Answer:
The first object is experiencing a larger centripetal force because its radius is smaller compared to the second object.
Explanation:
Given;
radius of the first object, r₁ = 10 cm = 0.1 m
radius of the second object, r₂ = 0.2 m
let the mass of the two objects, = m
let the speed of the two objects = v
The centripetal force of the first object is given by;
[tex]F_c_1 = \frac{mv^2}{r_1} \\\\F_c_1 = \frac{mv^2}{0.1}\\\\F_c_1 = 10mv^2[/tex]
The centripetal force of the second object is given by;
[tex]F_c_2 = \frac{mv^2}{r_2} \\\\F_c_2 = \frac{mv^2}{0.2}\\\\F_c_1 = 5mv^2[/tex]
Therefore, the first object is experiencing a larger centripetal force because its radius is smaller compared to the second object.
Mass is sometimes described as the difficulty of acceleration of an object. How does Newton's second law agree with this description?
Answer:
Increasing force tends to increase acceleration while increasing mass tends to decrease acceleration. Thus, the greater force on more massive objects is offset by the inverse influence of greater mass. Subsequently, all objects free fall at the same rate of acceleration, regardless of their mass.
If the mass increases, it's harder to accelerate
Because force tends to rise with mass while mass tends to decrease with force, mass is sometimes referred to as the difficulty of accelerating an item. As a result, the greater mass's inverse effect balances out the larger force exerted on more massive objects.
Newton's second law agreement with difficulty of acceleration of an object-While acceleration tends to decrease as mass increases, it tends to increase as force increases. As a result, the bigger force acting on more massive objects is balanced off by the greater mass's inverse effect.As a result, all things fall in free fall at the same rate of acceleration regardless of mass. As the mass increases, accelerating becomes more difficult.Newton's second law of motion is applicable when there are unbalanced forces acting on an object.The second law states that an object's rate of acceleration depends on both its mass and the net force acting on it.An object's acceleration is directly proportional to the net force applied on it and inversely proportional to its mass.An object's acceleration increases as the amount of force exerted on it does.A decreasing acceleration is caused by a rise in an object's mass.The acceleration of an item caused by a net force is inversely proportional to the mass of the object and directly proportional to the magnitude of the net force in the same direction.To learn more about Newton's second law of motion click here-
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PLZ HELP!! List properties of ions.
a mule pulls a cart of milk 10 meters, with a force of 50 newtons calculate the work done by the mule
Answer:
500 JExplanation:
The work done by an object can be found by using the formula
workdone = force × distance
From the question we have
workdone = 50 × 10
We have the final answer as
500 JHope this helps you
Which type of star cluster is shown?
Answer:
♡ madeline here ♡
you forgot the attachment, luv ☆
have a great day!
- madeline/madi ✧･ﾟ: *✧･ﾟ:･ﾟ✧*:･ﾟ✧･ﾟ
Explanation:
OPENNNN
I AM CORRECT AND DATS MY NAMEEE OO I BE LIKE 2POC CHAINS:);)
Which condition must be met in order for an equation to be balanced? The elements in the reactants are the same as the elements in the products. There are fewer elements in the reactants than there are in the products. The number of atoms in the reactants is greater than the number of atoms in the products. The number of atoms in the reactants equals the number of atoms in the products
Answer:
The elements in the reactants are the same as the elements in the products
Explanation:
The condition for a balanced equation is as follows :
The number of atoms for each element in reactant = Number of atoms for each element in product.
Total charge on reactant and product must be same.
The example of a balanced equation is:
Reaction of carbon and hydrogen :
[tex]C+2H_2\rightarrow CH_4[/tex]
No. of carbon atom on Carbon on LHS = 1
No. of carbon atom on Hydrogen on LHS = 4
No. of carbon atom on Carbon on RHS = 1
No. of carbon atom on Hydrogen on RHS = 4
So, for a balanced equation, The elements in the reactants are the same as the elements in the products. Hence, the correct option (a).
Answer:
The answer is A
Explanation:
What is matter made of
Answer: Matter is made up of atoms that also come together to form molocules. Atoms contain Electrons (Negetive), nutronons (nuaetral), and protons (positive).
You are traveling down the highway when you notice a cop 200 meters ahead of you. For the next 5 seconds, you step on the bake to avoid a speeding ticket. The brake causes an acceleration on your car of -2.0 m/s^2.
Answer:
ok, I don't see the question.
Explanation:
What does a generator do?
O A. Turns mechanical energy into electrical energy
O B. Turns sound energy into electrical energy
O c. Uses electricity to make magnets
O D. Turns electrical energy into mechanical energy
A shopping cart given an initial velocity of 2.0 m/s undergoes a constant acceleration of 3.0 m/s2. What is the cart’s displacement after the first 4.0 s of its motion?
What is your car's initial velocity?
How long is the cart accelerating for?
What is the acceleration of the cart?
Write the equation you will use to solve this problem.
What is the displacement of the shopping cart?
32 m
10 m
55 m
80 m
Final Velocity = 14m/s
Displacement = 56m
Explanation:
U (initial velocity) = 2m/s
A (acceleration) = 3m/s^2
T (time) = 4s
v (final velocity) = ?
S (displacement) = ?
FIRST FIND FINAL VELOCITY:
[tex]a = \frac{v - u}{t} [/tex]
(i) Multiply both sides by t:
[tex]a \times t = v - u[/tex]
(ii) Add u to both sides:
[tex](a \times t) + u = v[/tex]
(iii) rearrange formula:
[tex]v = (a \times t) + u[/tex]
v = ( 3 × 4 ) + 2
v = 12 + 2
v = 14m/s
SECOND FIND DISPLACEMENT:
[tex]v = \frac{s}{t} [/tex]
(i) Multiply both sides by t:
[tex]v \times t = s[/tex]
(ii) Rearrange formula:
[tex]s = v \times t[/tex]
s = 14 × 4
s = 56m
Not sure why it isn't one of the options but im pretty sure I did all the steps right...
The diagram shows the electrical circuit inside a flashlight when the switch is
open and closed.
Which series of energy transformations occurs when the switch is closed?
A. Chemical energy - Electrical energy - Light energy
B. Mechanical energy - Light energy - Electrical energy
C. Electrical energy Light energy - Mechanical energy
D. Light energy - Electrical energy - Chemical energy
Answer:
A.
Explanation:
I got it right ;)
Answer:
Chemical energy ---> Electrical energy ---> Light energy
Explanation:
If a 28-N force causes a rock to accelerate at 4 m/s/s, what is the mass of the rock?
Answer:
7kg
Explanation:
Given parameters:
Force on the rock = 28N
Acceleration = 4m/s²
Unknown:
Mass of the rock = ?
Solution:
According to newton's second law of motion;
Force = mass x acceleration
Insert the given parameters to find the mass;
28 = mass x 4
mass = [tex]\frac{28}{4}[/tex] = 7kg
A cube of wood having an edge dimension of 19.5 cm and a density of 651 kg/m3 floats on water.
Required:
a. What is the distance from the horizontal top surface of the cube to the water level?
b. What mass of lead should be placed on the cube so that the top of the cube will be just level with the water surface?
Answer:
a) y ’= 0.068 m , b) m_lead = 2,599 kg
Explanation:
a) To solve this exercise, let's use Archimedes' law, which establishes that the pressure of the water is equal to the weight of the dislodged liquid.
Let's write the forces in the equilibrium condition
B - W = 0
B = W
Thrust is
B = ρ_liquid g V_water
Body weight is
W = m g
the definition of density
ρ_body = m / V
we substitute
W = ρ_body g V_body
The volume of the body is
V_body = L³
The volume of water is
V_agua = y L²
we substitute
ρ_liquid g and L2 = rho_body g L3
ρ_liquid y = ρ_body L
y = L ρ_body /ρ_liquid
let's calculate
y = 651/100 0.195
y = 0.1269 m
this is the distance from the bottom of the cube, the distance from the top of the cube
y ’= 0.195 -y
y '= 0.195 - 0.1269
y ’= 0.068 m
b) In this case the equilibrium equation is
B - W_body - W_lead = 0
B = W_body + W_lead
ρ_liquido g V_liquido = ρ_body g V_body + m_lead g = 0
ρ_liquid L3 = ρ_body L3 + m_lead = 0
m_lead = L3 (ρ_liquid - ρ_body)
let's calculate
m_lead = 0.195 3 (1000 - 651)
m_lead = 2,599 kg
Look at the Kunoichi's of Naruto but as a Gang.
Who do you think looks the baddest out of the group(but in a good way)?
My opinion is Hinata...just saying
Answer:
hinata for sure
Explanation:
seems reasonable
A motorcycle has a mass of 240 kg and accelerates at a rate of 4 m/s2
Work out the driving force of the motorcycle.
Solution:
Using
F = m a
F = 240 x 4
F = 960 N
Answer:
960N
Explanation:
Given parameters:
Mass of the motorcycle = 240kg
Acceleration of the motorcycle = 4m/s²
Unknown:
Driving force of the motorcycle = ?
Solution:
According to the Newton's second law of motion "the force on a body is the product of mass and acceleration".
Force = mass x acceleration
Insert the parameters and solve;
Force = 240 x 4 = 960N
You are riding in an elevator that is accelerating upward. Suppose you stand on a scale. The reading on the scale is __________.
a. Greater than your true weight
b. Equal to your true weight
c. Less than your true weight
d. It's impossible to determine
Answer: A
Explanation: Your body gets pulled down, causing ur body to have more weight but not mass.
If a rock hits the ground with a KE of 33,000 J, falling from a height of 10 m, what is its weight? Remember, weight is measured in newtons (N), and is equal to mass times gravity.
A. 330 N
B. 33 N
C. It can't be computed from this information
D. 3,300 N
Answer is 3,300N
Explanation
What power is supplied to the starter motor of a large truck that draws 290 A of current from a 20.4 V battery hookup?
Answer:
Power = 5.916 Kw
Explanation:
Given:
Current = 290 A
Volt = 20.4 V
Find:
Power
Computation:
Power = IV
Power = (290)(20.4)
Power = 5916 w
Power = 5.916 Kw
A force is exerted on a charge carrying particle by a ________ _____ only when the particle moves ________the field lines. If a charged particle moves parallel to the magnetic field, the force exerted by the magnetic field on the charged particle is__________.
Answer:
force is exerted on a charge carrying particle by a MAGNETIC FIELD only when the particle moves PERPENDICULAR the field lines. If a charged particle moves parallel to the magnetic field, the force exerted by the magnetic field on the charged particle is_ ZERO
Explanation:
This complementation exercise refers to the magnetic force that the formula has
F = q v x B
where the bold letters indicate vents and the x the vector product. The module of this product is
F = qv B sin θ
where θ is the angle between the speed and direction of the magnetic field.
It can be seen that for the force to be different from zero, the angle must not be parallel θ = 0
sin 0 = 0
the maximum value is obtained for an angle of θ = 90º
sin 90 = 1
Using these concepts we see that the missing words are.
force is exerted on a charge carrying particle by a MAGNETIC FIELD only when the particle moves PERPENDICULAR the field lines. If a charged particle moves parallel to the magnetic field, the force exerted by the magnetic field on the charged particle is_ ZERO_______
A force of 1.50 N acts on a 0.20 kg trolley so as to accelerate it along an air track. The track and force are horizontal and in line. How fast is the trolley going after acceleration from rest through 30 cm, if friction is negligible?
Answer:
Final velocity, V = 2.1213 m/s.
Explanation:
Given the following data;
Force, F = 1.50N
Mass, m = 0.2kg
Displacement, S = 30cm to meters = 30/100 = 0.3m
To find the acceleration;
Force is given by the multiplication of mass and acceleration.
Mathematically, Force is given by the formula;
[tex] F = ma[/tex] .......equation 1
Where;
F represents force.m represents the mass of an object.a represents acceleration.Making acceleration (a) the subject, we have;
[tex]Acceleration (a) = \frac{F}{m}[/tex]
Substituting into the above equation, we have;
[tex]Acceleration, a = \frac{1.5}{0.2}[/tex]
Acceleration, a = 7.5m/s²
Now to find the final velocity, we would use the third equation of motion;
[tex] V^{2} = U^{2} + 2aS [/tex] .....equation 2
Where;
V represents the final velocity measured in meter per seconds. U represents the initial velocity measured in meter per seconds. a represents acceleration measured in meters per seconds square. S represents the displacement measured in meters.Note: Since the trolley is starting from rest, we know that it's initial velocity is 0.
Substituting the values into equation 2, we have;
[tex] V^{2} = 0^{2} + 2*7.5*0.3[/tex]
[tex] V^{2} = 0 + 4.5[/tex]
[tex] V^{2} = 4.5[/tex]
Taking the square root, we have;
[tex] V = \sqrt {4.5}[/tex]
V = 2.1213 m/s.
Therefore, the speed of the trolley after accelerating from rest through 0.3 m, if friction is negligible is 2.1213 m/s.
A 1.20 kg solid ball of radius 40 cm rolls down a 5.20 m long incline of 25 degrees. Ignoring any loss due to friction, how fast will the ball be rolling when it reaches the bottom of the incline?
Answer:
1.6s
Explanation:
Given that A 1.20 kg solid ball of radius 40 cm rolls down a 5.20 m long incline of 25 degrees. Ignoring any loss due to friction,
To know how fast the ball will roll when it reaches the bottom of the incline, we need to calculate the acceleration at which it is rolling.
Since the frictional force is negligible, at the top of the incline plane, the potential energy = mgh
Where h = 5.2sin25
h = 2.2 m
P.E = 1.2 × 9.8 × 2.2
P.E = 25.84 j
At the bottom, K.E = P.E
1/2mv^2 = 25.84
Substitutes mass into the formula
1.2 × V^2 = 51.69
V^2 = 51.69/1.2
V^2 = 43.07
V = 6.56 m/s
Using the third equation of motion
V^2 = U^2 + 2as
Since the object started from rest,
U = 0
6.56^2 = 2 × a × 5.2
43.07 = 10.4a
a = 43.07/10.4
a = 4.14 m/s^2
Using the first equation of motion,
V = U + at
Where U = 0
6.56 = 4.14t
t = 6.56/4.14
t = 1.58s
Therefore, the time the ball rolls when it reaches the bottom of the incline is approximately 1.6s
Superman strikes a golf ball on the ground at a 38 degree angle above the horizontal at 147 m/s. What is the maximum height the golf ball reaches?
255 m
418 m
687 m
1103 m
The ball is hit with an initial vertical velocity of
(147 m/s) sin(38º) ≈ 90.5 m/s
Recall that
v ² - u ² = 2 a ∆y
where u and v are initial and final velocities, respectively; a is acceleration; and ∆y is displacement.
Vertically, the ball is in freefall, so it is only subject to acceleration due to gravity, with magnitude g = 9.80 m/s² in the downward direction. At its maximum height, the ball has zero vertical velocity (v = 0) and the displacement is equal to the maximum height, so
0² - (90.5 m/s)² = 2 (-g) ∆y
∆y = (90.5 m/s)² / (2g)
∆y ≈ 418 m
4- If the length of the pendulum 28 cm and the mass of the bullet (projectile) is 70 g, and the mass of the block 240 g, and the maximum angle reached is ϴ = 44˚. Answer the followings:
a. The maximum height reached.
b. The mechanical energy after collision.
c. The bullet velocity.
bhai I know this answer if you mark as brain last you see my attachment
A wave with a frequency of 230 Hz has a wavelength of 0.25 meters. At what speed will this wave travel?
Which TWO statements describe events that help drive tectonic plate movement
A. Energy from the sun heats magma beneath earths surface
B. Convection currents cause hotter magma to rise and cooler magma to sink
C. Thermal energy from earths core is transferred outward to the mantle by conduction
D. Subduction plates cause cooling at convergent boundaries
Answer:
The answer is D & B
Explanation:
I took the quiz on this. I hope this helps!
The two statements describe events that help drive tectonic plate movement are:
B. Convection currents cause hotter magma to rise and cooler magma to sink
D. Subduction plates cause cooling at convergent boundaries
What is a tectonic plate?A tectonic plate (also called lithospheric plate) is a massive, irregularly shaped slab of solid rock, generally composed of both continental and oceanic lithosphere.
Plate size can vary greatly, from a few hundred to thousands of kilometers across; the Pacific and Antarctic Plates are among the largest.
Plate thickness also varies greatly, ranging from less than 15 km for young oceanic lithosphere to about 200 km or more for ancient continental lithosphere (for example, the interior parts of North and South America).
Tectonic plates, large slabs of rock that divide Earth’s crust, move constantly to reshape the Earth’s landscape. The system of ideas behind plate tectonics theory suggests that Earth's outer shell (lithosphere) is divided into several plates that glide over the Earth’s rocky inner layer above the soft core (mantle).
The plates act like a hard and rigid shell compared to Earth's mantle. The mantle sits between Earth's dense, very hot core and its thin outer layer, the crust.
At subduction zones, a convergent boundary occurs when two tectonic plates push together. When an ocean plate and a continental plate collide, the ocean plate slides under the continental plate, and bends downward.
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Which formula can be used to find the tangential speed of an orbiting object? v = StartFraction 2 pi r over T EndFraction v = StartFraction square root of 2 pi r over T EndFraction v = GStartFraction m Subscript central Baseline over r EndFraction v = rStartFraction (m Subscript central Baseline) over G EndFraction
Answer:
It's A v=2pi/T
Explanation:
I took the test and got it correct.
The correct formula that can be used to find the tangential speed of an orbiting object is : ( A ) v = 2π r /T
Tangential speedTangential speed is the speed or velocity of an object moving in a circular path is calculated as 2π r/T where T = time it takes to complete one rotation and 2π r is angular velocity( w ).
Therefore from the options listed above the correct expression for the tangential speed is v =2π r /T
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If the speed of a roller coaster at the bottom of a hill is 20.0 m/s , what is the tallest hill the coaster can climb, assuming no friction losses ?
Answer:
20.4 meters
Explanation:
KE = 1/2 m v^2 = mgh = PE (convert all kinetic energy to potential energy, because at the highest point the coaster can climb, it will be stopped!)
=> h = (1/2 m v^2) / (mg) = v^2/(2*g) = (20 m/s)^2 / (2*9.8 m/s^2) = 20.4 m
The tallest height that the roller coaster can climb is 20 m.
A roller coaster is a device in which energy conversions from potential to kinetic energy takes place. Hence the roller coaster can easily be used to demonstrate the conversion of mechanical energy from one form to another.
Given that the velocity of the roller coaster at the bottom of the hill is 20.0 m/s, potential energy is converted into kinetic energy.
Hence;
mgh = 1/2mv^2
gh =1/2v^2
h = 1/2v^2/g
h = 0.5 × (20)^2/10
h = 20 m
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If a 28-N force causes a rock to accelerate at 4 m/s/s, what is the mass of the rock?
Answer:
Explanation:
we know that
F=ma
F=28 N
a=4 m/s²
m=F/a
m=28/4
m=7 kg
A person weighs 780N on earth. What is his mass on earth, mass on moon? What is his weight on the moon?
Answer:
79.6kg
127.5N
Explanation:
Given parameters:
Weight of the person on earth = 780N
Now, we are to find;
Mass on earth;
Mass on moon;
Weight on moon
Solution:
The mass on earth and on the moon are the same. Mass is the amount of matter in a substance.
Weight = mass x acceleration due to gravity
780 = mass x 9.8
mass = [tex]\frac{780}{9.8}[/tex] = 79.6kg
Mass on earth and moon = 79.6kg
The acceleration due to gravity on the moon is 1.6m/s²
Weight on moon = 79.6 x 1.6 = 127.5N
Light reflects off many objects. Which model of light behavior best helps explain this effect7(2 points)
оа
Particle model
b
Wave model
Ос
Magnetic model
Od
Electric model
feather is dropped from 13 m high after it has fallen 3 m what is its acceleration
Answer:
Explanation:
The constant acceleration of any object, neglecting air resistance and friction, is always -9.8. Proof:
[tex]s(t)=-4.9t^2+13[/tex] which is the position of this feather before it is dropped. The first derivative of position is velocity, so the velocity function for the feather is:
[tex]v(t)=-9.8t[/tex]. We could find the velocity that the feather is experiencing at 3 seconds, but that is not what we are being asked. What we are being asked is the acceleration of the feather at 3 seconds. So we find the acceleration function of the feather:
a(t) = -9.8
It turns out that the time doesn't matter to acceleration due to gravity because feathers and elephants all fall under the same pull.