Probenecid is a drug used by some athletes to prevent the excretion of other substances into urine, thus lowering their detectable concentrations. A scientist makes three measurements of a urine sample known to contain probenecid and obtains a confidence interval of 11.8±0.5 mg/L at the 95% confidence level. What would happen to the confidence interval at the same confidence level if the number of measurements is increased to 10 assuming the standard deviation remains the same?
Answer:
The confidence interval will decrease
Step-by-step explanation:
Generally the confidence interval is mathematically represented as
[tex]\= x \pm z_c * \frac{s}{\sqrt{n} }[/tex]
Here [tex]z_c[/tex] is called the critical value of [tex]\frac{level \ of \ significance }{2}[/tex] obtained from the normal distribution table , s is the standard deviation , n is the sample size (number of measurements )
Now looking at the formula we that if the increase the sample size that the confidence level would decrease
So if the n is increased to 10
The confidence interval would decrease
A car is advertised as $288/month for 72 months. What is the cost of the car?
To
$14,400
$20,736
O
$28,800
O $17,280
Answer:
$20,736
Step-by-step explanation:
When these kind of advertisements are displayed,, it means the EMI cost per month shall be $288.
Since it provides the time period, that is 72 months,
Total cost of car in this case shall be $288 [tex]\times[/tex] 72 months = $20,736
Also, these include an interest factor, but overall it is = $20,736 only,
If one down payment for full price of the car is made the cost shall reduce by the interest amount, but since no interest rate is provided it shall be ignored.
(6n-7)+(8n+2)=23 HELP FAST PLEASE
Answer:
n=2
Step-by-step explanation:
(6n-7)+(8n+2)=23
14n-5=23
14n=28
n=2
What is the value of y?
Answer:
y = 40
Step-by-step explanation:
The sum of the angles of a triangle are 180 degrees
y+10 + 2y +50 = 180
3y+60 = 180
Subtract 60 from each side
3y+60-60 = 180-60
3y = 120
Divide each side by 3
3y/3 = 120/3
y = 40
when do historians believe that Euclid complete his work
Answer:
2.999 millions hours ago
Step-by-step explanation: :)
helppp please I have limited time
Answer:
p = T - a - b
Step-by-step explanation:
Hope that helps, not sure if it is correct though.
It takes Dariya 35 seconds to download 5 songs from the Internet. How can the number of seconds it would take Dariya to download 7 songs at this rate be determined? ( need help )
By dividing 35 by 7.
By multiplying 35 by 7.
By finding the unit rate and dividing it by 7.
By finding the unit rate and multiplying it by 7.
To determine the number of seconds it would take Dariya to download 7 songs at the same rate, we first find the unit rate and multiply it by 7.
Hence, option 4. By finding the unit rate and multiplying it by 7 is the right option.
Unit Rate = 7second/song.
Time to download 7 songs = 49 seconds.
What do we mean by unit rate?A unit rate is a quantity taken for a unit of another quantity.
How do we solve the given question?We are given that it takes Dariya 35 seconds to download 5 songs from the Internet. We are asked about the time it will take Dariya to download y songs at the same rate.
We will first determine the unit rate of the time taken for downloading a song.
5 songs take 35 seconds.
∴ 1 song takes 35/5 = 7 seconds.
∴ Unit rate is 7seconds/song.
Now to determine the time for downloading 7 songs, we multiply the unit rate by 7.
∴ Time taken to download 7 songs = 7 songs * unit rate
or, Time taken to download 7 songs = 7 songs * 7 second/song
or, Time taken to download 7 songs = 49 seconds.
∴ To determine the number of seconds it would take Dariya to download 7 songs at the same rate, we first find the unit rate and multiply it by 7.
Hence, option 4. By finding the unit rate and multiplying it by 7 is the right option.
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State the domain and range in set notation
Answer:
Image result for State the domain and range in set notation
The domain is the set of all first elements of ordered pairs (x-coordinates). The range is the set of all second elements of ordered pairs (y-coordinates). Only the elements "used" by the relation or function constitute the range. Domain: all x-values that are to be used (independent values).
Step-by-step explanation:
Answer:
4
Step-by-step explanation:
The last option is not complete, but since the first three options are incorrect, the last option is correct
Solve -6(4-x)≤-4(x+1) for x
No silly answers please.
Answer:
x≤2
Step-by-step explanation:
Answer:
x ≤ 2
Step-by-step explanation:
well, -6 x 4 = -24
-6 x X = -6x
so far, we have -24 -6x ≤-4(x+1)
-4 x X = -4x
and -4 x 1 = -4 , so we now have -24 -6x ≤ -4x + -4
now we subtract x on one side, and to the other side as well, and you do the same for the numbers!
Determine what to add to make the trinomial a perfect square. x2+8x+___
Answer: 16
Step-by-step explanation:
For a perfect square each factor is identical.
Now, we have to find a number that adds to get 8.
The only option is (x+4)(x+4). When you distribute, you get x²+8x+16.
Now, we know that the missing number is 16.
A village fete has a children’s running race each year, run in heats of up to ten children. For each heat the first three contestants past the finishing line qualify for the final. There are three prizes in the final for 1st, 2nd and 3rd places. One year 29 children enter the race so there are three heats, of ten, ten and nine children. One year 29 children enter the race so there are three heats, of ten, ten and nine children. 1) What is the probability that three randomly chosen competitors win prizes? 2) What is the probability that two randomly chosen competitors win prizes? 3) How many ways are there to select ten competitors for the first heat? 4) Once the competitors have been selected for the first heat, how many different groups of three qualifiers are possible from this heat
Answer: 1) 1/3,654 2) 3/406 3) 72,684,900,288,000 4) 120
Step-by-step explanation:
1) First and Second and Third
[tex]\dfrac{3\ total\ prizes}{29\ total\ people}\times \dfrac{2\ remaining\ prizes}{28\ remaining\ people}\times \dfrac{1\ remaining\ prize}{27\ remaining\ people}=\dfrac{6}{21,924}\\\\\\.\qquad \qquad \qquad \qquad \qquad \qquad \qquad \qquad \qquad \qquad \qquad \qquad \qquad \quad =\large\boxed{\dfrac{1}{3,654}}[/tex]
2) First and Second
[tex]\dfrac{3\ total\ prizes}{29\ total\ people}\times \dfrac{2\ remaining\ prizes}{28\ remaining\ people}=\dfrac{6}{812}=\large\boxed{\dfrac{13}{406}}[/tex]
[tex]3)\quad \dfrac{29!}{(29-10)!}=\large\boxed{72,684,900,288,000}[/tex]
[tex]4)\quad _{10}C_3=\dfrac{10!}{3!(10-3)!}=\large\boxed{120}[/tex]
How do you do this problem?
Answer:
Your answer is absolutely correct
Step-by-step explanation:
The work would be as follows:
[tex]\int _0^{\sqrt{\pi }}4x^3\cos \left(x^2\right)dx,\\\\\mathrm{Take\:the\:constant\:out}:\quad \int a\cdot f\left(x\right)dx=a\cdot \int f\left(x\right)dx\\=> 4\cdot \int _0^{\sqrt{\pi }}x^3\cos \left(x^2\right)dx\\\\\mathrm{Apply\:u-substitution:}\:u=x^2\\=> 4\cdot \int _0^{\pi }\frac{u\cos \left(u\right)}{2}du\\\\\mathrm{Apply\:Integration\:By\:Parts:}\:u=u,\:v'=\cos \left(u\right)\\=> 4\cdot \frac{1}{2}\left[u\sin \left(u\right)-\int \sin \left(u\right)du\right]^{\pi }_0\\\\[/tex]
[tex]\int \sin \left(u\right)du=-\cos \left(u\right)\\=> 4\cdot \frac{1}{2}\left[u\sin \left(u\right)-\left(-\cos \left(u\right)\right)\right]^{\pi }_0\\\\\mathrm{Simplify\:}4\cdot \frac{1}{2}\left[u\sin \left(u\right)-\left(-\cos \left(u\right)\right)\right]^{\pi }_0:\quad 2\left[u\sin \left(u\right)+\cos \left(u\right)\right]^{\pi }_0\\\\\mathrm{Compute\:the\:boundaries}:\quad \left[u\sin \left(u\right)+\cos \left(u\right)\right]^{\pi }_0=-2\\=> 2(-2) = - 4[/tex]
Hence proved that your solution is accurate.
Answer:
[tex]\int\limits^{\sqrt{\pi}}_0 {4x^3\cos(x^2)} \, dx=-4[/tex]
Step-by-step explanation:
So we have the integral:
[tex]\int\limits^{\sqrt{\pi}}_0 {4x^3\cos(x^2)} \, dx[/tex]
As told, let's use u-substitution first and then use integration by parts.
For the u-substitution, we can let u to be equal to x². So:
[tex]u=x^2[/tex]
Differentiate:
[tex]du=2x\, dx[/tex]
We can rewrite our integral as:
[tex]\int\limits^{\sqrt{\pi}}_0 {2x(2x^2)\cos(x^2)} \, dx[/tex]
Therefore, by making our u-substitution, our integral is now:
[tex]\int\limits {2u\cos(u)} \, du[/tex]
We also need to change our bounds. Substitute them into u. So:
[tex]u=\sqrt{\pi}^2=\pi\\u=(0)^2=0[/tex]
Therefore, our integral with our new bounds is:
[tex]\int\limits^{\pi}_{0} {2u\cos(u)} \, du[/tex]
Now, let's use integration by parts. Integration by parts is given by:
[tex]\int\limits {v}\, dy=vy-\int y\, dv[/tex]
(I changed the standard u to y because we are already using u).
Let's let v be 2u and let's let dy be cos(u). Thus:
[tex]v=2u\\dv=2\,du[/tex]
And:
[tex]dy=\cos(u)\\y=\sin(u)[/tex]
So, do integration by parts:
[tex]=2u\sin(u)-\int \sin(u)2\,du[/tex]
Simplify:
[tex]=2u\sin(u)-2\int \sin(u)\,du[/tex]
Evaluate the integral:
[tex]=2u\sin(u)+2\cos(u)[/tex]
Now, use the bounds. So:
[tex](2(\pi)\sin(\pi)+2\cos(\pi))-(2(0)\sin(0)+2\cos(0))[/tex]
Evaluate:
[tex]=(2\pi(0)+2(-1))-(0(0)+2(1))[/tex]
Simplify:
[tex]=(-2)-(2)[/tex]
Subtract:
[tex]=-4[/tex]
And we're done!
Solve 3(x - 1) + 2 = 5x + 6, Answer is a decimal round to the hundredth (2 digits) or use / for fraction bar.
Answer:
x=-3.5
Step-by-step explanation:
3(x-1)+2=5x+6
3x-3+2=5x+6
3x-1=5x+6
3x-5x=6+1
-2x=7
[tex] - \frac{7}{2} [/tex]
x=-3.5
a right rectangular prism has these dimensions:
Length: 1 1/3
width: 5/6
height: 2/3
si el perímetro del círculo es 10π,determina el perímetro del rectángulo
Use rounding (to the nearest 10) to estimate the product of 3217 X 44.
The required, when rounded to the nearest 10, the estimated product of 3217 × 44 is 128,800.
What is the product?In mathematics, products are defined as the repetitive addition of a value a number of times to another value.
Here,
To estimate the product of 3217 × 44 by rounding to the nearest 10, we can round each number to the nearest 10 and then multiply:
3217 rounds to 3220
44 rounds to 40
So we can estimate the product as:
3220 × 40 = 128,800
Therefore, when rounded to the nearest 10, the estimated product of 3217 x 44 is 128,800.
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(c) Given that the system has at least one type of defect, what is the probability that it has exactly one type of defect
Answer:
The probability is 0.357
Step-by-step explanation:
Given that,
The system has at least one type of defect,
Suppose, A certain system can experience three different types of defects.
Let [tex]A_{i}[/tex] (i = 1,2,3) denote the event that the system has a defect of type i.
Suppose that the following probabilities are,
[tex]P(A_{1})=0.11[/tex]
[tex]P(A_{2})=0.08[/tex]
[tex]P(A_{3})=0.05[/tex]
[tex]P(A_{1}\cup A_{2})=0.13[/tex]
[tex]P(A_{1}\cup A_{3})=0.13[/tex]
[tex]P(A_{2}\cup A_{3})=0.11[/tex]
[tex]P(A_{1}\cap A_{2}\cap A_{3})=0.01[/tex]
[tex]P(A_{1}\cap A_{2})=0.06[/tex]
[tex]P(A_{1}\cap A_{3})=0.03[/tex]
[tex]P(A_{2}\cap A_{3})=0.02[/tex]
[tex]P(A_{1}\cup A_{2}\cup A_{3})=0.14[/tex]
We need to calculate the probability that it has exactly one type of defect
Using given data
[tex]P=\dfrac{P(A_{1}\cap A_{2}'\cap A_{3}')}{P(A_{1}\cup A_{2}\cup A_{3})}+\dfrac{P(A_{1}'\cap A_{2}\cap A_{3}')}{P(A_{1}\cup A_{2}\cup A_{3})}+\dfrac{P(A_{1}'\cap A_{2}'\cap A_{3})}{P(A_{1}\cup A_{2}\cup A_{3})}[/tex]
[tex]P=\dfrac{P(A_{1})-P(A_{1}\cap A_{2})-P(A_{1}\cap A_{3})+P(A_{1}\cap A_{2}\cap A_{3})}{P(A_{1}\cup A_{2}\cup A_{3})}[/tex] + [tex]\dfrac{P(A_{2})-P(A_{1}\cap A_{2})-P(A_{2}\cap A_{3})+P(A_{1}\cap A_{2}\cap A_{3})}{P(A_{1}\cup A_{2}\cup A_{3})}[/tex]+ [tex]\dfrac{P(A_{3})-P(A_{1}\cap A_{3})-P(A_{2}\cap A_{3})+P(A_{1}\cap A_{2}\cap A_{3})}{P(A_{1}\cup A_{2}\cup A_{3})}[/tex]
P = [tex]\dfrac{P(A_{1})+P(A_{2})+P(A_{3})-2P(A_{1}\cap A_{2})-2P(A_{1}\cap A_{3})-2P(A_{2}\cap A_{3})+3P(A_{1}\cap A_{2}\cap A_{3})}{P(A_{1}\cup A_{2}\cup A_{3})}[/tex]
Put the value into the formula
[tex]P=\dfrac{0.11+0.08+0.05-2(0.06)-2(0.03)-2(0.02)+3(0.01)}{0.14}[/tex]
[tex]P=0.357[/tex]
Hence, The probability is 0.357
help me please this is due today :(:
Answer:
F(-6, 3) --> F'(-6,3)
G(-4,3) --> G'(-8,3)
H(-2,4) --> H'(-10,4)
Answer:
F(-6,3)
G(-8,3)
H(-10,4)
Step-by-step explanation:
If your reflecting over the red line then all I do is first try to recreate the shape on the other side of the red line. (Like a reflection) And then look at the points it landed on. And that's your answer
the ratio of two numbers is 3:7. the product of these 2 numbers is 189. what is the smaller of these numbers?
Answer:
9.
Step-by-step explanation:
I am assuming that the two numbers are positive.
Let the numbers be 3x and 7x.
Then 3x * 7x = 19
21x^2 = 189
x^2 = 9
x = 3.
So the smaller of these numbers is 3*3 = 9.
Answer:
9 if that does not work try - 21
Step-by-step explanation:
Let the two numbers be x and y
x/y = 3/7 which means that x is the smaller number.
x*y = 189
Cross multiply the top equation
7x = 3y
Divide by 7
x = 3/7 ^ y
x*y = 189
(3/7 y) * y = 189
Multiply by 7
3y^2 = 189*7
3y^2 = 1323
Divide by 3
y^2 = 441
Take the square root of both sides
y = 21
The question is a bit ambiguous. You could use - 9 and - 21 in which case the smallest number is -21. I think they intend 9 however.
x = 3/7 * 21
x = 3*3
x = 9
Check
x*y = 9 * 21 = 189
The freeman family is barbecuing veggi burgers corn on the cobs and mushrooms caps in their local park if 3/8 of the items are barbecued are veggie burgers and 1/3 of the items are barbecued are corn on the cobs what fraction of barbecued items are mushrooms caps
Answer:
7/24
Step-by-step explanation:
Solve for x. 6x−24=x−2
Answer:
22/5
Step-by-step explanation:
6x-24=x-2
6x-x=-2+24
5x=22
x=22/5
If you are dealt 4 cards from a shuffled deck of 52 cards, find the probability that all 4 cards are picture cards .
Answer:
If we defelt 4 cards from 52 cards
Step-by-step explanation:
P(b) favorable outcome /total number of outcomes
48/52
The probability that all 4 cards are picture cards is 0.00183
How many kinds are in a deck of 52?A standard 52-card deck comprises 13 ranks in each of the four French suits: clubs (♣), diamonds (♦), hearts (♥) and spades (♠). Each suit includes three court cards (face cards), King, Queen and Jack, with reversible (double-headed) images.
as, we know
A face card is any of the twelve cards in a deck which has a picture of a face. The face cards are kings, queens, and jacks.
So, the possibilities to get a picture card is are 3*4=12.
Now, he probability that all 4 cards are picture cards
=(12/52) * (11/51) * (10/50) * (9/49)
=( 11880 / 6497400 )
= ( 0.0018284237 )
= 0.00183
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......................................................
Answer:
x = 6
Step-by-step explanation:
Area of rectangle = length * width
= 10 * (x +2)
= 10*x + 10*2
= 10x + 20 square units
Area of triangle = [tex]\frac{1}{2}*bh[/tex]
[tex]=\frac{1}{2}*2*(x + 4)\\\\\\=1 * (x +4)\\\\\\[/tex]
= (x + 4) square units
Area of rectangle = 8* area of triangle
10x + 20 = 8 *( x+ 4)
10x + 20 = 8x + 32
Subtract 20 form both sides.
10x = 8x + 32 - 20
10x = 8x + 12
Subtract 8x form both sides
10x - 8x = 12
2x = 12
Divide both sides by 2
2x/2 = 12/2
x = 6
Help...plzz giving 25 points
Answer: the integers are closed under addition, multiplication, and subtraction, but NOT division.
Step-by-step explanation:
The length of XY is 24 centimeters. The midpoint of XY is M, and C is on XM so that XD is 2/3 of XM. Point D is on MY so that MD is 3/4 of MY. What is the length of CD?
The length of CD is centimeters
Answer:
CD = 13 cm
Step-by-step explanation:
We assume you intend XC = 2/3 of XM, since XD cannot be that fraction of XM.
__
Of course XM = MY = 12, since M is the midpoint of a segment 24 cm long. Then 2/3 of XM is 8 cm, and 3/4 of MY is 9 cm.
CD = CM + MD = 4 cm + 9 cm
CD = 13 cm
i need alot of help plzzzzzz 50 points and ill give brainliest
Answer:
y=4
y=8
y=12
y=16
2)4=19
5=22
addition of 3 to each value
3)17
4)3a^2
5)a^4
6)1
7)An arithmetic sequence is such that the difference between any term and the one immediately preceeding it is constant.
8)A geometric sequence is such in which each term is a constant multiple of its preceeding.
9)1.25
10)B.
Answer:
y=4
y=8
y=12
y=16
2)4=19
5=22
addition of 3 to each value
3)17
4)3a^2
5)a^4
6)1
7)An arithmetic sequence is such that the difference between any term and the one immediately proceeding it is constant.
8)A geometric sequence is such in which each term is a constant multiple of its proceeding.
9)1.25
10)B.
Step-by-step explanation:
Graph the line with slope -1/2
passing through the point (-2, 4).
This image should help with that.
A.
Write an expression for the perimeter?
B.
Write an expression for area
C.
Write Both as equations
Answer:
A. x+2+x+2
B. 2(x)
C. x+2+x+2=p
2(x)= a
The endpoints of (MP)are M(2,1) and P(12,6). If point K partitions (MP) in a ratio of MK:KP = 3:2, what are the coordinates of K?
Answer:
K(8, 4)
Step-by-step explanation:
Given:
M(2, 1), P(12, 6)
MK:KP = 3:2
Required:
Coordinates of K
SOLUTION:
Coordinates of K can be determined using the formula below:
[tex] x = \frac{mx_2 + nx_1}{m + n} [/tex]
[tex] y = \frac{my_2 + ny_1}{m + n} [/tex]
Where,
[tex] M(2, 1) = (x_1, y_1) [/tex]
[tex] P(12, 6) = (x_2, y_2) [/tex]
[tex] m = 3, n = 2 [/tex]
Plug in the necessary values to find the coordinates of K:
[tex] x = \frac{mx_2 + nx_1}{m + n} [/tex]
[tex] x = \frac{3(12) + 2(2)}{3 + 2} [/tex]
[tex] x = \frac{36 + 4}{5} [/tex]
[tex] x = \frac{40}{5} [/tex]
[tex] x = 8 [/tex]
[tex] y = \frac{my_2 + ny_1}{m + n} [/tex]
[tex] y = \frac{3(6) + 2(1)}{3 + 2} [/tex]
[tex] y = \frac{18 + 2}{5} [/tex]
[tex] y = \frac{20}{5} [/tex]
[tex] y = 4 [/tex]
The coordinates of K = (8, 4)
Introduction to Interval Notation
What is the domain and range?
2.
The domain of this function is 3≤x≤5 in interval notation that is [3,5]
The range is -3≤y≤3. In interval notation that is [-3,3]
4.
The domain of this function is -5≤x≤-1 in interval notation that is [-5,-1]
The range is 1≤y≤5. In interval notation that is [1,5]
:)