Probably the two elements with properties most like beryllium are magnesium and aluminum.
According to the electronic configuration elements that will react similarly to beryllium are magnesium and calcium.
What is electronic configuration?Electronic configuration is defined as the distribution of electrons which are present in an atom or molecule in atomic or molecular orbitals.It describes how each electron moves independently in an orbital.
Knowledge of electronic configuration is necessary for understanding the structure of periodic table.It helps in understanding the chemical properties of elements.
Elements undergo chemical reactions in order to achieve stability. Main group elements obey the octet rule in their electronic configuration while the transition elements follow the 18 electron rule. Noble elements have valence shell complete in ground state and hence are said to be stable.
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Using your knowledge of symbols, determine which compound listed must contain both copper and oxygen.
1. malachite, Cu 2CO 3(OH) 2
2. calcite, CaCO 3
3. glucose, C 6H 12O 6
4. chalcopyrite, CuFeS 2
Answer:
The correct option is Malachite which has both copper nd oxygen.
Explanation:
As we the symbol of copper is Cu while the symbols of oxygen is O. As the chemical formula of malachite is Cu₂CO₃(OH)₂. So it has Cu as well as O.
Glucose has only oxygen but no copper
Chalcopyrite has copper but no oxygen
Calcite has oxygen but no copper.
So correct answer is only malachite.
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Calculate the mass in grams of carbon dioxide produced from 11.2 g of octane (C8H18) in the reaction above.
18 + 25 O2 --> 16 CO2 + 18 H2O
89.6 g
17.3 g
34.5 g
46.2 g
Answer:
34.6g
Explanation:
Given parameters:
Mass of Octane = 11.2g
Reaction expression;
2C₈H₁₈ + 25O₂ → 16CO₂ + 18H₂O
Mass of octane = 11.2g
Unknown:
Mass of carbon dioxide produced = ?
Solution:
From the balanced reaction equation;
2 mole of octane produced 16 moles of carbon dioxide
From the given specie, let us find the number of moles;
Number of moles = [tex]\frac{mass}{molar mass}[/tex]
Molar mass of C₈H₁₈ = 8(12) + 18(1) = 114g/mole
Number of moles of octane = [tex]\frac{11.2}{114}[/tex] = 0.098mole
2 mole of octane produced 16 moles of carbon dioxide
0.098 mole of octane will produce [tex]\frac{0.098 x 16}{2}[/tex] = 0.79mole of CO₂
Mass of CO₂ = number of moles x molar mass
Molar mass of CO₂ = 12 + 2(16) = 44g/mol
Mass of CO₂ = 0.79 x 44 = 34.6g