Please help, im really confused. ill mark brainliest

Answer:

The metal is most likely Sodium.

Explanation:

Iron is not soft enough to be cut with a knife and will not react violently with water.  When Iron reacts with water it just slowly rusts.

Copper is somewhat malleable, however, does not really react with water and only forms an oxide layer in the air.

Sodium is soft enough to be cut with a knife (I know this because I have worked with it and seen people work with it).  It is also an alkali metal which are known to explode when in water.

Gold is malleable but does not really react with anything and is considered inert.

Answer:

70.98% is the mass percentage of bromine in the original compound

Explanation:

First, we need to convert mass of AgBr to moles with its molar mass (AgBr: 187.77g/mol). Moles of AgBr = Moles of Br. With molar mass of Br-: 79.904g/mol we can find mass of bromide and mass percentage as follows:

0.7514g AgBr * (1mol / 187.77g) = 0.00400 moles AgBr = Moles of Br-

0.00400 moles Br- * (79.904g / mol) = 0.320g Br- in the sample

Mass percentage is:

0.320g Br- / 0.4505g sample * 100

Answer:

what the heck what is that?

Explanation:

Answer:

oop whats dis

Explanation:

Answer:

Use a glass testtube

Insert a 1-hole stopper in which you insert a glass tube (use a bit of glycerine around the bottom end which makes it slip easier into the stopper)

Fill the testtube with colored water

Place rubber stopper

Make sure there are no air bubbles and that the column in the glass tube is low, as indicated

Place testtube assembly into water which you will heat (hot plate)

Observations

You will observe that the water column in the glass tube moves up as the temperature of the water in the testtube increases. With a 20 mL testtube, and a temperature change from 20 degrees C to 80 degrees C, you should get something like 15-20 cm of change in height.

What do YOU observe?

How do YOU explain your observation?

What is happening there?

Explanation

The water in the testtube expands as it is heated. There is only one direction to expand in, the glass tube. This glass tube is narrow so that a small change in volume will result in a considerable change in height; your signal is amplified.

This is the same phenomenon as in thermometers with a glass bulb on the lower end. Thermometers use a variety of liquids including alcohol (expands more than water) and mercury (is dangerous when spilled).

Explanation:

hope this helps

Answer:

Experiment 1:

What happens to the water in the small tube as the water in the test tube absorbs heat?

Answer: As the water in the test tube absorbs heat the water in the small tube continues to rise

Why do you think a small tube was used to observe the expansion of water?

Answer: The small tube was used to observe the expansion of water to show a visible change that could also be measure with a ruler

Experiment 2:

Compare the circumference of the balloon before and after freezing. What is the percent increase in this measurement?

Answer: The circumference of the balloon increased after it was put in the freezer. The measurement increased by about 5%, it started at 39.5cm then increased to 41.5cm

According to the data, an increase in temperature caused the water molecules to expand because it gained energy which caused it to move more rapidly ultimately resulting in an increase of volume of water. In addition, when being froze water expands making it less dense than the water from which it freezes, causing the volume to also increase. The difficulty I faced in this experiment is pinpointing the exact change in the waters expansion. Two real world issues are when icebergs float as a result of water freezing resulting in expansion, another one is the warming of Earth due to the heat-trapping from greenhouse gases. This heat is absorbed by oceans and seas causing the temperature to rise and the water to expand.

Explanation:

We are given:

The force applied on the poor hamster (F) = 12 N

Acceleration of the poor Hamster (a) = 8 m/s²

Solving for the mass of the Poor Hamster:

From newton's second equation of motion, we know that:

F = ma

replacing the given values

12 = 8 * m

m = 12/8 kg

m = 3/2 kg

The poor Hamster weighs 3/2 kg

Answer:

Hydrogen sulfide reacts with aqueous selenous acid to produce selenium disulfide:

H2SeO3 + 2 H2S → SeS2 + 3 H2O

Selenium disulfide consists of 8-membered rings. It has an approximate composition of SeS2, with individual rings varying in composition, such as Se4S4 and Se2S6. Selenium disulfide has been used in shampoo as an antidandruff agent, an inhibitor in polymer chemistry, a glass dye, and a reducing agent in fireworks.[15]

Selenium trioxide may be synthesized by dehydrating selenic acid, H2SeO4, which is itself produced by the oxidation of selenium dioxide with hydrogen peroxide:[17]

SeO2 + H2O2 → H2SeO4

Hot, concentrated selenic acid can react with gold to form gold(III) selenate.[18]

Answer:

.082 M

Explanation:

You just do C1V1=C2V2

The concentration of the potassium bitartrate acid is determined as 0.082 M.

The concentration of the potassium bitartrate acid is calculated as follows;

C1V1 = C2V2

where;

C2 = (C1V1)/(V2)

C2 = (0.055 x 8.2)/(5.5)

C2 = 0.082

Learn more about concentration here: https://brainly.com/question/17206790

#SPJ2

Water is oxidized and reduced at both electrodes

Electrolysis utilizes electrical energy to carry out non-spontaneous redox reactions. The ions in the solution flowed by an electric current will move toward the electrode opposite the charge.

The negative ions from the solution will move towards the positive electrode, and release electrons around the positive electrode (oxidation occurs) and electrons flow to the negative pole

While around the negative electrode electron binding occurs and a reduction reaction occurs

the reaction at the cathode:

1. the reduced active metal is water, other than that the metal will be reduced

2. H⁺ of the acid will be reduced

For reactions in anode:

1. if the electrodes are not inert then the metal is oxidized

2. If inert then:

a. OH⁻ from the base will be oxidized

b. The halogen metal will oxidize

2H₂O(l)+2e⁻⇒ H₂(g)+2OH⁻(aq)

2H₂O(l)⇒4H⁺(aq)+O₂(g)+4e⁻

Answer:

B. honey dissolving in tea

Explanation:

Answer:

deez

Explanation:

thx

Answer:

Atoms in the equation are already in balance

Explanation:

It's D

Answer: the focal point

Answer:

the higher the energy tje lower the wavelength

Explanation:

inverse relationship

Answer:

It's an example of an inverse relationship :)

Answer:

sharing of electrons between atoms

Answer:

3.58*10^-4kJ

Explanation:

Given

T1=23.0 °C

T2=100.0 °C

c=1.79 J/g·°C

Volume of olive =3 quarts

Converting to liter

1 quart =0.946353 L

3 quarts=x

Cross multiplying

x=0.946353*3

x=2.83L

To mL= 0.0028mL

We are given the density as 0.916 g/mL

Mass= density *volume

Mass= 0.916*0.0028

Mass=0.0026g

We know that the quantity of heat is expressed as

Q=mcΔT

Q=0.0026*1.79(23-100)

Q=0.004654*(77)

Q=0.358J

In kJ we divide 0.36 by 1000

=0.000358358

=3.58*10^-4kJ

Mass C₂H₂ needed : 22.165 g

Reaction

2C₂H₂+ 5O₂ ⇒ 4CO₂ + 2H₂O

75.0 grams of CO₂ , mol CO₂ (MW=44 g/mol) :

[tex]\tt \dfrac{75}{44}=1.705[/tex]

mol C₂H₂ :

[tex]\tt \dfrac{2}{4}\times 1.705=0.8525[/tex]

mass C₂H₂ (MW=26 g/mol) :

[tex]\tt 0.8525\times 26=22.165~g[/tex]

Answer:

Explanation:

Li+H2O..................LiOH+H2

mass of Li=17.8 g

No of moles of Li=17.8/7=2.5

mass of H2O=50.0 g

No of moles of H2O=50.0/18=2.8

limiting reagent is Li so 1 mole of Li produce 1 mole of LiOH therefore 2.5 mole of Li produce 2.5 moles of LiOH now we have to convert it into grams

moles=given mass/molar mass

given mass=moles*molar mass

molar mass of LiOH=24

mass=2.5*24=60 gram

Answer:

Viscosity is the measure of resistance of a fluid to flow. A fluid that is highly viscous has a high resistance (like having more friction) and flows slower than a low-viscosity fluid. To think of viscosity in everyday terms, the easier a fluid moves, the lower the viscosity

Explanation:

Answer:

KOH  molar mass = 39 + 16 + 1 = 56g

To make 1 L of 1M soln needs 56g KOH

To make 500mL 1M needs 56/2 = 28g

To make 500mL 0.2M needs 28 x 0.2gn:

Answer:

True

Explanation:

Answer:

because some things have a higher density than other things

Explanation:

Answer:

some things float bc they have air inside of them which makes them rise bc air rises and gravity pulls so theyre working against each other. some things sink bc theyre heavy and gravity is already pulling them down so them being heavy just makes them sink faster. hope this helps!!!

Explanation:

Answer:

15.14×10⁷ g

Explanation:

Given data:

Number of particles of NaCl = 1.56×10³⁰ particles

Mass of sodium chloride = ?

Solution:

The given problem will solve by using Avogadro number.

It is the number of atoms , ions and molecules in one gram atom of element, one gram molecules of compound and one gram ions of a substance.  The number 6.022 × 10²³ is called Avogadro number.

1 mole = 6.022 × 10²³ particles

1.56×10³⁰ particles × 1 mol / 6.022 × 10²³ particles

0.259 ×10⁷ mol

Mass in gram:

Mass = number of moles × molar mass

Mass = 0.259 ×10⁷ mol × 58.44 g/mol

Mass = 15.14×10⁷ g

Answer:proton,neutrons,and electrons.

Explanation:

Answer:

Question 2

5087.9 or 5088

Answer:

5.6 M

Explanation:

Given data:

Mass of C₆H₁₂O₆ = 25 g

Volume of solution = 25 mL (25 mL×1 L/1000 mL=0.025 L)

Molarity of solution = ?

Solution:

Molarity is used to describe the concentration of solution. It tells how many moles are dissolve in per litter of solution.

Formula:

Molarity = number of moles of solute / L of solution

Number of moles of C₆H₁₂O₆:

Number of moles = mass/molar mass

Number of moles = 25 g/ 180.16 g/mol

Number of moles = 0.14 mol

Molarity:

M = number of moles / volume in L

M = 0.14 mol/ 0.025 L

M = 5.6 M

Answer:

Common water treatment processes such as flocculation, sedimentation, filtration and disinfection are employed to remove general impurities such as floating and suspended matters, colloidal particles, dissolved organic matter and destruction of disease-causing microorganisms (pathogens).

Explanation:

Answer:

a. W = 5,708 J, Q = 5,708 J, ΔU = 0 and ΔH = 0.

b. 2,231 J.

Explanation:

Hello!

a. In this case, since this is an isothermal process (constant temperature) it is possible to infer that the work is computed as shown below:

[tex]W=nRTln(\frac{p_1}{p_2} )=1mol*8.314\frac{J}{mol*K}*298.15Kln(\frac{10.bar}{1.0bar} )\\\\W=5708J[/tex]

Now, since this is an isothermal process we know by definition ΔU = 0 and ΔH = 0, therefore the involved heat is:

[tex]Q-W=0\\\\Q=W=5708J[/tex]

b. In this case, since the process is isobaric but goes to the same final volume in part a, we can compute the initial and final volume based on the part a's conditions by using the ideal gas equation:

[tex]V_1=\frac{nRT}{p_1} =\frac{1mol*0.083145\frac{*L}{mol*K}*298.15K}{10.bar} =2.48L\\\\V_2=\frac{nRT}{p_2} =\frac{1mol*0.083145\frac{*L}{mol*K}*298.15K}{1.bar} =24.8L[/tex]

Thus, the work done here is:

[tex]W=p(V_2-V_1)=1bar(24.8L-2.48L)=22.3bar*L*\frac{1x10^5Pa}{1bar} *\frac{1m^3}{1000L} \\\\W=2231J[/tex]

Best regards!