Please help me with the question please ASAP

Answer:

25 grams of protein

Step-by-step explanation:

10 grams of protein is in 1 cup of milk.

To understand how many grams of protein are in 0.5 cups of milk, I would need to divide 10 by 2, to get 5.

There are 5 grams of protein in 0.5 cups of milk.

Now if I want to see how many grams of protein are in 2 cups of milk, I would multiply 10 by 2, to get 20.

There are 20 grams of protein in 2 cups of milk.

But, the question is asking for how much protein is in 2.5 cups of milk.

Since we know how much is in 2 cups, and 0.5, we can just add them together, because 2+0.5 is 2.5.

20+5 is 25 grams.

There are 25 grams of protein in 2.5 cups of milk.

Answer:

1/11

Step-by-step explanation:

(6, 4) and (-5, 3)

Slope:

m=(y2-y1)/(x2-x1)

m=(3-4)/(-5-6)

m= (-1)/(-11)

m = 1/11

Answer:

Minimum: (2,4)

Step-by-step explanation:

h(x)=3([tex]x^{2}[/tex]-4x)+16

=3([tex]x^{2}[/tex]-4x+4-4)+16   (- For the balance of equation, and attention 1)

=3[tex](x-2)^{2}[/tex]-3*4+16

=3[tex](x-2)^{2}[/tex]+4

1. [tex](a-b)^{2}=a^{2} -2ab+b^{2}[/tex]

2. The formula for the vertex form is y = [tex]a(x-h)^{2}+k[/tex], the vertex is (h,k)

Answer:

5 o clock

Step-by-step explanation:

The solution to the given integral is: frac{pi}{4}g(x) + frac{1}{2}cdot frac{Gamma(frac{3}{2})Gamma(frac{1}{2})}{Gamma(2)} cdot g(x).

Given integral: int_0^1 (1-t^2)g(x) dt

To solve the given integral, we will make use of Beta function.

The Beta function is defined as follows:

B(p,q) = int_0^1 t^{p-1}(1-t)^{q-1} dt

Using substitution, t = sin theta, we get:

int_0^1 (1-t^2)g(x) dt = int_0^{frac{pi}{2}} (1-sin^2 theta)g(x) cos theta dtheta

= int_0^{frac{\pi}{2}} cos^2 theta g(x) d\theta

= frac{1}{2}\int_0^{\frac{\pi}{2}} (1+\cos 2\theta) g(x) d\theta

= frac{1}{2} \left(\int_0^{\frac{\pi}{2}} g(x) dtheta + int_0^{frac{pi}{2}} g(x) cos 2theta dtheta right)

Using B(p,q)$ for the second integral, we get:

int_0^1 (1-t^2)g(x) dt = frac{1}{2}left(frac{pi}{2}g(x) + frac{1}{2}cdot frac{Gamma(frac{3}{2})Gamma(frac{1}{2})}{Gamma(2)} cdot g(x) right)

= frac{pi}{4}g(x) + frac{1}{2}cdot frac{Gamma(frac{3}{2})Gamma(frac{1}{2})}{Gamma(2)} cdot g(x).

Hence, the value of the given integral int_0^1 (1-t^2)g(x) dt is frac{pi}{4}g(x) + frac{1}{2}cdot frac{Gamma(frac{3}{2})Gamma(frac{1}{2})}{Gamma(2)} cdot g(x).

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Answer:

Step-by-step explanation:

[tex]9x6x12[/tex]= 648 the length(12m), width(6m), and height(9m) that all i can give you for now because this got me losing brain sells

Answer:

for the first question the answer is 3

for the second question the answer is 9

Step-by-step explanation:

12/4=3, 6/2=3, 9/3=3

8+8+12+12+6+6 = 52 & 108 + 108 + 72 + 72 + 54 + 54= 468

468 / 52 = 9

The equations Verdita could use to represent the data sets include the following:

A. Data Set A: y = 4x-2

Data Set B: y = x +4

In Mathematics and Geometry, the point-slope form of a straight line can be calculated by using the following mathematical equation (formula):

y - y₁ = m(x - x₁)

Where:

First of all, we would determine the slope of data set A;

Slope (m) = (y₂ - y₁)/(x₂ - x₁)

Slope (m) = (2 + 6)/(1 + 1)

Slope (m) = 8/2

Slope (m) = 4

At data point (1, 2) and a slope of 4, a linear equation for data set A can be calculated by using the point-slope form as follows:

y - y₁ = m(x - x₁)

y - 2 = 4(x - 1)

y = 4x - 2

At data point (0, 4) and a slope of 1, a linear equation for data set B can be calculated by using the point-slope form as follows:

y - y₁ = m(x - x₁)

y - 4 = 1(x - 0)

y = x + 4

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Missing information:

The question is incomplete and the complete question is shown in the attached picture.

Answer:

4 hours and 10 min

Step-by-step explanation:

For this equation we will do ratios:

[tex]\frac{18}{30} =\frac{150}{x} \\\\18x=4500\\x=250[/tex]

250 min =

4 hours and 10 min

4(60) = 240

240 + 10 = 250 minutes

The Romberg integration method is used to approximate definite integrals. Given the values R21 = 6 and R22 = 6.28, we can determine the value of R11.

To find R11, we can use the formula:

R11 = (4^1 * R21 - R22) / (4^1 - 1)

Substituting the given values, we have:

R11 = (4 * 6 - 6.28) / (4 - 1)

    = (24 - 6.28) / 3

    = 17.72 / 3

    ≈ 5.9067

Therefore, the approximate value of R11 is approximately 5.9067.

Romberg integration is an extrapolation technique that refines the accuracy of numerical integration by successively increasing the order of the underlying Newton-Cotes method. The notation Rnm represents the Romberg approximation with m intervals and n steps. The general formula for calculating Rnm is:

Rnm = (4^n * Rn-1,m-1 - Rn-1,m) / (4^n - 1)

In this case, R21 represents the Romberg approximation with 2 intervals and 1 step, while R22 represents the approximation with 2 intervals and 2 steps. By substituting these values into the formula, we can calculate R11. The numerator is obtained by multiplying R21 by 4 and subtracting R22. The denominator is calculated by subtracting 1 from 4^n. Evaluating this expression yields the approximate value of R11 as 5.9067.

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Answer:

The top graph.

Step by step:

Before the tickets go on sale, 120 tickets were already sold.

After that, the tickets sell at a constant rate for a total of 8 hours.

At the end of this time, all the tickets were sold (we have 0 tickets left)

If x (horizontal axis) represents the hours since tickets go on sale, and y (vertical axis) represents the number of raffle tickets sold.

Then, at x = 0, we should already see y = 120

Because we start with 120 tickets sold.

Then, as x increases, the number of tickets sold also should increase, until we get x = 8 hours, where y stops increasing because all tickets are already sold.

Then we should have an increasing line that stops increasing at x = 8 hours.

Then the correct option is the above graph, where we have:

An increasing line.

y = 120 in the vertical axis (y = 120 when x = 0)

Answer:

40.95

Step-by-step explanation:

P = 1500 + 75 = 1575

I = Prt

I = 1575(1.3%)(2)

I = 40.95

The range of the function f is (0, [infinity]). The correct option is d.

The range of the function f : [0, [infinity]) → R, defined by the rule f(t) = e^(-2x), can be determined by analyzing the behavior of the exponential function.

As x approaches infinity, e^(-2x) approaches 0, but it never reaches 0. This means that the function f(t) will approach 0 as t approaches infinity, but it will never actually reach 0.

On the other hand, as x approaches negative infinity, e^(-2x) approaches positive infinity. Therefore, the function f(t) will approach positive infinity as t approaches 0.

Based on this analysis, we can conclude that the range of the function f is (0, [infinity]), which means option (d) is the correct answer.

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In this study, there are a total of 40 subjects. The researcher samples 20 healthy people and 20 people with pre-existing conditions. Out of these, 10 healthy people and 10 people with pre-existing conditions are given a flu shot, while the other 10 from each group are not given flu shots.

To calculate the total number of subjects (N), we add the number of healthy people to the number of people with pre-existing conditions:

N = Number of healthy people + Number of people with pre-existing conditions

N = 20 + 20

N = 40

Therefore, the total number of subjects in the study is 40.

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The correct option is (a). The other options are incorrect because the given series satisfies all the conditions of the alternating series test, and thus, the test is applicable.

The given series is as follows: n+1
(-1)
(n +1)
7t
ns1

An alternating series test is a significant tool for determining whether or not a given series converges. A series is said to be convergent if the sequence of partial sums converges to a finite limit, and divergent otherwise. For the alternating series test to apply to a series, there must be the following three conditions: The series must have alternating terms, meaning that every other term is negative. The sequence of absolute values of the terms of the series must be monotonically decreasing, meaning that the absolute values of each successive term must be smaller than the preceding term's absolute value. The sequence of absolute values must approach zero in the limit. Thus, it can be observed that for the given series, the first two conditions are met. Now, to check the third condition, we must calculate the limit of the terms.

Let us take an=1/(n+1)7tnSince lim an=0, the series passes the third test as well.

Thus, we can apply the alternating series test to the given series. By the alternating series test, we have that the series converges. Thus, the correct option is (a). The other options are incorrect because the given series satisfies all the conditions of the alternating series test, and thus, the test is applicable. Thus, we can safely conclude that option (a) is correct.

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Answer:

138.23

Step-by-step explanation:

Let L be the linear operator in R2 defined by L(x) = (3x1 - 2x2, 9x1 - 6x2)T. The bases of the kernel and image of L are to be determined. To find the bases of the kernel and image of L, we first recall the definitions of kernel and image of a linear operator. Definition of Kernel: Let T be a linear operator on a vector space V. Then the kernel of T, denoted as ke T, is the subspace of V that consists of all vectors that are mapped to the zero vector of the range of T. Definition of Image: Let T be a linear operator on a vector space V. Then the image of T, denoted as im T, is the subspace of the range of T consisting of all vectors that are mapped by T to some vectors in the range of T. The kernel and image of L are given as follows. Kernel of L: For L(x) = (3x1 - 2x2, 9x1 - 6x2)T to be zero vector, we must have 3x1 - 2x2 = 0 and 9x1 - 6x2 = 0, which implies that x1 = (2/3)x2.

Therefore, a typical element of the kernel of L can be expressed as (x1, x2)T = (2/3)x2(1, 3)T, where x2 is a scalar. Hence, a basis for the kernel of L is {(1, 3)T}. Image of L: The image of L is the subspace of R2 consisting of all vectors that can be expressed in the form L(x) = (3x1 - 2x2, 9x1 - 6x2)T, where x is any vector in R2. It follows that any vector in the image of L is of the form (3x1 - 2x2, 9x1 - 6x2)T = x1(3, 9)T + x2(-2, -6)T. Therefore, a basis for the image of L is {(3, 9)T, (-2, -6)T}.Hence, the bases of the kernel and image of L are as follows. Kernel: {(1, 3)T}Image: {(3, 9)T, (-2, -6)T}.

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Answer:

120

equation: 40+8(10)=120

Step-by-step explanation:

The math for this is $40 initial plus $8x the 10 weeks which equals 80 so

40+80=120

Answer:

yes cs its a orange juice

Step-by-step explanation:

Answer:

taking back the answer spot that is rightfully mine!

Step-by-step explanation:

Answer:

3

Step-by-step explanation:

[tex]18*\frac{1}{6} \\\\3[/tex]

Answer:

=3x

Step-by-step explanation:

18x^1 / 6

=3x

Answer:

hope this helps :)

Step-by-step explanation:

Answer:

24

Step-by-step explanation:

added all the sides hope this helps

Answer: x=6

Step-by-step explanation: Hope this help :D

Answer:

2305.33π square inches

Step-by-step explanation:

The volume of a sphere is V = (4/3) πr ^ 3

Because the diameter is 24, the radius is 12.

Substituting 12 for r in the above equation:

V = (4/3) π (12 ^ 3) = (4/3) (1728) π = 2305.33π square inches, or 7238.23 square inches.

Answer:

Measure the length, width and height of the square or rectangle prism or object in inches. Record each of these on paper. Multiply the three measurements together to find the volume using either paper and pencil or a calculator. This is the equation: Volume = length x width x height.

I think that is:

24/2 = 12² = 144 x 3.14 = 452.16.

¯\_(ツ)_/¯

Answer:

21?i think

Step-by-step explanation:

Answer to question 1 is D

answer to question 2 is A

The integral ∫ 1/ (z-a)(z-b) dz over the circle Cr, where a and b are complex numbers and |a| < R < |b|, evaluates to 2πi/(a-b).

To show this, we can use the Residue theorem. Since the function 1/(z-a)(z-b) has two simple poles at z=a and z=b within the region enclosed by the circle Cr, we can evaluate the integral by summing the residues at these poles.

The residue at z=a is given by Res(a) = 1/(b-a), and the residue at z=b is given by Res(b) = -1/(b-a). By the Residue theorem, the integral is equal to 2πi times the sum of the residues.

Therefore, ∫ 1/ (z-a)(z-b) dz = 2πi * (1/(b-a) - 1/(b-a)) = 2πi/(a-b).

This result shows that the integral over the circle Cr simplifies to a complex constant determined by the difference between a and b.

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