Part 1. Using the two functions listed below, insert numbers in place of the letters a, b, c, and d so that f(x) and g(x) are inverses.

f(x)=
x+a
b

g(x)=cx−d

Part 2. Show your work to prove that the inverse of f(x) is g(x).

Part 3. Show your work to evaluate g(f(x)).

Part 4. Graph your two functions on a coordinate plane. Include a table of values for each function. Include five values for each function. Graph the line y = x on the same graph.

Task 2
Part 1. Create two radical equations: one that has an extraneous solution, and one that does not have an extraneous solution. Use the equation below as a model:

a√x+b+c=d

Use a constant in place of each variable a, b, c, and d. You can use positive and negative constants in your equation.

Part 2. Show your work in solving the equation. Include the work to check your solution and show that your solution is extraneous.

Part 3. Explain why the first equation has an extraneous solution and the second does not.

Answers

Answer 1

See below for the solution to the inverse function and the rational equation

The function and the inverse

Create functions f(x) and g(x)

The functions are given as:

f(x) = x + a/b

g(x) = cx − d

Let a = 4 and b = 2.

So, we have:

f(x) = x + 4/2

Rewrite as:

y = x + 2

Swap x and y

x = y + 2

Make y the subject

y = x - 2

So, we have:

g(x) = x - 2

So, the functions are:

f(x) = x + a/b ⇒ f(x) = x + 4/2

g(x) = cx − d ⇒ g(x) = x - 2

Show that the functions are inverse functions

In (a), we have:

f(x) = x + 4/2

g(x)= x - 2

If the functions are inverse functions, then:

f(g(x)) = x

We have:

f(x) = x + 4/2

This gives

f(g(x)) = g(x) + 4/2

This gives

f(g(x)) = x - 2 + 4/2

Evaluate

f(g(x)) = x

Evaluate g(f(x))

In (a), we have:

f(x) = x + 4/2

g(x)= x - 2

We have:

g(x)= x - 2

This gives

g(f(x)) = f(x) - 2

This gives

g(f(x)) = x + 4/2 - 2

Evaluate

g(f(x)) = x

Graph the functions

See attachment for the graph

The table of values is:

x    f(x)    g(x)

0    2     -2

1     3      -1

2    4       0

3    5      1

4    6      2

Radical equations

Create the equations

The form of the equations is given as:

[tex]a\sqrt{x + b} + c= d[/tex]

So, we have:

[tex]\sqrt{4x + 5} + 1 = 0[/tex] --- has extraneous solution

[tex]2\sqrt{3x - 1} + 2 = 8[/tex] --- has no extraneous solution

The equation solution

Equation 1 with extraneous solution

[tex]\sqrt{4x + 5} + 1 = 0[/tex]

Subtract 1 from both sides

[tex]\sqrt{4x + 5} = -1[/tex]

Square both sides

4x + 5 = 1

Evaluate the like terms

4x = -4

Divide by 4

x = -1

Substitute x = -1 in [tex]\sqrt{4x + 5} + 1 = 0[/tex] to check

[tex]\sqrt{4(-1) + 5} + 1 = 0[/tex]

[tex]\sqrt{-4 + 5} + 1 = 0[/tex]

[tex]\sqrt{1} + 1 = 0[/tex]

Evaluate the root

[tex]1 + 1 = 0[/tex]

[tex]2= 0[/tex] --- false

Equation 2 without extraneous solution

[tex]2\sqrt{3x - 1} + 2 = 8[/tex]

Subtract 2 from both sides

[tex]2\sqrt{3x - 1} = 6[/tex]

Divide by 2

[tex]\sqrt{3x - 1} = 3[/tex]

Square both sides

3x - 1 = 9

Evaluate the like terms

3x = 10

Divide by 3

x = 10/3

Substitute x = x = 10/3 in [tex]2\sqrt{3x - 1} + 2 = 8[/tex] to check

[tex]2\sqrt{3 * \frac{10}{3} - 1} + 2 = 8[/tex]

[tex]2\sqrt{10 - 1} + 2 = 8[/tex]

[tex]2\sqrt{9} + 2 = 8[/tex]

Evaluate the root

[tex]2*3 + 2 = 8[/tex]

[tex]8 = 8[/tex] --- true

Why the equations have (or do not have) an extraneous solution

The first equation has an extraneous solution because the solution is false for the original equation and the second does not have an extraneous solution because the solution is true for the original equation

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Part 1. Using The Two Functions Listed Below, Insert Numbers In Place Of The Letters A, B, C, And D So

Related Questions

Mary wants to fence in a rectangular run for her dogs. She has decided that the run will be 5 yards wide. A rectangle with a width of 5 yards and height of x. Which statement best describes the possible lengths of the run if she can use no more than 40 yards of fencing? at most 8 yards at most 15 yards more than 8 yards more than 15 yards Mark this and return

Answers

The length of the run is at most 15 yards

How to determine the true statement?

The given parameters are:

Width = 5 yards

Height = x

Perimeter = Not more than 40 yards

The perimeter is calculated as:

P  = 2 *(Width + Height)

So, we have:

2 *(5 + x) ≤40

Divide by 2

5 + x ≤ 20

Subtract 5 from both sides

x ≤ 15

This implies that the length of the run is at most 15 yards

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(LOOK AT IMAGE)
A regular 8-sided polygon and a regular 10-sided polygon share a single side, as shown below. Calculate the size of the angle marked b. Give your answer in degrees (°). ​

Answers

Answer: 9

Step-by-step explanation:

The interior angle of the 8-sided polygon is

[tex]\frac{180(8-2)}{8}=135^{\circ}[/tex]

The interior angle of the 10-sided polygon is

[tex]\frac{180(10-2)}{10}=144^{\circ}[/tex]

Taking the difference, we get [tex]b=9^{\circ}[/tex]


y = 4x - 10
y = 2
What is the solution to the system of equations?
(3, 2)
(2, 3)
(-2, 2)
(2,-2)

Answers

Answer:

x= 3

y=2

Step-by-step explanation:

Let's solve your equation step-by-step.

2=4x−10

Step 1: Flip the equation.

4x−10=2

Step 2: Add 10 to both sides.

4x−10+10=2+10

4x=12

Step 3: Divide both sides by 4.

4x/4=12/4

x=3

Answer:

since y=2 substitute y into y=4x-10

2=4x-10

2+10=4x

12=4x

Divide both sides by 4

12/4=4x/4

x=3

Therefore the answer is (2,3)

Check

y= 4x-10

2= 4×3-10

2= 12-10

2=2

If n(A) equals 100 and n(B) is equals to 120 and A is the subset of B, find the value of an n(A union B)

Answers

Answer:

200

Step-by-step explanation:

Solution,

Given,

n(A)=100

n(B)=120

A⊂B

n(A∩B)=20

n(A∪B)=n(A)+n(B)-n(A∩B)

n(A∪B)=100+120-20

n(A∪B)=200

n(A union B) is equal to the number of elements in set B, which is 120.

How to find n(A union B)

If A is a subset of B, it means that every element in set A is also an element of set B.

In this case, n(A) represents the number of elements in set A, which is 100, and n(B) represents the number of elements in set B, which is 120.

To find the value of n(A union B) (the number of elements in the union of sets A and B), we need to consider that the union of two sets includes all the elements that are in either set A or set B, or both.

Since A is a subset of B, all the elements in set A are already included in set B. Therefore, the union of sets A and B will be equal to set B itself.

Thus, n(A union B) is equal to the number of elements in set B, which is 120.

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How do I solve quadratic equations for example,h(t) = – 0.07t2 + 0.007t + 5

Answers

Answer:

  x ≈ -8.402, 8.502

Step-by-step explanation:

The usual methods of solving quadratic equations apply to this one. Any of them can be used: graphing, factoring, completing the square, quadratic formula.

Solution

Often, when the coefficients are non-integers and have no obvious relationship to each other, the most convenient method of solution is the quadratic formula. It tells you the solution to ax²+bx+c=0 is ...

  [tex]x=\dfrac{-b\pm\sqrt{b^2-4ac}}{2a}[/tex]

Your equation has the coefficients, a = -0.07, b = 0.007, c = 5, so the solutions are ...

  [tex]x=\dfrac{-0.007\pm\sqrt{0.007^2-4(-0.07)(5)}}{2(-0.07)}=\dfrac{-0.007\pm\sqrt{1.400049}}{-0.14}\\\\x=0.05\pm\sqrt{\dfrac{200007}{2800}}=0.05\pm\sqrt{71.4310\overline{714285}}\\\\\boxed{x\approx\{-8.40169,\,8.50169\}}[/tex]

Answer:

[tex]t=8.50, -8.40\:\: \sf (2 \:d.p.)[/tex]

Step-by-step explanation:

Quadratic equations are in the form [tex]ax^2+bx+c=0[/tex],  where [tex]a\neq 0[/tex].

There are three basic methods to solve quadratic equations algebraically:

FactoringCompleting the SquareQuadratic Formula

Given quadratic equation:

[tex]h(t)=-0.07t^2+0.007t+5[/tex]

Method 1 - Factoring

If the trinomial is able to be easily factored, set the equation equal to zero and factor.  Set each factor equal to zero and solve.

As the given example is not easily factored, factoring is not the best method to use on this occasion.

Method 2 - Completing the Square

If the quadratic expression is not able to be easily factored, try completing the square.

Divide all terms by [tex]a[/tex] (-0.07):

[tex]\implies t^2-\dfrac{1}{10}t-\dfrac{500}{7}=0[/tex]

Move the constant to the right side:

[tex]\implies t^2-\dfrac{1}{10}t=\dfrac{500}{7}[/tex]

Add the square of half the coefficient of t to both sides:

[tex]\implies t^2-\dfrac{1}{10}t+\left(-\dfrac{1}{20}\right)^2=\dfrac{500}{7}+\left(-\dfrac{1}{20}\right)^2[/tex]

[tex]\implies t^2-\dfrac{1}{10}t+\dfrac{1}{400}=\dfrac{200007}{2800}[/tex]

Factor the perfect trinomial:

[tex]\implies \left(t-\dfrac{1}{20}\right)^2=\dfrac{200007}{2800}[/tex]

Square root both sides:

[tex]\implies t-\dfrac{1}{20}=\pm\sqrt{\dfrac{200007}{2800}[/tex]

Add 1/20 to both sides:

[tex]\implies t=\dfrac{1}{20}\pm\sqrt{\dfrac{200007}{2800}[/tex]

As decimals to 2 decimal places:

[tex]\implies t=8.50, -8.40\:\:\sf(2 \:d.p.)[/tex]

Method 3 - Quadratic Formula

[tex]x=\dfrac{-b \pm \sqrt{b^2-4ac} }{2a}[/tex]

This can be used to find both real and imaginary or complex solutions.

Identity the variables:

[tex]a=-0.07, \quad b=0.007, \quad c=5[/tex]

Substitute the values into the quadratic formula and solve for t:

[tex]\implies t=\dfrac{-0.007 \pm \sqrt{0.007^2-4(-0.07)(5)} }{2(-0.07)}[/tex]

[tex]\implies t=\dfrac{-0.007 \pm \sqrt{1.400049}}{-0.14}[/tex]

[tex]\implies t=\dfrac{0.007 \pm \sqrt{1.400049}}{0.14}[/tex]

[tex]\implies t=8.50, -8.40\:\: \sf (2 \:d.p.)[/tex]

Finally, a non-algebraic method of solving a quadratic equation is by graphing using a graphical calculator (see attached).  The solutions are the points at which the curve intercepts the x-axis.

Micaela has a bat that is 30 inches long. She wants to fit it in a cube shaped box that has sides that are 17 inches. Will the bat fit? Justify your answer

Answers

The bat will not fit in the cube shaped box

How to determine if the bat will fit?

The side length of the cube is given as:

x = 17

The diagonal of the cube is calculated as

[tex]d = x\sqrt 3[/tex]

So, we have:

[tex]d = 17\sqrt 3[/tex]

Evaluate

d = 29.4

29.4 is less than the length of the bat (30 inches)

This means that the bat will not fit in the cube shaped box

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Fernando and Maria are at opposite sides of a park. They plan to meet later at a fountain that is located somewhere between them. Maria will arrive at the fountain first, before Fernando even leaves his starting location. The ratio of Maria's starting location to the fountain to Fernando's starting place is 5:3. What is the location of the fountain? Round to the nearest tenth, if necessary.

(, )

Answers

The location of the fountain based on the information given is (-1, 0.5).

How to illustrate the location?

From the graph, the coordinates are (4, 2) and (-4,   -2).

The ratio is given as 5:3.

The coordinates of the fountain will be:

[(5 × -4 + 3 × 4)/(5 + 3), (5 × -3 + 3 × 2)/(5 + 3)]

= (-1, -0.5)

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Which model represents the factors of 4x^2-9

Answers

The model (x+a)(x-a) will represents the factors of 4x²-9 as (2x+3)(2x-3).

What are the quadratic equations in one variable completing the squares method?

The "completing the squares" method aims to construct a quadratic equation of the form where the x variable is entirely covered by a single squared term, which is the square of a linear expression in x, as the name suggests.

The quadratic equation can resemble this:

x²-a² = (x+a)(x-a)

Given equation;

⇒4x²-9

⇒(2x)²-3²

The equation can be modeled as;

(2x+3)(2x-3)

Hence the model (x+a)(x-b) will represents the factors of 4x²-9 as (2x+3)(2x-3).

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An italian restaurant receive a shipment of 86 veal cutlet.if it takes to make a dish,how many cutlet will the restaurant have left over after making as many dishes as possible?

Answers

Answer:

They have none left over and they can make 43 dishes

Step-by-step explanation:

The triangles are similar. If WZ = 15, ZY = 12, and XY = 11, find WV. Round to the nearest tenth.

Answers

Answer:

13.8

Step-by-step explanation:

because they're similar, we know that

zy ÷ wz has the same ratio as xy ÷ wv

12 / 15 = 11 / wv

cross multiply

12wv = 165

÷ 12     ÷12

wv = 13.75

13.75 rounded to nearest tenth is 13.8

Antonio graphs these equations and finds that the lines intersect at a single point,
(-5, 0.25).
Equation A: 4y-3x=16
Equation B: -x-8y=3

which statement is true about the values of x=-5 and y=0.25?

Answers

Option B is correct. The statement that is true about the values we have been given here is that They are the only values that make both equations true.

How to solve for the equations

We have been given two equations

The first equation is

4y-3x=16

We have to plug in the values (-5, 0.25) in this equation

4(0.25) -3(-5) =16

Then we have

1 + 15 = 16

Hence 16 = 16 This satisfies the equation.

In the second equation we have to follow the same step

-x-8y=3

Such that

-(-5)-8*0.25 = 3

5-2 = 3

3 = 3 This also satisfies the equation.

Therefore the correct answer option is B

Complete question

a. They satisfy equation 8 but not equation A.

B. They are the only values that make both equations true.

C. They show that the equations represent the same line.

D. They satisfy equation A but not equation B.

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The price of a roll of fabric is reduced by 20%
to £60.
What was its original price?

Answers

The original price is £75

How to determine the original price?

Let the original price be x.

The reduced price is given as:

Reduced =60

So, we have:

Reduced = Original price * (1 - discount)

This gives

x * (1- 20%) = 60

Evaluate the difference

x * 0.8 = 60

Divide by 0.8

x = 75

Hence, the original price is £75

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Ten out of 50 participants scored between 65 and 75 on a test. What is the relative frequency of the class interval 65-75

Answers

The relative frequency of the class interval 65-75 is .20.

What is relative frequency?

The word 'relative' is used to indicate that an event is being considered in relation or in proportion to something else.

Frequency is a way to measure how often a particular event occurs. Relative frequency, on the other hand, is a way to measure how often a particular event occurs against total occurrences.

Given that: 50 participants scored between 65 and 75 on a test.

Hence,

The relative frequency of the class interval 65-75 = 75 - 65 = 20

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P is a rectangle with a length of 40 cm and a width of x cm q is a rectangle with a width of y cm the length of q is 25% more than the length of p the area of q is 10% less than the area of p work out the ratio of x:y

Answers

In rectangles P and Q, where the area of rectangle Q is 10% less than the area of rectangle P, we have the ratio of x:y = 25:18.

The area of a rectangle is the product of its length and its width.

In the question, we are given two rectangles:-

Rectangle P:

length = 40 cm,

width = x cm,

Thus, the area = length * width = 40x.

Rectangle Q:

length = 25% more than the length of P = 40 + 25% of 40 = 40 + 0.25*40 = 40 + 10 = 50 cm.

width = y cm,

Thus, the area = length * width = 50y.

Now, we are given that, the area of rectangle Q is 10% less than the area of rectangle P.

Thus, we can write that,

Area of rectangle Q = Area of rectangle P - 10% of the area of rectangle P,

or, 50y = 40x - 10% of 40x,

or, 50y = 40x - 0.10*40x,

or, 50y = 40x - 4x,

or, 50y = 36x,

or, y = 36x/50.

We are asked to find the ratio of x:y = x/y.

Substituting y = 36x/50, we get,

x/y = x/(36x/50) = 50x/36x = 25/18.

Thus, the ratio x:y = 25:18.

Thus, in rectangles P and Q, where the area of rectangle Q is 10% less than the area of rectangle P, we have the ratio of x:y = 25:18.

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Use the following information to answer the question.

Triangle ABC has side lengths AB=16, BC=13, and AC=7.
Triangle DEF has side lengths DE=4, EF=3.25, and DF=1.75.
Janna needs to prove △ABC∼△DEF.

Which methods can she use to help her prove the triangles are similar by the SSS Similarity Theorem?

Select all that apply.
(The choices are in the image)

Answers

For Janna to prove that △ABC∼△DEF by the SSS similarity theorem, she will use: B. DE/AB = EF/BC = DF/AC = 1/4.

What is the SSS Similarity Theorem?

According to the SSS similarity theorem, if the ratio of the corresponding sides of two triangles are equal, then both triangles are similar.

The ratio of the corresponding sides of the triangles given are:

DE/AB = 4/16 = 1/4

EF/BC = 3.25/13 = 1/4

DF/AC = 1.75/7 = 1/4

Therefore, what Janna needs is:

B. DE/AB = EF/BC = DF/AC = 1/4

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Which pair of equations generates graphs with the same vertex?

Answers

The pair of equations that generates graphs with the same vertex is

B) y = –4x2 and y = 4x2

What is vertex ?

A vertex serves as  angular point that allows the meeting of two or more lines .

To express a quadratic equation we can use :

[tex][y = a(x - h) ^{2} + k][/tex]

where vertex is (-h , k)

If we look at first option, the the vertices are  [tex](-4 , 0) and (4 , 0)[/tex]

Then the second option, graphs' vertices are the same thing which is ,[tex](0 , 0).[/tex]

Therefore, the pair of equations that generates graphs with the same vertex is B) y = –4x2 and y = 4x2

CHECK THE COMPLETE QUESTION BELOW:

Which pair of equations generates graphs with the same vertex?

A) y = –(x + 4)2 and y = (x – 4)2

B) y = –4x2 and y = 4x2

C) y = –x2 – 4 and y = x2 + 4

D) y = (x – 4)2 and y = x2 + 4

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Please help ill give whoever answers the best the brainliest answer :))

Answers

Answer:

Step 3 is wrong and the answer should be 576

Step-by-step explanation:

Step 1 and step 2 are correct

Step 2: 4 × 12^2

You don't multiply 12 by 4, you first complete the exponent since, in PEMDAS, Exponent is before Multiplying.

Step 3 should be: 4 × (12×12)

= 4 × 144

= 576

Farmers Jay, Peter and Sam own rectangular farms, as indicated in the figure. Jay owns 2 acres of land, Peter owns 4 acres and sam owns 6 acres. Find the areo of the comman pasture

Answers

The area or the common pasture will be 12 acres.

How to calculate the area?

Based on the information given, the formula to use will be:

ab/ac = 2/4

b/c = 1/2 .... i

Also, ab/bd = 2/6

a/d = 1/3 .... ii

Multiply both equation

1/2 × 1/3 = 1/6

Therefore, the area will be

= 6 × 2

= 12 acres

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Verbal
4. Are one-to-one functions either always increasing or
always decreasing? Why or why not?

Answers

Answer:

If a function is continuous and one - to - one then it is either always increasing or always decreasing.

Step-by-step explanation:

An easy way to see this on a graph is to draw a horizontal line through the graph . If the line only cuts the curve once then the function is one - to - one.

Answer:

If a one-to-one function is not continuous, it is sometimes increasing or decreasing. If a one-one function is continuous, it is always increasing or always decreasing.

For example, if [tex]$f(x)=\left\{\begin{array}{lll}-x & \text { if } & |x| \geq 1 \\ x & \text { if } & |x| < 1\end{array}\right.$[/tex]

This function is one-to-one and it is not always increasing or decreasing.

Step-by-step explanation:

A statement that are one-to-one functions either always increasing or always decreasing is given.

It is required to explain the given condition.

To explain the given condition, consider a continuous and a not continuous function then explain about the one-to-one function.

If a one-to-one function is not continuous, it is sometimes increasing or decreasing.

For example, if [tex]$f(x)=\left\{\begin{array}{lll}-x & \text { if } & |x| \geq 1 \\ x & \text { if } & |x| < 1\end{array}\right.$[/tex]

This function is one-to-one and it is not always increasing or decreasing.

If a one-one function is continuous, it is always increasing or always decreasing.

For example, if f(x)=x-3. It is a continuous function and it reaches a minimum value at some values of x and it then keeps increasing.

There will be the same output value for different input values. It does not pass the horizontal line test and so it is not a one-to-one function.

the table shows a proportional relationship between the distance a snall travels and the time it takes what is the proportional constant in centimeters per minute

Answers

The constant of proportionality in centimeters per minute is: 5.5.

How to Find the Constant of Proportionality?

To find the constant of proportionality of the table shown in the image attached below, use one pair of points, (12, 66).

Constant of proportionality, k = y/x, therefore, the proportional constant in centimeters per minute would be:

k = 66/12 = 5.5 cm per min.

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Rectangle ABCD is rotated 180°. What rule shows the input and output of the rotation, and what is the new coordinate of A′?

Answers

If A was placed at (-5,1) and was rotated to 180 degrees. I belive it would be (-5,1)

Could use some Geometry help

Answers

I am not 100% sure but I think it is 85 degrees

DO NOT take my word for it

Step-by-step explanation:

I'm not sure but I think it is 75 degree

5. The perimeter of a room is measured and found
to be 652 inches. Trim for the room is sold by
the foot. How many feet of trim must be
purchased so that the room can be trimmed?
(A) 50 ft
(B) 54 ft
(C) 55 ft
(D) 60 ft

Answers

Answer: C

Step-by-step explanation:

12in is 1 ft

652/12 is 54r4

so atlease 55

What QUANTITY does 25.0 m represent?
length
millimeters
meters
milliliters

Answers

Answer:

Step-by-step explanation:

m represents the meters.

Question 5
Sam wants to build a toy box in the shape of a rectangular prism that will
hold 36 cubic feet. If the height needs to be 1 foot less than the width and
the length is twice the width, find the height of the toy box.

Answers

Considering the volume of the given rectangular prism, the height is of 5.03 feet.

What is the volume of a rectangular prism?

The volume of a rectangular prism of length l, width w and height h is given by:

V = lwh.

In this problem, we have that:

h = w - 1 -> w = h + 1.l = 2w = 2(h + 1) = 2h + 2.

The volume is of 365 cubic feet, hence:

lwh = 365

(2h + 2)(h + 1)h = 365

(2h² + 4h + 2)h - 365 = 0

2h³ + 4h² + 2h - 365 = 0.

Using a cubic equation calculator, the height is of h = 5.03 feet.

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Find the area of the trapezoid

Answers

Answer:

294.84 ft²

Step-by-step explanation:

A = (B + b)h/2

A = (28.5 ft + 18.3 ft)(12.6 ft)/2

A = 294.84 ft²

Answer: 294.84 ft^2

Step-by-step explanation:

Area of trapezoid=((a+b)/2)*h

here

a=28.5 ft

b=18.3 ft

h=12.7 ft

Area=((28.5+18.3)/2)*(12.7)

Area=294.84 ft^2

Triangles G H L and K H J are connected at point H. Angles Angles L G H and H K J are congruent. Sides G H and H K are congruent.

Which congruency theorem can be used to prove that △GHL ≅ △KHJ?
SSS
ASA
SAS
AAS

Answers

The congruence theorem that can be used is: B. ASA

What is the ASA Congruence Theorem?

If we have two triangles that have two pairs of corresponding congruent angles (e.g. ∠LGH ≅ ∠HKJ and ∠LHG ≅ ∠KHJ), and a pair of corresponding congruent sides (e.g. GH ≅ HK), the triangles are said to be congruent triangles by the ASA congruence theorem.

Therefore, triangles GHL and KHL in the image given are congruent triangles by the  ASA congruence theorem.

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Answer: Option 2 or B. ASA

Step-by-step explanation: Trust me!

If you are working on Edge the answer is correct. The proof is down below. I hope someone finds this helpful. Good luck everyone!  :)

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Ella completed the following work to test the equivalence of two expressions.


2 f + 2.6. 2 (0) + 2.6. 0 + 2.6. 2.6. 3 f + 2.6. 3 (0) + 2.6. 0 + 2.6. 2.6.


Which is true about the expressions?

The expressions are equivalent because Ella got different results when she substituted zero for f.

The expressions are equivalent because Ella got the same result when she substituted zero for f.

The expressions are not equivalent because Ella would get different results when substituting different numbers for f.

The expressions are not equivalent because Ella would get the same results when substituting different numbers for f.

Answers

The expressions are not equivalent, even though Ella got the same result when she substituted zero for f. Then the correct option is C.

What is an equivalent expression?

The equivalent is the expressions that are in different forms but are equal to the same value.

Ella completed the following work to test the equivalence of two expressions.

First expression,                Second expression

⇒ 2f + 2.6                           ⇒ 3f + 2.6

⇒ 2(0) + 2.6                       ⇒ 3 (0) + 2.6

⇒ 0 + 2.6                           ⇒ 0 + 2.6.

⇒ 2.6                                 ⇒ 2.6

The expressions are not equivalent, even though Ella got the same result when she substituted zero for f.

Then the correct option is C.

The complete question is attached below.

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Miguel's coffee shop makes a blend that is a mixture of two types of coffee. Type A coffee costs Miguel $ per pound, and Type B coffee costs $ per pound. This month's blend used three times as many pounds of Type B coffee as Type A, for a total cost of $. How many pounds of Type A coffee were used

Answers

The amount of Type A coffee that was used is 40 pounds.

From the given information;

Type A coffee costs Miguel $5.95 per pound

Type B coffee costs $4.65 per pound.

For this month, the equation can be expressed as:

A + 3A

Thus;

5.95A + 3(4.65)A = 796.00

5.95A +13.95A = 796.00

19.9A = 796.00

A = 796.00/19.9

A = 40

Therefore, we can conclude that the amount of pounds of type A coffee that was used is 40 pounds.

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Come up with two examples of ratio relationships that are interesting to you.

In mathematics a ratio is a comparison of two or more numbers that indicates their sizes in relation to each other

Answers

Answer:

1:3 is an example and for every two boy there are 5 girls is another example

Edited: I go out Five times as much as My sister does. My sister goes out only 3 times. Which is 15:1

I see 5 blue cars for every 6 red cars. Which is 5:6

Ratio is always represented in terms of ':' like a:b

Examples

#1

Sam has 2 apples Jane has 4 apples

The ratio of apples is 2:4 or 1:2

#2

dummy stars present at your home =10Stars present in Big dipper =7

The ratio is 10:7

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