Please help me with question 6!!The neutralization of a weak base and a strong acid should product a solution that is:a. basicb. neutralc. all of aboved. acidic

From the mole ratio and the masses of reactants:

The maximum amount of the product that can be formed is calculated from the equation of reaction as follows:

The mole ratio of hydrogen to nitrogen is 3 : 1

From the given data:

4.67 grams of hydrogen gas are allowed to react with 4.67 grams of nitrogen.

The moles of the reactants is determined as follows:

Moles of hydrogen = 4.65/2 = 2.325 moles

Moles of nitrogen = 4.67/28 = 0.1667 moles

Hence, the limiting reagent is nitrogen while the excess reagent is hydrogen.

The maximum moles of ammonia (NH₃ ) that can be formed = 0.1667 moles.

mass of ammonia formed = 0.1667 * 17 grams

mass of ammonia formed = 2.83 g

The moles of the excess reagent remaining after the reaction is complete = 2.325 - (0.1667 * 3) = 1.825

moles of the excess reagent remaining = 1.835 moles

mass of the excess reagent remaining = 1.825 * 2

mass of the excess reagent remaining = 3.65 grams

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Br2 represents both an element and a molecule.

A molecule is defined as a group of atoms bonded together. An element is defined as a substance that cannot be chemically broken down further into simpler substances. Br2 is only bromine and it is two bromine atoms boned together to form a molecule.

The electronic configuration of Lithium is 1s²2s¹.

The configuration notation allows scientists to clearly describe and record how electrons are positioned around an atom's nucleus. As a result, it is simpler to comprehend and anticipate how atoms will interact to create chemical bonds.

Lithium is the third element with a total of three electrons. We shall describe the lithium electron configuration with the first two electrons in the 1s orbital. Li's third electron is in the 2s orbital since there can only be two electrons in the 1s orbital. Therefore, Li's electron configuration will be 1s22s1.

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Answer:

valence electrons

Explanation:

they are the electrons that are in the outermost shell

Answer:

D.) mole, 6.022 x 10²³

Explanation:

Avogadro's Number is a ratio which states that there are 6.022 x 10²³ particles per every one mole.

The density of the unknown liquid 1.88kg/m³

The density of a liquid is a measure of how heavy it is for the amount measured and if you weigh equal amounts or volumes of two different liquids, the liquid that weighs more is more dense and if a liquid that is less dense than water is gently added to the surface of the water, it will float on the water

Here given data is cylinder weighs 26.145 g and when the cylinder contains 48.3 of an unknown liquid and it weighs 65.055 g then we have to find density of the unknown liquid = ?

So density = mass/volume

cylinder weighs + liquid weighs = 91.2g

Density = 91.2g/48.3

Density = 1.88kg/m³

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ANSWER

T

EXPLANATION

Given that;

The mass of the object is 9.6 grams

The volume of the object is 3.2mL

Follow the steps below to find the density of the object

Substitute the given data into the formula above

Convert the volume of the object to cm^3

Recall, that 1mL is equivalent to 1cm^3

Hence, 3.2mL is 3.2 cm^3

Therefore, the density of the object is 3.00 g/mL

The number of moles of silver present in a silver spoon that has a mass of 12.86g is 0.12 moles.

The number of moles of a substance can be calculated by dividing the mass of the substance by its molar mass as follows:

The mass of a substance is the quantity of matter which a body contains, irrespective of its bulk or volume.

The mole of a substance is the amount of substance of a system which contains exactly 6.02214076 × 10²³ elementary entities e.g. atoms, molecules.

moles = mass ÷ molar mass

According to this question, silver spoon has a mass of 12.86g. The number of moles can be calculated as follows:

Molar mass of silver (Ag): 107.8682g/mol

moles = 12.86g ÷ 107.8682g/mol

moles = 0.12 moles

Therefore, 0.12 moles of silver are present in the silver spoon.

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The empirical formula of the compound is CH₂O.

The empirical formula of a compound is the simplest formula of a compound showing the elements in the compound combined in their simplest mole ratios.

The empirical formula is determined from the simplest whole number mole ratio in which the elements in the compound combine.

The empirical formula of the compound is calculated below as follows:

mole of carbon = 0.250

mole of hydrogen = 0.50

moles of oxygen = 0.250

Diving by the smallest ratio to convert to whole number ratios

mole ratio of carbon to hydrogen to oxygen will be:

C = 0.25 / 0.25 = 1

H = 0.50 / 0.25 = 2

O = 0.25 / 0.25 = 1

Empirical formula = CH₂O

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The enthalpy of the reaction when 0.384 g of sodium metal is added to an excess of hydrochloric acid and 3990 J of heat is produced is 266 KJ.

The balanced chemical equation of reaction is -

2 Na(s) + 2 HCl(aq)  ⟶  2 NaCl(aq) + H₂(g)

We know that,

weight of sodium metal is 0.384 g

Molar mass of Na is 23 g/mol

we will calculate the number of moles,

Number of moles = Given mass

                                 Molar mass

Moles of Na =  0.348 g   = 0.015 mol

                        23 g/mol

We will calculate the energy in 1 mole of sodium metal

In 0.015 moles of sodium metal, 3990 J of energy is produced.

so, in 1 mole of sodium metal, 3990 J of energy is produced

                                                  0.015

In 1 mole, 266000 J of energy is produced.

1 J = 0.001 KJ

266000 J = 266 KJ

The enthalpy of the reaction will be 266 KJ.

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According to the given data The enthalpy for the reaction, ΔH rxn is 255.95 kJ/mol.

Enthalpy is a characteristic or state function which resembles energy; it has the same dimensions as energy and is thus measured in joules or ergs. The value of enthalpy is entirely determined by the temperature, pressure, and content of the system, not on the history.

Calculate the change in enthalpy for the reaction

CH₄(g) + NH₃(g) → HCN(g) +3H₂(g)

From the given reactions

Reaction 1: N₂(g) + 3H₂(g) → 2NH₃(g) Change in enthalpy: -91.8 kJ/mol

Reaction 2: C(s, graphite) + 2H₂(g) → CH₄(g) Change in enthalpy: -74.9 kJ/mol

Reaction 3: H₂(g) +2C(s, graphite) +N₂(g) → 2HCN (g) Change in enthalpy: +270.3 kJ/mol

Reactions 1 and 2 to get reaction 4 and 5 respectively

Reaction 4: 2NH₃(g)  → N₂(g) + 3H₂(g)                 ΔHo : 91.8 kJ/mol

Reaction 5: CH₄(g) → C(s, graphite) + 2H₂(g)       ΔHo : 74.9 kJ/mol

Now, multiply reactions 4 and 3 by half (1/2) to get 6 and 7 respectively

Reaction 6: NH₃(g)  → ¹/₂N₂(g) + ³/₂H₂(g)                           ΔHo : 45.9 kJ/mol

Reaction 7: ¹/₂H₂(g) +C(s, graphite) +¹/₂N₂(g) → HCN (g)   ΔHo : +135.15 kJ/mol

Now,

Add reactions 5, 6, and 7 together  

Reaction 5: CH₄(g) → C(s, graphite) + 2H₂(g)                    ΔHo : 74.9 kJ/mol

Reaction 6: NH₃(g)  → ¹/₂N₂(g) + ³/₂H₂(g)                           ΔHo : 45.9 kJ/mol

Reaction 7: ¹/₂H₂(g) +C(s, graphite) +¹/₂N₂(g) → HCN(g)    ΔHo : +135.15 kJ/mol

----------------------------------------------------------------------------------------------------------

CH₄(g) + NH₃(g) → HCN(g) + 3H₂(g)                             ΔH rxn = 255.95 kJ/mol

The enthalpy for the reaction, ΔH rxn is 255.95 kJ/mol

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The transformation of inputs into outputs is referred to as the production process.

A production process is a way to use economic resources, such as labor, expensive machinery, or land, to create goods and services for customers.

The transformation of inputs into outputs is referred to as the production process. The primary categories include mass, batch, job, just-in-time, and flexible manufacturing systems.

A production process is a method of delivering goods and services to clients while utilizing resources or economic inputs like labor, expensive machinery, or land.

Therefore, the correct answer is option A. analyze existing resources, such as water availability

The complete question is:

Society decides that it needs to produce more corn to feed the growing population. What must it do before it begins the production process?

A. analyze existing resources, such as water availability

B. determine how people will receive the surplus crops

C. study the profitability of increasing corn production

D. understand who is in a position of authority to produce more

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Balanced  equation of C3H8O3 + O2 = CO2 + H2O is 2C3H8O3 + 7O2 → 6CO2 + 8H2O

Balance the equation C3H8O3 + O2 = CO2 + H2O using the algebraic method.

            aC3H8O3 + bO2 = cCO2 + dH2O

         C: 3a + 0b = 1c + 0d

         H: 8a + 0b = 0c + 2d

         O: 3a + 2b = 2c + 1d

       3a - 1c = 0

       8a - 2d = 0

       3a + 2b - 2c - 1d = 0

      a = 2 (C3H8O3)

      b = 7 (O2)

      c = 6 (CO2)

      d = 8 (H2O)

               2C3H8O3 + 7O2 = 6CO2 + 8H2O

                   Reactants       Products

              C    6                   6

              H   16                16

              O   20                 20

Since there is an equal number of each element in the reactants and products of 2C3H8O3 + 7O2 = 6CO2 + 8H2O, the equation is balanced.

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Answer: Carbon strengthens iron by distorting its crystal lattice. This distortion is similar in effect to work hardening.

Taking into account the reaction stoichiometry, 45.35 grams of copper(II) chloride are needed to produce 42.8 g copper(II) phosphate in the presence of excess sodium phosphate.

In first place, the balanced reaction is:

3 CuCl₂ + 2 Na₃PO₄ → Cu₃(PO₄)₂ + 6 NaCl

By reaction stoichiometry (that is, the relationship between the amount of reagents and products in a chemical reaction), the following amounts of moles of each compound participate in the reaction:

The molar mass of the compounds is:

Then, by reaction stoichiometry, the following mass quantities of each compound participate in the reaction:

The following rule of three can be applied: if by reaction stoichiometry 380.62 grams of Cu₃(PO₄)₂ are produced by 403.32 grams of CuCl₂, 42.8 grams of Cu₃(PO₄)₂ are produced by how much mass of CuCl₂?

mass of CuCl₂= (42.8 grams of Cu₃(PO₄)₂× 403.32 grams of CuCl₂) ÷380.62 grams of Cu₃(PO₄)₂

mass of CuCl₂= 45.35 grams

Finally, 45.35 grams of CuCl₂ is required to produce 42.8 g copper(II) phosphate.

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Explanation:

The law of conservation of mass:

In a chemical reaction, the mass is neither created nor destroyed. In other words, the mass of any one element at the beginning of a reaction will equal the mass of that element at the end of the reaction.

------------------

According to this task, the statement that demonstrates the law of conservation of mass is:

Answer: there are 10 aluminum (Al) atoms represented on each side of the equation.

Answer:

12.1 grams and 77.8%

Explanation:

(Note: in this answer, sig figs are rounded in the end, not along the way) The molar ratio of calcium sulfate to calcium hydroxide is 1:1
there are 6.56 grams of calcium hydroxide, so the number of moles is the number of grams / the molar mass, which is (6.56 grams) / (74.093 g/mole)
=0.08854 moles of calcium hydroxide
Theoretically, 0.08854 moles of calcium hydroxide would make 0.08854 moles of calcium sulfate.
To find the number of grams of calcium sulfate, multiply the number of moles by the molar mass, which is .08854 * 136.14 = 12.054 grams, or
12.05 grams
The percentage yield of calcium sulfate is just the actual yield / predicted yield, which is 9.37/12.05 which is 0.7776, or 77.8%

If 10.5 g of Ag and 7.5 g of S are reacted and 9.8 g of  [tex]Ag_2S[/tex] is obtained, the percent yield of the reaction would be 81.4%

Ag and S react to form [tex]Ag_2S[/tex] as follows:

[tex]2Ag + S -- > Ag_2S[/tex]

The mole ratio of Ag to S is 2:1.

10.5 g of Ag = 10.5/108

                     = 0.0972 moles

7.5 g of S = 7.5/32

                = 0.2344 moles

In other words, Ag is limiting in availability.

The mole ratio of Ag to  [tex]Ag_2S[/tex] = 2:1

0.0972 Ag is equivalent to 0.0972/2 = 0.0486 moles of  [tex]Ag_2S[/tex]

0.0486 moles  [tex]Ag_2S[/tex] weighs = 0.0486 x 247.8

                                              = 12.04 grams

percent yield of  [tex]Ag_2S[/tex] = 9.8/12.04 x 100%

                                   = 81.4%

The percent yield of [tex]Ag_2S[/tex] that the chemist actually obtained is 81.4%.

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Step 1 -

A decomposition reaction is a reaction in which a compound is decomposed, i.e., we usually heat a substance thus forming new substances, such as gaseous substances.

Generally speaking, a decomposition reaction will involve only one reactant: the substance to be decomposed.

Step 2 - Examples of decomposition reactions

Let's take a closer look at some examples:

We can already state some conclusions:

a) The products are not always the same. They depend on the reactant. Therefore, they are not always predictable.

b) The reactant can be an ionic compound (such as ZnCO3) but also a covalent compound (such as H2CO3).

c) The reactant does not decompose into its constituent elements.

Step 3 - Finding the wrong answer

Therefore, the only wrong answer is item b), the products are the constituent elements.

Answer:

C is the answer

Explanation:

Li2CO3 + HCl - - - - - - -> LiCl + H2O + CO2

Li. Li. H. Li. H. H. C

C Cl. Cl. O. O. O

O. O. O

2 Li ------>1Li so we put 2 in front LiCl on the right side to make 2Li---->2Li.

1H------->2H so we put 2 in front HCl on left side to make

Li2CO3 + 2HCl - - - - - - -> 2LiCl + H2O + CO2

The percent yield of the reaction is calculated as follows:

Percent yield = actual yield/ theoretical yield * 100 %

The percent yield of the reaction is less than 100%.

The percent yield of a reaction is the ratio of the actual yield of a reaction and the theoretical yield of the reaction.

Mathematically:

The percent yield of any reaction is never 100& percent because no reaction actually goes to completion forming exactly all the product that is expected.

Considering the give reaction of the formation of nitric acid in the atmosphere:

The equation of the reaction is:

4 NO (g) + 3 O₂ (g) + 2 H₂0 (g) ---> 4 HNO₃ + excess oxygen.

The percent yield will require the actual yield and the theoretical yield in order to be calculated.

For example, if the actual yield is 12 g and the theoretical yield is 15 g, percent yield = 12/15 * 100%

Percent yield = 80%

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The most complete list of the parts of the experiment presented in this scenario include:

This refers to the procedures which are performed in other to support or refute a hypothesis. It is also used to ascertain the authenticity of the claim by other people such as scientists etc who review it.

In the scenario given, we were told that the group of identical mice is given the supplement and the other group is not given any thing which means that the control group is the one which wasn't given anything while the ones who were given something is the experimental group.

The dependent variable is the supplement which was given to the mice and is therefore the reason why option B was chosen as the correct choice.

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An oxidation number is a number assigned to an atom that allows chemists to keep track of how many electrons are available for transfer and whether a particular reactant is being oxidized or reduced in a reaction.

Determine if the substance in question is an element. An unbonded free atom always has an oxidation number of 0. An oxidation number is a number assigned to a compound or element to indicate the number of electrons that have been lost or gained. A negative number indicates that an electron was gained and a positive number indicates that an electron was lost.

Determine if the substance in question is an ion. Aeon has an oxidation number corresponding to the charge. This applies to both ions that are not bonded to other elements and ions, which are part of the ionic compound. The oxidation number explains the ability of elements or compounds that provides or obtain electrons during a chemical reaction.

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Lewis structures for all reactant and product molecules and the show the bonding relationship between atoms of a molecule and the lone pairs of electrons in the molecule

Lewis structure for the reactants and product molecules can be drawn by following the octet rule and considering covalent bonding between the bonded atoms

Here given reaction is

Cl₂(g) + F₂(g) → 2CIF(g)

And lewis structure of reactant means Cl₂(g) + F₂(g) in Cl₂(g) one chlrine has three lone pair attached and another clorine also three lone pair attached whereas F₂(g) also has three pair of lone pair are attached and product means CIF(g) has Cl has three lone pair and F also has three lone pair attached

Lewis structures for all reactant and product molecules are given below

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The net momentum if North is the positive direction is 20,000Kgm/s.

Momentum can simply be defined as the product of the mass of a particle and its velocity.

Momentum is a vector quantity that possesses a magnitude and a direction.

The Formula of momentum is given below:

Momentum, p = m * v

where;

m is the mass and v is the velocity of the body.

S.I. unit of momentum is kgm/s.

We have the given data as follows:

m1 = 500 kg

v1 = 30 m/s

m2 = 200 kg

v2= 25 m/s

Momentum = m1v1 + m2v2

= (500 * 30) + (200 * 25)

= 15000 + 5000

= 20,000 kgm/s

Momentum = 20,000Kgm/s.

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Kelvin temperature will the reaction proceed 4.50 times faster than it did at 315 K is 293K

Temperature is the degree of hotness or coldness of an object

Here given data is certain reaction has an activation energy of 36.11 kJ/mol and reaction proceed 4.50 times faster than it did at 315 K and we have to find kelvin temperature = ?

Then, we have to use the arrhenius equation and set k1 = 1 and k2 = 4.50 because rate = k[A] so as long as concentration of reactants doesn't vary, rate is proportional to k

ln (k₂/k₁) = Ea/R(1/T₁ - 1/T₂)

k₂ = 4.50

k₁ = 1

Ea = 36.11 J/mole

R = 8.314 J/mol⁻k

T ₁= 315 K

T₂ = ?

ln(4.50/1) = 36.11/8.314 (1/314 - 1/T₂)

1.50 = 4.343 (1/315 - 1/T₂)

1.50 = 0.013 - 4.343/T₂

-1.48 = - 4.343/T₂

T₂ = 293 K

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The number of molecules contained in a 4.30-g sample of dimethylmercury is 1.12 × 10²² molecules.

The number of molecules of a substance can be calculated by multiplying the number of moles in the substance by Avogadro's number as follows:

no of molecules = no of moles × 6.02 × 10²³

According to this question, 4.30-g sample of dimethylmercury (C₂H₆Hg) is given. The molar mass of C₂H₆Hg is 230.659 g/mol.

no of moles of dimethyl mercury = 4.3g ÷ 230.659 g/mol = 0.0186 moles

no of molecules of dimethyl mercury = 0.0186 moles × 6.02 × 10²³

no of molecules = 1.12 × 10²² molecules

Therefore, the number of molecules in 4.3g of C₂H₆Hg is calculated to be 1.12 × 10²² molecules.

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