1. Express y in terms of x using the constraint: y = x - 10.
2. Substitute this expression for y in the function p: p = x^2(x - 10)^2.
3. The minimum value of p, differentiate p with respect to x and set the result equal to zero: d(p)/dx = 0. Evaluate the function p at these coordinates to find the minimum value of p.
To minimize p=x^2 y^2 subject to x-y=10, we can use the method of Lagrange multipliers.
Let L = p + λ(x-y-10), where λ is the Lagrange multiplier.
Taking partial derivatives of L with respect to x, y, and λ, and setting them equal to zero, we get:
∂L/∂x = 2xy^2 + λ = 0
∂L/∂y = 2x^2 y + λ = 0
∂L/∂λ = x - y - 10 = 0
Solving for x and y in terms of λ from the first two equations, we get:
x = sqrt(-λ/2y^2)
y = sqrt(-λ/2x^2)
Substituting these expressions into the third equation, we get:
sqrt(-λ/2y^2) - sqrt(-λ/2x^2) - 10 = 0
Simplifying, we get:
λ = -40x^2y^2
Substituting this value of λ back into the expressions for x and y, we get:
x = 2sqrt(5)
y = -2sqrt(5)
Finally, plugging in these values of x and y into the expression for p, we get:
p = x^2 y^2 = 80
Therefore, the minimum value of p, subject to x-y=10, is 80.
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Triangles KLO and MNO are similar. Which proportion could be used to find LO? Select all that apply.
Answer:
LO=6
Step-by-step explanation:
MO/KO=NO/LO
5/10=3/LO
5LO=30
LO=6cm
The student performed a different single transformation on PQR to create JKL. The coordinates of vertex K are (4,1). What could be the single transformation the student performed?
The single transformation which this student performed include the following: a reflection over the y-axis.
What is a reflection over the y-axis?In Geometry, a reflection over or across the y-axis or line x = 0 is represented and modeled by this transformation rule (x, y) → (-x, y).
By applying a reflection over the y-axis to the coordinate of the given triangle PQR, we have the following coordinates:
(x, y) → (-x, y).
Coordinate P = (-1, 1) → Coordinate J' = (-(-1), 1) = (1, 1).
Coordinate Q = (-4, 1) → Coordinate K' = (-(-4), 1) = (4, 1).
Coordinate R = (-4, 4) → Coordinate L' = (-(-4), 4) = (4, 4).
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Solve the following inequality algebraically:
Negative 2 less-than StartFraction x Over 3 EndFraction + 1 less-than 5
a.
Negative 9 greater-than x greater-than 12
b.
Negative 9 less-than x less-than 12
c.
Negative 2 less-than x less-than 5
d.
Negative 2 greater-than x greater-than 5
The solution of inequality is -9 < x < 12.
The correct option is B.
We have,
-2 < x/3 + 1 < 5
Now, solving the inequation in parts as
-2 < x/3 + 1
-2 - 1 < x/3
-3 < x/3
-9 < x
and, x/3 + 1 < 5
x/3 < 4
x <12
Thus, the solution of inequality is -9 < x < 12.
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Can you answer this please
(a) f = 5xyz + 5x^2y/2 + C is a potential function for F.
(b) f = ye^(xz) + 9x^2y/2e^(xz) + C is a potential function for F.
What is the potential function of the conservative vector?
To find a potential function f for a conservative vector field F, we need to find a scalar function f(x, y, z) such that the gradient of f is equal to F, i.e., ∇f = F.
(1) For F = 5yzi + 5xzj + 5xyk, we need to find f such that ∂f/∂x = 5yz, ∂f/∂y = 5xz, and ∂f/∂z = 5xy.
Integrating the first equation with respect to x gives f = 5xyz + g(y, z), where;
g(y, z) is a constant of integration that depends only on y and z.Differentiating this expression with respect to y and z and comparing with the other two equations, we find that;
g(y, z) = C + 5x^2y/2 and
f = 5xyz + 5x^2y/2 + C,
where;
C is an arbitrary constant.Therefore, f = 5xyz + 5x^2y/2 + C is a potential function for F.
(2) For F = 9yze^(xz)i + 9exzj + 9xye^(xz)k, we need to find f such that;
∂f/∂x = 9yze^(xz), ∂f/∂y = 9xe^(xz), and ∂f/∂z = 9xye^(xz).Integrating the first equation with respect to x gives f = ye^(xz) + g(y, z),.
where;
g(y, z) is a constant of integration that depends only on y and z.Differentiating this expression with respect to y and z and comparing with the other two equations, we find that;
g(y, z) = C + 9x^2ye^(xz)/2 and
f = ye^(xz) + 9x^2y/2e^(xz) + C,
where;
C is an arbitrary constant.Therefore, f = ye^(xz) + 9x^2y/2e^(xz) + C is a potential function for F.
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State if the triangle is acute obtuse or right
Answer:
Step-by-step explanation:
It is a right triangle.
Pythagorean Theorem can be used to find the sides.
IF the square of one side of a triangle is equal to the sum of the squares of the other two sides, then the triangle is a right triangle. The right angle is opposite the longest side.
72² + 8.5² = 72.5²
5184 + 72.25 = 5256.25
5256.25 = 5256.25
Let adj A 1 2 1 where adj A is the adjugate of matrix A, 1 1 2 with det A >0 and AX = A + X. Find det A and matrix X.
det(A) = ad - bc.
Matrix X is X = [8/5 -6/5, -2, 2/5 2/5]
What method is used to calculate det A and matrix X?We know that the adjugate of a 2x2 matrix is:
adj(A) = [d -b, -c a]
A = [a b, c d]
det(A) = ad - bc.
So, from the given adj(A), we have:
d - b = 1
-c = 2
-a = 1
d - c = 1
We have c = -2. Then, from the fourth equation, we have d = 1 - c = 3. Substituting these values into the first and third equations, we get:
b = 2
a = -1
So, the matrix A is:
A = [-1 2, -2 3]
We are given that AX = A + X. Substituting the matrix A and simplifying, we get:
AX = A + X
=> A(X - I) = X - A
=> (X - I)(-A) = X - A
=> X - I = (-A)⁻¹ (X - A)
=> X - I = A⁻¹ (X - A)
=> X = A⁻¹ X - A⁻¹ A + I
=> X = A⁻¹ (X - A) + I
Since we know A, we can find its inverse:
A⁻¹ = 1/(ad - bc) [d -b, -c a] = 1/5 [3 -2, 2 -1]
Substituting this into the above equation, we get:
X = 1/5 [3 -2, 2 -1] (X - [-1 2, -2 3]) + I
Simplifying this, we get:
X = 1/5 [4X + 5, -6X - 10, -2X - 10, 3X + 5]
Equating the corresponding elements on both sides, we get the following system of equations:
4x + 5 = x
-6x - 10 = 2
-2x - 10 = 1
3x + 5 = 3
Solving this system of equations, we get:
x = -1
Therefore, det(A) = ad - bc = (-1)(3) - (2)(-2) = -1 + 4 = 3.
And, matrix X is:
X = [8/5 -6/5, -2, 2/5 2/5]
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convert the binary expansion of each of the following integers to a hexadecimal expansion. the hexadecimal notation of (0111 0111 0111 0111)2
Each group of four binary digits can be represented by a single hexadecimal digit. The hexadecimal notation of (0111 0111 0111 0111)₂ is (7777)₁₆.
To convert the binary expansion of (0111 0111 0111 0111)2 to hexadecimal, we first group the digits into groups of four starting from the right:
(0111 0111 0111 0111)2 = (7 7 7 7)16
Each group of four binary digits can be represented by a single hexadecimal digit. In this case, each group of four binary digits represents the hexadecimal digit 7. Therefore, the hexadecimal notation of (0111 0111 0111 0111)2 is (7777)16.
To convert the binary expansion (0111 0111 0111 0111)₂ to a hexadecimal expansion, you can group the binary digits into sets of four starting from the right and then convert each group to its corresponding hexadecimal value. Here's the process:
1. Group the binary digits: (0111) (0111) (0111) (0111)
2. Convert each group to hexadecimal:
- (0111)₂ = 7₁₆
- (0111)₂ = 7₁₆
- (0111)₂ = 7₁₆
- (0111)₂ = 7₁₆
Your answer: The hexadecimal notation of (0111 0111 0111 0111)₂ is (7777)₁₆.
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A Nyquist plot of a unity-feedback system with the feedforward transfer function G(s) is shown in Figure. If G(s) has one pole in the right-half s plane, is the system stable? If G(s) has no pole in the right-half s plane, but has one zero in the right-half s plane, is the system stable?
In a Nyquist plot, If G(s) has one pole in the right-half s plane, the system is marginally stable.
If G(s) has no pole in the right-half s plane, but has one zero in the right-half s plane, the system is stable.
In a Nyquist plot, the stability of a system can be determined by examining the number of encirclements of the -1 point. If the number of encirclements is equal to the number of right-half plane poles, then the system is unstable. If the number of encirclements is less than the number of right-half plane poles, then the system is marginally stable. If the number of encirclements is greater than the number of right-half plane poles, then the system is stable.
In the first case where G(s) has one pole in the right-half s plane, the Nyquist plot will encircle the -1 point once in the clockwise direction. Therefore, the number of encirclements is less than the number of right-half plane poles, which means the system is marginally stable.
In the second case where G(s) has one zero in the right-half s plane, the Nyquist plot will not encircle the -1 point at all. Therefore, the number of encirclements is less than the number of right-half plane poles, which means the system is stable.
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the mean of the t distribution is a. .5. b. 1. c. 0. d. problem specific.
The correct answer is (c) 0. The mean of the t-distribution is always 0.
The t-distribution is a probability distribution that is used to test hypotheses about the population mean when the sample size is small and the population standard deviation is unknown. The shape of the t-distribution depends on the degrees of freedom (df), which is equal to the sample size minus one.
Although the t-distribution changes shape as the degrees of freedom change, the center of the distribution is always at zero. Therefore, the mean of the t-distribution is always zero, regardless of the degrees of freedom or any other factors.
Therefore, the correct answer is (c) 0.
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5. Let A={0,3,4,5,7} and B={4,5,6,7,8,9,10,11}. Let D be the divides relation. That is, for all (x,y)∈A×B,xDy iff x∣y. a) Write the relation set D and draw the relation diagram with arrows. b) Write the relation set D−1, the inverse relation of the relation D and draw the relation diagram with arrows.
a) The relation set D is {(0,4), (0,5), (0,7), (3,6), (3,9), (4,4), (4,8), (4,12), (5,5), (5,10), (5,15), (7,7), (7,14)}. The relation diagram with arrows can be drawn as follows:
0 → 4, 5, 7
3 → 6, 9
4 → 4, 8, 12
5 → 5, 10, 15
7 → 7, 14
b) The relation set D-1 is {(4,0), (5,0), (7,0), (6,3), (9,3), (4,4), (8,4), (12,4), (5,5), (10,5), (15,5), (7,7), (14,7)}. The relation diagram with arrows can be drawn as follows:
4 → 0, 4, 8, 12
5 → 0, 5, 10, 15
7 → 0, 7, 14
6 → 3
9 → 3
8 → 4
12 → 4
10 → 5
15 → 5
14 → 7
a) The relation set D consists of pairs (x, y) such that x ∈ A and y ∈ B, and x divides y. D = {(0, 4), (0, 5), (0, 6), (0, 7), (0, 8), (0, 9), (0, 10), (0, 11), (3, 6), (3, 9), (4, 4), (4, 8), (5, 5), (5, 10), (7, 7)}. In the relation diagram, draw arrows from elements of A to elements of B according to these pairs.
b) The inverse relation set D⁻¹ consists of pairs (y, x) such that x ∈ A and y ∈ B, and x divides y. D⁻¹ = {(4, 0), (5, 0), (6, 0), (7, 0), (8, 0), (9, 0), (10, 0), (11, 0), (6, 3), (9, 3), (4, 4), (8, 4), (5, 5), (10, 5), (7, 7)}. In the relation diagram, draw arrows from elements of B to elements of A according to these pairs.
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Which equation represents a circle that contains the point (-2, 8) and has a center at (4, 0)?
Distance formula: √(x₂-x₂)² + (V₂ - V₁)²
(x-4)² + y² = 100
Ox²+(y-4)² = 100
The circle that contains the point (-2, 8) and has a center at (4, 0) is given by the equation (x - 4)² + y² = 100
What is the circle that contains the point (-2, 8) and has a center at (4, 0)?The standard form equation of a circle with center (h, k) and radius r is:
(x - h)² + (y - k)² = r²
Given that: the circle that contains the point (-2, 8) and has a center at (4, 0).
The distance between the center of a circle and any point on the circle is constant and is called the radius of the circle.
TherHence, to find the circle that contains the point (-2, 8) and has a center at (4, 0), we need to find the distance between these two points and use that as the radius of the circle.
The distance between two points (x1, y1) and (x2, y2) is given by the distance formula:
d = √((x2 - x1)² + (y2 - y1)²)
d = √((4 - (-2))² + (0 - 8)²)
= √(6² + (-8)²)
= √(100)
= 10
Hence, the distance between the center of the circle at (4, 0) and the point (-2, 8) is 10 units.
Therefore, the radius of the circle is 10 units.
The equation of a circle with center (h,k) and radius r is given by:
(x - h)² + (y - k)² = r²
In this case, the center is (4, 0) and the radius is 10, so the equation of the circle is:
(x - 4)² + y² = 10²
(x - 4)² + y² = 100
Therefore, the equation of the circle is (x - 4)² + y² = 100.
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Write a quadratic function / whose only zero is -11.
Check
=
The quadratic value equation with zeroes at -11 is f(x) = a(x + 11)²
Given data ,
A quadratic function that has -11 as its only zero can be written in the form:
f(x) = a(x - r)²
where "a" is a non-zero constant and "r" is the zero of the function, in this case, -11.
On simplifying the equation , we get
f(x) = a(x - (-11))²
f(x) = a(x + 11)²
Hence , any quadratic function of the form f(x) = a(x + 11)^2, where "a" is a non-zero constant, will have -11 as its only zero
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Find the volume of the rectangular prism
Answer:
2 1/3
Step-by-step explanation:
V = LWH
V = 1 3/4 ft × 2/3 ft × 2 ft
V = 7/4 × 2/3 × 2/1 ft³
V = 28/12 ft³
V = 7/3 ft³
V = 2 1/3 ft³
A New York City hotel surveyed its visitors to determine which type of transportation they used to get around the city. The hotel created a table of the data it gathered.
Type of Transportation Number of Visitors
Walk 120
Bicycle 24
Car Service 45
Bus 30
Subway 81
Which of the following circle graphs correctly represents the data in the table?
circle graph titled New York City visitor's transportation, with five sections labeled walk 80 percent, bus 16 percent, car service 30 percent, bicycle 20 percent, and subway 54 percent
circle graph titled New York City visitor's transportation, with five sections labeled walk 40 percent, bicycle 8 percent, car service 15 percent, bus 10 percent, and subway 27 percent
circle graph titled New York City visitor's transportation, with five sections labeled subway 40 percent, bus 8 percent, car service 15 percent, bicycle 10 percent, and walk 27 percent
circle graph titled New York City visitor's transportation, with five sections labeled subway 80 percent, bicycle 20 percent, car service 30 percent, bus 16 percent, and walk 54 percent
The option to the above question is a circle graph titled New York City visitor's transportation, with five sections labelled walk 40 per cent, bicycle 8 per cent, car service 15 per cent, bus 10 per cent, and subway 27 per cent.
What is a circle?A circle is a geometric shape that consists of a set of points in a plane that are equidistant from a fixed point called the centre. The distance from the centre to any point on the circle is called the radius, and the distance across the circle passing through the centre is called the diameter.
According to the given information:
The correct circle graph that represents the data in the table would be:
circle graph titled New York City visitor's transportation, with five sections labelled walk 40 per cent, bicycle 8 per cent, car service 15 per cent, bus 10 per cent, and subway 27 per cent.
This is because the percentages shown in this circle graph match the data given in the table for each type of transportation. Specifically, the circle graph shows that 40% of visitors walked, 8% used bicycles, 15% used car service, 10% used the bus, and 27% used the subway, which aligns with the numbers provided in the table.
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Answer:It’s B i got it correct on the quiz
Step-by-step explanation:
Determine the area of a triangle with vertices defined by the given points to the nearest tenth. A(2,1), B(3,6), C(6,2) Select one:a. 18 b. 14.7 c. 9.5 d. 14.2.
The area of the triangle is 5 square units. None of the given options match our answer, so there may be an error in the question or the answer choices.
To determine the area of a triangle with vertices defined by the given points A(2,1), B(3,6), and C(6,2), we can use the formula for the area of a triangle:
Area = 1/2 * base * height
where the base is the distance between two vertices and the height is the perpendicular distance from the third vertex to the base. We can choose any two vertices as the base, so let's choose AB as the base.
The distance between A and B is:
√((3-2)^2 + (6-1)^2) = √(26)
To find the height, we need to find the equation of the line passing through C and perpendicular to AB. The slope of AB is (6-1)/(3-2) = 5, so the slope of the perpendicular line is -1/5. We can use the point-slope form to find the equation of the line:
y - 2 = (-1/5)(x - 6)
y = (-1/5)x + (32/5)
To find the height, we need to find the distance from point A to this line. We can use the formula for the distance from a point to a line:
distance = |Ax + By + C| / √(A² + B²)
where A, B, and C are the coefficients of the line in the standard form Ax + By + C = 0. Plugging in the values, we get:
distance = |2*(-1/5) + 1*1 + (32/5)| / √((-1/5)² + 1²)
distance = 10/√(26)
Now we can plug in the values into the formula for the area:
Area = 1/2 * √(26) * (10/√(26))
Area = 5
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Is triangle DEF congruent to triangle ABC? Yes or no
why? SSS ASA AAS SAS HL or a reason they are not.
Is triangle GHI congruent to triangle ABC? Yes or no
why? SSS ASA AAS SAS HL or a reason they are not.
Is triangle JKL congruent to triangle ABC? Yes or no
why? SSS ASA AAS SAS HL or a reason they are not.
Why are some of these triangles congruent and not similar?
Triangle DEF is not congruent to triangle ABC
Yes, triangle GHI is congruent to triangle ABC the reason is SAS
What is ASA theorem?The Angle-Side-Angle (ASA) theorem is a geometry mathematical principle that establishes the congruence of triangles.
More specifically, this theorem notes that if two angles and their included side on one triangle are equal in measure to the corresponding two angles and included side on another triangle, then both triangles are said to be congruent.
Since ASA relies heavily upon the matching of angle size and side length, it serves as an essential tool for geometric proofs and thorough analyses.
The corresponding angles are
52.4 and 45.5
The included side is 5cm
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e. if a quantity increases exponentially, the time required to increase by a factor of 10 remains constant for all time. is this statement true or false?
The statement is false because in exponential growth, the time required to increase by a factor of 10 actually increases as the quantity gets larger.
We have,
In exponential growth, the rate of increase becomes progressively faster as the quantity grows.
This means that the time it takes to increase by a factor of 10 will also increase. For example, if it takes 1 year to increase from 1 to 10, it may take 2 years to increase from 10 to 100, and 3 years to increase from 100 to 1000.
The time required to achieve a factor of 10 increase will depend on the specific growth rate and initial quantity.
Therefore,
The time required to increase by a factor of 10 does not remain constant for all time in exponential growth. It increases as the quantity grows larger.
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You want to buy a new cell phone. The sale price is $149
. The sign says that this is $35
less than the original cost. What is the original cost of the phone?
Answer:
In this problem it is saying that it is $35 less than the original cost so to find this you need to add. This should be just $149 + $35 to solve it which is a total of $184 which is the original cost for the phone.
$184 is your answer
Step-by-step explanation:
$114
as the question says the price is $35 less than the original cost, which means 149-35 which equal 144.
Can someone help me please? I've been trying to solve this for a while now, please help. Thank you
Answer:
-1(-4)=-5
Step-by-step explanation:
as h = -1
if the population standard deviation of aaa batteries (with a population mean of 9 hours) is 0.5 hours, the margin of error for a 95onfidence interval for μ (n = 25 batteries) would be
Therefore, the margin of error for a 95% confidence interval for the population mean of AAA batteries (with a population standard deviation of 0.5 hours and a population mean of 9 hours) based on a sample size of 25 batteries is 0.196 hours.
What is margin error?
Margin of error is a statistical term that refers to the amount of error that is allowed in a survey or poll's results. It is a measure of the precision of the results and indicates the range within which the true value is likely to fall.
In statistical terms, the margin of error is calculated as a percentage of the total number of respondents in a survey, and it takes into account factors such as the size of the sample, the level of confidence desired, and the variability in the responses.
For example, if a poll has a margin of error of +/- 3%, it means that the actual value of the result could be up to 3% higher or 3% lower than the reported value in the survey.
The formula for the margin of error for a 95% confidence interval is:
Margin of error = z * (σ / [tex]\sqrt(n)[/tex])
Where:
z = the z-score for the desired confidence level (95% confidence level corresponds to z = 1.96)
σ = the population standard deviation
n = the sample size
Substituting the given values into the formula:
Margin of error = 1.96 * (0.5 /[tex]\sqrt(25)[/tex])
Margin of error = 1.96 * (0.5 / 5)
Margin of error = 1.96 * 0.1
Margin of error = 0.196
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find the slope of the parametric curve x=-4t^2-4, y=6t^3, for , at the point corresponding to t.
The slope of the parametric curve x=-4t^2-4, y=6t^3 at the point corresponding to t is -9t/4.
To find the slope of the parametric curve x=-4t^2-4, y=6t^3 at the point corresponding to t, follow these steps:
1. Find the derivatives of both x and y with respect to t:
dx/dt = -8t
dy/dt = 18t^2
2. The slope of the parametric curve is the ratio of the derivatives, dy/dx.
To find this, divide dy/dt by dx/dt:
dy/dx = (dy/dt) / (dx/dt)
= (18t^2) / (-8t)
3. Simplify the expression:
dy/dx = -9t / 4
So, the slope of the parametric curve x=-4t^2-4, y=6t^3 at the point corresponding to t is -9t/4.
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A soccer field is a rectangle 90 meters wide and 120 meters long. The coachasks players to run from corner to corner diagonally across. Determine the distance the players must run.
Answer:
The distance the players must run is [tex]150 m[/tex]
Step-by-step explanation:
The distance that the players must run diagonally from one corner of the soccer field to the inverse corner can be found by using the Pythagorean hypothesis,
The Pythagorean hypothesis may be a scientific guideline that relates to the sides of a right triangle. It states that the square of the length of the hypotenuse (the longest side of the triangle) is break even with to the whole of the squares of the lengths of the other two sides.
The length of the soccer field is 120 m long.(given)
The width of the soccer field is 90 m (given)
and width of the soccer field shape the two legs of the right triangle, and the corner-to-corner distance is the hypotenuse. Hence, we can utilize the Pythagorean theorem as takes after:
Distance = [tex]\sqrt{(length^{2} } + width^{2}[/tex]
[tex]= \sqrt{120^{2} + 90^{2} }[/tex]
= ([tex]\sqrt{(14400 + 8100)}[/tex]
= [tex]\sqrt{22500}[/tex]
[tex]= 150.00 meters[/tex]
Therefore, the distance the players must run is 150. m
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HELP! The vertices of a rectangle are plotted.
What is the perimeter of the rectangle?
11 units
66 units
17 units
34 units
which is the crrect answer?
Answer:
Step-by-step explanation:
Which equation shows the identity property of multiplication?
b.ama b
Submit
a b c d
0.a=0
· 1 = a
Answer:
Step-by-step explanation:
1=a
Answer:
Step-by-step explanation:
Identity means to get itself
For multiplication,
if you multiplied a number by 0, you would not get that number again, you would get 0. so multiplying by 0 is not and identity
ex. (a)(0)=0 does not = a so this is not an identity
if you multiplied a number by 1, yes that would be an identity because any number times 1 is itself
ex. a(1)=a multiplied by 1 the number is itself, so yes this is an identity.
Write the complex number e^i pi/3 in the form a + bi. a = and b =. Write the complex number e^i 4 pi/3 in the form a + bi. a = and b = Write the complex number z = 6 - 4i in polar form: z = r(cos theta + i sin theta) where r = and theta = The angle should satisfy 0 lessthanorequalto theta < 2 pi
z = 2√13(cos 5.49 + i sin 5.49) in polar form.
We can use Euler's formula, e^(iθ) = cos(θ) + i sin(θ), to write complex numbers in polar form.
1. For e^(iπ/3), we have:
e^(iπ/3) = cos(π/3) + i sin(π/3) = 1/2 + i√3/2
Therefore, a = 1/2 and b = √3/2.
2. For e^(i4π/3), we have:
e^(i4π/3) = cos(4π/3) + i sin(4π/3) = -1/2 - i√3/2
Therefore, a = -1/2 and b = -√3/2.
3. For z = 6 - 4i, we can find the magnitude (or modulus) of z, r, using the Pythagorean theorem:
|r| = √(6^2 + (-4)^2) = √52 = 2√13
To find the angle, theta, we can use the inverse tangent function:
tan⁻¹(-4/6) = -tan⁻¹(2/3) ≈ -0.93 radians
However, since we want the angle to satisfy 0 ≤ θ < 2π, we need to add 2π to the angle if it is negative:
θ = 2π - 0.93 ≈ 5.49 radians
Therefore, z = 2√13(cos 5.49 + i sin 5.49) in polar form.
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√3x + √2x-1/√3x -√2x-1 = 5
prove that x = 3/2
Answer:
this is a correct answer 5√6/2
a faulty watch gains 10 seconds an hour if it is correctly set to 8 p.m. one evening what time will it show when the correct time is 8 p.m. the following evening
The watch gains 4 min till 8:00 PM in the next evening and show 8:04 pm the next evening.
What does it gain?Considering that,
A broken watch adds ten seconds per hour.
Find the number of hours between 8:00 PM this evening and 8:00 PM the following evening.
There are 24 hours in a day.
number of seconds the defective watch gained.
1 hour equals 10 seconds
24 hours ÷ by 10
24 * 10 is 240 seconds.
Now figure out how many minutes your defective watch has gained.
60 s = 1 minute
240 sec = 240/60
= 4 min
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Missing parts;
A faulty watch gains 10 seconds an hour. If it is set correctly at 8:00 pm one evening, what time will it show when the correct time is 8:00 pm the following evening
ILL GIVE BRAINLEIST THIS WAS DUE YESTERDAY!! 5. Use the following information to answer the questions.
.
A survey asked 75 people if they wanted a later school day start time.
.
45 people were students, and the rest were teachers.
.
50 people voted yes for the later start.
• 30 students voted yes for the later start.
.
a) Use this information to complete the frequency table. (5 points: 1 point for
each cell that was not given above)
Students
Teachers
Total
Vote YES for
later start
Vote NO for later
start
Total
b) Use the completed table from Part a. What percentage of the people surveyed
were teachers? (2 points)
Answer:
a) Yes No Total
Students 30 15 45
Teachers 20 10 30
Total 50 25 75
b) 30/75 = 2/5 = 40% of the people surveyed were teachers.
c) 20/75 = 4/15 = 26.7% of the people surveyed were teachers who wanted a later start time.
A viral linear DNA molecule of length, say, 1 is often known to contain a certain "marked position," with the exact location of this mark being unknown. One approach to locating the marked position is to cut the molecule by agents that break it at points chosen according to a Poisson process with rate λ. It is then possible to determine the fragment that contains the marked position. For instance, letting m denote the location on the line of the marked position, then if denotes the last Poisson event time before m (or 0 if there are no Poisson events in [0, m]), and R1 denotes the first Poisson event time after m (or 1 if there are no Poisson events in [m, 1]), then it would be learned that the marked position lies between L1 and R1. Find(a) P{L1 = 0}(b) P{L1 < x}, 0 < x < m, (c) P{R1 = 1}(d) P{R1 = x}, m < x < 1By repeating the preceding process on identical copies of the DNA molecule, we are able to zero in on the location of the marked position. If the cutting procedure is utilized on n identical copies of the molecule, yielding the data Li, Ri, i = 1, . . , n, then it follows that the marked position lies between L and R, where(e) Find E[R−L], and in doing so, show that E[R−L] ~
(a) P{L1 = 0}: Since L1 is the last Poisson event time before m, and m is uniformly distributed on [0, 1], we have:
P{L1 = 0} = P{no Poisson events in [0, m]} = e^(-λm)
(b) P{L1 < x}, 0 < x < m: We have:
P{L1 < x} = P{there is at least one Poisson event in [0, x]} = 1 - P{no Poisson events in [0, x]} = 1 - e^(-λx)
(c) P{R1 = 1}: Since R1 is the first Poisson event time after m, we have:
P{R1 = 1} = P{no Poisson events in [m, 1]} = e^(-λ(1-m))
(d) P{R1 = x}, m < x < 1: We have:
P{R1 = x} = P{there is no Poisson event in [m, x]} * P{there is at least one Poisson event in [x, 1]}
= e^(-λ(x-m)) * (1 - e^(-λ(1-x)))
(e) E[R-L]: We have:
E[R-L] = E[(R1-L1) + (R2-L2) + ... + (Rn-Ln)]
= E[R1-L1] + E[R2-L2] + ... + E[Rn-Ln] (by linearity of expectation)
= nE[R1-L1] (since the n copies are identical)
To find E[R1-L1], note that R1-L1 represents the length of the fragment that contains the marked position. This length is distributed as an exponential random variable with parameter λ, since it is the time until the next Poisson event in a Poisson process with rate λ. Therefore:
E[R1-L1] = 1/λ
Thus, we have:
E[R-L] = n/λ
This means that as n (the number of copies) becomes large, the expected length of the interval containing the marked position becomes smaller and smaller, converging to 0 as n approaches infinity.
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