Please help the question is on the photo attached

The symbol for atomic sulfur and molecular sulfur is different. The symbol for atomic sulfur is S and the symbol for molecule sulfur is S₈.

The symbol of an element or atom is just the representation with few alphabets with no digit.

example

Symbol for Oxygen is O

Symbol for Nitrogen is N

Symbol for sulfur is S

However in case of molecule we know that molecule is the combination of atoms. In sulfur molecule 8 sulfur atom is present so we represent the molecule as  S₈.

Thus the elemental form of sulfur is an eight atomic molecule

The forms is represented as S₈.

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Because AgCl is insoluble in water. But Cu2Cl2, MgCl2 are soluble in water.

Silver chloride, AgCl, is a white crystalline solid with a poor water solubility. AgCl occurs naturally as the mineral chlorargyrite. When exposed to sunshine or heat, silver chloride oxidises to silver and chlorine.

AgCl has various disinfecting and antiseptic qualities and is also used to treat mercury toxicity. This substance is used in antimicrobials, wound healing products, personal deodorants, water treatment, and antidotes.

Ingestion, inhalation, and skin contact are all harmful. Prolonged exposure can cause argyria, a blue discoloration of the skin. Irritating to the eyes and skin. Dangerous to the environment.

Light sensitive compounds include silver chloride. They may also respond to light extremely quickly and lose their characteristics. As a result, they must be stored in dark bottles to prevent light from entering.

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People argue how to take into account for varied roughness conditions in different regions of natural and restored waterways since they are typically constructed of compound channels rather than simple cross-sectional areas like rectangles, trapezoids, triangles, or simple curved forms.

What is a compound channel ?

A "compound" channel consists of a main channel that can handle regular flows and a flood plain that is submerged during heavy flows on one or both sides.

According to several researchers and practitioners, non-compound channels with channel beds and sides constructed of different materials or main channels with unusually shaped geometry and varying roughness should be the key applications for these composite roughness coefficient approaches. Furthermore, they propose the use of a composite roughness for compound channels when there are negligible roughness variations between the main channel and flood plains. These engineers recommend that the segmented conveyance approach instead be used in the majority of compound channel applications.

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A solution of 9% (by weight) ethylene glycol (62 g/mol) in water at 25 °C has a vapor pressure of 23.1 torr.

Raoult's Law.

Consider a 100 g solution.

Ethylene glycol mass is 9 g

water mass is 100 g - 9 g = 91 g moles.

Ethylene glycol = 9 g times 1 mole/62 g =0.1451 moles.

moles water = 9 g x 1 mole/18 g = 5.0555 moles water

Total moles are equal to 0.1451 + 5.0555 = 5.2006 moles

the mole percentage of water = 5.0555 moles/5.2006 moles  = 0.9720

Vapor pressure is equal to the mole percentage of water times the pure water vapor pressure (0.9720)(23.8 torr) = 23.1359 torr.

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organic compound contains 73.14% carbon, 7.37% hydrogen and the rest oxygen. if the mole mass of this compound was 82.1 grams per mole. the empirical formula for this compound would be C10H12O2

73.14% C , 7.37% H  , 19.49 % O

lets say there are 100g of compound then there are 73.14g C , 7.37g H  , 19.49g O

no of moles of C = 73.14 / 12.01 = 6.09 mol

no of moles of H = 7.37/1.0079 = 7.31 mol

no of moles of O = 19.49/15.9994 = 1.22 mol

now divide by the smallest no of moles( 1.22 mol) for each

we get C:H:O = 4.99 : 5.99 : 1.00

therefore C5H6O is the empirical formula

molecular formula = n ( C5H6O)

n = molecular mass / empirical mass of compound = 164.2 / 82 = 2

molecular formula =2( C5H6O) = C10H12O2

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At any time for at least the last years C) 65,000 years.

To protect the climate and to mitigate climate change, firstly we have to control the emission of the greenhouse gases. Burning of fossil fuels like coal, petroleum etc releases a huge quantity of carbon dioxide into the atmosphere. Therefore, reducing the greenhouse gas emission is important to mitigate or stop climate change.

C) 650,000 years

Over the past 650,000 years, there has been almost seven cycles of glaciation(glacial advance and retreat) leading to excessively high carbon dioxide levels.

Thus, option C is the correct choice.

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Yes, Water moves through osmosis as it transitions from a high concentration to a low concentration. Osmosis via the dialysis tube was demonstrated by the fact that there was an increase in liquid in the dialysis bag and a decrease in water and iodine solution in the cup.

Osmosis is the passage of water through a membrane, and movement occurs continuously. A membrane is not required for diffusion, which is the movement of molecules.

They both transition from a high concentration to a low concentration, they don't require energy, and they happen in both plants and animals.

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Mg(OH)[tex]_{2}\\[/tex] + 2HCl [tex]- >[/tex] HgCl[tex]\\_{2}[/tex] +2H[tex]_{2}[/tex]O

200Mg(OH)[tex]_{2}\\[/tex]  = 200/58.32 of Mg(OH)[tex]_{2}\\[/tex] = 3.429 mol of Mg(OH)[tex]_{2}\\[/tex]

1 mole of Mg(OH)[tex]_{2}\\[/tex] reacts with 2 moles of HCl = 10.125 moles of HCl

therefore result from the above equation is 6.858 moles of HCl .

Excess remaing HCl in the solution is 3.267 moles

we have to titrate the solution with 0.100M of NaOH.

HCl +NaOH [tex]- >[/tex] NaCl+ H[tex]_{2}[/tex]O

therefor the amount of NaOH required is 3.267/0.100

it is 32.67 ml

32.7ml of 0.100 m naoh would be needed to back titrate an analytical solution containing at most 200 mg of mg(oh)2 (fw 58.32) to which 45.0 ml of 0.225m hcl was added

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The energy of a wave with a wavelength of 7.3E-9 m is 2.72 x 10^-17 Joules.

The wavelength is described as the spatial period of a periodic wave the distance over which the wave's shape repeats.

To calculate the energy, we use the Planck's equation

E = h x c / λ

substitute the values of the given parameters, we have

Planck's constant in joules (h = 6.6261 × 10⁻³⁴ J⋅s),

speed of light (c = 299792458 m/s).

λ  =  7.3E-9 m

Energy =  6.6261 × 10⁻³⁴ x  (299792458/   7.3E-9 m)

Energy = 2.72 x 10^-17 Joules.

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The freezing point of a 0.09500 m aqueous solution of glucose is -0.1767 °C.

Let's use the freezing point depression's accumulative feature.

ΔT=Kf.m.i

i= Van't Hoff factor (number of ions dissolved). Due to the non-electrolyte nature of glucose, I = 1

m = molality (mol of solute/kilogram of solvent).

We have these numbers → is 0.095 m

The freezing-point-depression constant for water Kf is 1.86 °C/m when

ΔT = T° freezing pure solvent - T° freezing solution

(0° - T° freezing solution)=  1.86 °C/m for . 0.095 m. 1

T° of freezing solution= 1.86 °C/m. 0.095 m . 1 → -0.1767°C

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Answer:

MgS thus, magnesium sulphide

The strength of attraction of the water molecules to each other is the hydrogen bonding.

The slowest evaporating liquid might be the water. Water 's hydrogen bonding, being the most powerful sort of intermolecular force, might be the toughest to triumph over to break out into the fueloline kingdom and could bring about the longest time. Hydrogen bonds do not form in all molecules because hydrogen can only form these bonds with highly electronegative atoms. It is a weak type of force that happens when a hydrogen atom is bonded to an atom which has a high electronegativity.

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The equilibrium constant at a temperature of 25°C is Kp = 28.18. This value can be expressed to three significant digits as Kp = 28.2.

A state of balance between conflicting forces or influences is known as equilibrium. It is a principle that is applied in a variety of fields, including as physics, chemistry, and economics.

The following equation can be used to determine the equilibrium constant for the specified reaction:

Kp = [Cl₂]²[H₂O]² / [HCl]⁴[O₂]

The partial pressures of the gases can be used to determine Kp on the assumption that the gas is ideal.

Kp = (PCl₂)²(PH₂O)²/ (PHCl)⁴(PO₂)

Kp is easily calculable if the partial pressures of each gas are known. Finding the equilibrium constants at a given temperature is important because no pressures are provided in this scenario.

According to the information in the thermochemical table, Kp = 28.18 is the equilibrium constant at 25°C. 3 significant figures can be used to express this amount Kp = 28.2.

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Answer:

C6H12O6 is molar mass of fructose

Explanation:

the major component of honey is fructose.180.16g/mol

Here the correct conjugate acid-base pair will be: [tex]\mathrm{HSO}_3^{-} \:and\: \mathrm{SO}_3^{2-}[/tex]

Option (a) is the correct choice.

A conjugate acid-base pair, according to the Brnsted-Lowry definition of acids and bases, consists of two substances that are distinct only in that they contain a proton (H+). When a proton is supplied to a base, a conjugate acid is created, and vice versa when a proton is taken away from an acid, a conjugate base is created.

An illustration of a conjugate acid-base pair is HOCN and OCN-. There is only one proton (H+) that separates the two. Every base has a conjugate acid, and every acid has a conjugate base.

In the given chemical equation:

[tex]$$\begin{aligned}& \mathrm{HSO}_3{ }^{-}+{{\mathrm{CN}^-} \longrightarrow \:\:\:\:\:\:\:\mathrm{HCN}+\mathrm{SO}_3^2}^{2-} \\& \text { acid base } \text { conjugate base } \text { conjugate acid} \\& &\end{aligned}$$[/tex]

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The complete question should be like:

Identify the acid and conjugate base pair in the following:

[tex]$$\mathrm{HSO}_3{ }^{-}+\mathrm{CN}^{-} \rightarrow \mathrm{HCN}+\mathrm{SO}_3{ }^{2-}$$[/tex]

[tex](a) \:\mathrm{HSO}_3^-$ and $\mathrm{SO}_3{ }^{2-}\\(b) \:\mathrm{HCN}$ and $\mathrm{SO}_3{ }^{2-}\\(c) \:HSO_3^-$ and $CN^-\\(d)\: \mathrm{CN^-}$ and $S0_3{ }^{2-}[/tex]

The inhibitory effect of an uncompetitive inhibitor is greater at high [s] than at low [s] because kcat/kM = 8.5 x 107 (M.s)-1

Upland and lowland are conditional descriptions of a plain based on elevation above sea level. In studies of the ecology of freshwater rivers, habitats are classified as upland or lowland.

Uncompetitive inhibition is an example of a reversible inhibition.

At [S] > KM the effect of the inhibitor on reducing Vmax is apparent because as [S] increases, V approaches Vmax / α′

At [S] < KM the effect of the inhibitor is minimal because as [S] decreases, V approaches Vmax[S] / KM.

kcat = Vmax/[Etotal]

= ( 164*10-6 (mol/L)min-1 )/(1*10-9 mol/L)

= 1.64 x 10^5 min-1

kcat/kM = ( 164000 min-1 / 32*10-6 M

= 5125*106 (M.min)-1

= 8.5 x 107 (M.s)-1

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If the reaction occurs at 298K and 1 atmosphere of pressure, the work done by the CO₂ is -24.8 Joules.

Work is the energy required to move something against a force. The energy of a system can change due to work and other forms of energy transfer such as heat. Gases do expansion or compression work with the equation W = - P * ΔV.

From the question given

molarity of (NaHCO₃) = 0.1m

Volume of NaHCO₃ (V) = 100ml * 10⁻³ L / 1 ml = 0.1L

T (temperature) = 298k

P (pressure) = 1atm

moles of NaHCO₃

= molarity * Volume in Liters

= 0.1m * 0.1L = 0.01L

NaHCO₃ + HCl -> CO₂ + H₂O + NaCl

moles of CO₂ = moles of NaHCO₃ * (coefficient of CO₂ / Coefficient of NaHCO₃)

= 0.01L * 1/1

= 0.01 mol (moles of CO₂)

so, initial moles of CO₂ = 0

final moles of CO₂ = 0.01mol (based from the calculation)

Δn 0.01 - 0 = 0.01mol

Now, let's use work formula (as mentioned above on explanation part)

Work = - P * ΔV

= - Δn * R *T

Where R = 8.314J / mol.K

= - ( 0.01mol * 8.314 J / mol*K * 298K)

= -24.8J

Therefore, the work done by the CO₂ on this 100ml solution is -24.8Joules.

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The change in enthalpy of vaporization is 27.4 kJ/mol that can be calculated using Clausius-Clapeyron relation.

The Clausius-Clapeyron relation is used to characterize a discontinuous phase transition between two phases of the same constituent such as ice. The plot is drawn between 1/T vs ln P.

T1= 25+273=298 K

P1=363 Torr

T2= 46.3+273 = 319.3 K

P2= 760 Torr which is the atmospheric pressure.

By using the Clausius-Clapeyron equation,

ln(P2/P1)=ΔH/R[1/T1-1/T2]

ln (760/363)=ΔH/8.314x10^-3[1/298-1/319.3]

ΔH=27.44 kJ/mol

Therefore, the change in enthalpy of vaporization is 27.4 kJ/mol.

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2.17x10^-33kj/mol of energy is damaged by the photons which are caused by the light.

The Energy of Proton:

The energy of a photon has a direct relationship with the frequency of the photon. It can be defined as the energy a single photon carries.

The amount of energy is directly proportional to the photon's electromagnetic frequency and thus, equivalently, is inversely proportional to the wavelength.

Given that:

The light lies between 445nm and 470nm. so the value of c is 15nm

wavelength=4577.5nm

If the photon's wavelength is known, the photon's energy can be calculated using the formula :

[tex]E=\frac{h c}{wavelength}[/tex]

h is Planck's constant,h=6.626x10^-34  c is the speed of light and the wavelength of the radiation are all represented in the equation.

Now substitute the values in the formula,

[tex]E=\frac{ 6.626*10^-34*15}{457.5}[/tex]

E=2.17x10^-33kj/mol

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The reaction is exergonic. that is the free energy change delta G for a reaction is -46.11 kJ/mol, the reaction is exergonic.

Chemical thermodynamics, exergonic reactions are chemical reactions in which the change in free energy is negative (there is a net release of free energy).

This shows the spontaneous reaction when the system is closed and the initial and final temperatures are the same.

Reactions can be endergonic or exergonic. Endergonic reactions require heat or energy input. The exergonic reaction is the opposite. it gives off heat. Answer and Explanation:

Reactions with negative values of G are exergonic, meaning they release heat.

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The formula for the fluoride of e most likely to be EF4.

Define electron configuration.

The most common nomenclature for describing an atom's electronic configuration is its electron configuration. We allow each electron to occupy an orbital under the orbital approximation, which can be solved by a single wave function.

Since the valency of the element E is 4 and and the valency of flourine is 1, the compound of these two elements will have the formula EF4.

Therefore, the formula for the fluoride of e most likely to be EF4.

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The enthalpy of a system refers to the heat content of the system. In an endothermic reaction, the enthalpy of the system increases because heat is being absorbed from the surroundings. In an exothermic reaction, the enthalpy of the system decreases because heat is being released to the surroundings.

The temperature of the surroundings can also be affected by endothermic and exothermic reactions. In an endothermic reaction, the temperature of the surroundings decreases because heat is being absorbed by the system. In an exothermic reaction, the temperature of the surroundings increases because heat is being released by the system.

In summary, endothermic reactions absorb heat and have a positive enthalpy change, while exothermic reactions release heat and have a negative enthalpy change. The temperature of the system and the surroundings will change in opposite directions in endothermic and exothermic reactions.

The statement "Even though the full oxidation of glucose is exergonic, some of the reactions in glycolysis are endergonic" is a TRUE statement.

Glycolysis is the metabolic pathway of reactions that convert glucose into pyruvate (in the presence of oxygen) or lactate (in the absence of oxygen). There are ten sequences of reactions in it catalyzed by enzymes.

The overall reactions of glycolysis are exergonic, which means energy is released into its surroundings, However, some of the reactions within glycolysis absorb energy instead of releasing energy, making them endergonic reactions. One of them is the second reaction in glycolysis, where isomerase catalyzes the isomerization of G-6-P to F-6-P.

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• 2KOH(aqueous) + CaCl2(aqueous)—Ca(OH)2(aqueous) + 2KCl

• AgNO3(aqueous) + KCl(aqueous)—AgCl(precipitate) + KNO3(aqueous)

• NaCl and aqueous AgNO3 (aqueous) AgCl + NaNO3 in water;

Mg(OH)2 + 2HCl in water; MgCl2 (aqueous) + 2H2O(l)

How do you recognize a precipitation reaction in an equation?

Usually, only net ionic equations are used to describe precipitation reactions. A net ionic equation cannot be stated if all products are watery since all ions cancel each other out as spectator ions. As a result, there is no precipitation response.

An illustration of a precipitate equation

Precipitation reaction examples include adding 2 KI (aq.), 2 KNO3 (aq.), and PbI2 (s/ppt). Sodium chloride (NaCl) and insoluble barium sulfate are produced by the reaction of barium chloride (BaCl2) and sodium sulfate (Na2SO4) (BaSO4).

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The volume of 0.2500 m strontium hydroxide is required to completely react with 75.00 ml of 0.07942m hcl is 11.91 mL.

Calculation:-

Sr(OH)2 + 2 HCl => SrCl2 + 2 H2O

Moles of HCl = volume x concentration of HCl

= 75.00/1000 x 0.07942 = 0.0059565 mol

Moles of Sr(OH)2 = 1/2 x moles of HCl

= 1/2 x 0.0059565 = 0.00297825 mol

Volume of Sr(OH)2 = moles/concentration of Sr(OH)2

= 0.00297825/0.2500

= 0.01191 L = 11.91 mL

The health risks associated with radioactive strontium are very low at concentrations commonly found in the environment. Higher-than-normal levels of radioactive strontium lower blood cell concentrations and increase the risk of certain types of cancer. There is a possibility. Strontium is a soft silvery-yellow alkaline earth metal.

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A molar empirical mass of 60 g is present ( same as the given molar mass ). Consequently, the molecular formula is CN2OH4.

After dividing the actual yield produced in the lab by the predicted theoretical yield, multiply the result by 100 to determine the yield percentage.

Percent recovery is calculated as the difference between what you actually gathered and what you were expected to collect. Consider that after recrystallization, you obtained 7.0 g of dry pure material from 10.0 g of impure material. Your recovery rate is then 70% (7/10 x 100).

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100ml of 0.400 m AgNO3 and 90.0 ml of 0.250 m CaCl2 would combine to create 0.0225 moles of AgCl(s).

AgNO3 + CaCl2 -> AgCl + Ca(NO3)2 is the result of the given reaction

One mole of AgNO3 interacts with one mole of CaCl2 to produce one mole of AgCl in this reaction.

Given that AgNO3 (v1) has a volume of= 100 ml

Volume of CaCl2(v2) = 90ml

molarity of AgNO3 (m1) = 0.400M

Molarity of CaCl2 (m2) = 0.250M

Moles of AgNO3 formed: v1 x m1/1L = 0.1 x 0.4/1 = 0.04

moles of CaCl2 formed: v2 x m2/1L = 0.09 x 0.25/1L = 0.0225

Since AgNO3 exceeds 0.0225 moles of AgCl, CaCl2 is the limiting reactant in this limiting reactant problem.

Hence the number of moles of AgCl formed = 0.0225

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Starting with solid 3-sulfolene and decomposing was easier than starting with gaseous 1,3-butadiene.

3-Sulfolene is used to produce 1,3-butadiene by decomposition with maleic anhydride in solution. The solution should be heated slightly to decompose all the sulfolene to butadiene which reacts with the anhydride.

Diene is produced in a reaction vessel by heating butadiene sulfone until it decomposes into 1,3-butadiene and sulfur dioxide. The Diels-Alder reaction involves the replacement of four pi electrons from the diene and two pi electrons from the dienophile. This reaction is used to generate vitamin B6. The activation energies for these processes are reached only at high temperatures.

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These stars are so cool that nearly all of the hydrogen atoms are in the ground state that's why don't we see hydrogen Balmer lines in the spectra of stars with temperatures of 3,200 k.

The hydrogen emission spectrum includes the Balmer series as a subset. In the visible region of the electromagnetic spectrum, only these lines are present. The hydrogen Rydberg constant has a value of 109,677 cm. The section of the hydrogen emission spectrum known as the Balmer series is essentially where an electron is energised to go from the second shell to any other shell. Other transitions follow suit and have their own series titles. Here is a list of a few of them:

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