics teacher in me can't handle that. Simplifying a bit:

[tex]KE=(.06)^2[/tex] because the k = 2 cancels out the 2 in the denominator of the 1/2. So

KE = 3.6 × [tex]10^{-3[/tex]

Now plug that in for KE and solve for v:

KE = [tex]\frac{1}{2}mv^2[/tex]:

[tex]3.6*10^{-3}=\frac{1}{2}(5.0)v^2[/tex] and

[tex]v=\sqrt{\frac{2(3.6*10^{-3})}{5.0} }[/tex] gives us a velocity of

v= [tex]3.8*10^{-2[/tex]

Answer:

The correct answer is - At the maximum height, the velocity and acceleration vectors are perpendicular to each other.

Explanation:

When the football reaches maximum height, then the vertical component of velocity will be zero and therefore the only component of velocity left will be the horizontal component, and acceleration of the object will be downward, due to gravity.

So at the maximum height, there is horizontal velocity only which means velocity is horizontal and acceleration is vertical thus, the velocity and acceleration are perpendicular to each other.

Answer:

Train Bike Truck

Explanation:

Answer:

the types of force shown in the picture is

balanced force.

Answer:

15m

Explanation:

W=f×s

[tex]s = \frac{w}{f} \\ s = \frac{900j}{60n} \\ s = 15m [/tex]

Given:

Force,

Work done,

We know,

→ [tex]W = F\times s[/tex]

or,

→ [tex]s = \frac{W}{F}[/tex]

By putting the values, we get

      [tex]= \frac{900}{60}[/tex]

      [tex]= 15 \ m[/tex]

Thus the above response i.e., "Option c" is right.

Learn more about work done here:

https://brainly.com/question/8625856

Answer:

The impulse applied by the stick to the hockey park is approximately 7 kilogram-meters per second.  

Explanation:

The Impulse Theorem states that the impulse experimented by the hockey park is equal to the vectorial change in its linear momentum, that is:

[tex]I = m\cdot (\vec{v}_{2} - \vec{v_{1}})[/tex] (1)

Where:

[tex]I[/tex] - Impulse, in kilogram-meters per second.

[tex]m[/tex] - Mass, in kilograms.

[tex]\vec{v_{1}}[/tex] - Initial velocity of the hockey park, in meters per second.

[tex]\vec{v_{2}}[/tex] - Final velocity of the hockey park, in meters per second.

If we know that [tex]m = 0.2\,kg[/tex], [tex]\vec{v}_{1} = -10\,\hat{i}\,\left[\frac{m}{s}\right][/tex] and [tex]\vec {v_{2}} = 25\,\hat{i}\,\left[\frac{m}{s} \right][/tex], then the impulse applied by the stick to the park is approximately:

[tex]I = (0.2\,kg)\cdot \left(35\,\hat{i}\right)\,\left[\frac{m}{s} \right][/tex]

[tex]I = 7\,\hat{i}\,\left[\frac{kg\cdot m}{s} \right][/tex]

The impulse applied by the stick to the hockey park is approximately 7 kilogram-meters per second.  

Answer:

A screw is a mechanism that converts rotational motion to linear motion, and a torque (rotational force) to a linear force.[1] It is one of the six classical simple machines. The most common form consists of a cylindrical shaft with helical grooves or ridges called threads around the outside.[2][3] The screw passes through a hole in another object or medium, with threads on the inside of the hole that mesh with the screw's threads. When the shaft of the screw is rotated relative to the stationary threads, the screw moves along its axis relative to the medium surrounding it; for example rotating a wood screw forces it into wood. In screw mechanisms, either the screw shaft can rotate through a threaded hole in a stationary object, or a threaded collar such as a nut can rotate around a stationary screw shaft.[4][5] Geometrically, a screw can be viewed as a narrow inclined plane wrapped around a cylinder.

Explanation:

Work is transfer of energy in an object when it travel some distance by external force,

Work= force × displacement

Explanation:

Start with what you know and list your knowns and unknowns

F = ma

F= 3N

m = 6kg

a =?

3N = 6kg x a

solve for a

3N / 6kg = a

According to law of conservation of energy,

= ½mv² = mgh

= mv² = 2mgh

= v² = 2mgh/m

= v = √2gh

So, now just put the values of g & h, abd you are done;

= v = √2×9.8×1.6

= v = √31.36

= v = 5.6 m/s

Answer:

T = 0.01 s

Explanation:

Given that,

The frequency of the beats of a hummingbird, f = 100 Hz

We need to find the period of the hummingbirds flaps. Let the time is t. We know that the relation between frequency and time period is given by :

T = 1/f

Put all the values,

T = 1/100 = 0.01 s

So, the time period of the humming bird is 0.01 s.

The direction of acceleration due to gravity is always towards earth, going downwards.

mark me brainliesttt :))

Answer:

0.011

Explanation:

Answer:

9.5 m/s

Explanation:

Distance, S = 150m

Acceleration, a = 0.3 m/s^2

Initial velocity, u = 0 m/s

Final velocity, v

Use kinematics equation

v^2 - u^2 = 2aS

v^2 - 0 = 2*0.3*150 = 90

v = sqrt(90) = 9.49 m/s

Answer:

E = 1.1 10⁶ N / C

Explanation:

In this case they indicate that we can approximate the membrane as a parallel plate capacitor, we can use

            E = [tex]\frac{\sigma}{\epsilon_o }[/tex]

note that in this case the electric field created by each plate goes in the same direction, they are added

let's calculate

            E =  [tex]\frac{10^{-5}}{8.85 \ 10^{-12}}[/tex]

            E = 1.1 10⁶ N / C

Answer: [tex]0.05\ mm[/tex]

Explanation:

Given

Cross-sectional area of wire [tex]A_1=4\ mm^2[/tex]

Extension of wire [tex]\delta l=0.1\ mm[/tex]

Extension in a wire is given by

[tex]\Rightarrow \delta l=\dfrac{FL}{AE}[/tex]

where, [tex]E=\text{Youngs modulus}[/tex]

[tex]\Rightarrow \delta_1=\dfrac{FL}{A_1E}\quad \ldots(i)[/tex]

for same force, length and material

[tex]\Rightarrow \delta_2=\dfrac{FL}{A_2E}\quad \ldots(ii)[/tex]

Divide (i) and (ii)

[tex]\Rightarrow \dfrac{0.1}{\delta_2}=\dfrac{A_2}{A_1}\\\\\Rightarrow \delta_2=0.1\times \dfrac{4}{8}\\\\\Rightarrow \delta_2=0.05\ mm[/tex]

Answer:

a. Acceleration, a = 0.28 m/s²

b. Distance, S = 156 meters

Explanation:

Given the following data;

Initial velocity = 30 km/h

Final velocity = 45 km/h

Time = 15 seconds

a. To find the acceleration;

Conversion:

30 km/h to m/s = 30*1000/3600 = 8.33 m/s

45 km/h to m/s = 45*1000/3600 = 12.5 m/s

Mathematically, acceleration is given by the equation;

[tex]Acceleration (a) = \frac{final \; velocity - initial \; velocity}{time}[/tex]

Substituting into the equation;

[tex]a = \frac{12.5 - 8.3}{15}[/tex]

[tex]a = \frac{4.2}{15}[/tex]

Acceleration, a = 0.28 m/s²

b. To find the distance travelled, we would use the second equation of motion given by the formula;

[tex] S = ut + \frac {1}{2}at^{2}[/tex]

Where;

S represents the displacement or height measured in meters.

u represents the initial velocity measured in meters per seconds.

t represents the time measured in seconds.

a represents acceleration measured in meters per seconds square.

Substituting into the equation, we have;

[tex] S = 8.3*15 + \frac {1}{2}*(0.28)*15^{2}[/tex]

[tex] S = 124.5 + 0.14*225[/tex]

[tex] S = 124.5 + 31.5 [/tex]

S = 156 meters

Answer:

[tex] \large{ \tt{☄ \: EXPLANATION}} : [/tex]

[tex] \large{ \tt{♨ \:LET'S \: START}} : [/tex]

[tex] \large{ \boxed{ \tt{❁ \: ACCELERATION \: (a) = \frac{FINAL \: VELOCITY(v) - INITIAL \: VELOCITY(u)}{TIME \: TAKEN \: ( \: t \: )}}}} [/tex]

- Plug the values & then simplify !

[tex] \large{ \bf{↬a = \frac{60 - 0}{300} = \frac{60}{300} = \boxed{ \bold{ \bf{0.2 \: m {s}^{ - 2} }}} }}[/tex]

[tex] \large{ \tt{۵ \: AGAIN, \: USING\: SECOND \: EQUATION \: OF \: MOTION}} : [/tex]

[tex] \boxed{ \large{ \bf{✾ \: s = \frac{u + v}{2} \times t}}}[/tex]

- Plug the values & then simplify !

[tex] \large{ \bf{↦s = \frac{0 + 60}{2} \times 300 = \boxed{ \bold{ \bf{9000 \: m}}}}}[/tex]

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Answer:

What she said is right I know it is

Answer:

10 is the correct answer

Answer:

Total Distance: 420 meters

Diameter: 42 cm

Notice the units meters vs cm

420÷ 42 = 10 total revolutions

Answer:

84.05

Explanation:

F=f+F

F=49.05+35

=84.05

Answer:

Change is for better and is necessary too. Everyone knows it but only the ones who apply it are the ones whom we call as intelligent. When a person changes in an order to make his life better, he chooses the right thing because staying put at a place in life doesn't take anyone anywhere.

Taking the example of a few infamous personalities, whom we consider as intelligent, we see a common thing that each one of them had a certain vision in life and in order to achieve it, they were ready to accept any kind of change and still are. So, this makes it clear that change is what leads us to our goal and in order to achieve it, we need to change with time.

Answer:

3.125×10²¹ N/C

Explanation:

Electric Field: This can be defined as the force experienced per unit charge. The S.I unit of electric Field is N/C

Applying,

E = F/q.................. Equation 1

Where E = Electric Field, F = Force experienced, q = Charge of an electron.

From the question,

Given: F = 500 N, q = 1.6×10⁻¹⁹ C

Substitute these values into equation 1

E = 500/(1.6×10⁻¹⁹)

E = 312.5×10¹⁹

E = 3.125×10²¹ N/C

Answer:

The system will tend to person A

Explanation:

A force is defined as either a pull or a push, in this scenario person A weighs lass that person B, so the resultant effect of the 10N interactive force will tend towards person A.

This is solely because person A is less than person B in weigh

Answer:

The path difference must be equal to an integral (1 * lambda, 2 * lambda, -------n * lambda) number of wavelengths for constructive interference to occur.

Answer:

All of above

Explanation:

Answer:

When electrons flow through wires from a terminal to a terminal circuit is created.

Answer:

Coefficient of kinetic friction = 0.38 (Approx.)

Explanation:

Given:

Applied force = 45 N

Mass of wooden crate = 12 kg

Find:

Coefficient of kinetic friction

Computation:

Coefficient of kinetic friction = Applied force / (Mass)(Acceleration due to gravity)

Coefficient of kinetic friction = 45 / (12)(9.8)

Coefficient of kinetic friction = 45 / 117.6

Coefficient of kinetic friction = 0.3826

Coefficient of kinetic friction = 0.38 (Approx.)

Answer:

Breaker

Explanation: A wave is a motion or disturbance that transfers energy from one location to another without any permanent displacement of the particles involved in the wave motion.

Wave motion can occur in various media such as water, air etc a wave is described as a breaker when it steepens and before it finally stops or losses its energy/collapses.