Paano ka makaka tulong sa upang maiwasan ang suliranin ukol sa climate change

Answer:

zero(0)

Explanation:

if a molecule is moving along a straight path, there is zero rotational speed and that component give zero moment in the direction of the molecule's driving force

The ratio of total rotational kinetic energy to the total translational kinetic energy is 3 : 2. Thus, the rotational kinetic energy of oxygen with translational kinetic energy of 15 J is 10 J.

Rotational kinetic energy is the energy generated by virtue of the rotational motion of a molecule. The degree of freedom of a compound or molecules is the sum of its translational degree of freedom,  rotational degree of freedom and vibrational degree of freedom.

For a diatomic molecule, there are three translational degrees of freedom along x, y and z directions. Similarly there will be two rotational degree of freedom along the molecular axis.

The ratio of rotational degree of freedom to that of translational motion is 3/2.

Thus Te / Re = 3/2

          15 J/ Re = 3/2

Rotational kinetic energy Re = 30/3 =10 J.

Therefore, the rotational kinetic energy oxygen would be 10 J.

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#SPJ2

Answer:

Capacitor is a device which used to store energy .

Capacitance is the ratio of the change in an electric charge in a system to the corresponding change in its electric potential.

Explanation:

Answer:

F net ∞ [tex]\frac{1}{\sqrt{t} }[/tex]

Explanation:

In pic

_________________

(hopet his helps can I pls have brainlist (crown)☺️)

Answer:

Explanation:

Start with Carbon and assume we only get 1 sugar molecule from the process.

you have 6 carbons in the sugar on the right, so you need 6 carbons on the left which only come from CO₂

6 CO₂

you have 12 hydrogen atoms in the sugar on the right, so you need 12 hydrogen atoms on the left which only come from H₂O. At 2 hydrogen atoms per water molecule means you need 6 waters.

6 CO₂ + 6 H₂O → 1 C₆H₁₂O₆

you are supplied with 12 oxygen from the CO₂ and 6 oxygen from the H₂O, but you only need 6 oxygen for the sugar. That means there are 12 oxygen remaining which will become 6 O₂ molecules

6 CO₂ + 6 H₂O → 1 C₆H₁₂O₆ + 6 O₂

The work and energy theorem allows finding the result for where the kinetic energy of the car is before stopping is:

    The energy becomes:

Work is defined by the scalar product of force and displacement.

          W = F . d

Where the bold indicate vectors, W is work, F is force and d is displacement.

The work energy theorem relates work and kinetic energy.

            W = ΔK = [tex]K_f - K_o[/tex]

In this case the vehicle stops therefore its final kinetic energy is zero, consequently the work is:  

          W = - K₀

Therefore, the initial kinetic energy that the car has is converted into work in its brakes.  In reality, if assuming that there is friction, an important part is transformed into non-conservative work of the friction force, this work can be seen in a significant increase in the temperature of the discs on which the work is carried out.

In conclusion, using the work-energy theorem we can find the result for where the kinetic energy of the car is before stopping is:

    The energy becomes:

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The heat released by the aluminum during the process is [tex]3.6 \times 10^6 \ J[/tex].

The given parameters:

The heat released by the aluminum during the process is calculated as follows;

[tex]Q = mc \Delta t \\\\Q = 1.5\times 900 \times (2700 - 23)\\\\Q = 3.6 \times 10^6 \ J[/tex]

Thus, the heat released by the aluminum during the process is [tex]3.6 \times 10^6 \ J[/tex].

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Answer:

what is the full questio n because I can't see the momentum

The increase in the temperature of the soil when bag fall from the given height is 0.065 ⁰C.

The given parameters:

Apply the principle of conservation of energy as follows;

[tex]mgh = mC \Delta T\\\\gh = C \Delta T\\\\\Delta T= \frac{gh}{C}[/tex]

Convert the value of C in kcal/kg ⁰C  to  J/kg ⁰C

1 kcal = 4180 J

[tex]0.200 \ kcal/kg ^0 C= 0.2 \times 4180 (J/kg ^0C) = 836 \ J/kg^0 C[/tex]

The increase in the temperature of the soil is calculated as follows;

[tex]\Delta T= \frac{gh}{C}\\\\\Delta T= \frac{9.8 \times 5.5}{836} \\\\\Delta T= 0.065 \ ^0C[/tex]

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Answer:

Ok thanks for the points though

Explanation:

Answer:

Explanation:

The density of a substance can be found by using the formula

[tex]d = \frac{m}{v} \\ [/tex]

m is the mass

v is the volume

From the question

m = 200g

v = 100 mL

We have

[tex]d = \frac{200}{100} = 2 \\ [/tex]

We have the final answer as

Hope this helps you

Answer:

Explanation:

ASSUMING the 52° is the angle of incidence measured from the perpendicular to the surface

          n₁sinθ₁ = n₂sinθ₂

          1 sin52 = 1.33sinθ₂

                  θ₂ = arcsin(sin52 / 1.33)

                  θ₂ = 36°

as measured from the perpendicular to the surface

The characteristics of the speed of the traveling waves allows to find the result for the tension in the string is:  

         T = 10 N

The speed of a wave on a string is given by the relationship.

      v =[tex]\sqrt{\frac{T}{\mu } }[/tex]

Where   v es the velocty, t is the tension ang μ is the lineal density.

They indicate that the length of the string is L = 2.28 m and the pulse makes 4 trips in a time of t = 0.849 s, since the speed of the pulse in the string is constant, we can use the uniform motion ratio, where the distance traveled e 4 L

           v = [tex]\frac{d}{t}[/tex]  

           v = [tex]\frac{4 L}{t}[/tex]  

           v = [tex]\frac{4 \ 2.28 }{0.849}[/tex]  

            v = 10.7  m / s

Let's find the linear density of the string, which is the length of the mass divided by its mass.

            μ = [tex]\frac{m}{L}[/tex]  

            [tex]\mu = \frac{0.2}{2.28}[/tex]  

            μ = 8.77 10⁻² kg / m

The tension is:

        T = v² μ

Let's calculate

        T = 10.7²  8.77 10⁻²

        T = 1 0 N

In conclusion using the characteristics of the velocity of the traveling waves we can find the result for the tension in the string is:

         T = 10 N

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Answer: the answer is D if its not i'm really sorry

Please find attached photograph for your answer.

Hope it helps.

Do comment if you have any query.

Answer:

potential energy = mgh

= 400÷1000 × 10× 4÷100

= 0.4 × 10 × 0.04

=4/10 ×10×4/100

= 4/10 × 4/10

=16/100

= 0.16 joules

m1 (400) stretches 4cm

m1 (100g) stretches 1cm

so, m2(800g) stretches 8 cm

potential energy of m2 = mgh

= 800/1000 ×10×8/100

= 0.8 × 0.8

=8/10 ×8/10

= 64/100

=0.64 joules

Ratio of s1 to s2

16/100 ÷ 64/100

= 1:4 ( answer)

How to find g (acceleration due to gravity)

We know,

Acceleration due to gravity (g)

[tex] = \frac{GM}{ {R}^{2} } [/tex]

where, G = Gravitational constant

[tex] = 6.67 \times {10}^{11} N {m}^{2}/k {g}^{2} \\ [/tex]

M = Mass of the earth

[tex] = 6 \times {10}^{24} \: kg[/tex]

R = Radius of the earth

[tex] = 6.4 \times {10}^{6} m[/tex]

Putting these values of G, M and R in the above formula, we get

[tex]g \: = \: \frac{6.67 \times {10}^{11} N {m}^{2}/k {g}^{2} \times \: 6 \times {10}^{24} \: kg }{(6.4 \times {10}^{6}m {)}^{2} } \\ = 9.8m/ {s}^{2} [/tex]

So, the value of acceleration due to gravity is

[tex]9.8m/s ^{2} [/tex]

Hope it helps.

Do comment if you have any query.

Answer:

A5 A20 A32 5G A1 G A20 5G T mOBIL

Answer:

B. The light bulb shines brighter and the power increases.

Explanation:

Power is the product of voltage and current . Increasing the current at a constant voltage will increase the power.

Increasing the power means more heat and therefore more light must be emitted.

The length of the ship in terms of Emily's equal steps is 84.

The given parameters;

Defined parameters:

The velocity of Emily when moving forward in the direction of the ship:

[tex]V_s_1 = \frac{210}{t}[/tex]

The velocity of Emily when moving in opposite direction to the ship:

[tex]V_s_2 = \frac{42}{t}[/tex]

The constant velocity of the ship:

[tex]V = \frac{d}{t}[/tex]

Apply relative velocity formula to determine the length of the ship:

For forward (same direction) motion:

[tex](V_s_1 - V)t = d[/tex]

For backward (opposite direction) motion:

[tex](V_s_2 + V)t = d[/tex]

[tex](V_s_1 - V)t = (V_s_2 + V)t\\\\V_s_1 - V = V_s_2 + V\\\\\frac{210}{t} - \frac{d}{t} = \frac{42}{t} + \frac{d}{t} \\\\\frac{210}{t} - \frac{42}{t} = \frac{d}{t} + \frac{d}{t} \\\\\frac{210 - 42}{t} = \frac{d+ d}{t} \\\\\frac{168}{t} = \frac{2d}{t} \\\\2d = 168\\\\d = \frac{168}{2} \\\\d = 84[/tex]

Thus, we can conclude that the length of the ship in terms of Emily's equal steps is 84.

"Your question is not complete, it seems to be missing the following information;"

Emily sees a ship traveling at a constant speed along a straight section of a river. She walks parallel to the riverbank at a uniform rate faster than the ship. She counts 210 equal steps walking from the back of the ship to the front. Walking in the opposite direction, she counts 42 steps of the same size from the front of the ship to the back. In terms of Emily's equal steps, what is the length of the ship

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Answer:

In hydrogeology, groundwater flow is defined as the "part of streamflow that has infiltrated the ground, entered the phreatic zone, and has been (or is at a particular time) discharged into a stream channel or springs; and seepage water." It is governed by the groundwater flow equation.

Consult the attached free body diagram.

If we take the direction of F to be the positive horizontal axis, and upward to be the positive vertical axis, then using Newton's second law we have net forces

• ∑ F [horizontal] = F [archer] + T cos(180° - θ) + T cos(180° + θ) = 0

• ∑ F [vertical] = T sin(180° - θ) + T sin(180° + θ) = 0

since the bow is held in place while it's drawn. T is the magnitude of the tension in the string, and it can be shown to be equal in both strings since they both make the same angle with the negative horizontal axis (the dashed line).

We only really need the first equation. Simplifying it, we get

F [archer] - T cos(θ) - T cos(θ) = 0

F [archer] - 2T cos(θ) = 0

F [archer] = 2T cos(θ)

cos(θ) = F [archer] / (2T)

We're given that the tension T in the string is 0.842 times the force exerted by the archer, which is to say

T = 0.842 F [archer]

and from this we have

cos(θ) = F [archer] / (2 • 0.842 F [archer])

cos(θ) = 1/1.684

cos(θ) ≈ 0.593

Solving for θ gives an angle of θ ≈ arccos(0.593) ≈ 53.6°. Then the angle between the two tension forces is twice this, or about 2θ ≈ 107°.

Explanation:

[tex]if \: the \: masses \: of \: the \:two \: marbles\: equal \\ then \: each \: velocity \: sharing \: with \: other \: velocity[/tex]

This question involves the concepts of density, volume, and mass.

(a) The volume occupied by this amount of water is "90 m³".

(b) The length of an edge of each small cube is "83 μm".

(c) The length of the edge of each small cube is "equal" to the diameter of a molecule.

(a)

The volume can be found using the following formula:

[tex]V = \frac{nM}{\rho}[/tex]

where,

V = volume occoupied = ?

n = no. of moles = 5 mol

M = molar mass = 18 g/mol

[tex]\rho[/tex] = density of water = 1 g/m³

Therefore,

[tex]V=\frac{(5\ mol)(18\ g/mol)}{1\ g/m^3}\\\\[/tex]

V = 90 m³

(b)

First, we will find the volume of an individual molecule:

[tex]V_i =\frac{V}{nN_A}[/tex]

where,

[tex]N_A[/tex] = Avogadro's number = 6.02 x 10²³ molecules/mol

Therefore,

[tex]V_i=\frac{90\ m^3}{5\ mol(6.02\ x\ 10^{23}\ molecules/mol)}[/tex]

Vi = 3 x 10⁻²³ m³

This volume can be given as a volume of the sphere:

[tex]V_i=\frac{4}{3}\pi r^3\\\\r=\sqrt[3]{\frac{3(3\ x\ 10^{-23}\ m^3)}{4\pi}}[/tex]

r = 4.15 x 10⁻⁷ m

Diameter = d = 2r = 2(4.15 x 10⁻⁷ m)

d = 8.3 x 10⁻⁷ m = 83 μm

since the cubes are adjacent to each other. Therefore, the diameter will be equal to the edge length.

Edge Length = L = d

L = 8.3 x 10⁻⁷ m = 83 μm

(c)

The edge length is equal to the diameter of the molecule.

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Answer:

Groundwater Returning to earths Surface come Up Though A drought

Explanation:

THIS DOES NOT NEED TO BE EXPLAINED IT'S EZZZ

Answer:

A

Explanation:

for every action there is an equal and opposite reaction