Molecule A undergoes isomerization to molecule B in acetone. Using curved arrows, showing key intermediates and any formal charges, propose a detailed mechanism for this isomerization. Provide a brief explanation why this isomerization occurs.

Answer:

8.1 × 10² g

Explanation:

Step 1: Write the balanced equation

2 C₅₇H₁₁₀O₆ + 163 O₂ ⇒ 114 CO₂ + 110 H₂O

Step 2: Convert 1.6 lb of C₅₇H₁₁₀O₆ to g

We will use the conversion factor 1 lb = 453.592 g.

1.6 lb × 453.592 g/1 lb = 7.3 × 10² g

Step 3: Calculate the moles corresponding to 7.3 × 10² g of C₅₇H₁₁₀O₆

The molar mass of C₅₇H₁₁₀O₆ is 890.83 g/mol.

7.3 × 10² g × 1 mol/890.83 g = 0.82 mol

Step 4: Calculate the moles of water produced from 0.82 moles of C₅₇H₁₁₀O₆

The molar ratio of C₅₇H₁₁₀O₆ to H₂O is 2:110. The moles of H₂O produced are 110/2 × 0.82 mol = 45 mol

Step 5: Calculate the mass corresponding to 45 moles of H₂O

The molar mass of H₂O is 18.02 g/mol.

45 mol × 18.02 g/mol = 8.1 × 10² g

Answer:

they get animal cells

Explanation:

Answer:

an attraction between a partially positive region in one molecule and a partially negative region in another molecule....dipole-dipole interaction

an attraction between two temporarily polarized molecules...dispersion forces

an attraction between a negatively charged particle and a partially positive region in a molecule....ion dipole interaction

an attraction between a partially positive hydrogen atom in a molecule and a partially negative and highly electronegative atom on another molecule....Hydrogen bonding

Explanation:

Some molecules have permanent dipole. As a result of this, the positive part of one molecule may attract the negative part of the other molecule leading to dipole-dipole interaction.

Dispersion forces occur in all molecules and is as a result of temporary polarization of a molecule due to instantaneous dipole–induced dipole attractions.

If a charged particle is attracted by a dipole in a molecule, we call it ion-dipole interaction.

When hydrogen is bonded to a highly electronegative element, the positive end of the dipole is on hydrogen while the negative end of the dipole is on the electronegative element. Molecular associations often result from this permanent dipole and is called hydrogen bonding, e.g, HF.

Answer:

physical change

Explanation:

i got the same question sorry for the late response but that's the answer good luck

Answer:

[tex]\Delta _{vap}H(300.2K)=43,658\frac{J}{mol}=43.66\frac{kJ}{mol}[/tex]

Explanation:

Hello!

In this case, according to the Kirchhoff's law for the enthalpy change, it is possible to compute the heat of vaporization at 300.2 K by considering the following thermodynamic route:

[tex]\Delta _{vap}H(300.2K)=Cp_{liq}(T_b-T\°)+\Delta _{vap}H\°+Cp_{vap}(T-T_B)[/tex]

Whereas the first term stands for the effect of taking the liquid from 298.15 K to 373.15 K, the second term stands for the standard enthalpy of vaporization and the last term that of the vapor from the boiling point to 300.2 K; thus we plug in to obtain:

[tex]\Delta _{vap}H(300.2K)=75.37\frac{J}{mol*K} (373.2K-298.15K)+40,660\frac{J}{mol} +36.4\frac{J}{mol*K}(300.2K-373.2K)\\\\\Delta _{vap}H(300.2K)=43,658\frac{J}{mol}=43.66\frac{kJ}{mol}[/tex]

Best regards!

Answer:

I believe the correct answer is cold surfaces.

Explanation:

Answer:

C

Explanation:

Answer:

The answer is below

Explanation:

The unit cell edge length (a) = 0.298 nm = 0.289 * 10⁻⁷ cm

The unit volume (V) = a³ = (0.289 * 10⁻⁷ cm)³ = 24 * 10⁻²⁴ cm³

There are 2 atoms per cell, hence N = 2. Also, [tex]n_a=avogadro\ constant=6.02*10^{23}\ mol^{-1}[/tex]

[tex]atomic\ weight\ of\ iron(A_f)=55.85,atomic\ weight\ of\ vanadium(A_V)=50.94,[/tex]

[tex]density\ of\ iron(\rho_f)=7.87,density\ of\ vanadium(\rho_v)=6.1.\\\\V=\frac{nA_{av}}{n_a\rho_{av}} \\\\A_{av}=\frac{100}{C_v/A_v+C_f/A_f} \\\\\rho_{av}=\frac{100}{C_v/\rho_v+C_f/\rho_f} \\\\C_v=concentration\ of\ vanadium,C_f=concentration\ of\ iron.\\\\V=\frac{nA_{av}}{n_a\rho_{av}}=\frac{n*\frac{100}{C_v/A_v+C_f/A_f}}{n_a*\frac{100}{C_v/\rho_v+C_f/\rho_f}}\\\\[/tex]

[tex]24*10^{-24}=\frac{2*\frac{100}{C_v/50.94+C_f/55.85}}{6.02*10^{23}*\frac{100}{C_v/6.1+C_f/7.87}}\\\\7.2=\frac{C_v/6.1+C_f/7.87}{C_v/50.94+C_f/55.85}\ \ \ (1) \\\\Also:\\\\C_v+C_f=100\%\ \ \ (2)\\\\\\solving\ equation\ 1\ and\ 2\ simultaneously\ gives:\\\\C_v=10\% \ and\ C_f=90\%\\\\[/tex]

1s², 2s², 2p⁶, 3s², 3p⁵

Given

Phosphorus element

Required

The electron configuration

Solution

The energy level is expressed in the form of electron configurations.  

Writing electron configurations starts from the lowest to the highest sub-shell energy level. There are 4 sub-shells in the shell of an atom, namely s, p, d and f.

Charging electrons in the sub shell uses the following sequence:  

1s², 2s², 2p⁶, 3s², 3p⁶, 4s², 3d¹⁰, 4p⁶, 5s², 4d¹⁰, 5p⁶, 6s², etc.  

Electron configurations are based on the number of electrons in the atomic number.

The atomic number of the phosphorus is 15, so the number of electrons is 15.

The configuration:

1s², 2s², 2p⁶, 3s², 3p⁵

Answer:

1.62

Explanation:

From the given information:

number of moles of benzamide  [tex]=\dfrac{70.4 \ g}{121.14 \ g/mol}[/tex]

= 0.58 mole

The molality = [tex]\dfrac{mass \ of \ solute (i.e. \ benzamide )}{mass \ of \ solvent }[/tex]

[tex]= \dfrac{0.58 }{0.85 }[/tex]

= 0.6837

Using the formula:

[tex]\mathbf {dT = l \times k_f \times m}[/tex]

where;

dT = freezing point = 27

l = Van't Hoff factor = 1

kf = freezing constant of the solvent

∴

2.7 °C = 1 × kf ×  0.6837 m

kf = 2.7 °C/ 0.6837m

kf = 3.949 °C/m

number of moles of NH4Cl = [tex]\dfrac{70.4 \ g}{53.491 \ g /mol}[/tex]

= 1.316 mol

The molality = [tex]\dfrac{1.316 \ mol}{0.85 \ kg}[/tex]

= 1.5484

Thus;

the above kf value is used in determining the  Van't Hoff factor for  NH4Cl

i.e.

9.9 = l × 3.949 × 1.5484 m

[tex]l = \dfrac{9.9}{3.949 \times 1.5484 \ m}[/tex]

l = 1.62

Answer:

Solution A: 0.00400M

Solution B: 0.00400M

Solution C: 4.00x10⁻⁵M

Explanation:

Solution A is diluting the 0.100M NaCl from 10mL to 250mL. That is:

250mL / 10mL = 25 times.

That means molar concentration of sln A is:

0.100M / 25 = 0.00400M

Solution B is obtained diluting 25mL to 100mL:

100mL / 25mL = 4 times

0.00400M / 4 times = 0.00100M

And solution C is obtained diluting the solution C from 20mL to 500mL:

500mL / 20mL = 25 times

Solution C:

0.00100M / 25 times = 4.00x10⁻⁵M

The formula for serial dilution can be used to obtain the molarity of solution A, B , C.

M1V1 = M2V2

M2 = 0.100 M ×  10 mL/250-mL

M2 = 0.004 M

M1V1 = M2V2

M2 = 0.004 M × 25 mL/100-mL

M2 = 0.001 M

M1V1 = M2V2

M2 = 0.001 M × 20 mL/500-mL

M2 = 0.00004 M

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Nacl = (. 23+35. 5)

= 58.5g

.

1 mol of Nacl = 58.5g

X mol Of Nacl = 25g

X Mol of Na Cl =25 ÷ 58.5

X mol of Nacl = 0.4 mol

Answer:

The rate of disappearance of C₂H₆O = 2.46 mol/min

Explanation:

The equation of the reaction is given below:

2 K₂Cr₂O₇ + 8 H₂SO₄ + 3 C₂H₆O → 2 Cr₂(SO₄)₃ + 2 K₂SO₄ + 11 H₂O

From the equation of the reaction, 3 moles of C₂H₆O is used when 2 moles of Cr₂(SO₄)₃ are produced, therefore, the mole ratio of C₂H₆O to Cr₂(SO₄)₃ is 3:2.

The rate of appearance of Cr₂(SO₄)₃ in that particular moment is given 1.64 mol/min. This would than means that C₂H₆O must be used up at a rate which is approximately equal to their mole ratios. Thus,  the rate of of the disappearance of C₂H₆O can be calculated from the mole ratio of Cr₂(SO₄)₃ and C₂H₆O.

Rate of disappearance of C₂H₆O = 1.64 mol/min of  Cr₂(SO₄)₃  * 3 moles of C₂H₆O / 2 moles of Cr₂(SO₄)₃

Rate of disappearance of C₂H₆O = 2.46 mol/min of C₂H₆O

Therefore, the rate of disappearance of C₂H₆O = 2.46 mol/min

Answer:

Ions are formed when the number of protons in an atom does not equal the number of electrons. If more protons are present, the ion is positive and is known as a cation; if more electrons are present, the ion is negative and referred to as an anion. Ions are highly reactive species.

Explanation:

Answer:

An atom becomes charged when the number of protons does not equal the number of electrons. For example, if an element has six protons but only five electrons, the net charge of the element is +1. Conversely, if an element has six protons but seven electrons, then the net charge of the element is -1.

Explanation:

Answer:

Amount = 2250 g

Explanation:

Note: This question is incomplete and lacks each and every data to solve. However, I have found the similar question on the internet and will be solving this question for you. Cheers!

Data Missing:

Organic Compound O

Solubility = 0.225 g/ml

Temperature = 10°C

Calculate the greatest mass of O that can be dissolved in 10.0 L acetonitrile at 10°C temperature.

Solution:

As we know the volume of the acetonitrile = 10.0 L

but first, we need to convert this into mL

We know that,

1 L contains 1000 mL

So,

10 L will contain = 10 x 1000 mL

10 L = 10000 mL

We, can write, 10000 mL as:

1 x [tex]10^{4}[/tex] mL

Now, the formula to calculate the greatest amount of O that can be dissolved in 1 x [tex]10^{4}[/tex] mL acetonitrile at 10°C temperature is:

Amount  = Solubility x volume

Here,

Solubility = 0.225 g/ml

and

Volume = 1 x [tex]10^{4}[/tex] mL

Plugging in the values, we get:

Amount  = 0.225 g/ml x 1 x [tex]10^{4}[/tex] mL

Amount  = 0.225 x [tex]10^{4}[/tex] g

Amount = 2250 g

Answer: The comparison of the experimental amount of product to the calculated amount : Percentage yield

The calculated amount of product under ideal conditions : Theoretical yield

The amount of product experimentally produced : Experimental yield or actual yield

Explanation:

Theoretical yield is to determine how much of the product should be formed based on stoichiometry of the given reaction. It is the maximum amount of product that could be formed from the given amounts of reactants.

Experimental yield or actual yield is the amount of product that is actually formed when the reaction is carried out in the laboratory.

Percentage yield is the ratio of the experimental yield to the theoretical yield, expressed as a percentage.

Answer:

Na3PO4 + KCl = NaCl + K3PO4

Explanation:

You have to know the Chemical Formula for Sodium phosphide, = Na3PO4 and Potassium chloride. which is = KCI

Answer:

Silver Lake Picnic Area, Or C

Explanation:

Answer:

See explanation and image attached

Explanation:

"A formal charge (FC) is the charge assigned to an atom in a molecule, assuming that electrons in all chemical bonds are shared equally between atoms, regardless of relative electronegativity" (chemlibretext).

We can obtain the formal charge from the formula;

Formal Charge = [number of valence electrons on atom] – [non-bonded electrons + 1/2number of bonds].

A structure in which SO2 has a zero formal charge is attached to this answer.

Image credit: Chemtopper

Answer:

2.56 eV

Explanation:

Using the formula;

ΔE= -RH(1/n^2final - 1/n^2initial)

RH = -2.18 * 10-18 J

nfinal = 2

ninitial =1

Substituting values;

ΔE= -2.18 * 10-18 J(1/4^2 - 1/2^2)

ΔE= -2.18 * 10-18 J(0.0625 - 0.25)

ΔE= 4.09 * 10^-19 J

To convert to eV

4.09 * 10^-19 J/1.6 * 10^-19

=2.56 eV

Answer:

The Forces that form each star would be your answer :)

Answer:

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WHAT

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THIS

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Answer:

11.73 Kg of CO₂

Explanation:

We'll begin by writing the balanced equation for the reaction. This is illustrated below:

2C₈H₁₈ + 25O₂ —> 16CO₂ + 18H₂O

Next, we shall determine the mass of C₈H₁₈ that reacted and the mass of CO₂ produced from the balanced equation. This can be obtained as follow:

Molar mass of C₈H₁₈ = (12×8) + (18×1)

= 96 + 18

= 114 g/mol

Mass of C₈H₁₈ from the balanced equation = 2 × 114 = 228 g

Convert 228 g to kg.

1000 g = 1 Kg

Therefore,

228 g = 228 g × 1 Kg / 1000 g

228 g = 0.228 Kg

Molar mass of CO₂ = 12 + (16×2)

= 12 + 32

= 44 g/mol

Mass of CO₂ from the balanced equation = 16 × 44 = 704 g

Convert 704 g to Kg

1000 g = 1 Kg

Therefore,

704 g = 704 g × 1 Kg / 1000 g

704 g = 0.704 Kg

SUMMARY:

From the balanced equation above,

0.228 Kg of C₈H₁₈ reacted to produce 0.704 Kg of CO₂.

Finally, we shall determine the mass of carbon dioxide, CO₂, that will be produced by the reaction of 3.8 kg of octane, C₈H₁₈. This can be obtained as follow:

From the balanced equation above,

0.228 Kg of C₈H₁₈ reacted to produce 0.704 Kg of CO₂.

Therefore, 3.8 kg of C₈H₁₈ will react to produce = (3.8 × 0.704) / 0.228 = 11.73 Kg of CO₂

Thus, 11.73 Kg of CO₂ is added to the atmosphere per 3.8 kg of C₈H₁₈.

Answer:

1s22s22p3.

Explanation:

Electronic configuration of a neutral atom is 1s22s22p3.  

Please see the image attached

Neutral atom of nitrogen will have equal number of proton and electron i.e equal to 7. 7 electron of the nitrogen are placed into the s and p orbitals in the ground state.  

Answer:

particles bigger

Explanation:

Even when compared with animal cells, microorganisms become smaller. They are about 1/10 the size of a typical human cell. Therefore, compared with human-sized animal cells, the size of bacteria (such as bacterial cells) will be the size of a cat or puppy. The size of the virus is about 1/10 of that of other microorganisms such as bacteria.

Hope it helps. If not, I'm so sorry.

Answer:

particles are bigger than microorganism

Answer:

Other species will slowly die, because the species that eat snails and crayfish will not have anything to eat, then the thing that eats them will not have anything. This process will go on and on. So long story short populations will decrease, then off.

mass of PbI₂ = 27.6606 g

Given

Pb(NO₃)₂ + NaI → PbI₂ + NaNO₃

28.0 grams of Pb(NO₃)₂ react with 18.0 grams of NaI

Required

mass of PbI₂

Solution

Balanced equation

Pb(NO₃)₂ + 2NaI → PbI₂ + 2NaNO₃

The principle of a balanced reaction is the number of atoms in the reactants = the number of atoms in the product

mol Pb(NO₃)₂ :

= 28 : 331,2 g/mol

= 0.0845

mol NaI :

= 18 : 149,89 g/mol

= 0.12

Limiting reactant : mol : coefficient

Pb(NO₃)₂ : 0.0845 : 1 = 0.0845

NaI : 0.12 : 2 = 0.06

NaI limiting reactant (smaller ratio)

mol PbI₂ based on NaI

= 1/2 x 0.12 = 0.06

Mass PbI₂ :

= 0.06 x 461,01 g/mol

= 27.6606 g

Answer:

0.696 atoms of oxygen

Explanation:

We'll begin by calculating the number of mole in 50 g of scheelite CaWO₄. This can be obtained as follow:

Mass of CaWO₄ = 50 g

Molar mass of CaWO₄ = 40 + 184 + (4×16)

= 40 + 184 + 64

= 288 g/mol

Mole of CaWO₄ =?

Mole = mass / Molar mass

Mole of CaWO₄ = 50 / 288

Mole of CaWO₄ = 0.174 mole

Finally, we shall determine the number of oxygen atom in 50 g (i.e 0.174 mole) of CaWO₄. This can be obtained as follow:

1 mole of CaWO₄ contains 4 atoms of oxygen.

Therefore, 0.174 mole of CaWO₄ will contain = 0.696 atoms of oxygen.

Thus, 50 g (i.e 0.174 mole) of CaWO₄ contains 0.696 atoms of oxygen.

Answer:

35mL of the 7.5% solution are required to meake the media

Explanation:

To prepare the culture media there are required 2.625g of sodium bicarbonate. We have a 7.5% solution of sodium bicarbonate (That is, 7.5g of sodium bicarbonate in 100mL of solution). Thus, to obtain 2.625g we need:

2.625g Sodium bicarbonate * (100mL / 7.5g) =

Answer:

 (C) Mass of KCl(s), mass of H20, initial temperature of the water, and final temperature of the solution

Explanation:

molar enthalpy of solution of KCl(s) is heat evolved or absorbed when one mole of KCl is dissolved in water to make pure solution . The heat evolved or absorbed can be calculated by the following relation.

Q = msΔt where m is mass of solution or water , s is specific heat and Δt is change in temperature of water .

So data required is mass of water or solution , initial and final temperature of solution , specific heat of water is known .

Now to know molar heat , we require mass of solute or KCl dissolved to know heat heat absorbed or evolved by dissolution of one mole of solute .

The correct option is option C.

To determine the molar enthalpy of the solution of [tex]Kcl(s)[/tex] is pure [tex]H_2O(l)[/tex]

We need to know that the,

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