Answer:
t=8
Explanation:
u have solution I give solution also
don't mark plzz follow y
Protons are launched with an initial speed 9550 m/s at 37° above the horizontal, into a region where a uniform vertical electric field is present. The protons hit a target at a horizontal distance 1.27 mm from the point where the protons are launched. Find the electric field, the time of flight, and the maximum height reached by the protons above the point where they were launched.
Answer:
E=720,5 N/C
H=0,24mm
Explanation:
How does an electrometer differ from a voltmeter? What is meant by an electrical ground? What must you do before each measurement in this experiment and why?
Answer:
n an electrometer, it is built in such a way that its resistance in parallel is extremely high
Ground in a circuit is a reference point from which voltages are measured
all the instruments must be grounded and we must ground ourselves
Explanation:
When you build a voltmeter you have a resistance in parallel with the galvanometer, therefore when measuring the voltage of a circuit, so that there is no effect (load effect) by the voltmeter, a resistance must be much greater than the resistance where it is is measuring.
In an electrometer, it is built in such a way that its resistance in parallel is extremely high in the order of 10¹²Ω, so its load effect is very small and can be measured with high resistance mu
Electric ground in home and industrial installations is a protection system consisting of a metal piece connected to a buried ground electrode.
Ground in a circuit is a reference point from which voltages are measured and is common to all parts of the circuit
In an experiment where an electrometer is used, all the instruments must be grounded and we must ground ourselves, since it must be an instrument where very small voltages are measured at high impedances.
Which wavelength of light is NOT absorbed by riboflavin?
Answer:
525 nm and 550nm
Explanation:
The absorption spectrum of any compound is a plot of absorption against wavelength. Sometimes, the absorption is plotted against frequency or wave number. This plot appears as humps. The peak of the highest hump is the wavelength of maximum absorption. The concentration of each solution may be indicated above the hump when the instrument is calibrated using different concentrations of the analyte.
The absorption spectrum of riboflavin indicates that its wavelength of maximum absorption is 450nm and it does not absorb at light 525 nm and 550nm wavelengths respectively.
how are weak and strong forces different
Answer:
What is the difference between the electrons in the nucleus and the ones in orbit around the nucleus? ... The Strong Nuclear Force is an attractive force between protons and neutrons that keep the nucleus together and the Weak Nuclear Force is responsible for the radioactive decay of certain nuclei
Explanation:
HELP!!!
An arrow is shot into the air at an angle of 30.0 above the horizontal with a speed of 20.0 m/s. What are the x and y components of the
velocity of the arrow 1.0 s after it leaves the bowstring?
Answer:
Y(1s) = [tex]10\sqrt{3}[/tex] - 10.1
X(1s) = 10m/s
Explanation:
In annex I've done the explanation for the equations that I will just present here.
Assuming that the arrow stars from the position (0 ; 0) in the Cartesian Graphic, and with Xo and Yo the initial speeds:
[tex]Yo =\frac{\sqrt{3} }{2} . Vr\\Yo = \frac{\sqrt{3} }{2} . 20\\Yo = 10\sqrt{3} m/s \\Xo = \frac{1}{2} Vr\\Xo = 10m/s[/tex]
Ignoring friction with air, Xo = Xf
So, Xo is the same during all the movement.
X(1s) = 10m/s
For Yo is different. That component is suferring reductions from gravity.
We can find Yo(1s) with one the basic functions of cinematics:
Vf = Vo + at
Vf = Final Velocity
Vo = Start Velocity
a = aceleration - gravity (g) is negative here
t = time
Yf = Yo + gt
Yf = [tex]10\sqrt{3}[/tex] - 10.1
If you prefere, can be: Yf = 10. ([tex]\sqrt{3} - 1[/tex])
Derrick crawls 4 feet south, and then turns east and crawls 6 feet.
What distance did he cover?
What was his displacement?
Displacement is a vector quantity. The distance and displacement of the given object are 10 ft and 7.07 ft respectively.
Distance:
It can be defined as the change in position of the object. It is a scalar quantity.
Displacement = 4+6
Displacement = 10 ft
Displacement:It can be defined as the vector change in position overall change in position.It is a vector quantityVector quantity is the quantities that have both magnitude and direction.[tex]\rm Dislacement =\sqrt { 4^2 +6^2}\\\\ \rm Dislacement = 7.07 ft[/tex]
Therefore, the distance and displacement of the given object are 10 ft and 7.07 ft respectively.
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One of the specific goals of of environmental analysis is:____________
a: To provide organized information, for the development of the organization's internal analysis, mission, vision , values and strategy.
b: To measure organizational efficiency.
c: To ignore minor competitors.
d: To develop a list of "one-word: descriptions of the external environment.
Answer:
a: To provide organized information, for the development of the organization's internal analysis, mission, vision, values, and strategy.
Explanation:
Environmental analysis is a process in business wherein the internal and external factors that can affect a business are examined so as to help improve the organization's goals and strategies. The internal analysis serves as a guide to checkmate the organization and to see if they have adopted the right strategies that suit their external environment.
Competitors in the external environment can have a huge impact on the business. So the internal workings of the organization should align with the external factors. The organized information would also be useful in forecasting the growth of the business.
What would the American flag look like under a blue light?
Answer:
The flag will appear to be black.
Explanation:
This is because red is the only brighter color in the American flag, so when a blue light is shined, the red turns dark and then the flag looks just blank and black.
Answer:
As red light falls on a blue surface, it absorbs the red light and no light will be reflected back. Thus, the object appears to be black. When the flag is illuminated by red light, the red and white stripes of the flag will appear solid red, the stars will appear red, and the blue portion will appear black.
.A hard rubber ball, released at chest height, falls to the pavement and bounces back to nearly the same height. When it is in contact with the pavement, the lower side of the ball is temporarily flattened. Suppose the maxi-mum depth of the dent is on the order of 1 cm. Find the order of magnitude of the maximum acceleration of the ball while it is in contact with the pavement. State your assumptions, the quantities you estimate, and the values you estimate for them.
Answer:
a = 1.1 10⁵ m / s²
Explanation:
This is a momentum exercise, where we use the relationship between momentum and momentum
I = ∫ F dt = Δp
= p_f - p₀
as they indicate that the ball bounces at the same height, we can assume that the moment when it reaches the ground is equal to the moment when it bounces, but in the opposite direction
F t = 2 (m v)
therefore the average force is
F = 2 m v / t
where in general the mass of the ball unknown, the velocity of the ball can be calculated using the conservation of energy
starting point. Done the ball is released with zero initial velocity
Em₀ = U = mgh
final point. Upon reaching the ground, just before the deformation begins
Em_f = K = ½ m v²
energy is conserved in this system
Em₀ = Em_f
m g h = ½ m v²
v = √ (2gh)
This is the velocity of the body when it reaches the ground, so the force remains
F = 2m √(2gh) /t
where the height of the person's chest is known and the time that the impact with the floor lasts must be estimated in general is of the order of milli seconds
knowing this force let's use Newton's second law
F = m a
a = F / m
a = 2 √(2gh) / t
We can estimate the order of magnitude of this acceleration, assuming the person's chest height of h = 1.5 m and a collision time of t = 1 10⁻³ s
a = 2 √ (2 9.8 1.5) / 10⁻³
a = 1.1 10⁵ m / s²
Suppose a wheel with a tire mounted on it is rotating at the constant rate of 3.273.27 times a second. A tack is stuck in the tire at a distance of 0.365 m0.365 m from the rotation axis. Noting that for every rotation the tack travels one circumference, find the tack's tangential speed. tangential speed: m/sm/s What is the tack's centripetal acceleration?
Answer:
The tangential speed is [tex]v = 7.5 m/s [/tex]
The centripetal acceleration is [tex]a = 154 \ m/s^2[/tex]
Explanation
Generally the angular velocity is mathematically represented as
[tex]w = e * \frac{ 2 \ pi \ rad }{s}[/tex]
substituting 3.27 rev/s for e we have that
[tex]w = 3.27 * \frac{ 2 \ pi \ rad }{s}[/tex]
=> [tex]w = 20.55 \ rad /s[/tex]
The tangential speed is mathematically represented as
[tex]v = w * r[/tex]
substituting 0.365 m for r we have that
[tex]v = 20.55 * 0.365 [/tex]
=> [tex]v = 7.5 m/s [/tex]
Generally the centripetal acceleration is mathematically represented as
[tex]a = \frac{v^2}{r}[/tex]
=> [tex]a = \frac{7.5^2}{ 0.365}[/tex]
=> [tex]a = 154 \ m/s^2[/tex]
A penny is dropped from the top of the chrysler building ( 320 m high) . How fast is it moving when it hits the ground?
Which statement describes a question that can guide the design of a
scientific investigation?
A. It asks about a cause-and-effect relationship between two
variables.
B. It asks about how the observations will be organized,
C. It asks about whether a controlled variable is necessary.
D. It asks about the preferred outcome of the investigation.
Answer:
The correct answer is:
It asks about a cause-and-effect relationship between two variables (A)
Explanation:
Scientific investigations are aimed as developing a hypothesis and proving the validity or not of the hypothesis developed. In order for these hypotheses to be tested, experiments must be done, and the experiments are designed based on the identification of a cause-and-effect relationship existing between two variables to be tested, where the "cause" is varied to various degrees and the "effect" of the variation is recorded. Therefore, knowing the cause-and-effect relationship will guide the experimental design, which will be aimed at manipulating the causes to see how these manipulations affect the second variable.
Answer:
A
Explanation:
It takes you 9.5 min to walk with an average velocity of 1.2 m/s to the north
from the bus stop to the museum entrance. What is your displacement?
The direction of movement of the body or item is defined by velocity. Your total displacement will be 684 meters.
What is Velocity?The direction of movement of the body or item is defined by velocity. Speed is fundamentally a scalar number. Velocity is, in essence, a vector quantity. It is the pace at which distance changes. It is the displacement rate of change.
Given that It takes you 9.5 min to walk with an average velocity of 1.2 m/s to the north from the bus stop to the museum entrance.
Time = 9.5 minutes = 9.5 × 60 seconds = 570 seconds
Average Velocity = 1.2 m/s
Now, the displacement made by you can be written as,
Velocity = Displacement / Time
1.2 m/sec = Displacement / 570 seconds
Displacement = 1.2 m/sec × 570 seconds
Displacement = 684 meter
Hence, your total displacement will be 684 meters.
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The various types of tree sloths share the honor of being the slowest-moving
mammals. An average tree sloth moves with a speed of 0.743 m/s. How long does it
take a sloth moving at this speed to travel 22.30 m?
Answer:
16.568 Minutes
Explanation:
Time = speed (m/s) x distance (m)
I need with the basic understanding of this
Answer:
A = air resistance
B = lift
C = thrust
D = gravity
1.00 N, 2.86° above horizontal
Explanation:
Gravity pulls down on the bird. The thrust of the birds wings push it forward, and the lift pushes it up. Air resistance pushes it back.
The net force in the y direction is:
∑Fᵧ = lift − gravity
∑Fᵧ = 0.20 N − 0.15 N
∑Fᵧ = 0.05 N
The net force in the x direction is:
∑Fₓ = thrust − air resistance
∑Fₓ = 1.50 N − 0.50 N
∑Fₓ = 1.00 N
The magnitude of the resultant force is:
F² = Fₓ² + Fᵧ²
F² = (1.00 N)² + (0.05 N)²
F ≈ 1.00 N
The direction of the resultant force is:
tan θ = Fᵧ / Fₓ
tan θ = (0.05 N) / (1.00 N)
θ = 2.86° above horizontal
A satellite in outer space is moving at a constant velocity of 21.4 m/s in the y direction when one of its onboard thruster turns on, causing an acceleration of 0.250 m/s2 in the x direction. The acceleration lasts for 45.0 s, at which point the thruster turns off. (a) What is the magnitude of the satellite's velocity when the thruster turns off
Answer:
a) The magnitude of the satellite's velocity when the thruster turns off is approximately 24.177 meters per second.
b) The direction of the satellite's velocity when the thruster turns off is approximately 62.266º.
Explanation:
Statement is incomplete. The complete description is now described below:
A satellite in outer space is moving at a constant velocity of 21.4 m/s in the y direction when one of its onboard thruster turns on, causing an acceleration of 0.250 m/s2 in the x direction. The acceleration lasts for 45.0 s, at which point the thruster turns off.
(a) What is the magnitude of the satellite's velocity when the thruster turns off
(b) What is the direction of the satellite's velocity when the thruster turns off? Give your answer as an angle measured counterclockwise from the +x-axis. ° counterclockwise from the +x-axis
Let be x and y-directions orthogonal to each other and the satellite is accelerated uniformly from rest in the +x direction and moves at constant velocity in the +y direction. The velocity vector of the satellite ([tex]\vec{v}_{S}[/tex]), measured in meters per second, is:
[tex]\vec{v}_{S} = (v_{o,x}+a_{x}\cdot t)\,\hat{i}+v_{y}\,\hat{j}[/tex]
Where:
[tex]v_{o,x}[/tex] - Initial velocity in +x direction, measured in meters per second.
[tex]a_{x}[/tex] - Acceleration in +x direction, measured in meter per square second.
[tex]t[/tex] - Time, measured in seconds.
[tex]v_{y}[/tex] - Velocity in +y direction, measured in meters per second.
If we know that [tex]v_{o,x} = 0\,\frac{m}{s}[/tex], [tex]a_{x} = 0.250\,\frac{m}{s^{2}}[/tex], [tex]t = 45\,s[/tex] and [tex]v_{y} = 21.4\,\frac{m}{s}[/tex], the final velocity of the satellite is:
[tex]\vec{v}_{S} = \left[0\,\frac{m}{s}+\left(0.250\,\frac{m}{s^{2}} \right)\cdot (45\,s) \right]\,\hat{i}+\left(21.4\,\frac{m}{s} \right)\,\hat{j}[/tex]
[tex]\vec{v_{S}} = 11.25\,\hat{i}+21.4\,\hat{j}\,\,\left[\frac{m}{s} \right][/tex]
a) The magnitud of the satellite's velocity can be found by the resource of the Pythagorean Theorem:
[tex]\|\vec {v}_{S}\| = \sqrt{\left(11.25\,\frac{m}{s} \right)^{2}+\left(21.4\,\frac{m}{s} \right)^{2}}[/tex]
[tex]\|\vec{v}_{S}\| \approx 24.177\,\frac{m}{s}[/tex]
The magnitude of the satellite's velocity when the thruster turns off is approximately 24.177 meters per second.
b) The direction of the satellite's velocity when the thruster turns off is determined with the help of trigonometric functions:
[tex]\tan \alpha = \frac{v_{y}}{v_{x}} = \frac{21.4\,\frac{m}{s} }{11.25\,\frac{m}{s} }[/tex]
[tex]\tan \alpha = 1.902[/tex]
[tex]\alpha = \tan^{-1}1.902[/tex]
[tex]\alpha \approx 62.266^{\circ}[/tex]
The direction of the satellite's velocity when the thruster turns off is approximately 62.266º.
What must be the acceleration of a train in order for it to stop from 12m/s in a distance of 541m?
Please help!!
Answer:
The acceleration of the train must be - 0.133 m/s²
Explanation:
A train in order for it to stop 12 m/s in a distance if 541 m
That means the initial velocity of the train is 12 m/s
Its final velocity is zero (stop)
The distance it covers is 541 m
P.S. This is part of the answer of another brainly user this is not my knowledge.
But Hope I helped you
Answer:
-0.133 m/s²
Explanation:
Given:
Δx = 541 m
v₀ = 12 m/s
v = 0 m/s
Find: a
v² = v₀² + 2aΔx
(0 m/s)² = (12 m/s)² + 2a (541 m)
a = -0.133 m/s²
I need help ASAP plzzz!!!!
Answer:
1. coffee maker 2.store B. 3.yes 5. 180
Part A
What is the magnitude of the momentum of a 0.0073-kg marble whose speed is 0.65 m/s?
Express your answer to two significant figures and include appropriate units.
Part B
What is the speed of a 0.136-kg baseball whose momentum has a magnitude of 3.14 kg⋅m/s?
Express your answer to two significant figures and include appropriate units.
Answer:
(A). The magnitude of the momentum of the marble is 0.004745 kg m/s.
(B). The speed of baseball is 23.0 m/s
Explanation:
Given that,
Mass of marble = 0.0073 kg
Speed = 0.65 m/s
(A). We need to calculate the magnitude of the momentum of the marble
Using formula of momentum
[tex]p = mv[/tex]
Where, m = mass
v = velocity
Put the value into the formula
[tex]p=0.0073\times0.65[/tex]
[tex]p=0.004745\ kg m/s[/tex]
(B). Mass of baseball = 0.136 kg
Momentum of baseball = 3.14 kg m/s
We need to calculate the speed of baseball
Using formula of momentum
[tex]p=mv[/tex]
[tex]v=\dfrac{p}{m}[/tex]
Put the value into the formula
[tex]v=\dfrac{3.14}{0.136}[/tex]
[tex]v=23.0\ m/s[/tex]
Hence, (A). The magnitude of the momentum of the marble is 0.004745 kg m/s.
(B). The speed of baseball is 23.0 m/s
What is the net force acting on the box?
0 285 N
0 185 N
SN
0 85 N
0 65 N
Answer:
the answer would be D 65N
Explanation:
just got it correct on EDG
he atomic radii of Li and O2- ions are 0.068 and 0.140 nm, respectively. (a) Calculate the force of attraction in newtons between these two ions at their equilibrium interionic separation (i.e., when the ions just touch one another). (b) What is the force of repulsion at this same separation distance
Answer:
a
[tex]F = -1.07 *10^{-8} \ N [/tex]
b
[tex]F_r = 1.07 *10^{-8} \ N[/tex]
Explanation:
Generally the force of attraction between this two irons is mathematically represented as
[tex]F = \frac{k * [Q_{Li} ] * [Q_{O} ] }{ r^2}[/tex]
Here k is known as the proportionality constant with value [tex]k = 2.31 * 10^ {-28} J \cdot m[/tex]
substituting -2 for [tex] Q_{O} [/tex] i.e the charge on oxygen , +1 for [tex] Q_{Li} [/tex] i.e the charge on Lithium and [tex] [0.140 + 0.068 ] nm= 0.208 nm = 0.208*10^{-9} [/tex] for r
So
[tex]F = \frac{ 2.31 * 10^ {-28}* +1 * -2 }{ ( 0.208*10^{-9} )^2 }[/tex]
[tex]F = -1.07 *10^{-8} \ N [/tex]
Generally the force of repulsion will be the magnitude but different direction to the force o attraction
So Force of repulsionn is
[tex]F_r = 1.07 *10^{-8} \ N[/tex]
express forty meters with four significant figures
40.00 meters
add a decimal place so that trailing zeroes are counted as significant figures.
Does the US use the metric system? Please Only Real Answers Like Yes Or No Or yes because...... no because...... Thank You
Answer:
No
Explanation: It is the only country that does not. Hope this helped :)
Scientific notation: Convert 7.1 x 10-3 to decimal notation.
Answer: hey
your answer is gonna be
71000.
Explanation:
why is evidence good for practice
Answer:
HEYO BRO! (my bad for da caps)
Explanation:
Evidence-based practice (EBP) is the idea that occupational practices ought to be based on scientific evidence. That at first sight may seem to be obviously desirable, but the proposal has been controversial.
Happy to Help From, Adam
Nami conducts an investigation on plants. She places a grow light on a timer to give the plants different amounts of light to see if this would affect their growth. Which term describes the amount of light in this investigation?
Answer:
It is independent variable
Explanation:
Answer:
D!!!!!
Explanation:
edge 2021!
A sports car starts from rest at an intersection and accelerates toward the east on a straight road at 9.0 m/s2. Just as the sports car starts to move, a bus traveling east at a constant 16 m/s on the same straight road passes the sports car. When the sports car catches up with and passes the bus, how much time has elapsed
Answer:
3.6s
Explanation:
Have In mind that the sports car will catch up with bus when their positions are equal
So
S = ut + 1/2at²
where u is initial velocity
For sports car we have
x = 0 + 1/2 x 9 x t²
For Bus
S= 16ts + 0
Equating the two
1/2 x 9 x t² = 16t
4.5 x t = 16
t = 3.6s
what is alpha decay?
Answer:Alpha decay, type of radioactive disintegration in which some unstable atomic nuclei dissipate excess energy by spontaneously ejecting an alpha particle.
Explanation:
How fast does the moon rotate around the Earth?
The moon orbits the Earth once every 27.322 days. It also takes approximately 27 days for the moon to rotate once on its axis. As a result, the moon does not seem to be spinning but appears to observers from Earth to be keeping almost perfectly still.
Answer:
approximately 27 days
The moon orbits the Earth once every 27.322 days. It also takes approximately 27 days for the moon to rotate once on its axis.
Explanation:
When a piece of paper is held with one face perpendicular to a uniform electric field the flux through it is 25 N .m2 /C. When the paper is turned 25° with respect to the field the flux through it is:_____.1. 02. 12 N .m2 /C3. 21 N .m2 /C4. 23 N .m2 /C5. 25 N .m2 /CB. A charged point particle is placed at the center of a spherical Gaussian surface. The electric flux is changed if:______.1. the sphere is replaced by a cube of the same volume2. the sphere is replaced by a cube of one-tenth the volume3. the point charge is moved off center (but still inside the original sphere)4. the point charge is moved to just outside the sphere5. a second point charge is placed just outside the sphereC. A charge of 0.8 × 10−9 C is placed at the center of a cube that measures 5 m along each edge. What is the electric flux through any 2 faces of the cube?
Answer:
1) 23 N.m²/C
2) The point charge is moved just outside the sphere
3) 30 N.m²/C
Explanation:
1) The flux through the field can be gotten by finding the dot product of the angle the later is turned, and the given uniform electric field.
25 * cos 25 =
25 * 0.9063 =
22.66 or approximately, 23 N.m²/C
2) The point charge is moved just outside the sphere
3) Using Gauss' Law, the electric flux through one face of the cube is given as Φ = Q / 6ε₀, thus,
Φ = 0.8*10^-9 / 6 * 8.85*10^-12
Φ = 0.8*10^-9 / 5.311*10^-11
Φ = 15 N.m²/C
And therefore, the flux through any 2 faces of the cube is 2 * 15 = 30 N.m²/C