Answer:
a gray substance and colourless liquid
Explanation:
lead oxide is reduced to lead while hydrogen is oxidized to water
How much heat is released if you produced 1.24 mol of Oz?
Consider a buffer made by adding 132.8 g of NaC₇H₅O₂ to 300.0 mL of 1.17 M HC₇H₅O₂ (Ka = 6.3 x 10⁻⁵) What is the pH of this buffer?
Answer:
pH = 1.62
Explanation:
We can solve this problem using Henderson-Hasselbach's equation:
pH = pKa + log[tex]\frac{[A^-]}{[HA]}[/tex]Where
pKa = -log(Ka) = 4.20[A⁻] = [NaC₇H₅O₂][HA] = [HC₇H₅O₂]Now we convert 132.8 g of NaC₇H₅O₂ into moles, using its molar mass:
132.8 ÷ 144.11 g/mol = 0.921 molesThen we calculate [NaC₇H₅O₂]:
0.921 moles / 300.0 mL = 0.003 MNow we can proceed to calculate the pH of the solution:
pH = 4.20 + log[tex]\frac{0.003}{1.17}[/tex]pH = 1.62Which of the following is NOT a benefit of strength training? WILL GIVE BRAINLIEST! :)
A. Better control of muscle
B. More efficient movement
C. Decreased force variance
D. Increased flexibility
I think it's D
Explanation:
if you think abt it strength training means weights and stuff so I dont think it increases flexibility. it's that or letter C
Use the following chemical equation, how many moles of ammonia (NH 3 ) produced when 3.15 moles of nitrogen (N 2 ) reacts with hydrogen (H 2 ) ? N 2(g) + 3H 2(g) 2NH 3(g)
Answer:
[tex]n_{NH_3}^{produced}=6.3molNH_3[/tex]
Explanation:
Hello there!
In this case, according to the given chemical reaction, it is possible for us to use the 1:2 mole ratio of nitrogen to ammonia to calculate the moles of the latter that are produced when reacting 3.15 moles of the former with hydrogen as shown below:
[tex]n_{NH_3}^{produced}=3.15molN_2*\frac{2molNH_3}{1molN_2}[/tex]
Thus, by solving the equation we obtain:
[tex]n_{NH_3}^{produced}=6.3molNH_3[/tex]
Best regards!
Silver sulfate dissociates into silver ions and sulfate ions:
Ag2SO4(s) = 2Ag+ (aq) + SO42- (aq)
Which of the following equations is the equilibrium constant expression for
this reaction?
A. Kot
[Ag+][80.21
[Ag 2504)
O B. Ko = [Ag+ 12 [5042")
[A92504)
O C. KE =
[Ag+1?[s042-7
O D. KG
[A92504
[Ag+ ][5042-)
Answer:
A its a step by step equation the answer is A
Liquid water - heat =
Pls help now!!!
Answer:
cold or ice?
Explanation:
have a good day.
A motorcycle that travels north 201m in 7s. What is it's velocity?
7. D=
8. TE
9. V=
Part A
How many moles of chlorine gas are needed to make 0.6 moles of sodium chloride?
Given the reaction: 2Na + Cl2 + 2NaCl
O 1.2
O 0.6
0 3.6
O 0.3
not enough information
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Answer:
[tex]n_{Cl_2}=0.3molCl_2[/tex]
Explanation:
Hello there!
In this case, according to the given chemical reaction whereas the sodium chloride is in a 2:1 mole ratio with chlorine, the required moles of the later are computed as shown below:
[tex]n_{Cl_2}=0.6molNaCl*\frac{1molCl_2}{2molNaCl}[/tex]
So we cancel out the moles of NaCl to obtain:
[tex]n_{Cl_2}=0.3molCl_2[/tex]
Best regards!
1. What volume of gas (NU) is formed by the interaction of 13 g of zinc with 400 g of sulfuric acid solution with a mass fraction of 10%?
Answer:
4.5L of gas are produced
Explanation:
Based on the reaction:
Zn + H2SO4 → ZnSO4 + H2(g)
Where 1 mole of Zn reacts with 1 mole of sulfuric acid to produce 1 mole of H2, the gas
To solve this question we must find the moles of each reactant in order to find limiting reactant and, thus, the moles of H2 produced. Then using PV=nRT we can find the volume of the gas:
Moles Zn -Molar mass: 65.38g/mol-
13g * (1mol / 65.38g) = 0.20 moles Zn
Moles H2SO4 -Molar mass: 98g/mol-
400g * 10% = 40g H2SO4 * (1mol / 98g) = 0.41 moles H2SO4
As the ratio of the reaction is 1:1, the limiting reactant is Zn and the moles produced of H2 are 0.20 moles
Using PV = nRT; V = nRT/ P
Where V is the volume of the gas
n are the moles = 0.20 moles
R is gas constant = 0.082atmL/molK
T is absolute temperature = 273.15K at STP
P is pressure = 1atm at STP
V = 0.20mol*0.082atmL/molK*273.15K / 1atm
V = 4.5L of gas are produced
How many moles of solute are in a .5 liter solution of carbonated water, if the concentration is 3.0 M?
Answer:
[tex]1 \: litre \: solution \: contains \: 3 \: moles \\ 5 \: litres \: will \: contain \: \frac{(5 \times 3)}{1} \: moles \\ = 15 \: moles \: of \: solute[/tex]
6.3x10-5M. What is the pH?
Answer:
https://sensorex.com/ph-calculator/
Explanation:
go to this link and then scroll down a little bit and then you'll find the answer
What volume will 1.27 moles of helium gas occupy at 80.00 °C and 1.00 atm?
Pls and thank you :) !
Answer:
36.8 L
Explanation:
We'll begin by converting 80 °C to Kelvin temperature. This can be obtained as follow:
T(K) = T(°C) + 273
T(°C) = 80 °C
T(K) = 80 + 273
T(K) = 353 K
Finally, we shall determine the volume occupied by the helium gas. This can be obtained as follow:
Number of mole (n) = 1.27 moles
Temperature (T) = 353 K
Pressure (P) = 1 atm
Gas constant (R) = 0.0821 atm.L/Kmol
Volume (V) =?
PV = nRT
1 × V = 1.27 × 0.0821 × 353
V = 36.8 L
Thus, the volume occupied by the helium gas is 36.8 L
If four hydrogen atoms react with two hydrogen atoms, how many atoms
will be in the product?
Answer:6
Explanation:
The number of atoms in the product will be equal to six.
What is the balanced chemical equation?A chemical equation represents a chemical reaction in terms of the chemical symbols of the substances. A chemical equation of a reaction posses of participated reactants, formed products, and an arrow to indicate the direction of the chemical reaction.
The chemical equation of a reaction in which the number of atoms of each element is equal on either side of the equation is known as a balanced chemical equation.
The law of conservation of mass is always followed by a balancing of a chemical equation. By following this law, the total mass of all the elements on the reactant side will be equal to the total mass of all elements on the product side in a balanced chemical equation.
Therefore, the number of hydrogen atoms on the reactant side is equal to 6 (4+2) and the same number of atoms will be on the product side.
Learn more about the balanced chemical equation, here:
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i need help help me please
Answer:
C is the correct answer.
Explanation:
We can eliminate some answers immediately:
A is incorrect because nitrogen and hydrogen do not change their identity, they just combine into a new molecule that contains them. Notice how there are 2 nitrogen atoms and 6 hydrogen atoms on both sides of the equation.
B is incorrect because the first law of thermodynamics tells us that matter and energy will always be conserved, so the mass of the products must be equal to the mass of the reactants, not less than the mass of the reactants.
C is correct because balanced chemical equations help chemists predict how much product will form from certain amounts of reactants.
D is incorrect because this equation is showing the exact opposite. Molecular hydrogen and nitrogen can combine stoichiometrically to form ammonia.
Humans are always consumers. Most humans are omnivores, but some
humans eat only plant matter making them herbivores. However, all
humans are considered to be -
Select one:
autotrophs
heterotrophs
producers
carnivores
Answer:
A. Autotrophs
Explanation:
an autotroph, def an organism that is able to form nutritional organic substances from simple inorganic substances such as carbon dioxide.
humans and other mammals, plants, and a select few other things
Determine the mass and weight of the air in your living room at 20°C ; the room has the following dimensions ;4m ×5m floor and ceiling is at 3m height. Take the density of the air as
Answer:
Volume of air is [tex]60[/tex] cubic meter
Mass of air is [tex]72.246[/tex] Kilogram
Explanation:
As air occupies the volume of the container in which it is kept. The volume of air here in this case will be equal to the volume of the room.
Volume of the room = length * breadth * height
Volume of the room = [tex]4*5*3 = 60[/tex] cubic meter.
Volume of air is also [tex]60[/tex] cubic meter.
Density of air at 20 degrees C [tex]= 1.2041[/tex] kg/cu.m
Mass of air
Volume * density
[tex]60 * 1.2041 = 72.246[/tex] kilogram
Volume of air is [tex]60[/tex] cubic meter
Mass of air is [tex]72.246[/tex] Kilogram
14.3 moles of methane (CH4) burns completely, find the grams of H20 would be produced CH4 + 202 CO2 + 2H20 w
Answer:
514.8 grams of H₂O would be produced.
Explanation:
The balanced reaction is:
CH₄ + 2 O₂ → CO₂ + 2 H₂O
By stoichiometry of the reaction (that is, the relationship between the amount of reagents and products in a chemical reaction), the following amounts of moles participate in the reaction:
CH₄: 1 mole O₂: 2 molesCO₂: 1 mole H₂O: 2 molesBeing the molar mass of each compound:
CH₄: 16 g/moleO₂: 32 g/moleCO₂: 44 g/mole H₂O: 18 g/moleBy stoichiometry, the following amounts of mass participate in the reaction:
CH₄: 1 mole* 16 g/mole= 16 gramsO₂: 2 moles* 32 g/mole= 64 gramsCO₂: 1 mole* 44 g/mole= 44 gramsH₂O: 2 moles* 18 g/mole= 36 gramsYou can apply the following rule of three: if 1 mole of methane produces 36 grams of water, 14.3 moles of methane produces how much mass of water?
[tex]mass of water=\frac{14.3 moles of methane*36 grams of water}{1 mole of methane}[/tex]
mass of water= 514.8 grams
514.8 grams of H₂O would be produced.
Combine terms: 12a + 26b -4b – 16a.
Answer:
= -4a+22b
Explanation:
i hope this helps :)
Answer:
12a-16a =-4a
26b -4b =22b
the final answer is-4a +22b
What is the frequency of a light source that has a wavelength of 430 NM? What is the energy of this wave?
Answer:
Explanation:
[tex]c = f \lambda[/tex]
where c = speed of light (3x10^8m/s)
f = frequency
[tex]\lambda[/tex] = wavelength.
We can solve that the frequency is (3x10^8)/(420 x 10^-9) = 7.14x10^14 Hz
Also, E = hf where h = 6.62x10^-34.
So the energy is (6.62x10^-34) x (7.14x10^14) = 4.73x10^-19 J.
Hope this helps and tell me if I made any mistakes.
A sample of 0.0255 mol potassium hydroxide, KOH, was dissolved in water to yield
10.0 mL of solution. What is the molarity of the solution?
According to molar concentration, the molarity of the solution is 2.55 M.
What is molar concentration?Molar concentration is defined as a measure by which concentration of chemical substances present in a solution are determined. It is defined in particular reference to solute concentration in a solution . Most commonly used unit for molar concentration is moles/liter.
The molar concentration depends on change in volume of the solution which is mainly due to thermal expansion. Molar concentration is calculated by the formula, molar concentration=mass/ molar mass ×1/volume of solution in liters.
In terms of moles, it's formula is given as molar concentration= number of moles /volume of solution in liters.
Substituting values in the given second formula, molarity=0.0255/0.010=2.55 M.
Thus, the molar concentration of the solution is 2.55 M.
Learn more about molar concentration,here:
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Your teacher gives you 0.09 L of a 0.850 M solution of NaCl dissolved in water. What will the new volume be if you dilute it down to 0.500 M?
Answer:
[tex]V_2=0.153L[/tex]
Explanation:
Hey there!
In this case, according to the equation for dilution process, in which the moles of the solute remain the same after the addition of additional solvent:
[tex]M_1V_1=M_2V_2[/tex]
Thus, by solving for the new volume, V2, of the base, NaOH, we can obtain:
[tex]V_2=\frac{M_1V_1}{M_2}=\frac{0.09L*0.850M}{0.500M}\\\\V_2=0.153L[/tex]
Best regards!
9. The broken appearance of pencil in a glass of water is due
to the refraction of light in water,
yes or no
Students can demonstrate reflection by doing which of the following?
A Warming metal under a heat lamp.
B. Observing their own image in still water.
C. Enlarging an image using a hand lens.
0
D. Measuring a shadow made by the Sun.
Answer:
a
Explanation:
How many grams of water can be heated from 15.0°C to 75°C using 12,500 Joules?
Answer:
m = 49.8 g
Explanation:
Hello there!
In this case, for this calorimetry processes we can define the involved heat in terms of mass, specific heat and temperature as shown below:
[tex]Q=mC\Delta T[/tex]
Thus, given the heat, final and initial temperature and specific heat of water (4.184), the mass of water can be computed as shown below:
[tex]m=\frac{Q}{C\Delta T}\\\\m=\frac{12500J}{4.184\frac{J}{g\°C}(75\°C-15.0\°C)} \\\\m=49.8g[/tex]
Best regards!
In the endothermic reaction below, how would adding heat affect the equilibrium of the system? (2 points)
A + B + energy ⇄ + D
a. shift it to the left toward the reactants
b. shift it to the right toward the products
c. equally create more products and reactants
d. it would have no effect
If 2.00 moles of H2 and 1.55 moles of Oz react how many moles of H20
can be produced in the reaction below?
2 H2(g) + O2(g) → 2 H2O(g)
Considering the limiting reactant concept, how many moles of copper(1) sulfide are produced from the reaction of 20 mole of
copper and 2.4 mole of sulfur?
2 Cu(s) + s(s) Cu2S(s)
(No links or bad answer real d
What is the correct coefficient for Fe2O3 in the balanced version of the following equation?
Fe2O3 + 3H2 → 2Fe + 3H2O
__Fe2O3+3H2→2Fe+3H2O
Answer:
The coefficient of Fe₂O₃ is 1
Explanation:
__Fe₂O₃ + 3H₂ —> 2Fe + 3H₂O
To know the correct coefficient of Fe₂O₃, we shall balanced the equation. This can be obtained as follow:
Fe₂O₃ + H₂ —> Fe + H₂O
There are 2 atoms of Fe on the left side and 1 atom on right side. It can be balance by writing 2 before Fe as shown below:
Fe₂O₃ + H₂ —> 2Fe + H₂O
There are 3 atoms of O on the left side and 1 atom on the right side. It can be balance by writing 3 before H₂O as shown below:
Fe₂O₃ + H₂ —> 2Fe + 3H₂O
There are 2 atoms of H on the left side and 6 atoms on the right side. It can be balance by writing 3 before H₂ as shown below:
Fe₂O₃ + 3H₂ —> 2Fe + 3H₂O
Now, the equation is balanced.
Thus, the coefficient of Fe₂O₃ is 1
What would happen to the moon’s interia were to increase? A the moon will fly into space. B the moon will smash into Earth. C the moon will smash into pluto.
Answer:
B
Explanation:
Jupiter's mass is more than _________ the mass of the other planets put together.
Answer:
2.5 times
Explanation:
Jupiter's mass is 2.5 times that of all the other planets in the Solar System combined—this is so massive that its barycenter with the Sun lies beyond the Sun's surface at 1.068 solar radii from the Sun's center.