Please help me out you can just give me the answer! PLEASE AND THANK YOU!

Answer:

Option 3 is not true for f(x) and g(x).

The incorrect statement will be;

⇒ f (x) × g(x) = 4x⁵ + 8x⁴ - 13x³ - 17x² + 3x + 9

Division method is used to distributing a group of things into equal parts. Division is just opposite of multiplications. For example, dividing 20 by 2 means splitting 20 into 2 equal groups of 10.

Given that;

The function are,

⇒ f(x) = 2x² + x - 3

And , g(x) = 2x³ + 3x² - 2x - 3

Now,

Since, The function are,

⇒ f(x) = 2x² + x - 3

And , g(x) = 2x³ + 3x² - 2x - 3

Hence, We get;

⇒ f (x) + g(x) = 2x² + x - 3 + 2x³ + 3x² - 2x - 3

                   = 2x³ + 5x² - x - 6

⇒ g (x) - f (x) = (2x³ + 3x² - 2x - 3) - (2x² + x - 3)

                   = 2x³ + 3x² - 2x - 3 - 2x² - x + 3

                   = 2x³ + x² - 3x

⇒ f (x) × g(x) = (2x² + x - 3) (2x³ + 3x² - 2x - 3)

                 = 4x⁵ + 6x⁴ - 4x³ - 6x² + 2x⁴ + 3x³ - 2x² - 3x - 6x³ - 9x² + 6x +9

                = 4x⁵ + 8x⁴ - 7x³ - 17x² + 3x + 9

Thus, The incorrect statement is,

⇒ f (x) × g(x) = 4x⁵ + 8x⁴ - 13x³ - 17x² + 3x + 9

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Answer:

581

mark me as brainliest plz

a)The probability that 3 balls drawn have the same color=1/28.

b)The probability that 3 balls drawn have different colors= 3/14.

c)A and B are mutually exclusive events.

Explanation:

Given that a vase contains 9 balls: 3 blue, 3 red, and 3 green ones. Three random balls are drawn from the vase and are not put back in.

The events that are considered are: A = the 3 balls drawn to have the same color. B = the 3 balls drawn have different colors.

(a) Calculation of P(A), We need to find the probability that 3 balls drawn have the same color.

P(A) = probability of getting 3 blue balls + probability of getting 3 red balls + probability of getting 3 green balls.

The probability of getting 3 blue balls is 3/9 × 2/8 × 1/7 = 1/84.

The probability of getting 3 red balls is 3/9 × 2/8 × 1/7 = 1/84.

The probability of getting 3 green balls is 3/9 × 2/8 × 1/7 = 1/84

Therefore, P(A) = 1/84 + 1/84 + 1/84 = 3/84 = 1/28.

(b) Calculation of P(B), We need to find the probability that 3 balls drawn have different colors.

P(B) = probability of getting one ball of each color + probability of getting 2 balls of one color and one ball of another color.

The probability of getting one ball of each color is 3/9 × 3/8 × 3/7 = 27/252

The probability of getting 2 balls of one color and one ball of another color is 3(3/9 × 2/8 × 3/7) = 27/252

Therefore, P(B) = 27/252 + 27/252 = 54/252 = 3/14.

(c) Finding if are A and B independent,

A and B are not independent as P(A) = 1/28 and P(B) = 3/14.

The probability of both A and B occurring together is zero, as it is impossible to draw 3 balls that are of the same color and 3 balls of different colors at the same time. Hence, A and B are mutually exclusive events.

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a) The probability that the 3 balls drawn have the same color:

               P(A) =  0.0095 or 0.95%

b) The probability that the 3 balls drawn have different colors:

               P(B) = 0.2143 or 21.43%

c) A and B are not independent.

Explanation:

a)

P(A) = (3/9) × (2/8) × (1/7) + (3/9) × (2/8) × (1/7) + (3/9) × (2/8) × (1/7)

          = 0.0095 or 0.95%

Note: In the first fraction, the numerator is 3 because there are three blue balls. The denominator is 9 because there are 9 balls in total.

Since the first ball has been drawn, there are only 8 balls left, hence 2/8 in the second fraction. And so on.

b)

P(B) = (3/9) × (3/8) × (3/7) + (3/9) × (3/8) × (3/7) + (3/9) × (3/8) × (3/7)  

       = 0.2143 or 21.43%

Note: In the first fraction, the numerator is 3 because there are three blue balls. The denominator is 9 because there are 9 balls in total.

Since the first ball has been drawn, there are only 8 balls left, hence 3/8 in the second fraction. And so on.

c)

P(A)P(B) = 0.0095 × 0.2143

             = 0.00204

             ≈ 0.2%

P(A ∩ B) = 0 (because if you have 3 balls of different colors, then you cannot have 3 balls of the same color at the same time)

Therefore, A and B are not independent.

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Yes, the given matrix A is diagonalizable.

Let the matrix A be given by A = [−2 2 1 0 0 2].

To determine if this matrix is diagonalizable, we need to check whether A has enough linearly independent eigenvectors. If there are enough such eigenvectors, then A will be diagonalizable. Otherwise, A will not be diagonalizable.

To find the eigenvalues and eigenvectors of the matrix A, we solve the equation Ax = λx, where λ is a scalar (eigenvalue) and x is the corresponding eigenvector. This gives: (A - λI)x = 0, where I is the identity matrix.To solve for the eigenvalues, we need to find λ such that det(A - λI) = 0. This gives us the characteristic equation:

(−2 − λ)(2 − λ)(1 − λ) − 4(2 − λ) = 0, which simplifies to λ^3 − λ^2 − 10λ − 12 = 0.

To find the eigenvectors, we solve for x in the equation (A - λI)x = 0, using each eigenvalue λ obtained from the characteristic equation.To solve for λ, we need to solve the characteristic equation. Factoring it gives (λ - 4)(λ + 1)^2 = 0, which has eigenvalues λ1 = 4 and λ2 = −1 (multiplicity 2).

Since we have two distinct eigenvalues (λ1 = 4 and λ2 = −1), we know that A is diagonalizable if and only if it has two linearly independent eigenvectors corresponding to each eigenvalue.To find the eigenvectors corresponding to λ1 = 4, we need to solve the system (A - 4I)x = 0.

This gives the matrix equation:

[−6 2 1 0 0 −2][x1 x2 x3 x4 x5 x6] = [0 0 0 0 0 0]

Solving this system gives x1 = -x3/6 - x6/2, x2 = x2, and x4 = x4. We can choose any two of these variables (for example, x3 and x6) and solve for the other three variables in terms of them.

Doing so gives:

x1 = -1/6

x3 - x6/2x2 = x2x4 = x4x5 = 0

So, the eigenvectors corresponding to λ1 = 4 are of the form [x1 x2 x3 x4 x5 x6] = [−1/6t  −2s  t  0  0  −2t], where t and s are arbitrary constants.To find the eigenvectors corresponding to λ2 = −1, we need to solve the system (A + I)x = 0.

This gives the matrix equation: [−1 2 1 0 0 2][x1 x2 x3 x4 x5 x6] = [0 0 0 0 0 0]

Solving this system gives x1 = -x3 + 2x6, x2 = x2, and x4 = -2x6. We can choose any two of these variables (for example, x3 and x6) and solve for the other three variables in terms of them. Doing so gives: x1 = 2t - s, x2 = x2, x4 = -2t ,x5 = 0

So, the eigenvectors corresponding to λ2 = −1 are of the form [x1 x2 x3 x4 x5 x6] = [2t − s  0  t  −2t  0], where t and s are arbitrary constants.Since we have four linearly independent eigenvectors (two corresponding to each eigenvalue), we can diagonalize the matrix A by forming the matrix P whose columns are these eigenvectors.

The matrix P is given by P = [−1/6 −2 2 0 0 2][0 1 0 0 0 0][1 −2 0 0 0 0][0 0 0 1 0 0][0 0 1 0 0 0][−2 0 0 0 0 1]

Hence A is diagonalizable.

Answer: Yes, the given matrix A is diagonalizable.

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The long-range prediction for the fraction of mice in each compartment is approximately 40% in Compartment A, 30% in Compartment B, and 30% in Compartment C.

To determine the long-range predictions, we can set up a system of equations based on the probabilities of mice moving between compartments. Let's denote the fraction of mice in compartment A as x, in compartment B as y, and in compartment C as z.

For compartment A, the fraction of mice in the next step will be 0.2x (moving to B) and 0.4x (moving to C). Similarly, for compartments B and C, the fractions in the next step will be 0.25y + 0.4z and 0.45y + 0.3z, respectively.

Setting up the equations, we have:

x = 0.2x + 0.4z
y = 0.25y + 0.4z
z = 0.45y + 0.3z

Simplifying and solving the equations, we find:

x = 0.4
y = 0.3
z = 0.3

Therefore, the long-range prediction for the fraction of mice in compartment A is 0.4, in compartment B is 0.3, and in compartment C is 0.3. This means that over time, approximately 40% of mice will be in compartment A, 30% in compartment B, and 30% in compartment C.

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The client index of the company in 2020 compared to 2019 is 2.14.

To calculate the client index of the company in 2020 compared to 2019 we can use the formula below;

Client Index = (Number of clients in current year / Number of stores in current year) / (Number of clients in previous year / Number of stores in previous year)

The client index of the company in 2020 compared to 2019 is: 2.14 (rounded to 2 decimal places).

Clients in 2019 = 9539Clients in 2020 = 12504Premium Clients of the Year 2020 = 1230Stores in 2019 = 17Stores in 2020 = 12

To calculate the client index of the company in 2020 compared to 2019 we can use the formula below;

Client Index = (Number of clients in current year / Number of stores in current year) / (Number of clients in previous year / Number of stores in previous year)We can substitute the values into the formula and simplify it as follows;

Client Index = (12504 / 12) / (9539 / 17) = (1042 / 1) / (561 / 1) = 1042 / 561 = 1.85714285714 ≈ 2.14

Therefore, the client index of the company in 2020 compared to 2019 is 2.14 (rounded to 2 decimal places).

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Answer:

sorry

Step-by-step explanation:

i can't understand your question

there is no clarity

Step-by-step explanation:

f(x) = x^2 represents a quadratic function, where the input value (x) is squared and the resulting output value is equal to the square of x.

g(x) = (x+3)^2 - 1 represents another quadratic function, where the input value (x) is first added to 3, then squared, and the resulting output value is equal to the square of (x+3) minus 1.

To evaluate these functions for a specific value of x, we simply substitute that value into the function in place of x. For example, if we want to find f(4), we would replace x with 4 to get:

f(4) = 4^2 = 16

Similarly, if we want to find g(-2), we would replace x with -2 to get:

g(-2) = (-2+3)^2 - 1 = 1^2 - 1 = 0

We can also graph these functions on a coordinate plane by plotting points for various values of x and their corresponding values of f(x) or g(x). The graph of f(x) = x^2 is a parabola that opens upwards, while the graph of g(x) = (x+3)^2 - 1 is also a parabola, but it has been shifted 3 units to the left and 1 unit downwards compared to the graph of f(x).

Answer:

A.  g(x) = -[tex]x^{2}[/tex] - 4

Step-by-step explanation:

f(x) is flipped, so [tex]x^{2}[/tex] becomes -[tex]x^{2}[/tex].

After being flipped, the graph is move down 4 units.

Therefore, g(x) = -[tex]x^{2}[/tex] - 4

Answer:

2 2/5

Step-by-step explanation:

2.4 = 2 4/10 = 2 2/5 (all you had to do is divide by 2)

The answer would be 2 2/5 (could also be 1.2 as a decimal)

Hopefully this helps :3 sorry if wrong :( plz mark brainiest if correct :D Your bootiful/handsome! Have a great day luv <3

-Bee~

Step-by-step explanation:

The

2

is in the ones place, and the

4

is in the tenths place.

2.4

means two and four tenths. So in fraction form it is 2 4/10

Answer link

Answer:

[tex]\implies\boxed{ 10^a = 300 }[/tex]

Step-by-step explanation:

We are provided logarithmic equation , which is ,

[tex]\implies log_{10}^{300}= a [/tex]

Say if we have a expoteintial equation ,

[tex]\implies a^m = n [/tex]

In logarithmic form it is ,

[tex]\implies log_a^n = m [/tex]

Similarly our required answer will be ,

[tex]\implies\boxed{ 10^a = 300 }[/tex]

Answer:

77

Step-by-step explanation:

7x10 is 70 plus 7 is 77

Phone calls and days of the week are independent. There is insufficient evidence to conclude otherwise.

In the analysis of phone call frequencies for each day of the week, we need to determine if phone calls are equally likely to occur on any day. Using a significance level of 0.10, we can perform a chi-square goodness-of-fit test.

The null hypothesis (H₀) states that the distribution of phone calls is uniform over the days of the week, while the alternative hypothesis (H₁) suggests that the distribution is not uniform.

To calculate the expected frequencies, we divide the total number of phone calls (581) by the number of days (7), resulting in an expected frequency of 83 for each day.

The degrees of freedom for this test are (number of categories - 1), which in this case is 7 - 1 = 6.

Using the chi-square test statistic and the calculated expected frequencies, we can find the p-value associated with the test statistic. If the p-value is less than the significance level of 0.10, we reject the null hypothesis in favor of the alternative hypothesis. Otherwise, we fail to reject the null hypothesis.

Based on the analysis, the p-value is not provided, so we cannot draw a specific conclusion.

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Answer:

[tex]\begin{array}{cc}{Cars} & {Months} & {28} & {3} & {29} & {3} & {30} & {1} & {31} & {2} \ \end{array}[/tex]

Step-by-step explanation:

Given

Data:

[tex]29\ 30\ 29[/tex]

[tex]29\ 31\ 28[/tex]

[tex]28\ 31\ 28[/tex]

Required

Construct a frequency table

From the given data, we have:

28 occurs 3 times

29 occurs 3 times

30 occurs 1 time

31 occur 2 times

Hence, the frequency table is:

[tex]\begin{array}{cc}{Cars} & {Months} & {28} & {3} & {29} & {3} & {30} & {1} & {31} & {2} \ \end{array}[/tex]

Answer:

Hope it helps! follow me!  brainliest! Peace out!

Step-by-step explanation:

Cars:      months:

28           3

29           3

30           1

31            2

Answer:

325

Step-by-step explanation:

got it right on edg

The required equation of the circle that shown in the graph is,
(x + 1)² + (y - 2)² = 4 where (-1 , 2) is the center of the circle and 2 unit is the radius of the circle. Option C is correct.

A graph of the circle is shown, It is to determine the equation of the circle.

The circle is the locus of a point whose distance from a fixed point is constant i.e center (h, k). The equation of the circle is given by

(x  - h)² + (y - k)² = r²

where h, k is the coordinate of the circle's center on the coordinate plane and r is the circle's radius.

From the graph, the center is ( -1, 2) and the radius is  2. Now put these values in the standard equation of the circle.
(x - (-1))² + (y - 2)² = 2²
(x +1 )² + (y - 2)² = 4

Thus, the required equation of the circle that shown in the graph is,
(x + 1)² + (y - 2)² = 4 where (-1 , 2) is center of the circle and 2 unit is the radius of the circle. Option C is correct.

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The position function is obtained by integrating the acceleration function twice and applying initial conditions: s(t) = -5/16 sin(4t) + 9/4t + 6.

To find the position function, we need to integrate the acceleration function twice with respect to time (t) and apply the initial conditions.

Given:

Acceleration function: a(t) = 5 sin(4t)

Initial velocity: v(0) = 1

Initial position: s(0) = 6

First, integrate the acceleration function to find the velocity function:

v(t) = ∫(a(t)) dt = ∫(5 sin(4t)) dt = -5/4 cos(4t) + C1

Next, apply the initial velocity condition to solve for the constant C1:

v(0) = -5/4 cos(0) + C1 = 1

C1 = 1 + 5/4 = 9/4

Now, integrate the velocity function to find the position function:

s(t) = ∫(v(t)) dt = ∫(-5/4 cos(4t) + 9/4) dt = -5/16 sin(4t) + 9/4t + C2

Finally, apply the initial position condition to solve for the constant C2:

s(0) = -5/16 sin(0) + 9/4(0) + C2 = 6

C2 = 6

Therefore, the position function is:

s(t) = -5/16 sin(4t) + 9/4t + 6 (Expression using t as the variable).

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Answer:

A

Step-by-step explanation:

A line of best fit is a line that gives an estimate of where the line would be, therefore it is close to most of the data points.

Answer:

A)

Step-by-step explanation:

Answer:

I think the answer is 49in^2

Answer:

Answer:

Area of a CIRCLE with radius of 3 inches is

PI * radius^2 =

3.14159265 * 3^2 =

28.27433385  square inches.  

Since we are dealing with a SEMI-CIRCLE, we divide that by 2 and get:

14.137166925  square inches which rounds to about

14.14 square inches

Step-by-step explanation:

Answer: 30pi^2 divided by 2

Explanation:

To find the area of a circle, it is pi x radius ^2

Since it is a semicircle 30 is the radius.

pi x radius ^ 2 = 30pi^2

the area would be 30pi^2 divided by 2

the 95% confidence interval for the true proportion of all adults in the town who do not have health insurance is approximately (0.2686, 0.4586).

To find a confidence interval for the true proportion of adults in the town who do not have health insurance, we can use the following formula:

Confidence Interval = Sample Proportion ± Margin of Error

First, we need to calculate the sample proportion:

Sample Proportion ([tex]\hat{p}[/tex]) = Number of adults without health insurance / Total number of adults

Total number of adults = 99 (given)

Number of adults with health insurance = 99 - 63 = 36

Sample Proportion ([tex]\hat{p}[/tex]) = 36 / 99 ≈ 0.3636

Next, we need to calculate the margin of error. Since the sample size is large and we are working with proportions, we can use the formula for the margin of error in a proportion:

Margin of Error = Z * √[([tex]\hat{p}[/tex] * (1 - [tex]\hat{p}[/tex])) / n]

Where:

Z is the Z-score corresponding to the desired level of confidence (95% confidence corresponds to a Z-score of approximately 1.96)

[tex]\hat{p}[/tex] is the sample proportion

n is the sample size

Margin of Error = 1.96 * √[(0.3636 * (1 - 0.3636)) / 99]

Calculating the margin of error:

Margin of Error ≈ 1.96 * √(0.2332 / 99)

             ≈ 1.96 * √(0.002352525)

Margin of Error ≈ 1.96 * 0.048503

Margin of Error ≈ 0.095

Finally, we can construct the confidence interval:

Confidence Interval = Sample Proportion ± Margin of Error

Confidence Interval = 0.3636 ± 0.095

Confidence Interval ≈ (0.2686, 0.4586)

Therefore, the 95% confidence interval for the true proportion of all adults in the town who do not have health insurance is approximately (0.2686, 0.4586).

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1. Current Yield on Chester's bond Chester has a par value of $500 bond issued by Harris County, which pays 6.2% yearly interest. When Chester bought it, the market rate of Harris County bonds was 101.760. As the bond is purchased at a premium, the bond's price is above the par value. It is trading above the face value of $500 per bond.Using the current market rate formula, C = (I/PV) + (FV/PV)n

Where ,C = Current YieldI = Yearly Interest PV = Current Market RateFV = Par Value ($500)n = Number of Years Then,

98.626 = (6.2/ PV) + (500 / PV)101.760

[tex](PV) = $498.70PV = $4.90[/tex]

Therefore, the current market price of the bond is $4.90.Using the current yield formula, Current Yield = (Yearly Interest/Current Market Price) x 100Current

Yield [tex]= (6.2/4.90) x 100 = 126.53[/tex]

Therefore, the current yield on Chester's bond is 126.53%.2. Investment with a greater return after six years After six years, the return on stocks and bonds investment will be calculated as: Stocks

Return = [tex]1,000(1 + 0.053)^6 = $1,385.94[/tex]

Bonds Return = [tex]1,400(1 + 0.041)^6 = 1,734.69[/tex]

Therefore, the return on bonds investment is $1,734.69, and the return on stocks investment is $1,385.94. The bonds investment will show a greater return after six years, and the difference is $348.75.3. Greater percent yield of Maria's Investment Maria owns four par value $1,000 bonds and 126 shares of stock in Prince Waste Collection. The bonds pay a yearly interest of 7.7%, and Maria bought them when the market value was 97.917.The cost of one stock = $19.33 and the yearly dividend per stock is 85 cents.

Maria's total investment in stocks = [tex]126\times$19.33 = $2,439.18[/tex]

Maria's total investment in bonds = $1,000 x 4 = $4,000 When Maria bought bonds, the market value of the bond was [tex]979.17 ($1,000 x 0.97917).[/tex][tex]= (Yearly Interest / Purchase Price) \times 100= (7.7 / 979.17) \times 100 = 0.786%[/tex]

The stock's annual yield[tex]= (Dividend / Purchase Price) \times100= (0.85 / 19.33) \times 100 = 4.4%[/tex]

Therefore, the percent yield on stocks is greater, and the difference is 3.61%.

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Answer:

12 units

Step-by-step explanation:

got it right on edg

The variance is calculated as the average of the squared deviations from the average return. The standard deviation is the square root of the variance. For X, the standard deviation is √(130.24%) = 36.07%. For Y, the standard deviation is √(388.48%) = 62.35%.

First, calculate the average returns by summing up the returns for each year and dividing by the total number of years. For X, the average return is

(21% - 16% + 9% + 18% + 4%) / 5 = 7.2%.

For Y, the average return is

(24% - 3% + 26% - 13% + 30%) / 5 = 12.8%.

Next, calculate the variances. For X, subtract the average return from each year's return, square the result, and calculate the average of these squared deviations. The variance for X is

(6.2^2 + (-23.2)^2 + 1.8^2 + 10.8^2 + (-3.2)^2) / 5 = 130.24%.

Similarly, for Y, the variance is

(11.2^2 + (-15.8)^2 + 13.2^2 + (-25.8)^2 + 17.2^2) / 5 = 388.48%.

Finally, calculate the standard deviations by taking the square root of the variances. For X, the standard deviation is √(130.24%) = 36.07%. For Y, the standard deviation is √(388.48%) = 62.35%.

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Answer:

324

Step-by-step explanation:

1 yards = 36 inches

36 x 9 = 324

Answer:

Steps:

V = H × (h×bl)/2

V = 6 × (4.2×2.8)/2

V = 6 × 11.76/2

V = 6 × 5.88

V = 35.28 m³

Answer: a

Step-by-step explanation: A plane is a 2d surface so if it ever intersects a 3d object the cross-section will be a 2d figure, in this case, a rectangle.

The combination of food A and food B that meets the requirements and has the greatest amount of protein is 2 units of food A and 1 unit of food B, with a total of 30 grams of protein.

We can approach the problem of finding the combination of food A and food B that meets the requirements and has the greatest amount of protein using linear programming.

1) Variables:

Let x be the number of units of food A.
Let y be the number of units of food B.

2) Organizational chart:

Food A:
Sodium: 120 mg/unit
Fat: 1 g/unit
Protein: 5 g/unit

Food B:
Sodium: 60 mg/unit
Fat: 1 g/unit
Protein: 4 g/unit

Meal requirements:
Sodium: ≤ 480 mg
Fat: ≤ 6 g

Objective: Maximize protein

3) Objective equation:

Maximize z = 5x + 4y

4) Constraint inequalities:

120x + 60y ≤ 480 (sodium constraint)
x + y ≤ 6 (fat constraint)
x ≥ 0, y ≥ 0 (non-negative constraint)

5) Graph the constraints:

To graph the constraints, we can first graph the boundary lines.

120x + 60y = 480
x + y = 6

Then we can shade the feasible region, which is the region that satisfies all the constraints.

The feasible region is a polygon with vertices at (0,0), (4,2), (6,0), and (3,3).

6) Find the vertices:

The vertices of the feasible region are (0,0), (4,2), (6,0), and (3,3).

7) Test the vertices:

We can test each vertex by substituting its coordinates into the objective equation and finding the maximum value.

(0,0): z = 0
(4,2): z = 30
(6,0): z = 30
(3,3): z = 27

The maximum value of the objective function is 30, which occurs at the points (4,2) and (6,0).

8) Write the complete solution:

To maximize protein while satisfying the sodium and fat constraints, we need to use 4 units of food A and 2 units of food B, or 6 units of food A and 0 units of food B. Both of these combinations have a total of 30 grams of protein.

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Step-by-step explanation:

6×10

=60

niceeeeeeeeeeee