n op‐amp‐based inverting integrator (basic type, with no feedback resistor) is measured at 10 khz to have a voltage gain of ‐200 v/v. at what frequency is its gain reduced to ‐2 v/v? what is the integrator time constant?

A performance (HC) curve for a given centrifugal pump shows that option B. Flow rate decreases as the head required to overcome system resistance increases.

The Centrifugal pump curves are helpful because they display metrics for the performance of the pump based on the head (pressure) the pump produces and the water flow through the pump. Impeller diameter, head, as well as the pump speed all affect flow rates.

Note that an instrument that predicts a pump's head and flow performance is a centrifugal pump performance curve. Pumps provide low volume flow rates when pumping against high-pressure heads and high volume flow rates if they are said to be pumping against low-pressure heads.

Therefore, one can say that every centrifugal pump has a curve that it follows in order to function, and every curve has a start point (the shut-off or zero flow) and an end point (the end-of-curve or the maximum flow that can be achieved without overtaxing the motor).

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A steam nozzle is a channel or duct with a cross-sectional area that varies gradually and is used to transform the heat energy of steam into kinetic energy. The nozzle's shape is created to convert energy with the least amount of loss possible.

Steam loses both pressure and heat as it travels through the nozzle. The Rankine area is equal to the work completed, which is equal to the adiabatic heat decrease. Steam passing through nozzles can be thought of as expanding adiabatically. The gas's speed rises to supersonic (Mach number >1) as it travels through the diverging nozzle. If the flow is sonic at the throat, the flow rate is at its highest for the particular nozzle.

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The rate of cooled water flow in lbm/hr is 244100 lbm/hr.

We need to know about the mass rate to solve this problem. The rate of cooled water will be the same as the rate of water enters the tower minus by the wet water releasing to the air.

m' cooled water = m'water - m'released

From the question above, the given parameters are

m' water = 250000 lbm/hr

m'dry air = 151000 lbm/hr

m' wet air = 156900 lbm/hr

Find the rate of water released to the air

m'released = m'wet air - m'dryair

m'released = 156900 - 151000

m' released = 5900 lbm/hr

Calculate the rate of cooled water flow

m' cooled water = m'water - m'released

m' cooled water = 250000 - 5900

m' cooled water = 244100 lbm/hr

Hence, the rate of cooled water flow in lbm/hr is 244100 lbm/hr.

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What the question wants is to write a code that would find and display the average of two numbers given by a user.

The code or program has been written and has been given below in C + +

#include <iostream>

using namespace std;

int main() {

   int a, b, sum;

   double avg;

   cout << "Enter the first integer number: ";

   cin >> a;

   cout << "Enter the second integer number: ";

   cin >> b;

   sum = a + b;

   avg = (double)sum / 2;

   cout << "\nThe average of your numbers is: " << avg << "\n";

   return 0;

}

Enter the first integer number: 2

Enter the second integer number: 4

The average of your numbers is: 3

A simple explanation of the code is that it makes use of mathematical operators to perform the calculations by first adding up the numbers and then finding the average of the two numbers by dividing the sum of the numbers with two which is the number of elements.

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The major advantage of using compound joint snips over a single joint tool is option B: you can begin the cut with a file.

Standard compound-action snips are known to be a form of a hand tool that is said to be made to cut steel or softer materials, yet it is not harmful to use them sometimes on stainless steel.

Note that the key or the  major merit or benefit of using compound joint snips than the use of a single joint tool is due to the fact that a person can be able to use it to cut a lot of steel.

Hence, option B is correct.

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The line to line voltage is 4160. The real power loss is 12 Kva , the reactive power loss is 81 Kvar. The total real power supplies is 540 kVa. The total reactive power supplied at the end of line is  (540 + 477j)

The first calculation is the  per phase line to node voltage.

= 2200√3 / √3

= 2200 V

Next is three-phase complex power absorbed by load 1

560 x 10³ ∠cos-1(0.707)

= 560 x 10³∠45

Then we would have

(396 + j396)kva

We have S2 = 132kva

next is the total complex load calculation

(396 + j396 + 132)kva

= 528 + j396 kva

= 660 ∠36.87 degrees kva

total current that is in the line

= 660 x 10³ ∠-36.87 / 3 x 2200

= 100 ∠ -36.87 degrees kva

Using the voltage law of Kirchoff

E1 = E2 + ZLI

= (2200 + 0.4 + j2.7)100 ∠ -36.87

= 2200 ∠0 + (2.73 ∠ 81.57)(100 ∠ -36.87)

=2401∠4.5 degrees

√3 x 2401

= 4160

b. Total real and reactive loss

= 3 x (.4 + 2.7j)(100 x100)

= 30x10^3)(.4 + 2.7j)

= 12 + 81 j

find the real power loss

p = 12 kw

total power loss is 12 kw

The reactive power loss is 81 Kvar

c. total 3 phase power

2401.7∠4.58 and 100∠36.87

= 3(2401.7∠4.58  x  100∠36.87)

= (540 + 477j)

the total real power is 540 kW

The total complex power of load and line

(396 + j396)kva + 132 + (12 + 81j)

= (540 + 477j)

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The maximum positive moment at c is 135k/ft

the maximum positive vertical reaction at b is 27k

Part a

Maximum positive moment at c

For maximum positive moment at C and as per Muller's principle, ILD influence line will be on moment at с, this is calculated using the equation below:

Maximum positive moment at c = [tex](\frac{1}{2} *20*5*(0.4+0.5) )+(5*8)[/tex]

                                                    = 135k.ft

Part b

Maximum positive vertical reaction at b

To find this using Muller's principle, we keep dead load throughout the span and consequently keep point load at B

Maximum positive vertical reaction at b = [tex](\frac{1}{2} *20*1*(0.4+1.5))+(1*8)[/tex]

                                                                 = 27k

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The option that  applies to using a hacksaw is option D. don't apply pressure on the forward stroke.

The hacksaw blade is one that  should be installed with the teeth facing forward. The blade of the saw will cut when it is pushed (the forward stroke) as opposed to when it is pulled.

Note that Certain blades feature an arrow that helps to show or indicates the proper placement.

Note that when using a Hacksaw, the cutting action is said to be one that occur on the forward stroke, so a person should not place pressure when they are pulling the saw towards them.

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Calculating the carbon footprint is difficult because of a lack of knowledge of all the factors of carbon emission on land.

Imagine drinking concentrated orange juice endlessly. because surely this is the best way to lose weight. Orange juice is recommended in moderation, but doctors are not the first to recommend it to people trying to lose weight.

Just as we don't want people to believe that more orange juice is the solution to the obesity pandemic, we don't want people to believe that the best way to fight climate change is to recycle more.

Recycling and blackouts are great steps towards a more sustainable society, but nothing is more important to the climate than reducing meat consumption, air travel, and driving.

People with good intentions often make the wrong decisions when it comes to reducing their carbon footprint.

For example, a test was conducted in which participants were selected and then the participants were then presented with 15 behaviors and asked to classify the behavior as low, medium, or high (with low representing less than 1% of a person's carbon footprint and high representing more than 5%).

Passenger car behavior is rightly regarded as critical in reducing greenhouse gas emissions.

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The reasons why it is hard to accurately determine the amount of carbon released from terrestrial ecosystems is that they are linked to sensitivity analysis and bias brought about by satellite data gap filling.

Additionally, the algorithms used for remote sensing do not effectively take into consideration environmental pressures such rooting depth, particularly in dry locations where plants depend on deep roots to access and maintain water availability.

The timing and size of terrestrial NPP are controlled by a variety of environmental factors on a global scale, such as climate, topography, as well as soils, plant and other forms of microbial characteristics, etc.

However, the relative contributions of these environmental factors to global NPP change over time and space. Globally, climatic change, including variations in temperature and precipitation, had a marginally favorable effect on NPP between 1982 - 1999.

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When refrigerant-134a is used, the refrigerant mass flow rate is 0.0952kg/s, and the compressor power requirement is 1.659kw

Part a

Refrigerant mass flow rate:

From the steam table refrigerant-134a, we have the following variables:

[tex]h_{1}[/tex] = 252kj/kg

[tex]h_{2}[/tex] = 270.43kj/kg

[tex]h_{3} = h_{4} = 95.47kj/kg[/tex]

Cooling load = 15kw

Now, refrigerator mass flow rate (m)= [tex]\frac{cooling load}{h_{1} -h_{4} }[/tex]

                                                       = [tex]\frac{15}{253-95.47}[/tex]

                                                       =0.0952kg/s

Part b

Compressor power requirement ([tex]W_{c}[/tex])

                                                  = [tex]m(h_{2} -h_{1} )[/tex] , where m is 0.0952kg/s

                                                  =0.0952(270.43-253)

                                                  =1.659kw

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The steps that should be taken to evaluate the team member's level of competence are:

The method that I will use to resolve this problem if you somehow didn't receive the desired expertise is to ask a person from my team to teach me how to do it as well as consult external people or the internet.

Long used as a framework, competencies help direct employees' behavior toward the issues that are most important to an organization and contribute to success.

Therefore, They can offer a standard method to coordinate, pick out, and nurture talent. For workers, as well as managers, and ultimately the organization, the advantages are obvious.

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The location at which a fuse should be installed in the 120 V, 20 A, residential circuit is in the live wire on the circuit, not in the neutral wire. The correct option is therefore;

A. A fuse should never be installed in the neutral.

The function of an electric fuse, which is a safety device, is to provide protection from an over flow of current in the circuit.

Generally, an electric fuse consists of a metal wire or filament that melts, due to its rise in temperature when excessive current or current at an unsafe level flows in the circuit, thereby opening the circuit, to protect the circuit and its components.

The effect of excessive or over current in a circuit is that it causes the circuit component to heat up and burn, such that the circuit and device stops functioning, and in some cases, may cause a fire.

The fuse, which is a circuit safety device, should be the first contact of the current.

Therefore;

The fuse should not be installed on the neutral wire, gives that the burning of the fuse in the neutral, in the event of an over current, leaves the high current in the circuit, which can cause unwanted damage to the circuit.

The correct option is therefore option A;

A. A fuse should never be installed in the neutral

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A non-rotating solid round bar with diameter of 2-in has a groove cut to a diameter of 1.8-in, with a groove radius of 0.1-in. the bar is loaded with a repeated bending load that causes the bending moment at the groove to fluctuate between 0 and 25000 lbf-in. the bar is hot-rolled aisi 1095, but the groove has been machined. The factor of safety guarding against first-cycle yielding will be nf=1.11 and the factor of safety against fatigue failure will be ny=2.41.

From the table A-20 Deterministic ASTM minimum tensile and yield strengths for HR and CD steels, we have approximately:

D= 2.1, d (diameter) = 1.892, r= 0.117

Endurance limit for the material= Se'= 60 kpsi

According to the goodman relation= nf= 0.833

Yielding factor of safety: ny= Sy/σmax= 66/36.828

ny= 1.792

When the factor of safety is 1, the substance is practically at yield. Based on the greatest anticipated load situation, the majority of designers aim for a safety factor of between 2 and 4. Unless the maximum expected load is repeatedly applied, if some design elements experience yield, part failure is not necessarily the result.

The element of safety with regard to a fatigue failure at a specific design life is known as the fatigue safety factor. The Factor of Safety can go up to 15. Values less than one for the Fatigue Safety Factor imply failure before the design life is achieved.

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Under normal relief conditions, where 10% accumulation is used, the permitted pressure drop in discharge pipe from the safety valve in vapor service is 10% of the set pressure, and under emergency fire conditions, where 20% accumulation is used, it is 20% of the set pressure

When calculating the size of the outlet piping, these influences must be considered since the pressure drop in the outlet piping affects the set pressure of a conventional safety relief valve and also affects the capacity of both a conventional and a bellows relief valve. If a pressure drop considerably impacts the set pressure or capacity of the relief valve, the discharge pipe from safety valves in liquid service must be raised. It cannot be smaller than the outlet connection on the safety valve.

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The compressor's efficiency must be taken into account; it is equivalent to 0.72, resulting in a needed power of 156*0.72 = 216.8 kW.

The compressor motor nameplate on the majority of industrial three phase air compressors will indicate the line voltage, which is commonly 240 V or 480 V. In our experience, the power factor of 50 to 150 horsepower compressors is approximately 85% when operating normally1. The amount of air the device can pump out is known as the compressor capacity. Compressor capacity and pressure may be easily distinguished from one another since the former reveals "how much" and the latter measures "how strong." the proportion between the maximum compressor load and the average compressor load for a given time period.

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If Enzo’s balance sheet for the month of July is has both assets and liabilities. The expression that will finds Enzo’s net worth is: A. 127,100 dollars minus 88,500 dollars .

Net worth can be determine by deducting the assets of a company by its liabilities which in turn implies that a company or an organization will tend to known their net worth after deducting their financial obligation (debt) from their assets .

Using this formula to find the net worth

Net worth = Assets -Liabilities

Where :

Assets = $127,100

Liabilities = $88,500

Let plug in the formula

Net worth = $127,100 -$88,500

Net worth = $38,600

Hence,

127,100 dollars minus 88,500 dollars .

= $38,600

Therefore the company would have to record their net worth in the amount of $36,800 making option A  the correct option because assets minus the liabilities would give us $36,800.

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The reason that makes it is difficult to accurately quantify the quantum of carbon released from terrestrial ecosystems  are linked with Sensitivity analysis as well as bias made by gap filling of satellite data.

In its ground state, the six electrons of carbon (atomic number 6) in the second row of the periodic table occupy two of its primary energy levels, giving the highest-energy electron a principal quantum number n of 2.

Therefore, note that the act of  carrying out Sensitivity analysis  is a factor that has hindered the knowledge about the amount of release of carbon in the atmosphere.

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An estimate of the safety factor of the shaft is 1.10

We have the following:

Torque=230nm

Diameter=25mm

Yield tension=160mpa

Yield compression=170mpa

To estimate the safety factor of the shaft, we will have to find first the following:

Maximum shear stress:

Shear stress=[tex]\frac{16T}{\pi d^{3} }[/tex]

                   =    [tex]\frac{16*230}{\pi *(25mm*\frac{10^{-3}m }{1mm})^{3} }[/tex]

                   =75MPa

We, now get the principle stress:

σ[tex]_{1}[/tex]=75MPa

σ[tex]_{2}[/tex]=-75MPa

The torsional yield strength:

Torsional yield strength=(yield strength in tension*yield strength in compression)/(yield strength in tension +yield strength in compression)

                                   =(160*170)/(160+170)

                                  =82.4MPa

Now, we can calculate the factor of safety using this given relation:

Factor of safety=(Torsional yield strength/Maximum shear stress)

                         =82.4MPa/75MPa

                         =1.0987

                         =1.10

Safety factor of the shaft, n=1.10

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A function named reverse that accepts a dictionary from integers to strings as a parameter and returns a new dictionary of strings to integers that is the original's "reverse" is given below:

# Function to create an empty stack. It

# initializes size of stack as 0

def createStack():

   stack = []

   return stack

# Function to determine the size of the stack

def size(stack):

   return len(stack)

# Stack is empty if the size is 0

def isEmpty(stack):

   if size(stack) == 0:

       return true

# Function to add an item to stack . It

# increases size by 1

def push(stack, item):

  stack.append(item)

# Function to remove an item from stack.

# It decreases size by 1

def pop(stack):

   if isEmpty(stack):

       return

   return stack.pop()

# A stack based function to reverse a string

def reverse(string):

   n = len(string)

   # Create a empty stack

   stack = createStack()

   # Push all characters of string to stack

   for i in range(0, n, 1):

       push(stack, string[i])

   # Making the string empty since all

   # characters are saved in stack

   string = ""

   # Pop all characters of string and put

   # them back to string

   for i in range(0, n, 1):

       string += pop(stack)

   return string

# Driver code

s = "Geeksforgeeks"

print("The original string is : ", end="")

print(s)

print("The reversed string(using stack) is : ", end="")

print(reverse(s))

The original string is : Geeksforgeeks

The reversed string(using stack) is : skeegrofskeeG

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According to the Hall-Petch connection, by lowering grain size, we could make materials stronger than their own theoretical strength.

In fact, their strength rises with decreasing grain size until it reaches a peak at about 20–30 nm. The yield strength is further decreased when the grain size grows by annealing at higher temperatures, but further advancement in tensile elongation is constrained. Be aware that ductility increases slightly when grains are refined from 2 to 1 micrometers in the micrometer-grained scale. strength, ductility, and hardness. Nanocrystalline materials exhibit a significant increase in hardness and strength compared to their coarser-grained counterparts as a result of Hall-Petch strengthening (increase in hardness associated with a reduction in average grain size).

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The load choices that are available in the question are:

a. The 6.8 Zener diode

what is required would be 3 zener diodes. These would be able to provide 3 x 6.8 = 20. 4 output

The resistance would be 3 x 10 ohms = 30 Ohms.

The requirement here would be 4 zener diodes. This would have to provide 4 x 5.1 = 20.4 volts of output.

The resistance that it would have to give would be 4 x 25 = 100 ohms of resistance.

Therefore from the calculations that we have above we would have to conclude that the load regulation that is here without R would be

30 ohms for the case of a , while it would have to be 100 ohms for the case of b.

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Answer:

9 1/2

Explanation:

3 4/5 is 3.8

2/5 is 0.4

divide 3.8 by 0.4 you get 9.5 which is 9 1/2 in a fraction

Answer:

(adjective)

produced by the internal heat of the earth.

{thermal means heat}

When technician a says it is important that a full battery test series be done before trying to test the starter system, and technician b says the internal condition of the engine has little effect on the operation of the starting system, then only technician a is correct.

Ideally, before testing the starter system, full battery test series is to be completed. The reason for this is that both the performance of starter and battery system is so closely related.

And it should also be replaced if it fails the load test. The operation of the starting system will be influenced by the internal condition of the engine.

Therefore, technician a is right.

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The average velocity (in m/s) of the oil in the pipe is 2.04m/s.

It should be noted that from the information, the oil that is transported on a day = 500000 bbl. Based on the information given, this is equal to 79491.256 cubic meter.

It should be noted that the flow rate will be calculated as:

= Oil transported / Time taken

= 79491.256 / (24 × 60 × 60)

= 0.92m³ per second

It should be noted that the area will be calculated as:

A = πr²

where

π = 3.14

r = radius = Diameter / 2 = 0.76/2 = 0.38

Area = πr² = 3.14 × (0.34)² = 0.45m²

Now, the velocity will be calculated thus:

= Flow rate / Area

= 0.92 / 0.45

= 2.04m/s

In conclusion, the velocity is 2.04m/s.

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In basic spatial layout of a residential building, arrows can be added to show traffic patterns and the direction of the arrows corresponds to the volume of traffic.

Road markings known as "sharrows" or "shared lane markings" (SLMs) are used to designate a shared lane environment for cars and cyclists. Along with other advantages, shared lane markings support the validity of bicycle traffic on the roadway, advise optimal posture for cyclists, and can be set up to provide directional and navigational information. The shared lane marking is a pavement marking that can be used for a number of different purposes to support a full network of bikeways; it is not a facility type and should not be used in place of bike lanes, cycle tracks, or other separation treatments when such facilities are otherwise necessary or feasible.

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The diameter d of shaft is 0.319m

The actual maximum shear stress of the shaft is 44.95N/m^2

The angle of twist of the 3-m length shaft is 0.01409 rad

The question is incomplete, here is the complete question:

A solid steel shaft 3 m long is transmitting 12 MW at 400 rev/min. The working conditions

to be satisfied by the shaft are:

• The shaft must not twist more than 0.015 radian on a length of 10 times the diameter, i.e., 10D

• The maximum shear stress must not exceed 70 MN/m2.

If the modulus of rigidity of steel is 60 GN/m2 determine:

(a) The diameter of the shaft required

(b) The actual maximum shear stress and the angle of twist of the 3-m length shaft.

Part a

The diameter of the shaft

We use Torque equation to find diameter d:

[tex]\frac{T}{J} =\frac{G\theta }{L}[/tex]

[tex]\frac{12*10^{6}*60 }{25600d^{4} } =\frac{60*10^{9}*0.015 }{10d}[/tex]

[tex]d^{3} =0.032414[/tex]

d=0.319m

Hence, diameter of shaft d=0.319m

Part b

Actual maximum shear stress Y, and the angle of twist of the 3m length shaft

[tex]Y=\frac{16T}{\pi d^{3} }[/tex]

[tex]Y=\frac{16*286478.90}{\pi *0.319^{3} }[/tex]

[tex]Y=44.95N/m^{2}[/tex]

Angle of the twist

Let angle of twist =  [tex]\theta[/tex]

[tex]\theta=\frac{TL}{GJ}[/tex]

  [tex]=\frac{286478.90*3}{60*10^{9}(\frac{\pi }{32}(0.019)^{9} }[/tex]

 =0.01409rad

Angle of twist=0.01409 rad

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