Plaskett's binary system consists of two stars that revolve in a circular orbit about a center of mass midway between them. This statement implies that the masses of the two stars are equal (see figure below). Assume the orbital speed of each star is |v with arrow| = 160 km/s and the orbital period of each is 14.3 days. Find the mass M of each star. (For comparison, the mass of our Sun is 1.99 1030 kg.)

Electromyography (EMG) measures muscle response or electrical activity in response to a nerve's stimulation of the muscle. The test is used to help detect neuromuscular abnormalities.

Electromyography (EMG) :

(EMG) detects the electrical activity that occurs when a muscle is stimulated by a nerve. The test is used to identify aberrant neuromuscular function. One or more tiny needles, commonly known as electrodes, are introduced through the skin and into the muscle during the test. An oscilloscope is then used to display the electrical activity that the electrodes picked up (a monitor that displays electrical activity in the form of waves). In order to hear the activity, an audio amplifier is employed. The electrical activity of muscles during rest, a light contraction, and a strong contraction is measured by EMG. At rest, muscle tissue doesn't typically create any electrical signals. A brief period of activity can be seen on the oscilloscope when an electrode is introduced, but there should be no signal beyond that.

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The negative charge passes through the surface is 9 A/s

The Intrinsic property of protons and electrons are known as Electric Charge

Protons are known as positive charge

Electrons are known as negative charge

Give that

I =18A

The current is flowing to the right

The equal amount of positive and negative charges.

that is total charge is q= Q+Q=2Q. that is magnitude

Then, the rate of charge that pass though is dq/dt

Give that,

q=it

2Q=it

Let differentiate with respect to t

2dQ/dt=I

Then, dQ/dt=i/2

Since I=18A

Then, dQ/dt=18/2

dQ/dt= 9 A/s. Toward the left

9 A/s negative charge passes through the surface .

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The direction of the electric field based on the information given about the dipole is along the x axis.

It should be noted that a dipole simply means a pair of opposite charges that are separated by a distance.

By default, the direction of the dipole is always from the negative charge -q to the positive charge q.

In this case, since the equipotential surfaces are planes parallel to the YZ planes., the direction of the electric field is along the x axis.

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Complete question:

A dipole with its charges,-q and +q located at the points (0,-b,0) and (0+b,0) is present in uniform electric field E whose equipotential surfaces are planes parallel to the YZ planes.

What is the direction of the electric field?

Answer:

c option 22.0A

Explanation:

V=IR

I=R/V

Answer:    

Explanation:

When two waves of similar frequency arrive at the same point and superimpose, they alternately constructively and destructively interfere. This alternating is known as a beat because it produces an unpleasant pulsing sound

The length of an organ pipe is 19.48

Given,

An organ pipe that is open on both ends and has a fundamental frequency of  n1 = 8.75Hz & the speed of sound in air is v =  341m/s

we have the formula for fundamental frequency in open pipe as

       n1 = v /λ1 = v / 2L

   so  L = v / 2n1

plug in the values for L

n1 = v / λ1 = v / 2L

     L = v / 2n1

     = 341 / 2 (8.75)

    = 19.48

The length of an organ pipe is 19.48

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882J of gravitational potential energy is gained by the eagle.

Here, we have been provided with data-

mass, m = 4.5 kg

height, h = 25 m

We have to find the gravitational potential energy.

In the question, it is given that the eagle is at a height of 5m and it flies from there 20 m more to reach its nest.

So, gravitational potential energy is given as

P.E = m x g x h

P.E = 4.5 × 9.8 × 20

P.E =  882J

Thus, the correct option is (b).

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Answer:

b

Explanation:

its b

(a) Fundamental frequency of clothesline is 6.98Hz.

(b) Frequency of second harmonic is 13.98Hz.

The wave velocity expression is,

        v = √T / √μ

here, T is tension μ is mass per unit length

     v = √22.1 / √(12.5×10⁻³/7.66)

     v = 116.37 m/s

    For the fundamental frequency,

                  v = fλ

     116.37 m/s= 7.6 ×λ

         λ = 15.31 m

     For the second Harmonic,

          λ₂=  v/ f₂ = 116.37 / 15.2 = 7.66 m

     Now consider mass is increased

             μ= 14.8 × 10⁻³ / 7.66

                v = √T / √μ

                v = √22.1 / √14.80 × 10⁻³/7.66

                v = 106.95 m/s

          Fundamental harmonic,

                f₁ = v/λ₁ = 106.95 / 15.31 = 6.98 Hz

                f₂= v/ λ₂ = 106.95 / 7.65 = 13.98 Hz

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[Your question is incomplete, but most probably your full question was-

a) What is the frequency of the fundamental harmonic for a clothesline with a mass of 14.8 g?

(b) What is the frequency of the second harmonic for a clothesline with a mass of 14.8 g?]

Repetitive Transcranial Magnetic Stimulation (TMS) is the procedure that is being performed on Tommy, while he is awake.

What is Transcranial Magnetic Stimulation?

Transcranial magnetic stimulation (TMS) is a non-invasive method for mood control. It does not require the patient to be sedated and is usually performed on completely conscious patients.

Tommy sings during the procedure because the region of the brain responsible for memory and singing is stimulated by this procedure.

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The launch speed of a horizontally launched projectile is 13.28 m/s.

The time of motion is calculated as follows;

t = √(2h / g)

where;

t = √(2 x 19.3 / 9.8)

t = 1.98 s

X = Vxt

Vx = X/t

Vx = (26.3)/(1.98)

Vx = 13.28 m/s

Thus, the launch speed of a horizontally launched projectile is 13.28 m/s.

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the action-reaction forces that the blocks exert on each other will 13 N and 22N

Force is the product of mass and acceleration. There will be constant acceleration on both object X and Y.

Given that the Mass of block X is 10 kg and that of block Y is 5 kg. The magnitude of force of friction on blocks X and Y is 8.0 N and 4.0 N respectively. if an applied force of 40 N [right] acts on block,

We are given that:

With the use of the formula below,

F - [tex]F_{r}[/tex] = ma

Where

The acceleration will be;

40 - (8 + 4) = (10 + 5)a

40 - 12 = 15 a

28 = 15a

a = 28/15

a = 1.8667 m/[tex]s^{2}[/tex]

The tension between the two blocks will be

Force applied-frictional force on X-tension = mass of X × acceleration

That is,

F - [tex]F_{r}[/tex] = ma

40-8-T = 10 × 1.8667

32 - T = 18.667

T = 32 - 18.667

T = 13.33 N

The opposite reaction will be

F - 8 = 10 x 1.8667

F - 4 = 18.67

F = 18.67 + 4

F = 22.67 N

Therefore, the action-reaction forces that the blocks exert on each other will 13 N and 22N

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Answer: Only 25% of the intensity of a polarized light wave passes through a polarizing filter. Then the angle between the electric field and the axis of the filter will be 60 degrees.

Explanation: To find the answer of the problem given, we have to know about the Malu's law of polarization.

                                         [tex]I=I_0cos\alpha[/tex]

                                        [tex]\frac{I}{I_0} =0.25\\[/tex]

                                        [tex]cos^2\alpha =0.25\\cos\alpha =\sqrt{0.25} =0.5\\\alpha =cos^-1(0.5)=60 degrees[/tex]

Thus, we can conclude that, the angle between the electric field and the axis of the filter will be 60 degrees.

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The additional force must be added to produce equilibrium is 5 N force acting in the same direction as the 10 N force (Option A)

To have equilibrium,

Force to the left = force to the right

But

The force to the right is greater than the force to the left.

Thus,

Force to the left + additional force = force to the right

10 + additional force = 15 N

Collect like terms

Additional force = 15 - 10

Additional force = 5 N

Therefore, an additional force of 5 N acting in the same direction of the 10 N force is needed to obtain the equilibrium of the system (Option A)

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(a) The unknown charge kept at distance 0.250m directly below  -0.450 charge is  2.315 x 10⁻¹² C.

(b) The magnitude of the force is 29.16 x 10¹² N.

The electrostatic force F between two charged objects placed distance apart is directly proportional to the product of the magnitude of charges and inversely proportional to the square of the distance between them.

F = kq₁q₂/r²

where k = 9 x 10⁹ N.m²/C²

Given is a negative charge -0.450 exerts an upward 0.150N force on an unknown charge 0.250m directly below it .

In equation of the magnitude of force, only the magnitude of charges are taken.

Substituting the values into the expression ,we get the charge

0.150 = (9 x 10⁹ x 0.450x q)/ (0.25)²

q = 2.315 x 10⁻¹² C

Thus, the magnitude of the unknown charge is 2.315 x 10⁻¹² C.

b)Let the unknown charge be  0.450C to exert on -450C.

Substituting the values into the expression ,we get the electrostatic force

F = kq₁q₂/r²

F = (9 x 10⁹ x 0.450x 0.450)/ (0.25)²

q = 2.315 x 10⁻¹² C

Thus, the magnitude of the force is 29.16 x 10¹² N.

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Answer:

yes

Explanation:

banked curve :

is a road that looks like the top part of a race track

its looks elevated

often seen in bicycle race track (velodrome)

Banking the curve can help keep cars from skidding. When the curve is banked, the centripetal force can be supplied by the horizontal component of the normal force.

sfuca

If they had done a risk assessment first "The student would have no injuries because he would know hydrochloric acid is dangerous and would be wearing gloves when using it"

An aqueous solution of hydrogen chloride HCl that is a strong corrosive irritating acid, is normally present in dilute form in gastric juice, and is widely used in industry and in the laboratory.

Maintain a safe distance between your hands and your body, mouth, eyes, as well as a face when utilizing lab supplies and chemicals.

If they had done a risk assessment first "The student would have no injuries because he would know hydrochloric acid is dangerous and would be wearing gloves when using it"

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The Frictional force is 99 N; option C.

The frictional force between the floor and the surface is calculated as follows:

Frictional force = coefficient of friction * normal reaction

Frictional force = 660 * 0.15

Frictional force = 99 N

In conclusion, the frictional force is determined from the coefficient of friction and the normal reaction of the box on the floor.

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Chains are the type of resistance training equipment which has a fixed range of motion.

This is a type of force which restricts the motion of an object thereby slowering it down.

Chains help to build stamina and power though varying the loads in a fixed range of motion. This is why it was chosen as the most appropriate choice.

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Nutrients found in packed items include carbohydrates, fats and proteins and the amount of nutrients present in them is found in calories/grams.

Macronutrients are nutrients that contain calories that must be consumed in the diet to perform metabolic functions.

These macronutrients are specified in packed foods, and include proteins, carbohydrates and lipids.

Macronutrients provide 4 calories (proteins and carbohydrates) or 9 calories per gram (fats).

In conclusion, nutrients include carbohydrates, fats (lipids) and proteins and their proportions are expressed in grams.

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Answer:

E = 1/2 * k x^2 is the energy stored in the spring

E = 1/2 * 260 N/m * .08^2 m = .832 Joules

When thrown from the balloon, the sandbag has a constant horizontal/forward velocity. As the text puts it, "the sandbag continues forward as if it had not been dropped." What this means is that the sandbag has no acceleration in the horizontal plane of motion, so it moves in this direction at a constant speed. So for any time [tex]t[/tex], the horizontal velocity is given by

[tex]v_x(t) = 12\dfrac{\rm m}{\rm s}[/tex]

In the vertical plane of motion, the sandbag has no vertical velocity until it's released and allowed to fall. As it's falling, however, the sandbag is being pulled down by gravity and is accelerating with magnitude [tex]g=9.8\frac{\rm m}{\mathrm s^2}[/tex], so its vertical/downward velocity at time [tex]t[/tex] is given by

[tex]v_y(t) = -gt[/tex]

So, after 3 seconds have passed, the sandbag has horizontal velocity [tex]v_x = 12\frac{\rm m}{\rm s}[/tex] and vertical velocity [tex]v_y = -g(3\,\mathrm s) = -29.4\frac{\rm m}{\rm s}[/tex]. If the question is specifically asking about speed you would just ignore the negative signs.

Answer:

Most interstellar clouds are much bigger than our solar system.

Explanation:

An interstellar cloud  refers:

Interstellar clouds can be large up to 106 solar masses

It is also often said to be the most massive entities in the galaxy.

Hence

we can say about Interstellar clouds,

They are much bigger than our solar system.

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Answer:

kinetic energy and potential and electrical energy

Explanation:

it will be need to maintain the motion of the vehicle and produce electrical energy

Answer:

B

Explanation:

Astronomers cannot use parallax to find the distance to most stars. This is because the stars are: B too close.

B is the answer

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The balance point of the bar from the 100 g mass is 12 cm.

Apply principle of moment as follows;

Let the balance point from 100 g mass = x

Clockwise moment = anti clockwise moment

100x = 150(20 - x)

100x = 3,000 - 150x

250x = 3000

x = 3000/250

x = 12 cm

Thus, the balance point of the bar from the 100 g mass is 12 cm.

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Pluto would be placed 39.74 feet far from the Sun.

Astronomers use the gap between Earth and the sun, which is ninety-three million miles, as a new unit of measure called the Astronomical Unit.

Map scale refers to the connection (or ratio) between the space on a map and the corresponding distance on the ground. For example, on a 1:one hundred thousand scale map, 1cm at the map equals 1km on the ground.

The distance between the earth and solar, a = around 150 million km, is defined as one Astronomical Unit (AU). The radius of the solar, the solar is around 700,000 km.

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1st

Newton's laws of motion are three basic laws of classical mechanics that describe the relationship between the motion of an object and the forces acting on it. These laws can be paraphrased as follows: Law 1. A body remains at rest, or in motion at a constant speed in a straight line, unless acted upon by a force.

2nd

Newton's second law of motion can be formally stated as follows: The acceleration of an object as produced by a net force is directly proportional to the magnitude of the net force, in the same direction as the net force, and inversely proportional to the mass of the object.

3rd

His third law states that for every action (force) in nature there is an equal and opposite reaction. If object A exerts a force on object B, object B also exerts an equal and opposite force on object A. In other words, forces result from interactions.

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