On the graph of f(x) = sin(x) on the interval [0, 2π), the function achieves a maximum value at x = π/2.
The function f(x) = sin(x) is a periodic function with a period of 2π. Within one period, the function oscillates between the values of -1 and 1. The maximum value of sin(x) is 1, and it occurs when the angle x is π/2.
In the given interval [0, 2π), the function f(x) = sin(x) completes one full period. Starting from x = 0, the function increases and reaches its maximum value of 1 at x = π/2. After that, it starts decreasing and goes through one complete cycle by the time it reaches x = 2π.
Therefore, on the graph of f(x) = sin(x) on the interval [0, 2π), the function achieves a maximum value at x = π/2.
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a sine function has an amplitude of 3, a period of π, and a phase shift of pi over 2 period what is the y-intercept of the function?
The y-intercept of the sine function with an amplitude of 3, a period of π, and a phase shift of π/2 is 0.
The general form of a sine function is y = A×sin(Bx - C) + D, where A represents the amplitude, B determines the period, C is the phase shift, and D is the vertical shift.
In this case, the given amplitude is 3, indicating that the maximum value of the function is 3 and the minimum value is -3.
The period is π, which means the function completes one full cycle in π units of x.
The phase shift is π/2 period, which shifts the graph to the right by π/2 units.
Since the y-intercept is the point where the graph intersects the y-axis (x = 0), and the sine function passes through the origin (0, 0), the y-intercept is 0.
Therefore, the y-intercept of the given sine function is 0.
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An ocean liner leaves port at 9:00 a.m. traveling directly out to sea at 22 miles per hour. A ferry leaves port at 9:30
a.m. traveling the same direction at 28 miles per hour. Use this information to complete the sentences.
A pair of parametric equations representing the paths of the boats are
From the time the ocean liner leaves until the ferry overtakes it is minutes at a distance from the port of
approximately miles.
Answer:
x=22t and y=28(t-0.5)
140
51
Step-by-step explanation:
right on edg
Answer:
A pair of parametric equations representing the paths of the boats are
✔ x = 22t and y = 28(t – 0.5) (Negative 0.5).
From the time the ocean liner leaves until the ferry overtakes it is
✔ 140.
minutes at a distance from the port of approximately
✔ 51 miles.
Step-by-step explanation:
Edge 2022
multiply
12 times 1/3?
Answer:
4
Step-by-step explanation:
12(1/3)
so it is just 12/3 which is 4
Hope that helps :)
How many 5 bills seth has
Answer:
22= 6(1x+5x)
Step-by-step explanation:
He could have 4 $5 bills and 2 $1 bills.
Answer:
he has 4 $5 bills
Step-by-step explanation:
22 - 2 = 20
20 divided by 4 = 5
so 4 $5 bills and 2 $1 bills
At 2 pm, the temperature was -9 degrees. If the temperature drops 8 degrees, what is the new temperature?
Answer:
At 2 pm, the temperature was -9 degrees. If the temperature drops 8 degrees, what is the new temperature?
Step-by-step explanation:
sorry I can't delete it
Answer:
-15
Step-by-step explanation:
-7 Dropping 8 would be -15 because 8+7 is 15 but its negative so its -15 (im terrible at explaining)
What is the probability of rolling a number less than 4 on a number cube labeled 1 trough 6?!
Answer:
3/6
Step-by-step explanation:
1 2 and 3 are less than 4 so only 3 numbers
raindrops are falling at an average rate of 20 drops per square inch per minute. what would be a reasonable distribution to use for the number of raindrops hitting a particular region measuring 5 square inches in a minute? why? using your chosen distribution, compute the probability that the region has no rain drops in a given 6-second time interval.
The number of raindrops hitting a particular region can be modeled using the Poisson distribution. The Poisson distribution is commonly used to describe the number of events occurring in a fixed interval of time or space when these events happen randomly and independently with a known average rate. In this case, the average rate is given as 20 drops per square inch per minute. The probability that the region has no raindrops in a given 6-second time interval is approximately 0.7165
To compute the probability that the region has no raindrops in a given 6-second time interval, we need to convert the rate to match the time interval. Since the rate is given per minute, we can divide it by 60 to get the rate per second: λ = 20/60 = 1/3 drops per square inch per second.
Using the Poisson distribution, the probability of observing exactly k events in a given time interval is given by the formula:
P(X = k) = (e^(-λ) * λ^k) / k!
Where e is Euler's number (approximately 2.71828), λ is the average rate, and k is the number of events.
In our case, we want to find the probability that the region has no raindrops in a 6-second time interval, which corresponds to k = 0.
P(X = 0) = (e^(-1/3) * (1/3)^0) / 0! = e^(-1/3)
Using a calculator, we can evaluate e^(-1/3) ≈ 0.7165.
Therefore, the probability that the region has no raindrops in a given 6-second time interval is approximately 0.7165 or 71.65%.
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A kindergarten teacher asked the students' parents to send their child to school with two fruits (apples and/or oranges). Below are the combinations of fruits brought to class the next day.
Fruit
2 Apples : 9 students
1 Apple and 1 Orange : 4 students
2 Oranges : 8 students
What is the frequency of oranges in the classroom? Round your answer to 4 decimal places.
The frequency of oranges in the classroom can be calculated as follows:Frequency of oranges in the classroom = Total number of oranges / Total number of fruits= 16/42 = 0.3809 (rounded to 4 decimal places)Thus, the frequency of oranges in the classroom is approximately 0.3809.
To determine the frequency of oranges in the classroom, we need to calculate the proportion of students who brought oranges out of the total number of students.
First, let's calculate the total number of students:
Total students = Number of students with 2 apples + Number of students with 1 apple and 1 orange + Number of students with 2 oranges
Total students = 9 + 4 + 8 = 21
Next, let's calculate the number of students who brought oranges:
Number of students with oranges = Number of students with 1 apple and 1 orange + Number of students with 2 oranges
Number of students with oranges = 4 + 8 = 12
Finally, we can calculate the frequency of oranges:
Frequency of oranges = Number of students with oranges / Total students
Frequency of oranges = 12 / 21 ≈ 0.5714 (rounded to 4 decimal places)
Therefore, the frequency of oranges in the classroom is approximately 0.5714.
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To determine the frequency of oranges in the classroom, it is important to add up the total number of fruits brought to the classroom. The given information is as follows:
2 Apples: 9 students
1 Apple and 1 Orange: 4 students
2 Oranges: 8 students
Thus, the frequency of oranges in the classroom is approximately 0.2105.
Total number of fruits = 2(9) + 1(4) + 2(8)
= 18 + 4 + 16
= 38 fruit in total
So, total number fruits are 38.
Frequency of oranges = Number of oranges / Total number of fruits
There are 8 oranges brought to class, so the frequency of oranges is:
8 / 38 ≈ 0.2105 (rounded to 4 decimal places)
Hence, the frequency of oranges in the classroom is approximately 0.2105.
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Algebra 2 PLEASE HELP
Answer:
[tex]\frac{x+20}{x+4}[/tex]
Step-by-step explanation:
Can't cancel out terms like that
need to factor out the top and bottom
[tex]\frac{x^{2} +16x-80}{x^{2} -16}[/tex] = [tex]\frac{(x+20)(x-4)}{(x-4)(x+4)}[/tex] now cancel out the (x-4) from the top and bottom
= [tex]\frac{x+20}{x+4}[/tex]
Answer & Explanation:
Error: individual terms in an equation in a fraction cannot be directly canceled out.
Correction:
the easy way (solve the quadratic equation in the numerator and complete the square in the denominator):
(x^2 + 16x - 80) / (x^2 - 16)
(x+20)(x-4) / (x+4)(x-4)
x+20 / x+4
the complicated way (manipulate the exponents and common factors):
(x^2 + 16x - 80) / (x^2 - 16)
(x^2 - 4x + 20x - 80) / x^2 - 2^4
x(x^2-1 - 2^2)+4*5(x - 2^4-2) / (x - 2^2)(x + 2^2)
x(x-4)+20(x-4) / (x-4)(x+4)
x(x-4)+(2^2 (5))(x-4) / (x-4)(x+4)
(x-4)(x + 2^2 (5)) / (x-4)(x+4)
(x-4)(x+20) / (x-4)(x+4)
x+20 / x+4
Mrs. Canales has 1,248 student pictures to displayaround the school. She plans to put them on 24 poster boards with the same amountof pictures on each poster board. How many student pictures will Mrs.Canales place on each poster board?
Answer:
52
Step-by-step explanation:
Its simple, its just division because she is asking how many for EACH(key word) so 1,248/24 equals 52 giving your answer.
mark brainliesttt??
HELP !!
In a sequence of numbers, a4=9, a5=15, a6=21, a7=27, and a8=33.
Which recursive rule can be used to find the nth term of the sequence, an?
a1=−9; an=an−1+6
a1=−9; an=6an−1
a1=9; an=an−1+6
a1=9; an=6an−1
Answer:
Given sequence:
a₄=9, a₅=15, a₆=21, a₇=27, and a₈=33Common difference is:
33-27 = 27 - 21 = 21 - 15 = 15 - 9 = 6Find the first term:
a₃ = 9 - 6 = 3a₂ = 3 - 6 = - 3a₁ = -3 - 6 = -9Recursive formula:
a₁ = -9 and aₙ = aₙ₋₁ + 6Correct choice is A
What are the first, second, and third quartiles from the set of
data: (3,4,5,6,7,37,100)?
The first, second, and third quartiles from the set of data (3,4,5,6,7,37,100) include the following:
Q₁ = 4.
Q₂ = 6.
Q₃ = 37
How to determine the statistical measure of the data set?Based on the data set, the first quartile (Q₁) can be calculated as follows;
Q₁ = [(n + 1)/4]th term
Q₁ = (7 + 1)/4
Q₁ = 2nd term
Q₁ = 4.
For the second quartile (Q₂), median, or 50th percentile, we have the following:
second quartile (Q₂) = 4th term
second quartile (Q₂) = 6.
For the third quartile (Q₃), we have:
Q₃ = [3(n + 1)/4]th term
Q₃ = 3 × 2nd term
Q₃ = 6th term
Q₃ = 37
In conclusion, a box plot for the given data set is shown in the image attached below.
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An electrician bent a section of copper wire into a partial circle as shown. The dimensions are
given in feet (ft).
2.5 f
880
2.5
ft
What is the length of the section of wire to the nearest hundredth of a foot?
Answer:
Length = 3.84 feets (nearest hundredth)
Step-by-step explanation:
The length of section of wire can be obtyaiejd using the length of of a arc formular :
Length of arc = θ/360° * 2πr
Radius, r = 2.5 feets
Length of arc = (88/360) *2πr
Length of arc = (88/360) * 2π*2.5
Length of arc = 0.244444 * 15.707963
Length of arc = 3.8397
Length = 3.84 feets (nearest hundredth)
Answer:
Step-by-step explanation:
3.84
Para resolver un sistema de ecuaciones lineales 2x2 por el método de sustitución se debe tener en cuenta:
A) consiste en despejar la misma incógnita en las dos ecuaciones y después igualar los resultados. En primer lugar, elegimos la incógnita que deseamos despejar. En este caso, empezaré por la «x» y despejo la misma en ambas ecuaciones.
B) debemos saber representar las gráficas de las rectas. Nosotros lo haremos uniendo puntos calculados previamente. Terminaremos con un sistema de dos inecuaciones (o desigualdades). En este caso, la solución del sistema es la intersección de dos regiones del plano.
C) es un método lineal ya que no se basa en despejes, se utilizan procesos algebraicos estructurados.
D) consiste en despejar o aislar una de las incógnitas (por ejemplo, x ) y sustituir su expresión en la otra ecuación. De este modo, obtendremos una ecuación de primer grado con la otra incógnita, y . Una vez resuelta, calculamos el valor de x sustituyendo el valor de y que ya conocemos.
AYUDA PLS
Answer:
El método de igualación consiste en despejar la misma incógnita en las dos ecuaciones y después igualar los resultados.
Los pasos a seguir son los siguientes:
sistema de ecuaciones
En primer lugar, elegimos la incógnita que deseamos despejar. En este caso, empezaré por la «x» y despejo la misma en ambas ecuaciones.
x+y=7; x=7-y
5x-2y=-7; 5x=2y-7
x=(2y-7)/5
Una vez hemos despejado, igualamos:
7-y = (2y-7)/5
5.( 7-y) = (2y -7)
35 -5y= +2y -7
42=7y
y=42/7=6
y=6
Por último, sustituimos el valor que hemos calculado despejando la otra incógnita en una de las ecuaciones iniciales.
Create a real-world application and its complete solution that requires concepts of linear algebra.
Real-World Application: Image Compression: Image compression is a fundamental concept in the field of computer graphics and image processing.
Linear algebra plays a crucial role in various image compression techniques. Let's consider a complete solution for image compression using concepts of linear algebra.
Image Representation:Linear algebra concepts, such as matrix operations and transformations, are fundamental to every step of the image compression process outlined above. By applying these techniques, we can achieve efficient storage and transmission of images while balancing the trade-off between image quality and compression ratio.
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what is the are of this?
Answer:
Ok first of all you start out splitting the shape into seperate rectangles, in this case 2. take those 2 rectangles and find the area of them. Say we start from the smaller rectangle. 2 x 4 = 8 so the area of the smaller rectangle is 8. Keep that in mind. Next we have to multiply 10 x 5 because that is the labeled number of meters and that equals 50. So add 50 + 8 = 58
Step-by-step explanation:
Your answer is 58 meters
Really hope i helped and have a wonderful day! :)
Answer:
58 m³
Step-by-step explanation:
To find the area of irregular shapes like this, it is easy to split the shape into 2 individual shapes, find the area of both, then add the areas to find the total.
Now, we'll split it into 2 rectangles with areas of:
2 x 4
10 x 5
To find area, you multiply the length of one side by the other. The first rectangle's area is (2 x 4) and the other rectangle's area is (10 x 5).
10 x 5 = 50
2 x 4 = 8
50 + 8 = 58
The area of the figure is 58 m³.
What is the perimeter of AOJL?
3
Ρ 2
K
M
9
Answer:
dunno.
Step-by-step explanation:
duno
i need help please and thanks
Answer:
[tex]48cm^{2}[/tex]
Step-by-step explanation:
Split the shape up into two rectangles
(1) rectangle would be 2 x 10 = 20
(2) rectangle would be 4 x 7 = 28
Add them up = [tex]48cm^{2}[/tex]
What is the value of 3^2? (3^2 means 3 raised to the second power.)
Answer:
9
Step-by-step explanation:
SOMEONE HELPPP
What is the classification of the figure?
A box contains 3 red and 7 green marbles. If 9 marbles are drawn without replacement, what is the expected number of red marbles?
The expected number of red marbles is 197/240.
Given that a box contains 3 red and 7 green marbles. If 9 marbles are drawn without replacement, we need to determine the expected number of red marbles.
The total number of marbles in the box = 3 + 7 = 10The probability of selecting a red marble at the first draw = 3/10
The probability of selecting a red marble at the second draw = 2/9
The probability of selecting a red marble at the third draw = 1/8
∴ The expected number of red marbles = Probability of selecting a red marble at the first draw + Probability of selecting a red marble at the second draw + Probability of selecting a red marble at the third draw= 3/10 + 2/9 + 1/8= (216 + 240 + 135) / (10 * 9 * 8)= 591/720= 197/240
Hence, the expected number of red marbles is 197/240.
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The given information is: A box contains 3 red and 7 green marbles. If 9 marbles are drawn without replacement, what is the expected number of red marbles?The expected number of red marbles can be found as follows:
Let us assume that X is a random variable, that represents the number of red marbles drawn from the box.
If we want to calculate the expected value of X, then we can use the formula:E(X) = Σ(xP(x))Where Σ(xP(x)) is the sum of all possible outcomes, multiplied by their respective probabilities.
The probability of drawing a red marble on the first draw is 3/10.
The probability of drawing a red marble on the second draw is 2/9, since there are only 2 red marbles left out of 9 marbles total.
The probability of drawing a red marble on the third draw is 1/8, since there are only 1 red marble left out of 8 marbles total.
Since we are drawing 9 marbles without replacement, we need to multiply all these probabilities together to get the probability of drawing a certain sequence of red and green marbles.
P(X = k) represents the probability of drawing k red marbles out of 9 marbles.Using the formula: E(X) = Σ(xP(x))E(X) = Σ(kP(X = k))k ranges from 0 to 3.
So, the expected value of red marbles is:E(X) = 0P(X = 0) + 1P(X = 1) + 2P(X = 2) + 3P(X = 3)E(X) = 0 + 1(3/10)(6/9)(5/8) + 2(3/10)(2/9)(5/8) + 3(3/10)(2/9)(1/8)E(X) = 0 + 0.27917 + 0.0625 + 0.01406E(X) = 0.35573
Therefore, the expected number of red marbles is approximately 0.356.
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Nick is curious about which cell phone provider is most used by his neighbors. He asks several neighbors about their provider and draws a conclusion based on the answers he received. What kind of statistical study did Nick conduct? A. survey B. experiment C. observational study D. theoretical study
Answer:
A. Survey
Step-by-step explanation:
Answer:
Option A. Survey
Step-by-step explanation:
What is survey?
Survey is defined as the act of examining a process or questioning a selected sample of individuals to obtain data about a service, product, or process.
Nick collected samples and then concluded his answer which is a survey he conducted.
Correct answer is Option A.
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Find the total surface area.
Answer:
SA = 48 cm²
Step-by-step explanation:
SA = (3x12) + (4x3) = 48 cm²
9 ft =_________in. How many inches????
108 inches
hope this helped <3
Euler's formula, v − e + f = 2, relates the number of vertices (v), the number of edges (e), and the number of faces (f) of a polyhedron. Solve Euler's formula for v.
a) v = e + f + 2
b) v = e + f - 2
c) v = e - f - 2
d) v = e - f + 2
Euler's formula, v − e + f = 2, relates the number of vertices (v), the number of edges (e), and the number of faces (f) of a polyhedron.
Therefore, the correct option is (d) v = e - f + 2.
To solve Euler's formula for v, we'll have to isolate v on one side of the equation. The first step is to add e to both sides of the equation:
v − e + f + e = 2 + e
v + f = e + 2
Now subtract f from both sides of the equation:
v + f - f = e + 2 - f
v = e + 2 - f
Hence, the solution for Euler's formula for v is:
v = e + 2 - f
Therefore, the correct option is (d) v = e - f + 2.
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The length of a rectangular frame is 15 inches and the width of the frame is 8 inches. What
is the length of the diagonal of this frame in inches?
Record your answer. Be sure to use the correct place value.
Today the high tide in Matheshan's Cove Lakeshore, is at midnight. The water level at high tide is 12.5 m. The depth, d metres, of the water in the cove at time t hours is modelled by the equation d(t)= 8+ 4.5sinl ő t).Kairvi is planning a day trip to the cove tomorrow, but the water needs to be at least 5 m deep for her to manoeuvre her sailboat safely. How can Kairvi determine the times when it will be safe for her to sail into Matheshan's Cove?
Solve the inequality 8 + 4.5sin(πt) ≥ 5 to find the times when it is safe for Kairvi to sail into Matheshan's Cove.
How can Kairvi determine the safe times to sail into Matheshan's Cove based on the water depth equation and the condition for safe sailing?To determine the times when it will be safe for Kairvi to sail into Matheshan's Cove, we need to solve the inequality 8 + 4.5sin(πt) ≥ 5, where t represents time in hours.
Here are the steps to solve the inequality:
Subtract 8 from both sides of the inequality:
4.5sin(πt) ≥ 5 - 8
4.5sin(πt) ≥ -3
Divide both sides of the inequality by 4.5 to isolate the sine function:
sin(πt) ≥ -3/4.5
sin(πt) ≥ -2/3
To find the values of t that satisfy this inequality, we need to consider the inverse sine (arcsine) function. Taking the inverse sine of both sides, we get:
πt ≥ arcsin(-2/3)
Solve for t by dividing both sides by π:
t ≥ (1/π)arcsin(-2/3)
The resulting expression (1/π)arcsin(-2/3) represents the minimum time at which the water depth will be at least 5 meters. To determine the specific times, you can use a calculator or reference table to evaluate the arcsin function and calculate the corresponding time values.
Note: Keep in mind that this solution assumes a 24-hour time format and that the given water depth equation and conditions are accurate.
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¿can you help me, please?
Use the four-step process to find f'(x) and then find f'(1), f'(2), and f'(3). f(x) = -x² + 4x-9 f'(x) =
The derivative of f(x) = -x² + 4x - 9 is f'(x) = -2x + 4. Evaluating f'(x) at x = 1, 2, and 3 gives f'(1) = 2, f'(2) = 0, and f'(3) = -2. To find the derivative of the function f(x) = -x² + 4x - 9, we will use the four-step process.
After applying the process, we obtain the derivative f'(x) = -2x + 4. Evaluating this derivative at x = 1, x = 2, and x = 3 gives us f'(1) = 2, f'(2) = 0, and f'(3) = -2.
The four-step process involves the following steps:
1. Begin by applying the power rule, which states that the derivative of [tex]x^n[/tex] is [tex]nx^{(n-1)[/tex], where n is a constant. In this case, we have -x², so the derivative becomes -2x.
2. Apply the power rule to the next term, which is 4x. The derivative of 4x is 4.
3. Since -9 is a constant term, its derivative is zero.
4. Combine the derivatives obtained in steps 1, 2, and 3 to find the overall derivative of the function f(x). In this case, f'(x) = -2x + 4.
To find the values of f'(1), f'(2), and f'(3), we substitute the corresponding values of x into the derivative function.
When x = 1, f'(1) = -2(1) + 4 = 2.
When x = 2, f'(2) = -2(2) + 4 = 0.
When x = 3, f'(3) = -2(3) + 4 = -2.
Therefore, the derivative of f(x) is f'(x) = -2x + 4, and the values of f'(1), f'(2), and f'(3) are 2, 0, and -2, respectively.
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How many residuals lie outside the 95% prediction bands? According to the SRM, how many of these should lie above and how many should lie below the estimated regression line?
The number of residuals outside the 95% prediction bands depends on the specific data and regression model. The explanation below provides general insights.
The number of residuals lying outside the 95% prediction bands can vary depending on the data and the estimated regression model. In a simple linear regression, the prediction bands represent the range within which future observations are expected to fall with 95% confidence.
Ideally, if the model assumptions are met and the regression is a good fit, we would expect only about 5% of the residuals to fall outside the prediction bands by chance. However, if the assumptions are violated or the model is not appropriate, more residuals may deviate beyond the bands.
The distribution of residuals above or below the estimated regression line depends on the symmetry of the errors. If the errors are normally distributed and the model is unbiased, roughly half of the residuals lying outside the prediction bands should be above the line, and the other half should be below the line.
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