Based on the information given, it can be deduced that the initial cost will be $187 and the hourly rate is $72 per hour.
From the information given, the initial cost is $187. The cost for 2 hours is $259 and the cost for 3 hours is $331.
Therefore, the rate per hour will be:
= $259 - $187 = $72
The equation will then be:
= 187 + 72h
Lastly, the difference in the costs is $72.
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Write five demicals that round to 0.96?
Answer:
0.964
0.959
0.961
0.958
0.963
Step-by-step explanation:
Anything below 5 can be rounded down, anything above 5 can be rounded up.
You can have a decimal after 0.96 to be less than 5, or a decimal after 0.95 to be greater than 5.
Here's some I picked:
0.964
0.959
0.961
0.958
0.963
Jose and Gavin are reading the same book. At the beginning of the month, Jose was
on page 10 and Gavin was on page 37. Jose will read 17 pages per day and Gavin will
read 14 pages per day. Let J represent the page of the book that Jose is on at the end
oft days into the month, and let G represent the page of the book that Gavin is on at
the end oft days into the month. Write an equation for each situation, in terms of t,
and determine what page Jose and Gavin will be on on the day they are both on the
same page.
Using linear functions, it is found that:
Jose's equation is: [tex]J = 17x + 10[/tex].Gavin's equation is: [tex]G = 14x + 37[/tex].They will be on the same page on the 9th day.Linear function:A linear function is modeled by:
[tex]y = mx + b[/tex]
In which:
m is the slope, which is the rate of change.b is the y-intercept, which is the value of y when x = 0.Jose:
Initially, he was on page 10, hence [tex]b = 10[/tex].He reads 17 pages per day, hence [tex]m = 17[/tex].Hence, Jose's equation is: [tex]J = 17x + 10[/tex].Gavin:
Initially, he was on page 37, hence [tex]b = 37[/tex].He reads 14 pages per day, hence [tex]m = 14[/tex].Hence, Gavin's equation is: [tex]G = 14x + 37[/tex].The day they will both be on the same page is x for which:
[tex]J = G[/tex]
Hence:
[tex]17x + 10 = 14x + 37[/tex]
[tex]3x = 27[/tex]
[tex]x = \frac{27}{3}[/tex]
[tex]x = 9[/tex]
They will be on the same page on the 9th day.
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?/5 =8/10 type the missing number that makes this fraction equal
Answer:
[tex]?=4[/tex]
Step-by-step explanation:
[tex]\frac{?}{5}=\frac{8}{10}[/tex]
[tex]\frac{2?}{10}=\frac{8}{10}[/tex]
[tex]2?=8[/tex]
[tex]?=4[/tex]
(100 points will award brainliest)
In the image below, the m
Answer: 67°.
Step-by-step explanation:
1) m∠PMR=m∠LMN=3x+19°;
2) m∠LMN+m∠LMP=180°, it can be written as 3x+19+9x-31=180;
3) if to solve the equation 3x+19+9x-31=180, then x=16;
4) m∠PMR=3x+19=48+19=67°.
solve for x. 2/x-3=x/12-4x
Answer:
x= 47 18+2 201 i ≈0.382978723+0.603295612i x= 47 −2 201 i+18 ≈0.382978723−0.603295612i Hopefully this makes just the same amount of sense as this question
The perimeter of a rectangle is 39.2 km, and its diagonal length is 14 km.
Find its length and width
Using the formulas to find its length =
P= 2 ( l + w )
d= w² + l²
There are 2 solutions for,
l = P / 4 + 1 / 4 √8d² - p²
= 39.2 / 4 + 1 / 4 × √8 × 14² - 39²
= 11. 2 km answer.
Using the formula to find its width =
w = p / 2 - l
= 39.2 / 2 - 11.2
= 8.4 km answer.
≈ the length of a rectangle is 11.2 km and the width is 8.4 km
fnd the highest common factor of -8xy and 20y
Answer:
[tex]\huge\boxed{\boxed{2}\cdot\boxed{2}\cdot\boxed{y}=4y}[/tex]
Step-by-step explanation:
[tex]-8y=-2\cdot\boxed{2}\cdot\boxed{2}\cdot \boxed{y}\\\\20y=\boxed{2}\cdot\boxed{2}\cdot5\cdot\boxed{y}[/tex]
Is 6.32332333... a rational or irrational number? a Choose the correct answer below. O rational number O irrational number
Answer:
Irrational number because it cannot be written in fraction form a/b where b is not supposed to be 0
which inequality matches the graph?
A. x>4
B. x<4
C. x=4
D. x >4
Answer:
B
Step-by-step explanation:
The line goes left which means its going to be less than 4.
Answer:
[B] x < 4
Step-by-step explanation:
First you must know the following:
> ⇒ greater than
< ⇒ less than
≥ ⇒ greater than or equal to
≤ ⇒ less than or equal to
= ⇒ equal
When going to the left it means less than
Thus, we can conclude that
x < 4
Kavinsky
Quantity is proportional of 40/8
HELP ILL MARK BRAINLIEST ANSWER THIS QUESTION IN THE PIC
Mrs. Baca uses a phone card to call a relative in Colombia, It cost her 45 cents to talk for 15 minutes. Choose True or False for each statement.
A. For 45 cents, Mrs. Baca can talk for 3 minutes. True or False.
B. The call rate is 3 cents per minute. True or False.
C. The call rate can represent by the ratio 445:15. True or False.
D. Divide 75 by 15 to find the number of minutes Mrs. Baca can talk. True or False.
Answer:
A: False
B: True
C: False
D: False
Hope This Helps!!!
factorise
18p+6
please im so bad
What is the domain of the absolute value function below?
(will give brainless)!!!!
Answer:
D <----last option Domain is set of real numbers or (-∞,+∞)
Use the order of operations to simplify 4(3.5 - 1.5) - 1/2.
a. 19 1/2
b. 7 1/2
c. 12
d. -4
[tex]\huge\textbf{Hey there!}[/tex]
[tex]\mathbf{4(3.5 - 1.5) - \dfrac{1}{2}}\\\\\mathbf{\rightarrow 4(2) - \dfrac{1}{2}}\\\\\mathbf{\rightarrow 8 - \dfrac{1}{2}}\\\\\mathbf{\rightarrow \dfrac{15}{2} \approx 7.5 \approx \boxed{\bf 7 \dfrac{1}{2}}}\\\\\\\\\huge\boxed{\textbf{Therefore, your answer is: \boxed{\mathsf{Option \ B. \ 7 \dfrac{1}{2}}}}}\huge\checkmark[/tex]
[tex]\huge\textbf{Good luck on your assignment \& enjoy}\\\huge\textbf{your day!}[/tex]
~[tex]\frak{\bf Amphitrite1040:)}[/tex][tex]\huge \bf {Question}:—[/tex]
[tex] \boxed{\bf \: 4(3.5 - 1.5) - 1/2}[/tex]
[tex]\bf\huge Solution:—[/tex]
[tex] \sf \longmapsto \: 4*(3.5-1.5)-1/2[/tex]
[tex] \boxed{\bf \: Convert \: 1/2 \: i nto \: Decimal:—}[/tex]
[tex]\sf \longmapsto \: 4*(3.5-1.5)-0.5[/tex]
[tex] \boxed{\bf \: Subtract \: 3.5-1.5 :—\: (2 \: is \: the \: result)}[/tex]
[tex]\sf \longmapsto \: 4*(2) - 0.5[/tex]
[tex] \boxed{\bf Multiply \: 4 \: and \: 2:—(8 \: is \: the \: result)}[/tex]
[tex]\sf \longmapsto8-0.5[/tex]
[tex] \boxed{\bf \: Simply \: Subtract:—}[/tex]
[tex]\sf \longmapsto7.5[/tex]
[tex]\boxed{\bf Convert \: to \: Fraction, \: And \: Fraction\:to\:Mixed \:Fraction:—}[/tex]
[tex]\sf\longmapsto 15/2[/tex]
[tex] \boxed{\bf \: Mixed \: Fraction:—}[/tex]
[tex]\boxed{\sf\longmapsto 7 \dfrac{1}{2} }[/tex]
________________________________
[tex]\boxed{\bf Solving \: in \: another \: way:—}[/tex]
[tex]\sf \longmapsto4*2-1/2[/tex]
[tex]\sf \longmapsto4*(2)-1/2[/tex]
[tex]\sf \longmapsto8-1/2[/tex]
[tex]\sf \longmapsto \: 15/2[/tex]
[tex] \boxed{\bf \: Mixed \: Fraction:—}[/tex]
[tex]\boxed{\sf \longmapsto \: 7 \dfrac{1}{2} }[/tex]
________________________________
[tex] \boxed{\bf \: \: Answer \: i s \: Option \: B}[/tex]
[tex] \boxed{\huge\sf \: (B) \: \bf \: 7\dfrac{1}{2}} [/tex]
V is themidpoint of UW. If UV = x + 8 and VW = 9x, what is VW?
Answer:
x=1
Step-by-step explanation:
If V is the midpoint of the line UW, that would mean that there's an equal distance between UV and 9x. So, the value of UV and VW would eed to be the same.
x+8=9x
8=8x
x=1
Helppppppppppppp helppppppppppppp
Answer:
Should be the first answer, x=5
Step-by-step explanation:
This would flip the graph and the square would land on top of where it currently is.
Solve the following compound inequality: 4 less-than-or-equal-to x + 4 less-than-or-equal-to 12. a. 0 less-than-or-equal-to x less-than-or-equal-to 8 c. 8 less-than-or-equal-to x less-than-or-equal-to 16 b. x less-than-or-equal-to 8 d. no solution Please select the best answer from the choices provided A B C D
Answer:
A. 0 <= x <= 8
Step-by-step explanation:
4 <= x + 4 <= 12
Remove 4 from all sides
4 - 4 <= x + 4 -4 <= 12 - 4
0 <= x <= 8
5. The combined perimeter of a circle and a square is 16. Find the dimensions of the circle and square
that produce a minimum total area.
The dimensions of the circle and square that produce a minimum total area are 1.12 and 2.24 respectively
Represent the side length of the square with s, and the radius of the circle with r.
So, the perimeter (P) and the area (A) of the shape are:
[tex]P =4s + 2\pi r[/tex]
[tex]A =s^2 + \pi r^2[/tex]
The perimeter is 16. So, we have:
[tex]4s + 2\pi r = 16[/tex]
Divide through by 4
[tex]s + 0.5\pi r = 4[/tex]
Make s the subject
[tex]s = 4 - 0.5\pi r[/tex]
Substitute [tex]s = 4 - 0.5\pi r[/tex] in [tex]A =s^2 + \pi r^2[/tex]
[tex]A = (4 - 0.5\pi r )^2 + \pi r^2[/tex]
Expand
[tex]A = 16 - 4\pi r + 0.25(\pi r)^2 + \pi r^2[/tex]
This gives
[tex]A = 16 - 4\pi r + (0.25\pi^2 + \pi )r^2[/tex]
Differentiate with respect to r
[tex]A' = 0 - 4\pi + 2(0.25\pi^2 + \pi )r[/tex]
[tex]A' = - 4\pi + 2(0.25\pi^2 + \pi )r[/tex]
Set to 0
[tex]- 4\pi + 2(0.25\pi^2 + \pi )r =0[/tex]
Add 4pi to both sides
[tex]2(0.25\pi^2 + \pi )r =4\pi[/tex]
Divide both sides by 2
[tex](0.25\pi^2 + \pi )r =2\pi[/tex]
Make r the subject
[tex]r =\frac{2\pi}{(0.25\pi^2 + \pi )}\\[/tex]
Factor out pi
[tex]r =\frac{2\pi}{\pi(0.25\pi + 1 )}[/tex]
Cancel out the common factors
[tex]r =\frac{2}{0.25\pi + 1 }[/tex]
Express pi as 3.14
[tex]r =\frac{2}{0.25\times 3.14 + 1 }[/tex]
[tex]r =\frac{2}{1.785}[/tex]
Divide
[tex]r =1.12[/tex]
Recall that:
[tex]s = 4 - 0.5\pi r[/tex]
This gives
[tex]s =4 -0.5 \times \pi \times 1.12[/tex]
This gives
[tex]s =4 -0.5 \times 3.14 \times 1.12[/tex]
[tex]s =2.24[/tex]
Hence, the dimensions of the circle and square that produce a minimum total area are 1.12 and 2.24 respectively
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Image attached giving 25 points please help
help me plsss! need help
Harry has $10 in his bank account, and he adds $2 every week. based on this information, which representation best shows the relationship between the amount of money harry has in his bank account ,y, and the number of weeks that have passed, x? (im testing....)
Answer:
y= (2x)+10
Step-by-step explanation:
if harry has an initial balance of $10 in his bank account, he will have something +10 for the initial 10.
If he adds $2 to his bank account every week, then the amount of money in his bank account (y) can be modeled by the equation
y = (2x)+10
where y represents how much money he has in his bank account and x represents the amount of weeks he is adding $2.
Which of the equations will be a true statement if p = 10 3 ? Select the two choices that apply.
A. 3.4 ÷ p = 0.034
B. 437 ÷ p = 0.437
C. 53.45 ÷ p = 53.45
D. 6,340 ÷ p = 6.34
E. 2,458.2 ÷ p = 24.582
Answer:A
Step-by-step explanation: make me brainlist if correct
A linear function and an exponential function are shown below.
Over which interval does the growth rate of the exponential function exceed the growth rate of the linear function?
Answer:
x >2
Step-by-step explanation:
*The exponential function gets steeper when x is greater than 2
Answer:
D. x>2 is the answer got it right
Evaluate.
(jk−1)÷j when j=−4 and k=−0.7
Enter your answer as a decimal in the box.
Answer:
(jk - 1) / j
jk = (-4 x -0.7) = 2.8
(2.8 - 1) / - 4
1.8 / -4 = -0.45
Answer is -0.45 when j = -4 and k = -0.7
A hybrid car can go 400 miles on 8 gallons of gas. How far can the car take you with 1 gallon of gas?
Answer:
50 miles
Step-by-step explanation:
Take the number of miles and divide by the number of gallons
400 miles / 8 gallons
50 miles per gallon
Answer:
50 miles
Step-by-step explanation:
if for each 8 gallons it can go to 400 miles
so the 8 will be divided to 8 and get 1
and also divide the 400 into 8 you will get 50 miles per 1 gallon
For the following equation, find a solution for the variable. Show all of your work and use complete sentences to explain the solving process that you used to find a solution for the equation. Be sure to include at least two terms from the word bank. 4+ x = 7
Answer:
x=33
Step-by-step explanation:
you move the 4 to the other side
x=7-4
so
x=3
Answer:
x=3
Step-by-step explanation:
This should be easy.
4+x=7
-4 -4
x=7-4
x=3
Word explanation:
Here, we're solving for the variable x, first, we need to isolate x and therefore subtract 4 on both sides, 7 minus 4 is 3, so x is equal to 3.
i need help fast plz
Answer:
27/16
Step-by-step explanation:
[tex]12 \div \left(2 + \dfrac 23 \right)^2\\\\\\=12 \div \left(\dfrac 83 \right)^2\\\\\\=12 \div \dfrac{64}9\\\\\\=12 \times \dfrac{9}{64}\\\\\\= \dfrac{3 \times 9}{16}\\\\\\=\dfrac{27}{16}\\\\\\=1\dfrac{11}{16}[/tex]
What is the answer to the equation?
x+3x+3y+3z=21
Find the value of X.
Answer:
[tex] x = \frac{21 - 3y - 3z}{4} [/tex]Step-by-step explanation:
Question:-To find value of xEquation:-x + 3x + 3y + 3z = 21Solution:-=> x + 3x + 3y + 3z = 21
[On adding like terms x and 3x]=> 4x + 3y + 3z = 21
[On subtracting both sides with 3y]=> 4x + 3y + 3z - 3y = 21 - 3y
[On Simplification]=> 4x + 3z = 21 - 3y
[On subtracting both sides with 3z]=> 4x + 3z - 3z = 21 - 3y - 3z
[On Simplification]=> 4x = 21 - 3y - 3z
[On dividing both sides with 4][tex] = > \frac{4x}{4} = \frac{21 - 3y - 3z}{4} [/tex]
[On Simplification][tex] = > x = \frac{21 - 3y - 3z}{4} (ans)[/tex]
Given :
x + 3x + 3y + 3z = 21To Find :
The value of xSolution :
[tex]\qquad { \dashrightarrow \: { \sf{x + 3x + 3y + 3z = 21}}}[/tex]
Adding the like terms :
[tex]\qquad { \dashrightarrow \: { \sf{4x + 3y + 3z = 21}}}[/tex]
Transposing 3y to the other side which then becomes negative :
[tex]\qquad { \dashrightarrow \: { \sf{4x + 3z = 21 - 3y}}}[/tex]
Now, Transposing 3z to the other side which then becomes negative :
[tex]\qquad { \dashrightarrow \: { \sf{4x = 21 - 3y - 3z}}}[/tex]
Dividing both sides by 4 :
[tex]\qquad { \dashrightarrow \: { \sf{ \dfrac{4x}{4} = \dfrac{21 - 3y - 3z}{4} }}}[/tex]
[tex]\qquad { \dashrightarrow \: { \sf{{x} = \dfrac{21 - 3y - 3z}{4} }}}[/tex]
Therefore, the value of x = 21 – 3y – 3z/4