Answer:
c) H2O and HSO4-
Explanation:
The dehydration of 2-methylcyclohexanol occurs in the presence of H2SO4. Recall that acids are proton donors in solution; the equilibrium shown below is then set up,
H2SO4(aq) + H2O(l) ⇄H3O^+(aq) + HSO4^-(aq)
The species H2O and HSO4- are two proton acceptors in the system. According to the Brownstead- Lowry definition, a base is a proton acceptor in solution.
Hence H2O and HSO4- are bases present in the dehydration of 2-methylcyclohexanol.
Urgent help me please answer it if you know it
What elements in group 17 are solids liquids and gass?
Answer: \(\left( \ce{F} \right)\), chlorine \(\left( \ce{Cl} \right)\), bromine \(\left( \ce{Cl} \right)\), iodine \(\left( \ce{I} \right)\), and astatine \(\left( \ce{At} \right)\)
Explanation:
Which of the following is an example of a mixture?
A.
calcium
B.
the atmosphere
C.
carbon dioxide
D.
water
Answer:
B. the atmosphere
Explanation:
hope it helps
Explain how the immune system responds to pathegons
Answer:
The immune system responds to antigens by producing cells that directly attack the pathogen, or by producing special proteins called antibodies. Antibodies attach to an antigen and attract cells that will engulf and destroy the pathogen. The main cells of the immune system are lymphocytes known as B cells and T cells.
What is the mass, in grams, of 2.3 moles of gold?
Answer:
453.031g
Explanation:
atomic mass (molar mass)- 196.97g/m
2.3(196.97)=453.031
Please help me please it due today at 11:00am plz help me
Answer:
Point F
Explanation:
Point F is the maximum potential energy.
Point G is lots of kinetic energy.
Point H is low potenital energy and low kinetic energy.
2.) Given that the reaction below is a precipitation reaction, what is the missing symbol?
AND
3.) Which of the following would produce a precipitate when mixed water (H20)?
PLZ HELP IM GONNA FAIL THE SEMESTER!!!! I'LL AWARD BRAINLIEST!!
Answer:
2) (s)
3) PbBr2
Explanation:
2) This is a precipitation rxn which means if forms a solid, We use (s) for solid.
3) Refer to solubility table
A particular reaction has an enthalpy and entropy of reaction of ∆H = +33 kJ/mol and ∆S = +0.15 kJ/mol⋅K. At the three indicated temperatures, determine if either reactants or products are favored?
Answer:
Explanation: check my paage
Whats the answer 50 points and brainliest if its right
Answer:
D
Explanation:
Question 1 of 10
In which state of matter do the particles move independently of one another?
A. Amorphous solid
B. Gas
C. Crystalline solid
D. Liquid
Answer:
Gas (B)
Explanation:
How does body temperature, energy level, and water level affect a person’s ability to survive?
During bromination using NBS, the addition product is not observed because the rate of addition is _______than the rate of the chain propagation steps.
Answer:
slower
Explanation:
NBS is used in place of Br2 during bromination because the use of Br2 tends to result in the formation of a large concentration of the addition product. This is because, the Br2 interacts with the double bond to yield only the dibromide (addition product).
The usefulness of NBS lies in the fact that it provides a lower concentration of Br2, and such that the rate addition is slower than the chain propagation steps. Only the monobromination product is observed
The low concentration of Br2 allows the free-radical reaction to out-compete the alkene addition reaction.
Which of the following is chemical property?
Question is in the picture help ASAP please
Answer:
C
Explanation:
Which are the three most common gases Giving Brainliest
Answer:
B
Explanation:
i hope this helps
how does mass and volume affect sinking and floating? Please don't plagiarize....
Answer:
If an object has a higher density than the fluid it is in (fluid can mean liquid or gas), it will sink. If it has a lower density, it will float. Density is determined by an object's mass and volume. If two objects take up the same volume, but have one has more mass, then it also has a higher density.
Explanation:
An object has a mass of 3.50 grams and a density of 5.61 g/mL. What is the volume of this object? *
Answer:
0.62 mLExplanation:
The volume of a substance when given the density and mass can be found by using the formula
[tex]volume = \frac{mass}{density} \\[/tex]
From the question we have
[tex]volume = \frac{3.50}{5.61} \\ = 0.6238859...[/tex]
We have the final answer as
0.62 mLHope this helps you
The following concerns the combustion of nitromethane (CH3NO2 - a popular fuel for top-fuel dragsters) according to the reaction below:_______. 2 CH3N02 (1) + ž02(g) → 2C02) + 3H20 (1) + N2(9) a. Burning 121 L of nitromethane at constant pressure releases 1.6 x 100 kJ of energy. What is the enthalpy of combustion of this reaction? The density of nitromethane is 1.16 g/cm². b. Assume you transfer heat involved in the previous problem to 1 kL of water that is initially at 25.0 °C. What is the final temperature of the water?
Answer:
695.8kJ/mol = Enthalpy of combustion
Final temperature = 407.4°C
Explanation:
Taken the reaction:
2CH₃NO₂ + 3/2 O₂ → 2CO₂ + 3H₂O + N₂
The enthalpy of the reaction is the heat released when 1 mole of nitromethane are in combustion.
We need to find the moles presents in 121L of nitromethane using its density and molar mass (61.04g/mol). As these moles releases 1.6x10⁶kJ, we need to find heat released per mole of nitromethane
Mass nitromethane:
121L = 121000cm³ * (1.16g/cm³) = 140360g
Moles:
140360g * (1mol / 61.04g) = 2299.5 moles of nitromethane
Heat released per mole of nitromethane:
1.6x10⁶kJ / 2299.5 mol = 695.8kJ/mol = Enthalpy of combustion
The symbol - is because the heat is released, a + symbol is when the heat is absorbed.
Using:
Q = m×C×ΔT
Where Q is heat (1.6x10⁶kJ = 1.6x10⁹J)
m is mass of water:
1kL = 1000L = 1x10⁶mL = 1x10⁶g
C is specific heat of water: 4.184J/g°C
And ΔT is change in temperature.
Solving for ΔT:
1.6x10⁹J = 1x10⁶g * 4.184J/g°C * ΔT
ΔT = 382.4°C
As initial temperature was 25°C, final temperature is:
382.4°C + 25°C =
407.4°C
what is the device to use to measure a potential difference in a circuit called?
Answer:
c. Voltmeter
Explanation:
PLATO LIVES MATTER
How many grams of oxygen gas will be produced when 2.50 moles of potassium chlorate is decomposed?
Answer:
[tex]m_{O_2}=120gO_2[/tex]
Explanation:
Hello!
In this case, since the decomposition of potassium chlorate is:
[tex]2KClO_3\rightarrow 2KCl+3O_2[/tex]
We can see a 2:3 mole ratio between potassium chlorate and oxygen (molar mass 32.0 g/mol), thus, via stoichiometry, we compute the mass of oxygen that are produced by the decomposition of 2.50 moles of this reactant:
[tex]m_{O_2}=2.50molKClO_3*\frac{3molO_2}{2molKClO_3} *\frac{32.0gO_2}{1molO_2}\\\\m_{O_2}=120gO_2[/tex]
Best regards!
The mass of 900. atoms of sodium(Na)
Answer:
3.44 × 10⁻²⁰ g Na
General Formulas and Concepts:
Chemistry - Atomic Structure
Reading a Periodic TableUsing Dimensional AnalysisAvogadro's Number - 6.022 × 10²³ atoms, molecules, formula units, etc.Explanation:
Step 1: Define
900 atoms Na
Step 2: Identify Conversions
Avogadro's Number
Molar Mass of Na - 22.99 g/mol
Step 3: Convert
[tex]900 \ atoms \ Na(\frac{1 \ mol \ Na}{6.022 \cdot 10^{23} \ atoms \ Na} )(\frac{22.99 \ g \ Na}{1 \ mol \ Na} )[/tex] = 3.4359 × 10⁻²⁰ g Na
Step 4: Check
We are given 3 sig figs. Follow sig fig rules and round.
3.4359 × 10⁻²⁰ g Na ≈ 3.44 × 10⁻²⁰ g Na
Determine the correct hybridization (from left to right) about each central atom in
CH3CH2OH.
A) 1st C sp3 ; 2nd C sp2 ; O sp B) 1st C sp3 ; 2nd C sp3 ; O sp3
C) 1st C sp ; 2nd C sp2 ; O sp3 D) 1st C sp3 ; 2nd C sp2 ; O sp2
Answer:
B) 1st C sp3 ; 2nd C sp3 ; O sp3
Explanation:
Both carbons in ethanol have an sp³ configuration of their orbitals, given that each carbon atom binds to four other atoms, as can be seen on the extended formula in the attachment.
In these carbons (1st and 2nd) one s orbital and three p orbitals are hybridized to form four hybrid orbitals sp³. These orbitals form four bonds and their bond angles are close to the tetrahedral value of 109.5º,as can be seen for methanol which also has an sp³ configuration.
The oxygen atom can also be described as having sp³ hybrid orbitals. Two of the four hybrid sp³ orbitals in oxygen are occupied by lone electron pairs, and two are used to form bonds with other atoms (in this case the oxygen is bonded to a carbon atom and a hydrogen atom).
Therefore, the three central atoms have an sp³ configuration.
Balance chemical equation hbr(aq)+o2(g) h20(l)+br2(l)
Which products are formed when aluminum is added to a silver chloride solution? Use the activity series below if needed. Al> Mn > Zn>.Cr > Fe > Cd> Co > Ni > Sn > Pb>H> Sb > Bi > Cu> Ag > Pd >Hg > Pt O none O only AICI3 O AlCl3 and Ag O AIAg3 and Cl2
Answer:
AlCl3 and Ag
Explanation:
Edge 2020
The products formed when aluminum is added to a silver chloride solution are "AlCl3 and Ag".
The reaction of aluminum and silver chloride is a single substitution type of reaction that is expressed as follows: Al (s) + 3AgCl (aq) = AlCl3 (aq) + 3Ag (s)When aluminum is added to the silver chloride solution, the cations are exchanged in the process forming AlCl3 and Ag.
Chemical reaction, a process in which one or more substances, the reactants, are converted to one or more different substances, the products. Substances are either chemical elements or compounds. A chemical reaction rearranges the constituent atoms of the reactants to create different substances as products.Chemical reactions are an integral part of technology, culture, and indeed of life itself. Burning fuels, smelting iron, making glass and pottery, brewing beer, and making wine and cheese are among many examples of activities incorporating chemical reactions that have been known and used for thousands of years. Chemical reactions abound in the geology of Earth, in the atmosphere and oceans, and in a vast array of complicated processes that occur in all living systems.Learn more about chemical reactions
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HURRY
Which part of an atom is mostly empty space?
nucleus
proton cloud
electron cloud
neutron
Answer:
Electron cloud
Explanation:
If you were to scale the size of the atom up to have the nucleus be about the size of a basket ball, then the placement of the actual electrons (about the size of a large marble at this scale) throughout the cloud would be many yards away from the nucleus.
6.0 L of a gas exert a pressure of 2.5 atm. When the pressure is increased 2 points
to 10.0 atm, what is the new volume of the gas?
O 1.0L
O 1.5L
O 1.7L
O 25L
Which pair of elements would you expect to have similar properties?
Li and Fe
At and F
F and o
Ge and As
From the following heats of reaction,
2C (graphite) + H2 (g) -->C2H2 (g) H = 227 kJ
6C (graphite) + 3H2 (g) -->C6H6 (l) H = 49 kJ
calculate the heat for the reaction
3C2H2 (g) -->C6H6 (l)
A. 26.7 kJ
B. -26.7 kJ
C. -178 kJ
D. 178 kJ
E. -632 kJ
F. 632 kJ
Answer:+178
Explanation:
The heat of the reaction for the following reactions is 178 kJ. the correct option is D.
What is the heat of the reaction?The heat that is added or removed during a chemical reaction is called the heat of reaction.
It is also called the enthalpy of the reaction.
The heat is absorbed or released to maintain the temperature of the reaction.
The enthalpy can be calculated by subtracting the enthalpy of the product from the enthalpy of the reactant.
Thus, the correct option is D.
Learn more about the heat of the reaction
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How much work (in JJ) is required to expand the volume of a pump from 0.0 LL to 2.5 LL against an external pressure of 1.1 atmatm
Answer:
- 278.85 J
Explanation:
Given that:
Pressure = 1.1 atm
The initial volume V₁ = 0.0 L
The final volume V₂ = 2.5 L
The work that takes place in a reaction at constant pressure can be expressed by using the equation:
W = P(V₂ - V₁ )
Since the volume of the gas is expanded from 0 to 2.5 L when 1.1 atm pressure is applied. Then, the work can be given by the expression:
W = - P(V₂ - V₁ )
W = -1.1 atm ( 2.5 - 0.0) L
W = -1.1 atm (2.5 L)
W = -2.75 atm L
Recall that:
1 atm L = 101.4 J
Therefore;
-2.75 atm L = ( -2.75 × 101.4 )J
= -278.85 J
Thus, the work required at the chemical reaction when the pressure applied is 1.1 atm = - 278.85 J
2. Combining 0.242 mol Fe2O3 with excess carbon produced 10.2 g Fe.
Fe2O3+3C⟶2Fe+3CO
(a) Actual yield of Fe mole
(b) percentage mole
(c) theoretical yield of iron mmoles
actual yield = 0.182 mole
theoretical yield : 0.484 mole
percentage mole(% yield)=37.6%
Further explanationPercent yield is the comparison of the amount of product obtained from a reaction with the amount you calculated
General formula:
Percent yield = (Actual yield / theoretical yield )x 100%
An actual yield is the amount of product actually produced by the reaction. A theoretical yield is the amount of product that you calculate from the reaction equation according to the product and reactant coefficients
Reaction
Fe₂O₃+3C⟶2Fe+3CO
a. actual yield of Fe mole
10.2 g produced
[tex]\tt mol~Fe=\dfrac{10.2}{56}=0.182[/tex]
b. percentage mole and theoretical yield
0.242 mol Fe₂O₃ = 2 x 0.242 mol Fe = 0.484 mol (theoretical yield)
percentage yieldpercentage mole)
[tex]\tt \dfrac{0.182}{0.484}=0.376=37.6\%[/tex]
1) If a bottle of olive oil contains 1.3 kg of olive oil, what is the volume, in milliliters, of the olive oil? Express your answer to two significant figures and include the appropriate units. 2) A cannon ball made of iron has a volume of 116 cm^3. What is the mass, in kilograms, of the cannon ball? Express your answer to three significant figures and include the appropriate units. 3) A balloon filled with helium has a volume of 6.1 L. What is the mass, in grams, of helium in the balloon? Express your answer to two significant figures and include the appropriate units.
Answer:
1) 1.4 × 10³ mL
2) 0.913 kg
3) 1.1 g
Explanation:
1)
Step 1: Calculate the volume of 1.3 kg of olive oil
The density of olive oil is 0.917 kg/L.
1.3 kg × (1 L/0.917 kg) = 1.4 L
Step 2: Convert the volume to mL
We will use the relationship 1 L = 10³ mL.
1.4 L × (10³ mL/1 L) = 1.4 × 10³ mL
2)
Step 1: Calculate the mass of the cannon ball
The density of iron is 7.87 g/cm³.
116 cm³ × 7.87 g/cm³ = 913 g
Step 2: Convert the mass to kg
We will use the relationship 1 kg = 10³ g.
913 g × (1 kg / 10³ g) = 0.913 kg
3)
Step 1: Calculate the mass of the helium in the balloon
The density of balloon is 0.18 g/L.
6.1 L × 0.18 g/L = 1.1 g