Answer:
x=20 degrees
I did what your teacher did down there; I added all the exterior angles and set them equal to 360°
Just combined the like terms and got the answer!
*3x + 4x + 3x = 10x
12 - 10 - 2 = 0
90 + 70 = 160
Put them "as an equation": 10x + 160 = 360
Get rid of what's surrounding the x, so subtract 160 from both sides.
10x = 200
To get rid of whats beside the x *again*, divided 10x by 10 on both sides.
x = 20
71.1g of sugar is needed to make 9 cakes. How much sugar is needed for 4 cakes?
Base on the given ratio of quantity of sugar to number of cakes, the quantity of sugar needed to bake 4 cakes is 31.6g of sugar
How much sugar is needed for cakes?Ratio refers to a number representing a comparison between two named things or quantities. The ratio of sugar and cake is the comparison between the quantity of sugar used to make cake.
If 71.1g of sugar is needed to make 9 cakesQuantity of sugar needed to make 4 cakes = xFind the ratio of quantity of sugar to number of cakes
Quantity of sugar : Number of cakes
71.1 g : 9 cakes = x : 4 cakes
71.1 / 9 = x / 4
cross product71.1 × 4 = 9 × x
284.4 = 9x
divide both sides by 9x = 284.4 / 9
x = 31.6g of sugar
In conclusion, the quantity of sugar needed to bake 4 cakes is 31.6g of sugar
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The speed of a car from point A to D is m/s however the velocity is 10 m/s due West. Calculate the speed of vehicle in m/s if it covers a distance of 1.5 km in 5 minutes.
Speed of car is 5 m/sec
What is speed?
In ordinary language and kinematics, an object's speed is defined as the magnitude of its position change over time or the magnitude of its position change per unit of time; it is therefore a scalar number. The distance traveled by an item in a time interval is divided by the duration of the period; the instantaneous speed is the limitation of the average speed as the length of time period tends to zero. Velocity is not the same as speed. Distance divided by time is the dimension of speed. The metre per second (m/s) is the SI unit of speed, while the kilometre per hour (km/h) is the usual unit.
The speed of the car = 1.5/5 km/min = 0.3 km/min
Speed in m/sec = 0.3x1000/60 = 5m/sec
Hence, speed of car = 5 m/sec
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Solve the x and y
1.5x-4.5y=9
Answer:
1.5x=9+4.5y
x= [tex]\frac{9+4.5y}{1.5}[/tex]
x = 6 + 3y
3y= x - 6
y = x/3-2
1. A grocery store sells salmon for $7.84 per pound. What would be the cost of 2 1/4
pounds of salmon?
Answer:
$17.64
Step-by-step explanation:
Multiply 7.84 by 2.25
7.84 x 2.25 = 17.64
Answer:
$17.64
Step-by-step explanation:
1 pound salmon = 7.84
2.25 (2 1/4) pound salmon = 17.64
solve the system of equations
If you know the names of the remaining students in the spelling bee, what is the probability of randomly selecting an order and getting the order that is used in the spelling bee?.
The probability of randomly selecting an order and getting the order that is used in the spelling bee is 0.001388888
Given we have the following:
Number of students in the spelling bee = 6
Number of ways selecting a student in the spelling bee = 6!
The probability of randomly selecting an order and getting the order that is used in the spelling bee :
P(selecting the correct spelling bee order) = 1/6!
= 1/6*5*4*3*2*1
= 1/720
= 0.001388888
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K
An investor has $75,000 to invest in a CD and a mutual fund. The CD yields 7% and the mutual fund yields 6%
The mutual fund requires a minimum investment of $9,000, and the investor requires that at least twice as much
should be invested in CDs as in the mutual fund. How much should be invested in CDs and how much in the
mutual fund to maximize the return? What is the maximum return?
DO
To maximize income, the investor should place $ in CDs and $
dollar as needed.)
The maximum return is $ (Round to the nearest dollar as needed.)
H
min
CH
point(s) possible
MA
√i Vi
P
in the mutual fund. (Round to the nearest
X
(,)
More
Next
x
25000 in mutual funds
50000 in CD
Pool of money managed by a professional Fund Manager is termed mutual fund. It is a trust that collects money from other investors who have a common investment objective and invests the same in equities and bonds.
Let X be the amount in Mutual Funds
Y be the amount in CDs
the constraints:
Y = 2x
x>9000
Y = 75000 - x
There has to be at least 2x + x = 75000
3x = 75000
x = 25000
Objective function for the return of investment is R(x,y) = 0.06X + 0.07Y
After graphing linear equations and inequalities, the vertices of the critical region are as:
(9000,18000) --> 1710
(25000,50000) ---> 4750
(75000,0) --> 3750
25000 in mutual funds
50000 in CD
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30 POINTS!
Select ALL the correct answers
Which figures show that ST || QR?
The figure that shows that ST || QR is the first figure
How to find the figure that show that ST is parallel to QR
For lines ST and QR to be parallel they have equal distance form the base of the triangle.
Taking the ratio of the distances from the apex we have
PS / SQ = PT /TR
The figure that has it's ratio equal is the figure that the lines ST and QR are parallel
Checking the first figure gives
= PS / SQ
= 7.5 / 17.5
= 0.428571
Also
= PT /TR
= 8.7 / 20.3
= 0.428571
since the ratio is equal the two lines are parallel in the
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Answer:I’m not sure what the second one is
Step-by-step explanation:
Writing to Explain Timothy is solving the problem 50+ 108x ÷ 4.
What order of operations should he follow?
Answer:
27x+50
Step-by-step explanation:
How to solve your problem
50 + 108x/4
Simplify
Cancel terms that are in both the numerator and denominator
50+ 108x/4
50+ 27x
Rearrange terms
50 + 27x
27x +50
=27x+50
Find y' if arctan (xy) = 4 + xy².
Answer:
y=2x
Step-by-step explanation:
hope this helps
:) :3
What do you add to
[tex]3 \frac{3}{8} [/tex]
to make 7?
Answer:
[tex]\frac{29}{8}[/tex]
Step-by-step explanation:
3[tex]\frac{3}{8}[/tex] equals to [tex]\frac{27}{8}[/tex], then we can write out the equation:
[tex]\frac{27}{8} + x = 7[/tex]
then subtract [tex]\frac{27}{8}[/tex]on both sides of the equal sign,
[tex]x = 7 - \frac{27}{8}[/tex]
and then we calculate x
[tex]x=\frac{56-27}{8}[/tex]
[tex]x=\frac{29}{8}[/tex]
Thus the answer is [tex]\frac{29}{8}[/tex]
Simplify: (8c3+c2d)−(9cd2−5d3)+(−3c2d−8cd2)
3862 × 874 pls write step by step
надеюсь что объяснила точно и нормально
CAN SOMEONE PLEASE HELP ME
Answer:
^2¤{{●○|<♤7◇○◇○◇7~♡6°<♤~{¡\ ~announced unbeknownst.fi
How can you write the expression using rational exponents?
5 square root n4
By using exponent properties, we can see that the equivalent expressions are:
[tex]5*\sqrt{n^4} = 5*n^2[/tex]
How to rewrite the expression?Here we need to use some rules for exponents and roots. Remember that:
[tex]\sqrt[n]{x} = x^{1/n}[/tex]
We also will use that:
[tex](a^n)^m = a^{n*m}[/tex]
Now we have the following expression:
[tex]5*\sqrt{n^4}[/tex]
Particularly, the square root is equivalent to an exponent of 1/2, then we can write:
[tex]5*\sqrt{n^4} = 5*(n^4)^{1/2}[/tex]
Using the second property we can rewrite:
[tex]5*(n^4)^{1/2} = 5*n^{4*1/2} = 5*n^2[/tex]
So the equivalent expressions are:
[tex]5*\sqrt{n^4} = 5*n^2[/tex]
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Which function is odd? Check all that apply.
A. y = sin x
B. y = csc x
C. y = tan x
D. y = cos x
The odd function is
y = sin x
y = cos x
A function f is deemed weird if f(-x) Equals -f for any value of x. (x). A function is said to be an even function if f(-x) = f for any value of x. (x).
What do odd functions entail?
The meaning of odd function
T function where the absolute value does not change if the independent variable's sign is reversed but the sign of the function itself does.
If f(-x) = -f for any number x, a function f is considered strange (x). When f(-x) = f for any number x, a function is referred to as an even function (x). Even while most functions are neither odd nor even, some of the most significant functions are.
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Answer:
A. y = sin x
B. y = csc x
C. y = tan x
Step-by-step explanation:
If g(x) and f(x) are inverse functions, which graph represents g(x)?
--6-5 1-3-2-1 1 2 3 4 5 6
Mark this and return
7 7 7 7 4
Save and Exit
Next
Submit
Answer:
A) 2nd graph
Explanation:
The 1st graph shows a radical expression, where:
to find the inverse, replace f(x) with y, switch the x and the y, then solve for y. The only graph showing exponential growth is the 2nd graph (note how at 1 it's 1, at 2 it's 4, at 3 it will be 9, etc.)
2) Mr. Jonas took out a loan of $12,400. The interest rate is 3% per year, and the
interest is not compounded. How much amount will Mr. Jonas have to repay
after 4 years?
The amount which Mr. Jonas will have to repay after 4 years is $13,888 when the interest rate is 3% per year on a loan of $12,400.
According to the question,
We have the following details:
The amount of the loan or the principal amount = $12,400
Interest rate = 3% per year
Time = 4 years
Now, it is given that the interest is not a compound interest. So, the total interest can be found using the formula of simple interest.
Simple Interest (S.I.) = (Principal*rate*time)/100
S.I. = (12400*3*4)/100
S.I. = (12400*12)/100
S.I. = 148800/100
S.I. = $1,488
Now, the total amount Mr. Jonas have to repay will be the sum of the loan he has taken out and the simple interest after 4 years.
Total amount = Principal + S.I.
Total amount = 12400+1488
Total amount = $13,888
Hence, the total amount of loan Mr. Jonas has to repay is $13,888.
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What is the value of x in the triangle?
Neil bought a house for £235 000
In the first year the value of the house depreciated by 4%
In each of years 2 and 3 the value of the house increased by 6%
Work out the value of the house at the end of year 3
Answer:
Based on the given conditions, formulate: 235000×(1+1-4%)
Calculate the sum or difference:235000×(2-0.04)
Calculate the sum or difference:235000×1.96
Calculate the product or quotient:460600
get the result:460600
So the answer is 460600
Answer:
£ 253,484.16
Step-by-step explanation:
Cost of house for first year = £235,000
Year 1
Depreciation for first year is 4% = 4/100
Depreciation in £ = 235,000 x 4/100 = £9,400
Effective value of house at end of first year
= 235000 - 9400 = £225,600
Year 2
In the second year the house value increased by 6% = 6/100
So total increase in £ at the end of year 2 with an initial value of £225,600 = £225,600 x 6/100 = £13,536
So actual value of house at end of year 2
= £225,600 + £13,536
= £239,136
Year 3
The value increased by 6% for year 3.
Value at beginning of year 3 = £239,136
Increase in value at 6% = £239,136 x 6/100 = £14,348.16
Total Value at end of year 3
= £239,136 + £14,348.16
= £253,484.16
Answer: £253,484.16
Note
Another way of quickly calculating this is noting that 4% depreciation means the new value is (1 - 4%) of initial value = 1 - 4/100 = 0.96
An increase of 6% means the new value will be 1.06 times the initial value
So the value of the house after 4% depreciation for the first year and 6% appreciation for the next 2 years
= 235000 x (0.96)(1.06)(1.06) = 253,484.16
Find the value of (-10)⁰
Answer:
1
Step-by-step explanation:
Anything to the power of 0 is 1 except for 0. If the base is o, the answer is undefined. It is will dividing by 0. That is also undefined.
Answer:
-10degree
Step-by-step explanation:
because the 0 is the degree
Which equation shows a line perpendicular to y = 3x + 2
a) y-1=1/3 (x-2)
b) y-1=3(x-2)
c) y-1=-1/3(x-2)
d) y-1=-3(x-2)
The straight line y-1=-1/3(x-2) is perpendicular to y = 3x + 2 .
The common form for two-variable linear equations is Ax + By = C which is also the general form of a straight line.
For instance, the linear equation 6x+5y=11 uses standard form. Finding an equation's two intercepts (x and y) is fairly straightforward with this procedure.
The cartesian equation for a straight line is Y = mx + c, where m stands for the gradient or slope of the line and c for the point at which it intersects the y-axis.
If two geometrical objects cross at a right angle, they are perpendicular.
We know that when two line are perpendicular the product of their respective slopes equal to -1.
Now in the given options let us find the slope of each line.
a) y-1=1/3 (x-2)
slope = 1/3
b) y-1=3(x-2)
slope = 3
c) y-1=-1/3(x-2)
slope = -1/3
d) y-1=-3(x-2)
slope = -3
Therefore the slope of the third equation is the negative reciprocal of the slope of the given line.
Hence y-1=-1/3(x-2) is perpendicular to y = 3x + 2 .
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At a garage sale, Liyah priced
her scooter for $15.50. She
ended up selling it for $10.75.
Find the percent of decrease
in the price of the scooter.
Round to the nearest tenth if
necessary
If she priced scooter for $15.50 and ended up selling it for $10.75, then the percentage of decrease in the price of the scooter is 30.64%
The initial price of the scooter = $15.50
The selling price of the scooter = $10.75
The amount decrease in the price of the scooter = Initial price of the scooter - The selling price of the scooter
= 15.50-10.75
= $4.75
The percent of decrease in the price of the scooter = (The amount decrease in the price of the scooter ÷ The initial price of the scooter)×100
= (4.75/15.50)×100
= 30.64%
Hence, if she priced scooter for $15.50 and ended up selling it for $10.75. then the percentage of decrease in the price of the scooter is 30.64%
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GCF(a, b)• LCM (a, b) = 77
What are the possible values of a and b?
The variables a and b have a possible value of 7 and 11
How to determine the possible values of a and b?The given parameters are
GCF(a, b)• LCM (a, b) = 77
As a general rule, the product of two numbers equals the product of the greatest common factor and the least common multiple of the numbers
This implies that
a * b = GCF(a, b)• LCM (a, b)
So, we have
a * b = 77
Express 77 as 7 * 11
a * b = 7 * 11
By comparison, we have
a = 7 and b = 11
Hence, the possible values are a = 7 and b = 11
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Brett earns a base salary of £78 per week plus a commission of 20% of sales. How much did Brett make last week if he managed to sell £85 worth of merchandise?
By taking the 20 percent of £85 and adding that to the base salary, we can see that last week Brett earned £95
How much did Brett make last week?Here we need to work with percentages. We know that Brett wins a commission of 20% of sales.
So, if he sells a total amount of A (A is in dollars). Then what he gets is:
0.2*A
Where 0.2 is the decimal form of 20%.
Here we know that Brett wins £78 as a base, and last week he sell a total of £85, then the amount he gets by the commission is:
0.2* £85 = £17
Adding that to the base he already earns each week, we get:
£78 + £17 = £95
In this way, we conclude that last week Brett earned £95
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what is the mean of 21,23,19,23,and 21
Answer:
21.4 (or 107/5)Step-by-step explanation:
what is the mean of 21,23,19,23,and 21?
Find the sum of the values by adding them all up. Divide the sum by the number of values in the data set.
(21+23+19+23+21) : 5 =
107 : 5 =
21.4 (or 107/5)
Pls help
Step by step
At a book fair, a tote bag costs $5 and books cost $3.50 each. you spend a total of $19.00 before taxes. how many books did you buy in addition to the tote bag?
Answer:
4 books
Step-by-step explanation:
Let b equal the number of books.
[tex]5 + 3.50b = 19[/tex]
[tex]3.50b = 14[/tex]
[tex]b = 4[/tex]
write an equation for there consevite integers whose sum id 306
The equation for three consecutive integers whose sum is 36 is n + (n+1) + (n+2) = 306.
What is an equation?A mathematical statement called an equation includes the sign "equal to" between two expressions with equal values.
What are consecutive numbers?Whole numbers that follow one another without a gap are known as consecutive integers.
Given the sum of three consecutive integers = 306
Let the integers be n, n+1, n+2
Then, n + (n+1) + (n+2) = 306
⇒3n + 3 = 306
⇒n = 303/3
⇒n = 101
Hence, n+1 = 102 and n+2 = 103
Therefore, the equation for three consecutive integers whose sum is 36 is n + (n+1) + (n+2) = 306.
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Select three names for the angle.
∠K , ∠1 and ∠JKL are the three names of the angle 1 indicated by red color in the figure given in the question.
We need to select three names of the angle 1 indicated by red color in the figure given in the question . We are provided with the following options ∠JLK , ∠K , ∠LJK , ∠1 , ∠JKL and ∠J .
∠JLK is not similar to ∠1 . ∠K and ∠1 are same angle. ∠LJK is not similar to ∠1 . ∠JKL and ∠1 are same angle. ∠J and ∠1 are different angles. So, we can finally conclude that the three names of the angle 1 indicated by red color in the figure given in the question are ∠K , ∠1 and ∠JKL .
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