answer: associative property
Step-by-step explanation:
its any of this greater than 7.03 7.031 7.030 7.003 7.0
7.031 is greater than 7.03.
The given value is having a 2-digit decimal place.
The options which are provided are:
1)7.031
2)7.030
3)7.003
4)7.0
Comparing the first decimal placeholder of each option with the question, all options have the same digit which is zero.
Comparing the second decimal placeholder of each option with the question, only option 1)7.031 and option 2)7.030 is having .03 the rest of the options, option 3)7.0003 and 4)7.0 have .00 has their second digit hence both option 7.0003 and 7.0 are smaller than 7.03.
Out of the remaining options, when options 1)7.03 and 2)7.031 are compared it can be seen that 7.031 is greater because the third decimal placeholder of 7.031 is 1 and 7.03 is 0 hence 7.031 is greater than 7.03.
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Create an equation that is parallel to the line y = 2x + 3 and goes through the point (0, -2).
Find the difference between 2.5 and 7.5 and the sum of 2.75 and 9.55
⇒To get the difference we subtract.
[tex]2.5-7.5=-5\\[/tex]
⇒To get the sum we add.
[tex]2.75+9.55=12.3[/tex]
Goodluck!!
A) The linear model represents the height, f(x), of a water balloon thrown off the roof of a building over times, x measured in seconds. During what interval(s) of the domain is the water balloon's height staying the same?
A.0 ≤ x ≤ 2
B.2 ≤ x ≤ 5
C.5 ≤ x ≤ 6
D.6 ≤ x ≤ 8
B) The linear model represents the height, f(x), of a water balloon thrown off the roof of a building over time, x, measured in seconds. During what interval(s) of the domain is the water balloon's height increasing?
A.0 ≤ x ≤ 2
B.40 ≤ y ≤ 70
C.5 ≤ x ≤ 8
D.40 ≤ y ≤ 10
C) The linear model represents the height, f(x), of a water balloon thrown off the roof of a building over time, x, measured in seconds. During what interval(s) of the domain is the water balloon's height decreasing the fastest?
A.5 ≤ x ≤ 9.5
B.8 ≤ x ≤ 9.5
C.6 ≤ x ≤ 8
D.5 ≤ x ≤ 6
D) The linear model represents the height, f(x), of a water balloon thrown off the roof of a building over time, x, measured in seconds. Justify your answer from Part C.
A.5 ≤ x ≤ 9.5 is the interval where the balloon's height is decreasing.
B.8 ≤ x ≤ 9.5 is the interval where the slope is the steepest.
C.6 ≤ x ≤ 8 is the interval where the balloon's height decreases the most.
D.5 ≤ x ≤ 6 is the interval where the slope is the steepest.
Please help as fast as possible <3
As shown in the reference graph attached hereby with the question statement, if the linear model represents the height, f(x), of a water balloon thrown off the roof of a building over time "x" measured in seconds, then,
(A) During (2 ≤ x ≤ 5) seconds in the time domain, the water balloon's height remains the same.
(B) During (0 ≤ x ≤ 2) seconds, the height of the water balloon is increasing.
(C) During (5 ≤ x ≤ 6) seconds, the height of the water balloon decreases the fastest.
(D) From Part (C), it can be justified that 5 ≤ x ≤ 9.5 is the interval where the balloon's height is decreasing, and, (5 ≤ x ≤ 6) is the interval where the slope is the steepest.
As per the question statement and the reference graph attached alongside, the linear model represents the height, f(x), of a water balloon thrown off the roof of a building over time "x" measured in seconds.
We are required to determine the correct time domains for four different situations, by observing the plotted graph.
Part (A) is to determine the correct time domain where the water balloon's height remains the same.
From the graph, it is clear that, the height remains constant at (y = 70), parallel to the x-axis from the 2nd second to the 5th second. Hence, During (2 ≤ x ≤ 5) seconds in the time domain, the water balloon's height remains the same.
Part (B) is to determine the correct time domain where the height of the water balloon is increasing.
From the graph, it is clear that, the slope of the concerned graph rises only from [(y = 40) to (y = 70)], starring from the 0th second until the 2nd second. Hence, During (0 ≤ x ≤ 2) seconds in the time domain, , the height of the water balloon is increasing.
Part (C) is to determine the correct time domain where the height of the water balloon decreases the fastest.
From the graph, it is clear that, the graph decreases thrice, first from [(y = 70) to (y = 40)], starting at the 5th second uptil the 6th second, then from [(y = 40) to (y = 10)], starting at the 6th second uptil the 9th second and lastly, from [(y = 10) to (y = 0)], starting at the 9th second till the 9.5th second. Here, we can easily calculate that, the balloon dropped 30ft in 1 sec at the first instance, 30ft in 3 seconds at the second instance and, 10ft in 0.5 seconds.
Since, [(30/1) > (10/0.5) > (30/3)],
Or, [30 > 20 > 10],
Thus, During (5 ≤ x ≤ 6) seconds, the height of the water balloon decreases the fastest.
Part (D) is to determine the correct statement mentioned under it's options, with judgement based on Part (C).
Option (i) states that [(5 ≤ x ≤ 9.5) is the interval where the balloon's height is decreasing] which is true, as we can observe from the graph that the slope is decreasing during the time interval of 5 to 9.5th seconds, although at different rates at different intervals.
Option (ii) states that [(8 ≤ x ≤ 9.5) is the interval where the slope is the steepest] which means that, during this above said interval, the height of the balloon drops the fastest which is false, as we have already proved in part (C) that during (5 ≤ x ≤ 6) seconds, the height of the water balloon decreases the fastest.
Option (iii) states that, [(6 ≤ x ≤ 8) is the interval where the balloon's height decreases the most] which is false, as balloons height falls the farthest by 30fts in two separate intervals, between (5 ≤ x ≤ 6) seconds and (6 ≤ x ≤ 9) seconds.
Finally, Option (iv) states that [(5 ≤ x ≤ 6) is the interval where the slope is the steepest] which means that, during this above said interval, the height of the balloon drops the fastest which is true, as we have already proved in part (C) that during (5 ≤ x ≤ 6) seconds, the height of the water balloon decreases the maximum in the shortest time period.
Time Domain: Time domain refers to the analysis of mathematical functions, physical signals or time series of economic or environmental data, with respect to the time interval over which, the function occurs.To learn more about Time Domain, click on the link below.
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How do I solve for number 4 and 5?
Answer:
i cant really see the words
Step-by-step explanation:
Draw a line representing the "rise" and a line representing the "run" of the line. State the slope of the line in simplest form.
The cost of gasoline is $2.45 per gallon. The price per gallon increased an average of 2% per hour over the period of a day. This can be modeled by the function G(t) = 2.45(1.02)t, where t is the number of hours since midnight. What would be the most appropriate
Answer:
The average cost for a gallon of gasoline in 2006 was $2.45. In 2007, the average cost of a gallon of gasoline was $3.29.
Evaluate these expressions.
Type the correct answer in each box.
6² =
8²=
15² =
Question 11
I just want the answer :)
The value of x is 4
The value of m ∠VUR = 126°
How to determine the valuesFrom the image shown, we have that;
A triangle is formedThe inscribed triangle is an equilateral triangleNote that all the sides of a equilateral triangle are equal.
Then, we have;
RV = SV = RSRV = 3x + 8SV = 6x - 4Now, equate the side lengths of the inscribed triangle, we have;
3x + 8 = 6x - 4
collect like terms
3x - 6x = -4 - 8
subtract the like terms
-3x = -12
Make 'x' the subject of formula
x = -12/-3
Find the quotient
x = 4
Note that m ∠VRS and m ∠VUR are on a straight line, we have;
m ∠VRS + m ∠VUR = 180
substitute the values
54° + m ∠VUR = 180
m ∠VUR = 180 - 54
m ∠VUR = 126°
Hence, the values are 4 and 126°
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Determine the value of y in the inequality.
18 + 6y < 42
Answer:
y<4
Steps:
18 + 6y < 42
6y < 42 - 18
y < 24/6
y < 4
Answer:
y<4
Step-by-step explanation:
18+6y<42
Subtract 18 from both sides.
6y<42−18
Subtract 18 from 42 to get 24.
6y<24
Divide both sides by 6. Since 6 is positive, the inequality direction remains the same.
[tex]y < \frac{24}{6} [/tex]
Divide 24 by 6 to get 4.
y<4
Label the rotated image PQR. Let P represent A'. Q represent B', and R represent C.
What is the m∠QPT? Show work.
Answer:
m∠QPT = 32°
Step-by-step explanation:
∠QPT and ∠SPR are vertical angles, meaning that the measure of their angles are congruent (the same).
Vertical angles are formed when two lines intersect, creating opposite angles. Those opposites are congruent (equal).
Step 1: Set the measure of the angles to equal each other.
[tex]\implies m \angle QPT = m \angle SPR[/tex]
[tex]\implies (2x+12) = (4x - 8)[/tex]
Step 2: Subtract 4x from both sides.
[tex]\implies 2x-4x+12 = 4x - 4x - 8[/tex]
[tex]\implies -2x+12 = - 8[/tex]
Step 3: Subtract 12 from both sides.
[tex]\implies -2x+12-12 = - 8-12[/tex]
[tex]\implies -2x = -20[/tex]
Step 4: Divide both sides by -2.
[tex]\implies \dfrac{-2x}{-2} = \dfrac{-20}{-2}[/tex]
[tex]\implies x = 10[/tex]
Step 5: Find the measure of ∠QPT by substituting 10 for x.
[tex]\implies [2(10)+12]^{\circ}[/tex]
[tex]\implies 32^{\circ}[/tex]
Therefore, the measure of ∠QPT is 32°.
Geometry homework
-foundation’s of geometry-
I need help
Answer:
m<2=m<5=50
m<4=85
m<6=45
Step-by-step explanation:
Answer:
1:85 2:50 3:45 4:85 5:50 6:45
Step-by-step explanation:
pls give brainliest
1 should be like 4 and 3 should be like 6.
Like 6+1 is 130 so 2 is 50
Jonathan has 3982 stickers in his sticker collection. Jessie has 2825 stickers in his collection. How many stickers do Jonathan and Jessie have altogether?
A total of 77 tornadoes have been documented in tuscaloosa county in the period beginning on january 1, 1950 and ending on december 31, 2020. What is the recurrence interval for tornadoes in tuscaloosa county?.
The number of tornadoes is 77
total time for occurrence is 70 years
using these
= ( 77/70)
= ( 1.1 )
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help meeeeeeeeeeee pleaseeeeeeeeeeeeee!!
Answer:
use a calculator or try math app
your balance is 89.75 and you deposit 156.90 and write a check for 34.79 and a withdrawal of 50.00 what is your new balance
Solve the equation.
2x^2 = -128
[tex]\quad \huge \quad \quad \boxed{ \tt \:Answer }[/tex]
[tex]\qquad \tt \rightarrow \: 8i[/tex]
____________________________________
[tex] \large \tt Solution \: : [/tex]
[tex]\qquad\displaystyle \tt \rightarrow \: 2 {x}^{2} = - 128[/tex]
[tex]\qquad\displaystyle \tt \rightarrow \: {x}^{2} = - \frac{ 128}{2} [/tex]
[tex]\qquad\displaystyle \tt \rightarrow \: {x}^{2} = - 64[/tex]
[tex]\qquad\displaystyle \tt \rightarrow \: x = \sqrt{ - 64} [/tex]
[tex]\qquad\displaystyle \tt \rightarrow \: x = \sqrt{( - 1) \sdot(64)} [/tex]
[tex]\qquad\displaystyle \tt \rightarrow \: x = \sqrt{ 64} \sdot \sqrt{ - 1} [/tex]
[tex]\qquad\displaystyle \tt \rightarrow \: x = 8 \sdot i[/tex]
[tex]\qquad\displaystyle \tt \rightarrow \: x = 8i[/tex]
[ i = iota, and i² = -1 ; (complex number) ]
Answered by : ❝ AǫᴜᴀWɪᴢ ❞
Answer:
[tex]x=8i[/tex]
Step-by-step explanation:
Given equation:
[tex]2x^2=-128[/tex]
Divide both sides of the equation by 2:
[tex]\implies \dfrac{2x^2}{2}=\dfrac{-128}{2}[/tex]
[tex]\implies x^2=-64[/tex]
Square root both sides:
[tex]\implies \sqrt{x^2}=\sqrt{-64}[/tex]
[tex]\implies x^2=\sqrt{-64}[/tex]
Rewrite -64 as 8² · -1:
[tex]\implies x=\sqrt{8^2 \cdot-1}[/tex]
[tex]\textsf{Apply radical rule} \quad \sqrt{ab}=\sqrt{a}\sqrt{b}:[/tex]
[tex]\implies x=\sqrt{8^2}\sqrt{-1}[/tex]
[tex]\textsf{Apply radical rule} \quad \sqrt{a^2}=a, \quad a \geq 0:[/tex]
[tex]\implies x=8\sqrt{-1}[/tex]
[tex]\textsf{Since $\sqrt{-1}=i$}[/tex]
[tex]\implies x=8i[/tex]
Imaginary numbers
Since there is no real number that squares to produce -1, the number [tex]\sqrt{-1}[/tex] is called an imaginary number, and is represented using the letter i.
An imaginary number is written in the form [tex]bi[/tex], where [tex]b \in \mathbb{R}[/tex].
3. The boundary line on the graph represents the equation 6 = 5x + 2y.Write an inequality that is represented by the graph. **
Step 1. The expression we have for the graph is:
[tex]6=5x+2y[/tex]To find the inequality that represents the graph, we need to solve for y first.
Step 2. Solve for y in the equation:
[tex]6=5x+2y[/tex]We can also represent this as follows:
[tex]5x+2y=6[/tex]Move 5x to the right side as a -5x:
[tex]2y=-5x+6[/tex]Move the two that is multiplying on the left side, to divide on the right side:
[tex]y=\frac{-5x+6}{2}[/tex]Simplify:
[tex]\begin{gathered} y=-\frac{5}{2}x+\frac{6}{2} \\ \downarrow \\ y=-\frac{5}{2}x+3 \end{gathered}[/tex]This is the equation of the line.
Step 3. Find the inequality.
Since the shaded part is below the line, and it has a dotted line, the inequality that represents this is:
[tex]y<-\frac{5}{2}x+3[/tex]Which are the values below the dotted line.
Answer:
[tex]y<-\frac{5}{2}x+3[/tex]I’m stuck on what equation I need to set up
The painting is a square, which means all its sides are equal.
If x is the length of one side, then, all the remaining 3 sides also have the same length: x.
The area of a square is the square if its side, then, for a square with sides x:
[tex]\text{Area}=x\cdot x=x^2[/tex]We know that the area of the painting will be 400 square inches, then:
a. The equation that can be set up to find the length of a side is:
[tex]x^2=400in^2[/tex]b. We can solve the equation by finding a number that multiplied by itself gives 400. For this case, we have two solutions. 20 and -20, since:
[tex]20^2=20\cdot20=400[/tex]And:
[tex](-20)^2=(-20)\cdot(-20)=400[/tex]-20 is also a solution because as a negative number, when multiplied by itself, gives a positive one. (A product between negative numbers gives always a positive number).
c. We have two solutions, however, only one of them makes sense: the 20. A negative length makes no sense, so we can discard the second solution (-20).
d. The length of the wood trim needed to go around the painting is then 20 inches. (we should not forget the units.)
Amy, Ravi, and Bob have a total of $127 in their wallets. Bob has 4 times what Ravi has. Ravi has $7 less than Amy. How much do they have in their wallets?
I ONLY HAVE A FEW MINUTES LEFT TO TURN THIS IN!!
If Amy, Ravi, and Bob have a total of $127 in their wallets. Bob has 4 times what Ravi has. Ravi has $7 less than Amy. The amount they have have in their wallets is : Army has $22.33, Ravi $89.33, Henry $15.33.
How to determine wallet amount?Let Army represent x dollars
Let Ravi represent 4x
Let Bob represent x - 7
Hence,
x + x - 7 + 4x = 127
Simplify by combining like terms
6x - 7 = 127
Add 7 to both sides of the equation leaving 6x
6x = 127+7
6x = 134
x =134/6
x = 22.33
x = Army has $22.33
Ravi
4x where x = 22.33
4(22.33) = 89.33
Bob
x - 7 where x = 22.33
22.33 -7 = 15.33
Prove :
Ravi + Bob + Henry = 127
= 22.33 +89.33 + 15.33 = 126.99 ≅127 (Approximately)
Therefore the have $22.23, $89.33 and 15.33 respectively.
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If h represents a number, which EQUATION is a correct translation of “Seventy less than 9 times a number is 375"?
Given the word exprssion:
Seventy less than 9 times a number is 375
Where h represents the number.
We have:
Seventy less than 9 times a number: 9h - 70
Seventy less than 9 times a number is 375: 9h - 70 = 375
Therefore, the equation that is a correct translation of Seventy less than 9 times a number is 375 is: 9h - 70 = 375
ANSWER:
9h - 70 = 375
PLEASE HELP !! Write the equation of the line that passes through the points(4,7) and(5,−7). Put your answer in fully simplified point-slope form, unless it is a vertical or horizontal line.
// ignore, made mistake//
Answer:
(4.7) and (5.-7)
Step-by-step explanation:
find the gradient using the formula:
y2-y1 (divide this by the bottom)
x2-x1
-7-7
5-4
=-14/1
-14 is the answer
then you will say y-y1= m(x-x1)
you can choose to sub any point
I will use (4;7)
therefore...
y-7=-14(x-4)
y= -14x+56+7
y= -14x+63
c) Calculate the percentage his peanuts. 2. Sipho's aunt sells her business and the new owner is not prepared to supply Sipho with free packaging. He now has to buy the packets and pays R50 for 1 000 packets. a) Calculate what one packet costs him. b) If Sipho continues to sell the packets at R1 each, calculate the percentage profit that he will make on his peanuts. c) If Sipho wants to make the same profit on the peanuts as before, calculate what he should charge for a 100 g of peanuts. d) What practical problem do you foresee in the case of Question 2. c)? e) Describe how you would advise Sipho to price his peanuts. lu huving a product and selling it at a profit. (2)
According to the given problem,
(i) It is given that,
The cost price of 1000 packets of peanuts = Rs. 50
We need to find the cost price of 1 packet of peanut = [tex]\frac{50}{1000}[/tex] = Rs. 0.05
(ii) Selling price at which Sipho continues to sell 1 packet = Rs. 1
Then Selling price of 1000 packets = 1000 x 1 = Rs. 1000
Then Profit made by sipho = Selling Price - Cost Price
= 1000 - 50
= Rs.950
Profit percentage gained by Sipho = [tex]\frac{Profit}{Cost Price}[/tex] x 1000
= [tex]\frac{950}{50}[/tex] x 1000
= 1900 %
(iii) The profit earned by sipho remains same, we nee to find the cost price at which Sipho should sell 100gm of her peanuts is Rs. 1
(iv) I would advice Sipho to sell peanuts at a selling price more than the cost price in order to gain profit
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-7/8 is at most the difference of twice a number m and 5/4
Answer:
Step-by-step explanation:
The given inequality can be written as 2m - 5/4 ≤ -7/8.
An inequality -7/8 is at most the difference of twice a number m and 5/4 which is 2m - 5/4 ≤ -7/8.
Difference of twice a number 'm' and 5/4 is 2m - 5/4 and this is at most -7/8 means less than or equal to.
∴ The given statement can be written as 2m - 5/4 ≤ -7/8
Answer:
2m - 5/4 ≤ -7/8
Step-by-step explanation:
hope this helps
21) Richard has 18 1/3 coins of the coins are dimes, of the coins are nickels, and the rest
are quarters. How many of the 18 coins are quarters?
The number of quarters, Richard have is 3 out of 198 coins he have.
What is termed as the fraction?Fractions are defined as a numerical value that represents a portion of a whole. A fraction is a portion as well as section of any quantity taken from the whole, which can be any amount, a specific value, or an item. Every fraction has a numerator and a denominator separated by a horizontal bar recognized as the fractional bar.For the given question,
The total number of coins Richard have is 18.
The fraction of dimes is 1/3.
1/3 of 18 = (1/3)×18 = 6
The number of dimes is 6.
The fraction of nickles is 1/2.
1/2 of 18 = (1/2)×18 = 9
Let the number of quarters be 'x'.
Total coin = dimes + nickles + quarters.
18 = 6 + 9 + x
x = 18 - 15
x = 3
Thus, the number of quarters, Richard have is 3.
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help me please if you can:)
In the polygon, The triangles are not similar
What is similar triangles ?The term similar triangles refers to triangles that the ratio of the sides are equal.
In the problem, the sides of the triangles are given as
In DQRS: QR = 4 RS = 15, and < DR = 36In DUVT: VT = 8 TU = 32, and < DT = 36The ratio of the sides
In DQRS: QR / RS = 4/15 = 0.27
In DUVT: VT / TU = 8/32 = 0.25
0.27 ≠ 0.25
since the ratio of the sides are not equal the two triangles are not similar
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The value of [tex]\sqrt{6}[/tex] is not -4 because ______.
The solution of the value is mathematically given as
√6 =2.449
This is further explained below.
What is square Root?Generally, In mathematics, the term "square root" refers to a component of a number that, when multiplied by itself, results in the same value as the original number.
As an example, both 3 and –3 are square roots of the number 9.
A number y is said to have a square that is equal to a given number x if and only if it satisfies the following condition: y2 = x.
Another way to express this is to say that the number y has the same value as its own square. For example, the square roots of 16 are 4 and -4, since 42 divided by 2 is 16.
In conclusion,
√6 is not -4
because
√6 =2.449
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The equation P=3s represents the perimeter P of an equilateral triangle with side length s. is there a proportional relationship between the perimeter and the side length of an equilateral triangle? Explain.
The constant of proportionality (K ) we will write
Perimeter = 3 ( side) where K = 3
Perimeter of any polygon is defined as the sum of all sides of polygon.
Given polygon is a triangle. A triangle is any polygon which has three sides.
And as the sides of a polygon increases the perimeter also increases.
One can say that perimeter and side of a polygon has a direct relationship.
That is when we write it mathematically we write it like:
Perimeter ( P ) ∝ Sides of polygon
However given is an equilateral triangle
this means that all sides of the triangle are equal
so let us consider the side of the triangle as "s"
Thus we get that perimeter will be 3 times s
which when mathematically written will be:
Perimeter ∝ ( side)
to remove the constant of proportionality (K ) we will write
Perimeter = 3 ( side) where K = 3
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20 POINTS What are the lengths of the major and minor axes of the ellipse?
(x−3)212+(y+4)224=1
Drag a value to the boxes to correctly complete the table.
Put responses in the correct input to answer the question. Select a response, navigate to the desired input and insert the response. Responses can be selected and inserted using the space bar, enter key, left mouse button or touchpad. Responses can also be moved by dragging with a mouse.
Length of major axis Length of minor axis
The lengths of the axes in the elipse are given as follows:
Major axes: [tex]8\sqrt{14}[/tex].Minor axes: [tex]4\sqrt{53}[/tex].Equation of an elipseThe equation of an elipse of center (x*, y*) is given according to the following rule:
(x - x*)²/a² + (y - y*)²/b² = 1.
The lengths of the axes are given as follows:
Major axes: 2 x greater of a or b.Minor axes: 2 x lesser of a or b.In this problem, the equation of the elipse is given as follows:
(x - 3)²/212 + (y + 4)²/224 = 1.
Hence the measures of a and b are calculated as follows:
Measure of a: a² = 212 -> a = sqrt(212) -> a = 2sqrt(53).Measure of a: b² = 224 -> b = sqrt(224) -> b = 4sqrt(14).Hence the lengths of the axes have numeric values given by:
Major axes: 2 x 4sqrt(14) = 8sqrt(14) = [tex]8\sqrt{14}[/tex].Minor axes: 2 x 2sqrt(53) = 4sqrt(53) = [tex]4\sqrt{53}[/tex].The difference in the measures is because I suppose there was a typo in the equation of the ellipse, but the procedure is as presented in this problem.
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