Of the 500 sample households, 7 had three or more large-screen TVs. Among the sample households, 121 had no car, 172 had one car, and 207 had two or more cars. Estimate the percentage of households in the town with one or more cars; attach a standard error to the estimate. If this is not possible, explain why not.

The steps used to solve the quadratic equation are

8(x2 + 2x) = –3

8(x2 + 2x + 1) = –3 + 8

x = –1 Plus or minus StartRoot StartFraction 5 Over 8 EndFraction EndRoot

Given the equation;

8x² + 16x + 3 = 0

Collect like terms

8x² + 16x = -3

Take the common factors, we have

8(x² + 2x) = -3

Completing squares in the brackets and balancing the equation in the right side

8(x² + 2x + 1) = -3 + 8

Factoring the perfect square

[tex]8(x + 1)^2} = 5[/tex]

Make 'x' subject

[tex](x + 1)^2= \frac{5}{8}[/tex]

[tex](x + 1) =[/tex] ±[tex]\sqrt{\frac{5}{8} }[/tex]

[tex]x =[/tex] -1 ±[tex]\sqrt{\frac{5}{8} } }[/tex]

Thus, we can clearly see the steps used to solve the quadratic equation are

8(x2 + 2x) = –3

8(x2 + 2x + 1) = –3 + 8

x = –1 Plus or minus StartRoot StartFraction 5 Over 8 EndFraction EndRoot

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if stretched vertically by a factor of 2, the resulting function will be g(x) = 2|x| and a horizontal compression by a factor of 2, the resulting function will be 1/2|x|

Transformation is a technique used to change the position of an image on an xy-plane.

If the function f(x)is vertically stretched by "a" units, the resulting function will be f(x) = a|x|.

Hence if stretched vertically by a factor of 2, the resulting function will be g(x) = 2|x|

For a horizontal compression by a factor of 2, the resulting function will be 1/2|x|

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Answer:

y = [tex]\frac{29}{3}[/tex]

Step-by-step explanation:

88 = 10y + 30 - 4y , that is

88 = 6y + 30 ( subtract 30 from both sides )

58 = 6y ( divide both sides by 6 )

[tex]\frac{58}{6}[/tex] = y , that is

y = [tex]\frac{29}{3}[/tex]

The expression that represent the area of the cut off part is 81π / 4

The area of the cut off part can be found as follows:

Area of a circle = πr²

where

Therefore, the cut off part is like 1 / 4th of a circle.

Hence,

area of the cut off region = πr² / 4

r = 9 inches

area of the cut off region =  π9² / 4

area of the cut off region = 81π / 4

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Lets simplify the given problem,

The speed with which the plane flies = 350 mph

The direction of flight of the plane = N 40° E

The speed with which the wind blows = 40 mph

The direction in which the wind blows = S 40° E

Therefore, we have;

The resolution of the components of the motion of the plane, given as follows;

= 350 × sin(40°)·i + 350 × cos(40°)·j

The resolution of the components of the motion of the wind, given as follows;

= 40 × sin(40°)·i - 40 × cos(40°)·j

The resultant motion of the plane is given as follows;

= 262.563·i + 254.435·j

The direction of motion of the plane = tan⁻¹(262.563/254.435) ≈ N 45.9° E

Therefore, the plane's drift = Plane's Track - Plane's Heading  = N 45.9° E - N 40° E ≈ 5.9° ≈ 5.89°

Drift Angle of the plane is 5.89 degree.

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Answer: A 5.9

Step-by-step explanation:

cuz i said so

Answer: [tex]52.6^{\circ}[/tex]

Step-by-step explanation:

Let the angle of depression be x.

[tex]\sin x=\frac{27}{34}\\\\x=\sin^{-1} \left(\frac{27}{34} \right) \approx 52.6^{\circ}[/tex]

The value of x is  21√2/2

The correct option is (A)

Trigonometry is a branch of mathematics that studies relationships between the sides and angles of triangles.

In triangle having angle 60.

sin 60 = P/ 7√3

√3/2= P/7√3

2P= 21

P= 21/2

Now again

cos 45= 21/2/x

1/√2 = 10.5/x

x=  21√2/2

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Answer:

  1 ÷ 3

Step-by-step explanation:

You want 1/3 written as a quotient.

The quotient of A and B is "A divided by B." There are two ways to write this using math symbols:

  A/B

  A÷B

The fraction 1/3 is already written as a quotient. This set of symbols can be read as either of ...

The other way to write the quotient is ...

  1 ÷ 3

__

Additional comment

When you learn about exponents, you learn another way to write the quotient of A and B is ...

  A·B⁻¹

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The length of the rectangular book is 5.8cm

In Euclidean plane geometry, a rectangle is a quadrilateral with four right angles. It can also be defined as: an equiangular quadrilateral, since equiangular means that all of its angles are equal (360°/4 = 90°); or a parallelogram containing a right angle. A rectangle with four sides of equal length is a square. The term oblong is occasionally used to refer to a non-square rectangle.

The perimeter of a rectangle is found by adding up the length of all four sides. The formula for the perimeter of a rectangle is,

P = length + breadth + length + breadth. Or, P = 2(length + breadth)

Given:

Perimeter = 16.84 cm.

length = 18/7 cm

substituting in the formula we get

16.84 = 2( 18/7 + width)

8.42 = 18/7 + width

5.8 cm = width

Thus the length of the rectangular book is 5.8cm.

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Answer:

276 cm²

Step-by-step explanation:

    Construct a line DE  parallel to AB.

DE = 13 cm

So, ABED is a parallelogram

In ΔDEC,

     DE = a = 13 cm

    EC = AB - BE

         = 30 - 16

   EC = b = 14 cm

 DC = c = 15 cm

Use Heron's formula to find the area of triangle.

[tex]\sf s = \dfrac{a+b+c}{2}\\\\=\dfrac{13+15+14}{2}\\\\=\dfrac{42}{2}\\\\s = 21[/tex]

s-a = 21 - 13 = 8

s - b = 21 - 14 = 7

s - c = 21 - 15 = 6

 [tex]\sf \boxed{\bf Area \ of \ triangle = \sqrt{s(s-a)(s-b)(s-c)} }[/tex]

                                [tex]\sf = \sqrt{21 * 8 * 7* 6}\\\\=\sqrt{3 * 7 * 2* 2 * 2 * 7 * 2 * 3}\\\\= 3 * 7 * 2 * 2\\\\= 84 \ cm^2[/tex]

Area of ΔDEC = 84 cm²

[tex]\sf \dfrac{1}{2}*base * height = 84\\\\ \dfrac{1}{2}*14*height = 84[/tex]

           [tex]\sf height =\dfrac{84*2}{14}\\\\[/tex]

                     = 6 *2

          height = 12 cm

Now we know the height of the trapezium. h = 12 cm

The length of the parallel sides are a = 30 cm & b =16 cm

[tex]\sf \boxed{Area \ of \ trapezium = \dfrac{(a +b)*h}{2}}[/tex]

                                [tex]\sf =\dfrac{(30+16)*12}{2}\\\\=\dfrac{46*12}{2}\\\\= 23 * 12\\\\= 276 \ cm^2[/tex]

By applying the rigid transformations of reflection on y-axis, vertical compression and vertical translation, we find the transformed function based on f(x) = 2ˣ is f''(x) = (1/3) · 2⁻ˣ + 2.

Rigid transformations are transformations applied on functions such that their Euclidean distance is conserved. In this problem we must use the following rigid transformations to determine an expression based on f(x) = 2ˣ.

Reflection on y-axis

f'(x) = f(-x)     (1)

f'(x) = 2⁻ˣ

Vertical compression

f''(x) = k · f'(x)     (2)

f''(x) = (1/3) · 2⁻ˣ

Vertical translation

f'''(x) = f''(x) + c     (3)

f''(x) = (1/3) · 2⁻ˣ + 2

By applying the rigid transformations of reflection on y-axis, vertical compression and vertical translation, we find the transformed function based on f(x) = 2ˣ is f''(x) = (1/3) · 2⁻ˣ + 2.

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We'll prove first the triangles formed by diagonal are congruent then we'll prove the angles on either side of diagonal are congruent.

The steps are:

=============================================================

Let's take an mathematical example

Let's find the ratio of volume of a cone and cylinder if radius and height are same for both .

See

The ratio is 1:3

#Example 1

Ratio of gems=3:4

#Example 2

Ratio of ocean to continents=5:7

Note:-

Two examples are already provided on your another question .You may refer there

The number of pizza lunches sold more based on the survey is 5.

The information is incomplete and an overview will be given.

Let the number of pizza lunches sold be 24.

Let the number of hot dog lunches be 19.

Therefore, the number of pizza lunches sold more will be:

= 24 - 19

= 5

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Answer: C, 7

Step-by-step explanation:

Using the combination formula, it is found that there are 16,800 ways for them to do it.

[tex]C_{n,x}[/tex] is the number of different combinations of x objects from a set of n elements, given by:

[tex]C_{n,x} = \frac{n!}{x!(n-x)!}[/tex]

In this problem, we have that:

Hence the number of ways is:

[tex]N = C_{10,1}C_{9,3}C_{6,3}C_{3,3} = \frac{10!}{1!9!} \times \frac{9!}{3!6!} \times \frac{6!}{3!3!} \times \frac{3!}{3!0!} = 16800[/tex]

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Answer:

6[tex]x^{2}[/tex] - 19x + 15

Step-by-step explanation:

(2x - 3) (3x - 5)

2x(3x-5) - 3 (3x-5)

6[tex]x^{2}[/tex] - 10x - 3 (3x - 5)

6[tex]x^{2}[/tex] - 10x - 9x + 15

6[tex]x^{2}[/tex] - 19x + 15

Answer:

6x² - 19x + 15

Step-by-step explanation:

(2x - 3)(3x - 5)

each term in the second factor is multiplied by each term in the first factor, that is

2x(3x - 5) - 3(3x - 5) ← distribute parenthesis

= 6x² - 10x - 9x + 15 ← collect like terms

= 6x² - 19x + 15

Answer:

4

Step-by-step explanation:

The mean is the average of the numbers.

if you rearrange the data, you will get the order, 3,3,4,5,5.

you add all of them together to get the number twenty, then you divide 20 by the total number of data plots which is five. Then you get the number 4 which is your answer

3+3+4+5+5 = 20

20/5 = 4

Step-by-step explanation:

1. -5(a - 9) = -5a + 45

2. [tex]\frac{-8.3-(+2.7)}{\frac{1}{5} } = \frac{-8.3-2.7}{0.2} =\frac{-11}{0.2}=-55[/tex]

3.13p + 13 - p = (13p - p) + 13 = 12p + 13

4. -11b - 3(-4b + 1) = -11b + 12b - 3 = b - 3

5.

[tex]-2n+\frac{1}{6}-4\frac{1}{2}n = (-2n-4\frac{1}{2}n)+\frac{1}{6} = [-\frac{4}{2} n-(\frac{8}{2}+\frac{1}{2} )n]+\frac{1}{6} = -\frac{4}{2} n- \frac{9}{2} n+\frac{1}{6} =-\frac{13}{2}n\\+ \frac{1}{6}[/tex]

6. It didn't show all the information on the question.

7. [tex]-\frac{3}{5}(20r-5)-(-6r) =-12r+3+6r = (-12r+6r)+3=-6r+3[/tex]

8. [tex]-\frac{5}{6}x+\frac{4}{9}+\frac{2}{3}x+\frac{1}{3}=(-\frac{5}{6}x+\frac{2}{3}x)+(\frac{4}{9}+\frac{1}{3})=(-\frac{5}{6}x+\frac{4}{6}x)+(\frac{4}{9}+\frac{3}{9})=-\frac{1}{6}x+\frac{7}{9}[/tex]

9.It didn't show all the information on the question.

Answer:

1

Step-by-step explanation:

Using long division, 189 divided by 7 is 27

The picture below represent how to use long division.

Firstly, we divided 1 by 7, it can't go. Therefore, it zero. we put zero at the quotient space.

Multiply zero by 7 and subtract from 189.

We use 18 to divide 7. It will give us 2 remainder 4. we put the 2 at the quotient side and multiply it by 7 to get 14.

Then we subtract 14 from 18. And so on. This is done till we get 0.

Therefore, using long division, 189 divided by 7 is 27

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The hypotenuse of the right triangle ABC, with legs of 5 and 12 inches is 13 inches, computed using the Pythagoras Theorem. Hence, the 3rd option is the right choice.

The Pythagoras Theorem states that in a right triangle, the square of the hypotenuse is always equal to the sum of the squares of the other two legs.

If the hypotenuse is taken as a, and the two legs are taken as b and c, then by the Pythagoras Theorem, we can write that:

a² = b² + c².

In the question, we are given that the right triangle ABC, has legs of lengths 5 and 12 inches each, and we are asked to find the length of the hypotenuse.

Thus, taking b = 5 and c = 12, in the above equation, we get:

a² = 5² + 12²,

or, a² = 25 + 144,

or, a² = 169,

or, a² = 13²,

or, a = 13.

Thus, the hypotenuse of the right triangle ABC, with legs of 5 and 12 inches is 13 inches, computed using the Pythagoras Theorem. Hence, the 3rd option is the right choice.

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Answer:

24 cm^2

Step-by-step explanation:

The three sides are equal (SSS: side, side, side) so the triangles are congruent.

Answer:

x = 5

Step-by-step explanation:

given B is the midpoint of AC , then

AB = BC ( substitute values )

4x - 3 = 2x + 7 ( subtract 2x from both sides )

2x - 3 = 7 ( add 3 to both sides )

2x = 10 ( divide both sides by 2 )

x = 5

The terms are as follows:

t₃ = -62

t₇ = -29.6

tₙ = 10.8n - 105.2

t₁₄ = 46

t₁₉ = 100

Therefore,

tₙ = a + (n - 1)d

where

Hence,

46 = a + 13d

100 = a + 18d

5d = 54

d = 10.8

46 - 13(10.8) = a

a = 46 - 140.4

a = - 94.4

t₃ = a + 3d = - 94.4 + 3(10.8) = -62

t₇ = a + 6d = - 94.4 + 6(10.8) = -29.6

tₙ = -94.4 + 10.8n - 10.8 = 10.8n - 105.2

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Yes it is true that commercial truck owners violate laws requiring front license plates at a higher rate than owners of passenger cars because null hypothesis is rejected.

Given among 2049 Connecticut passenger cars, 239 had only rear license plates. Among 334 Connecticut trucks, 45 had only rear license plates.

let [tex]p_{1}[/tex] be the probability that commercial cars have rear license plates and [tex]p_{2}[/tex] be the probability that connected trucks have rear license plates.

                         Cars                     Trucks                         Total

Total                  2049                    334                             2383

x                          239                      45                                284

p                        0.1166                   0.1347                          0.1191

α=0.05

Hypothesis will be  :

[tex]H_{0}:p_{1} =p_{2}[/tex]

[tex]H_{1} :p_{1} < p_{2}[/tex]

It is a left tailed test at 0.05 significance.

Standard errors of p=[tex]\sqrt{p(1-p)/n}[/tex]

=[tex]\sqrt{(0.1191*0.8809)/2383}[/tex]

=[tex]\sqrt{0.1049/2383}[/tex]        

=0.0066

Test statistic Z=p difference/standard error

=(0.1166-0.1347)/0.0066

=-0.0181/0.0061

=-2.967

p value=0.001505<5%

Since p is less than 5% we reject null hypothesis.

We cannot calculate standard deviation so  we cannot calculate confidence interval.

Hence there is statistical evidence at 5% significance level to support that commercial truck owners violate laws requiring front license plates at a higher rate than owners of passenger cars.

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The probability that kids will be able to write something about both the French and Spanish classes after he is finished with the interviews is 91/100.

Given 25 kids has enrolled in atleast one foreign language class. 18 kids are in French class and 21 kids are in Spanish class.

We have to find the probability that kids will be able to write something about both the French and Spanish classes after Michael is finished with the interviews.

Let F is a set showing students knowing French,

S be a set showing students knowing Spanish ,

FS= Showing students both enrolled in one languages.

FS=F+S-(F∪S)

=18+21-25

=14

F-18-14=4

S=21-14

=7

4 outcomes lead to Michael being able to write both the languages are (F,S),(FS,S)(FS,F)(FS,FS)

Required probability is the sum of all the probabilities of (F,)(FS,S)(FS,F)(FS,FS)

P(F,S)=[tex]4C_{1}*7C_{1}/25C_{2}[/tex]

=(4*7)/300

=28/300

P(FS,S)=[tex](14C_{1}*7C_{1} )/25C_{2}[/tex]

=14*7/300

=98/300

P(FS,F)=[tex](14C_{1}*4C_{1} )/25C_{2}[/tex]

=14*4/300

=56/300

P(FS,FS)=[tex]14C_{2}/25C_{2}[/tex]

=91/300

Required probability=28/300+98/300+56/300+91/300

=(28+98+56+91)/300

=273/300

=91/100

Hence the probability that kids will be able to write both the languages is 0.91.

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The radius or any additional information related to the circle to assist in calculating the length of the 40-degree arc.

To find the length of a 40-degree arc, to know the radius or diameter of the circle to which the arc belongs. Once you have that information, use the formula to find the arc length:

Arc Length = (θ / 360) × 2 ×π ×r

Where:

θ = Central angle in degrees (40 degrees in this case)

r = Radius of the circle

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Answer: 180

Step-by-step explanation:

i got you!!!!!!! Hope u pass

Answer:

180

Step-by-step explanation:

<f and <g are on a straight line and they are supplementary angles which means their sum is equal to 180.

Answer:

A.  [tex]\frac{21}{4} \pi\ \space\ in[/tex]

Step-by-step explanation:

The formula for arc length is:

arc length = rθ

where:

r is the radius = 7 in

θ is the central angle in radians = 135  ×  [tex]\frac{ \space\ \pi\ }{180}[/tex]  = 3/4 π

Substituting these values into the formula:
arc length = 7 in × 3/4 π

                 = [tex]\frac{21}{4} \pi\ \space\ in[/tex]