we know that
If there is no correlation between x and y, that just means that there's no relationship, connection, or interdependence between the two variables
No correlation means that as the x-values increase, the y-values have no effect
the answer is the option A
Given m∥n, find the value of x
Answer:
x=55
Step-by-step explanation:
2x+6+x+9=180
3x=165
x=55
:]
6 to the negative 3rd power times 6 to the 2nd power times 6 to the 5th power times 6
The value of 6 to the negative 3rd power times 6 to the 2nd power times 6 to the 5th power times 6 is 6^5.
What is an exponent?The exponent is the number of times that a number is multiplied by itself. It should be noted that the power is an expression which shows the multiplication for the same number. For example, in 6⁴ , 4 is the exponent and 6⁴ is called 6 raise to the power of 4.
Based on the information given, the numbers will be expressed as:
6^-3 × 6^2 × 6^5 × 6
= 6^5
It's important to note that they've the same base. Therefore, the powers will be added thus:
= -3 + 2 + 5 + 1
= 5
This gives 6^5. This illustrates the concept of exponents.
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Lottery numbers in a particular state consist of 5 digits. Each lottery cube that is drawn/rolled has six sides, numbered 1-6. How many different lottery numbers are possible? O 720 lottery number O 7776 lottery numbers
As per the concept of probability, there are 7776 different lottery numbers are possible.
Probability:
Probability means the concept that is based on the possible chances of something to happen.
Given,
Lottery numbers in a particular state consist of 5 digits. Each lottery cube that is drawn/rolled has six sides, numbered 1-6.
Here we need to find how many different lottery numbers are possible.
Through the given question we know that,
The number of digits in a lottery ticket = 5
Side in cube = 6
So, in each time they will roll the dice 5 times to get one number.
So, the possible options of that event are,
For the first time we have 6 options
Second time we got 6 options
Third time also we got six option
Fourth time = 6 options
Fifth time = 6 options.
Therefore, it can be written as,
=> 6 x 6 x 6 x 6 x 6
=> 6⁵
=> 7776.
Therefore, there are 7776 different lottery numbers are possible.
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there are 13 porters carrying total weight of 195 kg on an expeditioin. extra porters joined the group so, they carry average weight of 13kg of baggage. find the number of portes added
Answer: 2 porters joined the group
Step-by-step explanation:
First, you are told that "13 porters are carrying a total weight of 195kg". You can use this information to create an equation to find the average weight carried by each porter.
[tex]\frac{195 kg}{13}=15kg[/tex]
^195kg (total weight) divided by 13 (the number of porters) is equal to 15kg (the average weight carried by each of the 13 porters).
You are then told that "extra porters join the group, so they carry an average weight of 13 kg of baggage". because some porters joined the group, you'll have to add p (p = number of porters) to the original equation and change the average weight from 15kg to 13kg.
[tex]\frac{195kg}{13 +p} = 13kg[/tex]
^195kg (total weight) divided by 13+p (total number of porters after some joined group) is equal to 13kg (new average weight)
You can then use your new equation to solve for "p" and find the number of porters added.
p = 2
Explain how you can use addition of groups to show that 4 x ( -3) = 12
The technique of repeated addition involves combining equal groups.
4 x ( -3) = 12.
Repeated addition is the combining of equal groupings. It offers a basis for comprehending multiplication. For instance, 3 x 5 can be expressed as 5 + 5 + 5 to represent 3 groups of 5 counters.
We have been given that
4 x ( -3) = 12
By using repeated addition for multiplication
Add 4 three times or add 3 for times ..
In question negative 3 is given so we add negative 4 , three times
(-4) + (-4) + (-4)
-12.
Or
Add negative 3 , four times
(-3) + (-3 )+ (-3) + (-3)
-12.
Hence, we solved given multiplication by the using repeated addition method.
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calcula la suma de los quince primeros multiplos de 9
Answer:
Step-by-step explanation:
9*(15/2)[2+14] = 9*15*16 = 2160.
4) Say there are 500,000 people in a county, of which approximately 300,000 are registered voters. According to the pir chart below, what is an estimate to the nearest person of how many people in the county are registered independents? (10 points) Approximately people in this county are registered independents. Registered County Voters Other 64 Independent 40% - Democrat u Republican independent Other
Since the chart has the name "Registered Country Voters", it only includes the registered voters, that is the approximately 300,000 people. Since 16% are independet, we can take 16% of 300,000 to get the registered independets. that is, multiply 0.16 (16%) by 300,000:
[tex]0.16\cdot300,000=48,000[/tex]So, the answer is 48,000.
Complete both transformations below.
Then enter the final coordinates of the figure.
A(-1,3)
B(2,1)
C(1-1)
1) <2,3>
2) Dilate K = 2
A" ([?], [])
B" ([][])
C" ([],[])
Enter
Answer:
A" (2, 12)
B" (8,8)
C" (6, 4)
Step-by-step explanation:
For each point P(x, y) of the image, the translations are as follows:
Translate P(x, y) by <2, 3> [tex]\longrightarrow[/tex] P'(x + 2, y + 3) [tex]\longrightarrow[/tex] P'(x', y')
Dilate P'(x', y') by 2 [tex]\longrightarrow[/tex] P'' (x'', y'') [tex]\longrightarrow[/tex] P(2x', 2y')
Point [tex]\longrightarrow[/tex] Translate <2, 3> [tex]\longrightarrow[/tex] Dilate by 2
A(-1, 3) [tex]\longrightarrow[/tex] A'(-1 +2, 3 + 3) => A'(1, 6) [tex]\longrightarrow[/tex] A''(2, 12)
B(2, 1) [tex]\longrightarrow[/tex] B'(2 + 2, 1 + 3) => B'(4, 4) [tex]\longrightarrow[/tex] B"(8, 8)
C(1, -1) [tex]\longrightarrow[/tex] C'(1 + 2, -1 + 3) => C'(3, 2) [tex]\longrightarrow[/tex] C"(6, 4)
Capital Gate Tower is
150 meters tall
(measured vertically
from the ground) and
makes a 72° angle
with the ground. If
you were to climb to
the top and then
accidently drop your
keys, how far from
the base of the tower
would they land?
Answer:
Step-by-step explanation:
[tex]\frac{150}{x} =tan72 \\x=150 cot~72=150 cot(90-18)=150 ~tan ~18 \approx 48.74 ~meteres[/tex]
Towson Corporation issued $150,000 of 7% ten year bonds at 103 on the semi-annual interest date. Towson uses the straight line method to amortize any bond premium or discount. What is the amount of bond amortization for each six month period? Answer in whole dollars (no cents).
The amount of bond amortization for each six month period is [tex]\$225[/tex].
In the given question,
Towson Corporation issued [tex]\$150,000[/tex] of [tex]7\%[/tex] ten year bonds at [tex]103[/tex] on the semi-annual interest date.
Towson uses the straight line method to amortize any bond premium or discount.
We have to find the amount of bond amortization for each six month period.
Cash issued [tex]=\$150,000[/tex]
Rate [tex]=7\%[/tex] ten year bond at [tex]103[/tex] n the semi-annual interest date.
So the cash proceed on issue of bond = Cash issued [tex]\times103[/tex] [tex]/100[/tex]
Cash proceed on issue of bond [tex]=\$150,000\times\frac{103}{100}[/tex]
Firstly simplifying ratio
After simplification of ratio
Cash proceed on issue of bond [tex]=\$150,000\times1.03[/tex]
Now simplifying after multiplication
Cash proceed on issue of bond [tex]=\$154,500[/tex]
Hence, the cash proceed on issue of bond is [tex]\$154,500[/tex].
Now we find the premium that issued in the bond.
Premium on issue of bond [tex]=\$154,500-\$150,000[/tex]
Simplifying
Premium on issue of bond [tex]=\$4,500[/tex]
Hence, the premium on issue of bond is [tex]\$4,500[/tex]
Now finding the amount of bond amortization for each six month period.
Bond Amortization = (Premium on issue of bond/10 years) * 1/2
Bond Amortization [tex]=(\frac{\$4500}{10})\times\frac{1}{2}[/tex]
Simplifying the ratio
Bond Amortization [tex]=\$450\times0.5[/tex]
Bond Amortization [tex]=\$225[/tex]
Hence, the amount of bond amortization for each six month period is [tex]\$225[/tex].
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1. In a factory, a machine takes 5 minutes to stitch a book. How many machines are needed to stitch
50 books in 10 minutes?
Answer: just multiply 5 by 2
Step-by-step explanation:
The table shows how much money Tearra has after buying some games and represents a linear function.
Number of games 0 1 2 3
Amount of money $106.50 $71 $35.50 $0
What is the yintercept of the function shown in the table, and what does it represent?
A. The y-intercept is (0,106,50). Tearra has $106.50 before buying any games.
B. The y-intercept is (0,106.50). Tearra spends $106.50 per game.
C. The y-intercept is (3,0), and the 3 represents the number of games Tearra buys.
D. The y intercept is (3,0), and the 3 represents the amount of money Tearra spends per game.
Answer:
C. The y-intercept is (0, 150). Diego has $150 before buying any
Step-by-step explanation:
Brainlylist?
Step-by-step explanation:
Answer: The answer would be A.
Step-by-step explanation:
1messageJosh wants to estimate the mean age in a population of trees. He'll sample n trees and build a 95% confidence interval for the mean age. He doesn't want the margin of error to exceed 3 years. Preliminary data suggests that the standard deviation for the ages of trees in this population is 16 years.Which of these is the smallest approximate sample size required to obtain the desired margin of error?11 trees110 trees144 trees43 trees87 trees
The formula for the margin of error is
[tex]\begin{gathered} \text{MOE}=SE\times critical\text{ value} \\ SE\Rightarrow\text{standard error} \end{gathered}[/tex]The critical value for 95% confidence interval is 1.96
The standard error is
[tex]\begin{gathered} SE=\frac{\sigma}{\sqrt[]{n}} \\ \sigma\Rightarrow standard\text{ deviation} \\ n\Rightarrow\text{sample size} \end{gathered}[/tex]To know which of the list of options will yield approximately the desired margin of error, we will have to calculate the margin of error with the following values
For 110 trees, n= 110, standard dev. =16
[tex]\begin{gathered} SE=\frac{16}{\sqrt[]{110}}=1.53 \\ \text{MOE}=1.53\times1.96=2.9988 \end{gathered}[/tex]For 144 trees, n=144, standard dev=16
[tex]\begin{gathered} SE=\frac{16}{\sqrt[]{144}}=\frac{16}{12}=1.33 \\ \text{MOE}=1.33\times1.96=2.61 \end{gathered}[/tex]For 43 trees, n=43 , standard dev.=16
[tex]\begin{gathered} SE=\frac{16}{\sqrt[]{43}}=2.44 \\ \text{MOE}=2.44\times1.96=4.782 \end{gathered}[/tex]For 87 trees, n= 87, standard dev=16
[tex]\begin{gathered} SE=\frac{16}{\sqrt[]{87}}=1.72 \\ \text{MOE}=1.72\times1.96=3.3712 \end{gathered}[/tex]Hence, from the above calculations, the most prefered is the sample size of 110 trees (because the margin of error of 2.9988 is approximately 3 )
Answer is 110 trees
Simplify the expression 5(-7 + 3k)
The given expression is,
[tex]5(-7+3k)[/tex]Opening the brackets and multiplying each term inside the bracket with 5, we get,
[tex]\begin{gathered} \lbrack5\times(-7)\rbrack+(5\times3k)=-35+15\text{ k} \\ 15k=35 \\ k=\frac{35}{15}=2.33 \end{gathered}[/tex]The simplified expression is 15k = 35 and the value of k is 2.33.
Tina couldn't wait to share the 36 cookies she made with her friends. If she shares with 8 friends, how many cookies (c) will each of them get?
Given:
Total number of cookies is, N = 36.
Number of friends is, n(f) = 8.
The objective is to find the number of cookies (c) will each of them get while sharing.
Consider the required number of cookies to each person as (c).
The value of c can be calculated as,
[tex]\begin{gathered} c=\frac{\text{Number of cookies (N)}}{Number\text{ of friends n(f)}} \\ =\frac{36}{8} \\ =4.5 \end{gathered}[/tex]Hence, each of them will get 4 and a half cookies.
How much interest is earned in an investment if $720 is deposited monthly at 7.8% compounded monthly if the term of the investment is 6 years?$__________Round to the nearest cent
Given:
The initial investment is, P = $720.
The rate of interest is, r = 7.8% = 0.078.
The number of years of investment is, t = 6 years.
Explanation:
The general formula to find the compound interest is,
[tex]A=P(1+\frac{r}{n})^{nt}[/tex]Here, n represents the number of times compounded in a year. It is given that the amount is compounded monthly, so the value of n = 12.
To find total amount after 6 years:
Now, substitute the given values in the general equation.
[tex]\begin{gathered} A=720(1+\frac{0.078}{12})^{12(6)} \\ =720(1+0.0065)^{72} \\ =1147.95 \end{gathered}[/tex]Thus, the total amount earned is $1147.95.
To fnd interest amount:
Now, the amount of interest can be calculated as,
[tex]\begin{gathered} I=A-P \\ =1147.95-720 \\ =427.95 \end{gathered}[/tex]Hence, the interest amount earned is $427.95 and the total amount earned is $1147.95.
can you help me find the answer to this question find the area of this figure round your answer to the nearest hundredth use 3.14 to approximate tt. a= ? ft 2
First, let's calculate the area of the triangle.
[tex]A=\frac{1}{2}b\cdot h[/tex][tex]A=\frac{1}{2}\cdot6\cdot8=\frac{48}{2}=24\text{ ft2}[/tex]Now let's calculate the area of the semicircle.
[tex]A=3.14\cdot\frac{r^2}{2}[/tex][tex]A=3.14\cdot\frac{4^2}{2}=25.12\text{ ft2}[/tex]The total area of the figure is:
24+25.12 ft2 = 49.12 ft2
One card is drawn from a standard deck of 52 playing cards. Find the probability of each of the following events:
1) Probability of drawing a spade is 14
2) Probability of drawing a seven is 1/13
3) Probability that a heart or spade is drawn = 1/2
4) Probability that blackjack is drawn = 1/26
Simply put, the probability is the likelihood that something will occur. When we don't know how an event will turn out, we can discuss the likelihood or likelihood of several outcomes. Statistics is the study of events that follow a probability distribution.
1) There are 13 spades in total.
hence, the likelihood of drawing a spade is 13/52, or 14.
2) The sum of the seven is four. (4 suits are in the room)
Probability = 4/52 = 1/13
(3) A heart or spade is drawn.
Total hearts and spades: 13 + 13 = 26
Probability = 26/52 = 1/2
4) A blackjack is drawn, with a total of two blackjacks.
Probability = 2/52 = 1/26.
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identify the mapping diagram that represents the relation and determine whether the relation is a function
F is the correct answer (option A) that is, the relation is like many to one. So, it is a function.
Given mapping diagram that represents the relation.
We have to determine whether the relation is a function.
(-8, -6), (-5, 2), (-8, 1), (7, 3)
Here,
Domain = (-8, -5, 7)
Range = (-6, 2, 1, 3)
A function is a relation where each input has only one output.
Here,
F. The relation is like many to one. So, it is a function.
G. The relation is many to one. So, it is a function.
H. The relation is one to many. It is not a function.
G. The relation is one to many. It is not a function.
So, F is the correct answer (option A) that is, the relation is like many to one. So, it is a function.
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Simplify the expression 7(6t+2)+3-5(t-1).
We are given the following expression:
[tex]7(6t+2)+3-5(t-1)[/tex]To simplify the expression, we will first use the distributive property on the parenthesis, like this:
[tex]7\times6t+7\times2+3-5\times t+5\times1[/tex]Solving the operations:
[tex]42t+14+3-5t+5[/tex]Now we add like terms:
[tex](42t-5t)+(14+3+5)[/tex]Solving the operations:
[tex]37t+22[/tex]This is the most simplified form of the equation
In triangle DEF, m∠D = (2x + 19)°, m∠E = (3x + 24)°, and m∠F = 87°. Determine the degree measure of the exterior angle to ∠D.
54°
39°
141°
126°
The value of x is equal to 10 and the exterior angle to angle d is equal to 141 degrees.
Exterior AnglesTo solve this problem, we have to recall that the sum of angles in a triangle is equal to 180 degrees.
Applying that formula here;
[tex]m < d + m < e + m < f = 180^0\\(2x + 19) + (3x + 24) + 87 = 180\\x = 10[/tex]
But the exterior angle to angle D can be found assuming the angle lies on a straight line, then the sum of angle D and it's exterior angle would be equal to 180 degrees.
Let y = exterior angle
[tex]m < d + y = 180\\2x + 19 + y = 180\\x = 10\\2(10) + 19 + y = 180\\20 + 19 + y = 180\\39 + y = 180\\y = 141^0[/tex]
The value of the exterior angle to d is equal to 141 degrees.
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Answer: its C
Step-by-step explanation: i got it right
Mrs. Jenkins is catering a school dance and wants to know how manystudents prefer tacos and how many prefer hot wings.296 students preferred tacos63% of students preferred hot wings.How many students in total were attending the dance?
Let x represent the total number of students that attended the dance. This means that
number of students that prefer tacos + number of students that prefer hot wings = x
Percentage is expressed in terms of 100. If 63% of the students preferred hot wings, then the number of students that preferred hotwings is
63/100 * x = 0.63x
If 296 students preferred tacos, it means that
293 + 0.63x = x
x - 0.63x = 296
0.37x = 296
x = 296/0.37
x = 800
Thus, a total of 800 students attended the dance
I need help with this question but no one is helping me! Can someone please help me.
Carry your intermediate competations at least four decimal places were on your answer to 2 decimal places
Given that Z follows the standard normal distribution, and that the left-tailed probability for a z-score c is:
[tex]P(Z\leqslant c)=0.8531[/tex]Then, we can see that the value of c, round to two decimal places, is:
[tex]c=1.05[/tex]Which analytical model best represents the data in the table below?
When x = 0, y = 2, then the constant term of the polynomial must be 2. This discards the last 2 options.
When x = 1, y = 11. Substituting x = 1 into the first two options, we get:
[tex]\begin{gathered} y=9\cdot1^2+2=9+2=11 \\ y=9\cdot1^2+11\cdot1+2=9+11+2=22 \end{gathered}[/tex]Then, y = 9x² + 2 is correct.
please help me with this calculate the volume of the cone and round it to the nearest hundredth
ANSWER:
The volumen of the cone is 667.07 cubic meters
The volume has the following formula
[tex]V=\frac{1}{3}\pi\cdot r^2\cdot h[/tex]replacing:
[tex]\begin{gathered} V=\frac{1}{3}\cdot3.1416\cdot7^2\cdot13 \\ V=667.07 \end{gathered}[/tex]Answer the question right and i will give u brainiest
Answer:
21 is -2 away, 22 is- 1 away 28 is 5 away, and 29 is 6 away
Step-by-step explanation:
Answer:
-2
-2
-2
-1
-1
-1
-1
-1
5
6
Help?
(ii) Not sure what scale factor is
(ii) And I’ve never learnt this
This video from khan academy should clear up your confusion on scale factors.
https://www.khanacademy.org/math/7th-engage-ny/engage-7th-module-1/7th-module-1-topic-d/v/identifying-scale-factors
Solve for x usingcross multiplication.3x + 6 = 4x - 364=35x = [?]Enter
Solving for x,
[tex]\begin{gathered} \frac{3x+6}{4}=\frac{4x-3}{5} \\ \\ \rightarrow5(3x+6)=4(4x-3) \\ \rightarrow15x+30=16x-12 \\ \rightarrow30+12=16x-15x \\ \rightarrow42=x \\ \\ \Rightarrow x=42 \end{gathered}[/tex]Two fields of equal soil types and slope both had corn planted last year. It was the first year that the newly installed center pivot irrigation systems were used - one system per field. However, these systems were made by two different manufacturers.
Suspecting that one of the systems in particular is oversupplying water to the corn, the farmer set up sensors on the edge of the field adjacent to a drainage ditch to measure the total runoff in the two fields. The data from these two sensors is displayed below:
Water runoff (gallons)
Irrigation System #1
11.4 12.4 12.1 11.8 11.8 11.7 12.3 12.0 11.8
Irrigation System #2
13.0 12.4 12.4 12.1 12.3 12.1 12.5 12.0 12.1
The question of interest is whether these two systems produce significantly different runoff. Find the value of the test statistic for the this test (hint: this is a kind of t-test - read the problem carefully to infer exactly which kind).
More surprising was a recent report of severe erosion brought on by rain in a well-kept, drip-irrigated subtropical fruit orchard in Limpopo
It is widely known and has been extensively researched for many years how soil erosion occurs in rangelands and locations where crops are watered by rain. However, it appears that knowledge of and research on the severe soil erosion that occurs in irrigated regions is lacking. When center pivot irrigation was used on highly crusting, extremely unstable soils, such as those from the Eastern Cape and the Lowveld of Mpumalanga, major gully (donga) erosion ensued, according to information the author has previously and more recently received. After the irrigation was put in place, they grew quite fast. More surprising was a recent report of severe erosion brought on by rain in a well-kept, drip-irrigated subtropical fruit orchard in Limpopo.
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