Please help this is for a friend with co vid- 19

The winning payout for the horse is $45

To determine the winning payout for the horse, you need to use the following formula:

Odds against winning: B / (A + B)

Betting amount: X Payout: X + (X * B / A)where A is the denominator of the odds and B is the numerator of the odds.

Here, the odds against winning are 2:7.

So, the denominator (A) is 7 and the numerator (B) is 2.

The betting amount is $35.

Plugging these values into the formula:

Payout = 35 + (35 * 2 / 7)

Payout = $45.

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Answer:

Step-by-step explanation:

m<1 = 50

m<2 = 22

m<3 = 108

m<4 = 50

m<5 = 65

m<6 = 50

m<7 = 43

m<8 = 65

m<9 = 75

m<10 = 18

m<11 = 25

m<12 = 40

m<13 = 115

m<14 = 65

m15 = 115

Answer:

B

Step-by-step explanation:

The function reaches the y-axis at the point (0,5).

The asymptote is the line that the function follows but never quite reaches. In this case, the function follows the path of y = 2. However, it never exactly fits the line.

The y-intercept is (0,5) and the asymptote is y = 2. The answer, then, is B.

Good luck ^^

The equation of the asymptote is y = 2 and the coordinate of the y-intercept will be (0, 5). Then the correct option is B.

An asymptote is a line that constantly reaches a given curve, but does not touch at any infinite distance.

The equation of the function is given below.

[tex]\rm f(x) = 3(0.2)^x + 2[/tex]

The asymptote of the function is given as by substituting x as infinity, then the equation of the asymptote will be

[tex]\rm y = 3(0.2)^{\infty} + 2\\\\y = 2[/tex]

Then the y-intercept of the function will be given by substituting y = 0, then the y-intercept will be

y = 3(0.2)⁰ + 2

y = 3 + 2

y = 5

The coordinate of the y-intercept will be (0, 5).

Then the correct option is B.

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Answer:

x=8

Step-by-step explanation:

The ratio of the sides is 7:14=1:2. So, the ratio of DF:XZ is 1:2. DF=2x-5, and XZ=22. This makes the ratio. 2x-5:22=1:2. That means 2x-5 is half of 22, which is 11. We can solve from there.

Check your work:

Answer:

960

20 times 12 moths to get 240 then multiply that by 4 years and get 960 .

Step-by-step explanation:

sorry if wrong ]

have a good day /night

may i pleae have a branlliest .

20 x 12=240 x 4 =960

Answer:

960

Step-by-step explanation:

Answer:

28

Step-by-step explanation:

Answer:

8

Step-by-step explanation:

(-2,c) and (-1,10)

10-c

-1--2

10-c

1

We need the fraction to be 2, or 2/1. The bottom number is 1, so we technically already have the answer. But we still need to plug in a number for c. To get 2, we need to subtract 8 from 10.

So c is 8.

---

hope it helps

sorry my work was a mess

Answer:

Any number less than greater than or equal to 18

Step-by-step explanation:

Answer:

4x² + 8x - 5

= 4(3/4)² + 8(3/4) - 5

= 4 × 9/16 + 24/4 - 5

= 36/16 + 24/4 - 5

= 9/4 + 6 - 5

= 9/4 +1

= 3.25

Step-by-step explanation:

Hope it helps!!

Question:

There are 30 candies in a box, all identically shaped. 5 are filled with coconut, 10 with caramel, and 15 are solid chocolate.

You randomly select a piece of candy and eat it (so it is NOT replaced!), then select a second piece. Find the probability of each event

(a) The probability of selecting two solid chocolates in a row.

(b) The probability of selecting a caramel and then a coconut candy.

Answer:

[tex](a)[/tex] [tex]P(Chocolates) = \frac{7}{29}[/tex]

[tex](b)[/tex] [tex]P(Caramel\ and\ Coconut) = \frac{5}{87}[/tex]

Step-by-step explanation:

Given

[tex]Coconut = 5[/tex]

[tex]Caramel = 10[/tex]

[tex]Chocolate = 15[/tex]

[tex]Total = 30[/tex]

For probabilities without replacement, 1 is subtracted after the first selection.

So, we have:

Solving (a): Two solid chocolates

This is calculated as:

[tex]P(Chocolates) = P(First\ Chocolate) * P(Second\ Chocolate)[/tex]

[tex]P(Chocolates) = \frac{n(Chocolate)}{Total} * \frac{n(Chocolate) - 1}{Total - 1}[/tex]

[tex]P(Chocolates) = \frac{15}{30} * \frac{15 - 1}{30 - 1}[/tex]

[tex]P(Chocolates) = \frac{15}{30} * \frac{14}{29}[/tex]

[tex]P(Chocolates) = \frac{1}{2} * \frac{14}{29}[/tex]

[tex]P(Chocolates) = \frac{7}{29}[/tex]

Solving (a): Caramel and Coconut

This is calculated as:

[tex]P(Caramel\ and\ Coconut) = P(Caramel) * P(Coconut)[/tex]

[tex]P(Caramel\ and\ Coconut) = \frac{n(Caramel)}{Total} * \frac{n(Coconut)}{Total - 1}[/tex]

[tex]P(Caramel\ and\ Coconut) = \frac{10}{30} * \frac{5}{30- 1}[/tex]

[tex]P(Caramel\ and\ Coconut) = \frac{10}{30} * \frac{5}{29}[/tex]

[tex]P(Caramel\ and\ Coconut) = \frac{1}{3} * \frac{5}{29}[/tex]

[tex]P(Caramel\ and\ Coconut) = \frac{5}{87}[/tex]

Answer:

35% of that number is 91.

Step-by-step explanation:

we need to first find 25% of what number equals 65.

65×100÷25 = 260

Then, if you use the same method again, 60% of 260 would be 156.

We know "that" number is 260, and all we need to do is find 35% of it.

35% of 260 = 91

Hope this helped :)

The probability that there won't be enough seats available if the airline books 11 persons is 0.3274. It is not unlikely for such an overbooking to occur because the probability of the overbooking is greater than 0.05.

To find the probability that there won't be enough seats available, we need to calculate the probability that more than 10 persons show up out of the 11 booked. This can be done using the binomial distribution.

The probability of a person showing up for the flight is given as 86.0%, which means the probability of not showing up is 14.0%. Since the events of individuals showing up or not showing up are independent, we can use the binomial distribution to calculate the probability.

Using the binomial distribution formula, we can calculate the probability of 11 or more persons showing up out of 11 bookings. This gives us a probability of 0.3274.

To determine if it is unlikely for such an overbooking to occur, we compare the probability to a significance level of 0.05. If the probability is less than or equal to 0.05, we can consider it unlikely. However, in this case, the probability of 0.3274 is greater than 0.05, indicating that it is not unlikely for such an overbooking to occur.

Therefore, the correct answer is OD. It is not unlikely for such an overbooking to occur, because the probability of the overbooking is greater than 0.05.

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Answer:

A. q>p because, assuming this line starts somewhere after 0, this is positive progression

Step-by-step explanation:

[tex]2 \sin(90 - x) - \cos(360 - x) [/tex]

[tex]2 \cos(x) - \cos(x) [/tex]

[tex] \cos(x) [/tex]

Jasmine's Z-score is 2. The number of parks per capita in the city is [tex]1.38 * 10^-4[/tex] in scientific notation.

To calculate Jasmine's Z-score, we can use the formula:

Z = (X - μ) / σ

where X is the individual score (85), μ is the mean (76), and σ is the standard deviation (4.5).

Z = (85 - 76) / 4.5

Z = 9 / 4.5

Z = 2

Since Jasmine's Z-score is 2, this tells us that her score of 85 is 2 standard deviations to the right of the mean.

Now let's calculate the probability of randomly selecting a math exam with fewer than 15 questions using the mean of 20 and a standard deviation of 2.5.

To apply the empirical rule, we need to determine how many standard deviations 15 is away from the mean.

Z = (X - μ) / σ

Z = (15 - 20) / 2.5

Z = -5 / 2.5

Z = -2

Since 15 is 2 standard deviations to the left of the mean, we can use the empirical rule to estimate the probability.

According to the empirical rule:

The data is within one standard deviation of the mean for about 68% of the time.

The data is within 2 standard deviations of the mean for about 95% of the time.

99.7% of the data are contained within a 3 standard deviation range around the mean.

Since 15 is beyond 2 standard deviations to the left, the probability of randomly selecting a math exam with fewer than 15 questions would be very close to 0. In this case, we can assume it's effectively 0%.

Now let's calculate the number of parks per capita in the city with 890,000 people and 123 parks.

Number of parks per capita = Number of parks / Population

Number of parks per capita = 123 / 890,000

To write the answer in scientific notation, we can express 890,000 as 8.9 x 10^5:

Number of parks per capita =[tex]123 / (8.9 * 10^5)[/tex]

Calculating the result:

Number of parks per capita =[tex]1.38 * 10^-4[/tex]

Therefore, the number of parks per capita in the city is[tex]1.38 * 10^-4[/tex] in scientific notation.

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Answer:

It will take her 15 weeks to have enough money for the computer.

Step-by-step explanation:

$1200 - $300 = $900

900 divided by 60 gives you 15

Therefor, it'll take Shirley 15 weeks to save $1200.

Answer:

The answer is 3,100

Step-by-step explanation:

If you subtract the 8,500 from his parents and his football scholarship you get 4,900 and then take the 1,800 from his saved money, You get what he still needs, which is 3,100.

Answer:

8/5 < x < 12/5

Step-by-step explanation:

(2 - x)² < 4/25​

2 - x < ±2/5

2 - x < 2/5

-x < -8/5

x > 8/5

2 - x > -2/5

-x > -12/5

x < 12/5

Therefore, your answer is 8/5 < x < 12/5

Answer:

c. 4

Step-by-step explanation:

yan sagot

Answer:

(0.4291, 0.4743)

Step-by-step explanation:

Using the relation :

p ± Zcritical * Sqrt[(p(1-p)) / n]

P = x / n =. 1447 / 3203 = 0.4517

1 - p = 0.5483

Zcritical at 99% = 2.575

Sqrt[(p(1-p)) / n] = sqrt(0.4517(0.5483)) / 3203) = 0.008793

p ± Zcritical * 0.008793

Lower boundary = 0.4517 - (2.575 * 0.008793) = 0.4291

Upper boundary = 0.4517 + (2.575 * 0.008793) = 0.4743

(0.4291, 0.4743)

Answer:

∠DAB = ∠DBA

Then AD=DB from above statement

Answer:

The absolute value of 12, is 12...

Step-by-step explanation:

Answer:

-12

Step-by-step explanation:

Step-by-step explanation:

feeling the compa

Como te amo mucho

Random samples of size 50 are taken from this population, and the number of fully vaccinated individuals in each sample, represented by the variable X, follows an approximately binomial distribution with n = 50 and p = 0.727.

(a) Using the binomial formulas, the mean (μ) of X is calculated as np, which is 50 * 0.727 = 36.4, rounded to the nearest tenth. The standard deviation (σ) is given by the square root of np(1-p), which becomes √(50 * 0.727 * 0.273) ≈ 4.1.(b) To determine the values within 3 sigma of the mean, we calculate 3 times the standard deviation (3σ) and find the range around the mean: 36.4 ± 3 * 4.1, resulting in the range of approximately 24.1 to 48.7. Therefore, the common numbers of fully vaccinated people expected in samples of this size, given the 72.7% vaccination rate, would fall within this range.(c) By using appropriate commands on a calculator or technology, the following probabilities can be determined:

The probability of one sample having exactly 35 fully vaccinated people is obtained from the binomial distribution as P(X = 35), which can be calculated using the binompdf command.

The value of P(X ≤ 25) can be found using the binomcdf command, representing the probability of having 25 or fewer fully vaccinated people in a sample. The probabilities should be reported to four decimal places for accuracy.

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a) The p- value is 0.0094.

b) True

c) Yes

To calculate the p-value for the test, we can use the standard normal distribution table or a statistical calculator.

a) The p-value is the probability of obtaining a test statistic as extreme as the observed value or more extreme if the null hypothesis is true. Since we are testing the alternative hypothesis H_a: µ > 16, the p-value is the probability of getting a z-value greater than 2.34.

Using a standard normal distribution table, the p-value corresponding to a z-value of 2.34 is 0.0094.

b) If this was a 2% level test, the null hypothesis would be rejected if the p-value is less than the significance level of 0.02.

Since the p-value (0.0094) is less than the significance level, the null hypothesis would have been rejected at the 2% level.

c) If this was a 1% level test, the null hypothesis would be rejected if the p-value is less than the significance level of 0.01.

Since the p-value (0.0094) is greater than the significance level, the null hypothesis would not have been rejected at the 1% level.

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Answer:

-8,5

Step-by-step explanation:

8,5 because the "m" is 5 squares down and 8 squares to the right.