On a coordinate plane, 2 lines intersect around (0.4, 2.8).
The graph on the left represents a system of equations.

How can the solution be located?

Which integers is the x-coordinate between?

Which integers is the y-coordinate between?

What is the solution approximated to the tenths place

Answer:

170.833

Step-by-step explanation:

we have to find real value which has to be find.

let take it as x,

in the question they said reduction percentage is equal to $123

then x*72/100=$123

x=$123*100/72

x=12300/72

x=170.8333

Answer:

I believe it's 211.90$.

Answer:

960

Step-by-step explanation:

(if i made any typos, sorry it is kind of hard to type on computer over writing on paper.)

A=2AB+(a+b+c)h

AB=s(s﹣a)(s﹣b)(s﹣c)

s=(a+b+c)/2

Solving forA

A=ah+bh+ch+1/2 sqrt(﹣a^4+2(ab)^2+2(ac)^2﹣b4+2(bc)^2﹣c^4)=10·12+24·12+26·12+1

2·﹣104+2·(10·24)2+2·(10·26)2﹣244+2·(24·26)2﹣264=960

The  journal entries relating to the building for the fifth year is: Debit Depreciation expense   $10,500; Credit To accumulated depreciation        $10,500.

Bailand Company

1. Dec 31  

Debit Depreciation expense         $10,500

Credit Accumulated depreciation                     $10,500

(Being the depreciation expense recorded)

Book value=$148,000-($148,000-$8,000/10×4)]

Book value=$148,000-$56,000

Book value=$92,000

Depreciation=$92,000-$8,000/8

Depreciation=$10,500

2. Dec 31  

Debit Depreciation expense $24,000.00

Credit Accumulated depreciation a/c               $24,000.00

[($92,000-$8,000)×6/21]

(Being the depreciation expense recorded)

3. Dec 31    

Debit Accumulated depreciation $3,200.00

[($8,000×4)/10]

Credit  Retained earnings              $3,200.00

(Being prior year adjustment for depreciation expense)

Dec 31  

Debit  Depreciation expense         $10,000.00

Credit Accumulated depreciation             $10,000.00

[($148,000-$8,000)/10]

(Being the depreciation expense recorded)

Therefore the  journal entries relating to the building for the fifth year is: Debit Depreciation expense   $10,500; Credit To accumulated depreciation   $10,500.

The complete question is:

Bailand Company purchased a building for $148,000 that had an estimated residual value of $8,000 and an estimated service life of 10 years. Bailand purchased the building 4 years ago and has used straight-line depreciation. At the beginning of the fifth year (before it records depreciation expense for the year), the following independent situations occur:

1. Bailand estimates that the asset has 8 years’ life remaining (for a total of 12 years).

2. Bailand changes to the sum-of-the-years’-digits method.

3. Bailand discovers that the estimated residual value has been ignored in the computation of depreciation expense.

Required: For each of the independent situations, prepare all the journal entries relating to the building for the fifth year. Ignore income taxes.

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Answer:

Step-by-step explanation:

The alternate interior angles theorem, and the angle sum theorem can be used here.

Alternate interior angles are found on either side of a transversal where it crosses a pair of parallel lines. They are between the parallel lines. Their vertices are at the junction of the transversal and the parallel lines. Alternate interior angles are congruent.

In this diagram, there are two pairs of alternate interior angles where the two transversals AD and BD cross parallel lines AB and CD.

At points A and D, the alternate interior angles are 70° and x, respectively. This tells you ...

  x = 70° . . . . alternate interior angles theorem

At points B and D, the alternate interior angles are w and 70°, respectively. This tells you ...

  w = 70° . . . . alternate interior angles theorem

The angle sum theorem tells you the sum of angles in a triangle is 180°. This fact can be used to find the measure of angle y.

  70° +w +y = 180°

  y = 180° -70° -w = 110° -70°

  y = 40° . . . . angle sum theorem

There is not enough information to determine the measure of angle z.

  z = indeterminate

Option c) 2x-3y ≥ 3 is correct inequality which has a shaded area below the boundary line.

Attempting all the equation on the graph to get the solutions

Inequality can be define as the relation of equation contains the symbol of ( ≤, ≥, <, >) instead of equal sign in an equation.

Since, while attempting all the option on graph. The one equation that satisfies the condition is 2x-3y ≥ 3 of having shaded area below the boundary line.

Thus, the option c) 2x-3y ≥ 3 is correct implification on graph which shows the shaded area below the boundary line.

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Answer:

2. (3+4) should be (3*4)

3. x is also x^1, so it should be x^(6+3+1)

4. you have to do 3^4 and 2^3 before timing them together

Answer is (4,7)

Step-by-step explanation:

Answer:

-960

Step-by-step explanation:

1) Expand [tex](x - 2y)^{10}[/tex] using the binomial theorem.

Binomial Theorem: [tex]\left(a+b\right)^n=\sum _{i=0}^n\binom{n}{i}a^{\left(n-i\right)}b^i[/tex]

1.1) Substitute the values into the theorem.

[tex]\sum _{i=0}^{10}\binom{10}{i}x^{\left(10-i\right)}\left(-2y\right)^i[/tex]

1.2) Expand summation.

[tex]=\frac{10!}{0!\left(10-0\right)!}x^{10}\left(-2y\right)^0+\frac{10!}{1!\left(10-1\right)!}x^9\left(-2y\right)^1+\frac{10!}{2!\left(10-2\right)!}x^8\left(-2y\right)^2+\frac{10!}{3!\left(10-3\right)!}[/tex]

[tex]x^7\left(-2y\right)^3+\frac{10!}{4!\left(10-4\right)!}x^6\left(-2y\right)^4+\frac{10!}{5!\left(10-5\right)!}x^5\left(-2y\right)^5+\frac{10!}{6!\left(10-6\right)!}x^4\left(-2y\right)^6+\frac{10!}{7!\left(10-7\right)!}x^3\left(-2y\right)^7+\frac{10!}{8!\left(10-8\right)!}x^2\left(-2y\right)^8+\frac{10!}{9!\left(10-9\right)!}x^1\left(-2y\right)^9+\frac{10!}{10!\left(10-10\right)!}x^0\left(-2y\right)^{10}[/tex]

1.3) Simplify them.

1.4) You will get:

[tex]=x^{10}-20x^9y+180x^8y^2-960x^7y^3+3360x^6y^4-8064x^5y^5+13440x^4y^6-15360x^3y^7+11520x^2y^8-5120xy^9+1024y^{10}[/tex]

2) We are told to find the coefficient of [tex]x^{7} y^{3}[/tex]. Find it from the simplified expansion. The coefficient is -960.

In 11.76 months, the value of the population will be 15000.

We have given that,

At the end of January 2003, the population of my town was 11,212.

the population is increased by 322 every month

So at the end of the second-month population will be 11534.

suppose x represents the year and  y represent the population

The population increased by 322 every month

Therefore the value of m =322

[tex](x_1,y_1)=(0,11212)[/tex]

We have m=332

[tex](x_2,y_2)=(x_2,15000)[/tex]

We have to determine the value of the x_2

[tex](y_2-y_1)=m(x_2-x_1)[/tex]

[tex]322\left(x_2-0\right)=15000-11212[/tex]

[tex]322\left(x_2-0\right)=3788[/tex]

[tex]\frac{322\left(x_2-0\right)}{322}=\frac{3788}{322}[/tex]

[tex]x_2=\frac{1894}{161}[/tex]

[tex]x_2=11.76[/tex]

Therefore in 11.76 months, the value of the population will be 15000.

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The graph of the function. f(x)=−|x+2|+1 is illustrated.

The given function is f(x)=−|x+2|+1.

We will have to draw the graph of the function.

When x = 1, f(1) will be -2. When x = 2, f(2,) will be -3

The points are illustrated based on the information given and the appropriate graph is illustrated and attached.

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Answer:

Infinite Number of Solutions

Step-by-step explanation:

Hello!

We can solve for y in the first equation, and plug that value in for y in the second equation.

Now that we know the equation for y, we can plug that in for y into the second equation to solve for x.

Since the equations match, there are an infinite number of solutions.

If we take a close look at the equations, we can also see that they are the same equation, but with flipped signs.

Answer:

The answer is D. 7x-8

Step-by-step explanation:

We can solve this problem by finding the area of the rectangle, which is equal to the length times the width. In this case, the length is 2x-3 feet and the width is 5 feet. Therefore, the area of the rectangle is (2x-3)(5), or 7x-8.

Answer:

14

Step-by-step explanation:

CB/AB = CE/ET

3/7 = 6/ET

ET = 14

Answer:

False

Step-by-step explanation:

The slope is 0.

Based on the account balances at the end of year, the retained earnings are $5,000.

First, find the net income:

= Service revenue - Salaries

= 35,000 - 29,000

= $6,000

Then find the assets:

= 22,000 + 14,000 + 5,200

= $41,200

Then the liabilities:

= 2,200 + 16,000

= $18,200

Retained earnings:

= Assets - Liabilities - Net income - Common stock

= 41,200 - 18,200 - 6,000 - 12,000

= $5,000

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Answer: 30

Step-by-step explanation: Formula for Area of a triangle = 1/2 Base * Height. 12*5 = 60; 60/2 = 30.

Answer:

30 cm squared

Step-by-step explanation:

This is a right angle triangle. That means that the base and height will just be the perpendicular sides of the triangle.

Our base in this case is 12 and our height is 5.

Area of a Triangle = 1/2(base)(height)

=1/2(12)(5)

=1/2(60)

=30

So, the area of this triangle is 30 cm squared.

The perimeter of the triangle is 30 units

The vertices are (−7,−1), (5,−1), and (5,4).

Start by calculating the distance between the vertices using:

[tex]d = \sqrt{(x_2 -x_1)^2 + (y_2 -y_1)^2[/tex]

So, we have:

[tex]d1 = \sqrt{(-1 + 1)^2 + (5 + 7)^2[/tex]

d1 = 12

[tex]d2 = \sqrt{(-1 - 4)^2 + (5 - 5)^2[/tex]

d2 =5

[tex]d3 = \sqrt{(-1 - 4)^2 + (-7 - 5)^2[/tex]

d3 = 13

The perimeter is then calculated as:

P = d1 + d2 + d3

This gives

P = 12 + 5 + 13

Evaluate

P = 30

Hence, the perimeter of the triangle is 30 units

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Answer:

5.5 in

Step-by-step explanation:

First we will calculate the total lawn grown after 8 weeks.

Grow Rate = [tex]2\frac{1}{8} in/2 weeks[/tex]

Total lawn grown after 8 weeks = [tex]2\frac{1}{8} *4\\=8.5 in[/tex]

Next we will calculate the total lawn mown after 8 weeks.

Mowing Rate = [tex]1\frac{3}{4} in/2weeks[/tex]

Total lawn mown after 8 weeks = [tex]1\frac{3}{4} *4\\=7 in[/tex]

Lawn Height after 8 weeks = Initial Lawn Height + Total lawn grown - Total lawn mown

= 4 in + 8.5 in - 7 in

= 5.5 in

The number of the sample that is necessary is 171. The number of employees that would be selected if E is 30 = 476

The standard deviation = 398

error E = 50

Alpha is = 1-0.90 = 0.10

a. We are to find the value of the size of the sample

Z∝/2 = Z0.05

= 1.645

sample size,n >= [Za/2 *(sigma/E)]^2

n >= [1.645 * (398/50)] ^2

n >= 171.46

n = 171

b.

error,E = 30

n >= [1.645 * (398/30)] ^2

n >= 476.27

n = 476

A survey is planned to determine the mean annual family medical expenses of employees of a large company. The management of the company wishes to be 90% confident that the sample mean is correct to within ±$50 of the population mean annual family medical expenses. A previous study indicates that the standard deviation is approximately $398. a. How large a sample is necessary?

b. If management wants to be correct to within ±$30, how many employees need to be selected?

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Answer:

Like terms

Step-by-step explanation:

Both terms have the same unit, which is pounds.

Answer: 4a^2-2b^2 (I think this is right)

Step-by-step explanation:

Using the order of operations I started by multiplying both of the sides separately. The left side of the equation becomes 2a^2-b^2-ab while the right becomes 2a^2-b^2+ab. Then I put the sides together to add them and after combining like terms it becomes 4a^2-2b^2.

Answer:

yes I think I'm new to this but I think that's a yes

[tex]im \: guessing \: its \: 4x {}^{2} - 3x + 1 \\ (correct \: me \: if \: im \: wrong)[/tex]

[tex](a - b) {}^{2} = a {}^{2} - 2ab + {b}^{2} [/tex]

[tex]4x {}^{2} = a {}^{2} \: \: \: \: \: \: \: \: \: \: \: b {}^{2} = 1 \\ a = 2x \: \: \: \: \: \: \: \: \: \: \: \: \: \: b = 1[/tex]

[tex](2x - 1) {}^{2} = 4x {}^{2} -4x + 1[/tex]

[tex]we \: need \: to \: add \: a \: - x \\ \: to \: the \: original \: equation[/tex]

The dot plot that represents the library book data is shown in the image below.

To construct a dot plot, each data point is represented as a dot. The number of dots one data point has represents the frequency at which that data point occurs in the data set.

The data set given in the table will have the following data points and frequencies:

1: 1

2: 3

3: 4

4: 4

5: 4

6: 0

7: 2

8: 2

The dot plot for the data is shown in the image below.

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