Match the graph to its equation. ​

Answer:

Step-by-step explanation:

Answer:

Slope: m = (y2 - y1)/(x2 - x1) = (-5 - 3)/(14 - 6) = -8/8 = -1

The equation of the line is y = -x + b

Substitute (6,3) into the equation:

3 = -6 + b

b = 9

Therefore, the equation of the line is y = -x + 9

Step-by-step explanation:

Answer: -17/12 or -1 5/12 or 1 5/12

Step-by-step explanation:

convert both equations into improper fractions

− 55/12 - (-19/6)

-55/12+19/6

find the common factor of the denominators

-55/12 + 38/12

-17/12

-1 5/12

The area of shaded region of standard normal distribution is 0.1292

what is standard normal distribution?

A unique type of normal distribution with a mean of 0 and a standard deviation of 1 is known as the standard normal distribution, or z-distribution.

Any normal distribution can be transformed into the common normal distribution by converting the individual values into z-scores. Z-scores indicate the number of standard deviations that each value in a z-distribution is from the mean.

solution:

For - 3.39 to 0

The standard deviation value is : 0.00035

For 0 to 1.13

The standard deviation value is : 0.3708

Then for - 3.39 to + 1.13 :

The area of the given shaded area is 0.1292

Hence,the area of shaded region of standard normal distribution is 0.1292

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The mode for a particular set of observations is 5 since it occurs the majority of the time.

The mode formula is described in statistics as the formula for calculating the mode of a given collection of data. The value that occurs most frequently in a particular set is referred to as the mode, and the mode differs across grouped and ungrouped data sets. The mode may be calculated quite easily. Put all of the numbers in a given set in order, either lowest to highest or highest to lowest, and then count how many times each number appears in the set. The mode is the one that appears the most.

Here,

given set of observation:

5, 7, 8, 5, 7, 6, 9, 5, 10, 6

Mode is the number which occurs the highest time.

So here 5 occurs the highest times(3 times).

So,5 is the mode.

The mode for given set of observation is 5 as it occurs most time.

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A domain is a component of the nomenclature used in web addresses to identify your website or a particular page of your website online.

A function's authorized range of values is known as its domain. For a function like f, this set contains of the x values (x). The set of those values represents the possible range of values that a function can take as input. The function's response to our x value entry is this group of values.

here ,

A domain is typically a sphere of knowledge or an area under one's control.

Users find it much easier to recall and search for online because it is a string of text linked to a website's numerical IP address.

Both the internet's architecture and the way a company's network resources are set up fall under the umbrella term "domain."

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a) The customer will earn $800 as interest in 20 years.

b) The account balance after 20 years will be - $ 3300.

Principle = $2500

Rate of simple interest = 1.6%

Time = 20 yrs

The simple interest is expressed as :

   S.I = [tex]\frac{PRT}{100}[/tex]

⇒ S.I = [tex]\frac{2500 * 1.6 * 20}{100}[/tex]

⇒ S.I = 25 * 20 *1.6

⇒ S.I = 800

The simple interest after 20 years = $800

The account balance after 20 years is -

= principle + simple interest

= 2500 + 800

=  3300

a) The customer will earn $800 as interest in 20 years.

b) The account balance after 20 years will be - $ 3300.

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Answer:

B

Step-by-step explanation:

16 = 2⁴

9 = 3²

(2⁴)¹¹¹ × (3²)²²² = 2⁴⁴⁴ × 3⁴⁴⁴ = (2×3)⁴⁴⁴ = 6⁴⁴⁴

you can only combine the exponents of the same bases, or the bases of the same exponent.

in our case here the latter is used.

and indeed

6⁴⁴⁴ = (6²)²²² = 36²²²

so, essentially you were right. but you still needed to transform this into the form of the given answer option.

Using trigonometric identities, If sinA + sin² A = 1, then the value of the expression (cos²A + cos⁴A) is; 1

We are told that sinA + sin² A = 1.

Now, we want to find (cos²A + cos⁴A).

From trigonometric identities, we know that;

cos²A = 1 -  sin² A

Thus;

cos²A + cos⁴A = 1 -  sin² A + cos⁴A

Similarly, using trig identities on the given expression;

From sinA + sin² A = 1, we can say that;

sinA = 1 - sin² A

Since cos²A = 1 -  sin² A, then we can say that;

sinA = cos²A

Thus;

sin²A = cos⁴A

Thus;

cos²A + cos⁴A = 1 -  sin² A +  sin²A

= sinA +  sin²A= 1

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Correct question is;

If sinA + sin² A = 1, then the value of the expression (cos²A + cos⁴A) is

Answer:

Step-by-step explanation:i think to answer is either 90p or 9p

Answer:

90p or 9p

Step-by-step explanation:

500 ≤x≤ 600  is the recommended range of doses. Typically, a phase I or early phase II clinical trial involves dose range.

To solve this problem using Clark's rule, we need to determine the range of pediatric doses for a child who weighs less than 90 pounds and for whom the adult dose is 1,000 mg.

A mathematical formula known as Clark's rule is used in medicine to determine the right dosage of medication for patients aged 2 to 17 depending on their weight and the recommended adult dose.

First, we can use the formula provided to calculate the child dose:

Child dose = (Weight of child / 150) * Adult dose

Since the weight of the child is less than 90 pounds, we can set the weight of the child to the minimum value in the range, which is 50 pounds. This gives us:

Child dose = (50 / 150) * 1000 mg

= 333.33 mg

Next, we can set the weight of the child to the maximum value in the range, which is 89 pounds. This gives us:

Child dose = (89 / 150) * 1000 mg

= 593.33 mg

Therefore, the recommended range of doses for a child who weighs less than 90 pounds and for whom the adult dose is 1,000 mg is 500 mg ≤ x ≤ 600 mg.

So, the correct answer is D. 500 ≤x≤ 600.

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The measure of angle 55 degrees Celsius

In order to get the measure of the unknown angle A, we are given a right-angled triangle with two known side lengths for the perpendicular and base.

To do that, we may use the tan formula, which uses the two provided side lengths.

the nearest tenth:

To get the solution in this case, we must apply the tan ratio.

tan = Adjacent or Opposite

tan = Opposite / Adjacent

Given: Opposite equals 4, adjacent equals 13.

Given: Adjacent = 13, opposite = 12.

tan θ = 12/13

θ = tan^-1 (12/13)

55 degrees.

55 degrees, please.

The measure of angle 55 degrees Celsius

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Answer:

Step-by-step explanation:

a=2

n=0.5

2a=0

2.2=0

4=0

2a=0

Explanation:

Characteristics about an equation are slope, intercepts, and things like that.

Part D of each problem is just referring to part a, b, and c

So, Part D is basically asking you to show your work, to explain slope-intercept equation, make observations about the problem, etc.

Hope I helped! :)

The 4 tests of congruency are:

Side - Side - Side (S.S.S. congruency)

Side - Angle - Side (S.A.S. congruency)

Angle - Angle - Side (A.A.S congruency)

Right - Hypotenuse - Side (R.H.S. congruency)

Tests of congruency:

Side - Side - Side (S.S.S. congruency)

If three sides of one triangle are equal to three sides of another triangle, the triangles are congruent.

Side - Angle - Side (S.A.S. congruency)

If two sides and the included angle of one triangle are equal to the corresponding sides and angle of another triangle, the triangles are congruent.

Angle - Angle - Side (A.A.S congruency)

If two angles and the non-included side of one triangle are equal to the corresponding angles and side of another triangle, the triangles are congruent.

Right - Hypotenuse - Side (R.H.S. congruency)

If the hypotenuse and one leg of one right-angled triangle are equal to the corresponding hypotenuse and leg of another right-angled triangle, the two triangles are congruent.

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The given equation of the horizontal asymptote is y=0

Because there is not a rational expression so there is no horizontal asymtotes.The given equation would be linear because degree of given function is 1.

An asymtote is a line being approached by a curve but never touching the curve at any finite distance.It is a line that the graph approaches as either x or y in positive or negative infinity.

The horizontal asympototes of a function can be determined by looking at the degree of the numerator and denominator.if we say N is the degree of numerator and Dis the degree of denominator.So it will be N<D.Then horizontal asymptotes will be y=0

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Negative infinity is obtained by taking the limit of a decreasing sequence of negative real numbers as they approach negative infinity.

Negative infinity is an abstract concept that is used to represent a value that is less than the lowest possible number.  To get negative infinity, one must take the limit of a decreasing sequence of negative real numbers. This means that the sequence of numbers must get closer and closer to negative infinity as it continues to decrease. For example, if you take the sequence of numbers -1, -2, -3, -4, -5, -6, and so on, the limit of this sequence is -∞. As the sequence continues to decrease, it eventually reaches a point where the numbers become so small that they cannot be measured. At this point, the limit of the sequence is -∞.

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According to the given statement 2.622 years will it take until 80 ounces of this substance remains.

Use a test tube holder that has an ounce marker or can be converted quickly to ounces (like cups). As you take the measuring cup from the ingredient, let it overflow. You may try and reduce measurement afterwards. Use a knife to level the measuring cup.

The equation may be used to predict how much of the chemical is still present after t years, measured in ounces.

y=1800e -0.00052t

In the equation above, we substitute y = 80 ounce to obtain the time.

80= 1800e -0.00052t

80/1800=e -0.00052t

2/45= e -000.52t

Considering both ends of the aforementioned equation

In(2/45)= In(e -000.52t)

In(2)-In(45)= In(e -000.52)

0.3010-1.653= -000.52t

-1.352= -000.52t

dividing by 000.52 on both side

1.352/000.52= t

t= 2.622 years

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A removable discontinuity is when a function has an isolated point where it is not defined, and the function can be made continuous by removing that point. A hole is an example of a removable discontinuity.

In mathematics, a discontinuity is a point or set of points where a function does not behave as expected or fails to exist. There are three types of discontinuities: removable discontinuities, jump discontinuities, and infinite discontinuities. A removable discontinuity is when a function has an isolated point where it is not defined, and the function can be made continuous by removing that point. In other words, the function can be made continuous by “filling in” the discontinuity. An example of a removable discontinuity is a hole, where the graph has a gap that can be filled in. Jump discontinuities occur when the left-hand and right-hand limits of the function do not agree at a point, and the function “jumps” from one value to another at that point. An example of a jump discontinuity is a cusp, where the graph has a sharp point. Finally, an infinite discontinuity is when the function does not exist at a point, such as a vertical asymptote. In all three cases, the discontinuity can be easily identified by looking at the graph of the function.

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The asymptotes for the given function f(x) = 7/(x^2-2x-24) are located at

x = -3 and x = 8.

The asymptotes of a function are the lines that the graph approaches, but never touches as it continues to infinity. In the given function, f(x) = 7/(x^2-2x-24), the asymptotes are located at x = -3 and x = 8.

To find the asymptotes of a function, you first need to factor the denominator of the function. In this case, the denominator is[tex]x^2-2x-24,[/tex]which can be factored into (x+3)(x-8). This means that there are two potential zeroes in the denominator, x=-3 and x=8. These two points are the two asymptotes of the graph of the given function.

To explain further, the two asymptotes divide the x-axis into three intervals. On the interval (-infinity, -3), the graph of the function will approach negative infinity as x approaches -3 from the left. On the interval (-3, 8), the graph of the function will approach positive infinity as x approaches 8 from the right. On the interval (8, infinity), the graph of the function will approach negative infinity as x approaches 8 from the right.

In summary, the asymptotes for the given function f(x) = 7/(x^2-2x-24) are located at x = -3 and x = 8.

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Answer:

Length of the base = 15 cm

Volume = 1125√2 cm³ = 1590.99 cm³ (2 d.p.)

Step-by-step explanation:

[tex]\boxed{\begin{minipage}{6.6cm}\underline{Lateral Surface Area of a square pyramid}\\\\$LSA=a \sqrt{a^2+4h^2}$\\\\where:\\\phantom{ww}$\bullet$ $a$ is the base edge \\\phantom{ww}$\bullet$ $h$ is the height\\\end{minipage}}[/tex]

[tex]\boxed{\begin{minipage}{6.6cm}\underline{Base Area of a square pyramid}\\\\$BA=a^2$\\\\where:\\\phantom{ww}$\bullet$ $a$ is the base edge \\\end{minipage}}[/tex]

If the lateral surface area (LSA) of the pyramid is three times the base area (BA):

[tex]\implies a \sqrt{a^2+4h^2}=3a^2[/tex]

Rearrange the equation to isolate h²:

[tex]\implies \sqrt{a^2+4h^2}=3a[/tex]

[tex]\implies (\sqrt{a^2+4h^2})^2=(3a)^2[/tex]

[tex]\implies a^2+4h^2=9a^2[/tex]

[tex]\implies 4h^2=8a^2[/tex]

[tex]\implies h^2=2a^2[/tex]

[tex]\boxed{\begin{minipage}{6.6cm}\underline{Total Surface Area of a square pyramid}\\\\$SA=a^2+a \sqrt{a^2+4h^2}$\\\\where:\\\phantom{ww}$\bullet$ $a$ is the base edge \\\phantom{ww}$\bullet$ $h$ is the height\\\end{minipage}}[/tex]

Given:

Substitute these values into the formula for the total surface area and solve for a:

[tex]\implies a^2+a\sqrt{a^2+4(2a^2)}=900[/tex]

[tex]\implies a^2+a\sqrt{a^2+8a^2}=900[/tex]

[tex]\implies a^2+a\sqrt{9a^2}=900[/tex]

[tex]\implies a^2+a(3a)=900[/tex]

[tex]\implies a^2+3a^2=900[/tex]

[tex]\implies 4a^2=900[/tex]

[tex]\implies a^2=225[/tex]

[tex]\implies a=15[/tex]

Therefore, the length of the base of the square based pyramid is:

To find the height (h), substitute the found value of a into the formula for h² and solve for h:

[tex]\implies h^2=2(15)^2[/tex]

[tex]\implies \sqrt{h^2}=\sqrt{2(15)^2}[/tex]

[tex]\implies h=\sqrt{2}\sqrt{(15)^2}[/tex]

[tex]\implies h=15\sqrt{2}[/tex]

Therefore, the height of the square based pyramid is:

[tex]\boxed{\begin{minipage}{5cm}\underline{Volume of a square pyramid}\\\\$V=\dfrac{1}{3}a^2h$\\\\where:\\\phantom{ww}$\bullet$ $a$ is the base edge \\\phantom{ww}$\bullet$ $h$ is the height\\\end{minipage}}[/tex]

Given:

Substitute the values into the formula and solve for volume:

[tex]\implies V=\dfrac{1}{3}(15)^2 \cdot 15\sqrt{2}[/tex]

[tex]\implies V=\dfrac{225}{3} \cdot 15\sqrt{2}[/tex]

[tex]\implies V=75\cdot 15\sqrt{2}[/tex]

[tex]\implies V=1125\sqrt{2}[/tex]

[tex]\implies V=1590.99[/tex]

Therefore, the volume of the square based pyramid is:

We are required to find the equivalent fraction here. When simplifying 16/64, we divide both sides by 16:

16 ÷ 16 = 1

64 ÷ 16 = 4

16/64 in its simplest form is 1/4. When we multiply both the numerator and denominator by 2, we will find that:

1/4 = 2/8

To verify this, we can multiply both parts of the fraction by 8:

2 × 8 = 16

8 × 8 = 64

Hence, we know our answer is correct.

Answer:

The equation would be

y =-5x + 5

Step-by-step explanation:

Use the x of 0 from the point given (0,5)

Use the y of 5 from the point given (0,5)

Use the slope that is given: -5

Use all of the above to solve for the y-intercept (b).

y = mx + b

5 = -5(0) + b

5 = 0 + b

5 = b

y =mx + b

y = -5x + 5

In the graph, the line crosses the y axis at (0,5) . The is the y -intercept or the "b" of the equation.

From that points move down 5 and one to the right.  This is the slope.  Once we have two points we can draw a line.

Answer:

Domain: (-∞, ∞); Range: [1, ∞)

Step-by-step explanation:

Domain is the set/interval of x-values that the function spans while the range is the set or interval of y-values that the function spans.

Domain

We can see that the arrows point towards negative and positive infinity for x and also see there are no holes or asymptotes for this graph. Therefore, the domain is (-∞, ∞) or {x | x is any real number}

Range

We can see that the arrows both point towards infinity for y-values and that the lowest y-value this graph touches is y = 1 (inclusive, meaning this y-value is included in the range). Thus, the range is [1, ∞) or {y | y ≥ 1}

The alternate angles between two parallel lines are equal, therefore, ∠ A = ∠ E.



An enclosed 2-D shape called a rectangle has four sides, four corners, and four right angles (90°). A rectangle has equal and parallel, opposite sides. Since a rectangle is a two-dimensional form, it has two dimensions: length and width. The rectangle's longer side is its length, while its shorter side is its breadth.

Given:

CD ≅ CB and CA ≅ CE

As you can see from the diagram, on joining BE and AD the figure will represent a rectangle ABED because the diagonals of the rectangle are equal and bisect each other.

Thus, DE || AB (Rectangle property)

∠ A = ∠ E, because the alternate angle of parallel lines is equal.

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Answer:a,9 b,11

Step-by-step explanation:

We can find out which method SSS, SAS, ASA, and AAS can be used to prove similarity by observing what three components are given.

If it is given that three sides are equal then we will use side side side(SSS) postulate.

If it is given that two sides and one angle is given then we will use the side angle side(SAS) postulate.

If two angles and one side is given then we will use the angle side angle (ASA) postulate.

To find which postulate will suit for that we will have to observe which components are given that are equal.

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According to square numbers , 1 is a square number while 2 is not .

What does Squaring mean ?

In mathematics, a square is the result of multiplying a number by itself. The verb "to square" is used to denote this operation. Squaring is the same as raising to the power 2, and is denoted by a superscript 2; for instance, the square of 3 may be written as 32, which is the number 9.

When you multiply an integer (a “whole” number, positive, negative or zero) times itself, the resulting product is called a square number, or a perfect square or simply “a square.” So, 0, 1, 4, 9, 16, 25, 36, 49, 64, 81, 100, 121, 144, and so on, are all square numbers.

Thus , 1 is a square number while 2 is not .

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Classifying triangles maze's path formed from the starting point is 3 - 10 - 17, 9 - 13 - 20, 4 - 7 - 8, 20 - 21 - 29, 15 - 19 - 25, 26 - 28 - 38, 4 - 11 - 13, 3 - 16 - 25, 12 - 35 - 37, 23 - 30 - 37, 9 - 40 - 41, 19 - 24 - 39, 16 - 16 - 22, and 13 - 18 - 29.

The full question is in the attachment. According to the Pythagorean theorem if there are three sides a, b, and c, where a ≤ b < c

But if a + b < c then a triangle cannot be formed

From point start

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Our final resulting answer will be -5.

To calculate the remainder, first divide the polynomials.

Set up the polynomials to be divided. if there is not a term for every exponent, insert one with a value of 0.

[tex]\sqrt[x-1]{x^{3}-2x^{2} +3x-7 }[/tex]

Divide the highest order term in the dividend [tex]x^{3}[/tex] by the highest order term in divisor x.

Multiply the new quotient term by the divisor.

The expression needs to be subtracted from the dividend, so change all the signs [tex]x^{3}[/tex]+[tex]x^{2}[/tex].

After changing the signs, add the last dividend from the multiplied polynomials to find the new dividend.

Pull the next terms from the original dividend down into the current dividend.

Divide the highest order term in the dividend -[tex]x^{2}[/tex] by the highest order term in divisor x.

Multiply the new quotient term by the divisor.

The expression needs to be subtracted from the dividend, so change all the signs in -[tex]x^{2}[/tex]-x.

After changing the signs, add the last dividend from the multiplied polynomial to find the new dividend.

Pull the next terms from the original dividend down into the current dividend.

Divide the highest order term in the dividend 2x by the highest order in divisor x.

Multiply the new quotient term by the divisor.

The expression needs to be subtracted from the dividend, so change all the signs in -2x+2.

After changing the signs, add the last dividend from the multiplied polynomial to find the new dividend.

The final answer is the quotient plus the remainder over the divisor.

[tex]x^{2}[/tex]-x+2-[tex]\frac{5}{x-1}[/tex]

Since the last term in the resulting expression is a fraction, the numerator of the fraction is the remainder.

So, our final answer will be -5.

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