The pressure in the upper portion of the pipe is calculated by applying Bernoulli's equation,
P₁ + ¹/₂ρv₁² + ρgh₁ = P₂ + ¹/₂ρv₂² + ρgh₂
given is
p1 =247kPa
v1=2.09 m/s
h1= 0
v2 =3.41 m/s
h2 = 10.68 m
p=817 [tex]m^{3[/tex]
p2 = ?
Solving for this we can get the required value.
Bernoulli's equation formula shows the relation between pressure, kinetic energy, and gravitational potential energy of a fluid in a container. We have the formula for Bernoulli's principle as follows: p + 1 2 ρ v 2 + ρ g h = A constant.
Bernoulli's principle is based on the principle of conservation of energy. According to it, "in a steady flow, the sum of all forms of energy in a fluid is the same at all points that are free of viscous forces". This required the sum of kinetic energy, potential energy and internal energy to be constant.
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The image below shows an onion root viewed under a microscope.
What does this image best demonstrate?
A.
Living organisms are composed of one or more cells.
B.
Cells of different organisms have a similar composition.
C.
New cells only arise from pre-existing cells.
D.
Each cell can perform all functions necessary for life.
Answer:
Explanation:
a
let x be the number of rolls of a die needed for all 6 numbers to turn up. calculate both the expected value and the variance of x.
For x be the number of rolls of a die needed for all 6 numbers to turn up then the expected value is 5 and the variance of x is 2.0833 .
But to be absolutely certain, we may apply an even more straightforward procedure to get the solution,
expected value = (1 -p)/p
Where p is the likelihood of success and (1-p) is the expected failure value for the number of rolls of a die needed for all 6 numbers to turn up.
Thus , the 6 number to turn up = p = 1/6
The 6 number to not turn up =(1 - p) = 5/6
Putting the value in above equation we get,
expected value = (1 - 1/6)/1/6 = (5/6)/(1/6)
expected value = 5
Thus, all outcomes on the die between 1 and 6 have an equal likelihood, the bounds are a = 1, b = 6 ,now calculating the variance of x i.e. V(x)
V(X) = ( b - a)²/12
V(X) = ( 6 - 1)²/12
V(X) = 2.0833
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electronic rack-and-pinion systems use an electric motor to pump the hydraulic fluid through the hoses.
Electric – power – steering rack. Let's break it down one by one. “Steering rack” is a set of rack and pinion gears that is connected to both front wheels. When we turn the steering wheel, the rack and pinion gears engage in a way that shifts the car wheels to the left or right, which steers the car
Electric systems do not require power steering fluid to work and only draw power when needed, making them more fuel efficient than hydraulic systems. A rack gear and a pinion gear that transmits the steering wheel rotation inside of your car to tire movement outside of your car.
By providing power assist via hydraulic pressure, this system delivers a naturally smooth steering feel and, thanks to the flexibility of control allowed by electric power, offers more precise steering power characteristics.
Hydraulic power steering systems tend to be heavier than electrical systems. Hydraulic power steering systems require hydraulic fluid, which must be changed from time to time. Electrical systems don't use any fluid, so you don't have to do as much maintenance.
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When you paddle a boat in the water, the force of your paddle
will push the water which will apply an equal force back on
you. True or false
The paddle will experience a force from the water equal to the product of the water pressure and the paddle's surface area.
what is pressure ?
Pressure (symbol: p or P) is the force applied perpendicular to the surface of an object per unit area across which that force is distribute Gauge pressure (sometimes called gauge pressure)[a] is the pressure relative to the ambient pressure.
Various units are used to express pressure. Some of these are derived from dividing a unit of force by a unit of area; for example, the SI unit of pressure, the pascal (Pa), is one newton per square metre (N/m2); similarly, the pound-force per square inch (psi) is the conventional unit of pressure in the imperial and US customary systems. Pressure can also be stated in terms of normal atmospheric pressure; this pressure equals the atmosphere (atm).
The paddle will experience a force from the water equal to the product of the water pressure and the paddle's surface area. Any more power will only go to raise the speed of the paddle. Because of this, more water may be forced into a smaller space.
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Answer: The answer is ture
Explanation: Newtons third law which says
In a generator, the _____ permits part of the current that normally flows through the series field to flow through the resistor. series field shunt rheostat.
In a generator, the series field shunt rheostat allows part of the current that normally flows through the series field to flow through the resistor.
The field rheostat is in series connected with the shunt field circuit. This provides the simplest method of controlling the terminal voltage of a dc generator.
Shunt motor is a particular kind of DC motor which runs at a constant speed. But using field and armature rheostat control method we can make it more versatile. Field rheostat provides above normal speed and armature rheostat provides wide range of below normal speed.
An ammeter and a rheostat are connected in series and a voltmeter is connected in parallel with battery.
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Q13: Which distance P, Q, R, or S, represents the amplitude of the wave below?
Answer:
The answer is S
Explanation:
Amplitude is defined as the height of a wave from its undisturbed level.
Four point charges have the same magnitude of 2.4×10^−12C and are fixed to the corners of a square that is 4.0 cm on a side. Three of the charges are positive and one is negative. Determine the magnitude of the net electric field that exists at the center of the square.
The magnitude of the net electric field at the center of the square is
5.38799 x 10^4 N/C.
What is an electric field?An electric field is described as the physical field that surrounds electrically charged particles and exerts force on all other charged particles in the field, either attracting or repelling them.
Qa = Charge at point
A = −2.4× 10 −12C
Qb = Charge at point
B = 2.4 × 10 −12C
Qc = Charge at point
C = 2.4×10−12C
Q = Charge at point
D = 2.4 ×10−12C
a= side of the square = 4cm = 0.04 m
Ea = magnitude of the electric field at center of the square due to charge
QAEb
= magnitude of the electric field at center of the square due to charge
QBEc
= magnitude of the electric field at center of the square due to charge
QCEd
= magnitude of the electric field at center of the square due to charge
QDE x = Net electric field in X-axis.
Ey
= Net electric field in Y-axis
Magnitude of electric field at distance R due to a charge q = kx q/R^2
Where k = 8.98 X 10^9
Magnitude of net electric field in X-axis is
Ex = Ea×cos45 + Ec × cos45 +Eb × cos45 − Ed × cos45
Ex =
3.80989 × 10^4 N/C (If you substitute values)
Magnitude of net electric field in Y-axis is
Ex = Ea× Sin45 + Ec × Sin45 +Eb × Sin45 − Ed × Sin45
Ex = 5.38799 × 10^4 N/C
Therefore, the magnitude of the net electric field at the center of the square is
5.38799 x 10^4 N/C.
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A proton moves at 4.20 x 105 m/s in the horizontal direction. It enters a uniform vertical electric field with a magnitude of 7.60 * 103 N/C. Ignore any gravitational effects_ Find the time interval required for the proton to travel 4.50 cm horizontally. ns (b) Find its vertical displacement during the time interval in which it travels 4.50 cm horizontally. (Indicate direction with the sign of your answer.) mm (c) Find the horizontal and vertical components of its velocity after it has traveled 4.50 cm horizontally_ j km/s
The time interval required for the proton to travel 4.50 cm horizontally is 1.07 x 10⁻⁷ s , vertical displacement during the time interval in which it travels 4.50 cm horizontallyis 0.0043 m, and the horizontal and vertical components of its velocity after it has traveled 4.50 cm horizontally_ j km/s.
a. Let t be the amount of time needed for a proton to move 4.50 cm 0.045 m horizontally. It is calculable as follows:
t = d/v
where t is time, d is distance and v is velocity
t= d/v
t = 0.045m / 4.20 x 10⁵ m/s = 1.07 x 10⁻⁷ s
b. because the initial speed in the vertical direction is 0. So,
Thus, q E = ma.
ay= (Ey q)/m
Displacement is given by :
y=ut + 1/2ayt²
y =1/2 ((Ey q)/m) t²
y =(1/2)(7.60 x 10³ N/C x 1.67 x 10⁻¹⁹)(1.07 x 10⁻⁷)²
y= 0.0043 m
c.Use the following kinematics equation for the vertical component of velocity:
V(y)²-u²= 2ayd
[tex]v_y=\sqrt{\frac{E_{y}q}{m}d_{y} } \\v_y=\sqrt{\frac{7.60 X 10^3 N/C _{} X 1.67 x 10^{-19}}{ 1.67 x 10^{-27}} 0.045[/tex]
v=1.8493 X10⁵ m/s
velocity horizontal component,
vₓ =d/t
vₓ= 0.045/( 1.07 x 10⁻⁷ s) = 4.20 x10⁵
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Geoff counts the number of oscillations of a simple pendulum at a location where the acceleration due to gravity is 9.80 m/s2, and finds that it takes 24.0 s for 14 complete cycles.
1) Calculate the length of the pendulum. (Express your answer to three significant figures.)
The length of the pendulum is 0.910m if acceleration due to gravity is 9.8 m/[tex]s^{2}[/tex] and it takes 24 s to go 14 cycles.
First we will calculate Time period of pendulum
T = no of oscillations/ time
= 14/24
= 0.5833
We can find length of pendulum using formula
L=g(T/2π)^2
= 9.8(0.583/2×3.14
=9.8(0.583/6.28)
= 0.910 m
A simple pendulum is an arrangement of oscillating bob that has periodic motion. The simple pendulum has a small bob of mass ‘m’ suspended by a thin string fixed to a platform and length of string is L.
The time taken to complete one oscillation is defined as the time period of the pendulum. For simple pendulum of length L , time period is T = 2π √R/2g.
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some students want to calculate the work done by friction as an object with unknown mass moves along a straight line on a rough horizontal surface. the students have a force probe, a meterstick, and a stopwatch. which of the following will allow the students to take the measurements needed to calculate the work done by friction?
Pulling the block at an unknown constant acceleration with the force probe for a measured distance will allow the students to take the measurements needed to calculate the work done by friction. the correct answer is C.
As is common knowledge, the product of force and displacement defines the amount of work done.
hence, it is said as
W =F.d
where,
W is work
F is force
D is displacement
Therefore, in this case, force and displacement must be known in order to determine the work done.
In order to determine the amount of work done, we must first pull the block with a constant acceleration. therefore the correct answer is C
Your question is incomplete but most probably your full question was
Some students want to calculate the work done by friction as an object with unknown mass moves along a straight line on a rough horizontal surface. The students have a force probe, a meterstick, and a stopwatch. Which of the following will allow lo lake the measurements needed to calculate the work done by friction?
(A) Pulling the block at an unknown constant acceleration with the force probe for a measured time.
(B) Pulling the block at an unknown constant speed with the force probe for a measured time.
(C) Pulling the block at an unknown constant acceleration with the force probe for a measured distance.
(D) Pulling the block at an unknown constant speed with the force probe for a measured distance.
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a refracting telescope has an objective lens of focal length 15.4 in and eyepieces of focal lengths 18 mm, 24 mm, 36 mm, and 85 mm.
The largest angular magnification is 0.9 of the refracting telescope has an objective lens of focal length 15.4 in and eyepieces of focal lengths 18 mm, 24 mm, 36 mm, and 85 mm.
The formula for angular magnification is M = F_o/F_e, where F_o is the focal length of the objective lens and F_e is the focal length of the eyepiece.
The largest angular magnification is achieved with the shortest focal length eyepiece, which in this case is 18mm.
Plugging the values into the formula, we get M = 15.4/18 = 0.86.
Expressing the answer to two significant figures, we get M = 0.9.
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The complete question is written here
a refracting telescope has an objective lens of focal length 15.4 in and eyepieces of focal lengths 18 mm, 24 mm, 36 mm, and 85 mm.What is the largest angular magnification you can achieve with this instrument?Express your answer to two significant figures.
Imagine a table that has a hole drilled through the center. Through this hole is a string that connects one mass that hangs under the table, to a mass that is on top of the table and spinning. mass M weighs 10kg, mass m weighs 5 kg, and the radius, R, of the circle mass M, traces out is 50cm.
1. Solve for Force centripetal
2. At what speed does the mass M need to rotate in order to keep mass m suspended
Answer: The speed at which mass M needs to rotate in order to keep mass m suspended is 0.7071067811865475 m/s.
Explanation:
Calculate the atmospheric pressure.
The atmospheric pressure of the sample when depth, density and total pressure is given is 62.5 x 10⁸ Pa.
What is atmospheric pressure?Atmospheric pressure is defined as a unit of measurement equal to the normalized atmospheric pressure at sea level and 15 °C. Because it is determined using a barometer, atmospheric pressure is also referred to as barometric pressure.
It can be expressed as
P = hрg
P = 25 x 2.5 x 10⁵ x 1000
P = 62.5 x 10⁸ Pa
Thus, the atmospheric pressure of the sample when depth, density and total pressure is given is 62.5 x 10⁸ Pa.
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Light enters a water at an angle of incidence of 24 degree. Calculate the angle of refraction.
The calculated value of angle of refraction be 29.88°.
What is refraction?Refraction is defined as "the change in a wave's direction as it passes through a medium."
Although light refraction is one of the most frequently seen phenomena, refraction can also occur with sound and water waves. We can use optical tools like lenses, prisms, and magnifying glasses thanks to refraction. We can focus light on our retina because of the refraction of light, which is another benefit.
Given that;
Angle of incident of light from air to water: i = 24°
Refractive index of water: n = 1.33
So, the angle of refraction be = sin⁻¹(nsini) = sin⁻¹( 1.33 sin24°) = 29.88°.
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What is a balanced force?
A. All applied forces create an equilibrium.
B. All applied forces equal gravity.
C. It keeps an object moving at a changing velocity.
D. When there is no change in direction.
A balanced force is referred to as when all the applied forces create an equilibrium which is therefore denoted as option A.
What is a Force?This is referred to as an influence that can change the motion of an object and the formulas is F= ma where m is the mass and a is acceleration of the body involved with its unit being Newton.
Equilibrium on the other hand is referred to as as a state in which all the individual forces and torques exerted upon an object are balanced and there is no movement of the body in any type of direction in this type of scenario.
Balanced force is referred to as a situation in which all the applied forces which creates an equilibrium as denoted above which is therefore the reason why option A was chosen as the correct choice.
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a 50kg astronaut is training in human centrifuge to prepare for a launch. the astronaut uses the centrifuge to practice having a 5.20g force (5.20 times his own weight) on his back.
A 50kg astronaut practising in a human centrifuge to get ready for a launch will experience a net centripetal force of 2499N. The astronaut practises being supported by a 5.20g strain on his back.
A force that causes a body to follow an arc is known as a centripetal force (from the Latin centrum, "centre," and petere, "to pursue"). It always moves in the opposite direction of the body's motion and in the direction of the immediate centre of the path's curvature. It was defined as "a force by which bodies are attracted, compelled, or gravitate, towards a point as to a centre" by Isaac Newton.
Net centripetal force = 5.10 * 50 * 9.8 = 2499 N
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The complete question is-
a 50kg astronaut is training in human centrifuge to prepare for a launch. the astronaut uses the centrifuge to practice having a 5.20g force (5.20 times his own weight) on his back. Find the net centripetal force?
The weight of a synthetic ball varies directly with the cube of its radius. A ball with a radius
of 2 inches weighs 2.00 pounds. Find the weight of a ball of the same material with a
3-inch radius.
The weight of a ball of the same material with a 3-inch radius is
(Type an integer or a decimal.)
lb.
The weight of a ball of the same material with a 3-inch radius is 12.15 pounds.
What is weight?All things close to Earth are constantly subject to the force known as weight. All items are pulled downward toward the Earth's center by the gravity of the planet.
As a result, kilograms times meters per second squared, which is equivalent to a newton, can be used to quantify weight in the SI (N).
Weight can be expressed using the formula W = m*g, where weight can be expressed as kg * m/s2, which is equivalent to N, since weight is the force that gravity extends on a mass.
Let w equal the ball's weight in pounds.
r is the spherical ball's radius in inches.
The constant, C, converts the connection into a formula and ensures that the units are calculated correctly.
So, w = C r 3.
First determine C using the 2 "example: C= w/r3 = 3.60/(2)3 = 3.60/8 = 0.45
Now that you know C, you can determine the larger 3's weight "ball:
w = 0.45 r3 = 0.45
3 = 0.45 (27) = 12.15 pounds
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At a saltwater aquarium, a ray of light strikes the glass, from the air, at an angle of 32° with respect to the normal. The glass has an index of refraction of 1.53. The saltwater has an index of refraction of 1.33. The air has an index of refraction of 1.000293. What is the angle of refraction of the light as it enters the water from the glass?
20.273° is the angle of refraction of the light as it enters the water from the glass.
What is angle of refraction?Snell's law states that the angle of refraction, θr, is proportional to the angle of incidence, θi and the ratio of the refractive indices of the two media that comprise the interface. The angle θr=θi and no refraction occur when the mediums have equal refractive indices.
Given that,
Saltwater has an index of refraction = 1.33
The glass has an index of refraction (n₁) = 1.53
Air has an index of refraction (n₂) = 1.000293.
According to Snell's law:
n₂/n₁ = sin θ₁ / sin θ₂
or, 1.000293 / 1.53 = sin θ₁ / sin (32°)
or, 0.6537 = sin θ₁ / 0.52992
or, 0.3465 = sin θ₁
or, θ₁ = sin⁻¹ (0.3465)
or, θ₁ = 20.273°
So, 20.273° is the angle of refraction of the light as it enters the water from the glass.
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A worker pushes a lawn mower with a force of 280 N. If the handle makes an angle of 40.0° with the lawn, what is the force pushing the lawn mover forward?
As an object moves from point A to point B only two forces act on it: one force is conservative and does -70 J of work, the other force is nonconservative and does +50) of work. Between A and B, A) the kinetic energy of object decreases, mechanical energy decreases.B) the kinetic energy of object increases, mechanical energy increases. C) the kinetic energy of object increases, mechanical energy decreases D) the kinetic energy of object decreases E) mechanical energy increases
As the object moves from point A to B, the kinetic energy of the object decreases and the mechanical energy of the object increases.
In this problem, the law of energy conservation is applied. It is given that the work done by conservative force is -70J and the work done by non-conservative force is 50J.
The resulting forces between these two forces is -70J + 50J = -20 J.
The conservative force is linked with the movement caused by the sum of two energies, therefore there is a decrease in kinetic energy. The increase in mechanical energy is due to the positive non-conservative force.
Thus, the correct answer is kinetic energy of the object decreases and the mechanical energy increases.
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a capacitor is charged at a constant charging current of 2.0 x 10^-5A. The time taken to charge the capacitor is 30s and during this time the voltage across the capacitor rises from OV to 12V. What is the capacitance of the capacitor?
Answer:
5×10-5 farads
Explanation:
Indications:
Q = charge
I = Current
t = Time
C = Capacitance
V = Voltage
Now, we know, Q = IT = 2×10^-5 ×30 = 6×10^-4 C
again, we know, Q = VC
⇒ C = Q/V = 6×10^-4/12 = 5×10^-5 Farads
A car makes a lab around a 50 m loop in 9 seconds. What his their velocity?
Answer:
It will 50 m time Taken to complete one round time taken to complete complete one one round, it will nine second. So distance covered in, covered in in one ground equal two prior to that is equal to pi In 250, 1200 five. Now everybody spirit average period equal fear equal distance upon
large dorm, half the rooms are randomly wired for high-speed internet connections (the treatment group), and final course grades are collected for all residents. Which of the following pose threats to internal validity, and why? a. Midway through the year all the male athletes move into a fraternity and drop out of the study (their final grades are not observed). b. Engineering students assigned to the control group put together a local area network so that they can share a private wireless internet connection that they pay fo
Answer:
HAHAHAHAHAHAHAHAH
Explanation:
HAHAHAHAHAHAHAHAHAHAHAHAHAHAHAHAHAHAHAHAHAHAHAHAAHAHAHAHAH
If you keep a gas's temperature constant, how would you increase the volume of the gas?
a
You would change the temperature
b
You would increase the pressure
c
You would decrease the temperature
d
You would decrease the pressure
when the temperature is kept constant, to increase the volume of the gas, you will decrease the pressure (Option D)
How do I increase the volume at constant temperature?The volume of a gas at constant temperature is explained by the Boyle's law equation which is states as follow:
The volume of a fixed mass of gas is inversely proportional to the pressure at conctant temperature. Mathematically, it is expressed as follow:
P ∝ = 1/V
P = K / V
P₁V₁ = P₂V₂
Where
P₁ and P₂ are initial and new pressure V₁ and V₂ are initial and new volume
From the above formula, we can see that volume and pressure exist in inverse proportionality. This means that when the volume increases, the pressure will decrease and also, when the volume decreases, the presure will increase.
With the above information, we can conclude that the correct answer to the question is: You would decrease the pressure (Option D)
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Janelle pushes a box filled with books across the floor of her room. She then add some books to the box and pushes it with the same force across the same floor. How will the motion of the box change?
A . It will move slower because as mass increases, the force of friction between the surface also increases.
B. It will move faster because as mass increases, the force of friction between the surfaces decreases.
C it will move with the same speed because the mass of the object does not affect the force of friction between the surfaces.
D. It will move with the same speed because the same force was applied on the box in both of the cases
The motion of the box changes as it will move slower because as the mass increases, the force of friction between the surface also increases. Thus, the correct option is A.
What is the force of friction?Force of friction is a type of contact force. Frictional force is the force which resists the motion when the surface of one object comes in contact with the surface of another object. Example of frictional force is the force of friction between two stones which are rubbed with each other. The SI unit of frictional force is Newton (N).
Frictional force can be calculated by the formula:
f = μN
where, f = frictional force,
μ = coefficient of friction,
N = Normal force
The mass of the objects (normal force - mg) which are in motion is directly proportional to the magnitude of the frictional force. As more books are added to the box while the force of push remains same the motion of the box will change and it will move slower because as mass increases, the force of friction between the surface also increases.
Therefore, the correct option is A.
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A block of mass 2kg which is placed on a horizontal surface is pulled by a horizontal force of 50N. What maximum coefficient of static friction is required?
gravity=10m/s2
Answer:
The maximum coefficient of static friction required to pull the box will be 0.4.
Explanation:
We have given a box of mass 2 kg and Force of 50 N. (g=10m/s)
As we know,
Coefficient of static friction: μ = F/N (I)(F=ma, a= g)
Putting value in equation (I), we get
μ= mg/
μ=2×10/50
μ=0.4
A 650 kg elevator starts from rest. It moves upward for 4.50 s with constant acceleration until it reaches its cruising speed, 1.75 m/s.
(a) What is the average power of the elevator motor during this period? W
(b) How does this power compare with the motor power when the elevator moves at its cruising speed? Pcruising = W
5789.8 W is the average power of the elevator motor during this period and 1.115 * 10⁴ W this power compare with the motor power when the elevator moves at its cruising speed.
What is an explain acceleration?The rate with which the speed and direction of a moving object vary over time. A point a object going straight ahead is pushed when it accelerates or decelerates.
Briefing:Mass of elevator = 650 kg
Time = 4.50 sec
Speed of the elevator = 1.75 m/s
Calculating the elevator's acceleration is necessary.
Using the acceleration formula
a = vf - vi / t
a = 1.75 / 4.50
a = 0.38 m/s2
(a). We must determine the net force acting on the elevator.
Using the force formula
T = mg + ma
T = m (g +a)
T = 650 (9.8 + 0.38)
T = 6617 N
We must determine the average velocity.
Using the average velocity formula
v' = vf + vi / 2
v' = 1.75 / 2
v' = 0.875 m/s
We must determine the average power.
Using the power formula
P = T * v'
P = 6617 * 0.875
P = 5789.8 W
(b). We must determine the motor's power input.
Using the power formula
P = F * v
P = mg * v
P = 650 * 9.8 * 1.75
P = 1.115 * 10⁴ W.
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the basic mental abilities that go into learning and understanding any subject have been classified as
fluid intelligence
The fundamental mental capacities required to acquire and comprehend any subject have been categorized as fluid intelligence.
Human intelligence includes the abilities to learn from experience, adapt to new situations, understand and manage abstract concepts, and use information to change one's environment. Using longitudinal research designs the same people's behavior is examined over time . For instance, if we were to examine the connection between intelligence and aging, a scientist might do a longitudinal research to see whether 20-year-olds lose intelligence as they age. Gardner's idea was criticized by Psychologists and teachers. Gardner's concept of intelligence, according to these opponents, is too wide, and his eight different "intelligences" only represent skills, personality traits, and other characteristics.
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In 1979, Dr. Hans Liebold of Germany drove a race car 12.6 km with an average speed of 404 km/h. Suppose Liebold applied the brakes to reduce his speed. What was the car’s final speed if −3.00 MJ of work was done by the brakes? Assume the combined mass of the car and driver to be 1.00 × 103 kg
The vehicle's last speed if −3.00 MJ of work was finished by the brakes will be 398.45 km each hour.
What is the conservation of energy?
According to the principle of conservation of mass, energy cannot be gained or lost; it can only be converted from one form of energy to another. This indicates that only if energy is introduced from outside, a unit always uses the same quantity of energy.
In 1979, Dr. Hans Liebold of Germany drove a race vehicle 12.6 km with a typical speed of 404 km/h. Assume Liebold applied the brakes to decrease his speed. Expect the consolidated mass of the vehicle and driver to be 1.00 and 103 kg.
The final speed is given as,
1/2 x m [(v₂)² - (v₁)²] = 3 x 10⁶
1/2 x (1 + 103) x [(v₂)² - (404 x 18/5)²] = 3 x 10⁶
(v₂)² = 2057687.06
v₂ = 1,434.43 m/s
v₂ = 398.45 km per hour
The vehicle's last speed if −3.00 MJ of work was finished by the brakes will be 398.45 km each hour.
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Compare the wavelength of an electron traveling at a speed of 1.0* 10^7m/s with that for a ball of mass 0.10kg traveling at 35m/s
The wavelength of the electron, given that it is travelling at 1.0×10⁷ m/s is higher than that of the ball travelleing at 35 m/s
How do I compare the wavelength of the electron and ball?To compare the wavelength of both the electron and ball, we shall determin the the wavelength of both the electron and ball. Details below:
For electron:
Mass of electron (m) = 9.1×10⁻³¹ KgVelocity of electron (v) = 1.0×10⁷ m/sPlanck's constant (h) = 6.626×10⁻³⁴ JsWavelength of electron (λ) = ?λ = 2h / mv
λ = (2 × 6.626×10⁻³⁴) / (9.1×10⁻³¹ × 1.0×10⁷)
λ = 1.46×10⁻¹⁰ m
For ball:
Mass of ball (m) = 0.10 KgVelocity of ball (v) = 35 m/sPlanck's constant (h) = 6.626×10⁻³⁴ JsWavelength of ball (λ) = ?λ = 2h / mv
λ = (2 × 6.626×10⁻³⁴) / (0.10 × 35)
λ = 3.79×10⁻³⁴ m
From the above calculation we obtained:
Wavelength of electron = 1.46×10⁻¹⁰ mWavelength of ball = 3.79×10⁻³⁴ mThus, we can conclude that the the wavelength of the electron is higher than that of the ball.
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