Please help me solve this.

Answer:

-70x, 26y^3, -3z

Step-by-step explanation:

The way to solve this is by combining like terms. The terms we have given to us include x, y^3, and z. As a result, we will group terms based on these variables.

1. Find all the terms with each variable.

* -35x, -35x

* 23y^3, 3y^3

* -3z

2. Combine like terms.

* -35x + (-35x) = -35x - 35x = -70x

* 23y^3 + 3y^3 = 26y^3

* -3z + 0 = -3z

Answer:

Hello! The answer is: [tex]-70x - 3z + 26y^3[/tex]

Step-by-step explanation:

First, rearrange to combine like terms:

[tex]-35x - 35x - 3z + 23y^3 + 3y^3[/tex]

Now, combine like terms:

[tex]-70x - 3z + 26y^3[/tex]

The equation of the hyperbola with foci (-2, 0), (2, 0), and vertices, (-1, 0), (1, 0) is [tex] \underline{\frac{ {x}^{2} }{ {1}^{2} } - \frac{ {y}^{2} }{ 3} } = 1[/tex]

The general form of the equation of an hyperbola is presented as follows;

[tex] \frac{ {x}^{2} }{ {a}^{2} } - \frac{ {y}^{2} }{ {b}^{2} } = 1[/tex]

Where a is obtained from the vertex written as (-a, 0), (a, 0)

The given vertex are (-1, 0), (1, 0), which gives;

a = 1

The general form of the foci of a hyperbola are; (-c, 0), (c, 0)

The given foci of the hyperbola are; (-2, 0), (2, 0)

Where;

Therefore;

By comparison, we have;

c² = 2²

Which gives;

The equation of the hyperbola is therefore;

[tex] \underline{\frac{ {x}^{2} }{ {1}^{2} } - \frac{ {y}^{2} }{ 3} } = 1[/tex]

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The expressions formed are,

Formation of expressions in 1, 2 and 3:

In 1, twelve times f is, 12f

Taking away 5, it becomes (12f-5)

In 2, sum of k and 6 is, (k+6)

One-half of the above quantity is, (k+6)/2

In 3, sum of 5 with x is, (x+5)

Now, x squared minus the above expression indicates (x²-x+5)

Formation of expressions in 4 and 5:

In 4, product of a and b, is ab and 3 times c is 3c

Sum of the expressions evaluated in the previous statement = ab+3c

In 5, 24 times the product of x and y is, 24xy

Adding, g in the above computed expression, we get, 24xy+g

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The sum of the geometric sequence is 31/3

The sequence is given as:

1/3, 2/3, 4/3, 8/3, 16/3

The sum of the sequence is;

Sum = 1/3+ 2/3+ 4/3+ 8/3+ 16/3

Evaluate

Sum = 31/3

Hence, the sum of the geometric sequence is 31/3

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There are 50-50 chances that you will get a head or a tail

y = 2x² - 16x - 32 is the quadratic function of function passes through the points (-2,0), (4,0), and (0,-32).

y=ax²+bx+c is called as Quadratic function

y=ax²+bx+c

The three points are (-2,0), (4,0), and (0,-32)

Let,

(-2,0) in equation

0=a(-2)²+b(-2)+c

0=-2b+c...(1)

(4,0)

0=a(4)²+b(4)+c

0=16a+4b+c..(2)

(0,-32)

-32=a(0)²+b(0)+c

c=-32...(3)

Hence put c value in (1)

0=-2b-32

2b=-32

b=-16

Now put b and c value in 2

0=16(a)+4(-16)+32

0=16a-64+32

0=16a-32

a=2

Hence y = 2x² - 16x - 32 is the quadratic function of function passes through the points (-2,0), (4,0), and (0,-32).

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2x = 10

☆...hope this helps...☆

_♡_mashi_♡_

Answer:

A. 2x = -10

E. 2x = 10

Explanation:

[tex]\sf |2x| = 10[/tex]

If |a| = b then a = b or a = -b

[tex]\sf 2x = 10 \quad or \quad 2x = -10[/tex]

divide both sides by 2

[tex]\sf x = 5 \quad or \quad x = -5[/tex]

Answer:

find the graph where y is 3 less than x in value

Step-by-step explanation:

the answer explains it if you showed us the graphs we would be able to answer it for you

Answer:165

Step-by-step explanation:

The confidence interval for the true mean height of the PBL above the Great Basin Desert is (651.48,748.52) and there is any sufficient evidence that the true mean is different from 700 m .

Given Heights in meters: 673,664,906,956,751,752,654,610,816,667,690,657,920,741,646,682,715,618 and confidence level of 95%.

We have to show the evidence that the true mean height is different from 700 m.

We have to first make hypothesis.

[tex]H_{0}:[/tex]μ=700

[tex]H_{1}[/tex]:μ≠700

We have to first find the population standard deviation.

σ=[tex]\sqrt{(x-x bar)^{2}/n-1 }[/tex]

=[tex]\sqrt{187375.1/17}[/tex]

=104.98

Z=(X-μ)/σ

=(700-728.78)/104.98      (μ=728.78 is calculated in figure)

=-0.2741

p value of -0.2741 =0.39358

0.39358

0.39358<0.90

so we reject the null hypothesis.

Which means that the true mean is different from 700m.

Confidence level=X±z*s/[tex]\sqrt{n}[/tex]

Upper level=700 +1.96*104.98/[tex]\sqrt{18}[/tex]

=700+48.52

=748.52.

Lower level=700-1.96*104.98[tex]\sqrt{18}[/tex]

=700-48.52

=651.48

Hence the confidence interval is (651.48,748.52).

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The chocolate will last for 1 day, if she gets 4 more dragons

The expression can be represented using the following ratio:

Ratio = Dragons : Days : Chocolate

For the 2 dragons she has, we have:

Ratio = 2 : 12 : 300

When she gets 4 more dragons, we have:

Ratio = 6 : days : 300

Equate both ratios

6 : days = 12 : 2

Express as fraction

days/6 = 2/12

Multiply both sides by 6

days = 6 * 2/12

Evaluate

days = 1

Hence, the chocolate will last for 1 day

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Answer:

78.5

Step-by-step explanation:

pi(r^2)

3.14(5^2)

3.14(25)

78.5

pls kindly see the attached picture for the answer and explanation thank you

Answer:

the point of intersection is (-1 , -2)

Step-by-step explanation:

[tex]\begin{cases}x-y=1&(1)\\ 3x-y=-1&(2)\end{cases}[/tex]

(2) - (1) ⇒ (3x - y) - (x - y) = (-1) - 1

⇒ 3x - y - x + y = -2

⇒ 3x - x  = -2

⇒ 2x  = -2

⇒ x  = -1

……………………………

Now ,we can determine the value of y

by substituting x by its value -1 in the first equation (1) :

(1) x - y = 1 ⇒-1 - y = 1 ⇒ -y = 2 ⇒ y = -2

========================

Conclusion:

x = -1

y = -2

Then ,the point of intersection of the graphs is (-1 , -2)

Hello !

[tex]\begin{cases} x - y &=1 \\ 3x-y &= - 1 \end{cases} \\\Leftrightarrow \begin{cases} x =y + 1 \\ 3x-y = - 1 \: \: \: \: \: (a)\end{cases} [/tex]

We replace x by y+1 in (a) :

[tex]3(y + 1) - y = - 1 \\ 3y + 3 - y = - 1 \\ 2y = - 4 \\ y = \frac{ - 4}{2} = - 2[/tex]

Now we replace x by -1 in the first equation.

[tex]x + 2 = 1 \\ x = -1[/tex]

The point of intersection is (-1;-2).

Have a nice day

Answer:

(5, -3)

Step-by-step explanation:

So the center of the two points, or a line can be defined using the equation: [tex]midpoint=(\frac{x_2+x_1}{2}, \frac{y_2+y_1}{2})[/tex]. So using the two points you gave, you simply plug the values in to get

[tex]midpoint=(\frac{3+7}{2}, \frac{-1+(-5)}{2})\\[/tex]

Add numerators:

[tex]midpoint=(\frac{10}{2}, \frac{-6}{2})[/tex]

Simplify fraction:

[tex]midpoint=(5, -3)[/tex]

The system of linear equations that represents this scenario is: q + d = 16

0.25q + 0.10d = 3.10

To represent the scenario described, we can set up a system of linear equations using the given variables:

Let q represent the number of quarters.

Let d represent the number of dimes.

We are given two conditions:

1) The total number of coins is 16:

q + d = 16

2) The total value of the coins is $3.10:

0.25q + 0.10d = 3.10

Therefore, the system of linear equations that represents this scenario is:

q + d = 16

0.25q + 0.10d = 3.10

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The diameter of the milky way is given as 4.3 x 10¹¹m while the diameter of the radius of the earth is 0.00276

The transformed system is given as 23.18 x 10⁸ in real length

Hence the diameter is

10 x 10²⁰ / 23.18 x 10⁸

= 4.3 x 10¹¹ m

Distance from the sun to the earth = 1.496 x 10¹¹m

Transformed system = 1.496 x 10¹¹m/23.18 x 10⁸

= 64.5 m

Actual radius = 6.4 x10⁶ / 23.18 x 10⁸

= 0.00276

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Answer:

The answer is C = -1

Answer:

Step-by-step explanation:

Argument

I think the answer is A = N or D. It that is true, then M = C because all three angles are equal which gives similarity. But there is a side involved. OM = CB. Therefore the two triangles are congruent by ASA

Answer

ASA

Answer:

a) 5.7%

b) 45.8%

c) 6.4%

d) 47.6%

Step-by-step explanation:

remember, we find percentage as:

specific / total

(ex. if we have 2 dogs and 2 cats, and we want to find what percentage of total animals are dogs, we divide 2/4 to get 0.5, or 50%)

percentage of female students who prefer sci-fi

here, we know we have 106 female students (total: 106)

and we have 6 of those students who prefer sci-fi (specific: 6)

6 / 106 = 0.05660..

which we can round to: 0.0566

So, the first percentage is 5.66%

(5.7%)

percentage of students who prefer comedies that are male

we have 118 students who prefer comedies (total: 118)

and 54 of those students that are male (specific: 54)

54 / 118 = 0.4576...

which we can round to 0.4576

So, the second percentage is 45.76%

(45.8%)

percentage of male students who prefer dramas

we have 94 male students (total: 94)

and 6 who prefer dramas (specific: 6)

6 / 94 = 0.0638298...

which we can round to 0.0638

So, the third percentage is 6.38%

(6.4%)

percentage of students who prefer action movies that are female

we have 42 students who prefer action movies (total: 42)

and 20 of those who are female (specific: 20)

20 / 42 = 0.47619..

which we can round to 0.4762

So, the fourth percentage is 47.62%

(47.6%)

hope this helps! have a lovely day :)

Th equation that can be used to determine when they would have saved the same amount is 0.3(10 + 4h) = 0.25(6h).

The equation that can be used to determine the amount saved by Fernando is:

total amount saved = percentage saved x (amount charged to drive to the appointment + total amount earned)

0.3( $10 + $4h)

The equation that can be used to determine the amount saved by Brenna is:

percentage saved x total amount earned

0.25h

When they save the amount amount, the two above equations would be equal:  0.3(10 + 4h) = 0.25(6h).

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The correct match for the graph of the total cost function is the option B graph.

The function is a type of relation, or rule, that maps one input to specific single output.

Given;

y = 2x is function

so, our graph should be of function y = 2x

Here, x is the number of pounds of rice scooped and purchased from a bulk bin at the grocery store and y is the total cost of the rice.

it means x is a number like 0, 1, 2, 3

so, the graph of the total cost function is a discrete function in nature.

Hence, graph-B is correct answer.

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The multiplicative rate of change of the function will be 0.5. Then the correct option is C.

Let b is the base and x is the power of the exponent function and a is the leading coefficient. The exponent is given as

y = a(b)ˣ

The missing table is attached below.

For x = 2, y will be 0.125

0.125 = ab²  ...1

For x = 3, y will be 0.0625

0.0625 = ab³   ...2

Divide equation 2 by equation 1, we have

b = 0.0625 / 0.125

b = 0.5

Then the correct option is C.

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Triangle ABC is congruent to triangle CDE using the side - angle - side congruence theorem. The sink hole is 52.2 ft and the Perimeter of ABC is 172.2 ft

Two triangles are said to be congruent if they have the same shape and their corresponding sides are congruent.

In the image shown:

AC = CE, BC = ED and they have the same angle (opposite angles are congruent).

Hence:

Triangle ABC is congruent to triangle CDE using the side - angle - side congruence theorem.

AB = DE = 52.2 ft

Perimeter of ABC = AB + BC + AC = 50 + 70 + 52.2 = 172.2 ft

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Answer:

29u

Step-by-step explanation:

a = (V-U)/t = (1.2u-u)/10 = 0.02u

D1: V₀t+0.5at² = (u)(10)+(0.5)(0.02u)+(10)(10) = 11u

D2: (V)(t) = (1.2u)(15) = 18u

D = D1 + D2 = 29u

For first half

We need acceleration first

So distance traveled (Apply second equation of kinematics

For second half

No acceleration

Distance=Speed×Time

Total distance

Answer:

3/25

Step-by-step explanation:

0.12=12/100

12/100 can be simplified 6/50 = 3/25

[tex] \qquad \qquad \bf \huge\star \: \: \large{ \underline{Answer} } \huge \: \: \star[/tex]

[ b ] is the Correct one

[tex]\textsf{ \underline{\underline{Steps to solve the problem} }:}[/tex]

[tex] \qquad❖ \: \sf \:4 \: log_{3}(y) - 6 \: log_{3}(x) + 7 \: log_{3}(z) [/tex]

[tex] \qquad❖ \: \sf \: \: log_{3}(y {}^{4} ) - \: log_{3}(x {}^{6} ) +\: log_{3}(z {}^{7} ) [/tex]

[tex] \qquad❖ \: \sf \: \: log_{3}(y {}^{4} ) + \: log_{3}(z{}^{7} ) - \: log_{3}(x {}^{6} ) [/tex]

([tex] \sf a\: log (b) = log {b}^{a}[/tex])

[tex] \qquad❖ \: \sf \: log_{3}( {y}^{4} {z}^{7} ) - log_{3}( {x}^{6} {}^{} ) [/tex]

([tex] \sf{log (a) + log (b) = log (ab)} [/tex])

[tex] \qquad❖ \: \sf \: log_{3} \bigg( \dfrac{y {}^{4} {z}^{7} }{ {x}^{6} } \bigg ) [/tex]

([tex] \sf{log (a) - log (b) = log (a/b)} [/tex])

[tex] \qquad \large \sf {Conclusion} : [/tex]

[ b ] is the Correct choice

Answer:

angle angle theorem.

Step-by-step explanation:

If you want to determine whether a few angles are similar you can use formulas such as SAS AAA ASA etc.

this means

side angle side

angle angle anlge

angle side angle

The quantity that is present after 2000 years will be A. 7.851 grams.

From the information given, initially at t = 0, the quantity is 10 grams.

After 2000 years, the appropriate quantity will be:

Q(2000) = 10 (1/2) × (2000/5730)

Q(2000) = 7.851 grams.

In conclusion, the correct option is A.

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Given that DE||AC, by similar triangles, we have;

A part of the question that appears missing is; side DE||AC

The completed two column proof is presented as follows;

Statement. Reason

1. DE||AC 1. Given

2. <EDB congruent to <CAB

<DEB congruent to <ACB

Which can be written as; <CAB congruent to <EDB, <ACB congruent to <DEB

2. If two parallel lines are cut by a common transversal, the corresponding angles are congruent

3. ∆ABC ~ ∆DBE 3. by AA criterion for similarity

4.

[tex] \mathbf{\frac{ AB }{ CB} } = \frac{ DB }{ EB} [/tex]

4. Corresponding sides of similar triangles are proportional

5. AB = AD + DB

CB = CE + EB 5. Segment addition postulate

6. [tex] \mathbf{\frac{ AD + DB }{ CE + EB} } = \frac{ DB }{ EB} [/tex]

6. Substitution property of equality

7. [tex] \frac{ AD + DB }{ DB} = \frac{ CE + EB }{ EB} [/tex]

7. Division property

8. [tex] \frac{ AD }{ DB} + 1 = \frac{ CE }{ EB} + 1 [/tex]

[tex] \frac{ AD }{ DB} = \frac{ CE }{ EB} [/tex]

8. Subtraction property

Therefore, the missing step in the proof is the option;

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