Nora's hair dryer is 64% efficient. If 1000 J of energy is supplied to the hair dryer, how much energy will it transfer usefully to Nora's hair?

(a) The initial horizontal velocity of the driver is 10 m/s.

(b) The time taken for him to reach the water is 1.75 s.

(c) The horizontal displacement is 17.5 m.

The initial horizontal velocity of the driver is given as 10 m/s.

h = vy(t) + ¹/₂gt²

where;

h = 0 +  ¹/₂gt²

2h = gt²

t = √(2h/g)

t = √(2 x 15 / 9.8)

t = 1.75 s

X = Vx(t)

X = 10 x 1.75

X = 17.5 m

Thus, the initial horizontal velocity of the driver is 10 m/s, the time of motion is 1.75 s and the horizontal displacement is 17.5 m.

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The magnitude of the force exerted by the rope on the bucket is 8N.

To find the answer, we need to know about the force.

Thus, we can conclude that there's no force on the bucket by the person as he is lowering it by constant velocity. But force on the bucket by the rope is 8N.

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Answer:

The mass of the second student is 60 kg.

Explanation:

Note: It is assumed that radius of piston is 0.23 m and density ρ is 850 kg/m^3 and mass of first student is 55 kg.

There occurs a change in pressure on a piston when some mass is added on the other piston.

This change of mass on the piston is given by the formula,

Δm=ρhA/g

where A is the area of piston.

Given h=35 cm or 0.35 m, change in mass is,

Δm=850*(0.35)*π*(0.23)^2 / 9.8

Δm=5.0 kg

Therefore, the mass of the second student is 55+5=60 Kg

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Answer:

D. 20 N

Explanation:

Force = mass(m) × acceleration due to gravity (g)

Force = 2kg × 10m/s²

Force = 20N

Using algebra to solve for the the cost of the glass lenses gives the value for cost of glass lenses to be 4.

The cost of the glass lenses is calculated as follows:

Let cost of glass be y

Cost of plastic lenses = 4y

Cost of eye exam and  frames be z.

z + y = 30  (i)

z + 4y = 42 (ii)

(ii) - (i)

3y = 12

y = 4

Inconclusion, the cost of the glass lenses is 4.

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Answer: For a pull box housing shielded conductors carrying over 1000V and used in an angled pull, the distance between a conductor entry and exit must be 36 times the outside diameter.

Explanation: To find the correct explanation to the question, we have to find more about the pull box housing shielded conductors.

Thus, we can conclude that, for a pull box housing shielded conductors carrying over 1000V and used in an angled pull, the distance between a conductor entry and exit must be 36 times the outside diameter.

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New kinetic energy:

If the initial kinetic energy of a car is 0.3 MJ and the speed of the car decreased two times then the new kinetic energy will be 0.075 MJ.

The calculation for kinetic energy:

Step-1:

It is given that the car has a kinetic energy of 0.3 MJ. It is required to find the new kinetic energy when the car's speed decreases two times from its initial speed.

Let the mass of the car is m and the initial speed of the car is v.

It is known that the kinetic energy is calculated as,

[tex]\text{K.E}=\frac{1}{2}\times \text{mass}\times\text{speed}^2[/tex]

Therefore the initial kinetic energy is the car is,

[tex]\text{K.E}_1=\frac{1}{2}\times \text{m}\times\text{v}^2[/tex]

Step-2:

The speed of the car is decreased two times. Thus the speed becomes v/2. Therefore the final kinetic energy is the car is,

[tex]\text{K.E}_2&=\frac{1}{2}\times \text{m}\times(\frac{v}{2})^2\\&=\frac{1}{4}\times\frac{1}{2}\times \text{m}\times\text{v}^2\\&=\frac{1}{4}\times\text{K.E}_1\\&=\frac{1}{4}\times {0.3}\text{ MJ}\\&=0.075 \text{MJ}[/tex]

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Forward and downward speed are referred to as acceleration and deceleration respectively.

This is the rate at which an object gains speed with respect to time with its unit being meter per second square(m/s²).

Objects in constant speed are said to have a uniform motion. The downward speed is known as deceleration which involves the object losing speed to return to a state of rest.

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Answer:

0.10 m/s

Explanation:

The graph appears to be linear, so the velocity is constant and is represented by the slope of the graph. The slope can be calculating by taking any two points and inputting them into the equation: [tex]\frac{y_2-y_1}{x_2-x_1}[/tex] which is essentially rise/run. In this case the slope is really easy to calculate taking the two points of (0, 0) and (10, 1). In this case you can easily see the rise is 1 and the run is 10. So the slope is 1/10. So the average velocity of the object was 0.10 m/s or 1/10 m/s

The size of the disc will Increase

The hole will enlarge in proportion to the metal if the disc is homogeneous and isotropic (the same in all directions). This is evident because, since the hole's edge is constructed of metal, the thermal expansion equation dL=LdT holds true for all lengths related to the metal, including the circle of the hole. Additionally, if the diameter of the hole increases, so does its circumference.

The analysis becomes more challenging if your disc has distinct areas formed of various metal kinds or if the metal that makes up your disc has an anisotropic crystal structure, meaning that it expands by different amounts in different directions. But given the total change in size is still an expansion, I believe the hole would become bigger in all scenarios.

Hence ,The size of the disc will Increase

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Answer:

A

Explanation:

At point 'A' the ball is highest to the ground.As the formula of  gravitational potential energy is Eg=MGH, in which 'M' is mass,'H' is height and 'G' is the gravitational pull of earth

Answer:

Pressure is the force acting normally per unit area.

Force.

Area.

This also proved by formula:

P=F/A.

Also pressure due to liquid depends on density ,gravity and height

Answer:

The families are thought to form as a result of collisions between asteroids. In many or most cases the parent body was shattered, but there are also several families which resulted from a large cratering event which did not disrupt the parent body (e.g. the Vesta, Pallas, Hygiea, and Massalia families).

Answer:

The acceleration of the rifle equals the force that the bullet exerts on the rifle divided by the mass of the rifle. The two forces are equal, but since the mass of the rifle is much greater than the mass of the bullet, the acceleration of the rifle is much less than the bullet's acceleration.

The approximate magnitude of the force of air resistance is 882 N

The magnitude of the force of air resistance can be obtained as illustrated below:

F = mg

F = 90 × 9.8

F = 882 N

Thus, approximate magnitude of the force of air resistance is 882 N

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Answer:

1.44 m

Explanation:

Potential energy = mgh

  832                 = 59 * 9.81* h

h = 832/(59*9.81) = 1.44 m

The diver has a mass of 59 kg and a gravitational potential energy of 832 J standing on the diving board. 1.44 meters high, the diver is above the water's surface.

Utilizing mechanical energy conservation, we can estimate the diver's height above the water's surface. The diver has gravitational potential energy at the top of the diving board, which is transformed into kinetic energy when they jump and descend towards the ocean. Each and every ounce of potential energy is changed into kinetic energy at the water's surface.

Given:

Mass of the object (diver) = 59 kg

Acceleration due to gravity = 9.81 m/s²

The height can be computed as:

h = GPE / (m × g)

h = 832 J / (59 kg × 9.81 m/s²)

h = 1.44 meters

Hence, the diver has a mass of 59 kg and a gravitational potential energy of 832 J standing on the diving board. 1.44 meters high, the diver is above the water's surface.

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It means mass can be converted into energy.

I. E. In a nuclear fission, we start of with a greater mass of our rectant, which then decrease due to mass being converted into the (thermal) energy released, in our reaction. Later, being used to produce electricity, for example.

Hope this helps!

The height is 0.70 meters

The formula for gravitational potential energy is

= mgh

m= mass, g= acceleration due to gravity, h= height

54.9= 8 × 9.8 × h

54.9= 78.4h

h= 54.9/78.4

= 0.70 meters

Hence the height at which the bacpack was lifted is 0.70 meters


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Answer:

its 0.7m

Explanation:

Interference and diffraction are the phenomena that support only the wave theory of light. Options 2 and 3 are correct.

The result of two or more wave trains flowing in opposite directions on a crossing or coinciding pathways. This phenomenon is known as the interference of waves.

The phenomenon of interference occurs when two wave pulses are traveling along a string toward each other.

The light wave hypothesis states that light behaves like a wave. Since light is an electromagnetic wave, it may be transmitted without a physical medium.

Light has magnetic and electric fields, much like electromagnetic waves do.

Transverse waves, such as those seen in light waves, oscillate in the same direction as the wave's path. A wave of light may experience interference as well as diffraction as a result of these properties.

All of the remaining options are the light phenomenon.

Hence, options 2 and 3 are correct.

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Answer:

Since velocity is a vector quantity there is no net displacement and the average velocity is zero

(A) is correct

The acceleration of the steel crate, given the data from the question is 6.0 m/s²

Fₙ = Fᵣ - Fբ

Fₙ = 1869 - 480

Fₙ = 1389 N

Fₙ = ma

Divide both sides by m

a = Fₙ / m

a = 1389 / 230

a = 6.0 m/s²

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An effective display of trend and magnitude is achieved by using a combination of a C)heat map and sparklines.

While the standard chart is designed to expose as a great deal fact as possible and is set off from the float of text, sparklines are meant to be succinct, memorable, and located in which they are mentioned.

A heatmap (or warmness map) is a graphical illustration of facts wherein values are depicted through color. They are crucial in detecting what does or does not paintings on a website or product page.

A warmth map visualization is a mixture of nested, colored rectangles, each representing an attribute detail. Heat Maps are regularly used inside the monetary services industry to review the reputation of a portfolio.

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Answer:

The magnetic field through the coil must change.

Explanation:

Intensity of light emitting from the bulb is 3.5 watt/m².

To find the answer, we need to know about the intensity of the light.

Intensity of light= power/area

Thus, we can conclude that the intensity of light bulb at 1.51 m is 3.5 watt/m².

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A movement which keeps the distal end of the body segment fixed in one location describes what type of kinetic chain movement is known as a closed kinetic chain movement.

A closed kinetic chain movement is defined as that position where the most distal aspects of a particular extremity are fixed to the earth or another solid object.

In conclusion; a movement which keeps the distal end of the body segment fixed in one location describes what type of kinetic chain movement is known as a closed kinetic chain movement.

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-3.6× 10^5J is the Work done by friction force

Work done = force × distance

v^2 = u^ +2as

u= 22m/s

a =10m/s^2

When the car stops the final velocity (v) =0

0= 22^2 +2×10×s

s = -484/20

s =-24.2m

Work done = force × distance

Force = mass × acceleration

Work done = 1500×10× -24.2

= -3.6×10^5J

Hence the Work done is -3.6×10^5J

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Answer:

0.010 m

Explanation:

So the equation for a pendulum period is: [tex]y=2\pi\sqrt{\frac{L}{g}}[/tex] where L is the length of the pendulum. In this case I'll use the approximation of pi as 3.14, and g=9.8 m\s. So given that it oscillates once every 1.99 seconds. you have the equation:

[tex]1.99 s = 2(3.14)\sqrt{\frac{L}{9.8 m\backslash s^2}}\\[/tex]

Evaluate the multiplication in front

[tex]1.99 s = 6.28\sqrt{\frac{L}{9.8m\backslash s^2}[/tex]

Divide both sides by 6.28

[tex]0.317 s= \sqrt{\frac{L}{9.8 m\backslash s^2}}[/tex]

Square both sides

[tex]0.100 s^2= \frac{L}{9.8 m\backslash s^2}[/tex]

Multiply both sides by m/s^2  (the s^2 will cancel out)

[tex]0.984 m = L[/tex]

Now now let's find the length when it's two seconds

[tex]2.00 s = 6.28\sqrt{\frac{L}{9.8m\backslash s^2}}[/tex]

Divide both sides by 6.28

[tex]0.318 s = \sqrt{\frac{L}{9.8 m\backslash s^2}[/tex]

Square both sides

[tex]0.101 s^2 = \frac{L}{9.8 m\backslash s^2}[/tex]

Multiply both sides by 9.8 m/s^2 (s^2 will cancel out)

[tex]0.994 m = L[/tex]

So to find the difference you simply subtract

0.984 - 0.994 = 0.010 m

the answer should be 0.00988 m

The magnitude of the force exerted by the second wire is 16.5 N.

Apply cosine rule to determine the force on the second wire;

W² = F₁² + F₂² - 2F₁F₂ cos(θ)

where;

(4.3 x 9.8)² = 31²  +  F₂²  - 2(31) F₂(cos 122)

1775.78 = 961  +  F₂²  + 32.85F₂

814.78 = F₂²  + 32.85F₂

F₂²  + 32.85F₂ - 814.78 = 0

Solve the quadratic equation using formula method;

F₂ = 16.5 N

Thus, the magnitude of the force exerted by the second wire is 16.5 N.

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1. The part that shows the body is accelerating is the first 2 hours (ABE). The acceleration is 20 Km/h²

2. The part that shows the body is coming to rest the last 2 hours (CDF)

3. The distance travelled in the first 2 hours is 40 Km

Acceleration is defined as the rate of change of velocity which time. It is expressed as

a = (v – u) / t

Where

From the diagram (ABE), we can see that the body starts from rest and attain a final velocity (40 Km/h) within the first 2 hours. This clearly indicates that the body is accelerating.

The acceleration can be obtained as followed:

a = (v – u) / t

a = (40 – 0) / 2

a = 20 Km/h²

From the diagram (CDF), we can see that the object velocity changes from 40 to 0 within the last 2 hours. This clearly indicates that the object caming to rest.

v² = u² + 2as

v² = 2as

s = v² / 2a

s = 40² / (2 × 20)

s = 40 Km

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