NEED THIS ASAP!!!! it for math

[tex]\frac{2}{243} (82^\frac{3}{2} -1)[/tex] is the required length of the curve y = 4 + 6[tex]x^\frac{3}{2}[/tex]

Given equation of curve:

y = 4 + 6[tex]x^\frac{3}{2}[/tex]

length of the curve is given by L= [tex]\int\limits^a_b {\sqrt{1+(y^')^2} } \, dx[/tex]

where [tex]y^'[/tex] is derivative of y with respect to x

so [tex]y^'[/tex] = 6*(3/2) * [tex]\sqrt{x}[/tex]

=> 9 [tex]\sqrt{x}[/tex]

given a=1 and b=0

so L= [tex]\int\limits^1_0 {\sqrt{1+(9\sqrt{x})^2 } } \, dx[/tex]

L=  [tex]\int\limits^1_0 {\sqrt{1+81x } } \, dx[/tex]

let 1+81x be t

81dx = dt

as the value of x changes after the substitution of the value.

so now the L changes as:

L= 1/81 [tex]\int\limits{\sqrt{t } } \, dt[/tex]

L=1/81* [tex]\left \{ {{t=82} \atop {t=1}} \right.[/tex]  [tex]\frac{t^\frac{3}{2} }{\frac{3}{2} }[/tex]

the min value of t=1 and max value of t=82

L=[tex]\frac{2}{243} (82^\frac{3}{2} -1)[/tex]

so the exact length of the curve is given by L=[tex]\frac{2}{243} (82^\frac{3}{2} -1)[/tex]

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The total annual salary with a festive bonus is Rs (12r+2000)

In maths, multiply means the repeated addition of groups of equal sizes.

Given that, there is an annual salary at r rupees per month along with a Christmas bonus of, Rs 2000.

Here, a person is getting monthly salary  = Rs r

Therefore, his annual salary = Rs r × 12

= Rs 12r

He is also getting a bonus for Christmas = Rs 2000

So, in total, he will get =  Rs (12r+2000)

Hence, The total annual salary with a festive bonus is Rs (12r+2000)

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The solution of the equation for values of a is 1/(x - 1)

From the question, we have the following parameters that can be used in our computation:

a^2x - a = ax

Rewrite properly as

a²x - a = ax

Divide through by a

So, we have

ax - 1 = x

Collect the like terms

ax - x = 1

Factor out x

This gives

a(x - 1) = 1

Divide both sides by x - 1

a = 1/(x - 1)

Hence, the solution is 1/(x - 1)

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The variable that researchers are trying to explain or predict is called the response variable. It is also sometimes called the dependent variable because it depends on another variable.

Variables used to explain or predict a response variable are called explanatory variables.

The students want to predict age using their height, so the explanatory variable is height and the response variable is age.

The values ​​of an ordinal variable have a meaningful order. For example, an education level (with possible values ​​of high school, bachelor's degree, and graduate degree) can be an ordinal variable.

"Hand" belongs to "Clock". "Experience" also belongs to "Year". So if he has 10 years of experience in the industry, no apostrophes are needed. An apostrophe is required if you have more than 10 years of experience.

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Using percentages we know that the total price of the book that Tommy will pay is $131.04.

What is the percentage?

In mathematics, a percentage is a number or ratio that is expressed as a fraction of 100.

Although "pct," "pct," and occasionally "pc" are also used as abbreviations, the percent symbol "%" is most usually used to denote it.

A% is a number that has neither dimensions nor a defined unit of measurement.

For instance, if you properly answered 75 out of 100 questions on a test, you would have received a 75% grade (75/100).

So, we know that the price of the book is 180.

Sales tax is 4%. So, the total price:

180/100 * 4 = 7.2$ ⇒ $187.2

Now, there is a 30% discount:

187.2/100 * 30 = $56.16

⇒ 187.2 - 56.16 = $131.04

Therefore, using percentages we know that the total price of the book that Tommy will pay is $131.04.

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Answer: (x- 1/4)^2=9/16

Step-by-step explanation:

x^2 -1/2x =8/16

(x^2-1/2x +1/16)^2= 8/16+1/16)

(x- 1/4)^2=9/16

Answer:

The price per cup would be 0.41 cents.

Step-by step explaination:

Answer:

$0.41

Step-by-step explanation:

To find the price per cup of milk, we first need to know how many cups are in a 3-quart carton.

1 quart is equivalent to 4 cups, so a 3-quart carton contains:

[tex]\sf 3\;quarts=3 \times 4 \;cups= 12\;cups[/tex]

Now, we can calculate the price per cup by dividing the total price by the number of cups:

[tex]\begin{aligned}\textsf{Price per cup} &= \dfrac{\textsf{Total price}}{\textsf{Number of cups}} \\\\&=\sf \dfrac{\$4.92}{12}\\\\&=\sf \$0.41\end{aligned}[/tex]

Therefore, the price per cup of milk is $0.41.

The value of α + β  is 4. Then the value of the expression 2⁻¹ x (α + β)² will be 8.

Let the equation be ax² + bx + c = 0 and the roots are α and β.

Then the sum of the roots will be

α + β = - b / a

And the product of the roots will be

α · β = c / a

The quadratic equation is given below.

x² - 4x + 1 = 0

The sum of the roots of the equation is given as,

α + β = - (-4) / 1

α + β = 4

Then the value of the expression will be given as,

⇒ 2⁻¹ x (α + β)²

⇒ 2⁻¹ x (4)²

⇒ 16 / 2

⇒ 8

The value of the expression 2⁻¹ x (α + β)² will be 8.

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Answer:

-3

Step-by-step explanation:

x² + x = 3

3 - 6 = -3

To calculate Keith's equivalent rate with simple compounding, we need to use the following formula:

r = (e^(i/n) - 1) * n

where r is the equivalent rate with simple compounding, i is the interest rate with continuous compounding, and n is the number of compounding periods per year.

In this case, we are given that i = 8.27% and we can assume that the number of compounding periods per year is 12, since many loans are compounded monthly. Plugging these values into the formula, we get:

r = (e^(0.0827/12) - 1) * 12

= (1.0082 - 1) * 12

= 0.0082 * 12

= 0.0984 or 9.84%

Therefore, Keith's equivalent rate with simple compounding is [B] 0.0998 or 9.98%.

Answer:

120°

Step-by-step explanation:

125° + ( y + 5 )° + y = 360°

or, 125° + y + 5° + y = 360°

or, 2y + 130° = 360°

or, 2y = 360° - 130°

or, 2y = 230

or, y = 230/ 2

. y = 115°

. .

. ( y + 5 )°

. . ( 115 + 5 )°

.

. . 120°

Option are wrong.

Answer:

77 melons

Step-by-step explanation:

[tex]11x \times x = 539 \\ 11 {x}^{2} = 539 \\ \frac{11x}{11} = \frac{539}{49} \\ {x}^{2} = 49 \\ \sqrt{ {x}^{2} } = \sqrt{49} \\ x = 7[/tex]

The oranges are 7

And the melons are 11 times the number of the oranges hence

11 x 7= 77

Answer:

There are 77 melons

Step-by-step explanation:

See picture below :)

The correct option c. 20 cm, is the length of each sides of the regular pentagon.

A quadrilateral with five equal sides is known as a regular Pentagon.

Regular pentagon perimeter equals 5*side

Since we already know that a normal pentagon's perimeter is 100 cm.

Hence, 100 = 5*side

Side = 20 cm

Each side is 20 cm long.

As a result, the side of a regular pentagon is 20 cm long.

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y = e is the equation of the tangent line to the given curve at the specified point , y = [tex]e^{x}[/tex] / x , (1, e)

Through the coordinate geometry formal of point-slope form, the equation of tangent and normal can be calculated.

The tangent has the equation (y - y1) = m(x - x1), and a normal travelling through this point and perpendicular to the tangent has the equation (y - y1) = -1/m (x - x1).

thus , y' =  [tex]\frac{e^{x}-xe^{x} }{x^{2} }[/tex]

y'(1) = 0 = m

Our slope is indicated by the horizontal line.

y−[tex]y_{1}[/tex]=m(x−[tex]x_{1}[/tex])

Our line will simply be our y-coordinate because our slope(m) is 0:

e

Therefore:

The tangent line's equation is y=e.

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Answer:

Step-by-step explanation:

∠1≅∠2 if RECT is the rectangle and M is the midpoint of EC.

A triangle is a three-sided polygon that consists of three edges and three vertices.

RECT is the rectangle and M is the midpoint of EC.

we need to prove angle one is congruent to angle two.

By given,RECT is the rectangle and M is the midpoint of EC.

∠E≅∠C

In the rectangle all the angles are 90 degrees.

∠EM≅∠MC.

As M is midpoint, it has equidistant from E and C.

ER≅CT both sides are congruent.

ΔERM≅ΔCTM both are similar triangles.

RM≅TM both sides are congruent.

∠1≅∠2 by SAS postulate.

Hence, RECT is the rectangle and M is the midpoint of EC then ∠1≅∠2

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Answer:

x = 3

Step-by-step explanation:

x + 6 = 9

Subtract 6 from both sides :

x = 9 - 6

x = 3

Hope this helped and have a good day

Answer:

x = 3

Step-by-step explanation:

x + 6 = 9  Subtract  from both sides of the equation

x + 6 - 6 += 9 - 6

x = 3

Check:

x + 6 = 9

3 + 6 = 9

9 = 9 Checks

The choice that provides the best example of alliteration for the given sentence is tested terrifically on teaching. (Option C)

Alliteration is a literary device in which there is a noticeable repetition of initial consonant sounds in consecutive or nearby words in a phrase. It refers to the occurrence of the same sound or letter at the beginning of adjacent or closely connected words. Alliteration is created by repeated sound at the start of the words and not the repeated letter. For example, the phrase “kids’ coats” is alliterative, and the phrase “phony people” is not alliterative. In the given sentence, author can create alliteration by using tested terrifically in place was absolutely aced.

Note: The question is incomplete. The complete question probably is: In the sentence, the author wants to use alliteration. Which choice provides the best example of this? Ted absolutely aced his teaching exam. A) NO CHANGE B) was astounded at how well he did on C) tested terrifically on teaching.

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The exact length of the curve is [tex]& \mathbf{L}=\mathbf{e}^5+\mathbf{4}[/tex].

Let the given equation is [tex]x=e^t-t, y=4 e^{\frac{t}{2}}, 0 \leq t \leq 5[/tex].

Length of Parametric Curve: A parametric curve is a function expressed in components form, such that x=f(t),y=g(t). The length of a parametric curve on the interval a ≤ t ≤ b is given by the definite integral [tex]$L=\int_a^b \sqrt{\left(\frac{d x}{d t}\right)^2+\left(\frac{d y}{d t}\right)^2} d t$[/tex]

Let’s begin by getting the first derivative of the components of the function with respect to the variable t.

[tex]$$\begin{aligned}x & =e^t-t, y=4 e^{\frac{t}{2}} \\\frac{d x}{d t} & =\frac{d}{d t}\left(e^t-t\right)=\frac{d}{d t}\left(e^t\right)-\frac{d}{d t}(t)=e^t-1 \\\frac{d y}{d t} & =\frac{d}{d t}\left(4 e^{\frac{t}{2}}\right)=\left(4 e^{\frac{t}{2}}\right) \frac{d}{d t}\left(\frac{t}{2}\right)=\left(4 e^{\frac{t}{2}}\right)\left(\frac{1}{2}\right)=2 e^{\frac{t}{2}}\end{aligned}$$[/tex]

Substitute the derivatives into the following definite integral which computes the length of the parametric curve on the interval [a,b]=[0,5].

[tex]$$\begin{aligned}L & =\int_a^b \sqrt{\left(\frac{d x}{d t}\right)^2+\left(\frac{d y}{d t}\right)^2} d t \\& =\int_0^5 \sqrt{\left(e^t-1\right)^2+\left(2 e^{\frac{t}{2}}\right)^2} d t \\& =\int_0^5 \sqrt{\left(e^{2 t}-2 e^t+1\right)+\left(4 e^t\right)} d t \\& =\int_0^5 \sqrt{\left(e^{2 t}+2 e^t+1\right)} d t \\& =\int_0^5 \sqrt{\left(e^t+1\right)^2} d t \\& =\int_0^5\left(e^t+1\right) d t\end{aligned}$$[/tex]

We need to find the value of the definite integral to get the exact length of the curve.

Take out the limits of integration and evaluate the resulting indefinite integral to solve.

[tex]$$\begin{aligned}L & =\left.\left[\int\left(e^t+1\right) d t\right]\right|_0 ^5 \\& =\left.\left[\int e^t d t+\int 1 d t\right]\right|_0 ^5 \\& =\left.\left[e^t+t\right]\right|_0 ^5\end{aligned}$$[/tex]

Evaluate the solution at the limits of integration to get the length.

[tex]$$\begin{aligned}& L=\left[e^{(5)}+(5)\right]-\left[e^{(0)}+(0)\right] \\& L=\left(e^5+5\right)-\left(e^0+0\right) \\& L=e^5+5-(1+0) \\& L=e^5+5-1 \\& \mathbf{L}=\mathbf{e}^5+\mathbf{4}\end{aligned}$$[/tex]

Therefore, the exact length of the curve is [tex]& \mathbf{L}=\mathbf{e}^5+\mathbf{4}[/tex].

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The difference between  51th term of a and 51th term of b is 1000.

nth term of an arithmetic series is given by [tex]a_n = a_0 +( n-1)* d[/tex]

where [tex]a_0[/tex] is first term of arithmetic series , [tex]a_n[/tex] is nth term of the series and d is the common difference

given [tex]a_0 = b_0 = 30[/tex]

and given that both series have common difference have absolute value of 10.

common difference of series a is 10 as this series is increasing

similary common difference of series b is -10 as it is decreasing

putting the values in the above equation we get:

[tex]a_5_1[/tex]  = [tex]a_0[/tex] +(n-1)*d

=> 30 + (51-1)*10

=> 30 + 500

so [tex]a_5_1[/tex] = 530

[tex]b_5_1[/tex]  = [tex]b_0[/tex] +(n-1)*d

=> 30 + (51-1)*-10

=> 30 -500

so [tex]b_5_1[/tex] = -470

so we have to find value of [tex]a_5_1 - b_5_1[/tex] which is 530 - (-470) =530 +470 =1000

so the differnce of 51th term of a and b is 1000

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Answer:

2 apples = 0.24 kg

12 apples = 1.44 kg

Step-by-step explanation:

Find the weight of one apple.

If 5 apples weigh 0.60 kg, then 1 apple weighs:

[tex]\implies \sf 1\;apple=\dfrac{0.60}{5}=0.12\; kg[/tex]

Therefore:

The function f(x,y) is at origin [tex]\left|\frac{\sin x y}{x y}-1\right| < \varepsilon[/tex].

We can treat this function as h=xy and then it will looks like sin h/h because if we choose any path passing through original it will always continuous so above f(x,y) is continuous

[tex]$$f(x, y)= \begin{cases}\frac{\sin x y}{x y,} & \text { if } x y \neq 0 \\ 1, & \text { if } x y=0\end{cases}$$[/tex]

Choose y=mx path y→0, x→0

[tex]$$\begin{aligned}\lim _{\substack{x \rightarrow 0 \\y=\infty}} f(x, x) & =\lim _{x \rightarrow 0} \frac{\sin m x^2}{m x^2} \\& =\lim _{x \rightarrow 0} \frac{\cos m x^2 \cdot 2 m x}{2 m x}=1\end{aligned}$$[/tex]

Now consider,

[tex]$|f(n, y)-L 1=| \frac{\sin x-1}{n y}-1 \mid < \varepsilon$[/tex]

[tex]$$$\forall \varepsilon > 0$, and $|n| < \delta,|y| < d$$$=\left|\frac{\sin x y}{x y}-1\right| < \varepsilon$$[/tex]

Hence f(x,y) is continues at origin.

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Discuss the continuity of the function:

[tex]$$f(x, y)= \begin{cases}\frac{\sin x y}{x y,} & \text { if } x y \neq 0 \\ 1, & \text { if } x y=0\end{cases}$$[/tex]

Answer:

Step-by-step explanation

The tens digit of a certain two-digit number is 1/3 of the units digit. When the digits are reversed, the new number exceeds twice the original number by 2 more than the sum of the digits. Find the original number.

An arithmetic sequence is a sequence of numbers in which each term after the first is obtained by adding a fixed number, called the common difference, to the previous term. For example, the sequence 1, 2, 3, 4, … is an arithmetic sequence because each term is obtained by adding 1 to the previous term, which is the common difference.

Out of the four given options, only the sequence 1/2, 1/4, 1/6, 1/8, … is an arithmetic sequence. The common difference of this sequence is 1/4-1/2 = -1/4, so each term is obtained by subtracting 1/4 from the previous term. The other three sequences, 3, 5, 7, 9, 11, …, 2, 6, 18, 54, …, and 64, 32, 16, 8, … are not arithmetic sequences because the difference between each consecutive pair of terms is not constant. Therefore, the correct answer is a.

Step-by-step explanation:

To prove that AC = BD, we can use the symmetric property. The symmetric property states that if two quantities are equal, then their opposites are also equal.

In this case, we are given that AB = CD. Since AB and CD are opposite quantities (they are the lengths of the diagonals of a rectangle), we can use the symmetric property to conclude that AC = BD.

Therefore, the reason that can be used to justify statement 4 in the proof is the symmetric property.

Answer:

Step-by-step explanation:

Answer:

We get the approximate value of [n] as 5.

What is logarithm? What is a mathematical equation and expression?

A quantity representing the power to which a fixed number (the base) must be raised to produce a given number. We can write -

$$$\log_{b}({b^x})=x$$

A mathematical expression is made up of terms (constants and variables) separated by mathematical operators. A mathematical equation is used to equate two expressions.

A mathematical equation is used to equate two expressions. Equation modelling is the process of writing a mathematical verbal expression in the form of a mathematical expression for correct analysis, observations and results of the given problem.

We have 31,100 is rounded to the nearest power of 10 and [N] represents a power of 10.

We can write -

We can write -10ⁿ = 31100

We can write -10ⁿ = 3110010ⁿ = 311 x 10²

We can write -10ⁿ = 3110010ⁿ = 311 x 10²10ⁿ ⁻ ² = 311

We can write -10ⁿ = 3110010ⁿ = 311 x 10²10ⁿ ⁻ ² = 311log(10ⁿ ⁻ ²) = log(311)

We can write -10ⁿ = 3110010ⁿ = 311 x 10²10ⁿ ⁻ ² = 311log(10ⁿ ⁻ ²) = log(311)(n - 2) log 10 = log (311)

We can write -10ⁿ = 3110010ⁿ = 311 x 10²10ⁿ ⁻ ² = 311log(10ⁿ ⁻ ²) = log(311)(n - 2) log 10 = log (311)n - 2 = log(311)/log(10)

We can write -10ⁿ = 3110010ⁿ = 311 x 10²10ⁿ ⁻ ² = 311log(10ⁿ ⁻ ²) = log(311)(n - 2) log 10 = log (311)n - 2 = log(311)/log(10)n - 2 = 2.5

We can write -10ⁿ = 3110010ⁿ = 311 x 10²10ⁿ ⁻ ² = 311log(10ⁿ ⁻ ²) = log(311)(n - 2) log 10 = log (311)n - 2 = log(311)/log(10)n - 2 = 2.5n = 4.5

We can write -10ⁿ = 3110010ⁿ = 311 x 10²10ⁿ ⁻ ² = 311log(10ⁿ ⁻ ²) = log(311)(n - 2) log 10 = log (311)n - 2 = log(311)/log(10)n - 2 = 2.5n = 4.5n = 5 (approx.)

We can write -10ⁿ = 3110010ⁿ = 311 x 10²10ⁿ ⁻ ² = 311log(10ⁿ ⁻ ²) = log(311)(n - 2) log 10 = log (311)n - 2 = log(311)/log(10)n - 2 = 2.5n = 4.5n = 5 (approx.)Therefore, we get the approximate value of [n] as 5.

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The area of the region bounded by the given curves is 0.7123 square units

In this question we have been given two curves y = sin^2(x), y = sin^3(x), 0 ≤ x ≤ π

We need to find the area of the region bounded by the given curves.

We know that the formula for the area between two curves f and g :

A = |∫_[a to b] [f(x) - g(x)] dx|

here, a = 0, b = π, f(x) = sin^2(x) and g(x) = sin^3(x)

So, A = |∫_[0 to π] [sin^2(x) - sin^3(x)] dx|

A = |∫_[0 to π] sin^2(x) dx - ∫_[0 to π] sin^3(x) dx|

consider ∫_[0 to π] sin^2(x) dx

= ∫_[0 to π] (1 - cos(2x) / 2) dx

= π/2

Now consider ∫_[0 to π] sin^3(x) dx

= ∫_[0 to π] (1 - cos^2(x)) sin(x)  dx

= 4/3

So A = |π/2 - 4/3|

        = 3π - 8/2

        = 0.7123

Therefore, the required area: 0.7123 square units

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