Answers
180-77=103
so then simplify (6x-17)=103
6x=120
x=20
Related Questions
Calculate the distance between point B (3,-7) and point C (0,8) on the coordinate grid
Answers
Answer:
Distance= 15.3
Step-by-step explanation:
x d
Students in an Introductory Statistics class at BYU-Idaho were studying prices of cold cereal at grocery stores in Rexburg. To get a sample of cold cereal prices, they went to Albertson's and rolled a die to decide which box from the left of the top shelf they would start on. They then recorded every 6th cereal after the first, moving from left to right down the shelves, recording the name, size, and price of each cereal in their sample. Is this study an experiment or an observational study, and why
Answers
Answer: Observational study
Step-by-step explanation:
The study illustrated in the question is an observational study. It is referred to as an observational study, because in this case, the price of the individual cereals us not being controlled by the students. They've no control over it.
If it was an experiment, there'll have been a control group and the students will have control over the price. Also, the sampling methods used here is a systematic random sampling.
Verify the following properties of the Fourier transform 1. (Fu)(E) = 27 (F-\u) (-) 2. (F(t,0)) (E) - (FU)(8 + a)
Answers
The properties of the Fourier transform stated in (1) and (2) are incorrect.
How to find that are the given properties of the Fourier transform (1) and (2) accurate?The properties of the Fourier transform stated in (1) and (2) are incorrect.
Let's examine each property:
(1) (Fu)(E) = 27 (F-\u) (-):
The expression on the left side, (Fu)(E), represents the Fourier transform of a function u evaluated at frequency E.
However, the expression on the right side, 27 (F-\u) (-), is not a valid representation of the Fourier transform.
The notation (F-\u) (-) is unclear and does not align with the standard conventions of the Fourier transform.
(2) (F(t,0))(E) - (FU)(8 + a):
Similarly, the expression on the left side, (F(t,0))(E), suggests the Fourier transform of a function F evaluated at time t and frequency E.
However, the subtraction of (FU)(8 + a) is not a well-defined operation in the context of the Fourier transform. The relationship between F(t,0) and FU is not clear, and the addition of 8 + a lacks proper justification.
Therefore, both properties (1) and (2) provided for the Fourier transform are inaccurate.
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PLSSSSSS HELPPPPP PLS I NEED HELPPP PLSS
Let equal the price of one smoothie. Complete the equation.
(5 smoothies) (price of 1 1 Smoothie)+tip= $23
Answers
Answer:
5x+3=23
Step-by-step explanation:
Answer:
$4 per smoothie
Step-by-step explanation:
5x+4=23
How do you expand (4x+2)2
Answers
Answer:
=8x+4
Step-by-step explanation:
=2(4x+2)
a=2,b=4x,c=2
=2 x 4x + 2 x 2
Simplify- 2 x 4x + 2 x 2: 8x + 4
use spherical coordinates. evaluate ∭E (x² + y²) dv, where e lies between the spheres x² + y² + z² = 9 and x² + y² + z² = 16.
Answers
The value of ∭E (x² + y²) dv over the region E between the given spheres.
To evaluate the integral ∭E (x² + y²) dv using spherical coordinates, we first need to express the volume element dv in terms of spherical coordinates.
In spherical coordinates, the volume element is given by dv = r² sin(φ) dr dφ dθ, where r represents the radial distance, φ represents the polar angle, and θ represents the azimuthal angle.
Since we are integrating over the region E between the spheres x² + y² + z² = 9 and x² + y² + z² = 16, the limits of integration for r, φ, and θ will be as follows:
r: from the lower sphere to the upper sphere, which corresponds to r = 3 to r = 4
φ: from 0 to π (since we are considering the entire range of polar angle)
θ: from 0 to 2π (since we are considering the entire range of azimuthal angle)
Now, let's substitute these values and evaluate the integral:
∭E (x² + y²) dv = ∭E (r² sin(φ) cos²(θ) + r² sin(φ) sin²(θ)) dr dφ dθ
Integrating over θ from 0 to 2π, and integrating over φ from 0 to π, we have:
∭E (x² + y²) dv = ∫[0,2π] ∫[0,π] ∫[3,4] (r² sin(φ) cos²(θ) + r² sin(φ) sin²(θ)) dr dφ dθ
Now, we can evaluate the integral by performing the integration step by step, starting from the innermost integral.
After evaluating the integral, the final result will give us the value of ∭E (x² + y²) dv over the region E between the given spheres.
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Answers
Answer:
Function 1 has the greatest rate of change.
Step-by-step explanation:
The rate of change is also known as the slope.
Slope is rise over run: change in y over change in x.
Function 1's slope: 3 / 2
Function 2's slope: (0 - (-4)) / (5 - (-5)) = 4/10 = 2/5
3/2 > 2/5
Function 1 has the greatest rate of change.
Find 8.76 - 10.91. Write your answer as a decimal.
Answers
Answer:
-2.15
Step-by-step explanation:
Plug it into the calculator and it should give you the same answer.
Answer:
The answer is -2.15.
Step-by-step explanation:
Hope this helped Mark BRAINLIEST!!!
Describe the translation in each function as it relates to the graph of f(x) = x.
g(x)=x-5
Answers
Answer:
f(x) was translated to the left by 5 units to form g(x)
Step-by-step explanation:
Given the function f(x) = x to g(x)=x-5, if you look at the g(x) function, you will see that 5 was subtracted from the abscissa x that is;
g(x) = f(x) - 5
This shows' that the function f(x) was translated to the left by 5 units to form g(x). This described the required translation
What is the surface area of the right prism below?
A. 360 sq. units
B. 384 sq. units
C. 432 sq. units
D. 336 sq. units
Answers
The surface area of the right prism cone is,
⇒ 1960 units²
What is Multiplication?To multiply means to add a number to itself a particular number of times. Multiplication can be viewed as a process of repeated addition.
Given that;
A right prism shown in image.
Now, We get;
Base area of cone = 14 x 10
= 140
And, Height of cone = 6
And, Perimeter of the base = 2 (10 + 14)
= 280
Thus, WE know that;
The surface area of the right prism cone is,
⇒ 2B + hP
⇒ 2 × 140 + 6 × 280
⇒ 280 + 6 × 280
⇒ 280 + 1680
⇒ 1960 units²
Thus, The surface area of the right prism cone is,
⇒ 1960 units²
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Q5. If X represents the shear strength of 3/8-inch anchor bolts, the sample size is 78, the sample mean i = 4.25, s = 1.30, and u represents the true share strength. a. Find the 2-sided 90% confidence interval for u. b. Compute a 90% confidence lower bound for u.
Answers
The 90% confidence lower bound for u is: u>4.066
To find the confidence intervals for the true shear strength u, we will use the sample mean, sample standard deviation, and the given sample size.
a. Two-Sided 90% Confidence Interval for u:
The formula for the confidence interval is given by:
x' = z × s/√n < u < x' +z × s/√n
Where:
x' is the sample mean (given as 4.25)
s is the sample standard deviation (given as 1.30)
n is the sample size (given as 78)
z is the z-score corresponding to the desired confidence level (90% confidence level has z-score of 1.645)
Plugging in the values and simplifying:
4.25 - 0.184 < u < 4.25 + 0.184
Therefore, the 2-sided 90% confidence interval for u is:
4.066 < u < 4.434
b. 90% Confidence Lower Bound for u:
The formula for the confidence interval lower bound is given by:
x' - z × s/√n < u
Plugging and simplifying the values we get:
Simplifying the expression:
4.25 - 0.184 < u
Therefore, the 90% confidence lower bound for u is:
u > 4.066
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Does the boxplot represent the information given in the histogram?
A) Yes
B) No, the boxplot should be skewed right
C) No, the median should be in the middle of the box
D) No, the left whisker should extend to zero
E) No, the right whisker should extend to 55
Answers
To determine whether the boxplot represents the information given in the histogram, we need to examine the characteristics of both the boxplot and the histogram.
The boxplot provides a visual representation of the distribution of a dataset, showing the minimum, first quartile, median, third quartile, and maximum values. It also displays any outliers that may be present. On the other hand, a histogram provides a graphical representation of the frequency or count of data values within specified intervals or bins.
Without specific information or visuals of the boxplot and histogram in question, it is not possible to directly compare them and determine their compatibility. Therefore, it is not possible to answer the question based on the information provided.
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A car can go 35 1/2 miles in 1 1/2 miles gallons. How many gallons does a car need to go 639 miles?
Need work please!!
Answers
Answer: 27 gallons
Step-by-step explanation:
Since the car can go 35½ miles in 1½ miles gallons, we need to first calculate the number of miles that the car can go in 1 gallon. This will be:
= 35½ / 1½
= 71/2 / 3/2
= 71/2 × 2/3
= 23⅔ miles per gallon.
Therefore, the amount of gallons that the car need to go 639 miles will be:
= 639 / 23⅔
= 639 ÷ 71/3
= 639 × 3/71
= 27
The car will need 27 gallons.
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Answers
Answer: 13
Step-by-step explanation: the square root is 12.68925
so i rounded up to 13
Answer:
12.6885775404 or 13 if you need to round up
Step-by-step explanation:
Increasingly, developers are using tools that can quickly create screen mockups, referred to as element. A) Protoypes B) Wireframes C) Forms D) Reports
Answers
Increasingly, developers are using tools that can quickly create screen mockups, referred to as element Wireframes
Wireframes:Wireframes is a type of tool which is allow designers to quickly and effectively mock up an outline of a design as easily as possible. Designers easily drag the images and drop to placeholder images , header and content also.
There are three types of wireframes, which is very useful :
Low-fidelity wireframes.Mid-fidelity wireframes.High-fidelity wireframes.Wireframes generally is used for visual designer, developer, business analysts, user experience designers and information architecture and user research.
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What is -a-2 if a = -5?
Answers
Answer:
3
Step-by-step explanation:
-(-5) -2
5 - 2
3
Answer:
-7
Step-by-step explanation:
-a - 2 = -5 + -2 (different sign- keep the first number same, change the sign to addition and the additive inverse of the second number) -5 + -2 = -7Hope this helps
which expression is not equvialet to 28ax
Answers
2(19-7) im pretty sure
the bar graph shows the approximate average rainfall for different cities in Texas compare the total inches of rainfall to the average annual rainfall in san Antonio ?
Answers
Answer:
I don't know
Step-by-step explanation:
I don't know
a rectangular window dimensions areX by X +2 and window has a 3 inch frame all the way around the total area of the window and frame is 195 in
Answers
Answer:
Length of window = 9 inch
Width of window = 7 inch
Step-by-step explanation:
Given;
Area of window and frame = 195 inch²
Frame width = 3 inch
Length of window = x + 2
Width of window = x
Find:
Value of x
Computation:
Length of window and frame = x + 2 + 3 + 3
Length of window and frame = x + 8
Width of window and frame = x + 3 + 3
Width of window and frame = x + 6
Area of window and frame = (l)(b)
(x + 8)(x + 6) = 195
x² + 6x + 8x + (8)(6) = 195
x² + 14x + 48 = 195
x² + 14x - 147 = 0
x² + 21x - 7x - 147 = 0
x(x + 21) - 7(x + 21) = 0
So,
x + 21 = 0 and x - 7 = 0
So,
X = 7
Value of x = 7
Length of window = 9 inch
Width of window = 7 inch
11. The ages (in years) of 11 children and the number of words in their vocabulary. Find the correlation coefficient r.
Age, x
1
2
3
4
5
6
3
5
2
4
6
Vocabulary size, y
3
220
540
1100
2100
2600
730
2200
260
1200
2500
Answers
Exercises for Data Analytics Exercise Sheet-4 The fourth exercise is about linear regression. (4.1) Use "airquality" data set which provides air quality measurements in New York. (a) Identify variables which are strongly/weakly positively/negatively correlated. (b) Use t test and check if temperature is significantly different from 79. (c) Split the data into sample A with observations 1 to 77 and sample B with observations 78 to 153. Use t test and check if temperature is significantly different between samples A and B.
Answers
a) Variables strongly/weakly positively/negatively correlated in the "airquality" data set can be identified through correlation analysis.
b) The t-test can be used to check if the temperature variable in the "airquality" data set is significantly different from 79.
c) The t-test can be used to check if the temperature variable is significantly different between samples A and B (observations 1 to 77 and 78 to 153, respectively) in the "airquality" data set.
How to find the correlation analysis and t-tests applied to the "airquality" data set for variable identification and significance testing?a) To identify variables that are strongly/weakly positively/negatively correlated in the "airquality" data set, correlation analysis can be performed.
Correlation analysis measures the strength and direction of the linear relationship between variables.
By calculating correlation coefficients (such as Pearson's correlation coefficient), it is possible to determine if variables have a strong positive correlation (close to +1), weak positive correlation (between 0 and +1), strong negative correlation (close to -1), or weak negative correlation (between 0 and -1).
This analysis helps identify the nature of the relationships between variables in the dataset.
b) To check if the temperature variable in the "airquality" data set is significantly different from 79, a t-test can be conducted.
The t-test assesses whether the mean of a sample is significantly different from a hypothesized value (in this case, 79).
By comparing the t-statistic calculated from the sample data to the critical t-value at a given significance level, such as 0.05, it can be determined if the temperature is significantly different from 79.
If the calculated t-value falls outside the critical t-value range, the temperature variable is considered to be significantly different.
c) To check if the temperature variable is significantly different between samples A (observations 1 to 77) and B (observations 78 to 153) in the "airquality" data set, a t-test can also be used.
This comparison aims to determine if the means of temperature in samples A and B are significantly different.
By calculating the t-statistic and comparing it to the critical t-value at a chosen significance level, such as 0.05, it can be determined if the temperature variable differs significantly between the two samples.
If the calculated t-value falls outside the critical t-value range, it indicates a significant difference in temperature between samples A and B.
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5.
A. never
B. not enough information provided
C. sometimes
D. always
Answers
Answer:
Step-by-step explanation:
The correct answer is Always
kason11wd and 2 more users found this answer helpful
THANKS
1
4.0
(1 vote)
1
the correct answer was never. I appreciate your answer though.
.............................................................................................................................................................
P(A and B) means add A and B
if both A and B are both greater then 1/2
then when they are added they will always be greater than 1
bolivianouft and 2 more users found this answer helpful
THANKS
1
5.0
(1 vote)
1
the correct answer was never. I appreciate your answer though.
Answer:The correct answer is Always
What is the value of x?
Enter your answer in the box.
Answers
Answer:
the answer is 4
Step-by-step explanation:
This question: 1 point possible Submit test of the Serples of DNA are collected, and the four DNA bases of A, G, C, and Tare coded as 1, 2, 3, and 4, respectively. The results are listed below. Construct a % confidence interval imate of the mean What i confidence interval) 2.2.1.3.4.3.4.3.31 What is the confidence interval for the population meon ? Round to one decimal place as needed) What is the practical use of the confidence interval? Select the correct choice below and necessary, it in the answer boxes to complete your choice OA The confidence interval can be used to estimate that, with 99% confidence, the interval from to actuality contains the true mean DNA base of all people (Round to one decimal place as needed) OB. The given numbers are just subetties for the four DNA base names, so the numbers do not measure or court anything, and they are at the nominal level of measurement. The confidence interval has no practical u OC The confidence interval can be used to estimate that 99% of all people have DNA bases between and (Round to one decimal place as needed.) Next MacBook Air & 7 Statcrunch W E 4 He R % 5 T 6 29 U .00 8 1 9 17
Answers
The confidence interval for the population mean would be 1.8 < u < 3.4.
The practical use of the confidence interval is this: A The confidence interval can be used to estimate that, with 99% confidence, the interval from to actuality contains the true mean DNA base of all people.
What is the confidence interval?The confidence interval expresses the probability that a given population parameter will be centered between a set of values. So, the practical use of the confidence interval is to indicate that if the experiment is repeated 100 times, 99 of those times will give a result that shows that the true mean of all people falls within the obtained values.
The confidence interval is obtained thus: μ ± Ζ s/√n
where μ = sample mean
Z = confidence level
s = standard deviation
n = sample size
From the question DNA samples or n = 10
Critical value = 2.262
Sample mean = 2.6
Standard deviation = 1.0749
The margin of error = 2.262 * 1.0749/√10
= 0.769
We can construct the 95% confidence level interval as follows:
x bar - E < u < x bar + E
= 2.6 - 0.7690 < u < 2.6 + 0.7690
= 1.8 < u < 3.4.
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A retired couple supplement their income by making fruit pies, which they sell to a local grocery store. During the month of September, they produce apple and grape pies. The apple pies are sold for $4.50 to the grocer, and the grape pies are sold for $3.60. The couple is able to sell all of the pies they produce owing to their high quality. They use fresh ingredients. Flour and sugar are purchased once each month. For the month of September, they have 2,100 cups of sugar and 3,000 cups of flour. Each apple pie requires 1½ cups of sugar and 3 cups of flour, and each grape pie requires 2 cups of sugar and 3 cups of flour. a. Determine the number of grape and the number of apple pies that will maximize revenues if the couple working together can make an apple pie in 6 minutes and a grape pie in 3 minutes. They plan to work no more than 60 hours b. Determine the amounts of sugar, flour, and time that will be unused. (Leave no cells blank - be certain to enter "0" wherever required. Round your intermediate calculations and final answers to the nearest whole number.
Answers
By plugging in the values of x and y obtained from the linear programming solution, we can calculate the unused amounts of sugar, flour, and time.
To determine the number of grape and apple pies that will maximize revenues, we can use linear programming. Let's set up the problem:
Let x be the number of apple pies produced.
Let y be the number of grape pies produced.
Objective function:
Maximize Revenue = 4.50x + 3.60y
Constraints:
1.5x + 2y ≤ 2100 (sugar constraint)
3x + 3y ≤ 3000 (flour constraint)
6x + 3y ≤ 60*60 (time constraint, converting hours to minutes)
The problem can be solved using linear programming software or a graphing calculator. The optimal values for x and y will provide the number of apple and grape pies that maximize revenue.
Regarding part b, to determine the amounts of sugar, flour, and time that will be unused, we can compare the amount used with the amount available.
Unused Sugar = 2100 - (1.5x + 2y)
Unused Flour = 3000 - (3x + 3y)
Unused Time = (60*60) - (6x + 3y)
By plugging in the values of x and y obtained from the linear programming solution, we can calculate the unused amounts of sugar, flour, and time. Remember to round the final answers to the nearest whole number.
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Can you please help me?
Answers
Answer:
-3, -4, -4, 0, 16, 64, 192.
Step-by-step explanation:
I don't know for sure if this is correct, but when i did it theses are the answers i got. You do y=8*2^x. Meaning you substitute the x for the x values such as -3, -2, and -1.
Also if you have one there's a setting you can go to on an actual calculator and type in this on a Y/X chart. I didn't use one this time because i don't have one, but thought you'd find that information useful.
Please help me with the answer!!!
Answers
5x = 7x - 8
7x - 5x = 8
2x = 8
x = 8 ÷ 2
x = 4
2
(
3
r
+
4
)
−
3
(
r
+
1
)
=
11
Answers
Hey there!
ASSUMING
2(3r + 4) - 3 (r + 1) = 11
IF SO
2(3r + 4) - 3 (r + 1) = 11
2(3r + 4) - 3 (1r + 1) = 11
DISTRIBUTE
2(3r) + 2(4) - 3(1r) - 1(1) = 11
6r + 8 - 3r - 1 = 11
COMBINE the LIKE TERMS
(6r - 3r) + (8 - 3) = 11
6r - 3r + 8 - 3 = 11
3r + 5 = 11
SUBTRACT 5 to BOTH SIDES
3r + 5 - 5 = 11 - 5
SIMPLIFY!
3r = 11 - 5
3r = 6
DIVIDE 3 to BOTH SIDES
3r/3 = 6/3
SIMPLIFY!
r = 6/3
r = 2
Therefore, the answer should be: r = 2
Good luck on your assignment & enjoy your day!
~Amphitrite1040:)
Given the data 4, y, 9, 5, 2, 7. Find y if the mean is 5
Answers
Answer:
3
Step-by-step explanation:
(4+y+9+5+2+7)/6=5
(27+y)/6=5
Y=3
a child who is 44.39 inches tall is one standaer deviation above the mean. what percent of children are between 41.25 aand 44.29 inches tall?
Answers
A child who is 44.39 inches tall is one standard deviation above the mean. Approximately 50.58% of children are between 41.25 and 44.29 inches tall.
To find the percentage of children between 41.25 and 44.29 inches tall, we need to calculate the area under the normal distribution curve within this range.
Given that the child's height of 44.39 inches is one standard deviation above the mean, we can infer that the mean height is 44.39 - 1 = 43.39 inches.
Next, we need to determine the standard deviation. Since the child's height of 44.39 inches is one standard deviation above the mean, we know that the difference between the mean and 41.25 inches is also one standard deviation.
Let's denote the standard deviation as σ. We have:
43.39 - 41.25 = σ
Simplifying the equation:
σ = 2.14
Now, we can calculate the percentage of children between 41.25 and 44.29 inches tall using the z-scores.
The z-score formula is given by:
z = (x - μ) / σ
For the lower bound, x = 41.25 inches:
z₁ = (41.25 - 43.39) / 2.14 = -0.997
For the upper bound, x = 44.29 inches:
z₂ = (44.29 - 43.39) / 2.14 = 0.421
We need to find the area under the normal distribution curve between z₁ and z₂. Using a standard normal distribution table or a calculator, we can find the corresponding probabilities.
Let P₁ be the probability associated with z₁, and P₂ be the probability associated with z₂. Then, the percentage of children between 41.25 and 44.29 inches tall is given by:
Percentage = (P₂ - P₁) * 100
Using the z-score table or a calculator, we find that P₁ ≈ 0.1587 and P₂ ≈ 0.6645.
Substituting these values into the formula:
Percentage = (0.6645 - 0.1587) * 100 ≈ 50.58%
Therefore, approximately 50.58% of children are between 41.25 and 44.29 inches tall.
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