Answer:
2605 N
Explanation:
[tex]F_{Earth} = m g_{earth}[/tex]
[tex]F_{Jupiter} = mg_{jupiter}[/tex]
[tex]F_{Earth} = 982 N[/tex]
[tex]982 N = m (9.8 m/s^2)\\[/tex]
[tex]m = 982 N[/tex] ÷ [tex]9.8 m/s^2[/tex]
[tex]m = \frac{4910}{49}[/tex] kg
[tex]F_{Jupiter} = \frac{4910}{49} * 26 m/s^2[/tex]
[tex]F_{Jupiter} = 2605.30...[/tex] ≈ 2605 N
n 1986, a nuclear power accident in chernobyl, ukraine led to high radiation levels for kilometers surrounding the plant. the high levels of radiation caused elevated mutation rates in the surviving organisms, and evolutionary biologists have been studying vole populations in the chernobyl area ever since. based on your understanding of evolutionary mechanisms, which of the following most likely occurred in the vole populations following the accident?
Based on my understanding of evolutionary mechanisms, Mutation led to increased genetic variation in 1986, nuclear power accident Chernobyl, Ukraine.
Mutations:
Mutations, or changes in the nucleotide sequence, can be caused by transposition, covalent changes in structure brought on by reactions with environmental chemicals or physical agents, or errors during DNA replication. Cells are where the majority of sequence changes are corrected.
Without these mutations, populations of species would not change in a way that would allow them to adapt to environmental changes. A mutation is an abrupt change to DNA. Radiation or any type of mutagen can cause mutations. Mutations were brought about by the radiation in this catastrophe. As a result, the organism will vary.
Genetic Variation:
The variety in DNA sequence seen in each of our genomes is referred to as genetic variation. We are all different from one another in terms of our hair color, complexion tone, and even the form of our features due to genetic variance.
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consider an earthquake to be a three-dimensional wave traveling through the earth's crust. the intensity of the earthquake passing through the earth is measured to be 11000 j/(m2*sec) at a distance 35 km from the source. the earthquake lasts for 14 seconds. ef picup part description answer save status a. determine the intensity at 1.3 km from the source. (include units with answer) format check click here to check your answer 6.25 pts.75% 2% try penalty 1 hint available
The Energy that can be captured is 8.267*10^7 KwH, Energy produced by earth quake in 11 seconds is 1.86*10^15 J.
What is intensity?
Intensity is the amount of energy a wave carries over a surface of a particular area in a unit of time, and it is the same as the energy density times the wave speed. The most popular unit of measurement is watts per square meter. The strength and size of a wave affect its frequency.
What is earth quake ?
An earthquake is the abrupt release of energy from the earth's crust that causes the earth's surface to shake. Seismic waves, also called S waves, are consequently produced.
I = 11000 J/(m^2 s)
r = 35 km
t = 11 s
a) from the given data
Energy produced by earth quake in 11 seconds
E = I*A*time
= I*4*pi*r^2*t
= 11000*4*pi*(35*10^3)^2*11
= 1.86*10^15 J
using,
log(E) = 4.8 + 1.5*M
log(1.86*10^15) = 4.8 + 1.5*M
==> M = 6.98
b) Energy that can be captured, E_captured = 16% of E
= 0.16*1.86*10^15
= 2.976*10^14
= 2.976*10^14/(3.6*10^6) KwH
= 8.267*10^7 KwH
the number of houses the earthquake could power for a year, N = E/10000
= 8.267*10^7/10000
= 8267
Therefore, Energy that can be captured is 8.267*10^7 KwH, Energy produced by earth quake in 11 seconds is 1.86*10^15 J.
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the colors in a rainbow are caused by the colors in a rainbow are caused by different amounts of absorption for light of different colors by the water in the raindrops. the interaction of the light reflected from different raindrops. the downward motion of the raindrops. different amounts of refraction for light of different colors by the water in the raindrops.
Varying degrees of refraction for various colours of light by the water in raindrops.
What is absorption ?
A chemical or physical phenomena known as absorption occurs when molecules, atoms, and ions from the substance being absorbed move into the bulk phase (gas, liquid, or solid) of the medium in which they are being absorbed.
What is reflected ?
When a wave encounters a barrier between two media, it will abruptly change direction and reflect. The approaching wave disturbance, at least in part, stays in the same medium.
Different amounts of refraction for light of different colors by the water in the raindrops. because, the amount of light will under go refraction, internal reflection and dispersion.
Therefore, option (d) is correct.
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A 150-kg electromagnet is at rest and is holding 100 kg of scrap steel when the current is turned off dropping the steel. - 2- Knowing that the cable and the supporting crane have a total stiffness equivalent to a spring of constant k 60 kN/m and a damper c = 300 Ns/m, determine (a) the frequency of oscillation (b) the maximum upward displacement І В
The frequency of the oscillation is determined to be 0.123 Hz.
The number of waves passing through a fixed point in unit time is said to be frequency.
Given that, Mass of the scrap steel = 100 kg
Spring constant k = 60 kN/m
The formula for time period is as follows,
T = 2π √(m/k)
And the relation between time period and frequency is, T = 1/f
f = 1 / [2π √(m/k)] = 1/ [ 2π √(100/60) = 1/ [ 2π * 1.29] = 1/8.105 = 0.123 Hz
Thus, the frequency of oscillation is 0.123 Hz.
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construction worker Bob IS standing at the top of a slanted rooftop when he accidentally drops & orange from his lunch bag; The orange rolls down the rool, which i> angled at 0 28,58 relative t0 Ihe harizontal as shown the figure below The bottom edge of the roofus meters above Ihe ground. Ihe orarge leaves the right edge ol Ihe rooftop with velocity 0l Ti 4.471,how fal, Arto the right of the roof edge does his 8 meter tall fellow consiruction warker Werdy have sland on the ground 50 that the orange just barely passes over her head? [Figure not diawn t0 scalel Imapa *x4: ALhae
Wendy must stand 1.19m to the left of the edge of the roof so that the orange just barely passes over her head.
Bob's orange will travel down the slanted roof with a velocity of 4.47 m/s, and it will hit the ground 3.0 m below the edge of the roof. The height of the orange above the ground at the edge of the roof is 1.8 m, and the angle of the roof is 28.5° relative to the horizontal.
To calculate the distance Ar that Wendy has to stand from the edge of the roof, we must first calculate the time it takes for the orange to reach the ground. Using the equation for the vertical displacement of an object with an initial velocity, we can solve for the time, t:
d = v*t - (1/2)*g*t^2
0 = 4.47*t - (1/2)*9.8*t^2
t = 0.938s
Next, we must calculate the horizontal displacement of the orange from the time, t. Using the equation for the horizontal displacement of an object with an initial velocity and a constant acceleration we can solve for the displacement:
x = v*t + (1/2)*a*t^2
x = 4.47*0.938 + (1/2)*0*0.938^2
x = 4.19m
To calculate the distance Ar that Wendy must stand from the edge of the roof, we must subtract the horizontal displacement of the orange from the height of the edge of the roof:
Ar = 3.0 - 4.19
Ar = -1.19m
Therefore, Wendy must stand 1.19m to the left of the edge of the roof so that the orange just barely passes over her head.
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Which of these is NOT a vector quantity?
O rotational kinetic energy
tO ranslational momentum
O velocity
O angular momentum
O acceleration
Answer: Rotational kinetic energy is not a vector quantity
Explanation:
Vector A volume that requires both magnitude and direction to be fully defined is called a vector.
Kinetic Energy It's defined as the energy held by a body when it's in stir,i.e haste isn't 0. When haste is 0, Kinetic Energy is basically 0.
Kinetic Energy is given by
K = 1 2 m v 2
where m = mass, v = haste.
Mass is a scalar volume and the haste which is a vector is squared which makes it a scalar volume as well. thus, Kinetic Energy is a scalar.
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the in situ moisture content of a soil is 15% with saturation level equal to 70% and void ratio of 0.9. the specific gravity of soil solids is 2.75. this soil is to be excavated and transported to a construction site for use in a compacted fill. if the specifications call for the soil to be compacted
This soil is to be excavated and transported to a construction site for use in a compacted Volume fill is 8680.73 m³
The specific gravity of solids = 2.75
situ moisture content of a soil is 15% with saturation level equal to 70% and void ratio of 0.9.
Dry weight = 103.5
Yd = 16.5/(1 + 18/100) = 14.34KN/m³
Volume of soil to be excavated to produce 7651m³
V = Yd compacted / Yd insite × compacted fill volume
V = 16.27/14.34 × 7651 = 8680.73 m³
No of trucks = V × Yinsity / 1.78 = 8680 × 16.5/178 = 826trucks.
Using the human body, such as by pinching or measuring an object's volume using the size of your hand, is the most traditional method of doing so. The human body, however, is incredibly unpredictable due to its differences. A more accurate technique to measure volume is to utilize fairly constant and long-lasting natural objects, like gourds, sheep or pig stomachs, and bladders. Small volumes are typically measured using standardized human-made containers today since metallurgy and glass manufacture have advanced through time. [3]: 393 By using a multiple or portion of the container, this approach is frequently used to measure small volumes of fluids or granular materials. To create a nearly flat surface, the container is shook or leveled off for granular items. The most exact approach to measure is not with this technique.
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A 10-cm-long spring is attached to the ceiling. When a 2.0 kg mass is hung from it, the spring stretches to a length of 15 cm.
What is the spring constant k? Answer for this already found= 392 N/m
1) How long is the spring when a 6.0 kg mass is suspended from it?
The spring is 20cm long when a 6.0 kg mass is suspended from it.
What is Hooke's Law's spring constant, k?K stands for the proportionality constant, commonly referred to as the "spring constant." In layman's words, stiffness and strength are shown by the k variable in Hooke's law (F = -kx). An object requires more force to be stretched to a specific length the greater the value of k.
F=-kx
“-ve" is for the direction of motion
K=F/x
Dimensions of F=[MLT-²]
Dimensions of x=[L]
K=[MLT-²]/[L]=[MT-²]
DIMENSIONS OF SPRING CONSTANT IS
[MT-²]
Why do we use the spring constant?The spring constant is calculated by dividing the force required to stretch or compress a spring by the lengthening or shortening of the spring. It is used to identify whether a spring is stable or unstable, and consequently, what system it should be employed in.
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A student initially stands on a circular platform that is free to rotate without friction about its center. The student jumps off tangentially, setting the platform spinning. Quantities that are conserved for the student-platform system as the student jumps include which of the following? 1. Angular momentum II. Linear momentum III. Kinetic energy Al only B Il only С I and II only D II and III only E I, II, and 111
The quantity conserved for the student platform system when the student jumps is included in the momentum angular.
The true choice is A.
Angular momentum is simply defined as the momentum possessed by objects that move circularly.
Momentum angle also has meaning as a measure used to see how much linear momentum is directed around a certain point. This point is known as the center point.
Since angular momentum and linear momentum are vectors, the direction must be considered. As in this question, the direction of the linear momentum keeps changing as the circular platform rotates, and the direction of the angular momentum is always the same (both off the page and into the page). That's why linear momentum changes but angular momentum doesn't. So, the quantity conserved for the student platform system when the student jumps is included in the momentum angular.
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Most of the mass of our Galaxy lies
a) in the bright spiral arms.
b) between Earth and the Galactic center.
c) outside the luminous part of the Milky Way Galaxy.
d) within the bulge.
e) at the galactic center.
c) outside the luminous part of the Milky Way Galaxy.
While much of the mass of our Galaxy lies within the bright spiral arms, the majority of the mass actually lies outside the luminous part of the Milky Way Galaxy.So the correct option is c.
The Milky Way Galaxy is a vast and expansive collection of stars, gas and dust that spans the universe. It is estimated to contain between 200 and 400 billion stars, making it one of the largest galaxies in the universe. The Milky Way is a spiral galaxy, meaning that it is composed of a central bulge surrounded by four main spiral arms. The luminous part of the Milky Way Galaxy, which is visible from Earth, lies within the spiral arms.
However, the majority of the mass of our Galaxy does not lie within the luminous part of the Milky Way Galaxy. Instead, much of the mass of the Milky Way lies outside the visible part of our Galaxy. This mass is found in the form of dark matter, which is an invisible form of matter that does not emit any light. Dark matter makes up around 85 percent of all the matter in the Universe and is believed to be responsible for the structure and evolution of galaxies.
The rest of the mass of our Galaxy is located within the bulge at the center of the Milky Way, as well as between Earth and the Galactic center. This mass is made up of stars, gas, dust and other forms of matter. While much of the mass of our Galaxy is invisible, it is still an important component of the Milky Way. Without this mass, the structure and evolution of the Milky Way would be drastically different.
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the top of the saturated zone, as marked by the dashed line in the illustration, is called the water .
The dashed line in the figure denotes the water, which is at the top of the saturated zone. The underground region is included in the saturated zone.
The geologic medium's whole network of connecting apertures is fully submerged in water. This zone is frequently divided into the phreatic zone and the capillary fringe by hydrogeologists. The area of ground directly below the water table is known as the zone of saturation. Water has seeped into the pores and cracks of the earth and rocks. Over the water table, the saturated zone is more corrosive than the saturated zone. One extreme of the area's moisture content and the other extreme of the soil's dryness. a saturated area. The unsaturated zone can contain discrete saturated zones.
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The complete question is-
The top of the saturated zone, as marked by the dashed line in the illustration, is called ?
orientation of patterns: explain why the diffraction pattern of the hair appears in the direction that it does (i.e., horizontal vs. vertical)
Additionally, if the light is sent as a vertical array of lines, these lines can be bent into horizontal rows of dots.
Simply put, what is diffraction?The act of light spreading out after passing through a tiny area or bending around an object is known as diffraction. The diffraction of light waves is a topic covered in physics classes. Sound, radio, and water waves are all susceptible to diffraction.
What is diffraction and how does it work?Water waves bending around a stationary object are the most typical instance of diffraction. Around an object's edge, light bends similarly. They diffract, or shift direction, noticeably.
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based on these insights, you create your primary message. which of the following reflect the expectations of a primary message? A
Although electric vehicle sales demand is on the rise, low availability of charging stations and short battery range are significant hurdles that Gaea must overcome
B
Electric vehicle sales demand is expected to grow by more than 400% by 2025. However, the number of publicly available vehicle charging stations is a significant factor in consumer buying decisions. Currently, there are many locations with so few charging stations that electric car owners would run out of power when traveling between stations. Vehicle battery range is also a significant factor for consumers. In 2020, the average battery range was 210 miles. However, the vast majority of people say they will not buy an electric car until the battery range is at least 300 miles per charge
C
Electric vehicle demand is skyrocketing
D
The number of publicly available vehicle charging stations is a significant factor in consumer buying decisions. Therefore, Gaea must begin building vehicle charging stations
The insights to be used in creating a primary message is that; Electric vehicle demand is skyrocketing. Option C
What are electric vehicles?We can see that the demand for electric vehicles has increased in the recent times. Why has the demand for electric vehicles increased? We know that in the recent times there has been a push for the use of cleaner energy.
This has made a strong impressions upon governments around the would and has led to an increase in the rate at which any kind of research that tries to fund the use of devices that use alternative energy to fossil fuels is concerned.
As a result of this, there has been an increase in the demand and the use of the electric vehicles especially in the developed countries where more people can be able to afford the vehicles.
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A vertical plate is submerged in water and has the indicated shape. Find a Riemann sum that describes the hydrostatic force against one side of the plate. Then, write the sum as an integral and evaluate it.The pressure of a fluid that is exerted on an object due to its gravity is called hydrostatic pressure. Mathematically hydrostatic pressure is represented as P=rhogh. The hydrostatic force is calculated by multiplying the hydrostatic pressure with the area.
The hydrostatic force is calculated by multiplying the hydrostatic pressure with the area is 6000lb.
What is hydrostatic force ?
A hydrostatic force is the outcome of a liquid's pressure loading when it acts on submerged surfaces. Calculating the hydrostatic force and determining the Centre of pressure are two important concepts in fluid mechanics.
What is gravity ?
A planet or other body's gravity draws objects toward its centre. The force of gravity keeps all the planets in their orbits around the sun.
The area of the strip is calculated as follows
Astrip = 6dy
Pstrip = pgy
Here, the density of water is p, the acceleration due to gravity is g and the vertical height of the strip from free surface of water is y.
The weight density of water is
Pg= 62.5 lb/ft3
The hydrostatic force again one side of the plate is calculated as follows.
F hydrostatic = ∫ P strip A strip
Substitute all the values in the above equation and integrate.
F hydrostatic = ∫ (pgy) (6dy)
F hydrostatic = ∫6pg ydy
F hydrostatic = 6pg y²/2
F hydrostatic = 6pg (6²/2 – 2²/2)
F hydrostatic = 6 X 62.5 (6²/2 – 2²/2)
F hydrostatic= 6000 lb
Therefore, hydrostatic force is calculated by multiplying the hydrostatic pressure with the area is 6000lb.
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In a Geiger tube the total time taken to create a pulse and then let the electrons recombine with the ions to again form a neutral state is about
A. 1 μs
B. 30 μs
C. 300 μs
D. 10,000 μs
In a Geiger tube, the total time taken to create a pulse and then let the electrons recombine with the ions to again form a neutral state is about C. 300 μs
How to calculate the ions?As we know that in G. M. Counter, slow positive ion takes 100μs to reach at cathode. If in this time, any other ion enters then no recording of this ion , known as dead time after this time also counter takes 100μs more, known as recovery time.
The sum of these times know as paralysis time of gm counter will be:
= (100+100+100)
= 300 μs.
Based on the information, the correct option is C.
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A 66.9 kg diver steps off a 6.07 m tower and drops straight down into the water. If he comes to rest 2.96 m below the surface of the water, determine the average resistance force exerted on the diver by the water.
The average resistance force exerted on the diver by the water is 2,000 N
According to the law of conservation of energy, the mechanical energy is constant.
Mechanical energy (EM) is equal to the kinetic energy (Ek) + potential energy (Ep).
In the given problem, the diver comes to rest at 2.96 m below the surface of the water. Hence, at this point, his velocity is zero, so is its kinetic energy. Therefore, according to the law of conservation of energy:
ΔE = - mg (h₂ - h₁)
Where:
m = mass of the diver
g = gravitation due to gravity
h = height
Hence,
ΔE = - 66.9 x 9.8 x (-2.96 - 6.07)
= 5920.25 Joule
This is equivalent to the work done by the resistance force.
Hence,
W = ΔE = F . s
Where:
s = distance under water
Hence,
5920.25 = F x 2.96
F = 5920.25 / 2.96 = 2,000 N
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a piston a has a diameter of 0.81 cm, as shown. a second piston b has a diameter of 4.0 cm. a b 578.8 n f in the absence of friction, determine the magnitude of the force f~ necessary to support the 578.8 n weight. answer in units of n.
11.7 N of force is needed to hold the weight m on Piston 2.
What are example and force?Force is the term used to describe a body's tendency to change or modify its state as a result of an external cause. When force is applied, the item can also alter its size, shape, and direction. kick a ball, pushing and pulling on the door, or kneading dough are a few examples.
Briefing:
The force required to support weight, m on Piston 2 is calculated from Pascal's principle as follows:
P₁ = P₂
where P₁ is pressure on Piston 1 = F₁/A₁
P₂ is pressure on Piston = F₂/A₂
F₁/A₁ = F₂/A₂
F₂ is the force on Piston 2 = 1189 N
A₁ is Area 1 = πr²
where r = d/2
A₁ = π * (0.81/2 *1/100)²
A₁ = 40.5* 10⁻⁵ m²
F₁ is the force on piston 1 = ?
A₂ is area 2
A₂ = π * (4.0/2 *1/100)²
A₂ = 2 * [tex]10^{-2}[/tex] m²
F₁ = A₁ * F₂/A₂
F₁ =40.5* 10⁻⁵ m² * 578.8 N / 2 * [tex]10^{-2}[/tex]m²
F₁ = 11.7N
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use the theory of elasticity and given applied pressure at the end of construction, determine the settlements at 2p and 3p
Elasticity theory is concerned with the relationship between forces applied to an item and the subsequent deformations.
In practice, analyzing a material's elastic behavior is reduced to studying basic deformations and determining the appropriate elastic constants. Our bodily tissues are pliable. This mechanical feature is particularly significant in the lungs, skin, and arteries, because aging produces emphysema, loose skin, and arteriosclerosis. Elastic fibers are extracellular matrix fibers that resemble rubber and are responsible for tissue elasticity. Elasticity refers to an object's or material's capacity to return to its original shape after being stretched or crushed. Because of its elastic nature, a rubber regains its shape after a long stretch.
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Nathalie, Selene, and Ella are playing tug-of-war, fighting over a .30 kg water bottle. Nathalie is pulling to the left with 85 N of force and Selene and Ella are both pulling to the right – Selene is pulling with 75 N of force. If the water bottle accelerates to the left at 2.0m/s2
A.Fnet on water bottle
B. FElla
The net force on the bottle is 6 N and the force exerted by Ella is 4 N.
We know the formula given by sir Issac Newton, which is, F = ma.
This formula means Force is equal to the mass of the particle times the acceleration of the particle.
So in this case the acceleration of the particle is given as 2 m/s.
The mass of the given particle is 3 kg.
Hence, the force on the particle is 3 X 2 = 6 Newtons.
In our case, the particle is a water bottle, hence the F net on the water bottle is 6 N.
Now, as the net force experienced by the bottle is 6 Newtons,
F Nathalie - F Selene -F Ella = 6N
85-75- F Ella =6 N
=> F Ella =4 N
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Figure shows three forces applied to a trunk that moves leftward by 3.00 m over a frictionless floor. The force magnitudes are F 1
​
=5.00 N,F 2
​
=9.00 N, and F 3
​
=3.00 N. and the indicated angle is θ=60.0 0
. During the displacement,
(a) what is the net work done on the trunk by the three forces?
(b) does the kinetic energy of the trunk increase or decrease?
The net work done on the trunk by the three forces is 1.50J and the kinetic energy of the trunk will increase
The data given in the question is:
F 1 =5.00N,
F2 =9.00N,
F3 =3.00N,
θ=60°
d=3m
Work done by each force can be found as
We know that, work done by a force is given by:
W =F d cosϕ,
where ϕ is the angle between Force and displacement vectors.
F₁ is in the direction of the displacement.
So,
W₁=F₁dcosϕ
=(5.00N)(3.00m)cos0°
=15.0J.
Force F₂ makes an angle of
ϕ ₂=180°−θ
=180° −60°
=120°
with the displacement i.e. in negative x direction.
So,
W₂=F₂dcosϕ₂
=(9.00N)(3.00m)cos120°
=−13.5J.
Force F₃ is perpendicular to the displacement.
So, W₃=F₃dcosϕ
=(3.00N)(3.00m) cos90°
=0J
Net Work done by three forces is
As work is a scalar quantity, so total work done will be the algebraic sum of all the individual works.
So, W=W₁+W₂+W₃
=15−13.5+0
=+1.50J.
According to Work energy theorem, total work done on a system equal the change in kinetic energy of the system.
Here, a positive work of 1.5 Joules is done on the trunk, so its Kinetic Energy will increase by 1.5 Joules.
Figure was missing it is attached with the answer
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You're carrying a 3.0-m-long, 20kg pole to a construction site when you decide to stop for a rest. You place one end of the pole on a fence post and hold the other end of the pole 35cm from its tip.
A) How much force must you exert to keep the pole motionless in a horizontal position?
Express your answer using two significant figures. answer must be "N"
You need to provide 132 N of force to maintain the pole horizontally.
The criteria are as follows: 3.2 m for the pole's length and 24 kg for its weight.
The pole's weight is determined as follows:
W = 24 x 9.8 = 235.2 N
The total force applied to maintain the pole's horizontality,
∑F = F1 + F2 = 235.2
F1 = 235.2 - F2
Consider the pole's core for a minute.
F1 × 1.6 = F2(1.6 - 0.35)
1.6(235.2 - F2) = 1.25 F2
376.2 - 1.6F2 = 1.25 F2
376.2 = 2.85 F2
F2 = 376.32 ÷ 2.85
F2 = 132.04
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A tank whose bottom is a mirror is filled with water to a depth of 19.3 cm. A small fish floats motionless 7.50 cm under the surface of the water. What is the apparent depth of the reflection of the fish in the bottom of the tank when viewed at normal incidence?
The fish's perceived depth is 5.3 cm, while the fish's picture is 24.8 cm. when observed at normal incidence, the perceived depth of a fish's reflect in the tank's bottom.
What do you deem an incident to be?
A "incidence" is the appearance of new cases of illness or injury within a population over a specific period of time. The amount of new cases in a population is how some public health experts define incidence, however
What distinguishes incidence from prevalence?
In contrast to prevalence, which is the percentage of a population with a particular characteristic, incidence is the number of new cases of a characteristic that appear in a population during a given time frame.
Briefing:
apparent depth=(Na/Nw)*s
=(1.00/1.33)*33cm
=24.8cm
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during a knee extension exercise there are two forces that are producing torque at the knee joint. one is the quadriceps muscle and the other is the weight at the ankle joint. the quad is capable of producing 500 newtons of force, while the weight at the ankle is 10 kg. the distance from the knee joint to the quad force is 0.05 meters and the distance from the knee joint to the weight is 0.38 meters (these are not the moment arms). the knee is flexed to 125 degrees. draw and calculate the moment arms for each force on the picture below and decide if the joint flexes or extends.
The Moment arm for equal force is 0.0287m, and the torque is -7.041Nm.
What is force ?
Everyday activities like walking, setting something down on a surface, tossing something into the air, and even the tides' regular variations all include the application of force. The result of the interaction between two or more things, a force is a push or a pull.
What is torque ?
The force that may cause an item to revolve along an axis is measured by torque. Similar to how force drives linear kinematics acceleration, torque drives angular acceleration. A vector quantity is torque.
a1 = a cos 55 = (0.38m) cos 55 = 0.218 m
Moment arm for equal force = q1 = q cos 55
= (0.05) cos 55
= 0.0287m
Now Tnet Fq - qT/counter clockwise – Wa a3/ clockwise
Tnet = (500 N) (0.207m) – (98N) (0.218m)
= 14.35Nm – 21.364 Nm
= -7.041Nm
As net torque is negative is weight will pull down the log joint will flex not extend.
Therefore, Moment arm for equal force is 0.0287m, and the torque is -7.041Nm.
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1. suppose a computer using direct mapped cache has 2^20 bytes of byte-addressable main memory, and a cache of 32 blocks, where each cache block contains 16 bytes.
Solution:
The block size = 16 words
Tag Block Offset
11 bits 5 bits 4 bits
The memory address 0DB63 will map to the 22nd block and 3 bytes of a block.
cache advantage is, when the cache block is made larger or bigger then, there are fewer misses. The disadvantage is that if the data is not used before the cache block is removed from the cache, then it is no longer useful.
After analyzing the question, the solution is:
As given The Cache of 32 blocks and the memory is word addressable:
The main memory size.
The block size.
The total number of blocks = main memory size/ block size:
Says it is 1 M words in size and it requires 20 bits. Now, from which 32 cache block requires 2^20, 20 bits, and block size means offset requires 2^4, 4 bits. Now the sizes of the bag, and, block and word fields are following:
Tag Block Offset
11 bits 5 bits 4 bits
The hexadecimal address value is 0DB63, its binary equivalent is
The tag = ( first 11 bits) = 0000 1101 101
block = ( next 5 bits ) = 10110
offset = ( next 4 bits ) = 0011
Therefore, the memory address 0DB63 will map to the 22nd block and 3 bytes of a block.
The main favored position or circumstance of the cache happens that, when the cache block is created best or considerably therefore, there happen hardly any misses. this takes place when the information in visible form in the block exists secondhand.
One of the loss exists that if the data exist not secondhand before the cache block exist detached from the cache, then it exist not any more valuable. in this place there exist an addition to the best miss punishment.
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what is the period if a runner completes 5 laps around a circular track in 450s
Answer:
90 seconds to complete one lap around the track
Explanation:
To find the period of a runner's laps, we need to first find the length of time it takes for the runner to complete one lap around the track. We can do this by dividing the total time it takes to complete 5 laps by the number of laps:
period = 450 seconds / 5 laps
period = 90 seconds/lap
This means that it takes the runner 90 seconds to complete one lap around the track. This is the period of the runner's laps.
spine in this situation. we will model the spine and upper body as a horizontal rigid rod of uniform density with a length of 50.0 cm and a mass of 40.0 kg. assume that the person attempts to lift an object with their arms, which we will model as attached at the far end of the rod. support of the back in this position is provided primarily by the erector spinalis muscle which we will model as being attached at one end to the spine at a point 33.0 cm from the hip at an angle of 10 degrees; the other end of the muscle is attached to the lower body below the hip.
The amount of tension in the back muscle is 3270 N.
Mass of object = 18.2 Kg
Mass of person = 40 Kg
Length = r = 0.5 m
Length at the spine at required position = r' = 0.33 m
Angle = θ = 10 degrees
Tension is defined as the force transmitted through a rope, string or wire when pulled by forces acting from opposite sides. The tension force is directed over the length of the wire and pulls energy equally on the bodies at the ends. Every physical object which is in contact exerts some force on one another.
Torque = Tension = T =
= T = r'sin10 -rmgsin90
= T = (0.5 X 40 X 9.8) / (0.33 X 0.1736)
= T = 3270 N
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The complete question:
We will model the spine and upper body as a horizontal rigid rod or uniform density with a length of 50.0 cm and a mass of 40.0 kg. Assume that the person attempts to lift an object with their arms, which we will model as attached at the far end of the rod. Support of the back in this position is provided primarily by the erector spinalis muscle which we will model as being attached at one end to the spine at a point 33.0 cm from the hip at an angle of 10 degrees; the other end of the muscle is attached to the lower body below the hip. The object being lifted has a mass of 18.2 kg. Calculate the tension , in the back muscle for this scenario.
If offspring is made asexually, how do they compare to the parent?
Answer: They will be an exact copy of the parent
Explanation:
A baseball player friend of yours wants to determine his pitching speed. You have him stand on a ledge and throw the ball horizontally from an elevation above the ground. The ball lands away. What is his pitching speed?
The pitching speed of basketball player is 58 m/s for A baseball player The ball lands away
As the ball thrown in horizontally, the initial vertical velocity of the ball is zero.
(Vy)t = 0
Use the kinematic equation of motion, y = (Vy)t+1/2gt² and find the time of flight of the baseball.
3.0 m = (0)t + 1/2 (9.8 m/s²)t²
3.0 m = (4.9 m/s²)t²
t= √3.0 m /4.9 m/s²
= 0.78 s
The maximum horizontal distance (range) travelled by the ball is.
x = v2t
V2 = x/t
= 30 m/0.78 s
= 38 m/s
Consider the ball is being thrown 5° above the horizontal. The maximum height to which the ball can go above the elevation is,
h= (vsin 5°)² / 2g
= [vsin 5°]² / 2(9.8 m/s²)
= 3.87×10^-4 V²
The time taken for ball to reach the ground from the height 0.559 m above the elevation of height 3.0 m is,
t=√2hmax/g
= √2(3.87x10^-4 v²) / 9.8 m/s²
= 8.88x10^-3 v
The horizontal range of the ball is.
x = v₂t
30 m = (v cos 5°) (8.88x10^-3 v)
V² = 30 m / (8.88×10^-3) cos 5°
v=58 m/s²
Consider the ball is being thrown 5° below the horizontal. The time of flight of the ball is,
t = v cos 5° / 30 m
=3.32×10^-2 v
The time taken for ball to reach the ground can be calculated as follows.
y = (Vy)t1 + 1/2 gt²
3.0 m = (vsin 5°) (3.32 × 10^−2 v) + 1/2 (9.8 m/s²) (3.32×10^-2 v)² =
3.0 m = (0.289×10^-2)v²+5.4×10^-3v²
8.29×10^-3 V^2 = 3.0 m
V = √3.0 m / 8.29 8 10^-3
= 19 m/s
Therefore, the minimum speed of the ball is 19 m/s and maximum speed of the ball is 58 m/s
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which of these variable stars would be classified as a rr lyrae? which of these variable stars would be classified as a rr lyrae? an f giant with a period of 14 hours a pulsar with a period of 0.14 seconds a k giant with a period of 14 days an m giant with a period of 140 days a b supergiant with a period of 0.14 days
An F giant with a period of 14 hours these variable stars would be classified as a RR Lyrae.
All the stars we see in the night sky are in our very own Milky way Galaxy. Our galaxy is referred to as the Milky way because it seems as a milky band of light inside the sky whilst you see it in a certainly darkish place. it's miles very difficult to be counted the range of stars in the Milky way from our position inside the galaxy.
The period of time at some stage in which an activity happens or a circumstance remains. it may be measured both in seconds or in thousands and thousands of years, depending upon the character of the pastime of situation being taken into consideration.
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a mass m starts at rest and then falls down distance l, where it contacts an unstressed spring of negligible mass. if the spring compresses for a maximum of l/2, find the force constant of the spring in terms of mg/l.
For a mass, the spring's force constant is 12 mg/L. M begins at rest and descends l distance before colliding with a negligible mass unstressed spring. if the spring is compressed for no longer than l/2.
The spring constant is significant because it demonstrates a fundamental material characteristic. The amount of force necessary to deform any spring made of any material is specified here. The material is more stiff when the spring constant is higher, and less stiff when the spring constant is lower. The force constant of an undamaged spring is k. It is stretched to an equilibrium length that is well inside the elastic limit by a weight that is suspended from it.
mg(L+L/2) = 0.5 kx^2
mg(3L)/2 = 1/2k(1/2)^2
3mgL/2 = kl^2/8
k = 12mg/L
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