Please help quickly !!

Please Help Quickly !!

Answers

Answer 1

Since these are right triangles, we can use Pythagorean Theorem.

Pythagorean Theorem: a^2 + b^2 = c^2

50^2 + 20^2 = c^2

2500 + 400 = c^2

2900 = c^2

c = sqrt[ 100 * 29]

c = 10 sqrt[29]

In the boxes, a = 10, b = 29.

Hope this helps!! :)


Related Questions

Match each expression on the left with an equivalent expression on the right. ​

Answers

The expression on the left matched with an equivalent expression on the right are;

3x + 0 = 3x

5/3 - x + 1/3 = -3/2x + 2 + 1/2x

2x - 3 = x - 3 + x

2x - 6 = -6 + 2x

3/5 - 13/5 = -6.9 + 4.9

How to solve equivalent expression?

3x + 0 = 3x

5/3 - x + 1/3

combine like terms

= 5/3 + 1/3 - x

= (5+1)/3 - x

= 6/3 - x

= 2 - x

-3/2x + 2 + 1/2x

combine like terms

-3/2x + 1/2x + 2

= (-3+1)x / 2 + 2

= -2/2x + 2

= -x + 2

2x - 3 = x - 3 + x

2x - 6 = -6 + 2x

3/5 - 13/5

= (3-13)/5

= -10/5

= -2

-6.9 + 4.9

= -2

Ultimately, an expression is said to be equivalent when the value on the right hand side is equal to the value on the left hand side.

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Find Y

A: 14.3
B: -6.3
C: 7.0
D: 11.6

Answers

Answer:

D

Step-by-step explanation:

Using the sine ratio in the right triangle

sin51° = [tex]\frac{opposite}{hypotenuse}[/tex] = [tex]\frac{9}{y}[/tex] ( multiply both sides by y )

y × sin51° = 9 ( divide both sides by sin51° )

y = [tex]\frac{9}{sin51}[/tex] ≈ 11.6 ( to 1 dec. place ) → D

Hurry plz
In which quadrant is the point (-5, -4) in?
IV
I
III
II

Answers

(-5,-4) would be in quadrant III

Answer:

(-5,-4) quadrant is in III quadrant

what is the least number which is to be added or subtracted to 651201 to get a perfect square?

Answers

Answer:

Add 48 to get a perfect square

Explanation:

A perfect square would be of the number 651249 which means that you have to add 48 to get a perfect square.

Triangle LMN is similar to triangle OPQ. Find the measure of side QO. Round your answer to the nearest tenth if necessary.

Answers

Answer:

90.8

Step-by-step explanation:

20/13 = x/59

13x = 1180

x=90.76

x=90.8

What are the first 5 terms of the sequence Tn= 2n-3?

(Please answer quickly)​

Answers

Answer:

-1, 1, 3, 5, 7

Step-by-step explanation:

What is -5+56<1 please and thank you

Answers

False hope that was it that’s what I got

PLEASE HELP WITH STEPS SOLVE IN SCIENTIFIC NOTATION WILL GIVE BRAINLIEST

Answers

Answer:

use this <3 (helps calculate scientific notation) https://www.calculatorsoup.com/calculators/math/scientific-notation-converter.php

Step-by-step explanation:

At a high school the average grade for the first semester for all subjects was 79.3. Based on this mean , the principal concludes that half of the grades were 79.3. Higher is her conclusion justified? Why or why not?

Answers

Answer:

That is incorrect. It would be appropriate if the median were 79.3, since the median is the value in the middle (when placing the data in order).

Conclusion of principal about mean is not justified. Mean represents the average of the data. For such conclusion mode is the correct option.

What is mean?

" Mean is defined as the ratio of the sum of all the given numbers in the data to the total numbers of numbers in the data. It is also known as average of the data."

What is mode?

" Mode represents the value which occurs maximum numbers of times in the set of data."

According to the question,

Average grade for the first semester for all subjects = 79.3

Based on this mean

Principal concludes that half of the grades scored 79.3.

For example:

There are 5 students 3students score 100 , one student score 48 and another one got 50.

Mean of the class = [tex]\frac{398}{5}[/tex]

                                   = 79.6

Here no student score 79.6.

Principal conclusion is not justified.

Mean is not the correct option to justify maximum number of students marks it is represented by mode.

Hence, conclusion of principal about mean is not justified. Mean represents the average of the data. For such conclusion mode is the correct option.

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At George Washington High School, 119 students walk to school. If this number is 35% of school enrollment, then how many students are enrolled at the school ?

Answers

Answer: 340 students

Step-by-step explanation:

The number of students walking to school is 119 and this is 35% of the total number of students.

Assume the total number is denoted by "x".

That would mean that the following formula captures the situation:

119 = 35% * x

119 = 0.35x

x = 119/ 0.35

= 340 students

What is the value of 3'5/3'3

Answers

Answer:

1.05128205

Step-by-step explanation:

hope it helps

#carryonlearning

Use the Law of Sines to solve for the variable. Round your answer to the
nearest whole number. Write the value only. *

Answers

Answer:

y ≈ 61

Step-by-step explanation:

Using the Sine rule in the triangle

[tex]\frac{y}{sin117}[/tex] = [tex]\frac{21}{sin18}[/tex] ( cross- multiply )

y × sin18° = 21 × sin117° ( divide both sides by sin18° )

y = [tex]\frac{21sin117}{sin18}[/tex] ≈ 61 ( to the nearest whole number )

I need help please!!

Answers

Answer:

20

Step-by-step explanation:

6×2=12 + 8 = 20

so you answer for number 3 is twenty

The circle below is
centered at (2, 3) and has a radius of 4. What is its equation?

Answers

Answer:

Step-by-step explanation:

The standard form of a circle is

[tex](x-h)^2+(y-k)^2=r^2[/tex] where h and k are the center of the circle and r is the radius. Filling in:

[tex](x-2)^2+(y-3)^2=16[/tex]

If tanΘ = 6/5 and cosΘ < 0, what is sin2Θ?
An explanation on how to solve this problem would be great, thanks!!

Answers

Answer:

[tex]\displaystyle \sin2\theta=\frac{60}{61}[/tex]

Step-by-step explanation:

We are given that:

[tex]\displaystyle \tan\theta=\frac{6}{5}\text{ and } \cos\theta <0[/tex]

And we want to find the value of sin(2θ).

First, recall that tangent is the ratio of the opposite side to the adjacent side.

Therefore, the hypotenuse is:

[tex]h=\sqrt{6^2+5^2}=\sqrt{61}[/tex]

Next, note that tangent is positive and cosine is negative. Tangent is positive in QI and QIII. Cosine is negative in QII and QIII.

Hence, we can conclude that θ must be in QIII.

In QIII, sine is negative, cosine is negative, and tangent is positive.

And with respect to θ, our opposite side is 6, adjacent side is 5, and the hypotenuse is √(61).

We can rewrite our expression as:

[tex]\sin2\theta=2\sin\theta\cos\theta[/tex]

Using the above information, substitute:

[tex]\displaystyle =2\left(-\frac{6}{\sqrt{61}}\right)\left(-\frac{5}{\sqrt{61}}\right)[/tex]

Simplify. Hence:

[tex]\displaystyle \sin2\theta=\frac{60}{61}[/tex]

I need help with this question

Answers

Answer:

b

Step-by-step explanation:

Plz answerrrr due todayy

Answers

Answer:

Step-by-step explanation:

87 = x + 90

Isolate the variable by subtracting 90 on both sides

87 = x + 90

-90      -90

x=-3

-4x = 16

Isolate the variable by dividing by -4 on both sides

-4x=16

/-4   /-4

x = -4

43 = 6x - 5

On a coordinate plane, a parabola opens down. It has an x-intercept at (negative 5, 0), a vertex at (negative 1, 16), a y-intercept at (0, 15), and an x-intercept at (3, 0).
The function f(x) = –x2 − 2x + 15 is shown on the graph. What are the domain and range of the function?

The domain is all real numbers. The range is {y|y < 16}.
The domain is all real numbers. The range is {y|y ≤ 16}.
The domain is {x|–5 < x < 3}. The range is {y|y < 16}.
The domain is {x|–5 ≤ x ≤ 3}. The range is {y|y ≤ 16}

Answers

Answer:

the domain is xl-5<×< 3 is the range of 16

The domain is all real numbers. The range is {y|y ≤ 16}.

Domain of the function

The domain of a function is all the of values of the input or independent variable into the function

Since the x-intercepts of the function are at (-5, 0) and (3, 0), and also, the graph opens downwards, the values of x are in the interval (-∞ ≤ x ≤ -5) ∪ (-5 ≤ x ≤ 3) ∪ (3 ≤ x ≤ ∞). This is (-∞ ≤ x ≤ ∞).

So, the domain is the set of all real numbers.

The range of a function

The range of a function is all the output values of the function

Since the vertex of the parabola is at (-1, 16) and its y-intercept is at (0, 15), the maximum value of y is 16. So, the values of y are in the range y ≤ 16.

So, the range of the function is {y|y ≤ 16}

So, the domain is all real numbers. The range is {y|y ≤ 16}.

Learn more about domain and range of a function here:

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cos C(sec C - 1) = 1 - cos C

Answers

Answer:

Step-by-step explanation:

Cos(Sec - 1 ) = 1 - cosC

Cos and Sec are reciprocals which when multiplied together is 1

-1 * Cos = -Cos

SO: 1 - Cos = 1 - Cos

Hope this helps!

A computer downloads a 48 kilobyte file in 5 seconds. At this rate, how long will it take the computer to download a file that is 120 kilobytes?​

Answers

The answer is 12.5 seconds.

48/5 = 120/x
x = 2.5
2.5 * 5 = 12.5

Answer:

12,5

Step-by-step explanation:

First, you need to find how many kilobytes do you download every seconds.

You simply divide 48 kilobyte / 5 seconds and you get 9,6 kB/s.

Now you know that your download speed is this you can find the amount of time needed for downloading 120 kilobytes.

You simply divide [tex]\frac{120 kilobytes}{9,6 kilobytes/s} = 12.5 s[/tex].

12,5 seconds.

If using the method of completing the square to solve the quadratic equation x^2+5x+10=0x 2 +5x+10=0, which number would have to be added to "complete the square"?

Answers

Answer:

(5/2)² must be added to the equation to complete the square.

Step-by-step explanation:

The given equation is

x^2+5x+10=0

writing it in in square form

(x)² + 2(x) (5/2) + (5/2)²-(5/2)² + 10= 0

We multiply (5/2) to the mid term because we have to make 2x equal to 5x.

As the square formula tells that square of first element plus 2 into first element multiplied by second element plus square of second element.

Making 2x equal to 5x gives (5/2) as the second element.

Therefore add square of the second element but also subtract square of second element to make it equal to the given original equation.

Now we can solve it.

(x)² + 2(x) (5/2) + (5/2)²-(5/2)² + 10= 0

(x + 5/2)²-(5/2)² + 10= 0

(x + 5/2)²- 25/4+ 10= 0

(x + 5/2)²- 25*5 +10*5/4*5= 0

(x + 5/2)²-  125+50/20= 0

(x + 5/2)²-  175/20= 0

(x + 5/2)²=  175/20

Janelle draws line segments AB and BC in the same plane such that AB = 8 cm and BC = 6 cm. Then Janelle draws
line segment AC.
Use this information to determine the length, in centimeters, of AC for the following two situations.
• AB, BC, and AC form a triangle. Enter a possible value of AC in the first response box.
• Points A, B, and C lie on the same line, and C lies between A and B. Enter this value of AC in the second
response box.

Answers

Answer:

Step-by-step explanation:

• AB, BC, and AC form a triangle. Enter a possible value of AC....

So it asks for only a possible value of AC as there are many possible values.

Given AB = 8 cm and BC = 6 cm, they are in the ratio of 3:4.

Line segments of 3, 4 and 5 length will form a right-angled triange.

A possible value of AC = 5*2 = 10cm

• Points A, B, and C lie on the same line, and C lies between A and B.

So AC+CB = AB

AC+6 = 8

AC = 2cm

Enter this value of AC in the second

response box.

Answer:

Step-by-step explanation:

if ABC forms a triangle, AB=8 and BC=6

a possible value of AC=10cm

if ABC is a line segment n C is between A n B

AC + BC = AB

AC = 8 - 6 = 2cm

Find sin s, sin r , cos s , and cos r

Answers

Hi there! For this question, you need to know the ratio of sine and cosine.

sinA = opposite/hypotenusecosA = adjacent/hypotenuse

Define A = angle

opposite and adjacent side changes only if we focus on another angle.

From the picture, if we focus on angle S, the opposite would be 36. But if we focus on angle R (flip to make RT as base), see that the opposite would be 14.

Answer

sinS = 36/42 = 6/7sinR = 14/42 = 1/3cosS = 14/42 = 1/3cosR = 36/42 = 6/7

The bold one is simplest form while the non-bold is non-simplest.

Questions can be asked through comment.

Hope this helps, and Happy Learning ! :)

(6x2 -5x + 10) - (2x2 -x +13)

Answers

Answer:

[tex](6 {x}^{2} - 5x + 10) - 2 {x}^{2} - x + 13 \\ 6 {x}^{2} - 5x + 10 - 2 {x}^{2} + x - 13 \\ = 4 {x}^{2} - 4x - 3[/tex]

The water level in an ocean bay changes at an average rate of 3 meters per hour. At this rate, how many hours would it take for the water level to change 12 meters?

please help

Answers

Answer:

4 hours

Step-by-step explanation:

You divide 12 by 3 and the answer is 4.

hope this helped

(trigonometry) solve for x

Answers

Answer:

Step-by-step explanation:

take 23 degree as reference angle

using tan rule

tan 23=opposite/adjacent

0.42=25/x

x=25/0.42

x=59.52

x=60

Select the correct image. ​

Answers

Answer:

Triangle 2

Step-by-step explanation:

That is Pythagorean Theorem, which is only for right triangles. The second triangle has the little square, so you know it is 90 degrees.

In circle O, AE and DC are chords and intersect at B. If arc AC is 36 degrees and arc DE is 20 degrees, what is the measure of angle ABC? (Type in numbers only)

Answers

Answer: 28

You add 36 and 20 and divided it by 2

Here is a diagram and its corresponding equation. Find the solution to the equation.

4(+7)=38

Answers

Answer:

The solution to the equation is:

x = 2.5 or x = 5/2

Step-by-step explanation:

To find the solution to the equation, you only must operate the equation until you clear the x variable, with the next steps:

Equation: 4(x+7) = 38

And we solve:

4x + 28 = 38 (we multiply 4 by x and 7)4x = 38 - 28 (we pass the +28 to subtract to the right side of the equality and operate)x = 10 / 4 (we pass the 4 that is multiplying to divide to the right side of the equality)x = 2.5 (we divide)

As you can see, the solution of the equation is x = 2.5 or x = 5/2

Somebody plz help me solve!!

Answers

Answer:

C)  x = 3

Step-by-step explanation:

factor out a 2 to get:

2(x² - 6x + 9) = 0

(x-3)² = 0

x = 3

Answer and Step-by-step explanation:

First, to find the zeros of the function, we can take out a common factor from the equation, and then factor.

The equation has a common factor of 2 (so distribute of the 2 from all of the numbers).

2([tex]x^2 - 6x + 9[/tex])

Now, we factor. Find two numbers that multiplies to [tex]9x^2[/tex] and adds up to -6x.

-3x and -3x.

Now, we substitute these two for -6x.

[tex]2(x^2 - 3x-3x+9)[/tex]

Factor.

[tex]2(x - 3)(x-3)[/tex]

Finally, we set all of the values to 0 and solve for x.

2 ≠ 0

x - 3 = 0    x = 3

x - 3 = 0    x = 3

That means the answer is C. x = 3

(Not shown, but the multiplicity of this x value is 2, because there are two

x = 3)

#teamtrees #PAW (Plant And Water)

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