please and this quickly and no links please

Please And This Quickly And No Links Please

Answers

Answer 1

Answer:

11 months

Step-by-step explanation:

Since he has already read 14 books subtract them from the 80 books. you'll end up with 66. then diviid by 6 and you'll get 11 months


Related Questions

A 20-inch television screen has a width of 12 inches. What is the length of the television screen?

Answers

The answer will have to be x=16

Use the Linear Approximation to estimate Δꜰ=ꜰ(3.5)−ꜰ(3) ꜰᴏʀ ꜰ(x)=41+x2 (Use decimal notation. Give your answer to five decimal places.)
Δf≈ help (decimals)
Calculate the actual change.
(Use decimal notation. Give your answer to five decimal places.)
Δf = help (decimals)
Compute the error and the percentage error in the Linear Approximation.
(Use decimal notation. Give your answer to five decimal places.)
Error = help (decimals)
Percentage error = % help (decimals)

Answers

To estimate Δf = f(3.5) - f(3) using the linear approximation, we'll use the formula:

Δf ≈ f'(a) * Δx

where f'(a) represents the derivative of f at the point a, and Δx represents the change in the x-values.

Given that f(x) = 41 + [tex]x^2[/tex], we can calculate the derivative as:

f'(x) = 2x

Now, let's calculate the values step by step:

Calculate Δf:

Δf ≈ f'(a) * Δx

Δf ≈ f'(3) * (3.5 - 3)

Δf ≈ 2(3) * (3.5 - 3)

Δf ≈ 6 * 0.5

Δf ≈ 3

Calculate the actual change:

To calculate the actual change, we need to evaluate f(3.5) and f(3) separately:

f(3.5) = 41 +[tex](3.5)^2[/tex]

f(3.5) = 41 + 12.25

f(3.5) = 53.25

f(3) = 41 + [tex](3)^2[/tex]

f(3) = 41 + 9

f(3) = 50

Δf = f(3.5) - f(3)

Δf = 53.25 - 50

Δf = 3.25

Calculate the error and the percentage error:

Error = |Δf - Δf_approx|

Error = |3.25 - 3|

Error = 0.25

Percentage error = (|Δf - Δf_approx| / Δf) * 100

Percentage error = (0.25 / 3.25) * 100

Percentage error ≈ 7.69%

So, the results are as follows:

Δf ≈ 3

Actual change (Δf) ≈ 3.25

Error ≈ 0.25

Percentage error ≈ 7.69%

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cars that are ready for shipping weigh 2 tons. a car being built weighs 1,135 pounds. how much more weight, in pounds, will be added to the car so it will be ready for shipping​!?!

Answers

2,865 pounds will be added

please helpppp which function h(x) results when g(x) is translated 7pi/8 units right and one unit down????

Answers

Answer:

The second option

Step-by-step explanation:

Help on here too plz there’s more in my acc I need help on all

Answers

x=2rad10
y=4rad5

it’s a 45-45-90 triangle so the two legs are the same. the equation for hypotenuse would be h=rad2 x leg. substitute; h=rad2 x 2rad10 = 4rad5

task 1
Find the surface area of the Trumpet.

Answers

The surface area of the trumpet is [tex]\( 1256.64 \pi \)[/tex] square feet.

To find the surface area of the trumpet, we need to calculate the areas of the curved surface and the base separately, and then sum them.

The curved surface area of a truncated cone can be calculated using the formula:

[tex]\[ CSA = \pi \times (r_1 + r_2) \times l \][/tex]

Where [tex]\( r_1 \) and \( r_2 \)[/tex] are the radii of the two bases, and [tex]\( l \)[/tex] is the slant height of the truncated cone.

Given that the base diameter is [tex]40[/tex] feet, the radius of the larger base [tex](\( r_1 \))[/tex] is half of that, which is [tex]20[/tex] feet. The slant height [tex](\( l \))[/tex] can be calculated using the Pythagorean theorem:

[tex]\[ l = \sqrt{(h^2 + (r_1 - r_2)^2)} \][/tex]

The height [tex]h[/tex] of the truncated cone is [tex]30[/tex] feet, and the radius of the smaller base [tex](\( r_2 \))[/tex] can be calculated as half the diameter, which is [tex]10[/tex] feet.

Substituting the values into the equations:

[tex]\[ l = \sqrt{(30^2 + (20 - 10)^2)} = \sqrt{(900 + 100)} = \sqrt{1000} = 10\sqrt{10} \]\[ CSA = \pi \times (20 + 10) \times (10\sqrt{10}) = 30\pi\sqrt{10} \][/tex]

The base area of the truncated cone is the area of a circle with radius [tex]\( r_1 \):\[ BA = \pi \times r_1^2 = \pi \times 20^2 = 400\pi \][/tex]

Finally, we can find the total surface area by adding the curved surface area and the base area:

[tex]\[ Surface \, Area = CSA + BA = 30\pi\sqrt{10} + 400\pi \][/tex]

[tex]\[ Surface \, Area = 30\pi\sqrt{10} + 400\pi \]\[ Surface \, Area = \pi(30\sqrt{10} + 400) \]\[ Surface \, Area \approx 1256.637 \pi \]\[ Surface \, Area \approx 1256.64 \pi \][/tex]

Therefore, the simplified surface area of the trumpet is approximately [tex]\( 1256.64 \pi \)[/tex] square feet.

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what is the equation of the line that passes through the point (-6,-6) and has a slope of 2/3?

Answers

Answer:

-6=2/3*-6

Step-by-step explanation:

y=mx+b

slope = m b=y intercept

PLEASE HELP!!
In a right triangle, the length of one of the sides is 13.7, while one of the other sides measures 14.3. Find the length of the hypotenuse.

Answers

The length of the hypotenuse is approximately 19.8 units.

In a right-angled triangle, the hypotenuse is the longest side, and it is opposite to the right angle. To find its length, we can use the Pythagorean theorem, which states that in a right-angled triangle, the square of the length of the hypotenuse is equal to the sum of the squares of the lengths of the other two sides. Therefore, we have:

h^2 = 14.3^2 + 13.7^2

h^2 = 204.49 + 187.69

h^2 = 392.18

h = sqrt(392.18)

h ≈ 19.8

We can round the answer to one decimal place, as this is the nearest level of precision to the data provided. Note that for a right-angled triangle, the hypotenuse is always the longest side, so it makes sense that the hypotenuse is longer than both of the other sides in this case.

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You must estimate the mean temperature (in degrees Fahrenheit)
with the following sample temperatures:



79.5


102.8


80.8


76.8


80.4


79.2


86


67.7



Find the 98% confidence interval. Enter your answer as an open-interval (i.e., parentheses) accurate to two decimal places (because the sample data are reported accurate to one decimal place). * Answer should be obtained without any preliminary rounding.

98% C.I. =

Answers

The interval value at 98% confidence level for the given scenario is (73.51 ; 89.79)

From the data :

Mean(x) = (79.5+102.8+80.8+76.8+80.4+79.2+86+67.7)/8

Mean = 81.65

Sample standard deviation :

s = √[(x1 - mean)² + (x2 - mean)² + ... + (x(n) - mean)²] / n

Using a statistical calculator :

s = 9.98

The confidence interval is defined thus :

Mean ± Tcritical × s/√n

Tcritical at 98% = 2.306

Substituting values into the formula :

81.65 ± (2.306 × 9.98/√8)

81.65 ± 8.137

(73.51, 89.79)

Therefore, the confidence interval for the given scenario is (73.51 ; 89.79)

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MARKING BRAINLIST ASAPP pleaseee help

Answers

Answer:38

Step-by-step explanation:I think it's 38 because it said right 8 and down 15 so it's kinda like a grid right mean stay positive but also means it goes up so I did 45 plus 8 which is 53 minus 15 which is 38. Hope this gets brainliest

please help please it would me me sm <3

Answers

Answer:

25

Step-by-step explanation:

4x25=100

100-25=75 degrees

Answer:

25°

Step-by-step explanation:

(4x-25)=75

4x=100

x=25

1. What is the domain of
f (x)= 9 - x?

Answers

Answer:

theres no answer

Step-by-step explanation:

Help Please! Find The Area Of A Circle With D=8.2

Answers

Answer:

52.81

Step-by-step explanat

I NEED HELP
Please write the right answer
Your portfolio must include a minimum of the following five types of equations and solutions:

Two one-step equations
Two equations that contains fractions
One equation with distributive property
One equation with decimals
One real-world problem that is solved by an equation
Remember that each equation must include at least one variable. Once you have created each equation, you will solve it and show your work. Pretend that you are teaching the equations to a new pre-algebra student. Or you can actually teach them to a sibling or friend!

This is a total of 7 equations and solutions.

Answers

Answer:

1).  (x - 4 = 13)

2).  (r + 17 = 51)

3). (7/9x =28)

4). (2/3x = 2)

5). { 3(x-2) = -9 }

6). (x -1.75 = 8.85)

7). Natalie buys organic almonds priced at $77 from the grocery store. How much did

she pay the cashier, if she received $23 in change?

Step-by-step explanation:

1. add 4 on both sides and it will be x=17

2. subtract 17 on both sides and it will be x= 34

3. multiply 9/7 on both sides and it will be x= 257/7 then you divide 257 by 7 then the final answer will be x= 36

4. multiply 3/2 on both sides and it will be x=6/2 then you divide 6 from 2 and the finial answer will be x= 3

5. you will distribute 3 into x and 2 and you will be 3x-6=-9 then you will add 6 on both sides so you will get 3x=3 and then divide 3 on both side so you will get x=1

6. add 1.75 on both sides so x= 10.6

7. the equation will be 23 +x = 77 so first you will subtract 23 on both sides and x will equal 54 so Natalie paid $54

Answer:

i'm taking that test rn

Step-by-step explanation:

Your customer has found base plates that are defective, they exceed the maximum width dimension of 4.005. As a result the mating component will not fit on these base plates properly. You manufacture these base plates on four identical CNC milling machines with approximately 25% of the production coming from each machine.
Simplified drawing of base plate is shown below.
Assignment:
Your manager has requested you sample 50 pieces from the manufacturing floor that were manufactured from each machine, analyze the data and come up with recommendations to solve the problem. (The data for the 50 piece sample is attached at the end of the assignment.)
Introduction: describing the process and statement of the general problem(s)
Analysis of the data: Graphical analysis is required
Each table and graph must be briefly explained at the point of the table or graph to indicate how it relates to the study at hand.
A brief summary of the findings relating back to specific analytical tools
Cause and effect diagram(s): identifying PERTINENT possible solutions to the problem(s)

Answers

The problem at hand involves base plates that exceed the maximum width dimension, resulting in improper fitting of the mating component. To address this issue, a sample of 50 base plates manufactured from each of the four CNC milling machines was analyzed.

Graphical analysis of the data revealed insights into the problem. Recommendations for solving the problem include identifying pertinent possible solutions through cause and effect diagrams.

The analysis of the sample data from each CNC milling machine provides valuable insights into the issue of base plates exceeding the maximum width dimension. By graphically analyzing the data, patterns or variations can be identified, helping to pinpoint the specific source of the problem. This analysis may involve creating graphs or tables to visualize the measurements and compare them across the machines.

To identify possible solutions, cause and effect diagrams, such as fishbone diagrams, can be utilized. These diagrams help to identify potential causes of the issue by categorizing them into different categories such as machine factors, material factors, human factors, and environmental factors.

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[tex] \sqrt{39} [/tex]
Please help me to find the answer of square root 39
plz​

Answers

Answer:

hi dear friend the answer is 6.245. hope that helps it has been a pleasure to help you can always look out for me if you have a math problem.

A bottling company uses a filling machine to fill plastic bottles with cola. The bottles are supposed to contain 300 milliliters (ml). In fact, the contents vary according to a Normal distribution with mean μ=298ml and standard deviation σ=3ml. What is the probability that the mean contents of six randomly selected bottles are less than 295 ml?

Answers

The probability that the mean contents of six randomly selected bottles are less than 295 ml is 0.007, or 0.7%.

To find the probability that the mean contents of six randomly selected bottles are less than 295 ml, we can use the Central Limit Theorem. According to the Central Limit Theorem, the distribution of sample means from a population with any distribution approaches a normal distribution as the sample size increases.

In this case, we have a normal distribution with a mean (μ) of 298 ml and a standard deviation (σ) of 3 ml. We want to find the probability of the mean contents of six bottles being less than 295 ml.

First, we need to calculate the standard error of the mean, which is the standard deviation of the sampling distribution of the mean. The formula for the standard error is σ / √n, where σ is the population standard deviation and n is the sample size.

In our case, σ = 3 ml and n = 6. Therefore, the standard error (SE) is:

SE = 3 / √6 ≈ 1.225 ml

Next, we need to calculate the z-score, which is the number of standard errors the sample mean is away from the population mean. The formula for the z-score is (x - μ) / SE, where x is the sample mean.

In our case, x = 295 ml, μ = 298 ml, and SE = 1.225 ml. Therefore, the z-score is:

z = (295 - 298) / 1.225 ≈ -2.449

Finally, we can use a standard normal distribution table or a calculator to find the probability corresponding to the z-score. The probability that the mean contents of six bottles are less than 295 ml is the area under the normal curve to the left of the z-score.

Using a standard normal distribution table or calculator, we find that the probability corresponding to a z-score of -2.449 is approximately 0.007.

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BRAINLY TO WHOEVER HELPS AND GETS IT RIGHT

~no links pls~

Answers

Answer:

the answer is C

Step-by-step explanation:

BABYSHARK

Answer:

I think its c?

Step-by-step explanation:

Hope this helps and have a wonderful day!!!

The integral ſ sin(x - 2) dx is transformed into ', g(t)dt by applying an appropriate change of variable, then g(t) is: g(t) = cos (33) g(t) = sin (5) This option This option g(t) = cos (3 g(t) = sin This option

Answers

The integral oſ sin(x - 2) dx is transformed into g(t)dt by applying an appropriate change of variable is g(t) = sin(t).

To transform the integral ∫sin(x - 2) dx into the form ∫g(t) dt using a change of variable, we can let u = x - 2.

Then, differentiating both sides with respect to x gives du = dx.

Substituting these values in the integral, we have:

∫sin(x - 2) dx = ∫sin(u) du

The integral has now been transformed into the integral of sin(u) with respect to u, denoted as g(t) dt.

Therefore, g(t) = sin(t).

So, the correct option is g(t) = sin(t).

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1. The values, x in a sample of 15 are summarized as follows
Σ(x-c) = 72,Σ(x-c)2 = 499.6
where c is a constant. Given that the sample mean is 104.8.
(a) Find the value of constant c.
(b) Find the variance of x.​

Answers

Answer:

(a) 100

(b) 10.27

Step-by-step explanation:

We are given  

No of elements = 15  

Σ(x-c) = 72,Σ(x-c)^2 = 499.6

,where c is a constant

and the sample mean is 104.8.

(a)  lets take into account Σ(x-c) = 72

this means that we have the sum of the 15 elements of x and each element of x is subtracted by the constant c

so the equation becomes Σxi -15c = 72, ............(1)

where xi means the sum of the elements of x from 1 to 15.

we are given the mean as 104.8

this means that Σxi/15 = 104.8

Σxi = 15*104.8 = 1572 .............(2)

substituting (2) in (1)

we get  

1572 - 15c = 72  

15c = 1500  

c = 100

(b) We will use the property that variance does not change when a constant value is added or subtracted to the elements. This we can observe in the given equation that c is a constant that has the value of 100.

so the variance is  

σ^2 = Σ(x-c)^2/15  - (Σ(x-c)/15 )^2

      = 499.6/15  - (72/15)^2

      = 33.31 - 23.04

   σ^2   = 10.27

Therefore the variance of the given problem is 10.27.

The science and technology class is studying robotics. One group builds a robot that can be controlled by entering positive and negative numbers into a control unit. Negative numbers make the robot roll backwards a specific number of inches. Positive numbers make it move forward a certain number of inches. For example, if −5 is entered, then the robot moves backwards 5 inches. The students enter the numbers −37, +22, and −16. What number do they need to enter to make the robot return to its original position of 0?

Answers

To achieve this, the students must enter +31 (forward) to bring the robot back to its starting position of 0.

The robot can move forward or backward depending on the type of number entered into the control unit. For example, entering a negative number causes the robot to roll backward a specific number of inches,

while entering a positive number makes it move forward a certain number of inches. If −5 is entered, the robot moves backwards by 5 inches. As a result, the students entered the numbers −37, +22, and −16 to move the robot.

The question asks what number needs to be entered to bring the robot back to its starting position of zero. To do so, we must first calculate how far the robot has traveled in total.

When a negative number is entered into the control unit, the robot rolls backward.

As a result, when we add the negative numbers and subtract them from the positive number,

we can determine the total distance traveled by the robot.-37 (back) + 22 (forward) - 16 (back) = -31 (inches traveled)Since the robot moved a total of 31 inches,

the students must enter the opposite number to bring the robot back to its starting position of 0.

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Let D be the region bounded by the two paraboloids z = 2x2 + 2y2 – 4 and z=5 - x2 - y2 where x > 0 and y > 0. Which of the following triple integral in cylindrical coordinates allows us to evaluate the volume of D? - √3 5-2 Salon dzdrde None of thes

Answers

Option D is the correct choice.

To evaluate the volume of D, the triple integral in cylindrical coordinates is required. So, let's derive the required triple integral.

Region D is bounded by two paraboloids z = 2x2 + 2y2 - 4 and z = 5 - x2 - y2 where x > 0 and y > 0.

In cylindrical coordinates,r = √(x^2 + y^2)z = zθ = tan-1(y/x)For the first paraboloid, the cylindrical equation of the paraboloid is: z = 2x2 + 2y2 - 4

By substituting the cylindrical coordinates values in this equation we get z = 2r2 sin2θ + 2r2 cos2θ - 4z = 2r2 (sin2θ + cos2θ) - 4z = 2r2 - 4 Now for the second paraboloid, the cylindrical equation of the paraboloid is: z = 5 - x2 - y2By substituting the cylindrical coordinates values in this equation we get:z = 5 - r2 The limits of r are 0 and √5; and the limits of θ are 0 and π/2.

Finally, the limits of z are obtained by equating the above two paraboloids.2r2 - 4 = 5 - r22r2 + r2 = 9r2 = 3z = 3We have got all the limits of cylindrical coordinates, we can now write the triple integral in cylindrical coordinates which evaluates the volume of D.

The triple integral is:∫(0 to π/2)∫(0 to √5)∫(2r2 - 4 to 3) r dz dr dθ

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Jim and three friends shared 2 poster boards for an art project. What part of the construction paper will each friend get? *

Answers

Answer: 1/2 of a sheet

Step-by-step explanation:

2 sheets divided by 4 people

2/4

Simplify to 1/2

Cindy lost 28 pounds while on a diet. She now weighs 157 pounds. Write and solve an equation to find her initial weight

Answers

Answer:

The equation is 157+28=185.

157+ 28= 185

I think that’s right

What is k^2+16k+64+89

Answers

Answer:

k²+16k+ 153

Step-by-step explanation:

k²+16k+64+89

= k²+16k+ 153

Triangle CDE, with vertices C(-8,-7), D(-2,-8) and E(-5,-2), is drawn on the coordinate grid below.
What is the area, in square units, of triangle CDE?

Answers

Answer:

Area = 24.75 sqr units

Step-by-step explanation:

You will need these formulas:

[tex]d = \sqrt{(x_2 - x_1)^2 + (y_2-y_1)^2}[/tex]

Midpoint = [tex](\frac{x_{1} + y_{1} }{2} , \frac{x_{2} + y_{2} }{2})[/tex]

Area = b x h

Let us treat CD as the base. Find the length of the base with the distance formula. Use the coordinates for points C & D.

[tex]d = \sqrt{(-2 - (-8))^2 + (-8-(-7))^2}[/tex]

[tex]d = \sqrt{37}[/tex]

The base is [tex]\sqrt{37}[/tex].

The height is the distance between point E and the midpoint of line CD.

Midpoint of CD = [tex](\frac{-8 + (-7) }{2} , \frac{-2 + (-8) }{2})[/tex] = ([tex]-\frac{15}{2}[/tex], [tex]-5[/tex])

Use the distance formula to find the height.

[tex]d = \sqrt{(-5 - (-\frac{15}{2} ))^2 + (-2-(-5))^2}[/tex]

[tex]d = \frac{\sqrt{61} }{2}[/tex]

Find the area with the two distances that were found.

Area = [tex](\sqrt{37}) (\frac{\sqrt{61} }{2})[/tex]

Area = [tex]\frac{\sqrt{2257} }{2}[/tex]

Area = 24.75 sqr units

Write your answer in simplest form 11/12- 3/4

Answers

Answer: 1/6 is its simplest form :)

For matrices: A = -1-41] 0 2 2 2 30] B = 33 -1 2 A. What is the dimension of A and B? B. What is the dimension of A B? C. What is A'B?

Answers

A. the dimension of A is 3x3. the dimension of B is 3x2.

B. the dimension of AB will be 3x2.

C. The value of AB = [[ -15 14] [ 4 -2] [ 13 -9]]

A. The dimension of a matrix is given by the number of rows and columns it has.

For matrix A, we have:

A = [[-1 -4 1], [0 2 2], [2 3 0]]

The matrix A has 3 rows and 3 columns, so the dimension of A is 3x3.

For matrix B, we have:

B = [[2 0], [3 -3], [-1 2]]

The matrix B has 3 rows and 2 columns, so the dimension of B is 3x2.

B. To multiply two matrices, the number of columns in the first matrix must be equal to the number of rows in the second matrix. In this case, A has 3 columns and B has 3 rows, so we can multiply them.

The dimension of AB will be the number of rows of A and the number of columns of B. Therefore, the dimension of AB will be 3x2.

C. [-1 -4 1] * [2 0]

   [0 2 2]    [3 -3]

   [2 3 0]    [-1 2]

  [-2-12-1   0+12+2]

= [0+6-2    0-6+4]

  [4+9+0   0-9+0]

  [ -15     14]

= [ 4         -2]

  [ 13       -9]

The value of AB = [[ -15 14] [ 4 -2] [ 13 -9]]

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Given question is incomplete, the complete question is below

For matrices: A =[[ -1 -4 1] [0 2 2][ 2 3 0]] B =[[2 0] [3 -3 ][-1 2] ]

A. What is the dimension of A and B?

B. What is the dimension of A*B?

C. What is A*B?

Please someone help with this

I’v been stuck on it all day

By the way I have already been sent that link that hacks you

Just show the work

Answers

ok, i will help you.

For the first equation, we have points

(-1, -4)

and

(1, -1)

we also know the y-intercept is

(0, -2)

we can make systems of equations to solve for the equation of this exponiental function

y=ab^x

-1=ab

-2=a*1

a=-2

-1=-2(b)

b=1/2

The exponiental fufnction here is y=(-2)(1/2)^x

2nd equation

(0, 6)

(1, 12)

12=ab

6=a*b^0=6

a=6

12=6(b)

b=2

2nd equation is

y=6(2)^x

helppppppppppp meeeeeeeeeee

Answers

Answer:

It's 11.72

Step-by-step explanation:

Area=)1/2×15/4×25/4

Answer》11.72

Hope it helps...

Have a great day

Answer:

i have made it in above picture

Other Questions
5) (10 points) A monopolist has two segmented markets with demand functions given by P = 160-Q and P = 130-0.5Q2, where p and p are the prices charged in each market segment, Q and Q Exercise 6-1A Calculate cost of goods sold (LO6-2) Russell Retail Group begins the year with inventory of $58,000 and ends the year with inventory of $48,000. During the year, the company has four pur A father is now planning a savings program to put his daughter through college. She is 13, she plans to enroll at the university in 5 years, and she should graduate in 4 years. Currently, the annual cost (for everything - food, clothing, tuition, books, transportation, and so forth) is $13,000, but these costs are expected to increase by 7% annually. The college requires total payment at the start of the year. She now has $6,000 in a college savings account that pays 8% annually. Her father will make six equal annual deposits into her account; the first deposit today and sixth on the day she starts college. How large must each of the six payments be? Do not round intermediate calculations. Round your answer to the nearest dollar. [Hint: Calculate the cost (inflated at 7%) for each year of college and find the total present value of those costs, discounted at 8%, as of the day she enters college. Then find the compounded value of her initial $6,000 on that same day. The difference between the PV of costs and the amount that would be in the savings account must be made up by the father's deposits, so find the six equal payments (starting immediately) that will compound to the required amount.] Wells Technical Institute (WTI), a school owned by Tristana Wells, provides training to individuals who pay tuition directly to the school. WTI also offers training to groups in off-site locations. Its unadjusted trial balance as of December 31, 2018, follows. WTI initially records prepaid expenses and unearned revenues in balance sheet accounts. Descriptions of items a through h that require adjusting entries on December 31, 2018, follow. Additional Information Itemsa. An analysis of WTIs insurance policies shows that $2,400 of coverage has expired. b. An inventory count shows that teaching supplies costing $2,800 are available at year-end 2017. c. Annual depreciation on the equipment is $13,200. d. Annual depreciation on the professional library is $7,200. e. On November 1, WTI agreed to do a special six-month course (starting immediately) for a client. The contract calls for a monthly fee of $2,500, and the client paid the first five months fees in advance. When the cash was received, the Unearned Training Fees account was credited. The fee for the sixth month will be recorded when it is collected in 2018. f. On October 15, WTI agreed to teach a four-month class (beginning immediately) for an individual for $3,000 tuition per month payable at the end of the class. The class started on October 15, but no payment has yet been received. (WTIs accruals are applied to the nearest half-month; for example, October recognizes one-half month accrual. )g. WTIs two employees are paid weekly. As of the end of the year, two days salaries have accrued at the rate of $100 per day for each employee. h. The balance in the Prepaid Rent account represents rent for December. Debit CreditCash 34,000Teaching supply 8,000Prepaid Insurance 12,000Prepaid rent 3000Professional library 35,000Account payable 26,000unearned training fee 12,500Prepare T-accounts (representing the ledger) with balances from the unadjusted trial balance please help with this?!? HELP PLS ILL GOVE BRAINLIEST What other interests could the Ancient Egyptians pursue since they already had a stable food source in the Nile? find the volume of the solid that results when the region bounded by y=x, y=0 and x=36 is revolved about the line x=36. What is the answer to this question? Question 1: 1 2/3 + 2 1/4 + 2 1/2 = Question 2: 4 + 2 1/3 + 1 1/2 =Please answer both questions! Rearrange the equation so uuu is the independent variable.-12u+13=8w-3 How is Lincolns speeches different from the other Modern presidential addresses Channing Corporation makes two products (A1 and B2) that require direct materials, direct labor, and overhead. The following data refer to operations expected for next month.A1 B2 TotalRevenue $ 220,000 $ 660,000 $ 880,000 Direct material 90,000 180,000 270,000 Direct labor 64,000 152,000 216,000 Overhead: Direct-material related 72,900 Direct-labor related 69,120 Required:Channing uses a two-stage cost allocation system, It uses direct-material costs to allocate direct-materials related overhead and direct-labor costs to allocate direct-labor related overhead costs.a. Compute the direct-material related overhead rate for next month.b. Compute the direct-labor related overhead rate for next month.c. What is the total overhead allocated to product A1 next month?d. What is the total overhead allocated to product B2 next month? y-5=4x and y=4x-5 has no solution true of false? nerves meaningbrainles If y varies directly as x, and y = 6 when x = 4, find y when x = 12.y = Running at an average rate of 10 m/s, a sprinter ran to the end of a track and then jogged back to the starting point at an average of 5 m/s. The sprinter took 60 s to run to the end of the track and jog back. Find the length of the track.d=300md is equal to 300 md=200md is equal to 200 md=600md is equal to 600 md=150md is equal to 150 m what is the approximate radius of a sphere with a volume of 900 cm squared A 12 cmB 36 cmC 18cmD 6cm Please Help. What expression is equivalent to 6( t - 5 ) + 3A. 6t - 2B. 6t - 12C. 3 ( 2t - 11 )D. 3 ( 2t + 9 ) On the map of Africa, the star is marking which of the following countries? Cool-Ices balance sheet for 30 November follows. Use it and the following information to prepare a cash budget for Cool-Ice for December.80% of sales are on account, of which half are collected in the month of the sale, 49% are collected the following month and 1% are never collected and are written off as bad debts.All purchases of materials are on account. Cool-Ice pays for 70% of purchases in the month of purchase and 30% in the following month.All other costs are paid in the month incurred.Cool-Ice is making monthly interest payments of 1% (12% per year) on a $20 000 long-term loan.Cool-Ice plans to pay the $500 of taxes owed as of 30 November in the month of December. Income tax expense for December is zero.40% of processing and set-up costs, and 30% of marketing and general administration costs, are depreciation.Cool-IceBalance sheet as of 30 NovemberAssetsCash$587Accounts receivable$4 800Less: Allowance for bad debts964 704InventoriesDirect materials169Finished goods974Fixed assets$190 000Less: Accumulated depreciation55 759134 241Total assets$140 675Liabilities and equityAccounts payable$696Taxes payable500Interest payable200Long-term debt20 000Ordinary shares10 000Retained earnings109 279Total liabilities and equity$140 675