Answer:
stars will emit more light due to their Luminosity, so they look very bright.
Explanation:
Luminous refers to..,
The total amount of energy radiated by a star or other celestial object per second. Therefore it is the power output of a star.Most of the really bright stars in our sky are not that very close to us yet they look bright because of the Luminosity of the star.
These stars are intrinsically so luminous.
A star's power output across all wavelengths is called its bolometric luminosity.
A star with large luminosity will have more measure of radiated electromagnetic power meaning.
so it will emit more light than a low luminosity star.
Hence,
those stars can easily be seen even across great distance.
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How does the area of triangle rst compare to the area of triangle lmn? the area of △rst is 2 square units less than the area of △lmn. the area of △rst is equal to the area of △lmn. the area of △rst is 2 square units greater than the area of △lmn. the area of △rst is 4 square units greater than the area of △lmn.
The area of △rst is equal to the area of △lmn.
The answer is option B.
Problem-solving is the act of defining a problem; figuring out the purpose of the trouble; identifying, prioritizing, and selecting alternatives for an answer; and imposing an answer.
Problem-solving starts with identifying the issue. As an example, a trainer may need to parent out a way to improve a scholar's overall performance on a writing talent test. To do that, the instructor will overview the writing exams looking for regions for improvement.
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what is one standard kilogram
The Kilogram was for many years the only one of the seven SI base standards that was not defined in terms of a fundamental attribute of nature.
It was specified as the weight of a platinum-iridium cylinder stored in a lab outside of Paris under inert conditions.
The problem with that is that it needs to be managed in order to use such a standard for calibrating exact copies. No matter how meticulously you do it, surface molecules must experience some minimal impact.
Therefore, efforts have continued to find a replacement standard that is not a tangible thing. With the suggestion for a new Standard Kilogram utilizing a gadget called the Kibble Balance, it now seems that the quest is over.
Answer:
one standard kilogram is the mass of cylinder made up of platinum-iridum alloy with equal diameter and base kept Ar international bureau of weight and measures near paris
A toroid has a 4.63 cm square cross section, an inside radius of 15.0 cm, 527 turns of wire, and a current of 0.725 A. What is the magnetic flux through the cross section
Using the equation, B = (μoIN/2πr)
The inner radius is r = 16.2 cm,
so the field there is
B = (4π 10-7).(0.813).(535)/2π(0.162)
= 5.37 × 10-4 T
The outer radius is r = 16.2 + 5.2 = 21.4 cm.
The field there is B = (4π 10-7).(0.813).(535)/2π(0.214)
= 4.06 × 10-4 T.
A toroid having a square cross-section, 5.20cm on edge and an inner radius of 16.2cm has 535 turns and carries a current of 813mA to calculate the magnetic.
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A solid disk is rolling without slipping on a level surface at a constant speed of 2.50 m/s. (a) if the disk rolls up a 30.0o ramp, how far along the ramp will it move before it stops? (b) explain why your answer in part (a) does not depend on either the mass or the radius of the disk.
(a) By using the law of conservation of energy, the distance moved by the solid disk along the ramp is 0.96 m.
(b) The answer does not depend on the mass and radius of the disc as these values are canceled when the law of conservation of energy is applied.
What is the law of conservation of energy?
The law of conservation of energy states that the total energy of an isolated system is conserved.
The total initial energy Ei of the disc rolling down an inclined plane is given by the formula,
Ei=1/2*mv^2 + 1/2*Iω^2
where m is the mass of the disc, v is the velocity of the disc, I is the moment of inertia and ω is the angular velocity of the disc.
For a solid disc, I=1/2mr^2, and since it is rolling without slipping, the rolling velocity of the disc will be equal to its translational velocity, that is,
v=ωr or ω=v/r
So using ω=v/r and I=1/2mr^2, it can be written,
Ei=1/2*m(v)^2 + 1/2*(1/2mr^2)(v/r)^2
Ei=1/2*m(v)^2*(1+1/2*)
Ei=3/4*mv^2
If the height covered by the disc is h before stopping, then its final total energy Ef will be equal to the potential energy, that is,
Ef=m*g*h
From the law of conservation of energy, it can be written,
Ei=Ef
3/4*mv^2=m*g*h
h=3v^2/(4g)
The length of the ramp is then given by the formula,
l=hcosecθ
where θ is the inclination angle. So
l= 3v^2/(4g)*cosecθ
Here g=9.8 m/s^2, v=2.5 m/s and θ=30.0 degree. Using these values,
l= 3*(2.5 )^2/(4*9.8)*cosec( 30)
l= 0.96 m
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The work required to accelerate an object initially at rest to a speed v0 is W. What is the additional work needed to increase its speed from v0 to 2v0? Group of answer choices W W/2 2W 3W None of them
The additional work needed to increase its speed from v0 to 2v0 is D)3W.
Work done is equal to a change in kinetic energy
w = 1/2mv^2-0
= 1/2mv^2
When v is 2v
w new = 1/2*m*(2v)^2 - 1/2mv^2
= 4 * 1/2mv^2 - 1/2mv^2
=4w-w
=3w
Kinetic electricity is a shape of electricity that an item or a particle has with the aid of the purpose of its motion. If work, which transfers energy, is carried out on an object by applying an internet pressure, the item quickens and thereby profits kinetic strength.
Types of Kinetic Energy.
radiant, thermal, sound, electrical,mechanical.Kinetic energy (KE) is the energy of a frame in movement, because of this, it's essentially the power of all moving items. it's far one of the fundamental forms of power, together with capability energy, which is the saved electricity contained inside items for relaxation.
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The additional work needed to increase its speed from v0 to 2v0 is D)3W.
Work done is equal to a change in kinetic energy
w = 1/2mv^2-0
= 1/2mv^2
When v is 2v
w new = 1/2*m*(2v)^2 - 1/2mv^2
= 4 * 1/2mv^2 - 1/2mv^2
=4w-w
=3w
Kinetic electricity is a shape of electricity that an item or a particle has with the aid of the purpose of its motion. If work, which transfers energy, is carried out on an object by applying an internet pressure, the item quickens and thereby profits kinetic strength.
Types of Kinetic Energy.
radiant,thermal,sound,electrical,mechanical.Kinetic energy (KE) is the energy of a frame in movement, because of this, it's essentially the power of all moving items. it's far one of the fundamental forms of power, together with capability energy, which is the saved electricity contained inside items for relaxation.
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A gas cylinder contains only the gases radon, nitrogen, and helium. The radon has a pressure of 222 torr while the nitrogen has a pressure of 446 torr. If the total pressure inside the cylinder is 771 torr, what is the pressure that is due to the helium?.
Answer:
103 torr
Explanation:
The remainder is due to the helium
771 - 222 - 446 = 103 torr due to helium
A toy dart gun uses a spring with a spring constant of 35 N/m. To use the dart gun, you compress the spring by pushing in a dart of mass 0.002 kg.
a. If you compress the spring by 0.02 m, what force is the spring exerting on the dart?
b. With the spring compressed 0.02 m, how much elastic potential energy is stored in the spring?
c. If you release the spring, it pushes the dart forward. What is the kinetic energy of the dart when it reaches the natural length of the spring? Explain how you found the answer.
d. What is the speed of the dart when it reaches the natural length of the spring?
(a) The force is the spring exerting on the dart is 0.7 N.
(b) The elastic potential energy stored in the spring is 7 x 10⁻³J.
(c) The kinetic energy of the dart when it reaches the natural length of the spring is 7 x 10⁻³J.
(d) The speed of the dart when it reaches the natural length of the spring is 2.65 m/s.
Force the spring exerting on the dart
F = kx
where;
k is spring constantx is compression of the springF = 35 N/m x 0.02 m
F = 0.7 N
Energy stored in the springU = ¹/₂kx²
U = ¹/₂(35)(0.02)²
U = 7 x 10⁻³ J
Kinetic energy of the dartThe elastic potential energy of the spring will be converted into kinetic energy of the dart, with a magnitude of 7 x 10⁻³ J when it reaches natural length of the spring.
Speed of the dartK.E = ¹/₂mv²
v² = (2K.E)/m
where;
v is the speed of the dartm is mass of the dartv² = (2 x 7 x 10⁻³)/(0.002)
v² = 7
v = 2.65 m/s
Thus, the force is the spring exerting on the dart is 0.7 N.
The elastic potential energy stored in the spring is 7 x 10⁻³J.
The kinetic energy of the dart when it reaches the natural length of the spring is 7 x 10⁻³J.
The speed of the dart when it reaches the natural length of the spring is 2.65 m/s.
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What are two forces on earth that could change the motion of the object?
Answer:
Force makes things move or, more accurately, makes things change their motion. Two natural forces that we have experienced are the force of gravity and magnetic forces magnetic forces. These two forces act at a distance and do not require direct contact between the objects to function..
The speed that a tsunami can travel is modeled by the equation , where s is the speed in kilometers per hour and d is the average depth of the water in kilometers. What is the approximate depth of water for a tsunami traveling at 200 kilometers per hour?.
0.32 km
How to reach the answer:
The formula below provides the tsunami's speed in response to the query.
s = 356√d
when the tsunami's speed is 200 km/h, the equation's "s" is changed to "200," and the equation of speed is then expressed as follows.
200 = 356√d
The equation can be changed to compute the depth of the water as,
√d = 200÷356
√d = 0.562
Now on squaring both sides:
(√d)² = (0.562)²
d = (0.562)² = 0.316 or 0.32
Therefore the approximate depth of water for a tsunami travelling at 200km/h is 0.32 km
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True or false cells of humans and plants are same.
Please answer number 3!! High-speed stroboscopic photographs show that the head of a 0.2kg golf club is traveling
at 55 m/s just before it strikes a 0.046kg golf ball at rest on a tee. After the collision, the
golf club head travels (in the same direction) at 40 m/s. Find the speed of the golf ball
just after impact.
The velocity of the golf ball is 65.2 m/s
What is the principle of conservation of momentum?The principle of conservation of momentum is that the momentum before collision is equal to the momentum after collision.
Given that;
(0.2kg * 55 m/s) + (0.046kg * 0 m/s) = (0.2kg * 40 m/s) + (0.046kg * v)
11 = 8 + 0.046v
v = 11 - 8/0.046
v = 65.2 m/s
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7. Suppose a force of 15 N is required to stretch and hold a spring 0.25 m from its equilibrium position. a. Assuming the spring obeys Hooks law, find the spring constant k. b. How much work is required to compress the spring 0.2 m from its equilibrium position
Spring constant k = 75 N/m
Hooke's law for this spring F(x) = 75x
Work = 1.5 J
What is work?When an object is moved over a distance by an external force, at least a portion of that force must be applied in the direction of the displacement. This is known as work.The amount of work required to move an object down a line from point a to point b in the direction of a variable force F is[tex]$W=\int_{a}^{b} F(x) d x$[/tex]
First solutionAccording to Hooke's law, the spring must be held stretched at x=0.2m by a force of 15N.
F (0.2) = k (0.2 m) = 15 N
Solve for k
k = 75 N/m
Hence, Hooke's law is F(x) = 75x
Second solution
The spring is compressed from x = 0 to X = 0.2,
[tex]$W=\int_{0}^{0.2} 75 x d x=\left.\left(\frac{75 x^{2}}{2}\right)\right|_{0} ^{0.2}$[/tex]
W = 1.5 J
So, the work is required to compress the spring 0.2 m from its equilibrium position W = 1.5 J
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Which of the following graphs represents the equation y-2 = 3(x-1)?
Answer:
Graph b
Explanation:
I used Desmond calculator which is a calculator where you can graph an equation! :)
Hello!
The slope-intercept form is :
y - 2 = 3(x - 1)
y - 2 = 3x - 3
y = 3x - 1
Two points that are found to be on the line :
(0, -1) and (1, 2)
∴ The graph which contains both points is Graph B.
What is typically responsible for forming volcanic island chains in the oceans?
A. Shield volcanoes
B. Fissures
Composite volcanoes
Hot spot volcanism
Hot spot volcanism is responsible for the formation of volcanic island chains in the oceans and is denoted as option D.
What is a Volcano?This is a rupture in the earth crust thereby giving rise to the release of hot lava, gases etc from below the surface.
The pushing of the lava through the cracks partially melts the plate at a subduction zone thereby forming the volcanic island chains.
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How much horsepower is produced by 2023 z’s 3. 0-liter twin-turbo 6-cylinder engine?.
400 horsepower is produced by 2023 z's 3. 0-liter twin-turbo 6-cylinder engine.
What is horsepower?The power an engine produced is referred to as horsepower. In the British Imperial System, one horsepower equals 33,000 foot-pounds of work per minute, i.e., the force required to lift a mass of 33,000 pounds off the ground in a single motion for one minute.
The new Z's 3.0-liter twin-turbo V6 engine produces 400 horsepower and 350 pound-feet of torque. This is 68 horsepower and 80 lb-ft more than the previous 370Z. The 6-speed manual transmission that comes standard or the optional 9-speed automatic transmission with paddle shifters are both paired with this one engine option.
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A mass m is placed on an inclined plane (m > 0) and slides down the plane with constant speed. If a similar block (same m) of mass 2m were placed on the same incline, it would:
A mass m is placed on an inclined plane (m > 0) and slides down the plane with constant speed. If a similar block (same m) of mass 2m were placed on the same incline, it would
For 2m, the gravitational force pressing downward on the plane is twofold. However, the normal force is also doubled, and as a result, so is the friction force (the same factor). This indicates that the two forces continue to cancel and produce a net force of zero.Gravitational forceThe force that binds all masses in the universe together, particularly the pull of the earth's mass on objects that are close to its surface.The attracting force that the earth exerts on all other objects in the cosmos is known as gravitational force. A ball being flung high and then falling back to the earth as a result of gravitational force is an example of gravitational force.Learn more about gravitational force here:
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Use the graph to complete the sentences about two runners.
Runner A is
than runner B.
Runner
has a head start.
Runner A is faster than runner B and Runner B has a head start.
What is a velocity time graph?The velocity time graph shows us how fast that an object can be. The slope of the graph is the acceleration.
If we look at the graph as shown in the image attached to this answer, we can see that Runner A is faster than runner B and Runner B has a head start.
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Answer:
Runner A is
✔ faster
than runner B.
Runner
✔ B
has a head start.
Explanation:
Lexy used the formula shown to calculate the force of gravity on a space shuttle.
Fg = GStartFraction (3 times 10 Superscript 5 Baseline kilograms) (6 times 10 Superscript 24 Baseline kilograms) over [(6.4 times 10 Superscript 6 Baseline m) + (1.8 times 10 Superscript 5 Baseline m)] Superscript 2 EndFraction
What does 3 × 105 kg represent?
the difference between Earth’s mass and the space shuttle’s mass
the sum of Earth’s mass and the space shuttle’s mass
the mass of Earth
the mass of the space shuttle
What 3 × 105 kg represents is the mass of Earth. Option D. This is further explained below.
What does 3 × 105 kg represent?Generally, the absence of discernible form in a huge mass of material
In conclusion, Transportation between Earth and space is accomplished by means of the space shuttle.
It gets people to spaceships in orbit. The mass of the space shuttle is 3108 kg.
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Answer:
D
Explanation:
lamp 1 and lamp 2 are in a series circuit
lamp 1 stops working
explain why lamp 2 also stops working
Lamps 1 and 2 are connected in series. lamp 1 stops working because the circuit is not complete.
What is a series circuit?In a series circuit, the amount of current flowing through any component is the same and the sum of the individual resistances equals the overall resistance of any series circuit.
The voltage in a series circuit is equal to the total of the individual voltage drops.
For the bulb to glow the circuit should be complete. If the circuit is not completed the bulb will not glow.
Lamps 1 and 2 are connected in series. lamp 1 stops working because the circuit is not complete.
Hence, lamp 1 stops working.
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Suppose a car traveling at 8m/s is brought to rest in a distance of 20m.what is it's deceleration and time taken.
The deceleration is -8 m/s² and the time taken by the car is 2.5 s.
It is given that,
Speed, v = 8 m/s
Distance, d = 20m
We need to find the time taken by the car and deceleration.
As we know speed is defined as
v = d/t
Plugging in the values,
t = 20/8
t = 2.5s
Now from the deceleration formula,
a = - v/ t
a is the deceleration, v is the speed and t is the time taken.
a = - 20/ 2.5
a = - 8 m/s²
Thus, the time taken by the car and deceleration is 2.5 s and -8 m/s² respectively.
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The velocity of a 0.25kg model rocket changes from 15m/s [up] to 40m/s [up] in
0.60s. The gravitational field intensity is 9.8N/kg. Calculate the force the escaping
gas exerts of the rocket.
Since g is constant, the force the escaping gas exerts on the rocket will be 10.4 N
What is Escape Velocity ?This is the minimum velocity required for an object to just escape the gravitational influence of an astronomical body.
Given that the velocity of a 0.25kg model rocket changes from 15m/s [up] to 40m/s [up] in 0.60s. The gravitational field intensity is 9.8N/kg.
To calculate the force the escaping gas exerts of the rocket, let first highlight all the given parameters
Mass (m) of the rocket 0.25 KgInitial velocity u = 15 m/sFinal Velocity v = 40 m/sTime t = 0.6sGravitational field intensity g = 9.8N/kgThe force the gas exerts of the rocket = The force on the rocket
The rate change in momentum of the rocket = force applied
F = ma
F = m(v - u)/t
F = 0.25 x (40 - 15)/0.6
F = 0.25 x 41.667
F = 10.42 N
Since g is constant, the force the escaping gas exerts on the rocket is therefore 10.4 N approximately.
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A projectile is launched with a velocity of 13.2 m/s at an angle of 37.0° above the horizontal.
How high above the point from which it was fired will the projectile be 1.0 s after firing?
a.
3.0 m
b.
12.8 m
c.
5.6 m
d.
13.2 m
The height reached by the projectile from the point of projection is determined as 12.84 m.
Height reached by the projectileH = vt + ¹/₂gt²
where;
v is vertical velocityt is time of motiong is acceleration due to gravityH = (13.2 x sin37)(1) + (0.5)(9.8)(1)²
H = 12.84 m
Thus, the height reached by the projectile from the point of projection is determined as 12.84 m.
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A steady current flows through an inductor. If the current is doubled while the inductance remains constant, the amount of energy stored in the inductor:.
If the current is doubled while the inductance remains constant, the amount of energy stored in the inductor 2LI².
Energy stored in inductor
The amount of energy stored in the inductor is given as;
E = ¹/₂LI²
where;
L is inductance I is current in the inductorWhen the current doubles, the new energy stored in the inductor;
E = ¹/₂L(2I)²
E = ¹/₂L(4I²)
E = 2LI²
Thus, if the current is doubled while the inductance remains constant, the amount of energy stored in the inductor 2LI².
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A mass is undergoing simple harmonic motion. When its displacement is 0, it is at its equilibrium position. At that moment, its speed is _______ and its acceleration is _______.
Answer:
When X = 0
Speed = maximum V (max) = ω A
Acceleration = zero a(max) = - ω^2 A
From x = A sin ω t sin = 0 so displacement = zero
V = ω A cos ω t cos = 1 and speed = maximum
a = - A ω^2 sin ω t sin = 0 and acceleration = zero
A typical muscle fiber is 2.0 cm long and has a cross-section area of 3.1 * 10-9 m2. When the muscle fiber is stimulated, it pulls with a force of 1.2 mN. What is the work done by the muscle fiber as it contracts to a length of 1.6 cm
= F.d
F = 1.2 x 10-3N
d= (2-1.6)10-2=0.004m
W=1.210-3(0.004)=4.8 x 10 -6 J
A typical muscle fiber is 2.0 cm long and has a cross-section area of 3.1 * 10-9 m2. When the muscle fiber is stimulated, it pulls with a force of 1.2 mN.
Please check the attached file for a brief answer.
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The work done by the muscle fiber is 4.80x 10 J
The work done by the muscle fiber as it contracts to a length is
W = FAL
= (1.20x103 N) (0.4x10-2 m)
= 4.80x 10 J
Muscle tissues contain something known as muscle fibers. Muscle fibers consist of a single muscle cellular.
They assist to control the physical forces in the body. When grouped collectively, they are able to facilitate organized movement of your limbs and tissues.
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A box having a mass of 7.3 kg is lifted 0.60 m from ground level to the top of a desk. What is the gravitational potential energy in J of the box on the desktop?
Considering the definition of potential energy, the potential energy of the box is 42.9678 J.
Potential energyPotential energy is the energy that measures the ability of a system to do work based on its position. In other words, this is the energy that a body located at a certain height above the ground has.
Gravitational potential energy is the energy associated with the gravitational force. This will depend on the relative height of an object to some reference point, the mass, and the strength of gravity.
So for an object with mass m, at height h, the expression applied to the gravitational energy of the object is:
Ep= m×g×h
Where:
Ep is the potential energy in joules (J).m is the mass in kilograms (kg).h is the height in meters (m).g is the acceleration of fall in m/s² (approximately 9.81 m/s²).Potential energy in this caseIn this case, you know:
m= 7.3 kgg= 9.81 m/s²h= 0.60 mReplacing in the definition of potential energy:
Ep= 7.3 kg × 9.81 m/s² × 0.60 m
Solving:
Ep= 42.9678 J
Finally, the potential energy of the box is 42.9678 J.
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How are mircowaves similar to radio waves
Microwaves is similar to radio waves such that they are both an electromagnetic wave of lower wavelength and high frequency.
What is a Wave?This is referred to a disturbance which carries energy without movement of the particles.
Microwaves and radio waves both have a low wavelength and high frequency which makes them similar to each other.
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A satellite orbits the earth at a speed of 8.0x 10^3m/s . Calculate the period of orbit of the satellite if the distance between the centre of the earth and the satellite is 6400km?
Hi there!
The period of an orbit can be found by:
[tex]T = \frac{2\pi r}{v}[/tex]
T = Period (? s)
r = radius of orbit (6400000 m)
v = speed of the satellite (8000 m/s)
This is the same as the distance = vt equation. The total distance traveled by the satellite is the circumference of its circular orbit.
Let's plug in what we know and solve.
[tex]T = \frac{2\pi (6400000)}{8000} = \boxed{5026.55 s}[/tex]
A top fuel dragster with a mass of 500.0 kg starts from rest and completes a quarter mile (402 m) race in a time of 5.0 s. The dragster's final speed is 130 m/s. Neglecting friction, what average power was needed to produce this final speed
The average power needed to produce this final speed is 1069.1 hp.
Mass of the dragster, m = 500.0 kg,
Displacement travelled by the dragster, s = 402 m,
Time taken in this travel, t = 5.0 s,
Final velocity of the dragster, v = 130 m/s.
Let the initial velocity of the dragster be u and acceleration be a.
Using kinematical equation, s = ut + (1/2)at^2.
402 = u*5 + (1/2)*a*5^2
10*u + 25*a = 804. ...........(1)
Using kinematical equation, v = u +at.
130 = u + 5*a
5*u + 25*a = 650. .............(2)
Solving (1)and (2), we get,
u = 30.8 m/s.
According to work-energy theorem,
Work done = change in kinetic energy
W = (1/2)*m*(v^2 - u^2)
W = (1/2)*500*(130^2 - 30.8^2)
W = 3987840. J
Therefore power rating of the dragster is given by,
P ⇒ W/t. = 3987840/5 = 797568 watt.
P ⇒ 797568/746 = 1069.1 hp.
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The answer is 1069.1 hp.
Mass of the dragster, m = 500.0 kg,
Displacement travelled by the dragster, s = 402 m,
Time taken in this travel, t = 5.0 s,
Final velocity of the dragster, v = 130 m/s.
Let the initial velocity of the dragster be u and acceleration be a.
Using kinematical equation, s = ut + (1/2)at^2.
402 = u*5 + (1/2)*a*5^2
10*u + 25*a = 804. ...........(1)
Using kinematical equation, v = u +at^.
130 = u + 5*a^
5*u + 25*a = 650. .............(2)
Solving (1)and (2), we get,
u = 30.8 m/s.
According to work -energy theorem,
Work done = change in kinetic energy
W = (1/2)*m*(v^2 - u^2)
, W = (1/2)*500*(130^2 - 30.8^2)
, W = 3987840. J
therefore Power rating of the dragster is given by,
P = W/t. = 3987840/5 = 797568 watt.
, P = 797568/746 = 1069.1 hp.
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What is the angular displacement (in rad) of an object that starts from rest and accelerates at a rate of 4 rad/s2 for a time of 4 seconds? (Please leave your answer with one decimal places with no units)
An object which starts from its resting place & accelerates at a speed of 4 rad/sec², the angular displacement is 8 rad.
An object's angular displacement is described in the following:
Angle displacement is equal to θ[tex]f[/tex]-θ[tex]i[/tex].
The following methodology must also be applied to determine angular displacement when the object's acceleration, starting velocity, and time are known:
θ=ωt+ 1/2αt²
[where θ= the angular displacement of an object,
ω= initial angular velocity,
α= angular acceleration,
t= time]
In this case, the object starts from the rest position.
So, the initial angular speed, ω= 0 rad/sec
Provided angular acceleration ,α = 4 rad/sec²
Time ,t= 4 sec
So, θ= [tex]0*4+ (1/2)*4*4[/tex]
⇒θ= 0+ 8
⇒θ= 8 rad
Therefore, it is concluded that the angular displacement is 8 rad.
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