Since the isotope is initially 154 mg, the amount of radioactive isotope left after 64 hours is 9.625 mg
To answer the question, we need to know what radioactive decay is.
What is radoactive decay?Radioactive decay is the spontaneous disintegration of a larger atom to a smaller one
What is half-life?Half-life of a radioactive isotope is the time it takes for the isotope to decay to half its initial value.
Amount left after n half livesThe amount left after n half lives is N = (1/2)ⁿN₀ where N₀ = initial mass of isotope.
Given that the half-life of the isotope is 16 hours, and we desire the amount present after 64 hours.
The number of half-lives after 64 hours is n = time/half-life
= 64 h/16 h
= 4
Since we have 154 mg of isotope present, N₀ = 154 mg
Given that
n = 4 and N₀ = 154 mgSubstituting the values of the variables into N, we have
N = (1/2)ⁿN₀
N = (1/2)⁴ × 154 mg
N = 154 mg/16
N = 9.625 mg
So, the amount of radioactive isotope left after 64 hours is 9.625 mg
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precal—easy one question. please help!!
please answer this question
Answer:
[tex]\displaystyle \int {x^{-11}(1 + x^4)^\Big{- \frac{1}{2}}} \, dx = \boxed{ - \frac{\sqrt{x^4 + 1} (8x^8 - 4x^4 + 3)}{30x^{10}} + C }[/tex]
General Formulas and Concepts:
Calculus
Differentiation
DerivativesDerivative NotationDerivative Rule [Basic Power Rule]:
f(x) = cxⁿf’(x) = c·nxⁿ⁻¹Integration
IntegralsIntegration Rule [Reverse Power Rule]:
[tex]\displaystyle \int {x^n} \, dx = \frac{x^{n + 1}}{n + 1} + C[/tex]
Integration Property [Multiplied Constant]:
[tex]\displaystyle \int {cf(x)} \, dx = c \int {f(x)} \, dx[/tex]
Integration Property [Addition/Subtraction]:
[tex]\displaystyle \int {[f(x) \pm g(x)]} \, dx = \int {f(x)} \, dx \pm \int {g(x)} \, dx[/tex]
Integration Methods: U-Substitution, U-Solve, Trigonometric Substitution
Step-by-step explanation:
*Note:
The problem is too big to fit all work. I will assume that you know how to do basic calculus.
Step 1: Define
Identify given.
[tex]\displaystyle \int {x^{-11}(1 + x^4)^\Big{- \frac{1}{2}}} \, dx[/tex]
Step 2: Integrate Pt. 1
[Integrand] Rewrite:Step 3: Integrate Pt. 2
Identify variables for u-substitution/u-solve.
Set u:Step 4: Integrate Pt. 3
Start solving the integral using u-solve:
[tex]\displaystyle \begin{aligned}\int {x^{-11}(1 + x^4)^\Big{- \frac{1}{2}}} \, dx & = \int {\frac{1}{x^{11}\sqrt{x^4 + 1}}} \, dx \\& = \int {\frac{1}{2u^6 \sqrt{u^2 + 1}}} \, du \\& = \frac{1}{2} \int {\frac{1}{u^6 \sqrt{u^2 + 1}}} \, du \\\end{aligned}[/tex]
Step 5: Integrate Pt. 4
Identify variables for trigonometric substitution.
Set u:Step 6: Integrate Pt. 5
Let's focus on just the integral itself. Apply the Trigonometric Substitution Integration Method and other basic integration techniques listed under "Calculus":
[tex]\displaystyle \begin{aligned}\int {\frac{1}{u^6 \sqrt{u^2 + 1} }} \, du & = \int {\frac{\sec^2 v}{\tan^6 v \sqrt{\tan^2 v + 1} }} \, dv \\& = \int {\frac{\sec v}{\tan^6 v}} \, dv \\& = \int {\cot v \csc v (\csc^2 v - 1)^2} \, dv \\\end{aligned}[/tex]
Step 7: Integrate Pt. 6
Identify variables for u-substitution/u-solve again.
Use another variable besides u to avoid confusion with earlier substitutions:
Set w:Step 8: Integrate Pt. 7
Reduce the integral using the U-Solve Integration Method and other basic integration techniques listed under "Calculus":
[tex]\displaystyle \begin{aligned}\int {\frac{1}{u^6 \sqrt{u^2 + 1} }} \, du & = \int {\frac{\sec^2 v}{\tan^6 v \sqrt{\tan^2 v + 1} }} \, dv \\& = \int {\frac{\sec v}{\tan^6 v}} \, dv \\& = \int {\cot v \csc v (\csc^2 v - 1)^2} \, dv \\& = \int {-(w^2 - 1)^2} \, dw \\& = - \int {(w^2 - 1)^2} \, dw \\& = - \int {\bigg( w^4 - 2w^2 + 1 \bigg)} \, dw \\\end{aligned}[/tex]
Step 9: Integrate Pt. 8
Solve the integral using basic integration techniques listed under "Calculus":
[tex]\displaystyle\begin{aligned}- \int {\bigg( w^4 - 2w^2 + 1 \bigg)} \, dw & = - \Bigg[ \int {w^4} \, dx - \int {2w^2} \, dx + \int {} \, dx \Bigg] \\& = - \Bigg[ \int {w^4} \, dx - 2 \int {w^2} \, dx + \int {} \, dx \Bigg] \\& = - \Bigg[ \frac{w^5}{5} - \frac{2w^3}{3} + w + C \Bigg] \\& = - \frac{w^5}{5} + \frac{2w^3}{3} - w + C \\& = - \frac{\csc^5 v}{5} + \frac{2\csc^3 v}{3} - \csc v + C \\\end{aligned}[/tex]
[tex]\displaystyle\begin{aligned}- \int {\bigg( w^4 - 2w^2 + 1 \bigg)} \, dw & = - \frac{(u^2 + 1)^\Big{\frac{5}{2}}}{5u^5} + \frac{2(u^2 + 1)^\Big{\frac{3}{2}}}{3u^3} - \frac{\sqrt{u^2 + 1}}{u} + C \\\end{aligned}[/tex]
Step 10: Integrate Pt. 9
Let's substitute our integral value into our integral from "Step 4":
[tex]\displaystyle\begin{aligned}\frac{1}{2} \int {\frac{1}{u^6 \sqrt{u^2 + 1}}} \, du & = - \frac{(u^2 + 1)^\Big{\frac{5}{2}}}{10u^5} + \frac{(u^2 + 1)^\Big{\frac{3}{2}}}{3u^3} - \frac{\sqrt{u^2 + 1}}{2u} + C \\& = - \frac{(x^4 + 1)^\Big{\frac{5}{2}}}{10x^{10}} + \frac{(x^4 + 1)^\Big{\frac{3}{2}}}{3x^6} - \frac{\sqrt{x^4 + 1}}{2x^2} + C \\& = \boxed{ - \frac{\sqrt{x^4 + 1}(8x^8 - 4x^4 + 3)}{30x^{10}} + C } \\\end{aligned}[/tex]
∴ we have found the indefinite integral.
___
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___
Topic: Calculus
In which of the following expressions does the number 2 fill in the blank so that the equation is true? Select all that apply.
A) 5(___ + 4) = 10 + 20
B) 9(3 + ___) = 27 + 18
C) 3(2 + 5) = ___ + 15
D) ___(5 + 6) = 10 + 12
Answer:
except c all
Step-by-step explanation:
because
5(2+4)=10+20
30=30
9(3+2)=27+18
45=45
2(5+6)=10+12
22=22
Answer:
except c all
Step-by-step explanation:
because
5(2+4)=10+20
30=30
9(3+2)=27+18
45=45
2(5+6)=10+12
22=22
two numbers are in the ratio of 10:16 if the sum of numbers is 572 find the numbers.
with steps
Answer:
yo dude dont be upset im doing what you did lol!
WILL GIVE BRAINLIEST 50 POINTS
1. Are the side lengths congruent?
2. Are the opposite sides parallel?
3. Are the adjacent sides perpendicular?
Answer:
1:If three pairs of sides of two triangles are equal in length, then the triangles are congruent. ASA (angle-side-angle): If two pairs of angles of two triangles are equal in measurement, and the included sides are equal in length, then the triangles are congruent. 2:All sides are equal in length. Diagonals bisect each other at a 90-degree angle. The sum of any two adjacent interior angles is 180 degrees. Opposite sides are equal and parallel to each other.3:Each pair of opposite sides is parallel, and adjacent sides are perpendicular. This means that every angle in a rectangle is a right (90∘) angle.
Step-by-step explanation:
Consider a triangle ABC like the one below. Suppose that A = 30°, B = 125°, and a = 38. (The figure is not drawn to scale.) Solve the triangle.
Round your answers to the nearest tenth.
If there is more than one solution, use the button labeled "or".
Answer:
C = 25°, b = 62.3, c = 32.1
Step-by-step explanation:
The Law of Sines can be used to solve a triangle when two angles and a side opposite one of them is given.
__
third angleThe angle sum theorem can be used to find the third angle.
C = 180° -A -B = 180° -30° -125° = 25°
__
unknown sidesThe Law of Sines tells you ...
a/sin(A) = b/sin(B) = c/sin(C)
b = a(sin(B)/sin(A)) = 38·sin(125°)/sin(30°) ≈ 62.3
c = a(sin(C)/sin(A)) = 38·sin(25°)/sin(30°) ≈ 32.1
The solution is ...
C = 25°, b = 62.3, c = 32.1
prove fermat's last theorem:no three positive integers a, b, and c satisfy the equation a^n + b^n = c^n for any integer value of n greater than 2
The proofing of Fermat's last theorem shows that y = a² - b², z = a² + b² and x = 2ab.
How to prove fermat's last theorem?The equation x² + y² = z². We can assume that x, y, and z are positive and relatively prime. Suppose that x is even. Then:
(z - y/2)(z + y/2) = (x/2)²
Hence,
(z - y)/2 = b²
(z + y)/2 = a²
Then, y = a² - b², z = a² + b² and x = 2ab.
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Please help me please please
Answer:
[tex]x \leqslant 4[/tex]
Goodluck
Step-by-step explanation:
X is smaller than or equal to 4
what is the inverse of the following function: y-x^3=3
Answer:
f^-1(x)=[tex]\sqrt[3]{x-3}[/tex]
Question 5 options:
Type right or left in the space.
17.2 is 17.2 units to the (right/left) of zero on the number line.
Answer:
17.2 is 17.2 units to the right of zero on the number line.
Step-by-step explanation:
On a number line positive numbers are on the right of 0 and negative numbers are one the left of 0.
Please mark brainliest :)
Answer: Right
Step-by-step explanation:
All positive numbers are to the right of zero on the number line.
All negative numbers are to the left of zero on the number line.
17.2 is a positive number, so;
17.2 is 17.2 units to the (right/left) of zero on the number line.
Which number line shows the N equality n <= -1?
Number line equality to -5< =< -1
Express this ratio as a fraction in simplest form. For homework, a student had to complete 15 problems total. If she finished 6 problems in class, what is the ratio of problems she still needs to complete to problems that she's already finished?
Answer:
3:2.
Step-by-step explanation:
They have 15 - 6 = 9 problems to do, so it is:
9:6
= 3:2.
Answer:
9/15
Step-by-step explanation:
15 - 6 = 9 as a fraction would be 9 meaning what is left and 15 as meaning how much they started with so it is 9/15 also called 9 over 15
Hope This Helped
Solve for x. Round to the nearest tenth.
What is the area of this rectangle?
52 sq ft
34 ft
42 sq ft
17 ft
Answer:
42 sq ft.
Step-by-step explanation:
[tex]A=w *l[/tex]
[tex]A=14 *3=42[/tex]
=42 sq ft
(note: i dont think it matters how you put the numbers, they still mulitply up to 42)
Hope this helped
~rere
This Diagram Shows a Regular Pentagon
Which of the following is not a type of electromagnetic radiation that telescopes can detect?
A. Microwave
B. Ultraviolet
C. Infrared
D. Heliocentric
Answer:
B I just got that question it was B
This figure represents an arrow painted on a walkway 12 times.
What is the area of the walkway that is painted with the 12 arrows?
70 cm²
90 cm²
840 cm²
1080 cm²
The area of the walkway that is painted with the 12 arrows will be 840 cm². Then the correct option is C.
What is Geometry?It deals with the size of geometry, region, and density of the different forms both 2D and 3D.
This figure represents an arrow painted on a walkway 12 times.
The figure is given below.
The figure is the combination of a triangle and a rectangle. Then the area of the figure will be
Area = 1/2 x 8 x 5 + 10 x 5
Area = 20 + 50
Area = 70 cm²
Then the area of the walkway that is painted with the 12 arrows will be
Area of the walkway = 70 x 12
Area of the walkway = 840 cm²
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Given that A, O & B lie on a straight line segment, evaluate obtuse ∠AOC.
The diagram is not drawn to scale. < AOC=
Answer:
∠ AOC = 124°
Step-by-step explanation:
the 3 angles lie on a straight line and sum to 180°
sum the 3 angles and equate to 180
3x + 94 + x + 30 + 2x - 4 = 180
6x + 120 = 180 ( subtract 120 from both sides )
6x = 60 ( divide both sides by 6 )
x = 10
Then
∠ AOC = 3x + 94 = 3(10) + 94 = 30 + 94 = 124°
The sum of three number is 99. The second number is 9 more than the first the third number is 4 times the second. What are you numbers?
Answer:
First Number=9
Second number=18
Third Number=72
Step-by-step explanation:
let's take the first number as X
X+(9+X)+[4(9+X)]=99
X+9+X+36+4=99
6X=99-45
X=54/6
X=9
A percent is a rate in which the first term is compared to ______
Answer:
From what we know about percentages and unit rates, the correct options are:
1) 100
2) 1
What is a percent?
Suppose we have an amount A, this would be the 100%.
If we want to know how much a quantity B represents, compared to A, we have:
A = 100%
B = x
where x is a percentage, to find the value of x we compute:
x = (B/A)*100%
While there is a dependence on A, we actually are comparing the term with 100 (because A represents a 100%), so the correct option is A: 100
PLS MARK ME AS THE BRAINLIST!!!
8. f^7 • f^1 (1 point)
A. f^8
B. f^7
C. (2f)^8
D. (2f)^7
Answer:f^8
Step-by-step explanation:
F^7 multiplied by F^1 =f (7+6+1)= f^8F
Complete the sentence to describe the triangle shown.
GHI is _____ and _____.
Evaluate 0.2x for x = 5.
A. 0.1
B. 1
C. 10
D. 0
What is the value of the expression?
Any help?
Answer:
32
Step-by-step explanation:
4 ÷ 1/8
make 4 into a fraction
4/1 ÷ 1/8
when dividing a fraction you change the divide into multiply and you flip the second fraction:
4/1 × 8/1 = 32
Answer:
32
Step-by-step explanation:
1/8 = 1 / 8 = 0.125 4 / 0.125 = 32
mad skillz gl cheating on your I-ready test
Solve for xxx.
Enter the solutions from least to greatest.
(-5x +4)(x -3)=0(−5x+4)(x−3)=0left parenthesis, minus, 5, x, plus, 4, right parenthesis, left parenthesis, x, minus, 3, right parenthesis, equals, 0
\text{lesser }x =lesser x=start text, l, e, s, s, e, r, space, end text, x, equals
\text{greater } x =greater x=start text, g, r, e, a, t, e, r, space, end text, x, equals
Then the two solutions of the quadratic equation are 4/5 and 3.
How to solve the equation?
Here we want to solve the quadratic equation:
(-5x + 4)*(x - 3) = 0
The two solutions are the values of x for which each parenthesis becomes equal to zero, so the two solutions are given by:
-5x + 4 = 0
x - 3 = 0
If we solve these two equations we get:
x = -4/-5 = 4/5
x = 3
Then the two solutions are 4/5 and 3.
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Elena is going to a farmer's market for fresh produce. She has two markets to
choose from and hopes to buy both cherries and asparagus. The table shows
the probability that each type of produce will be available at the markets.
North
South
market
market
Cherries
0.96
0.8
Asparagus
0.5
0.65
Assuming that the availability of cherries and the availability of asparagus are
independent of each other, which market should Elena choose to maximize
her chance of buying both?
O A. South market. There is a 0.77 probability of both cherries and
asparagus being available.
B. North market. There is a 0.77 probability of both cherries and
Elena should go to the south market because there is 0.52 probability of both cherries and asparagus being available.
How to determine the market to choose?The table is given as:
North market South market
Cherries 0.96 0.8
Asparagus 0.5 0.65
The probability of buying both produce at both markets is calculated as:
P(North) = 0.96 * 0.5 = 0.48
P(South) = 0.8 * 0.65 = 0.52
0.52 is greater than 0.48
Hence, Elena should go to the south market because there is 0.52 probability of both cherries and asparagus being available.
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A business serves 18 customers with 67 staff to maintain a strong ratio of staff to guests. How many staff members would be needed if 298 customers are expected?
Answer:
x = 67 *272 = 364.48 = 364 (rounded as requested).
Step-by-step explanation:
Use the proportion
50 = 272
67 x
Select the correct answer.
A machine uses pieces of tape to seal packages. It cuts the tape Into pieces exactly 2.375 Inches long. If It uses 4 pieces of tape for a package,
how many packages can it seal with a roll of tape 1,900 Inches long?
OA
200 packages
OB. 400 packages
OC 600 packages
OD.
800 packages
Answer:
A. 200 packages
Step-by-step explanation:
The number of packages per roll can be found by dividing the length of a roll by the length of tape needed for each package.
__
For each package:
(2.375 in/piece)×(4 piece/package) = 9.5 in/package
Per roll:
(1900 in/roll) / (9.5 in/package) = (1900/9.5) packages/roll
= 200 packages/roll
The machine can seal 200 packages with a roll of tape 1900 inches long.
Let f(x)=x-3 and g(x)= x^2-x. Find and simplify the expression. (f+g)(2)
Answer:
(f+g)(2) = 1Step-by-step explanation:
Given :
f(x) = x − 3
g(x) = x² − x
Note : (f+g)(x) = f(x) + g(x)
then
(f+g)(2) = f(2) + g(2)
= (2 - 3) + (2² - 2)
= -1 + 2
= 1
another method:
(f+g)(x) = f(x) + g(x) = x − 3 + x² − x = x² - 3
then
(f+g)(2) = 2² - 3 = 4 - 3 = 1
Find the sum of the whole numbers from 1 to 570
Answer:
162,735
Step-by-step explanation:
570(570 + 1)/2 = 162,735