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Option A that is 8.6 x 10^4 volt is the potential difference between a point 0.79 mm from a charge of 7.6nC and a point of infinity.

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The jeweler can determine which ring is Sara's by scratch test, acid test or magnet test.

Sara's solid gold ring is mixed with gold plated ring and now she has to identify which one is her real ring.

There are many method to identify if the ring is solid gold or not,

1. A scratch test. A scratch deep enough to penetrate till the metal of the gold-plated ring can tell if the ring is solid gold or not. The solid gold ring will be all uniformly distributed gold through the structure.

2. By acid test. By putting both the rings in the acid solution is can be found out which one is the real gold ring. The gold plated ring in the acid solution which eventually changes the color of the ring.

3. Magnet test. A very strong magnet will attract the gold plated ring but not solid gold ring because the solid gold rings are non-magnetic in nature.

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Answer:

Newton's 2nd Law

Explanation:

First law concerns balanced forces, which result in either static equilibrium or dynamic equilibrium, where there is no acceleration. Gravity causes the ball to accelerate so it can't be the first law.

Second Law deals with unbalanced forces (F=ma).

Third law relates to "action-reaction" which is unrelated to the scenario.

Answer:

Explanation:

The coulombs law is expressed as

F = kq1q2/r^2

where

F is the force

k is the coulomb constant and its value is 9 x 10^9 N/m^2C^2

q1 and q2 are the magnitude of the charges

r is the distance between them

From the information given,

r = 4 cm = 4/100 = 0.04m

For trial 1,

q1 = - 2μC

q2 = 8μC

Recall,

1 μC = 1 x 10^- 9 C

q1 = - 2 x 1 x 10^- 9 C

q2 = 8 x 1 x 10^- 9 C

F = (9 x 10^9 x 2 x 1 x 10^- 9 x 8 x 1 x 10^- 9)/0.04^2

F = 9 x 10^-5 N

There is an attraction

For trial 2,

q1 = - 4μC

q2 = 8μC

q1 = - 4 x 1 x 10^- 9 C

q2 = 8 x 1 x 10^- 9 C

F = (9 x 10^9 x 4 x 1 x 10^- 9 x 8 x 1 x 10^- 9)/0.04^2

F = 1.8 x 10^-4N

There is an attraction

For trial 3,

q1 = - 6μC

q2 = 8μC

q1 = - 6 x 1 x 10^- 9 C

q2 = 8 x 1 x 10^- 9 C

F = (9 x 10^9 x 6 x 1 x 10^- 9 x 8 x 1 x 10^- 9)/0.04^2

F = 2.7 x 10^-4N

There is an attraction

For trial 4,

q1 = - 8μC

q2 = 8μC

q1 = - 8 x 1 x 10^- 9 C

q2 = 8 x 1 x 10^- 9 C

F = (9 x 10^9 x 6 x 1 x 10^- 9 x 8 x 1 x 10^- 9)/0.04^2

F = 3.6 x 10^-4N

There is an attraction

The change in the value of the charge is proportional to the force

Answer:

productivity

Explanation:

it's the efficiency of production of goods or services

Answer:

Explanation:

The rate at which goods and services can be produced is called

b) productivity.

A) change in wave speed

Option A is correct

A. The velocity of car A with respect to car B is 20 km/h

The velocity of an object A relative to another object B is the velocity that object A would appear to have to an observer moving with B.

The velocity of car A with respect to car B is calculated as follows;

Va/b = Va - Vb

where;

Substitute the given parameters and solve for the  the velocity of car A with respect to car B.

Va/b = 50 km/h - 30 km/h

Va/b = 20 km/h

Thus, we can conclude that the velocity of car A with respect to car B will appear to decrease since they are moving in the same direction.

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a ) The mass of the child and basket = 5.61 kg

b ) The tension T in the cord attaching the child to the scale = 55 N

c ) The tension T' in the cord attaching the scale to the ceiling = 57.94 N

a ) The mass of the child and basket,

[tex]W_{b}[/tex] = 55 N

g = 9.8 m / s²

W = m g

[tex]m_{b}[/tex] = [tex]W_{b}[/tex]  / g

[tex]m_{b}[/tex] = 55 / 9.8

[tex]m_{b}[/tex] = 5.61 kg

b ) In the cord attaching the child to the scale,

∑ [tex]F_{y}[/tex] = 0

T - W = 0

T = W

T = 55 N

c ) In the cord attaching the scale to the ceiling,

[tex]m_{s}[/tex] = 0.3 kg

[tex]W_{s}[/tex] = [tex]m_{s}[/tex] * g

[tex]W_{s}[/tex] = 0.3 * 9.8

[tex]W_{s}[/tex] = 2.94 kg

∑ [tex]F_{y}[/tex] = 0

T - [tex]W_{s}[/tex] - [tex]W_{b}[/tex] = 0

T = 2.94 + 55

T = 57.94 N

Therefore,

a ) The mass of the child and basket = 5.61 kg

b ) The tension T in the cord attaching the child to the scale = 55 N

c ) The tension T' in the cord attaching the scale to the ceiling = 57.94 N

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Answer:

10 m/2²

Explanation:

v=t/d

blah blah blah

Answer:

10 m/s

Explanation:

Kinetic Energy = 1/2 m v^2

KE / ( 1/2 m) = v^2

then   v =  sqrt ( KE / (1/2  m  )  = 10 m/s

Centre of mass of the square piece at the middle of the stack is at x = 0 centre of mass of the bottom most square piece in the stack is at{ (l/4)^2 + (l/4)^2}^1/2 .

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F = force = 12 N

d = distance = 10 m

W= work

Apply:

W = F x d

Replacing:

W= 12 x 10 = 120 J

Answer:

B 2

Explanation:

Angle of reflection is the measure of the angle taken from the normal.

The average force a 70.0 kg sprinter exerts backward on the track is 84 N.

The law of conservation of energy states that energy can neither be created nor destroyed but can be converted from one form to another.

E = Fd

where;

The average force exerted by the sprinter is calculated as follows;

F = ma

where;

The acceleration of the sprinter is calculated as follows;

v² = u² + 2as

where;

(8)² = (2)² + (2x25)a

64 = 4 + 50a

60 = 50a

a = 60/50

a = 1.2 m/s²

Average force exerted by the sprinter;

F = ma

F = 70 kg x 1.2 m/s²

F = 84 N

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Option C) 3. There are about 3 measures until the next part enters in Kookaburra through the expression in Australian countryside.

The expression probably first appeared because of how many bushes and scrub there are in the Australian countryside. Gay — Up until the middle of the 1950s, the word gay denoted happiness and carelessness.

It therefore signified “happy and carefree” during the time this song was penned.

The state has issued them licenses and permits. For authorized and permitted educational initiatives, both kookaburras serve as educational ambassadors. Kookaburras are not recommended as pets by anyone.

They may be very unpredictable, demand a lot of space, must be maintained in a pack, are very loud, and need a special diet.

They consume insects, beetles, worms, frogs, small animals, snakes, lizards, and lizards.

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Answer:

The law of conservation of momentum tells us that momentum is conserved, therefore total initial momentum should be equal to total final momentum. In this case, we can expressed this mathematically as:

mA vA + mB vB = m v

where, m is the mass in kg, v is the velocity in m/s

since m is the total mass, m = mA + mB, we can write the equation as:

mA vA + mB vB = (mA + mB) v

furthermore, car B was at a stop signal therefore vB = 0, hence

mA vA + 0 = (mA + mB) v

1800 (vA) = (1800 + 1500) (7.1 m/s)

vA = 13.02 m/s

Explanation:

The answers include the following below:

This law states that the force which is needed to extend a spring is directly proportional to the distance in which the spring is extended from its rest or initial position.

The distance gotten is measured with the use of a ruler or a measuring tape so as to obtain an accurate result during the experimental procedures. Hooke'slaw is performed by adding some masses to a spring and taking note of the effect by measuring the length of the spring when the weight of the masses is increased.

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The work done to separate the plates of the parallel plate capacitor that's charged to a 0.00967 C is 2864.5 J

U = 1 / 2 C V²

U = Initial energy

C = Capacitance

V = Electric Potential

Q = Charge

C[tex]_{i}[/tex] = 5.13 μ F

Q[tex]_{i}[/tex] = 9.67 m C

C[tex]_{f}[/tex] = 1.27 μ F

As the capacitor is isolated, there'll be no further current flow and charge will remain constant.

Q[tex]_{f}[/tex] = Q[tex]_{i}[/tex] = 9.67 m C

Q = C V

Q² = ( C V )²

U[tex]_{i}[/tex] = 1 / 2 * C[tex]_{i}[/tex] * V[tex]_{i}[/tex]²

U[tex]_{i}[/tex] = 0.5 * ( C[tex]_{i}[/tex] * [tex]V_{i}[/tex] )² / C[tex]_{i}[/tex]

U[tex]_{i}[/tex] = 0.5 * Q[tex]_{i}[/tex]² / C[tex]_{i}[/tex]

U[tex]_{i}[/tex] = 0.5 * ( 9.67 * [tex]10^{-3}[/tex] / 5.13 * [tex]10^{-6}[/tex] )

U[tex]_{i}[/tex] = 942.5 J

U[tex]_{f}[/tex] = 1 / 2 * C[tex]_{f}[/tex] * [tex]V_{f}[/tex]²

U[tex]_{f}[/tex] = 0.5 * ( C[tex]_{f}[/tex] * [tex]V_{f}[/tex] )² / C[tex]_{f}[/tex]

U[tex]_{f}[/tex] = 0.5 * Q[tex]_{f}[/tex]² / C[tex]_{f}[/tex]

U[tex]_{f}[/tex] = 0.5 * ( 9.67 * [tex]10^{-3}[/tex] / 1.27 * [tex]10^{-6}[/tex] )

U[tex]_{f}[/tex] = 3807 J

W = U[tex]_{f}[/tex] - U[tex]_{i}[/tex]

W = 3807 - 942.5

W = 2864.5 J

Therefore, the work done to separate the plates of the parallel plate capacitor is 2864.5 J

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xplanation:

A swinging edndulum bob performs a simple harmonic motion under the influence of the gravity of the earth. In simple harmonic motion, the restoring force acts on the displaced mass which continuously tries to bring the mass to the equilibrium position.

The object of mass m falls due to the gravity of the earth.

Thus for the motion of the pendulum, a gravitational force acts as a restoring force and the object of mass will fall due to the gravity of the earth. The motion of the pendulum and the falling mass is due to the gravity of the earth and the acceleration due to the gravity of the earth is independent of the mass that is accelerating towards the earth.

inal answrer:

The correct option is (B) although they both accelerate due to gravity at the same rate, a restoring force acts on the bob.

uestion 5.

iven:

Mass, m = 25 kg

Tension = 47 N

Let's find the maximum acceleration the truck can have before the crate breaks.

Let the magnitude of the force be expressed as:

= m x a

efore the cord breaks , the maximum tension, T, in the string is:

= ma

Where:

T is the maximum tension

m is the mass

a is the maximum acceleration

ence, to findt he maximmum acceleration, rewrite the equation for a.

We have:

Now, input 47N for T and 25 kg for m to solve for a:

herrefore, the maximum acceleration of the truck before the cord breakes is 1.88 m/s²

The speed of the object when it strikes the earth's surface is 8087.45 m/s

We'll begin by obtainig the time taken for the object to strike the earth's surface. This can be obtained as follow:

h = ½gt²

3337116.42 = ½ × 9.8 × t²

3337116.42 = 4.9 × t²

Divide both side by 4.9

t² = 3337116.42 / 4.9

Take the square root of both side

t = √(3337116.42 / 4.9)

t = 825.25 s

Finally, we shall determine the speed the object used in striking the earth's surface. This can be obtained as follow:

v = gt

v = 9.8 × 825.25

v = 8087.45 m/s

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Sonar systems function using sound waves mostly in water, whereas radar systems operate primarily using radio frequencies in the air. Despite the medium difference, radar and sonar's identical underlying concepts frequently lead to technical convergence.

Sonar, which stands for Sound Navigation and Ranging, is beneficial for exploring and charting the ocean since sound waves travel farther in water than radar and light waves do.

RADAR transmits electromagnetic waves, whereas active SONAR transmits acoustic (sound) waves. Both systems rely on these waves returning echoes from particular features or targets to determine the most important properties and qualities of the target (i.e., shape, size, speed, distance, etc.).

Both of these sensor systems depend on the sending and receiving of return signals to operate. While sonar systems function largely with sound waves in water, radar systems primarily use radio waves in the air.

Active SONAR transmits acoustic (sound) waves, whereas RADAR transmits electromagnetic waves. Both systems rely on these waves returning echoes from specific features or targets to identify the target's crucial characteristics and traits (i.e., shape, size, speed, distance, etc.).

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Answer:

See below

Explanation:

Find out how long the vertical velocity and accel cause the rock to ground out....then multiply this time by the horizontal speed....then use pythag theorem for the TOTAL distance

df = do + vo t + 1/2 a t^2       df = final height = 0    do = original = 1.6 m

                                              v o = original velocity = 0    accel = - 9.81 m/s^2

0 = 1.6 + 0 + 1/2 ( - 9.8)(t^2)   shows t = .5714 seconds to hit the ground

horizontal distance = .5711 seconds * 41 m/s = 23.43 m

vertical distance = 1.6 m

TOTAL distance = sqrt (( 23.42)^2 + (1.6)^2 )  = 23.48 m  

  If questioner wants horizontal disance <=====use first answer

       if Q   wants TOTAL distance  <====== use second answer

The time taken for Philippe to go 1000 m is 44.5 s.

The net force on the cart is calculated as follows;

F(net) = F - Ff

where;

F(net) = 745 cos(15)  -  100

F(net) = 619.6 N

The mass of the cart is calculated as follows;

W = mg

m = W/g

m = (6000) / (9.8)

m = 612.24 kg

The acceleration of the cart is calculated as follows;

a = F(net) / m

a = (619.6) / (612.24)

a = 1.01 m/s²

The time taken for Philippe to go 1000 m is calculated as follows;

s = vt + ¹/₂at²

s = 0 + ¹/₂at²

2s = at²

t² = 2s/a

t = √(2s/a)

t = √(2 x 1000 / 1.01)

t = 44.5 seconds

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Answer:

The frictional force between the wall and the ball

Answer:

771 .4  kg

Explanation:

Remember    F = ma      so     F/a = m    

m = 27000 N / 35 m/s^2 = 771 .4 kg

Decrease its voltage and decrease its current change to a circuit is most likely to decrease its electrical power.

The correct option is B.

When charged electrons (current) are forced through a conducting loop by the pressure of an electric circuit's power source, they may perform tasks like lighting a lamp. In a nutshell, voltage equal pressure and is expressed in volts.

Electric potential difference, often referred to as voltage, is measured in units called volts. According to official definitions, a volt is the difference in potential between two locations on a wire that's also conveying a current of one ampere and dissipating one watt of power.

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Given:

Lenght = 21 cm

Width = 10 cm

Height = 7 cm

Density = 1000 kg/m^3

Gravity = 9.8 m/s^2

Apply the formula:

Pressure = depth x density x gravity

Depth = Height = 7 cm = 0.07 m

Replacing:

P = 0.07 x 1000 x 9.8 = 686 Pa