Please help!!! And show your work or not I don’t care I need the answers

To find the answer to this problem, you will need to use the Pythagorean Theorem.

What is the Pythagorean Theorem?

The Pythagorean Theorem is an equation that represents the summation of the sides of a right triangle.

a² + b² = c², where a is the shortest leg of the triangle, b is the longest leg and c is the hypothenuse.

You have been given a (12) and b (16)

First, plug your given information into the equation: 12² + 16² = c²

Next, simplify your equation by squaring both terms:

12² = 144

16² = 256

Then, add these two answers together: 144+ 256= 400

This leaves you with the equation: 400 = c²

To isolate the c as an individual term, take the square root of both sides:

          [tex]\sqrt{400} = \sqrt{c^{2} }[/tex]

The above equation leaves you with the answer 20 = c, which is the hypothenuse

The height of the drone would be about 132.92 feet.

What is a tangent ratio in trigonometry?

The tangent ratio is the ratio of the opposite side to the adjacent side of a right triangle. Same to the sine and cosine ratios, tangent ratios can be used to calculate the angles and sides of right-angle triangles.

Given that the angle of elevation from the first and second base to the drone is 77° 9' and 65° 45' 18", respectively.

[tex]77^o9'=77\frac{9}{60}=77.15^o[/tex]

[tex]65^o 45' 18"=65+\frac{45}{60}+\frac{18}{3600}\\\\65^o 45' 18"=65.755^o[/tex]

tan 77°9 = h/AD        and        tan 65.75°=h/DB

AD + DB = 90

h/tan 77°9 + h/65.75° = 90

Solving this we get

h ≈ 132.92 feet.

Hence, the height of the drone would be about 132.92 feet.

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Answer:

Step-by-step explanation:

Due to the cast of the shadow regardless of that the line will still be 11 feet due to the lines length

On solving the provided question, we got that - The maximized value of the objective function is 38

Relationships between a group of inputs and one output per input are referred to as functions. A function is, to put it simply, a connection between inputs that are all connected to the same output. There is a domain and a codomain, or scope, for every function.

Given is the objective function:

Max P = 5x + 3y

The following are the constraints:

3x + 6y ≤ 48

2x + 8y ≤ 56 \sx ≥ 0 y ≥ 0

We employ the graphical method to achieve this.

The graph of the constraints is included as an attachment.

The graph leads us to the following doable point:

[tex](x,y) = (4,6)[/tex]

[tex]Substitute 4 for x and 6 for y in the objective function.\\Max P=5x+3y[/tex]

so,

[tex]P = 5x4+x6\\P = 38[/tex]

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The value of a and b for the given polynomial function f(x)=(x-a)(x-b) are a= -1, 2 and b=2, -1.

A function is said to as polynomial when a variable in an equation, such as a quadratic equation or cubic equation, etc., has only positive integer exponents or non-negative integer powers. For instance, the polynomial 2x+5 has an exponent of 1. The zero polynomial function, linear polynomial function, quadratic polynomial function, and cubic polynomial function are the four most common types of polynomials in precalculus and algebra.

Given,

f(x)=(x-a)(x-b)

From the above graph, f(x) passes through points (2, 0), (-1, 0), (0, -2)

Let us take (2, 0)

(2-a)(2-b)=0

4-2b-2a+ab=0

(-1, 0)⇒(-1-a)(-1-b)=0

1+b+a+ab=0

(0, -2)⇒-2=(-a)(-b)

ab= -2

a= -2/b

4-2b-2a-2=0

-2a-2b+2=0

a+b-1=0

b²-2b+b-2=0

b(b-2)+1(b-2)=0

b= 2 or b= -1

a+2-1=0

a= -1

a-1-1=0

a=2

The value of a and b for the given polynomial function f(x)=(x-a)(x-b) are a= -1, 2 and b=2, -1.

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Answer: second and third from the top right

Step-by-step explanation: 1:2 and 1 to 2 are the same thing, and are ratios. The rest of the answers have nothing to do with ratios.

Answer: -2

Step-by-step explanation:

Slope is rise/ run or y2 - y1 / x2 - x1

We see that y goes down by 6, and x go over by 3

So slope is -6/3 = -2

Answer:

Yes

Step-by-step explanation:

Since the point is in the intersection area (purple) of the lines it is a solution.

∠2 is congruent to ∠6 based on corresponding angle theorem.

So here ,

Since in this question they are corresponding angles of parallel lines cut by a transversal, they are ∠2 ≅ ∠6 according to the Vertical Angles Theorem.

The complete question is : "Lines c and d are parallel lines cut by transversal p. Horizontal and parallel lines c and d are cut by transversal p. On line c where it intersects with line p, 4 angles are formed. Clockwise, from uppercase left, the angles are: 1, 2, 3, 4. On line d where it intersects with line p, 4 angles are formed. Clockwise, from uppercase left, the angles are: 5, 6, 7, 8. Which must be true by the corresponding angles theorem?"

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a. In order to factor the equation, the vertex form needs to be expanded to the standard form first, to obtain the factors of the equation

b. The parabola is easily graphed with the information on the vertex given in the vertex form of the quadratic equation

c. The vertex, minimum or maximum of the parabola are easily obtained in the vertex form of the quadratic equation

d. The quadratic formula is defined based on the standard form of the quadratic equation

Answer:

[tex]\huge{\boxed{\text{A) Standard form}}}\\\huge{\boxed{\text{B) Vertex Form}}}\\\huge{\boxed{\text{C) Vertex Form}}}\\\huge{\boxed{\text{D) Standard Form}}}\\[/tex]

Step-by-step explanation:

Vertex form is represented as: [tex]f(x) = a(x-h)^2+k[/tex], where the vertex of the parabola is (h, k).

Standard form is represented as [tex]f(x) = ax^2+bx+c[/tex], where a, b, and c are constants.

A) When factoring an equation, the sum of the roots is equal to b and the sum of the roots is equal to c, meaning standard form is the beneficial.

B) When graphing a parabola, vertex form is extremely beneficial, as it provides the vertex of the parabola, and the direction in which it opens.  If "a" is positive, the vertex opens upward, while when "a" is negative, the vertex opens downward.  As such, graphing is greatly eased with this information.

C) As is evident from the name, vertex form is the best for identifying the vertex of a parabola, as it is explicitly shown via the constants h and k.

D) The quadratic formula directly uses the constants a, b, and c, so working in standard form is more beneficial, as it removes the effort of solving for each constant.

Hope it helps :) and let me know if you want me to elaborate.

Hypothesis test used to test the batting average of the two given team national league and American league is given z-test.

As given in the question,

Given : Mean batting for American league is not equal to Mean batting for National league.

Therefore, hypothesis test used to test the batting average of the national league and American league is given z-test.

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The value of the given logarithmic expression is -142.20.

In mathematics, an expression is defined as a set of numbers, variables, and mathematical operations formed according to rules dependent on the context.

Given the logarithmic values as,

log₃ (t) = 5.44

log₃ (y) = 11.03

log₃ (z) = 7.74

Now, the value of the expression can be written as,

12 log₃ (z⁷ / y⁵t²)

= 12 { log₃ (z⁷) - [ log₃ (y⁵) + log₃ (t²) ] }

= 12 { 7log₃ (z) - [ 5log₃ (y) + 2log₃ (t) ] }

= 12 [7×7.74 - (5×11.03 + 2×5.44)]

= 12 [ 54.18 - (55.15 + 10.88)]

= 12(54.18-66.03)

= 12 × (-11.85)

= -142.20

Hence, the value of the given expression is -142.20.

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Answer: 2

Step-by-step explanation:

[tex]\frac{8}{9} \approx 1\\\\\frac{9}{10} \approx 1\\\\\therefore \frac{8}{9}+\frac{9}{10} \approx 1+1=2[/tex]

Answer:

7

Step-by-step explanation:

Answer:7

Step-by-step explanation:

Go to 6 on the x value and then follow that line up until you reach the purple line. Then go to the left and see what the y vaule is(Height)

Answer:

Step-by-step explanation:

la première planche = 2x

la deuxième = x

la troisième = x-10

1ere planche + 2eme planche + 3eme planche = 50 pouces

donc :

(2x) + x + (x-10) =50

4x-10 = 50

4x-10+10 = 50 +10

4x = 60

4x diviser par 4 = 60 diviser par 4

x=15

la première planche = 30

la deuxième = 15

la troisième = 5

30+15+5=50

Simple random sampling is a sort of probability sampling in which a subset of participants from a population is randomly chosen by the researcher. There is an equal opportunity for selection for every person in the population. Then, information is gathered from as much of this random subset as is feasible.

What is simple random sampling, and why is it significant?

One technique researchers employ to select a sample from a broader population is a simple random sampling.

                               If there is an equal chance that any subject in a population will be chosen, this strategy is effective. In order to draw general conclusions about a group, researchers choose basic random sampling.

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Answer:

The sequences below is geometric sequences. 8,16,32

Step-by-step explanation:

It is geometric as far as it goes.

Notice that the ratio between each successive pair of terms is constant:

4/2=2

8/4=2

16/8=2

That these ratios are all the same is sufficient for the given terms to form a geometric sequence with general term:

an=[tex]2^{n}[/tex]

The sequence then continues:

2

,

4

,

8

,

16

,

32

,

64

,

128

,

256

,

512

,

1024

,

2048

,

...

The question is in the "...". Any finite number of terms does not determine an infinite sequence.

For example we can match the sequence  

2

,

4

,

8

,

16

 with a cubic polynomial:

[tex]a_{n}[/tex]=1/3([tex]n^{3}[/tex] -3[tex]n^{2}[/tex] +8n)

Then we would find that the next terms would be  

30

,

52

,

84

,

.

the second 4 11 ,17 is wrong

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The lengths of the parts of the median lines FA, BE, CD, that extends from the vertices of the triangle ΔACE to the midpoints of the sides EC, AE, and AC are;

A. G is called the centroid of the triangle ΔACE

B. G is also the center of gravity of a uniform density triangle. The correct option is True; T

C. GF = 5

D. DC = 18

E. GB = 7

A median of a triangle is a line segment that extends from a vertex of a triangle to the midpoint of the side opposite the vertex

The midpoints of the sides of the triangle = F, B, and D

The midpoint of EC = F

The midpoint of AC = B

Midpoint of AE = D

A. The lines CD, BE, and FA are called median lines

The point of intersection of the three median lines of a triangle is the centroid of the triangle.

B. The centroid of a triangle and center of gravity of the triangle are located at the same position in a uniformly dense triangle, therefore, G is the center of gravity, True, T

C. In the relationship of a median, we get;

AG = (2/3)·FA

GF =  (1/3)·FA

Therefore, AG = 2·(GF)

GF = 0.5 × AG

GF = 0.5 × 10 = 5

GF = 5

D. DG = (1/3) × DC

Therefore; DC = 3 × DG

DG = 6, therefore, DC = 3 × 6 = 18

DC = 18

E. EB = 21

GB = (1/3) × EB

Therefore; GB = (1/3) × 21 = 7

GB = 7

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The Domain and range tends to (-∞,∞) and for more clarity see the graph mentioned below.

Define Domain and Range

Given expression is,

f(x) = -1/4x³ + 4x - 3

In this x ∈ R, so

Domain = (-∞,∞) , { x|x  ∈ R }

Range =   (-∞,∞) ,{ y|y ∈ R }

Hence, the Domain and range tends to (-∞,∞) and for more clarity see the graph mentioned below.

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Answer:

The equation of the line that passes through the point (-6, -7) and has a slope of 1/3 is:

x - 3y + 15 = 0

Step-by-step explanation:

The equation of a line in slope-intercept form is given by y = mx + b, where m is the slope of the line and b is the y-intercept (the point at which the line crosses the y-axis).

To find the equation of the line that passes through the point (-6, -7) and has a slope of 1/3, we can use the point-slope form of a line:

y - y1 = m(x - x1)

Where (x1, y1) is a point on the line and m is the slope of the line.

Plugging in the given values, we have:

y - (-7) = (1/3)(x - (-6))

Which simplifies to:

y + 7 = (1/3)x + 2

Multiplying both sides by 3, we have:

3y + 21 = x + 6

Subtracting 21 and 6 from both sides, we have:

3y - x - 15 = 0

Therefore, the equation of the line that passes through the point (-6, -7) and has a slope of 1/3 is:

x - 3y + 15 = 0

The plane 13x + 11y + 20z = 39 is where the line x = t, y = 1 + t, and z = 1 t cross (2,3,-1).

A plane is an infinitely long, Euclidean, two-dimensional surface in mathematics. A plane is a point, a line, and three-dimensional space's equivalent in two dimensions. In geometry, a plane is a surface made up of all the straight lines connecting any two locations on it. It is, in other words, a level or flat surface. A plane is uniquely defined in a Euclidean space of any number of dimensions by one of the following: three non-collinear points are used.

Here,

13t+11(1+t)+20(1-t)=39

13t+11+11t+20-20t=39

4t+31=39

4t=8

t=2

x=2, y=3, z=-1

The line x = t, y = 1 + t, z = 1 − t intersects the plane 13x + 11y + 20z = 39 at (2,3,-1).

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The appropriate statistical conclusion is that there is sufficient evidence to conclude that the means are different.

The null and the alternative hypothesis for this problem are given as follows:

The p-value and the significance level for this problem are given as follows:

As the p-value is less than the significance level, there is enough evidence to reject the null hypothesis, thus the appropriate statistical conclusion is that there is enough evidence to conclude that the means are different.

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Answer:a,b,c

Step-by-step explanation:easy work just trust me

Answer:

65 = l + m + n

Step-by-step explanation:

The perimeter of a triangle is the sum of its 3 sides:

 65 = l + m + n

The ratio of heads to tails in the probability test is 2:1 or (D) 2/1.

A ratio is a relationship or comparison between two numbers belonging to the same unit in order to determine how much larger one number is than the other.

For instance, if a test result is 7 out of 10, the ratio of the number of points earned to the total number of points is 7:10.

So, we know that the coin is flipped 36 times in the probability test:

Head = 24

Tails = 36 - 24 = 12

The ratio of heads to Tails:

Heads:Tails
24:12

24/12

2/1

2:1

Therefore, the ratio of heads to tails in the probability test is 2:1 or (D) 2/1.

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Complete question:
In a probability, experiment Eric flip a coin 36 times. The coin landed on the head 24 times. What is the ratio of heads to tails in this experiment?

A.3/2

B.1/2

C.2/3

D.2/1

Answer:

y = -10x + 109

Step-by-step explanation:

Given equation,

→ y - 9 = -10(x - 10)

The slope-intercept form is,

→ y = mx + b

Rewrite in slope-intercept form,

→ y = mx + b

→ y - 9 = -10(x - 10)

→ y - 9 = -10x + 100

→ y = -10x + 100 + 9

→ [ y = -10x + 109 ]

Hence, answer is y = -10x + 109.

Answer:

Step-by-step explanation: Step one is distributive property because you distribute the numbers inside the parenthesis. Step 2 is communitive property because you switch the order. Step 3 is conbine-like terms. Step 4 is the addition property of equality. Step 5 is the division property of equality. Hope this helps!

Answer: 1

Step-by-step explanation:

Answer:

totally not confused whatso ever

Step-by-step explanation:

Answer:

1/ In decimal, 3/4 is 0.75

2/ In percent, 3/4 is 75%

Step-by-step explanation:

1/ take 3 divided by 4, and you will get 0.75 as an answer for decimal

2/ For percent, 3/4 is simple for of 75%/100%

To minimize the amount of paper used to create a rectangular poster with a given amount of printing and specific margins, you can use the formula for the area of a rectangle to determine the dimensions that will minimize the area of the poster.

In this case, the area of the poster must be at least 48 square inches to contain the printing, and the margins at the top and bottom must be 3 inches each, for a total of 6 inches. The margins at the sides must be 1 inch each, for a total of 2 inches. Therefore, the minimum area of the poster is 48 + 6 + 2 = 56 square inches.

To minimize the amount of paper used, we want to find the dimensions of the poster that will have the smallest possible area while still satisfying the constraints on the margins and the amount of printing. We can do this by using the formula for the area of a rectangle:

A = lw

where A is the area of the rectangle, l is the length, and w is the width.

In this case, we want to find the length and width that will minimize the area of the rectangle while still satisfying the constraints on the margins and the amount of printing. We can do this by setting the area of the rectangle equal to the minimum area we calculated above (56 square inches) and then solving for the length and width:

A = lw = 56

lw = 56

We can then use the constraints